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  • How can I edit my httpd.conf file?

    - by EmmyS
    I have xampp installed, and need to edit my httpd.conf file to add a virtual host block. If I right-click on the file in Nautilus and open with gedit, I can see all the content, but it's read-only. If I try to open it via terminal, like this: esther@estherLinuxSony:~$ sudo gedit opt/lampp/etc/extra/httpd-vhosts.conf It opens the root version of gedit, but there's no content in the file. How can I edit this file?

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  • Lot of "file not found" when using sudo find / -type s

    - by Andrea Moro
    In the attempt to understand why I keep getting the following error error: 'Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2)' while using the command sudo find / -type s the terminal prompted something like this find: ‘/proc/31348/task/31348/fd/5’: No such file or directory find: ‘/proc/31348/task/31348/fdinfo/5’: No such file or directory find: ‘/proc/31348/fd/5’: No such file or directory find: ‘/proc/31348/fdinfo/5’: No such file or directory What does this mean?

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  • How to identify doc, ppt, xls files

    - by Shelby. S
    So I was wondering how would you differentiate ppt, xls and doc files from each other in linux regardless of extensions. I tried 'file' but from the looks of it, all of MSOffice files are categorized under the same file type. Similarly I'm having trouble with docx, xlsx and pptx files, since they're essentially all zip files containing a bunch of xml. Thank you for your help! P.S. I also tried a python script importing the magic module, but no go.

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  • How does tomcat set its executable file as a windows service?

    - by Wing C. Chen
    Firstly, I am not at all familiar with windows batch file programing. Recently I am curious about how tomcat sets itself as a windows service using a batch file. I downloaded the service.bat file from tomcat 6. However, I still don't understand some part of it. I guess this is the line that the batch actually register the exe file to the OS, is it right? Is there any syntax explanation? "%EXECUTABLE%" //IS//%SERVICE_NAME% --StartClass org.apache.catalina.startup.Bootstrap --StopClass org.apache.catalina.startup.Bootstrap --StartParams start --StopParams stop And is this used to remove the service? "%EXECUTABLE%" //DS//%SERVICE_NAME% And this is the setting of the parameters? "%EXECUTABLE%" //US//%SERVICE_NAME% --JvmOptions "-Dcatalina.base=%CATALINA_BASE%;-Dcatalina.home=%CATALINA_HOME%;-Djava.endorsed.dirs=%CATALINA_HOME%\endorsed" --StartMode jvm --StopMode jvm Thanks.

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  • Easy way to lock a file on a remote machine (windows)?

    - by roufamatic
    I've tracked down an error in my logs, and am trying to reproduce it. My theory is that a file sometimes gets locked in a specific folder, and when the application (ASP.NET) tries to delete that folder it hangs. I don't have the application running on my own machine so I'm debugging this on a remote server. But for the life of me, I can't seem to figure out a way to lock a file that prevents it from being deleted by the process. My first thought was to map the network path to a local drive and just leave a command prompt open to that folder. Locally that always fouls up my folder deletes, but apparently SMB is a bit more robust and doesn't grant me a lock. After that I created an infinte loop vbscript in the folder and executed it remotely. The file was deleted out from underneath the executing code. Man! I then tried creating a file on the server in that folder and removing all permissions. That didn't do the trick. I don't have access to the IIS settings so perhaps it's running under a privileged system account. So: what's a program that you know is free and I can quickly use to create an exclusive lock on a file so I can test my delete theory? Like a really, really bad Notepad clone or something. :-)

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  • http_post() variables to php script from SMS message but only append data to text file if certain variable (telephone number) equals a known

    - by user1592162
    All, I have an SMS gateway application running on my server that passes incoming SMS messages to a php script. That script writes the data to a text file. Certain aspects of the message can be extracted as variables - for example: Message content: $msgdata Sender: $originator Time: $receivedtime etc... Using the script below I can easily write the message to a text file but it will write the data of every SMS that comes in. I only want to write to a text file if the $originator variable is a certain telephone number (e.g 07123456321) $date = date("d.m.Y H:i:s"); $msgdata = $_REQUEST["msgdata"]; $myFile3 = "test.txt"; $fh = fopen($myFile3, 'a') or die("can't open file"); $stringData3 = "$date - $msgdata\n"; fwrite($fh, $stringData3); fclose($fh); Your assistance is bery much appreciated. Many thanks in advance.

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  • Java- FileWriter/BufferedWriter - appending to end of a text file?

    - by KP65
    I've done this before once, I'm trying to replicate what I did so far and this is what I've got: try { BufferedWriter writer = new BufferedWriter(new FileWriter("file.P", true)); System.out.println("entered"); if (!(newUserName.isEmpty()) || (newUserPass.isEmpty())){ writer.newLine(); writer.write("hellotest123"); writer.close(); } It seems to find file.P, which is just a txt file, but it doesn't seem to append anything onto it? It enters the code and passes the IF statement fine, but nothing is appended to the text file? I'm slightly stuck!

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  • C# - retrieve file path from config file - @ doesn't do it's magic

    - by Bart
    Hi guys, I'm currently working on a web service that retrieves an XML message, archives it and then processes it further. The archive folder is read from the Web.config. This is what the archive method looks like private void Archive(System.Xml.XmlDocument xmlDocument) { try { string directory = System.Configuration.ConfigurationManager.AppSettings.Get("ArchivePath"); ParseMessage(xmlDocument); directory = string.Format(@"{0}\{1}\{2}", @directory, _senderService, DateTime.Now.ToString("MMMyyyy")); System.IO.Directory.CreateDirectory(directory); string Id = _messageID; string senderService = _senderService; xmlDocument.Save(directory + @"\" + DateTime.Now.ToString("yyyyMMdd_") + Id + "_" + System.Guid.NewGuid().ToString().Substring(0, 13) + ".xml"); } The path structure I retrieve is C:\Program Files\Subfolder\Subfolder. In the development, QA, UAT and PRD environments everything works fine. But on another machine I now need to install the web service on (which I cannot debug, unfortunately), the directory string is 'C:Files'. Just to be sure I double checked the .NET version on the different machines (I thought perhaps the usage of @ before a string was version-dependent); all machines use 2.0.50727. Does anyone recognize this problem? Thanks in advance!

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  • How to know the next temp file to be created in windows?

    - by Mike
    I am by no means a programmer but currently am wondering if an application creates a temp file that windows names. For example the file it creates is tmp001, is there a way i can take that name tmp001 and ask windows to give me the next temp file it would create before it creates it. Thanks, Mike

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  • Is there any way to "peek" at a file while it's uploading through HTTP onto a Windows box?

    - by iisystems
    I need to add a file upload function to an ASP.NET website and would like to be able to read a small portion of the file on the server while it's still uploading. A peek or preview type function so I can determine contents and give some feedback to the user while it is still uploading (we're talking about large files here). Is there any way to do this? I'm thinking worst case of writing a custom control which uploads only a fixed number of bytes of the file once chosen and then under the covers starts another upload of the full file. Not totally sure even this is possible, but I'm looking for a more elegant solution anyway... Thanks!

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  • How to load an ImageView from a png file?

    - by Peter vdL
    I take a picture with the camera using Intent intent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE ); startActivityForResult( intent, 22 ); When the activity completes, I write the bitmap picture out to a PNG file. java.io.FileOutputStream out = openFileOutput("myfile.png", Context.MODE_PRIVATE); bmp.compress(Bitmap.CompressFormat.PNG, 90, out); That goes OK, and I can see the file is created in my app private data space. I'm having difficulty when I later want to display that image using an ImageView. Can anyone suggest code to do this? If I try to create a File with path separators in, it fails. If I try to create a Uri from a name without separators, that fails. I can open the file OK using: java.io.FileInputStream in = openFileInput("myfile.png"); But that doesn't give me the Uri I need to set an image with iv.setImageURI(u) Summary: I have the picture in a png file in private app data. What's the code to set that into an ImageView? Thanks.

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  • How can I asynchronously monitor a file in Perl?

    - by Hussain
    I am wondering if it is possible, and if so how, one could create a perl script that constantly monitors a file/db, and then call a subroutine to perform text processing if the file is changed. I'm pretty sure this would be possible using sockets, but this needs to be used for a webchat application on a site running on a shared host, and I'm not so sure sockets would be allowed on it. The basic idea is: create a listener for a chat file/database when the file is updated with a new message, call a subroutine the called subroutine will send the new message back to the browser to be displayed Thanks in advance.

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  • Difficulty determining the file type of text database file

    - by Joseph Silvashy
    So the USDA has some weird database of general nutrition facts about food, and well naturally we're going to steal it for use in our app. But anyhow the format of the lines is like the following: ~01001~^~0100~^~Butter, salted~^~BUTTER,WITH SALT~^~~^~~^~Y~^~~^0^~~^6.38^4.27^8.79^3.87 ~01002~^~0100~^~Butter, whipped, with salt~^~BUTTER,WHIPPED,WITH SALT~^~~^~~^~Y~^~~^0^~~^6.38^4.27^8.79^3.87 ~01003~^~0100~^~Butter oil, anhydrous~^~BUTTER OIL,ANHYDROUS~^~~^~~^~Y~^~~^0^~~^6.38^4.27^8.79^3.87 ~01004~^~0100~^~Cheese, blue~^~CHEESE,BLUE~^~~^~~^~Y~^~~^0^~~^6.38^4.27^8.79^3.87 With those odd ~ and ^ separating the values, It also lacks a header row but thats ok, I can figure that out from the other stuff on their site: http://www.ars.usda.gov/Services/docs.htm?docid=8964 Any help would be great! If it matters we're making an open/free API with Ruby to query this data. Additionally I'm having a tough time posing this question so I've made it a community wiki so we can all pitch in!

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  • Which is better: many class definitions in the same file or every class definition in a separate file?

    - by Javed Akram
    Which is better: many class definitions in same file or every class definition in separate file? Examples: 1) Many classes in same file. Say, myManyClasses.cs: namespace myPack { class myClass1() { } class myClass2() { } class myClass3() { } . . . } 2) Every class in separate file: myClass1.cs namespace myPack { class myClass1() { } } myClass2.cs namespace myPack { class myClass2() { } } . . .

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  • Php efficiency question --> Database call vs. File Write vs. Calling C++ executable

    - by JP19
    Hi, What I wish to achieve is - log all information about each and every visit to every page ofmy website (like ip address, browser, referring page, etc). Now this is easy to do. What I am interested is doing this in a way so as to cause minimum overhead (runtime) in the php scripts. What is the best approach for this efficiency-wise: 1) Log all information to a database table 2) Write to a file (from php directly) 3) Call a C++ executable, that will write this info to a file in parallel [so the script can continue execution without waiting for the file write to occur ...... is this even possible] I may be trying to optimize unnecessarily/prematurely, but still - any thoughts / ideas on this would be appreciated. (I think efficiency of file write/logging can really be a concern if I have say 100 visits per minute...) Thanks & Regards, JP

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • How to check for a dynamically created file in Java?

    - by Moev4
    I have an application where I need to check for a file which may be created dynamically during my execution, I will give up after some MAX time where the file has yet to show up. I wanted to know if there was a more efficient method in Java of checking for the file other than polling for it and then sleeping every X seconds? If not what would be the most efficient manner of doing this?

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  • invalid file name in matlab when using file split

    - by klijo
    here jj will be the value of FN, but the trouble is iam getting a error message ??? Error using == fopen Invalid filename. DirName = 'Samples\mattest\jj'; FileName = split('\\',DirName); [a,b] = size(FileName); FN = FileName(b); file_1 = fopen(FN,'w'); split method was found at http://www.mathworks.com/matlabcentral/fileexchange/4873 Doesnt the code seem correct ? Could someone please help me ?

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  • Apache and linux file permissions can't browse file or directories

    - by dardub
    I just copied my magento site over to a local server running CentOS 5.4. The browser said it can't locate the location of the stylesheets. The stylesheets are within /skin/frontend/my_new_interface/design2/css. I tried to view in the browser and I can't view any of the files within the css directory. I verified a million times that I'm typing in the correct location. I can view files within /skin/frontend/my_new_interface/design2. Can't browse directories within browser however. I typed in ls -l css and get: -rwxr-xr-x 1 apache apache listed for all the files I tried chmod -R 755 and the directories I changed the apache conf Options Indexes But still when I browse the directories I get Forbidden. However, in another fresh installation of magento in the same www dir, I am able to browse directories. As far as I can tell both installations have same ownership and permissions. I also tried find . -type f -exec chmod 644 {} \; find . -type d -exec chmod 755 {} \; which was recommended in the magento wiki I've just run out of ideas.

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  • How to read a file line using php in a javascript variable without the breakline character ?

    - by coolboycsaba
    I have a txt file on the server which contains 10 lines of text. The text file is rewritten sometimes, and I get new lines using "\r\n". My problem shows when I want to load the lines in javascript variables. I do it like this, but this work only for numbers or for the last line of the file, because its not using the breakline tag: var x = '<?php echo $file[0]; ?>'; Ive tried to alert(x) but it`s not working.... (working only if I read the last line) Any idead ?

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  • PHP - Open or copy a file when knowing only part of its name?

    - by Gary Willoughby
    I have a huge repository of files that are ordered by numbered folders. In each folder is a file which starts with a unique number then an unknown string of characters. Given the unique number how can i open or copy this file? for example: I have been given the number '7656875' and nothing more. I need to interact with a file called '\server\7656800\7656875 foobar 2x4'. how can i achieve this using PHP?

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