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  • Ubuntu maverick username and password works with ssh but not with smb when I connect from MacOS 10.6.5

    - by biomed
    I have an Ubuntu Maverick desktop that I can easily connect using ssh but when I want to see the shared directories using "go to server", MacOs connects to the Ubuntu machine and I can see the shared directories but when I enter my username and passord to get access it complains about me entering wrong username and/or password. Any ideas? What more information would you need to give me some advise? Is there a step by step how-to manual to get this done? thanks

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  • Can I password protect a location (not directory) in apache using htaccess?

    - by dimvic
    I have used code like this in apache configuration to protect locations with password <Location ~ "/admin.*"> AuthType Basic AuthName "Protected Area" AuthUserFile /home/user/public_html/.htpasswd Require valid-user </Location> is there a way to do the same thing using an htaccess file? the locations I want to protect don't really exist on the filesystem, it's locations available thanks to mod_rewrite

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  • ExtJs getting the FormPanel that is created dynmaically from button click.

    - by sharad
    I have Extjs ViewPort panel, that contain center panel, that contain tablpanel, in which I have added gridpanel in one tab, on this I have put 'Add Person' button in tbar of , that will add a new tab of a FormPanel, in its Reset button, I am not able to access Form to reset it. Do any body have faced same issue... please help how to get it working. Ext.onReady( function(){ // Ext.get(document.body, true).toggleClass('xtheme-gray'); var myBorderPanel = new Ext.Viewport({ title: 'Software Releases', // renderTo: document.body, renderTo: Ext.getBody(), layout: 'border', id: 'main', items: [ { title: 'Center Region', region: 'center', // center region is required, no width/height specified tbar: [ { text: 'Add person', // only when user have write priovilege. handler: function() { var tabpanel = Ext.getCmp('main').findById('tabs'); var wtab = tabpanel.add({ // // var addrelease_win = new Ext.Window({ url: 'reledit-submit.json', id: 'addform0', // height: 300, width: 400, layout: 'form', frame: true, title: 'Add New Release', closable: true, items: [ { xtype: 'textfield', fieldLabel: 'Name' } buttons: [{ text: 'Save', scope: wtab, handler: function() { wtab.getForm().submit({ success: function(f,a) { Ext.Msg.alert('Success', 'It worked'); }, failure: function(f,a){ Ext.msg.alert('Warnning', 'Error'); } }); } },{ text: 'Reset', scope: wtab, handler: function() { // Ext.getCmp('addform0').getForm().reset(); // tabpanel.getActiveTab.reset(); // Ext.getCmp('main').findById('addform').getForm().reset(); // this.getForm().reset(); // this.getForm().reset(); // Ext.Msg.alert('sdfsd', 'asdfsd ' + Ext.getCmp('addform0').getValue() + ' sdfsd'); this.findById('addform0').getForm().reset(); // Ext.Msg.alert('sdfsd', 'asdfsd '); } }] }); // addrelease_win.show(); tabpanel.activate(tabpanel.items.length - 1); } } ], xtype: 'tabpanel', id: 'tabs', activeTab: 0, items: [{ title: 'Data', xtype: 'editorgrid', store: store, stripeRows: true, // autoExpandColumn: 'title', columns: [ {header: "Name" , dataIndex: "name" , width: 50, sortable: true}, {header: "DOB", dataIndex: "dob" , sortable: true} ], }) }], margins: '5 5 0 0' } ] }); }

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  • How can you connect to a password protected MS Access Database from a Spring JdbcTemplate?

    - by Tim Visher
    I need to connect to a password protected MS Access 2003 DB using the JDBC-ODBC bridge. I can't find out how to specify the password in the connect string, or even if that is the correct method of connecting. It would probably be relevant to mention that this is a Spring App which is accessing the database through a JdbcTemplate configured as a datasource bean in our application context file. Some relevant snippets: from application-context.xml <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate"> <property name="dataSource" ref="legacyDataSource" /> </bean> <bean id="jobsheetLocation" class="java.lang.String"> <constructor-arg value="${jobsheet.location}"/> </bean> <bean id="legacyDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.legacy.driverClassName}" /> <property name="url" value="${jdbc.legacy.url}"/> <property name="password" value="-------------" /> </bean> from our build properties jdbc.legacy.driverClassName=sun.jdbc.odbc.JdbcOdbcDriver jdbc.legacy.url=jdbc:odbc:Driver\={Microsoft Access Driver (*.mdb)};Dbq\=@LegacyDbPath@;DriverID\=22;READONLY\=true Any thoughts?

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  • Forms authentication: how do you store username password in web.config?

    - by Nick G
    I'm used to using Forms Authentication with a database, but I'm writing a little internal utility and the app doesn't have a database so I want to store the username and password in web.config. However for some reason, forms authentication is still trying to access SQL Server and I can't see how to stop it doing this and pick up the credentials from web.config. What am I doing wrong? I just get the error "Failed to generate a user instance of SQL Server due to a failure in impersonating the client. The connection will be closed." Here are the relevant sections of my web.config: <configuration> <system.web> <authentication mode="Forms"> <forms loginUrl="~/Login.aspx" timeout="60" name=".LoginCookie" path="/" > <credentials passwordFormat="Clear"> <user name="user1" password="[pass]" /> <user name="user2" password="[pass]" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration>

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  • Please explain in detail this part of YUI3 CSS Reset..

    - by metal-gear-solid
    What is the usefulness of these 2 things in CSS reset? What is the problem in resizing of input elements in IE and in which version? and if legend color doesn't inherit in IE then how it can be solved adding color:#000; /*to enable resizing for IE*/ input, textarea, select { *font-size:100%; } /*because legend doesn't inherit in IE */ legend { color:#000; }

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • How do I configure freeSSHd on Windows Server 2008 so I can log in using ssh?

    - by Daryl Spitzer
    I've installed freeSSHd on a Windows Server 2008 box (following the instructions in How to install an SSH Server in Windows Server 2008), including: created a user named "dspitzer" with NTLM authorization opened an exception for port 22 in the Windows Firewall But when I try to connect (from a Mac OS X 10.5.8 command-line), I get permission denied after entering the password: $ ssh 12.34.56.78 [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried: $ ssh [email protected] [email protected]'s password: Permission denied, please try again. [email protected]'s password: Permission denied, please try again. [email protected]'s password: Received disconnect from 12.34.56.78: 2: Too many attempts. I've also tried changing the authorization to "Password stored as SHA1 hash" and entering a simple password, but I get the same problem. And I've tried a different user name ("Administrator") with no luck. I've confirmed that I am connecting to the server I'm configuring—if I stop freeSSHd and try to connect I get: $ ssh 12.34.56.78 ssh: connect to host 12.34.56.78 port 22: Operation timed out I get the exact same results from a Linux command-line. Any advice or troubleshooting tips? Update: I tried disabling the firewall (in response to geeklin's comment) and it made no difference. Update #2: I no longer have this machine (I've changed employers), so I have no way of verifying the answers. I guess all I can do is make this question "community wiki".

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  • LDAP change user pass on client

    - by Sean
    I am trying to allow ldap users to change their password on client machines. I have tried pam every which way I can think of /etc/ldap.conf & /etc/pam_ldap.conf, as well. At this point I'm stuck. Client: Ubuntu 11.04 Server: Debian 6.0 The current output is this: sobrien4@T-E700F-1:~$ passwd passwd: Authentication service cannot retrieve authentication info passwd: password unchanged /var/log/auth.log gives this during the command: May 9 10:49:06 T-E700F-1 passwd[18515]: pam_unix(passwd:chauthtok): user "sobrien4" does not exist in /etc/passwd May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: reconnecting to LDAP server... May 9 10:49:06 T-E700F-1 passwd[18515]: pam_ldap: ldap_simple_bind Can't contact LDAP server getent passwd |grep sobrien4 (note keeping short since testing with that account, however it outputs all ldap users): sobrien4:Ffm1oHzwnLz0U:10000:12001:Sean O'Brien:/home/sobrien4:/bin/bash getent group shows all ldap groups. /etc/pam.d/common-password (Note this is just the most current, I have tried a lot of different options): password required pam_cracklib.so retry=3 minlen=8 difok=3 password [success=1 default=ignore] pam_unix.so use_authtok md5 password required pam_ldap.so use_authtok password required pam_permit.so Popped open wireshark as well, the server & client are talking. I have the password changing working on the server. I.E. the server that runs slapd, I can log in with the ldap user and change the passwords. I tried copying the working configs from the server initially and no dice. I also tried cloning it, and just changing ip & host, and no go. My guess is that the client is not authorized by ip or hostname to change a pass. Pertaining to the slapd conf, I saw this in a guide and tried it: access to attrs=loginShell,gecos by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read access to * by dn="cn=admin,dc=cengineering,dc=etb" write by self write by * read So ldap seems to be working okay, just can't change the password.

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  • FTP Upload ftpWebRequest Proxy

    - by Rodney Vinyard
    Searchable:   FTP Upload ftpWebRequest Proxy FTP command is not supported when using HTTP proxy     In the article below I will cover 2 topics   1.       C# & Windows Command-Line FTP Upload with No Proxy Server   2.       C# & Windows Command-Line FTP Upload with Proxy Server   Not covered here: Secure FTP / SFTP   Sample Attributes: ·         UploadFilePath = “\\servername\folder\file.name” ·         Proxy Server = “ftp://proxy.server/” ·         FTP Target Server = ftp.target.com ·         FTP User = “User” ·         FTP Password = “Password” with No Proxy Server ·         Windows Command-Line > ftp ftp.target.com > ftp User: User > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp.target.com/file.name); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("user, "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);   with Proxy Server ·         Windows Command-Line > ftp proxy.server > ftp User: [email protected] > ftp Password: Password > ftp put \\servername\folder\file.name > ftp dir           (result: file.name listed) > ftp del file.name > ftp dir           (result: file.name deleted) > ftp quit   ·         C#   //----------------- //Start FTP via _TargetFtpProxy //----------------- string relPath = Path.GetFileName(\\servername\folder\file.name);   //result: relPath = “file.name”   FtpWebRequest ftpWebRequest = (FtpWebRequest)WebRequest.Create("ftp://proxy.server/" + relPath); ftpWebRequest.Method = WebRequestMethods.Ftp.UploadFile;   //----------------- //user - password //----------------- ftpWebRequest.Credentials = new NetworkCredential("[email protected], "password");   //----------------- // set proxy = null! //----------------- ftpWebRequest.Proxy = null;   //----------------- // Copy the contents of the file to the request stream. //----------------- StreamReader sourceStream = new StreamReader(“\\servername\folder\file.name”);   byte[] fileContents = Encoding.UTF8.GetBytes(sourceStream.ReadToEnd()); sourceStream.Close(); ftpWebRequest.ContentLength = fileContents.Length;     //----------------- // transer the stream stream. //----------------- Stream requestStream = ftpWebRequest.GetRequestStream(); requestStream.Write(fileContents, 0, fileContents.Length); requestStream.Close();   //----------------- // Look at the response results //----------------- FtpWebResponse response = (FtpWebResponse)ftpWebRequest.GetResponse();   Console.WriteLine("Upload File Complete, status {0}", response.StatusDescription);

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  • How can I get access to password hashing in postgresql? Tried installing postgresql-contrib in ubun

    - by Tchalvak
    So I'm trying to just hash some passwords in postgresql, and the only hashing solution that I've found for postgresql is part of the pgcrytpo package ( http://www.postgresql.org/docs/8.3/static/pgcrypto.html ) that is supposed to be in postgresql-contrib ( http://www.postgresql.org/docs/8.3/static/contrib.html ). So I installed postgresql-contrib, (sudo apt-get install postgresql-contrib), restarted my server (as a simple way to restart postgresql). However, I still don't have access to any of the functions for hashing that are supposed to be in postgresql-contrib, e.g.: ninjawars=# select crypt('global salt' || 'new password' || 'user created date', gen_salt('sha256')); ERROR: function gen_salt(unknown) does not exist ninjawars=# select digest('test', 'sha256') from players limit 1; ERROR: function digest(unknown, unknown) does not exist ninjawars=# select hmac('test', 'sha256') from players limit 1; ERROR: function hmac(unknown, unknown) does not exist So how can I hash passwords in postgresql, on ubuntu?

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  • How to reduce timeout for bad password on disconnected laptop?

    - by Elroy Flynn
    I use a Windows 7 laptop computer. When not attached to my AD domain, if I enter an incorrect password, I have to wait approximately a full minute before the failure response comes back. When attached to the domain, the response is instant. I think that what's happening is that is that when my entry fails against the cached pw, Windows tries to reach the domain controller and the timeout for that operation is about 60s. Is there a registry entry that controls the timeout? I'd love to reduce it.

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  • How to deal with arrays of data in cookies

    - by peter
    Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

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  • Worksheet.Unprotect - Office Interop - Difference between 2003 and 2007

    - by sdmcnitt
    I have a .NET winforms app that automates Excel and checks for a worksheet password. The requirements are to be able to detect 1) that the protection is turned off 2) that the password is removed (protected but there is no password) 3) that the password matches the correct password from a database To meet the second requirement the program calls the Worksheet.Unprotect command with a null string, capturing the error. If error as expected, the 3rd check is made. If no error, then the Unprotect worked without a password == password was removed. The code sample below has these checks. The application can do this fine with Office 2003. I have since had my dev machine updated to Office 2007 and it no longer works as it did. When I call the Worksheet.Unprotect, Excel prompts for the password! I need to know how this should be accomplished in the new version of Excel or if there is a way to reference the old PIA. No matter what if I set a reference to Excel 11 it is replaced with the PIA for 12 in the GAC. 'return true if unprotect of worksheet does not generate an error 'all other errors will bubble up 'return false if specific error is "Password is invalid..." Try 'detect unprotected or no password If oWorksheet.ProtectContents Then 'try with no passsword and expect an error 'if no error then raise exception Dim blnRaiseException As Boolean = True Try 'oWorksheet.Unprotect(vbNullString) oWorksheet.Unprotect() Catch ex As Exception blnRaiseException = False End Try If blnRaiseException Then Throw New ExcelSheetNoPasswordException End If oWorksheet.Unprotect(strPwd) 'no error so if we get here -- success fnCheckWorksheetPwd = True 'leave as it was -- this may still cause workbook to think it is changed oWorksheet.Protect(strPwd) Else Throw New ExcelSheetNotProtectedException End If Catch COMex As System.Runtime.InteropServices.COMException 'handle error code -2146827284 If COMex.ErrorCode = -2146827284 Then 'this is the error we're looking for Else Throw End If Catch ex As Exception Throw End Try

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