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  • Performance issue when querying a large xml file through php/ajax on Apache Server

    - by Niall
    Hey, I have a simple "live search" (results displayed while typing) web site. This make up is Ajax to PHP querying a pretty large XML document (10,000+ lines). This is all been hosted on a local Apache server (xamp). The scale of the xml document seems to be causing huge performance issue with results taking 10ish seconds to give the results. I'm very new to PHP (this actually being my first play about) so there below is a snippet of code in case there is something obvious for($i=0; $i<($foodListXML->length); $i++){ $type=$foodListXML->item($i)->getElementsByTagName('type'); $foodnote=$foodListXML->item($i)->getElementsByTagName('foodnote'); $style=$foodListXML->item($i)->getElementsByTagName('style'); if ($type->item(0)->nodeType==1) { //find a link matching the search text if (stristr($type->item(0)->childNodes->item(0)->nodeValue,$q)){ $currentFoodName = $type->item(0)->childNodes->item(0)->nodeValue; $currentFoodStyle = $style->item(0)->childNodes->item(0)->nodeValue; $currentFoodNote = $foodnote->item(0)->childNodes->item(0)->nodeValue; if ($hint==""){ $hint= $currentFoodName . " , " . $currentFoodNote . " , <b>" . $currentFoodStyle. "</b>" . "<br>" ; } else{ $hint=$hint . $currentFoodName . " , " . $currentFoodNote . " , <b>" . $currentFoodStyle. "</b>" . "<br>" ; } } } } } Also if having the data in a DB and accessing that is faster, then I'm open to that.. All ideas really!! Thanks.

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  • Multiple schema validation in Java

    - by user279554
    Hi, I am trying to do multiple schema validation in Java. I don't understand where I am doing wrong. Any help will be appreciated. abc.xsd <?xml version="1.0" encoding="UTF-8"?> <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xn="project-xml-r4j_another.xsd"> <xsd:import namespace="project-xml-r4j_another.xsd"/> <xsd:element name="abc" type="abc"> </xsd:element> <xsd:complexType name="abc"> <xsd:sequence> <xsd:element name="test" type="test" minOccurs="0" maxOccurs="1"> </xsd:element> <!--<xsd:element name="proj" type="xn:proj"/>--> </xsd:sequence> <xsd:attribute name="id" type="xsd:ID" use="required"/> </xsd:complexType> <xsd:complexType name="test"> <xsd:attribute name="id" type="xsd:ID" use="required"></xsd:attribute> <xsd:attribute name="value" use="required"> <xsd:simpleType> <xsd:restriction base="xsd:string"> <xsd:maxLength value="100" /> </xsd:restriction> </xsd:simpleType> </xsd:attribute> </xsd:complexType> </xsd:schema> project-xml-r4j_another.xsd <?xml version="1.0" encoding="UTF-8"?> <xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" targetNamespace="project-xml-r4j_another.xsd" xmlns="project-xml-r4j_another.xsd" elementFormDefault="qualified" attributeFormDefault="unqualified"> <xsd:element name="proj" type="proj"> <xsd:annotation> <xsd:documentation> The project is the root tag of a project-xml. </xsd:documentation> </xsd:annotation> </xsd:element> <xsd:complexType name="proj"> <xsd:attribute name="id" type="xsd:ID" use="required"/> </xsd:complexType> </xsd:schema> Test case package test; import java.io.File; import java.io.IOException; import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.Schema; import javax.xml.validation.SchemaFactory; import javax.xml.validation.Validator; import org.apache.log4j.Logger; import org.junit.Test; import org.xml.sax.SAXException; import org.xml.sax.SAXParseException; import org.xml.sax.helpers.DefaultHandler; import com.ericsson.ccrtool.core.project.projectxml.InvalidProjectXmlException; public class TestSchema { private static final Logger logger = Logger.getLogger(TestSchema.class); static final String W3C_XML_SCHEMA = XMLConstants.W3C_XML_SCHEMA_NS_URI; @Test public void test() { System.out.println("TestSchema.test()"); try { SchemaFactory schemaFactory = SchemaFactory.newInstance(W3C_XML_SCHEMA); // create a grammar object. Source [] source = { new StreamSource(new File("C:\\jaydeep\\Ericsson\\R5B\\abc.xsd")), new StreamSource(new File("C:\\jaydeep\\Ericsson\\R5B\\project-xml-r4j.xsd"))}; Schema schemaGrammar = schemaFactory.newSchema(source); Validator schemaValidator = schemaGrammar.newValidator(); schemaValidator.setErrorHandler(new MessageHandler()); // validate xml instance against the grammar. schemaValidator.validate(new StreamSource("C:\\jaydeep\\Ericsson\\R5B\\project_tmmk17cells_xnaveen_project-xml.xml")); } catch (SAXException e) { throw new InvalidProjectXmlException("Project-xml validation failed, Exception: " + e.getMessage(), e); } catch (IOException e) { throw new InvalidProjectXmlException("Project-xml validation failed, Exception: " + e.getMessage(), e); } } class MessageHandler extends DefaultHandler { private String errMessage = ""; @Override public void warning(SAXParseException e) { logger.info("Warning Line " + e.getLineNumber() + ": " + e.getMessage()); } @Override public void error(SAXParseException e) { errMessage = new String("Error Line " + e.getLineNumber() + ": " + e.getMessage()); logger.info(errMessage); throw new InvalidProjectXmlException("Project-xml validation failed, Exception: " + errMessage); } @Override public void fatalError(SAXParseException e) { errMessage = new String("Error Line " + e.getLineNumber() + ": " + e.getMessage()); logger.info(errMessage); throw new InvalidProjectXmlException("Project-xml validation failed, Exception: " + errMessage); } } } Thanks, Jaydeep

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  • XML fix namespace declaration

    - by er4z0r
    Hi all, I am trying to detetct/work around this bug in RSS elements. That means I have to find a wrong namespace-declaration and change its value to the correct namespace. E.g: xmlns:media="http://search.yahoo.com/mrss" must be: xmlns:media="http://search.yahoo.com/mrss/" How can I achive that using the standard java XML APIs?

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  • XML validation in Java - why does this fail?

    - by jd
    hi, first time dealing with xml, so please be patient. the code below is probably evil in a million ways (I'd be very happy to hear about all of them), but the main problem is of course that it doesn't work :-) public class Test { private static final String JSDL_SCHEMA_URL = "http://schemas.ggf.org/jsdl/2005/11/jsdl"; private static final String JSDL_POSIX_APPLICATION_SCHEMA_URL = "http://schemas.ggf.org/jsdl/2005/11/jsdl-posix"; public static void main(String[] args) { System.out.println(Test.createJSDLDescription("/bin/echo", "hello world")); } private static String createJSDLDescription(String execName, String args) { Document jsdlJobDefinitionDocument = getJSDLJobDefinitionDocument(); String xmlString = null; // create the elements Element jobDescription = jsdlJobDefinitionDocument.createElement("JobDescription"); Element application = jsdlJobDefinitionDocument.createElement("Application"); Element posixApplication = jsdlJobDefinitionDocument.createElementNS(JSDL_POSIX_APPLICATION_SCHEMA_URL, "POSIXApplication"); Element executable = jsdlJobDefinitionDocument.createElement("Executable"); executable.setTextContent(execName); Element argument = jsdlJobDefinitionDocument.createElement("Argument"); argument.setTextContent(args); //join them into a tree posixApplication.appendChild(executable); posixApplication.appendChild(argument); application.appendChild(posixApplication); jobDescription.appendChild(application); jsdlJobDefinitionDocument.getDocumentElement().appendChild(jobDescription); DOMSource source = new DOMSource(jsdlJobDefinitionDocument); validateXML(source); try { Transformer transformer = TransformerFactory.newInstance().newTransformer(); transformer.setOutputProperty(OutputKeys.INDENT, "yes"); StreamResult result = new StreamResult(new StringWriter()); transformer.transform(source, result); xmlString = result.getWriter().toString(); } catch (Exception e) { e.printStackTrace(); } return xmlString; } private static Document getJSDLJobDefinitionDocument() { DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); DocumentBuilder builder = null; try { builder = factory.newDocumentBuilder(); } catch (Exception e) { e.printStackTrace(); } DOMImplementation domImpl = builder.getDOMImplementation(); Document theDocument = domImpl.createDocument(JSDL_SCHEMA_URL, "JobDefinition", null); return theDocument; } private static void validateXML(DOMSource source) { try { URL schemaFile = new URL(JSDL_SCHEMA_URL); Sche maFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = schemaFactory.newSchema(schemaFile); Validator validator = schema.newValidator(); DOMResult result = new DOMResult(); validator.validate(source, result); System.out.println("is valid"); } catch (Exception e) { e.printStackTrace(); } } } it spits out a somewhat odd message: org.xml.sax.SAXParseException: cvc-complex-type.2.4.a: Invalid content was found starting with element 'JobDescription'. One of '{"http://schemas.ggf.org/jsdl/2005/11/jsdl":JobDescription}' is expected. Where am I going wrong here? Thanks a lot

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  • Flex 3 - XML - '<' remplacing by '&lt'

    - by coulix
    Hello there, I moved from flash 9 to flash 10 with flex SDK 3.2 and some small oddities regarding encoding. When appending child nodes with appendchild call '<' is replaced by '&lt' and with > on save in the xml file. Any idea of what could be the cause ?

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  • Castel Windsor XML configuration for WCF proxy using WCF Integration Facility

    - by andreyg
    Hi everybody! Currently, we use programming registration of WCF proxies in Windsor container using WCF Integration Facility. For example: container.Register( Component.For<CalculatorSoap>() .Named("calculatorSoap") .LifeStyle.Transient .ActAs(new DefaultClientModel { Endpoint = WcfEndpoint.FromConfiguration("CalculatorSoap").LogMessages() } ) ); Is there any way to do the same via Windsor XML configuration file. I can't find any sample of this on google. Thanks in advance

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  • xml dom node children

    - by matt
    Need some help I've got lots of code and i want to make it shorter i know there's a way but I can't remember it this is code example: <?xml version="1.0" encoding="ISO-8859-1"?> <bookstore> <book category="cooking"> <title lang="en">Everyday Italian</title> <author>Giada De Laurentiis</author> <year>2005</year> <price>30.00</price> </book> <book category="children"> <title lang="en">Harry Potter</title> <author>J K. Rowling</author> <year>2005</year> <price>29.99</price> </book> <book category="web"> <title lang="en">XQuery Kick Start</title> <author>James McGovern</author> <author>Per Bothner</author> <author>Kurt Cagle</author> <author>James Linn</author> <author>Vaidyanathan Nagarajan</author> <year>2003</year> <price>49.99</price> </book> <book category="web" cover="paperback"> <title lang="en">Learning XML</title> <author>Erik T. Ray</author> <year>2003</year> <price>39.95</price> </book> </bookstore As you can see the different nodes, children now is there a way to make this code smaller so I don't have to keep writing the nodes and children

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  • php code to return xml

    - by anwar
    hi there i have a question and need help on this from you guys . I have a database created for a game called gamesleaderboard and the fields are id, player_name, score, leveltime. and my task is after getting the score, i have to insert it to a database and sort the dbase accordingly. after sorting, the code will return an xml in the following structure: Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 Samer920100 Seyd900110 Ahmad100080 Basel95090 plz tell me the necessary details how to do this thankyou.

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  • Sort/Group XML data with PHP?

    - by Volmar
    I'm trying to make a page using data from the discogs.com (XML)-API. i've been parsing it with simpleXML and it's working pretty well but there is some things i'm not sure how to do. Here is part of the XML: <releases> <release id="1468764" status="Accepted" type="Main"> <title>Versions</title> <format>12", EP</format> <label>Not On Label</label> <year>1999</year> </release> <release id="72246" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>LP</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="890064" status="Accepted" type="Main"> <title>The M.O.F Blend</title> <format>CD</format> <label>Blenda Records</label> <year>2002</year> </release> <release id="1563561" status="Accepted" type="TrackAppearance"> <title>Ännu En Gång Vol. 3</title> <trackinfo>Backtrack</trackinfo> <format>Cass, Comp, Mix</format> <label>Hemmalaget</label> <year>2001</year> </release> </releases> What i want to achieve is something similair to how discogs presents the releases: http://www.discogs.com/artist/Mics+Of+Fury where diferent versions of the same release are sorted together. (see. The M.O.F Blend in my link) This is done on discogs with having a master release that features the other releases. unfortunately this information isn't present in the API data, so i want to do the same thing by grouping the <release>-nodes with the same <title>-tags, or add a flag to the <releases> that don't have a unique <title>? any good ideas on the best way of doing this? i also like to know if it's possible to count the <release>-nodes (child of releases) that have the same type-attribute? like in this example count the releases with the type "Main"? maybe it's better to do this things with XMLReader or XPath?

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  • How to insert sub root node in xml file

    - by pravakar
    Hi guys hope all are doing good. I want to create one sub root node in my xml file like, <CapitalJobsList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <JobAds> -- element to create <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.500</DateEntered> <AdvertiserJobRef>83754865</AdvertiserJobRef> <Title>IT Operations Manager</Title> <DescriptionShort>Large scale/exciting projects Mentor and manage o...</DescriptionShort> <Description>Large scale/exciting projects Mentor and manage others Management/technical mix This is a fantastic opportunity to join a high profile client who is active across both the commercial and Government domain. As the IT Operations Manager you will be responsible for leading and mentoring a small team of Infrastructure Engineers to ensure the availability and performance of the IT infrastructure. You w</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83754865</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> <JobAd> <AdvertiserDetails> <AdvertiserId>718508549</AdvertiserId> <AdvertiserName>ABC</AdvertiserName> </AdvertiserDetails> <ConsultantDetails> <ContactName>Naga Divakar</ContactName> <ContactPhone>6239 7755</ContactPhone> <ContactEmail>[email protected]</ContactEmail> <ContactFax>12345678912</ContactFax> </ConsultantDetails> <JobAdDetails> <DateEntered>2009-10-03T21:09:35.530</DateEntered> <AdvertiserJobRef>83731488</AdvertiserJobRef> <Title>SAP Developers Required in Canberra - 12 month contract</Title> <DescriptionShort>My client, a large government department in Canbe...</DescriptionShort> <Description>My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. Two SAP Developers Required Expert level ABAP programming skills Large SAP landscape - SAP R/3, SAP Web, SAP BI, SAP ITS My client, a large government department in Canberra, seeks two SAP Developers for 12 month ongoing contracts. My client is a large government department in Canberra, a</Description> <SalaryMin>0.00</SalaryMin> <SalaryMax>0.00</SalaryMax> <WorkType xsi:nil="true" /> <Location>) as [JobAd/JobAdDetails/Bullets], isnull(Job</Location> <PostCode>2600</PostCode> <ClosingDate>2009-11-01T00:00:00</ClosingDate> <Keywords xsi:nil="true" /> <ApplyEmail xsi:nil="true" /> <ApplyURL>http://jobview.careerone.com.au/GetJob.aspx?JobID=83731488</ApplyURL> </JobAdDetails> <JobAdOptions> <BlindPost xsi:nil="true" /> <AdFormatType xsi:nil="true" /> <AdTemplateName xsi:nil="true" /> <ShowContactDetails xsi:nil="true" /> <ShowSalary xsi:nil="true" /> <HasVideo xsi:nil="true" /> <ResumeRequired>1</ResumeRequired> <ResidentsOnly>0</ResidentsOnly> </JobAdOptions> <CategoryList> <Category xsi:nil="true" /> </CategoryList> <RegionsList> <Region>ACT</Region> </RegionsList> <LevelsList> <Level xsi:nil="true" /> </LevelsList> </JobAd> </JobAds> </CapitalJobsList> I have used the sql query for xml path like: select r.advid as [JobAd/AdvertiserDetails/AdvertiserId], CompanyName as [JobAd/AdvertiserDetails/AdvertiserName], firstname +'' ''+ lastname as [JobAd/ConsultantDetails/ContactName], WorkPhone as [JobAd/ConsultantDetails/ContactPhone], AdvEmail as [JobAd/ConsultantDetails/ContactEmail], FaxNo as [JobAd/ConsultantDetails/ContactFax], Job_CreatedDate as [JobAd/JobAdDetails/DateEntered], Job_Id as [JobAd/JobAdDetails/AdvertiserJobRef], Job_Title as [JobAd/JobAdDetails/Title], substring(Job_Description,0,50)+''...'' as [JobAd/JobAdDetails/DescriptionShort], Job_Description as [JobAd/JobAdDetails/Description], CONVERT(DECIMAL(10,2),MinSalary) as [JobAd/JobAdDetails/SalaryMin], CONVERT(DECIMAL(10,2),MaxSalary) as [JobAd/JobAdDetails/SalaryMax], Job_Type as [JobAd/JobAdDetails/WorkType], isnull(Job_Bullets,'') as [JobAd/JobAdDetails/Bullets], isnull(Job_Location,'') as [JobAd/JobAdDetails/Location], Job_PostCode as [JobAd/JobAdDetails/PostCode], Job_ExpireDate as [JobAd/JobAdDetails/ClosingDate], Job_Keywords as [JobAd/JobAdDetails/Keywords], ApplyEmail as [JobAd/JobAdDetails/ApplyEmail], Job_BrandURL+Job_Id as [JobAd/JobAdDetails/ApplyURL], BlindPost as [JobAd/JobAdOptions/BlindPost], AdFormatType as [JobAd/JobAdOptions/AdFormatType], AdTemplateName as [JobAd/JobAdOptions/AdTemplateName], ShowContactDetails as [JobAd/JobAdOptions/ShowContactDetails], ShowSalary as [JobAd/JobAdOptions/ShowSalary], HasVideo as [JobAd/JobAdOptions/HasVideo], ResumeRequired as [JobAd/JobAdOptions/ResumeRequired], ResidentsOnly as [JobAd/JobAdOptions/ResidentsOnly], Job_Category as [JobAd/CategoryList/Category], Job_Location_State as [JobAd/RegionsList/Region], [Level] as [JobAd/LevelsList/Level] from DR_Adv_Registration r, DR_CareerOne_ACTJobs j where r.Advid = j.Advid and job_location_city like(''%'+''+ @City +''+'%'') and job_location_state in('''+ @State +''') and job_status=1 for xml path(''''), Root(''CapitalJobsList''),ELEMENTS XSINIL So, suggest me how to get the sub root node. Thanks in advance

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  • How to decode ASN.1 to XML with erlang

    - by shian
    Hi I use asn1 module in erlang to decode. The output is like {'UL-CCCH-Message',asn1_NOVALUE, {rrcConnectionRequest, {'RRCConnectionRequest', {'tmsi-and-LAI', {'TMSI-and-LAI-GSM-MAP', [1,0,0,0,0,1,1,1,1,1,1,0,1,0,0,0,0,1,1,0,1,1,0,1,0,1,1, 1,1,0,1,0], {'LAI', {'PLMN-Identity',[2,2,6],[0,1]}, [0,1,1,1,1,0,0,1,1,0,0,0,1,1,0,1]}}}, terminatingBackgroundCall,noError, {'MeasuredResultsOnRACH', {'MeasuredResultsOnRACH_currentCell', {fdd, {'MeasuredResultsOnRACH_currentCell_modeSpecificInfo_fdd', {'cpich-Ec-N0',39}}}}, asn1_NOVALUE}, asn1_NOVALUE}}} How can I output XML instead of erlang term?

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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