Search Results

Search found 11735 results on 470 pages for 'global variables'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 84/470 | < Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >

  • How to combine a list of choices to determine which select statement

    - by Larry
    I have a mysql db and am using php 5.2 What I am trying to do is offer a list of options for a person to select (only 1). The chosen option will cause a select, update, or delete statement to be ran. The results of the statement do not need to be shown, although, showing the old and then the new would be nice (no problems with that part tho'.). Pseudo-Code: Assign $choice = 0 Check the value of $choice // This way, if it = 100, we do a break Select a Choice:<br> 1. Adjust Status Value (+60) // $choice = 1<br> 2. Show all Ships <br> // $choice = 2 3. Show Ships in Port <br> // $choice = 3 ... 0. $choice="100" // if the value =100, quit this part Use either case (switch) or if/else statements to run the users choice1 If the choice is 1, then run the "Select" statement with the variable of $sql1 -- "SELECT .... If the choice is 2, then run the "Select" statement with the variable of $sql2 --- SELECT * FROM Ships If the choice is 3, then run the "Select" statement with the variable of $sql3 <br> .... If the choice is 0, then we are done. I figured the (3) statements would be assigned in php as: $sql1="...". $sql2="SELECT * FROM Ships" $sql3="SELECT * FROM Ships WHERE nPort="1" My idea was to use the switch statement, but got lost on it. :( I would like the options to be available over and over again, until a variable ($choice) is selected. In which case, this particular page is done and goes back to the "Main Menu"? The coding and display, if I use it, I can do. Just not sure how to write the way to select which one I want. It is possible that I would run all of the queries, and other times, only one, so that is why I would like the choice. An area I get confused in is the proper forms to use such as -- ' ' " " and ...?? Not sure the # of options I will end up with, but it will be more than 5 but less than 20 / page. So if I get the system down for 2-3 choices, I can replicate it for as many as I may need. And, as always, if a better way exists, I am willing to try it. Thanks again... Larry

    Read the article

  • How to change CSS color values in real-time off a javascript slider?

    - by bflora
    I'm making a page where the user gets a javascript slider that goes from 0 to 100 and can use it to set the opacity of a div on the page. I want the opacity of that div to change in real-time as they work the slider. I've not done this before. What's the best approach? There cursor in the slider displays the slider's current value as you move it. It seems to be that I just need to find a way to display that value in any arbitrary other place on the page so I can display it in the style settings for the div. The .js file that generates the slider has a line that (I think) is setting the current value in the cursor: $(this).children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); TO get this changing number to display somewhere else at the same time, do I just need to add a div somewhere and then add a line like this? $("#newDivId").children(".ui-slider-handle", context).html(parseInt(settings[index]['default'])); That seems like it would give me the number showing up in a div. How then would I get it into a form I could put into the style settings for a div? If this was a php variable, I would do something like this, style="opacity:<?php print $value ?>;" What would be the .js equivalent?

    Read the article

  • Variable not implementing correctly from if statement

    - by swiftsly
    I have an if statement that is supposed to set the variable $pc162v to a link specified in the MySQL table if content exists in the $vid column of the row. The problem is, the PHP is detecting that there's a link in the MySQL, but isn't setting the $pc162v variable correctly. Here's the variable declarations: $pc162v = ""; $vid162 = '<embed width="420" height="236" src="'.$pc162v.'" type="application/x-shockwave-flash"></embed>'; Here's the section of the if statement: if (empty($row[7])) { $vid162 = ''; } else { $pc162v = $row[7]; } In my web browsers, the part of the code where the variable $vid162 is used, shows up as the following: <embed width="420" height="236" src="" type="application/x-shockwave-flash"> I have also tried setting $vid162 to: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"></embed> and that just makes the code in my web browser: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"> Hope someone has a solution! Thanks in advance.

    Read the article

  • how can i acess a variable outside of an if statement in java

    - by themanepalli
    i have defined a variable inside an if statement and I am trying to access it outside of that if statement now. now the error is saying that it cannot find the symbol which is because its being defined as an intance variable, is there a way i can change it so i can access it outside the variable? heres the code if((e.getSource()==userOrder2)&& (orderType==1)) { String buyO= userOrder2.getText(); int buyOrder= Integer.parseInt(buyO); //variable im trying to access } // trying to use buyOrder in a different if statement if(orderType==1 && (stockPrice <= buyOrder)) { orderResult.setText("The Stock" + (stockName2.getText()) + "was bought at" + stockPrice); }

    Read the article

  • vb.net session variable passing "space" from one page to another

    - by iuret
    i have 2 aspx webpages with vb.net code. On the first page, I have a text box, on first page that says "Enter Hobby", but its not a required textbox. So if the user clicks submit, it'll load up the second page. Now in the second page i have textbox "hobby" which has maxlength = 10. and in the vb.net code i have hobby.text = session("hobby"). if the user doesnt fill up hobby in first page, the session comes with 10 "spaces" since maxlength is 10. I tried hobby.text = TRIM(session("hobby"), but nothing happens. Any idea how i can lose the spaces if nothing is inputted?

    Read the article

  • I am confused about how to use @SessionAttributes

    - by yusaku
    I am trying to understand architecture of Spring MVC. However, I am completely confused by behavior of @SessionAttributes. Please look at SampleController below , it is handling post method by SuperForm class. In fact, just field of SuperForm class is only binding as I expected. However, After I put @SessionAttributes in Controller, handling method is binding as SubAForm. Can anybody explain me what happened in this binding. ------------------------------------------------------- @Controller @SessionAttributes("form") @RequestMapping(value = "/sample") public class SampleController { @RequestMapping(method = RequestMethod.GET) public String getCreateForm(Model model) { model.addAttribute("form", new SubAForm()); return "sample/input"; } @RequestMapping(method = RequestMethod.POST) public String register(@ModelAttribute("form") SuperForm form, Model model) { return "sample/input"; } } ------------------------------------------------------- public class SuperForm { private Long superId; public Long getSuperId() { return superId; } public void setSuperId(Long superId) { this.superId = superId; } } ------------------------------------------------------- public class SubAForm extends SuperForm { private Long subAId; public Long getSubAId() { return subAId; } public void setSubAId(Long subAId) { this.subAId = subAId; } } ------------------------------------------------------- <form:form modelAttribute="form" method="post"> <fieldset> <legend>SUPER FIELD</legend> <p> SUPER ID:<form:input path="superId" /> </p> </fieldset> <fieldset> <legend>SUB A FIELD</legend> <p> SUB A ID:<form:input path="subAId" /> </p> </fieldset> <p> <input type="submit" value="register" /> </p> </form:form>

    Read the article

  • How do you set a variable to be an empty, but workable Jquery object?

    - by KallDrexx
    Outside of a for I declare a variable using var list;. I use this variable inside of my for loop like so: // add the html to the list if (list == undefined) list = item; else list.append(item.contents()); item is a cloned jquery object build from a $('list_template').clone(); call (list_template is a div with <li> elements inside). What I am doing is creating a list, which I will then appendTo() where I need it. Right now this code works fine, but it doesn't seem right to me. Unfortunatly, I cannot seem to figure out how to correctly declare the list variable to be an empty Jquery object. I have tried both: var list = $([]); var list = $(''); Both of those cause the append to not work correctly (or as expected) with list.html() being null. Is there a way to initialize my variable to an empty jquery object, so all I have to do is list.append(item.contents()); without the if/else statements?

    Read the article

  • variable being weirdly deleted

    - by calccrypto
    im having a weird problem with one variable: its not being recognized but its still printing. i would post my code, but it is massive. the basic idea is: # pseudocode def function(stuff): <do stuff> # These are the only 2 conditions if tag == 3: pka = <a string> if tag == 4: pka = <a string> print pka # (1) print pka # (2) <do stuff not modifying pka> print pka # (3) if pka == 'RSA': <do stuff> elif pka == 'DSA': <do stuff> my code will error at (2). however, it will print out (1), (2), and (3), all of which are the same. is there any general explanation of why this is happening? if my code is really needed, i will post it, but otherwise, i would rather not due to its size update: now the code will error at the if statement after (3), saying UnboundLocalError: local variable 'pka' referenced before assignment even though (1),(2),(3) just printed

    Read the article

  • Selecting multiple cached elements

    - by Globalz
    In jQuery you can select two elements by id like: $('#elem, #elem2'); BUT What if you have cached the elem and elem2, and what to apply the same method/function to them both? i.e. $elem = $('#elem'); $elem2 = $('#elem2'); This obviously wont work: $($elem, $elem2) Thanks!

    Read the article

  • which file stored os.environ,and store where , disk c: or disk d:

    - by zjm1126
    my code is : os.environ['ss']='ssss' print os.environ and it show : {'TMP': 'C:\\DOCUME~1\\ADMINI~1\\LOCALS~1\\Temp', 'COMPUTERNAME': 'PC-200908062210', 'USERDOMAIN': 'PC-200908062210', 'COMMONPROGRAMFILES': 'C:\\Program Files\\Common Files', 'PROCESSOR_IDENTIFIER': 'x86 Family 6 Model 15 Stepping 2, GenuineIntel', 'PROGRAMFILES': 'C:\\Program Files', 'PROCESSOR_REVISION': '0f02', 'SYSTEMROOT': 'C:\\WINDOWS', 'PATH': 'C:\\WINDOWS\\system32;C:\\WINDOWS;C:\\WINDOWS\\System32\\Wbem;C:\\Program Files\\Hewlett-Packard\\IAM\\bin;C:\\Program Files\\Common Files\\Thunder Network\\KanKan\\Codecs;D:\\Program Files\\TortoiseSVN\\bin;d:\\Program Files\\Mercurial\\;D:\\Program Files\\Graphviz2.26.3\\bin;D:\\TDDOWNLOAD\\ok\\gettext\\bin;D:\\Python25;C:\\Program Files\\StormII\\Codec;C:\\Program Files\\StormII;D:\\zjm_code\\;D:\\Python25\\Scripts;D:\\MinGW\\bin;d:\\Program Files\\Google\\google_appengine\\', 'TEMP': 'C:\\DOCUME~1\\ADMINI~1\\LOCALS~1\\Temp', 'BID': '56727834-D5C3-4EBF-BFAA-FA0933E4E721', 'PROCESSOR_ARCHITECTURE': 'x86', 'ALLUSERSPROFILE': 'C:\\Documents and Settings\\All Users', 'SESSIONNAME': 'Console', 'HOMEPATH': '\\Documents and Settings\\Administrator', 'USERNAME': 'Administrator', 'LOGONSERVER': '\\\\PC-200908062210', 'COMSPEC': 'C:\\WINDOWS\\system32\\cmd.exe', 'PATHEXT': '.COM;.EXE;.BAT;.CMD;.VBS;.VBE;.JS;.JSE;.WSF;.WSH', 'CLIENTNAME': 'Console', 'FP_NO_HOST_CHECK': 'NO', 'WINDIR': 'C:\\WINDOWS', 'APPDATA': 'C:\\Documents and Settings\\Administrator\\Application Data', 'HOMEDRIVE': 'C:', 'SS': 'ssss', 'SYSTEMDRIVE': 'C:', 'NUMBER_OF_PROCESSORS': '2', 'PROCESSOR_LEVEL': '6', 'OS': 'Windows_NT', 'USERPROFILE': 'C:\\Documents and Settings\\Administrator'} i find google-app-engine set user_id in os.version not in session,look here at line 96-100 and line 257 , and aeoid at line 177 , and i want to know : which file stored os.environ ,and store where , disk c: ,or disk d: ? thanks

    Read the article

  • how can i request a variable in my home.ctp of my cakePHP application?

    - by Simon
    I created a page using the MVC structure called 'sections' ( view is located in the app/views/sections folder, model in the model folder and the controller in the controller folder) when i request the variable $test, it works fine without any errors.. When i want to request this variable in my home.ctp, it provides me with an error, saying that the variable is undefined.. Is there any way in cakePHP to request this variable on any page you want it to? Thnx in advance!

    Read the article

  • Is an ArrayList automaticaly declared static ,if it is an instance variable?(Java)

    - by Alex
    Hy ,what i`m trying to do is something like this: private class aClass { private ArrayList idProd; aClass(ArrayList prd) { this.idProd=new ArrayList(prd); } public ArrayList getIdProd() { return this.idProd; } } So if i have multiple instances of ArrayLIst (st1 ,st2 ,st3) and I want to make new objects of aClass : { aClass obj1,obj2,obj3; obj1=new aClass(st1); obj2=new aClass(st2); obj3=new aClass(st3); }why all of the aClass objects will return st3 if I access the method getIdProd() for each of them(obj1..obj3)? is an arraylist as a instance variable automatically declared static?

    Read the article

  • Create Session Variable from different datasources?

    - by Szafranamn
    Currently I am developing a dynamic website using Dreamweaver cs5 with ColdFusion 9 and using Access to create my databases along with QuickBooks and QODBC to create database. I have established a login session variable stemming from the login page. This session variable is being drawn from one Datasource "Access" Table "Logininfo" Field "FullName" but I wanted to create another session variable either at this point or further into the member's page to use in a query sequence. This session variable would stem from another Datasoucre "QBs" Table "Invoice" Field "CustomerRefFullName" which is generated through Quickbooks and QODBC. I am not sure if this is possible but if it is how do I do it. I want to do this so I can query the Invoice database to upload the customer's Invoices unique to them onto their page. So it would have to be related to their login credentials. If there is another better route to take I would greatly appreciate the advice. Below is the login code if there is additional information needed let me know. This is my current thinking/plan to do what I wish to intend hence the need to create the session variable: I have another Datasource "QBs" with a Table "Invoice" when I create another webpage for the customer to see their invoice I need to create a recordset that accesses that Table. In order to do so I think the best way would some home convert the session.FullName (which came from Access Datasource, Logininfor Table) into a session.CustomerRefFullName (which would have to come from (Datasource: QBs Table: Invoice Field: CustomerRefFullName) that way I could set the query WHERE CustomerRefFullName and have each logged in user see their specific Invoices. So is there a way to turn the session variable off one datasource/table into a different sessionvariable off a new datasource/table even if it is unique just to that page??? <cfif IsDefined("FORM.username")> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username= AND Password=

    Read the article

  • PHP Classes: parent/child communication

    - by Fffff
    Hi all, I'm having some trouble extending Classes in PHP. Have been Googling for a while. $a = new A(); $a->one(); $a->b1(); // something like this, or... class A { public $test1; public function one() { echo "this is A-one"; $this->two(); $parent->two(); $parent->B->two(); // ...how do i do something like this (prepare it for using in instance $a)? } } class B extends A { public $test2; public function two($test) { echo "this is B-two"; } } I'm ok at procedural PHP.

    Read the article

  • Ruby on Rails- :symbols, @iVars and "strings" - oh my!

    - by Meltemi
    New to Rails and trying to get my head around when/why to use :symbols, @ivars , "strings" within the framework. I think I understand the differences between them conceptually only one :symbol instance per project one @ivar per instance multiple "strings" - as they are created whenever referenced (?) Feel free to correct me! The main confusion comes from understanding the rules & conventions of what Rails expects - where and WHY? I'm sure there's an "Ah ha!" moment coming but I haven't had it yet...as it seems pretty arbitrary to me (coming from C/Obj-C). -thx

    Read the article

  • Make a final call to the Database when user leaves website (ASPX)?

    - by Jisaak
    I have a system set up to lock certain content in a database table so only one user can edit that content at a time. Easy enough and that part is working fine. But now I'm at a road block of how to send a request to "unlock" the content. I have the stored procedure to unlock the content, but how/where would I call it when the user just closes their browser?

    Read the article

  • Rails - undefined method `name' for nil:NilClass

    - by sscirrus
    Hi guys, Quick question. Here is my code: #routes map.resources :customers, :has_many => [:addresses, :matchings] map.connect ":controller/:action/:id" #url path: http://127.0.0.1:3000/customers/index/3 #customers controller def index @customer = Customer.find(params[:id]) end #customers view/index.html.erb ... <%= @customer.name %> ... Error: undefined method `name' for nil:NilClass. Here's my reasoning. The parameter :id is coming from my url path (i.e. we're looking for customer #3 in the above path). @customer should find that array easily, then @customer.name should produce the name, but apparently @customer is blank. Why? I assume the problem is that I'm not producing an array in my controller?

    Read the article

  • How can i set isdigit() command as a variable?

    - by Nick
    I'm new to python but I caught on to the basics pretty quick and decided to start trying to make a program while I'm still learning, since I learn best by actually doing things. So I'm making a program in python that will add polynomials and I need to see if a character from the parser is numeric im using the isdigit() command. Instead of having to type isdigit() all the time in my code such as n.isdigit(), I want to assign it to a variable t = 'isdigit()' and then type n.t. This doesn't work, so is there an alternative to not typing the whole command?

    Read the article

  • Using different numeric variable types

    - by DataPimp
    Im still pretty new so bear with me on this one, my question(s) are not meant to be argumentative or petty but during some reading something struck me as odd. Im under the assumption that when computers were slow and memory was expensive using the correct variable type was much more of a necessity than it is today. Now that memory is a bit easier to come by people seem to have relaxed a bit. For example, you see this sample code everywhere: for (int i = 0; i < length; i++) int? (-2,147,483,648 to 2,147,483,648) for length? Isnt byte (0-255) a better choice? So Im curious of your opinion and what you believe to be best practice, I hate to think this would be used only because the acronym "int" is more intuitive for a beginner...or has memory just become so cheap that we really dont need to concern ourselves with such petty things and therefore we should just use long so we can be sure any other numbers/types(within reason) used can be cast automagically? ...or am Im just being silly by concerning myself with such things?

    Read the article

  • Ajax div can't access address bar variable

    - by Elaine Adams
    Can someone please advise me on how my Ajax div can get an address bar variable. The usual way just doesn't work. My address bar currently looks like this: http://localhost/social3/browse/?locationName=Cambridge Usually, I would use a little php and do this: $searchResult = $_POST['locationName']; echo $searchResult; But because I'm in an Ajax div, I can't seem to get to the variable. Do I need to add some JavaScript wizardry to my Ajax coding? (I have little knowledge of this) My Ajax: <script> window.onload = function () { var everyone = document.getElementById('everyone'), searching = document.getElementById('searching'), searchingSubmit = document.getElementById('searchingSubmit'); everyone.onclick = function() { loadXMLDoc('indexEveryone'); everyone.className = 'filterOptionActive'; searching.className = 'filterOption'; } searching.onclick = function() { loadXMLDoc('indexSearching'); searching.className = 'filterOptionActive'; everyone.className = 'filterOption'; } searchingSubmit.onclick = function() { loadXMLDoc('indexSearchingSubmit'); } function loadXMLDoc(pageName) { var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("leftCont").innerHTML=xmlhttp.responseText; } } function get_query(){ var url = location.href; var qs = url.substring(url.indexOf('?') + 1).split('&'); for(var i = 0, result = {}; i < qs.length; i++){ qs[i] = qs[i].split('='); result[qs[i][0]] = decodeURIComponent(qs[i][1]); } return result; } xmlhttp.open("GET","../browse/" + pageName + ".php?user=" + get_query()['user'],true); xmlhttp.send(); } } </script> <!-- ends ajax script -->

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >