Search Results

Search found 23433 results on 938 pages for 'xml documentation'.

Page 84/938 | < Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >

  • Joomla plugin install XML files <folder> tag

    - by Rixius
    While developing a joomla plugin, if my plugin folder looks like so: /install.xml /mainPg.php /subfolder/lib.php /subfolder/config.php Would the tag look like this? <files> <filename plugin="mainPg">mainPg.php</filename> <folder>subfolder</folder> </files>

    Read the article

  • Viewing large XML files in eclipse?

    - by Paul Wicks
    I'm working on a project involving some large XML files (from 50MB to over 1GB) and it would be nice if I could view them in eclipse (simple text view is fine) without Java running out of heap space. I've tried tweaking the amount of memory available to the jvm in eclipse.ini but haven't had much success. Any ideas?

    Read the article

  • XML Parsing Error: not well-formed

    - by jcure
    I get the above error when viewing a xml document. The problem seems to be the second ( = ) in the following link. http://mysite.com/viewpage.php?u=1020&op=new In the link & is replaced by & amp; without the space. Any help as to why this is throwing an error would be greatly appreciated.

    Read the article

  • How to merge 2 XML streams in Java by XSLT

    - by user327933
    I'd like to merge 2 XML streams (strings) in Java, necessarily by XSLT (that I could change the transformation), but the problem is that the XMLs come as a string. There are many examples, but through the files. Can this be done without saving them in files? Thanks.

    Read the article

  • XML Import how would you do it?

    - by Rico
    XML is used as one of our main integration points. it comes over by many clients at a time but too many clients importing at the same time can slow down our database to a crawl. Someone has to have solved a problem like this. I am basically using VB to parse through the data and import what i want and don't want. Is there a better way?

    Read the article

  • programming language xml reader

    - by matt
    Indentify a suitable programming language that will read the XML document and insert its contents into the database. i need help with this question i am getting really confused can some one show me and guide me thorught how to do this

    Read the article

  • How to get search results in XML format

    - by Shibin Moideen
    Hi, I am planning to make an iPhone search app. the user types in the search string. the string will be searched by some search engines like Google, Live, Yahoo ... I need to get the search result in the XML format. Is there any way to do this. Help needed. Please. Thanks and regards, Shibin

    Read the article

  • Passing input value thru XML loop and return value

    - by Mike Dyer
    "X" is reading the form value, but it is still passing and older "var thisMarket" value. The objective is to take a zip code via HTML form: <form id="market" name="market" onSubmit="return validateZIP(this.zip.value);" method="get" action=""> <input type="text" name="zip" id="zip" value="zipcode" onfocus="if(!this._haschanged){this.value=''};this._haschanged=true;" style="float:left; width:100px; margin-top:5px;"> <input type="image" style="float:left; margin-top:5px; border: 0pt none ; width: 22px; height:17px;" src="images/nav/bottom/linkbar/btn_search_btn.gif" onClick="findLda();"> </form> The script being passed thru is: function findLda(x){ marketName = new Array(); marketURL = new Array(); zip = new Array(); zip_temp = new Array(); zipMatch = false; var shareZip = "Shared Zips"; var thisMarket = "Market value"; xmlDoc=loadXML("/_includes/market.xml"); var Offer,node; document.getElementById('market').innerHTML=''; for(var j=0; j<xmlDoc.getElementsByTagName('market').length; j++){ node = xmlDoc.getElementsByTagName('market')[j]; marketName.push(node.childNodes[3].textContent); marketURL.push(node.childNodes[5].textContent); for(var k=0; k<node.getElementsByTagName('zip').length; k++){ if(node.getElementsByTagName('zip')[k].textContent!=null){ zip_temp.push(node.getElementsByTagName('zip')[k].textContent); } } zip.push(zip_temp); zip_temp = new Array(); } //loop the zip Array to find a match for the query Zip. for(k=0; k<zip.length; k++){ for(m=0; m<zip[k].length; m++){ if(x == zip[k][m].toString()){ zipMatch=true; thisMarket=marketName[k].toString(); } } } alert(thisMarket); } The objective naturally is to take field input (A), pass it thru market.xml - initialize a loop and match a zip (B), alert the result (C). Looking for any direction with what is existing or a completely new direction. Thanks!

    Read the article

  • WP7 Return the last 7 days of data from an xml web service

    - by cvandal
    Hello, I'm trying to return the last 7 days of data from an xml web service but with no luck. Could someone please explain me to how I would accomplish this? The XML is as follows: <node> <api> <usagelist> <usage day="2011-01-01"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-02"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-03"> <traffic name="total" unit="bytes">23579797</traffic> </usage> <usage day="2011-01-04"> <traffic name="total" unit="bytes">23579797</traffic> </usage> </usagelist> </api> </node> EDIT The data I want to retrieve will be used to populate a line graph. Specificly I require the day attribute value and the traffic element value for the past 7 days. At the moment, I have the code below in place, howevewr it's only showing the first day 7 times and traffic for the first day 7 times. XDocument xDocument = XDocument.Parse(e.Result); var values = from query in xDocument.Descendants("usagelist") select new History { day = query.Element("usage").Attribute("day").Value, traffic = query.Element("usage").Element("traffic").Value }; foreach (History history in values) { ObservableCollection<LineGraphItem> Data = new ObservableCollection<LineGraphItem>() { new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, new LineGraphItem() { yyyymmdd = history.day, value = double.Parse(history.traffic) }, }; lineGraph1.DataSource = Data; }

    Read the article

  • c# update xml file

    - by Pila
    I want to replace a xml node that is not a child of the root element. how can I do it - not in .Net 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like : XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); how can I replace this olditem?

    Read the article

  • Help with XML path views

    - by xmlpath
    Hi all, is there any tool that will give me a view for XML fields like so. I want something that will show me the a view like so, if i select element1 Service/Body/element1 Is there any tool for eclipse for doing the above. Thanks.

    Read the article

  • AS3 XML problem

    - by dd
    My Flash project is made of several .swf files, one of them loads XML gallery. everything works fine on my machine, but when I upload it to the testing server gallery content doesn't load. All my paths are relative to Main swf file. I can't make them absolute URLs, b/c I have to deliver zip package. What could be wrong?

    Read the article

  • xml schema construction

    - by amanrahahla
    in xml can any concept inhert the attribute of the main concept as an example: book( -author -title -isbn -price) and textbook as a subconcept from book can textbook take the same attribute of book and how?

    Read the article

  • update XML file

    - by Pila
    I want to replace an XML node that is not a child of the root element. How can I do it - not in .NET 3.5? I don't know the exact path to the node I want to replace, I get the node by XPath query like: XmlElement root = doc.DocumentElement; oldItem = root.SelectSingleNode("//Node1[@name='aaa']//Node2[Item='bbb']/Value"); How can I replace this old item?

    Read the article

  • One log4j.xml - many scripts

    - by psed
    One of my utility jar files is used by different nix scripts, located in different categories. Problem: unable to initialize log4j framework (unable to find log4j.xml). Solution, that allows to configure logger correctly while launching jar classes by different scripts - usage of env vars and force configuring using DOMConfigurtor.configure(pathToConfXml) method. is it possible to avoid path hardcoding and configure logger inside of a script? Appreciate all your help. Thanks.

    Read the article

< Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >