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  • What is the new line marker in an uploaded Word doc?

    - by Donde
    I am attempting to uplaod a Word doc and then write it line by line in HTML. I made a referecne to the Microsoft Word Object Library. Then I use the following code to grab the and put it in a string variable. However, I have tried multiple regex statements to replace the new line character with "" but nothing I have tried has worked... Dim wordApp As New Microsoft.Office.Interop.Word.Application Dim wordDoc As New Microsoft.Office.Interop.Word.Document Dim file As Object = "C:\test.doc" Dim nullobj As Object = System.Reflection.Missing.Value wordDoc = wordApp.Documents.Open(file, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj, nullobj) Dim strArticle As String = wordDoc.Content.Text 'It's not finding the new line marker here strArticle = Regex.Replace(strArticle, ControlChars.NewLine, "<BR>")

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  • All applications quit when printing on imac OS X 10.5.8

    - by Tamany
    I recently ran a software update. I'm not sure if my problems are associated with this but I'm pretty sure they are as I printed successfully before update. I checked the log at time of printing: 03/05/2010 22:03:15 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x17a82b50 03/05/2010 22:03:15 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:17 [0x0-0x51051].com.microsoft.Word[697] Mon May 3 22:03:17 leopards-imac-2.local Word[697] <Error>: The function `CGPDFDocumentGetMediaBox' is obsolete and will be removed in an upcoming update. Unfortunately, this application, or a library it uses, is using this obsolete function, and is thereby contributing to an overall degradation of system performance. Please use `CGPDFPageGetBoxRect' instead. 03/05/2010 22:22:09 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x1b036500 Any thoughts on how to fix this?

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  • All applications quit when printing on imac OS 10.5.8

    - by Tamany
    Hello and hoping someone might be able to help. Recently ran software update (not sure if problems are associated with this but pretty sure they are as i printed successfully before update. checked log at time of printing: any thoughts on how to fix this? THANKYOU!! 03/05/2010 22:03:15 Microsoft Word[697] * -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x17a82b50 03/05/2010 22:03:15 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:17 [0x0-0x51051].com.microsoft.Word[697] Mon May 3 22:03:17 leopards-imac-2.local Word[697] : The function CGPDFDocumentGetMediaBox' is obsolete and will be removed in an upcoming update. Unfortunately, this application, or a library it uses, is using this obsolete function, and is thereby contributing to an overall degradation of system performance. Please useCGPDFPageGetBoxRect' instead. 03/05/2010 22:22:09 Microsoft Word[697] * -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x1b036500

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  • Is there a way to synchronize sections of different Word documents? Alternatives?

    - by David Hodgson
    Hi, I'm working on how my company does documentation (especially programming documentation). I'd like to be able to synchronize sections of different Word documents, such that if a section in one document changes, the change is reflected in the other document, and vice versa. Is there a way to do this with Word, and if not, is there some word processing program that is good at this?

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • All applications quit when printing on Mac OS X 10.5.8

    - by Tamany
    I recently ran a software update. I'm not sure if my problems are associated with this but I'm pretty sure they are as I printed successfully before update. I checked the log at time of printing: 03/05/2010 22:03:15 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x17a82b50 03/05/2010 22:03:15 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:16 [0x0-0x51051].com.microsoft.Word[697] Ignoring Quickdraw drawing between QDBeginCGContext and QDEndCGContext 03/05/2010 22:03:17 [0x0-0x51051].com.microsoft.Word[697] Mon May 3 22:03:17 leopards-imac-2.local Word[697] <Error>: The function `CGPDFDocumentGetMediaBox' is obsolete and will be removed in an upcoming update. Unfortunately, this application, or a library it uses, is using this obsolete function, and is thereby contributing to an overall degradation of system performance. Please use `CGPDFPageGetBoxRect' instead. 03/05/2010 22:22:09 Microsoft Word[697] *** -[NSCFString _getValue:forType:]: unrecognized selector sent to instance 0x1b036500 Any thoughts on how to fix this?

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  • In Java, how do you parse through a single word string?

    - by Fraz
    I'm trying to parse though a string made up of a single word. How would you go about assigning the last letter of the word to a variable? I was thinking of using the Scanner class to parse the word and make each letter an element in an array but it seems Scanner.next() only goes through whole words and not the individual letters. Any help?

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  • How to load MS Word document in C# (.NET)?

    - by Skuta
    Hi, How do I load MS Word document (.doc and .docx) to memory (variable) without doing this?: wordApp.Documents.Open I don't want to open MS Word, I just want that text inside. You gave me answer for DOCX, but what about DOC? I want free and high performance solution - not to open 12.000 instances of Word to process all of them. :( Aspose is commercial product, and 900$ is a way too much for what I do.

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  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

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  • [AS 3.0] How to use the string.match method to find multiple occurrences of the same word in a strin

    - by Steven
    In Actionscript and Adobe Flex, I'm using a pattern and regexp (with the global flag) with the string.match method and it works how I'd like except when the match returns multiple occurrences of the same word in the text. In that case, all the matches for that word point only to the index for the first occurrence of that word. For example, if the text is "cat dog cat cat cow" and the pattern is a search for cat*, the match method returns an array of three occurrences of "cat", however, they all point to only the index of the first occurrence of cat when i use indexOf on a loop through the array. I'm assuming this is just how the string.match method is (although please let me know if i'm doing something wrong or missing something!). I want to find the specific indices of every occurrence of a match, even if it is of a word that was already previously matched. I'm wondering if that is just how the string.match method is and if so, if anyone has any idea what the best way to do this would be. Thanks.

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  • MapReduce

    - by kaleidoscope
    MapReduce is a programming model and an associated implementation for processing and generating large data sets. Users specify a map function that processes a key/value pair to generate a set of  intermediate key/value pairs, and a reduce function that merges all intermediate values associated with the same intermediate key. Many real world tasks are expressible in this model, as shown in the paper. Programs written in this functional style are automatically parallelized and executed on a large cluster of commodity machines. The run-time system takes care of the details of partitioning the input data,  scheduling the program's execution across a set of machines, handling machine failures, and managing the required inter-machine communication. This allows programmers without any experience with parallel and distributed systems to easily utilize the resources of a large distributed system. Example: A process to count the appearances of each different word in a set of documents void map(String name, String document):   // name: document name   // document: document contents   for each word w in document:     EmitIntermediate(w, 1); void reduce(String word, Iterator partialCounts):   // word: a word   // partialCounts: a list of aggregated partial counts   int result = 0;   for each pc in partialCounts:     result += ParseInt(pc);   Emit(result); Here, each document is split in words, and each word is counted initially with a "1" value by the Map function, using the word as the result key. The framework puts together all the pairs with the same key and feeds them to the same call to Reduce, thus this function just needs to sum all of its input values to find the total appearances of that word.   Sarang, K

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  • Project Euler 17: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 17.  As always, any feedback is welcome. # Euler 17 # http://projecteuler.net/index.php?section=problems&id=17 # If the numbers 1 to 5 are written out in words: # one, two, three, four, five, then there are # 3 + 3 + 5 + 4 + 4 = 19 letters used in total. # If all the numbers from 1 to 1000 (one thousand) # inclusive were written out in words, how many letters # would be used? # # NOTE: Do not count spaces or hyphens. For example, 342 # (three hundred and forty-two) contains 23 letters and # 115 (one hundred and fifteen) contains 20 letters. The # use of "and" when writing out numbers is in compliance # with British usage. import time start = time.time() def to_word(n): h = { 1 : "one", 2 : "two", 3 : "three", 4 : "four", 5 : "five", 6 : "six", 7 : "seven", 8 : "eight", 9 : "nine", 10 : "ten", 11 : "eleven", 12 : "twelve", 13 : "thirteen", 14 : "fourteen", 15 : "fifteen", 16 : "sixteen", 17 : "seventeen", 18 : "eighteen", 19 : "nineteen", 20 : "twenty", 30 : "thirty", 40 : "forty", 50 : "fifty", 60 : "sixty", 70 : "seventy", 80 : "eighty", 90 : "ninety", 100 : "hundred", 1000 : "thousand" } word = "" # Reverse the numbers so position (ones, tens, # hundreds,...) can be easily determined a = [int(x) for x in str(n)[::-1]] # Thousands position if (len(a) == 4 and a[3] != 0): # This can only be one thousand based # on the problem/method constraints word = h[a[3]] + " thousand " # Hundreds position if (len(a) >= 3 and a[2] != 0): word += h[a[2]] + " hundred" # Add "and" string if the tens or ones # position is occupied with a non-zero value. # Note: routine is broken up this way for [my] clarity. if (len(a) >= 2 and a[1] != 0): # catch 10 - 99 word += " and" elif len(a) >= 1 and a[0] != 0: # catch 1 - 9 word += " and" # Tens and ones position tens_position_value = 99 if (len(a) >= 2 and a[1] != 0): # Calculate the tens position value per the # first and second element in array # e.g. (8 * 10) + 1 = 81 tens_position_value = int(a[1]) * 10 + a[0] if tens_position_value <= 20: # If the tens position value is 20 or less # there's an entry in the hash. Use it and there's # no need to consider the ones position word += " " + h[tens_position_value] else: # Determine the tens position word by # dividing by 10 first. E.g. 8 * 10 = h[80] # We will pick up the ones position word later in # the next part of the routine word += " " + h[(a[1] * 10)] if (len(a) >= 1 and a[0] != 0 and tens_position_value > 20): # Deal with ones position where tens position is # greater than 20 or we have a single digit number word += " " + h[a[0]] # Trim the empty spaces off both ends of the string return word.replace(" ","") def to_word_length(n): return len(to_word(n)) print sum([to_word_length(i) for i in xrange(1,1001)]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • How to create Automation Add In Formula/Function and Excel Add In buttons (vsto) for them together?

    - by ticky
    Ok, let me explain it little bit better. Here is one example how to create formula/functions http://blogs.msdn.com/b/eric_carter/archive/2004/12/01/273127.aspx?PageIndex=1#comments I implemented something like that, I even added values in registry, so that this Automation AddIn doesn't have to be added manually in Excel, but automatically.. I created SETUP project for this project and it works GREAT. Then.. After some time, I wanted to create buttons in Excel for functions that I use. Those are custom functions, using some web services. I created Excel AddIn and added Ribbon with buttons - one button = one custom function. I can publish this project and I am creating VSTO, so this way, I can install excel ribbon buttons in custom group of mine. Now, I have 2 installations, first for Automation AddIn and second for Excel AddIn. How can I connect them? I tried to include VSTO to Setup - something like this: [I WILL ADD IT LATER] When I install it, it works great, it installs both parts. But when I install on my friends computer, it doesn't shows Ribbon buttons. What could be the problem? If there is some other way to integrate those two, I would be very grateful!!!!! Thanks! Tijana

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  • Strange (Undefined?) Behavior of Free in C

    - by Chris Cirefice
    This is really strange... and I can't debug it (tried for about two hours, debugger starts going haywire after a while...). Anyway, I'm trying to do something really simple: Free an array of strings. The array is in the form: char **myStrings. The array elements are initialized as: myString[index] = malloc(strlen(word)); myString[index] = word; and I'm calling a function like this: free_memory(myStrings, size); where size is the length of the array (I know this is not the problem, I tested it extensively and everything except this function is working). free_memory looks like this: void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { free(list[i]); } free(list); } Now here comes the weird part. if (size> strlen(list[i])) then the program crashes. For example, imagine that I have a list of strings that looks something like this: myStrings[0] = "Some"; myStrings[1] = "random"; myStrings[2] = "strings"; And thus the length of this array is 3. If I pass this to my free_memory function, strlen(myStrings[0]) > 3 (4 3), and the program crashes. However, if I change myStrings[0] to be "So" instead, then strlen(myStrings[0]) < 3 (2 < 3) and the program does not crash. So it seems to me that free(list[i]) is actually going through the char[] that is at that location and trying to free each character, which I imagine is undefined behavior. The only reason I say this is because I can play around with the size of the first element of myStrings and make the program crash whenever I feel like it, so I'm assuming that this is the problem area. Note: I did try to debug this by stepping through the function that calls free_memory, noting any weird values and such, but the moment I step into the free_memory function, the debugger crashes, so I'm not really sure what is going on. Nothing is out of the ordinary until I enter the function, then the world explodes. Another note: I also posted the shortened version of the source for this program (not too long; Pastebin) here. I am compiling on MinGW with the c99 flag on. PS - I just thought of this. I am indeed passing numUniqueWords to the free function, and I know that this does not actually free the entire piece of memory that I allocated. I've called it both ways, that's not the issue. And I left it how I did because that is the way that I will be calling it after I get it to work in the first place, I need to revise some of my logic in that function. Source, as per request (on-site): #include <stdio.h> #include <string.h> #include <ctype.h> #include <stdlib.h> #include "words.h" int getNumUniqueWords(char text[], int size); int main(int argc, char* argv[]) { setvbuf(stdout, NULL, 4, _IONBF); // For Eclipse... stupid bug. --> does NOT affect the program, just the output to console! int nbr_words; char text[] = "Some - \"text, a stdin\". We'll have! also repeat? We'll also have a repeat!"; int length = sizeof(text); nbr_words = getNumUniqueWords(text, length); return 0; } void free_memory(char **list, int size) { for (int i = 0; i < size; i ++) { // You can see that printing the values is fine, as long as free is not called. // When free is called, the program will crash if (size > strlen(list[i])) //printf("Wanna free value %d w/len of %d: %s\n", i, strlen(list[i]), list[i]); free(list[i]); } free(list); } int getNumUniqueWords(char text[], int length) { int numTotalWords = 0; char *word; printf("Length: %d characters\n", length); char totalWords[length]; strcpy(totalWords, text); word = strtok(totalWords, " ,.-!?()\"0123456789"); while (word != NULL) { numTotalWords ++; printf("%s\n", word); word = strtok(NULL, " ,.-!?()\"0123456789"); } printf("Looks like we counted %d total words\n\n", numTotalWords); char *uniqueWords[numTotalWords]; char *tempWord; int wordAlreadyExists = 0; int numUniqueWords = 0; char totalWordsCopy[length]; strcpy(totalWordsCopy, text); for (int i = 0; i < numTotalWords; i++) { uniqueWords[i] = NULL; } // Tokenize until all the text is consumed. word = strtok(totalWordsCopy, " ,.-!?()\"0123456789"); while (word != NULL) { // Look through the word list for the current token. for (int j = 0; j < numTotalWords; j ++) { // Just for clarity, no real meaning. tempWord = uniqueWords[j]; // The word list is either empty or the current token is not in the list. if (tempWord == NULL) { break; } //printf("Comparing (%s) with (%s)\n", tempWord, word); // If the current token is the same as the current element in the word list, mark and break if (strcmp(tempWord, word) == 0) { printf("\nDuplicate: (%s)\n\n", word); wordAlreadyExists = 1; break; } } // Word does not exist, add it to the array. if (!wordAlreadyExists) { uniqueWords[numUniqueWords] = malloc(strlen(word)); uniqueWords[numUniqueWords] = word; numUniqueWords ++; printf("Unique: %s\n", word); } // Reset flags and continue. wordAlreadyExists = 0; word = strtok(NULL, " ,.-!?()\"0123456789"); } // Print out the array just for funsies - make sure it's working properly. for (int x = 0; x <numUniqueWords; x++) { printf("Unique list %d: %s\n", x, uniqueWords[x]); } printf("\nNumber of unique words: %d\n\n", numUniqueWords); // Right below is where things start to suck. free_memory(uniqueWords, numUniqueWords); return numUniqueWords; }

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  • lnk2019 error in very simple c++ program

    - by Erin
    I have tried removing various parts and building, but nothing makes the lnk2019 error go away, or even produces any normal errors. Everything is in the one file at the moment (it won't be later when it is finished). The program has three lists of words and makes a jargon phrase out of them, and you are supposed to be able to add words, remove words, view the lists, restore defaults, save changes to file, and load changes from file. #include "stdafx.h" #include <iostream> #include <string.h> using namespace std; const int maxlist = 20; string adj1[maxlist], adj2[maxlist], noun[maxlist]; void defaultlist(int list) { if(list == 1) { adj1[0] = "green"; adj1[1] = "red"; adj1[2] = "yellow"; adj1[3] = "blue"; adj1[4] = "purple"; int i = 5; while(i != maxlist) { adj1[i] = ""; i = i + 1; } } if(list == 2) { adj2[0] = "shiny"; adj2[1] = "hard"; adj2[2] = "soft"; adj2[3] = "spiky"; adj2[4] = "furry"; int i = 5; while(i != maxlist) { adj2[i] = ""; i = i + 1; } } if(list == 3) { noun[0] = "cat"; noun[1] = "dog"; noun[2] = "desk"; noun[3] = "chair"; noun[4] = "door"; int i = 5; while(i != maxlist) { noun[i] = ""; i = i + 1; } } return; } void printlist(int list) { if(list == 1) { int i = 0; while(!(i == maxlist)) { cout << adj1[i] << endl; i = i + 1; } } if(list == 2) { int i = 0; while(!(i == maxlist)) { cout << adj2[i] << endl; i = i + 1; } } if(list == 3) { int i = 0; while(!(i == maxlist)) { cout << noun[i] << endl; i = i + 1; } } return; } string makephrase() { int num1 = rand()%maxlist; int num2 = rand()%maxlist; int num3 = rand()%maxlist; int num4 = rand()%1; string word1, word2, word3; if(num4 = 0) { word1 = adj1[num1]; word2 = adj2[num2]; } else { word1 = adj2[num1]; word2 = adj1[num2]; } word3 = noun[num3]; return word1 + " ," + word2 + " " + word3; } string addword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj1[i] == "") { adj1[i] = word; result = "Word was entered successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(adj2[i] == "") { adj2[i] = word; result = "Word was entered successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == "" || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "List is full. Please try again."; if(noun[i] == "") { noun[i] = word; result = "Word was entered successfully."; } } return result; } string removeword(string word, int list) { string result; if(list == 1) { int i = 0; while(!(adj1[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj1[i] == word) { adj1[i] = ""; result = "Word was removed successfully."; } } if(list == 2) { int i = 0; while(!(adj2[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(adj2[i] == word) { adj2[i] = ""; result = "Word was removed successfully."; } } if(list == 3) { int i = 0; while(!(noun[i] == word || i == maxlist)) { i = i + 1; } if(i == maxlist) result = "Word is not on the list. Please try again."; if(noun[i] == word) { noun[i] = ""; result = "Word was removed successfully."; } } return result; } /////////////////////////////main/////////////////////////////////// int main() { string mainselection; string makeselection; string phrase; defaultlist(1); defaultlist(2); defaultlist(3); cout << "This program generates jargon phrases made of two adjectives and one noun,"; cout << " on three lists. Each list may contain a maximum of " << maxlist << "elements."; cout << " Please choose from the following menu by typing the appropriate number "; cout << "and pressing enter." << endl; cout << endl; cout << "1. Make a jargon phrase." << endl; cout << "2. View a list." << endl; cout << "3. Add a word to a list." << endl; cout << "4. Remove a word from a list." << endl; cout << "5. Restore default lists." << endl; cout << "More options coming soon!." << endl; cin mainselection if(mainselection == 1) { phrase = makephrase(); cout << "Your phrase is " << phrase << "." << endl; cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; cin makeselection; while(!(makeselection == "1" || makeselection == "2" || makeselection == "3")) { cout << "You have entered an invalid selection. Please try again." << endl; cin makeselection; } while(makeselection == "1") { phrase = makephrase(); cout << "To make another phrase, press 1. To go back to the main menu,"; cout << " press 2. To exit the program, press 3." << endl; } if(makeselection == "2") main(); if(makeselection == "3") return 0; } return 0; } //Rest of the options coming soon!

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  • What word processor can manage left and right pages separately?

    - by chtfn
    I was after a word processor that can manage left and right pages separately so I can have my text on the right pages and my illustrations on the left pages. I know LibeOffice can set "left page" and "right page" formats, but there is no simple way to make the text jump from right page to right page when writing. I don't know what would be the best way to do that, but I guess I need an app that is designed for writing books and do that kind of thing, or an app that can associate a page format with an object format (so the "illustration" format can be exclusively associated with "left page" format, and "text body" exclusively associated with "right page", for example). Or is there an extension for LO or OOo out there that I didn't hear about? Cheers!

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  • Does having a Google "stop word" in a domain name have less SEO benefit than not having it?

    - by Dan
    Let me explain. Let's say my keyword I want to optimize is "green giraffes". But the domain greengiraffes.com (singular, plural, no hyphen, hyphen, etc.) is not available. I know that the search results for "green giraffes" and "about green giraffes" are essentially the same because "about" is a "stop word". Does that therefore also mean that the domain name "aboutgreengiraffes.com" is as good as "greengiraffes.com" in terms of SEO value? Are all stop words equal in that regard, or a shorter one (such as "e" or "z") is better?

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  • What does the English word "for" exactly mean in "for" loops?

    - by kol
    English is not my first language, but since the keywords in programming languages are English words, I usually find it easy to read source code as English sentences: if (x > 10) f(); = "If variable x is greater than 10, then call function f." while (i < 10) ++i; = "While variable i is less than 10, increase i by 1." But how a for loop is supposed to be read? for (i = 0; i < 10; ++i) f(i); = ??? I mean, I know what a for loop is and how it works. My problem is only that I don't know what the English word "for" exactly means in for loops.

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  • How do you properly word a Google search when you don't even have a solution in mind? [closed]

    - by Bruno Romaszkiewicz
    So, I'm stuck on a problem, looking for a solution, my rubber duck can't help me, my co-workers can't help me. Next natural step is research, right? Google can help me, He always can. Or so I'm told. My problem is, I never found much use for Google when looking for a programming solution, it's very useful for finding how to implement one, but when you don't even know where to start, how do you properly word a Google search? Is there any other option?

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  • Need suggestions on how to extract data from .docx/.doc file then into mssql

    - by DarkPP
    I'm suppose to develop an automated application for my project, it will load past-year examination/exercises paper (word file), detect the sections accordingly, extract the questions and images in that section, and then store the questions and images into the database. (Preview of the question paper is at the bottom of this post) So I need some suggestions on how to extract data from a word file, then inserting them into a database. Currently I have a few methods to do so, however I have no idea how I could implement them when the file contains textboxes with background image. The question has to link with the image. Method One (Make use of ms office interop) Load the word file - Extract image, save into a folder - Extract text, save as .txt - Extract text from .txt then store in db Question: How i detect the section and question. How I link the image to the question. Extract text from word file (Working): private object missing = Type.Missing; private object sFilename = @"C:\temp\questionpaper.docx"; private object sFilename2 = @"C:\temp\temp.txt"; private object readOnly = true; object fileFormat = Word.WdSaveFormat.wdFormatText; private void button1_Click(object sender, EventArgs e) { Word.Application wWordApp = new Word.Application(); wWordApp.DisplayAlerts = Word.WdAlertLevel.wdAlertsNone; Word.Document dFile = wWordApp.Documents.Open(ref sFilename, ref missing, ref readOnly, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing); dFile.SaveAs(ref sFilename2, ref fileFormat, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing,ref missing, ref missing,ref missing,ref missing,ref missing,ref missing, ref missing,ref missing); dFile.Close(ref missing, ref missing, ref missing); } Extract image from word file (Doesn't work on image inside textbox): private Word.Application wWordApp; private int m_i; private object missing = Type.Missing; private object filename = @"C:\temp\questionpaper.docx"; private object readOnly = true; private void CopyFromClipbordInlineShape(String imageIndex) { Word.InlineShape inlineShape = wWordApp.ActiveDocument.InlineShapes[m_i]; inlineShape.Select(); wWordApp.Selection.Copy(); Computer computer = new Computer(); if (computer.Clipboard.GetDataObject() != null) { System.Windows.Forms.IDataObject data = computer.Clipboard.GetDataObject(); if (data.GetDataPresent(System.Windows.Forms.DataFormats.Bitmap)) { Image image = (Image)data.GetData(System.Windows.Forms.DataFormats.Bitmap, true); image.Save("C:\\temp\\DoCremoveImage" + imageIndex + ".png", System.Drawing.Imaging.ImageFormat.Png); } } } private void button1_Click(object sender, EventArgs e) { wWordApp = new Word.Application(); wWordApp.Documents.Open(ref filename, ref missing, ref readOnly, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing, ref missing); try { for (int i = 1; i <= wWordApp.ActiveDocument.InlineShapes.Count; i++) { m_i = i; CopyFromClipbordInlineShape(Convert.ToString(i)); } } finally { object save = false; wWordApp.Quit(ref save, ref missing, ref missing); wWordApp = null; } } Method Two Unzip the word file (.docx) - Copy the media(image) folder, store somewhere - Parse the XML file - Store the text in db Any suggestion/help would be greatly appreciated :D Preview of the word file: (backup link: http://i.stack.imgur.com/YF1Ap.png)

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  • One letter game problem?

    - by Alex K
    Recently at a job interview I was given the following problem: Write a script capable of running on the command line as python It should take in two words on the command line (or optionally if you'd prefer it can query the user to supply the two words via the console). Given those two words: a. Ensure they are of equal length b. Ensure they are both words present in the dictionary of valid words in the English language that you downloaded. If so compute whether you can reach the second word from the first by a series of steps as follows a. You can change one letter at a time b. Each time you change a letter the resulting word must also exist in the dictionary c. You cannot add or remove letters If the two words are reachable, the script should print out the path which leads as a single, shortest path from one word to the other. You can /usr/share/dict/words for your dictionary of words. My solution consisted of using breadth first search to find a shortest path between two words. But apparently that wasn't good enough to get the job :( Would you guys know what I could have done wrong? Thank you so much. import collections import functools import re def time_func(func): import time def wrapper(*args, **kwargs): start = time.time() res = func(*args, **kwargs) timed = time.time() - start setattr(wrapper, 'time_taken', timed) return res functools.update_wrapper(wrapper, func) return wrapper class OneLetterGame: def __init__(self, dict_path): self.dict_path = dict_path self.words = set() def run(self, start_word, end_word): '''Runs the one letter game with the given start and end words. ''' assert len(start_word) == len(end_word), \ 'Start word and end word must of the same length.' self.read_dict(len(start_word)) path = self.shortest_path(start_word, end_word) if not path: print 'There is no path between %s and %s (took %.2f sec.)' % ( start_word, end_word, find_shortest_path.time_taken) else: print 'The shortest path (found in %.2f sec.) is:\n=> %s' % ( self.shortest_path.time_taken, ' -- '.join(path)) def _bfs(self, start): '''Implementation of breadth first search as a generator. The portion of the graph to explore is given on demand using get_neighboors. Care was taken so that a vertex / node is explored only once. ''' queue = collections.deque([(None, start)]) inqueue = set([start]) while queue: parent, node = queue.popleft() yield parent, node new = set(self.get_neighbours(node)) - inqueue inqueue = inqueue | new queue.extend([(node, child) for child in new]) @time_func def shortest_path(self, start, end): '''Returns the shortest path from start to end using bfs. ''' assert start in self.words, 'Start word not in dictionnary.' assert end in self.words, 'End word not in dictionnary.' paths = {None: []} for parent, child in self._bfs(start): paths[child] = paths[parent] + [child] if child == end: return paths[child] return None def get_neighbours(self, word): '''Gets every word one letter away from the a given word. We do not keep these words in memory because bfs accesses a given vertex only once. ''' neighbours = [] p_word = ['^' + word[0:i] + '\w' + word[i+1:] + '$' for i, w in enumerate(word)] p_word = '|'.join(p_word) for w in self.words: if w != word and re.match(p_word, w, re.I|re.U): neighbours += [w] return neighbours def read_dict(self, size): '''Loads every word of a specific size from the dictionnary into memory. ''' for l in open(self.dict_path): l = l.decode('latin-1').strip().lower() if len(l) == size: self.words.add(l) if __name__ == '__main__': import sys if len(sys.argv) not in [3, 4]: print 'Usage: python one_letter_game.py start_word end_word' else: g = OneLetterGame(dict_path = '/usr/share/dict/words') try: g.run(*sys.argv[1:]) except AssertionError, e: print e

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