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  • jquery form validate not allow space for username field?

    - by python
    I have used http://bassistance.de/jquery-plugins/jquery-plugin-validation/ my form validate : $("#form_person").validate({ rules: { username: { required: true, minlength: 2, maxlength:15 }, password: { required: true, minlength: 2 }, confirm_password: { required: true, minlength: 2, equalTo: "#password" }, email: { required: true, email: true } }, messages: { username: { required: "Please enter a username", maxlength:"max length 15 digits", minlength: "Your username must consist of at least 2 characters" }, password: { required: "Please provide a password", minlength: "Your password must be at least 5 characters long" }, confirm_password: { required: "Please provide a confirm password", minlength: "Your password must be at least 5 characters long", equalTo: "Please enter the same password as above" } }); Anybody help me to validate not allow space on username? thanks

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  • How can I clear the "authentication cache" in Windows 7 to a password protected samba share?

    - by Chris Drumgoole
    I have a Linux samba server and have explicitly listed users that can access the folder. I have successfully congfigured Samba to require a username and password when accessing the share from windows (using the smbpasswd, etc.). But now I want to force clear the auth cache on the windows machine. Such as when I go to a colleague's computer, I use my account to access a file in the protected share, but then before I leave his computer, i'll want to make sure the authorization cache is cleared so he cannot access that folder with my credentials. I found the command to use in the windows command prompt on google a couple of weeks ago but silly me I didn't save it... Hope someone can help, thanks! Oh, Samba is configured as a workgroup and not a domain (if that helps) - so windows users do NOT log into a domain on start up. thanks!

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  • How can I password-protect a Mac shared folder on a Windows workgroup?

    - by Phillip Oldham
    We have a Mac-mini running 10.5.8 which already acts as a fileserver for our simple Windows (mixed XP/Vista) workgroup. The Mac-mini is on the same workgroup and the files are shared via SMB, FTP, and AFP. Basic file-sharing is working, and has been for some time. We'd now like to add an additional directory/share which can be secured by a password so that only a small number on the network have access. Is this possible? I've already tried creating the additional folder on the mac system, adding it to the shared folders, and limiting it to a specific "shared user", however it's not possible to log-in from an XP machine. Adding a sub-directory to the currently working share and giving limiting it's access to the shared user doesn't work either.

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  • JavaScript and PHP - A little confused on how to work them together.

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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  • How can I password-protect a Mac shared folder on a Windows workgroup?

    - by Phillip Oldham
    We have a Mac-mini running 10.5.8 which already acts as a fileserver for our simple Windows (mixed XP/Vista) workgroup. The Mac-mini is on the same workgroup and the files are shared via SMB, FTP, and AFP. Basic file-sharing is working, and has been for some time. We'd now like to add an additional directory/share which can be secured by a password so that only a small number on the network have access. Is this possible? I've already tried creating the additional folder on the mac system, adding it to the shared folders, and limiting it to a specific "shared user", however it's not possible to log-in from an XP machine. Adding a sub-directory to the currently working share and giving limiting it's access to the shared user doesn't work either.

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  • How do I secure password parameters in RESTful web service URIs?

    - by adam
    i'm a newbie to server-side programming, so please forgive me if this gets messy. i've been contracted to create a web service to allow authenticated users to access a database. users have to enter a login and password. been reading and reading about REST vs SOAP, and i thought i'd settled on a RESTful design when i came across this statement: "Data that needs to be secure should not be sent as parameters in URIs." this seems like a major demerit against a RESTful approach. i'm aware that with https the password would be encrypted to prevent man-in-the-middle interception, but that leaves the server logs and client history as possible exposure points. is there a RESTful solution out there for this problem, or do i need to go SOAPy? any advice appreciated.

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  • How do I password protect IIS in a method analogous to Apache's AuthType / AuthUserFile mechanism?

    - by Matt
    I'm used to doing basic password protection for Apache w/ the following method in Apache config files: AuthType Basic AuthName "By Invitation Only" AuthUserFile /path/to/.htpasswd Require valid-user However, I've been asked to put some protection on a subdirectory of a site running ColdFusion on top of IIS6, and I'm unfamiliar with how to do this. How is this done? What should I look out for? I just need to password protect an administrative subdirectory, so I don't need a full user login system - just something that limits who can access the section of the site.

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  • How do I backup (from Vista Home Premium) to a FAT32 HDD connected to a wireless router with no user account or password set?

    - by Scubadooper
    I have a Seagate expansion 2TB HDD which I've managed to get working on my wireless router (thanks to fat32format) however I haven't managed to set my backup to work with it. Vist Home Premium requires that I input a username and password in the backup utility. As far as I'm aware that type of access control isn't set on the HDD: Can I set up the access control on the HDD? If so how Or, can I set the backup to work without it? If so how Thanks for your help, I haven't been able to find the answer anywhere on the net so far

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  • Connect to a DB with an encrypted password with Django?

    - by Liam
    My place of employment requires that all passwords must be encrypted, including the ones used to connect to a database. What's the best way of handling this? I'm using the development version of Django with MySQL at the moment, but I will be eventually migrating to Oracle. Is this a job for Django, or the database? Edit: The encrypted password should be stored in the settings.py file, or somewhere else in the filesystem. This is the password that will be used to connect to the database.

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  • Get with the ajax data into a php file

    - by Max Torstensson
    I'm trying to build a login system with ajax and php. I use a log-view where I then save the data in ajax which brings into my doLogin.php (php file). My problem is that php file should never be any ajax data for when I build it into a class and a function VIEW: public function DoLoginBox() { //inloggning form-tagg... return '<p>&nbsp;</p> <div id="content"> <h1>Login Form</h1> <form id="form1" name="form1" action="Handler/doLogin.php" method="post"> <p> <label for="username">Username: </label> <input type="text" name="username" id="username" /> </p> <p> <label for="password">Password: </label> <input type="password" name="password" id="password" /> </p> <p> <input type="submit" id="login" name="login" /> </p> </form> <div id="message"></div> </div>'; } AJAX: <script type="text/javascript"> $(document).ready(function() { $("#login").click(function() { var action = $("#form1").attr('action'); var form_data = { username: $("#username").val(), password: $("#password").val(), is_ajax: 1 }; $.ajax({ type: "POST", url: action, data: form_data, success: function(response) { if(response == 'success') $("#form1").slideUp('slow', function() { $("#message").html("<p class='success'>You have logged in successfully!</p>"); }); else $("#message").html("<p class='error'>Invalid username and/or password.</p>"); } }); return false; }); }); </script PHP: <?php require_once ("UserHandler.php"); class DoLogingHandler{ public function Login (){ $is_ajax = !empty($_REQUEST['is_ajax']); if(isset($is_ajax) && $is_ajax) { $username = $_REQUEST['username']; $password = $_REQUEST['password']; $UserHandler = new UserHandler(); $UserHandler -> controllDB($username,$password); if($username == 'demo' && $password == 'demo') { echo "success"; } } } } ` $DoLogingHandler = new DoLogingHandler(); $DoLogingHandler-Login(); ?

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  • How to prompt for username and password entry in C# / SQL ASP.NET web app?

    - by salvationishere
    How do I prompt for username and password in my C#/SQL web application? This was developed in VS 2008 on a 32-bit XP. The current connection string I'm using in my web.config file is: <add name="AdventureWorksConnectionString2" connectionString="Data Source=SIDEKICK;Initial Catalog=AdventureWorks;Persist Security Info=false; " providerName="System.Data.SqlClient" /> When I select Basic Authentication it pops up the warning: "The authentication option you have chosen results in passwords being sent over the network without data encryption..." How do I choose this authentication method and still send passwords over securely? So essentially I am looking for the most secure authentication method but that still requires users to input password?

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  • update value of a variable outside a class in VB.NET

    - by dpp
    I have a class derived from a Form, it has textbox for username and password and an OK button. I want it to behave like an InputBox so I can use it like this: Dim Username As String = "" Dim Password As String = "" Dim authorization As New Authorization(Username, Password) authorization.ShowDialog() 'The user will click OK and I will expect the Username and Password to change based on the user input MsgBox(Username & " " & Password) The Authorization class: Public Class Authorization Dim RefUsername As String Dim RefPassword As String Public Sub New(ByRef Username As String, ByRef Password As String) InitializeComponent() RefUsername = Username 'I'm trying to pass reference instead of value RefPassword = Password 'I'm trying to pass reference instead of value End Sub Private Sub OKButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AuthorizeButton.Click RefUsername = Username.Text 'I'm trying to change value of variable outside the class RefPassword = Password.Text 'I'm trying to change value of variable outside the class Me.Close() End Sub End Class In short, I want to change the value of variables outside the class when the user clicks the OK, how am I going to accomplish that?

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  • Logging in with sha1() encryption.

    - by Samir Ghobril
    Hey guys, I added this to my sign up code : $password=mysql_real_escape_string(sha1($_POST['password'])); and now it inserts the password into the database while its encrypted. But signing in doesn't seem to work anymore. Here is the login code. function checklogin($username, $password){ global $mysqli; $password=sha1($password); $result = $mysqli->prepare("SELECT * FROM users WHERE username = ? and password=?"); $result->bind_param("ss", $username, $password); $result->execute(); if($result != false){ $dbArray=$result->fetch(); if(!$dbArray){ echo '<p class="statusmsg">The username or password you entered is incorrect, or you haven\'t yet activated your account. Please try again.</p><br/><input class="submitButton" type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; if(isset($_POST['remember'])){ setcookie("jmuser",$username,time()+60*60*24*356); setcookie("jmpass",$password ,time()+60*60*24*356); } redirect(); }

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  • devise forgot password function not working when creating own user controller?

    - by ragupathi
    I use devise for authentication and i have created a user controller and specified as shown below in my routes which lets me to create users,edit and delete users, devise_for :users do resources :users, :only => [:index, :new, :create, :edit, :update, :destroy] end but i cannot able to make the forgot password functionality work using this but in case i specify as devise_for :users then i can able to use the forgot password function that comes with devise and i could not able to create , edit or delete when i specify like this. So how can i make both to work ? please help me

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  • header location won't work in php

    - by Jayden Kelly
    I am making a login page for my website but the header location won't work. here is the code of login.php: <?php include ( './includes/header.php' ); if (isset($_POST['submit'])) { $username = $_POST['username']; $password = $_POST['password']; $check_username = mysql_query("SELECT username FROM users WHERE username='$username'"); $numrows = mysql_num_rows($check_username); if ($numrows != 1) { echo 'That User doesn\'t exist.'; } else { $check_password = mysql_query("SELECT password FROM users WHERE password='$password' && username='$username'"); while ($row = mysql_fetch_assoc($check_password)) { $password_db = $row['password']; if ($password_db == $password) { $_SESSION['username'] = $username; header("Location: members.php"); } } } } ?> <h2>Login to Your Account</h2> <form action='login.php' method='POST'> <input type='text' name='username' value='Username ...' onclick='value=""'/><p /> <input type='password' name='password' value='Password ...' onclick='value=""'/><p /> <input type='submit' name='submit' value='Login to my Account' /> </form> I would really appreciate it if someone could help me, thanks. P.S. If you need the php part of the header file it is here: <?php session_start(); include ( './includes/functions.php' ); include ( './includes/connect_to_mysql.php' ); ?>

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  • segmentation fault using scanf

    - by agarrow
    noob question here: I'm trying to write a simple menu interface, but I keep getting a segmentation fault error and I can't figure out why. #include <stdlib.h> #include <stdio.h> int flush(); int add(char *name, char *password, char *type); int delete(char *name); int edit(char *name, char *password, char *type, char *newName, char *newPassword, char *newType); int verify(char *name, char *password); int menu(){ int input; char *name, *password, *type, *newName, *newPassword, *newType; printf("MAIN MENU \n ============\n"); printf("1. ADD\n"); printf("2. DELETE\n"); printf("3. EDIT\n"); printf("4. VERIFY\n"); printf("5. Exit\n"); printf("Selection:"); scanf("%d", &input); flush(); switch (input){ case 1: printf("%s\n", "Enter Name:"); scanf("%s", name); flush(); printf("%s\n", "enter password" ); scanf("%s", password); flush(); printf("%s\n","enter type" ); scanf("%s",type); add(name, password, type); menu(); break; case 2: printf("Enter Name:" ); scanf("%s",name); flush(); delete(name); menu(); break; case 3: printf("Enter Name:\n"); scanf("%s",name); flush(); printf("Enter Password\n"); scanf("%s", password); flush(); printf("enter type:\n"); scanf("%s", type); flush(); printf("enter your new username:\n"); scanf("%s",newName); flush(); printf("enter your new password\n"); scanf("%s", newPassword); flush(); printf("enter your new type\n"); scanf("%s",newType); flush(); edit(name, password, type, newName, newPassword, newType); menu(); break; case 4: printf("Enter Name\n"); scanf("%s",name); flush(); printf("Enter Password\n"); scanf("%s",password); flush(); verify(name, password); menu(); break; case 5: return 0; default: printf("invalid input, please select from the following:\n"); menu(); } return 0; } int flush(){ int ch; while ((ch = getchar()) != EOF && ch != '\n') ; return 0; } I get the segmentation fault after entering two fields, in any menu option

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  • Confused on the basics of AJAX

    - by Doug
    So right now, I'm just using a basic form to check a password. I want it to check the password and basically remain on page.html so I can use JavaScript to alert incorrect password or something. I'm not really sure how to do that. It seems it would bring me to check.php. I'm not too sure on the whole process, any help appreciated! Thanks! Page.html <form action="check.php" method="post"> <input type="password" name="password" /> <input type="submit" value="Submit" /> </form> check.php <?php $password = $_POST['password']; if ( $password != "testing" ) { die(); } ?>

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  • How can I retrieve "remembered"(stored) wi-fi password from a win. 7 device?

    - by user180880
    I have access to PC, and I am a standard user. Everything(incl. "show charecters" tickbox at wiriless menu) requires admin access. Now, that said machine is actually like a big tv with touch. Type-stuff is handled by virtual keyboard of windows. I can reach to c:\ProgramData\Microsoft\Wlansvc\Profiles\Interfaces and can see-open files there, which is I assume where passwords stored are. Now the problem is that these passwords is encypted. I'm ok with if there is a way with changing/resetting admin password as well. Considering this device has nothing but massive amounts of usb(yep, not even cd-dvd // rw) the only way is from inside or with usb without admin rights.

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  • PHP & MySQL - Undefined variable problem?

    - by TaG
    I keep getting the following error Undefined variable: password on line 33 how do I correct this problem? So this error will stop showing. Here is the php code. $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $password1 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password1']))); $password2 = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($_POST['password2']))); // Check for a password and match against the confirmed password: if ($password1 == $password2) { $sha512 = hash('sha512', $password1); $password = mysqli_real_escape_string($mysqli, $sha512); } else { echo '<p class="error">Your password did not match the confirmed password!</p>'; } //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, password) VALUES ('$user_id', '$first_name', '$password')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; }

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  • How to Set Ubuntu 12.04 to it's factory settings like when u first installed it?

    - by Cameron
    Well, this is a simple answered question, from the title, but my real problem is hard af. I have set ubuntu to use root, then it wouldn't let me log into the admin account only root and guest I deleted the admin account, remade another, then attempted to disable root account. This failed - I messed up the password, the original password was "root" I also didn't set a password for my new admin account, so It says it has one, whats the default password for it? I can't moderate my ubuntu system at all now. I have tried to drop to cmd shell thing, it asks for the root password, i type 'root' and any other possible passwords, it doesn't work. To reset ubuntu to factory settings i have found that i could enter the following code: sudo dpkg-reconfigure -phigh -a sudo Requires admin password, that I cant find out without root password and I don;t know. My goal is to try to fix this without remaking a bootable usb for ubuntu, because I lost the one i made for this. so If i can't, please say so. If you can help thanks!

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  • what other bash variables are available during execution such as $USER that can assist on my script?

    - by semi-newbie
    This is related to question 19245, in that one of the responders answered the question in an awesome way, and very VERY clear to any newbie. Now here is a question that i can't seem to figure. i wrote a script for starting the vmware firefox plugin (don't worry. i gave that up and now run vBox VERY happily. i left vmware for my servers :) ) I needed to start the plugin as sudo, but i also needed to pass an argument (password) to it, that happen to be the same. So, if my password was Hello123, the command would be: sudo ./myscript.sh hi other Hello123 running from command line, the script would ask for my sudo password and then run. i wanted to capture THAT password and pass it as well. i also wanted to run graphically, so i tried gksudo, and there is an option -p that returns the password for variable assignment. well, that was a nightmare, because i would still get prompted for the original sudo: see below Find UserName vUser=$USER Find password (and hopefully enable sudo) vP=gksudo -p -D somedescriptiontext echo Execute command gksudo ./myscript.sh hi $vUser $vP and i still get prompted twice. so my question is tri-fold: is there a variable i can use for the password, just like there is one for user, $USER? is there a different way i should be assigning the value resulting of the command i have in $vP? i am wondering if executing the way i have it, does it in an uninitiated session and not the current one, since i am getting some addtl warning type errors on some variables blah blah i tried using Zenity to just capture the text, but then of course, i couldn't pass that value to sudo, so i could only use as a parameter, which puts me back in 2 prompts. Thanksssssssssss!

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  • Cocos2d push scene with parameter, the parameter is reset after push. How to troubleshoot? Thoughts?

    - by user72693
    In the helloWorldLayer.m, I push a scene with some parameter like this [[CCDirector sharedDirector] replaceScene:[CCTransitionFade transitionWithDuration:0.2 scene:[RootLayer sceneWithInt:123]]]; where the RootLayer I have a modified method +(CCScene *) sceneWithInt:(int) i{ CCScene *scene = [CCScene node]; GameplayLayer *layer = [[GameplayLayer node] retain]; [layer setTestInt:i]; [scene addChild: layer z:0 tag:100]; return scene; } In the above, the "GameplayLayer" has an Int property "TestInt" which I would like to set it before this layer is push. However, the moment the GameplayLayer is loaded, that TestInt property is reset to 0. It is not passing correctly. I remember in my last project this can be done. How to troubleshoot this?

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  • How do I git reset --hard HEAD on Mercurial?

    - by obvio171
    I'm a Git user trying to use Mercurial. Here's what happened: I did a hg backout on a changeset I wanted to revert. That created a new head, so hg instructed me to merge (back to "default", I assume). After the merge, it told me I still had to commit. Then I noticed something I did wrong when resolving a conflict in the merge, and decided I wanted to have everything as before the hg backout, that is, I want this uncommited merge to go away. On Git this uncommited stuff would be in the index and I'd just do a git reset --hard HEAD to wipe it out but, from what I've read, the index doesn't exist on Mercurial. So how do I back out from this?

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  • How can I avoid properties being reset at design-time in tightly bound user controls?

    - by David Anderson
    I have UserControl 'A' with a label, and this property: /// <summary> /// Gets or Sets the text of the control /// </summary> [ Browsable(true), EditorBrowsable(EditorBrowsableState.Always), Category("Appearance") ] public override string Text { get { return uxLabel.Text; } set { uxLabel.Text = value; } } I then have UserControl 'B' which has UserControl 'A' on it, and I set the Text Property to "My Example Label" in the designer. Then, I have my MainForm, which has UserControl 'B' on it. Each time I do a build or run, the Text property of UserControl 'A' is reset to its default value. I suppose this is because since I am doing a rebuild, it rebuilds both UserControl 'A' and 'B', thus causing the problem. How can I go about a better approach to design pattern to avoid this type of behavior when working with tightly bound controls and forms in a application?

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