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  • How do I add artwork to an iTunes track with obj-c AppScript?

    - by demonslayer319
    aTrack is an ITReference* object, value is an NSImage* object, initialized via a URL to a jpeg. [[[[[aTrack artworks] data_] set] to:value] send]; I get the following message in GDB: 2010-03-09 16:59:42.860 Sandbox[2260:a0f] Can't pack object of class NSImage (unsupported type): <NSImage 0x10054a440 Size={0, 0} Reps=( I then tried the following code: NSData *imageData = [[NSData alloc] initWithData:[value TIFFRepresentation]]; [[[[[aTrack artworks] data_] set] to:imageData] send]; and get this message instead 2010-03-09 16:46:09.341 Sandbox[2193:a0f] Can't pack object of class NSConcreteData (unsupported type): <4d4d002a 00000000> In the AppScript documentation, it says that the "data" property of the "artwork" item is a PICTPicture image. How do I convert an NSImage to a PICT? Am I using the AppScript all wrong?

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  • PHP array ordering

    - by Melonheadjr44
    Hi, I was wondering how I could sort this array, when I use asort right now it does 14 17 16 15. How would I go to have 14 15 16 17 array(4) { [15]=> array(9) { [2025]=> string(80) "20:25 à 21:15 Spectacle / L'histoire d'un coeur / Auditorium, É.S.P. De La Salle" [2135]=> string(71) "21:35 à 22:25 Spectacle / Transfugue 2 / Auditorium, É.S.P. De La Salle" [1430]=> string(64) "14:30 à 15:30 Mise en lecture/Théâtre la Catapulte / De La Salle" [110]=> string(44) "11:00 à 13:00 Inscription / Pavillon Tabaret" [1330]=> string(49) "13:30 à 14:30 CÉRÉMONIE D'OUVERTURE / De La Salle" [1550]=> string(61) "15:50 à 16:40 Spectacle/Université Laurentienne / De La Salle" [170]=> string(57) "17:00 à 17:50 Spectacle/Université d'Ottawa / De La Salle" [1750]=> string(45) "17:50 à 19:00 REPAS DE L'AMITIÉ / De La Salle" [1915]=> string(76) "19:15 à 20:05 Spectacle / Attendre la pluie / Auditorium, É.S.P. De La Salle" } [16]=> array(8) { [1845]=> string(81) "18:45 à 19:35 Spectacle / Mimes d'horreur / Salle Académique, Université d'Ottawa" [1955]=> string(73) "19:55 à 20:45 Spectacle / Déroute / Salle Académique, Université d'Ottawa" [8]=> string(45) "08:30 à 11:30 Atelier / ABC du jeu dramatique" [13]=> string(41) "13:00 à 16:00 Atelier / Théâtre physique" [1130]=> string(28) "11:30 à 13:00 DÎNER LIBRE / " [1620]=> string(29) "16:20 à 18:20 SOUPER LIBRE / " [220]=> string(58) "22:00 à 23:30 BAL MASQUÉ / l'Agora du centre universitaire" [210]=> string(47) "21:00 à 22:00 Rétroaction / Université d'Ottawa" } [17]=> array(4) { [950]=> string(79) "09:50 à 10:40 Spectacle / Raison d'être / Salle Académique, Université d'Ottawa" [110]=> string(76) "11:00 à 11:50 Spectacle / Potionnée / Salle Académique, Université d'Ottawa" [120]=> string(28) "12:00 à 13:00 DÎNER LIBRE / " [1330]=> string(48) "13:30 à 14:30 CÉRÉMONIE DE CLÔTURE / De La Salle" } [14]=> array(1) { [150]=> string(49) "15:00 à 16:30 Préparation technique / De La Salle" } }

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  • How to make awkward pivot of sql table in MS SQL Server 2005?

    - by Oliver
    I have to rotate a given table from an sql server but a normal pivot just doesn't work (as far as i tried). So has anybody an idea how to rotate the table into the desired format? Just to make the problem more complicated, the list of given labels can vary and it is possible that a new label name can come into at any given time. Given Data ID | Label | Numerator | Denominator | Ratio ---+-----------------+-------------+---------------+-------- 1 | LabelNameOne | 41 | 10 | 4,1 1 | LabelNameTwo | 0 | 0 | 0 1 | LabelNameThree | 21 | 10 | 2,1 1 | LabelNameFour | 15 | 10 | 1,5 2 | LabelNameOne | 19 | 19 | 1 2 | LabelNameTwo | 0 | 0 | 0 2 | LabelNameThree | 15 | 16 | 0,9375 2 | LabelNameFive | 19 | 19 | 1 2 | LabelNameSix | 17 | 17 | 1 3 | LabelNameOne | 12 | 12 | 1 3 | LabelNameTwo | 0 | 0 | 0 3 | LabelNameThree | 11 | 12 | 0,9167 3 | LabelNameFour | 12 | 12 | 1 3 | LabelNameSix | 0 | 1 | 0 Wanted result ID | ValueType | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix ---+-------------+--------------+--------------+----------------+---------------+---------------+-------------- 1 | Numerator | 41 | 0 | 21 | 15 | | 1 | Denominator | 10 | 0 | 10 | 10 | | 1 | Ratio | 4,1 | 0 | 2,1 | 1,5 | | 2 | Numerator | 19 | 0 | 15 | | 19 | 17 2 | Denominator | 19 | 0 | 16 | | 19 | 17 2 | Ratio | 1 | 0 | 0,9375 | | 1 | 1 3 | Numerator | 12 | 0 | 11 | 12 | | 0 3 | Denominator | 12 | 0 | 12 | 12 | | 1 3 | Ratio | 1 | 0 | 0,9167 | 1 | | 0

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  • How does this method give me a -61 Error?

    - by prestonmarshall
    This is in an application I am using called Mirth, but it appears to be coming from inside an Apache Commons library from a method that checks if something is indeed Base64 encoded or not. All of the docs say the only return is true or false, so how am I getting -61? -61 org.apache.commons.codec.binary.Base64.isBase64(Base64.java:137) org.apache.commons.codec.binary.Base64.discardNonBase64(Base64.java:478) org.apache.commons.codec.binary.Base64.decodeBase64(Base64.java:374) org.apache.commons.codec.binary.Base64.decode(Base64.java:220) com.webreach.mirth.plugins.pdfviewer.PDFViewer.viewAttachments(PDFViewer.java:51) com.webreach.mirth.client.ui.browsers.message.MessageBrowser$16.doInBackground(MessageBrowser.java:1429) com.webreach.mirth.client.ui.browsers.message.MessageBrowser$16.doInBackground(MessageBrowser.java:1426) org.jdesktop.swingworker.SwingWorker$1.call(SwingWorker.java:276) java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:303) java.util.concurrent.FutureTask.run(FutureTask.java:138) org.jdesktop.swingworker.SwingWorker.run(SwingWorker.java:315) java.util.concurrent.ThreadPoolExecutor$Worker.runTask(ThreadPoolExecutor.java:886) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:908) java.lang.Thread.run(Thread.java:637)

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  • Confusion testing fftw3 - poisson equation 2d test

    - by user3699736
    I am having trouble explaining/understanding the following phenomenon: To test fftw3 i am using the 2d poisson test case: laplacian(f(x,y)) = - g(x,y) with periodic boundary conditions. After applying the fourier transform to the equation we obtain : F(kx,ky) = G(kx,ky) /(kx² + ky²) (1) if i take g(x,y) = sin (x) + sin(y) , (x,y) \in [0,2 \pi] i have immediately f(x,y) = g(x,y) which is what i am trying to obtain with the fft : i compute G from g with a forward Fourier transform From this i can compute the Fourier transform of f with (1). Finally, i compute f with the backward Fourier transform (without forgetting to normalize by 1/(nx*ny)). In practice, the results are pretty bad? (For instance, the amplitude for N = 256 is twice the amplitude obtained with N = 512) Even worse, if i try g(x,y) = sin(x)*sin(y) , the curve has not even the same form of the solution. (note that i must change the equation; i divide by two the laplacian in this case : (1) becomes F(kx,ky) = 2*G(kx,ky)/(kx²+ky²) Here is the code: /* * fftw test -- double precision */ #include <iostream> #include <stdio.h> #include <stdlib.h> #include <math.h> #include <fftw3.h> using namespace std; int main() { int N = 128; int i, j ; double pi = 3.14159265359; double *X, *Y ; X = (double*) malloc(N*sizeof(double)); Y = (double*) malloc(N*sizeof(double)); fftw_complex *out1, *in2, *out2, *in1; fftw_plan p1, p2; double L = 2.*pi; double dx = L/((N - 1)*1.0); in1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); in2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); p1 = fftw_plan_dft_2d(N, N, in1, out1, FFTW_FORWARD,FFTW_MEASURE ); p2 = fftw_plan_dft_2d(N, N, in2, out2, FFTW_BACKWARD,FFTW_MEASURE); for(i = 0; i < N; i++){ X[i] = -pi + (i*1.0)*2.*pi/((N - 1)*1.0) ; for(j = 0; j < N; j++){ Y[j] = -pi + (j*1.0)*2.*pi/((N - 1)*1.0) ; in1[i*N + j][0] = sin(X[i]) + sin(Y[j]) ; // row major ordering //in1[i*N + j][0] = sin(X[i]) * sin(Y[j]) ; // 2nd test case in1[i*N + j][1] = 0 ; } } fftw_execute(p1); // FFT forward for ( i = 0; i < N; i++){ // f = g / ( kx² + ky² ) for( j = 0; j < N; j++){ in2[i*N + j][0] = out1[i*N + j][0]/ (i*i+j*j+1e-16); in2[i*N + j][1] = out1[i*N + j][1]/ (i*i+j*j+1e-16); //in2[i*N + j][0] = 2*out1[i*N + j][0]/ (i*i+j*j+1e-16); // 2nd test case //in2[i*N + j][1] = 2*out1[i*N + j][1]/ (i*i+j*j+1e-16); } } fftw_execute(p2); //FFT backward // checking the results computed double erl1 = 0.; for ( i = 0; i < N; i++) { for( j = 0; j < N; j++){ erl1 += fabs( in1[i*N + j][0] - out2[i*N + j][0]/N/N )*dx*dx; cout<< i <<" "<< j<<" "<< sin(X[i])+sin(Y[j])<<" "<< out2[i*N+j][0]/N/N <<" "<< endl; // > output } } cout<< erl1 << endl ; // L1 error fftw_destroy_plan(p1); fftw_destroy_plan(p2); fftw_free(out1); fftw_free(out2); fftw_free(in1); fftw_free(in2); return 0; } I can't find any (more) mistakes in my code (i installed the fftw3 library last week) and i don't see a problem with the maths either but i don't think it's the fft's fault. Hence my predicament. I am all out of ideas and all out of google as well. Any help solving this puzzle would be greatly appreciated. note : compiling : g++ test.cpp -lfftw3 -lm executing : ./a.out output and i use gnuplot in order to plot the curves : (in gnuplot ) splot "output" u 1:2:4 ( for the computed solution )

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  • iPhone current user location coordinates showing as (0,0)

    - by ennuikiller
    I'm trying to get the users current latitude and longitude with this viewDidLoad method. The resulting map is correctly indicating the current location however the NSLog consistently shows: 2009-09-19 16:45:29.765 Mapper[671:207] user latitude = 0.000000 2009-09-19 16:45:29.772 Mapper[671:207] user longitude = 0.000000 Anyone know what I am missing here? Thanks in advance for your help! - (void)viewDidLoad { [super viewDidLoad]; [mapView setMapType:MKMapTypeStandard]; [mapView setZoomEnabled:YES]; [mapView setScrollEnabled:YES]; [mapView setShowsUserLocation:YES]; CLLocation *userLoc = mapView.userLocation.location; CLLocationCoordinate2D userCoordinate = userLoc.coordinate; NSLog(@"user latitude = %f",userCoordinate.latitude); NSLog(@"user longitude = %f",userCoordinate.longitude); }

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  • Get the number of calendar weeks between 2 dates in C#

    - by Phil Scholtes
    For the purposes of this question, let's assume the user will be from the US and will use the standard Gregorian calendar. So, a calendar week starts on Sunday and ends on Saturday. What I'm trying to do is determine the number of calendar weeks that exist between two dates. A perfect example of my problem exists in October 2010. Between 10/16 and 10/31 there are 4 calendar weeks. View a picture of October 2010 October 10 - October 16 October 17 - October 23 October 24 - October 30 October 31 - November 6 I'd prefer to stay away from any hardcoded logic like: if (Day == DayOfWeek.Saturday && LastDayOfMonth == 31) { ... } Can anyone think of a logical way to do this?

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  • How to see a branch created in master

    - by richard
    Hi, I create a branch in my master repository (192.168.1.2). And in my other computer, I did '$ git pull --rebase ', I see Unpacking objects: 100% (16/16), done. From git+ssh://[email protected]/media/LINUXDATA/mozilla-1.9.1 62d004e..b291703 master -> origin/master * [new branch] improv -> origin/improv But when I do a 'git branch' in my local repository, I see only 1 branch and I did '$ git checkout improv ' $ git branch * master $ git checkout improv error: pathspec 'improv' did not match any file(s) known to git. Did you forget to 'git add'?

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  • How to set that compiler flag?

    - by mystify
    Shark told me this: This instruction is the start of a loop that is not aligned to a 16-byte address boundary. For optimal performance, you should align the start of a hot loop using a compiler directive. With gcc 3.3 or later, use the -falign-loops=16 compiler flag. for (int i=0; i < 4; i++) { // line with the info //...code } How would I set that flag, and does it really improve performance?

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  • mysql alter to table

    - by user485783
    Hi, I drop the mysql alter code below to database via phpmyadmin one by one, it it work fine, is there anyone could help me how to drop it all together at once? or do you know the the samples of php code that may execute it? just let me know please. thanks in advace ALTER TABLE user ADD title varchar(16) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER user_id ALTER TABLE customer ADD title varchar(16) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER customer_id ALTER TABLE customer ADD date_birtdate datetime NOT NULL DEFAULT '0000-00-00 00:00:00' AFTER lastname ALTER TABLE customer ADD security_question varchar(96) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER fax ALTER TABLE customer ADD security_answer varchar(96) COLLATE utf8_bin NOT NULL DEFAULT '' AFTER fax ALTER TABLE customer ADD pin_number text COLLATE utf8_bin AFTER password ALTER TABLE customer ADD notes text COLLATE utf8_bin AFTER bank_number ALTER TABLE customer ADD last_active datetime NOT NULL DEFAULT '0000-00-00 00:00:00' AFTER date_added

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  • How do I check the validity of the Canadian Social Insurance Number in C#?

    - by user518307
    I've been given the assignment to write an algorithm in C# that checks the validity of a Canadian Social Insurance Number (SIN). Here are the steps to validate a SIN. Given an example Number: 123 456 782 Remove the check digit (the last digit): 123456782 Extract the even digits (2,4,6,8th digith): 12345678 Double them: 2 4 6 8 | | | | v v v v 4 8 12 16 Add the digits together: 4+8+1+2+1+6 = 22 Add the Odd placed digits: 1+3+5+7 = 16 Total : 38 Validity Algorithm If the total is a multiple of 10, the check digit should be zero. Otherwise, Subtract the Total from the next highest multiple of 10 (40 in this case) The check digit for this SIN must be equal to the difference of the number and the totals from earlier (in this case, 40-38 = 2; check digit is 2, so the number is valid) I'm lost on how to actually implement this in C#, how do I do this?

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  • Calculate hours difference in datetime

    - by ScG
    I have a series of datetime values. I want to select records with a difference of 2 or more hours between them. 2010-02-11 08:55:00.000 2010-02-11 10:45:00.000 2010-02-11 10:55:00.000 2010-02-11 12:55:00.000 2010-02-11 14:52:00.000 2010-02-11 16:55:00.000 2010-02-11 17:55:00.000 2010-02-11 23:55:00.000 2010-02-12 00:55:00.000 2010-02-12 02:55:00.000 Expected (The next date compared is with the last date that qualified for the 2 hr difference): 2010-02-11 08:55:00.000 2010-02-11 10:55:00.000 2010-02-11 12:55:00.000 2010-02-11 16:55:00.000 2010-02-11 23:55:00.000 2010-02-12 02:55:00.000 I am using SQL 2005 or 2008

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  • What's wrong in this iban validation code?

    - by Jackoder
    Hello coders, I'm working on a php iban validator but i have a problem I wrote like this: function IbanValidator($value) { $iban = false; $value= strtoupper(trim($value)); # Change US text into your country code if(preg_match('/^US\d{7}0[A-Z0-9]{16}$/', $value)) { $number= substr($value,4,22).'2927'.substr($value,2,2); $number= str_replace( array('A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'), array(10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35), $number ); $iban = (1 == bcmod($number,97)) ? true; } return $iban; } Thanks.

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  • How to find the Mac address of a 'shutdown' system on local lan (is it possible?)

    - by pirates-iiita
    hello everyone, Can anyone please tell the way to find out the mac address of a system which is: Shutdown Power plugged in Connected to Lan Nic card ON. Kindly post the solution as i urgently need it in my project... thank you Update I am asking how to find out the mac address of some other system which is already shutdown.... and which is on lan.. I want to find out its mac from my system.... and to be clear... i want to tell that.. arp table can be populated by using ping .. i.e. if 172.16.3.12 is not in arp table then it can be added by just ping 172.16.3.12 but a system can be pinged only if its on ... a shutdown system can't be pinged...

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  • Link to another file in chrome extension

    - by Hintswen
    I want to have a link in the popup.html file for my extension that loads another file (which will be included with the extension) how can I do this? or will I need to keep it in the same page? I tried using this code: <a href="/mail.html"> <img id="newmail_icon" src="" width="16" height="16" /> <span id="newmail">loading</span><br /> </a> But when I click the link nothing happens. I just found out that adding target="_blank" to the link will make it work and open in a new tab, but I can't get it to open in the popup. I have tried target="_self" but it didn't do anything.

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  • script to convert css sheet from px to em

    - by Sy Moen
    Anyone know of a script (php, python, perl, bash, whatever) that will convert a stylesheet from px to em? Like, it would take input of the filename and base font-size (default 16) and convert all px instances to em? eg: convertpx2ems --file stylesheet.css --base-font-size 16 would convert this: button { font-size:14px; padding:8px 19px 9px; } to something like this: button { font-size: .875em; padding: .5em 1.188em .563em; } ...maybe, is there a way to do this with sass?

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  • Scrollbar still is painted after it should be removed

    - by Walter Williams
    I have the following custom control and can place on a form (with AutoScroll set to true and the control anchored left, top and right). If the form is too short for the control, the form correctly resizes the control (to make room for the scroll) and displays the scroll bar. When the control is closed using the close glyph, the control is resized and the scroll bar is removed, but occasionally the scroll bar appears to remain painted. If the form is minimized or moved off-screen, the leftover paint is removed. I've tried Parent.Invalidate and have toyed with it in many ways but to no avail. Any suggestions? (Using VS 2008 Standard) using System; using System.ComponentModel; using System.Drawing; using System.Drawing.Drawing2D; using System.Windows.Forms; namespace GroupPanelTest { public class GroupPanel : GroupBox { #region Members private const Int32 iHeaderHeight = 20; private Int32 iFullHeight = 200; private Boolean bClosed = false; private Rectangle rectCloseGlyphBounds = Rectangle.Empty; private Boolean bIsMoveOverCloseGlyph = false; #endregion #region Properties [DefaultValue(false)] public Boolean Closed { get { return (this.bClosed); } set { if (this.bClosed != value) { this.bClosed = value; if (this.bClosed) { this.iFullHeight = base.Height; base.Height = GroupPanel.iHeaderHeight; } else { base.Height = this.iFullHeight; } foreach (Control con in base.Controls) con.Visible = !this.bClosed; this.Invalidate(); } } } public new Int32 Height { get { return (base.Height); } set { if (value != base.Height) { if (this.Closed) { this.iFullHeight = value; } else { Int32 iOldHeight = base.Height; base.Height = value; } } } } [DefaultValue(typeof(Size), "350,200")] public new Size Size { get { return (base.Size); } set { if (base.Size != value) { base.Size = value; if (!this.Closed) this.iFullHeight = value.Height; } } } [DefaultValue(typeof(Padding), "0,7,0,0")] public new Padding Padding { get { return (base.Padding); } set { base.Padding = value; } } #endregion #region Construction public GroupPanel () { SetStyle(ControlStyles.UserPaint, true); SetStyle(ControlStyles.ResizeRedraw, true); SetStyle(ControlStyles.AllPaintingInWmPaint, true); SetStyle(ControlStyles.OptimizedDoubleBuffer, true); SetStyle(ControlStyles.Selectable, true); this.Size = new Size(350, 200); this.Padding = new Padding(0, 7, 0, 0); // the groupbox will add to that this.rectCloseGlyphBounds = new Rectangle(base.ClientSize.Width - 24, 2, 16, 16); } #endregion #region Overrides protected override void OnSizeChanged (EventArgs e) { this.rectCloseGlyphBounds = new Rectangle(base.ClientSize.Width - 24, 2, 16, 16); base.OnSizeChanged(e); } protected override void OnPaint (PaintEventArgs e) { base.OnPaint(e); // we want all the delegates to receive the events, but we do this first so we can paint over it Graphics g = e.Graphics; g.FillRectangle(SystemBrushes.Window, this.ClientRectangle); Rectangle rectTitle = new Rectangle(0, 0, this.ClientRectangle.Width, GroupPanel.iHeaderHeight); g.FillRectangle(SystemBrushes.Control, rectTitle); g.DrawString(this.Text, this.Font, SystemBrushes.ControlText, new PointF(5.0f, 3.0f)); if (this.bIsMoveOverCloseGlyph) { g.FillRectangle(SystemBrushes.ButtonHighlight, this.rectCloseGlyphBounds); Rectangle rectBorder = this.rectCloseGlyphBounds; rectBorder.Inflate(-1, -1); g.DrawRectangle(SystemPens.Highlight, rectBorder); } using (Pen pen = new Pen(SystemColors.ControlText, 1.6f)) { if (this.Closed) { g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 3, this.rectCloseGlyphBounds.Top + 3, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 8); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 13, this.rectCloseGlyphBounds.Top + 3, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 8); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 3, this.rectCloseGlyphBounds.Top + 7, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 12); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 13, this.rectCloseGlyphBounds.Top + 7, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 12); } else { g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 3, this.rectCloseGlyphBounds.Top + 8, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 3); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 13, this.rectCloseGlyphBounds.Top + 8, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 3); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 3, this.rectCloseGlyphBounds.Top + 12, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 7); g.DrawLine(pen, this.rectCloseGlyphBounds.Left + 13, this.rectCloseGlyphBounds.Top + 12, this.rectCloseGlyphBounds.Left + 8, this.rectCloseGlyphBounds.Top + 7); } } } protected override void OnMouseDown (MouseEventArgs e) { if (e.Button == MouseButtons.Left && this.rectCloseGlyphBounds.Contains(e.Location)) this.Closed = !this.Closed; // close will call invalidate base.OnMouseDown(e); } protected override void OnMouseMove (MouseEventArgs e) { this.bIsMoveOverCloseGlyph = this.rectCloseGlyphBounds.Contains(e.Location); this.Invalidate(this.rectCloseGlyphBounds); base.OnMouseMove(e); } #endregion } }

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  • Is Eclipse Remote System Explorer broken on Windows?

    - by Kev
    I have the following setup on Windows 7 Ultimate x64: Eclipse Indigo 2.7.2 (Build: M20120208-0800) Remote System Explorer 3.3.2 (see screenshot) (Oracle/Sun) Java 1.6 Update 31 (x86) Despite all my best efforts I am unable to connect to a remote system (a Centos 5.6 server on my local LAN) using a Remote System Explorer SSH connection - I've tried both password authentication and using my SSH private key. Here is a screenshot of both the Eclipse error dialogue and what is logged in my /var/log/secure log file: /var/log/secure: Apr 1 12:00:21 nagios sshd[6176]: Received disconnect from 172.16.3.88: 3: com.jcraft.jsch.JSchException: Auth fail When I connect for the first time I do get prompted to verify the authenticity of the remote host and the RSA key fingerprint. But that's as far as things go. Performing the same operation with the same credentials on my Fedora Core 16 box (also running the same version of Eclipse and Java) to the same server is successful. This leads me to believe that RSE SSH support on Windows is either broken or there's some piece of the SSH-on-Windows puzzle I'm missing. Is this the case?

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  • Generating short license keys with OpenSSL

    - by Marc Charbonneau
    I'm working on a new licensing scheme for my software, based on OpenSSL public / private key encryption. My past approach, based on this article, was to use a large private key size and encrypt an SHA1 hashed string, which I sent to the customer as a license file (the base64 encoded hash is about a paragraph in length). I know someone could still easily crack my application, but it prevented someone from making a key generator, which I think would hurt more in the long run. For various reasons I want to move away from license files and simply email a 16 character base32 string the customer can type into the application. Even using small private keys (which I understand are trivial to crack), it's hard to get the encrypted hash this small. Would there be any benefit to using the same strategy to generated an encrypted hash, but simply using the first 16 characters as a license key? If not, is there a better alternative that will create keys in the format I want?

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  • Isn't the C++ standard library backward-compatible?

    - by Chris Metzler
    Hi. I'm working on a 64-bit Linux system, trying to build some code that depends on third-party libraries for which I have binaries. During linking, I get a stream of undefined reference errors for one of the libraries, indicating that the linker couldn't resolve references to standard C++ functions/classes, e.g.: librxio.a(EphReader.o): In function `gpstk::EphReader::read_fic_data(std::basic_string<char, std::char_traits<char>, std::allocator<char> > const&)': EphReader.cpp:(.text+0x27c): undefined reference to `std::basic_ostream<char, std::char_traits<char> >& std::__ostream_insert<char, std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*, long)' EphReader.cpp:(.text+0x4e8): undefined reference to `std::basic_ostream<char, std::char_traits<char> >& std::__ostream_insert<char, std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*, long)' I'm not really a C++ programmer, but this looks to me like it can't find the standard library. Doing some more research, I got the following when I looked at librxio's dependency for the standard library: $ ldd librxio.so.16.0 ./librxio.so.16.0: /usr/lib64/libstdc++.so.6: version `GLIBCXX_3.4.9' not found (required by ./librxio.so.16.0) libm.so.6 => /lib64/libm.so.6 (0x00002aaaaad45000) libstdc++.so.6 => /usr/lib64/libstdc++.so.6 (0x00002aaaaafc8000) libgcc_s.so.1 => /lib64/libgcc_s.so.1 (0x00002aaaab2c8000) libc.so.6 => /lib64/libc.so.6 (0x00002aaaab4d7000) /lib64/ld-linux-x86-64.so.2 (0x0000555555554000) So I read that as saying that librxio (one of the third-party libraries) requires at least v3.4.9 of the standard library. But the version I have installed is 4.1.2: $ rpm -qa | grep libstdc compat-libstdc++-33-3.2.3-61.x86_64 libstdc++-devel-4.1.2-14.el5.i386 libstdc++-devel-4.1.2-14.el5.x86_64 libstdc++-4.1.2-14.el5.x86_64 libstdc++-4.1.2-14.el5.i386 Shouldn't this work? The shared object major number is 6, same as for v3.4.9. At this level, shouldn't this be backward compatible? It seems like the third-party library is looking for an earlier version of the standard library than what I have installed; but isn't there backward compatibility between versions with the same major number for the shared library? Again, I'm not really a C++ programmer; but I don't see what the problem is. Any advice greatly appreciated. Thanks.

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  • accessing pdf via https URL

    - by Paul
    I send out a newsletter email containing URLs to a https website that then redirects to a pdf document. On first invocation of a URL the user is prompted with the typical https browser "security alert" popup, on selecting "Yes" the display of the PDF fails. The HTTP Header on the failed response is: HTTP/1.1 200 OK Server: ECS/HTTP-Server Date: Tue, 16 Mar 2010 15:57:26 GMT Content-type: application/pdf Content-language: en-US Set-cookie: JSESSIONID=0000r111cRz1Vc-PtCJg8Cdu4eR:-1; Path=/ Expires: Thu, 01 Dec 1994 16:00:00 GMT Cache-control: no-cache="set-cookie, set-cookie2" Connection: close Subsequent invocations of the URL successfully opens the PDF (at this point we have the session id cookie set by the initial failed request). The HTTP Header on the successful response is: HTTP/1.1 200 OK Server: ECS/HTTP-Server Date: Tue, 16 Mar 2010 16:53:03 GMT Content-type: application/pdf Content-language: en-US Connection: close The email client is Lotus Notes 6.5 which launches an IE6 browser Any ideas?

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  • pdf file creation in php

    - by pavun_cool
    Actually I have used following code , for creating the simple pdf file . It executed fine in the browsers. But I am not able to get the pdf file . But it gives me some output when I am running the code in CLI . my doubt is , where I need specify pdf file name ( creation file ) . <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

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  • Why won't this SQL CAST work?

    - by Kev
    I have a nvarchar(50) column in a SQL Server 2000 table defined as follows: TaskID nvarchar(50) NULL I need to fill this column with some random SQL Unique Identifiers (I am unable to change the column type to uniqueidentifier). I tried this: UPDATE TaskData SET TaskID = CAST(NEWID() AS nvarchar) but I got the following error: Msg 8115, Level 16, State 2, Line 1 Arithmetic overflow error converting expression to data type nvarchar. I also tried: UPDATE TaskData SET TaskID = CAST(NEWID() AS nvarchar(50)) but then got this error: Msg 8152, Level 16, State 6, Line 1 String or binary data would be truncated. I don't understand why this doesn't work but this does: DECLARE @TaskID nvarchar(50) SET @TaskID = CAST(NEW() AS nvarchar(50)) I also tried CONVERT(nvarchar, NEWID()) and CONVERT(nvarchar(50), NEWID()) but got the same errors.

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  • How to make awkward pivot of sql table in SQL Server 2005?

    - by Oliver
    I have to rotate a given table from an SQL Server but a normal pivot just doesn't work (as far as i tried). So has anybody an idea how to rotate the table into the desired format? Just to make the problem more complicated, the list of given labels can vary and it is possible that a new label name can come into at any given time. Given Data ID | Label | Numerator | Denominator | Ratio ---+-----------------+-------------+---------------+-------- 1 | LabelNameOne | 41 | 10 | 4,1 1 | LabelNameTwo | 0 | 0 | 0 1 | LabelNameThree | 21 | 10 | 2,1 1 | LabelNameFour | 15 | 10 | 1,5 2 | LabelNameOne | 19 | 19 | 1 2 | LabelNameTwo | 0 | 0 | 0 2 | LabelNameThree | 15 | 16 | 0,9375 2 | LabelNameFive | 19 | 19 | 1 2 | LabelNameSix | 17 | 17 | 1 3 | LabelNameOne | 12 | 12 | 1 3 | LabelNameTwo | 0 | 0 | 0 3 | LabelNameThree | 11 | 12 | 0,9167 3 | LabelNameFour | 12 | 12 | 1 3 | LabelNameSix | 0 | 1 | 0 Wanted result ID | ValueType | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix ---+-------------+--------------+--------------+----------------+---------------+---------------+-------------- 1 | Numerator | 41 | 0 | 21 | 15 | | 1 | Denominator | 10 | 0 | 10 | 10 | | 1 | Ratio | 4,1 | 0 | 2,1 | 1,5 | | 2 | Numerator | 19 | 0 | 15 | | 19 | 17 2 | Denominator | 19 | 0 | 16 | | 19 | 17 2 | Ratio | 1 | 0 | 0,9375 | | 1 | 1 3 | Numerator | 12 | 0 | 11 | 12 | | 0 3 | Denominator | 12 | 0 | 12 | 12 | | 1 3 | Ratio | 1 | 0 | 0,9167 | 1 | | 0

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