Search Results

Search found 69392 results on 2776 pages for 'batch file'.

Page 83/2776 | < Previous Page | 79 80 81 82 83 84 85 86 87 88 89 90  | Next Page >

  • bypass IIS xml file settings at file/folder level

    - by Matt Thrower
    Hi, Our site is currently set to pass all files with the xml file extension through the asp.net worker process because all the xml files on the site at the moment are generated dynamically on being hit, by writing the output directly into the response stream. However we now have a requirement to add a file which is much larger and takes several minutes to generate in this way. I wrote a console app to generate the file and set it to run nightly, but because of the global IIS setting directing xml files to run through asp_wp, it's not being served properly. I can't seem to find a way to make an exemption for the treatment of a single file in the IIS settings. Is there any other way we can do it? Cheers, Matt

    Read the article

  • Unexplained file not found for an existing file

    - by knishua
    Following is the error that occurs in this part of the code. Although the path is valid, a RuntimeError occurs—strange. What is happening, and how can I get this to work? for root,dirs,files in os.walk(self.path): for f in files : if (f.split('.')[1] == "mb"): z = utils.executeInMainThreadWithResult(self.contains,(f.split('.')[0])) if not (isinstance(z,NoneType)): cmds.symbolButton(self.arSubCategory + f.split('.')[0], image=(z[1].replace("\\","/")), width = 35,height = 70, c = "h.imp_file(" + "\"" + root.replace("\\","/") + "/" + f + "\"" + ")") def contains(self,imageName): print 'imageName : ',imageName,'\n' for root, dirs, files in os.walk(self.path+"images"): for g in files: x = re.search(imageName,g) if not (isinstance(x, NoneType)): print 'g ',root+"/"+g.replace("\\","/"),'\n' return (1,(root+"/"+g)) Error: # z is (1, 'T:/Reference_Library/Reference_work/Char_models/Workfiles/images\\rboxdisk1\\female\\highpoly/granny01_highpoly.jpg') Error: File not found: T:/Reference_Library/Reference_work/Char_models/Workfiles/images/rboxdisk1/female/highpoly/granny01_highpoly.jpg Traceback (most recent call last): File "<maya console>", line 115, in <module> File "<maya console>", line 65, in showWindowanimLibrary RuntimeError: File not found: T:/Reference_Library/Reference_work/Char_models/Workfiles/images/rboxdisk1/female/highpoly/granny01_highpoly.jpg

    Read the article

  • Download file from a regular site via proxy c#

    - by Dani
    I need to be able to download some file from a regular site using my proxy server, I already try this: System.Net.WebClient client = new System.Net.WebClient(); client.Proxy = new WebProxy(ip, port); client.DownloadFile(url); but it's not works at all, I don't know what I missed,(without a proxy it works) thanks, Dani.

    Read the article

  • Basic concepts in file system implementation

    - by darkie15
    I am a unclear about file system implementation. Specifically (Operating Systems - Tannenbaum (Edition 3), Page 275) states "The first word of each block is used as a pointer to the next one. The rest of block is data". Can anyone please explain to me the hierarchy of the division here? Like, each disk partition contains blocks, blocks contain words, and so on...

    Read the article

  • Most efficient way to search the last x lines of a file in python

    - by Harley
    I have a file and I don't know how big it's going to be (it could be quite large, but the size will vary greatly). I want to search the last 10 lines or so to see if any of them match a string. I need to do this as quickly and efficiently as possible and was wondering if there's anything better than: s = "foo" last_bit = fileObj.readlines()[-10:] for line in last_bit: if line == s: print "FOUND"

    Read the article

  • SQL query in JSP file pulling variable from VXML file

    - by s1066
    Hi I'm trying to get an SQL query to work within a JSP file. The JSP file is pulled by a VXML file here is my JSP file code: <?xml version="1.0"?> <%@ page import="java.util.*" %> <%@ page import="java.sql.*" %> <% boolean success = true; // Always optimistic String info = ""; String schoolname = request.getParameter("schoolname"); String informationtype = request.getParameter("informationtype"); try { Class.forName("org.postgresql.Driver"); String connectString = "jdbc:postgresql://localhost:5435/N0176359"; String user = "****"; String password = "*****"; Connection conn = DriverManager.getConnection(connectString, user, password); Statement st = conn.createStatement(); ResultSet rsvp = st.executeQuery("SELECT * FROM lincolnshire_school_information_new WHERE school_name=\'"+schoolname+"\'"); rsvp.next(); info = rsvp.getString(2); }catch (ClassNotFoundException e) { success = false; // something went wrong } %> As you can see I'm trying to insert the value of the variable declared as "schooname" into the end of the SQL query. However when I come to run the jsp file it doesn't work and I get an error "ResultSet not positioned properly". When I put a standard query in (without trying to make it value of the variable it works fine) Hope that makes sense, and thank you for any help!

    Read the article

  • Decompressing file with gzip produces file with no read-permissions on Windows 7

    - by Abiel
    I am attempting to decompress a .gz file using the GnuWin32 gzip program in Windows 7. I have full permissions on the compressed file, and my user account is an administrator. However, I end up not having read permissions on the decompressed file. To get read permissions I would have to manually change the permissions on it through right-clicking and selecting Properties Security. I am able to do this exact same thing with no permission problems in Windows XP, which leads me to believe that Windows 7's user account control system is causing problems. Does anyone know what I can do to make things work as I would expect (read permission on the decompressed file) in Windows 7? Thanks.

    Read the article

  • Reading a file N lines at a time in ruby

    - by Sam
    I have a large file (hundreds of megs) that consists of filenames, one per line. I need to loop through the list of filenames, and fork off a process for each filename. I want a maximum of 8 forked processes at a time and I don't want to read the whole filename list into RAM at once. I'm not even sure where to begin, can anyone help me out?

    Read the article

  • How to find all the file handles by a process programmatically?

    - by kumar
    I have a process "x" which uses "system" C function to start ntpd daemon. I observed that ntpd are passed the open file descriptors of "x". ntpd holds on to the file descriptors even after original file is deleted. for ex: Some log files used by "x" are rotated out after sometime, but "ntpd" has file handle opened for these deleted files. Will it cause any problem? Alternatively I thought of setting "FD_CLOEXEC" flag for all the file descriptors before calling "system" function. But as we are running as an extension library to third process "x"( "x" loads our library based on some condition), there is no easy way to know about all the file descriptors process has opened. One way is to read /proc//fd and set "FD_CLOEXEC" for each file handle and reset it back after "system" function returns. I'm using Linux 2.16. Is there any other easy way to find all the file handlers? Thanks,

    Read the article

  • How to open a .a file

    - by Mgst
    Heya! My name is Ale, and this is the first time that I post in this website. I've a little problem: I have to open a linker file, that have ".a" extension. I use Dev-C++, I don't know if it would be useful for you :-P I hope you will answer soon! Oh, and excuse me for my bad English, tell me if I made some mistakes! Thanks!!

    Read the article

  • Queuing asynchronous HTTP file uploads

    - by David Parunakian
    Is there a way to queue file uploads without resorting to Flash or Silverlight, just with cleverly used forms and JavaScript? Note that the upload should be executed asynchronously. By "queuing" uploads I mean that if the user tries to upload multiple files, they should not be transferred simultaneously, but rather one at a time, in a single HTTP connection.

    Read the article

  • how to read a static file in .py file using django ..

    - by zjm1126
    this is my error code: text = open('/media/a.txt', 'rb').read() and my perplexed is: when i use this : text = open('a.txt', 'rb').read() it can be running but when i put the 'a.txt' to the 'media' folder, i can't running , why ? thanks IOError at / [Errno 13] file not accessible: '/media/a.txt'

    Read the article

< Previous Page | 79 80 81 82 83 84 85 86 87 88 89 90  | Next Page >