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  • JQuery pass model to controller

    - by slandau
    I want to pass the mvc page model back to my controller within a Javascript Object. How would I do that? var urlString = "<%= System.Web.VirtualPathUtility.ToAbsolute("~/mvc/Indications.cfc/ExportToExcel")%>"; var jsonNickname = { model: Model, viewName: "<%= VirtualPathUtility.ToAbsolute("~/Views/Indications/TermSheetViews/Swap/CashFlows.aspx")%>", fileName: 'Cashflows.xls' } $.ajax({ type: "POST", url: urlString, data: jsonNickname, async: false, success: function (data) { $('#termSheetPrinted').append(data); } }); So where it says model: Model, I want the Model to be the actual page model that I declare at the top of the page: Inherits="System.Web.Mvc.ViewPage<Chatham.Web.Models.Indications.SwapModel>" How can I do that?

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  • FJSTransitionController setup and use in View Controller not main app delegate

    - by elliotrock
    I am trying to set up Corey Floyd's FJSTransitionController. My app uses a main view controller to manage the main view navigation. I also went through the source to fix it for ARC. Followed instructions and in my main delegate .h I have in the usual spots: FJTransitionController* mainTransitionController; @property (nonatomic,retain) FJTransitionController* mainTransitionController; delegate .m has the following @synthesize mainTransitionController And in the - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions mainTransitionController=[[FJTransitionController alloc] init]; // do I need to instantise? [self.window addSubview:mainTransitionController.view]; [mainTransitionController setViewControllerClass:[[mainViewController sendMissionsPanelViewController] class] forKey:@"missionView"]; The last line is complaining that there is no @interface for FJTransitionController? Any help please.

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  • Question and Answers form & controller problem

    - by user285245
    Hi, I have a Question table and an Answers table linked by questionID (1 to many). I'd like to be able to update both table from the one form. I can easily add a question but to have it also add the answers (into their own recordsets) is causing a headache. how do I set my form up to allow for the answers to be created and also what do I do in the Controller. Any help would be gratefully appreciated as I've not been able to locate any good examples on the web. thanks in advance.

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  • How to pass a variable through url and use it inside a controller

    - by anthonypliu
    I have this controller: public ActionResult Details(String UserName) { using (var db = new MatchGamingEntities()) { var Users = from m in db.Users join m2 in db.MyProfiles on m.UserId equals m2.UserId where m.UserName == UserName select new UserViewModel { UserName = m.UserName, LastActivityDate = m.LastActivityDate, Address = m2.Address, City = m2.City, State = m2.State, Zip = m2.Zip }; return View(Users.SingleOrDefault()); } } I type in the url Profiles/Details/hello, but it does not work, if I do Profiles/Details?UserName=hello then it works. I have another ActionResult just like this except taking in an int id as parameter and it works fine with the first url format.

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  • Problems loading controller from url with codeigniter?

    - by Cody Short
    I'm currently in the process of putting up my first website for public use. I am using the codeigniter framework in order to do this, but I am having trouble loading the controllers from the url. I currently have the default codeigniter installment that you download trying to get things to work. The controller welcome is loaded by default, but when I try to load it through the url it doesn't work. I was having the same problem with the site that I had uploaded earlier. The site is located at this link any help on this would be appreciated.

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  • Rails controller processing as HTML instead of XML

    - by Andy
    I've recently upgraded from Ruby 1.8.6 and Rails 2.3.4 to Ruby 1.9 and Rails 3.0.3. I have the following controller: class ChartController < ApplicationController before_filter :login_required respond_to :html, :xml def load_progress chart.add( :series, "Memorized", y_memorized ) chart.add( :series, "Learning", y_learning ) chart.add( :series, "Mins / Day", y_time ) chart.add( :user_data, :secondary_y_interval, time_axis_interval ) respond_to do |fmt| fmt.xml { render :xml => chart.to_xml } end # Also tried # respond_with chart end end However, when I call the 'load_progress method' I get the following: Started GET "/load_progress.xml" for 127.0.0. Processing by ChartController#load_progress as HTML Completed 406 Not Acceptable in 251ms I have also tried changing the respond_to block to respond_with chart But I get the same response. I've read all the new Rails documentation on the new respond_with format but I can't seem to elicit an XML response. Am desperately hoping someone has some ideas.

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  • How to connect Model through Controller to View using bindings?

    - by Paperflyer
    I have an NSTextField in my view. Its value is bound to an NSNumber *number in my controller. The controller simply calls through to the model (value) to get the appropriate value. // In the controller - (NSNumber *)number { return [NSNumber numberWithFloat:[model value]]; } - (void)setNumber:(NSNumber *)aNumber { [model setValue:[aNumber floatValue]]; } This is fine, only the controller is not notified of model changes and thus, changing the value in the model does not update the NSTextField. The only other option I can think of is to have the model notify the controller and the controller manually update the view through an Outlet. But this circumvents the binding. // In the model, after value change [[NSNotificationCenter defaultCenter] postNotificationName:@"ValueChanged" object:self]; // In the controller, after being notified - (void)updateView:(NSNotification *)aNotification { [myTextField setFloatValue:[model value]]; } Is there a better, binding-aware way to implement this communication?

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  • Micro Controller Serial Data identification or classification

    - by Posiedon
    I have a x51 family micro controller (P89V51RD2). I'm going to send some data from computer using serial port. The data i'll be sending are Character 'S' Character 'R' and a 2 digit integer. Upon receiving the data, I will be calling separate functions. I used if(chr=='S') and elseif(chr=='R')for character data. The main problem lies with identifying the 2 digit number sent. Any other data other than the above three mentioned will be discarded. Any ideas for identifying two digit integer ??

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  • Pass a datatable model to controller action in MVC

    - by user2906420
    Code: @model System.Data.DataTable <button type="submit" class="btn btn-primary" data-dismiss="modal" aria-hidden="true"> Download</button> [HttpPost] public void getCSV(DataTable dt) { MemoryStream stream = Export.GetCSV(dt); var filename = "ExampleCSV.csv"; var contenttype = "text/csv"; Response.Clear(); Response.ContentType = contenttype; Response.AddHeader("content-disposition", "attachment;filename=" + filename); Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.BinaryWrite(stream.ToArray()); Response.End(); } I want to allow the user to export a CSV file when the button is clicked on. the datatable should be passed to the method getCSV. Please can someone help me. thanks I do not mind using Tempdata to store the datatable and then access it in the controller

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  • Pass parameter to controller from @Html.ActionLink MVC 4

    - by NetraSW
    Hello All, @Html.ActionLink("Reply", "BlogReplyCommentAdd", "Blog", new { blogPostId = blogPostId, replyblogPostmodel = Model, captchaValid = Model.AddNewComment.DisplayCaptcha }) In above line: I get error on blogPostId. The parameters dictionary contains a null entry for parameter 'blogPostId' of non-nullable type 'System.Int32' for method 'System.Web.Mvc.ActionResult BlogReplyCommentAdd(Int32, Nop.Web.Models.Blogs.BlogPostModel, Boolean)' in 'Nop.Web.Controllers.BlogController'. An optional parameter must be a reference type, a nullable type, or be declared as an optional parameter. Parameter name: parameters I have already assign a value for this on top such as @{ var blogPostId = Model.Id; } My Controller : public ActionResult BlogReplyCommentAdd(int blogPostId, BlogPostModel model, bool captchaValid) {} M i doing something wrong? Please give me an example on this. Thanks

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  • Problem in building a tab bar inside navigation controller

    - by Heba
    Hello Everyone! I am really frustrated and I rally hope that you will help me to solve this problem! I'm trying to build a tab bar inside a navigation controller. I used this template provided by WiredBob. My problem is that I want to add more bar items to the tab bar, but I keep getting crash! From the log: 2010-05-24 00:15:43.469 NavTab[9315:207] * Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: '-[UITableViewController loadView] loaded the "AnnView" nib but didn't get a UITableView.' Also, I tried to fix the size of the a view in IB to fit in with the tab bar, but I couldn't! It was unchangeable. Thanks in advance :-)

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  • rootview controller in Interface builder?

    - by senthilmuthu
    hi, i have done in didapplicationfinishing function tabBarController = [[UITabBarController alloc] init] ; tabBarController.navigationItem.title = @"News"; SimpleTableViewController *rtbfViewController = [[SimpleTableViewController alloc] init]; //initWithStyle:UITableViewStyleGrouped]; rtbfViewController.tabBarItem.title = @"News1"; rtbfViewController.tabBarItem.image = [UIImage imageNamed:@"home.png"];; UINavigationController *table2NavController = [[[UINavigationController alloc] initWithRootViewController:rtbfViewController] autorelease]; [rtbfViewController release]; it works fine .suppose if i have Navigation controller in Interface Builder,how can i set initWithRootViewController in Interface builder?

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  • Codeigniter: Using data in a controller

    - by Kevin Brown
    I'm new to php and CI, and I'm having some trouble in my controller. I feel that I'm doing this the wrong way, and it could be easier, I just don't know the syntax: $data['members'] = $this->home_model->getUser($id); $credit = $this->home_model->getCredit($id); if ($credit == '0'){stuff...} So I'm getting the user's data that has their the same information as "getCredit" does, but I don't know how to get the single variable that I need for my if statement... How can I just use the "getUser" function so that I'm not pulling redundant information?

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • If a raid controller changes, are the drives still usable without re-formatting?

    - by Jeremy
    I've been wanting to do a raid 1 setup in my home with a pair of sata drives. Someone told me that if the controller fails, you can't just get a new controller because you'll have to reformat the drives. Or is that true only in some implementations? I was originally just looking at an onboard raid controller, or an entry level nas drvice like the intel SS4200-E, but If the hardware (controller) ever fails, will I be out of luck accessing the data if I can't get the exact same hardware to replace it?

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  • MVC : Does Code to save data in cache or session belongs in controller?

    - by newbie
    I'm a bit confused if saving the information to session code below, belongs in the controller action as shown below or should it be part of my Model? I would add that I have other controller methods that will read this session value later. public ActionResult AddFriend(FriendsContext viewModel) { if (!ModelState.IsValid) { return View(viewModel); } // Start - Confused if the code block below belongs in Controller? Friend friend = new Friend(); friend.FirstName = viewModel.FirstName; friend.LastName = viewModel.LastName; friend.Email = viewModel.UserEmail; httpContext.Session["latest-friend"] = friend; // End Confusion return RedirectToAction("Home"); } I thought about adding a static utility class in my Model which does something like below, but it just seems stupid to add 2 lines of code in another file. public static void SaveLatestFriend(Friend friend, HttpContextBase httpContext) { httpContext.Session["latest-friend"] = friend; } public static Friend GetLatestFriend(HttpContextBase httpContext) { return httpContext.Session["latest-friend"] as Friend; }

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  • UITabbar without controller

    - by Etienne
    Hello. I have a simple app where the only view controller has an outlet to a UITabBar. It also implements UITabBarDelegate and is set as the delegate for the UITabBar: @interface TheMainViewController : UIViewController <UITabBarDelegate> { IBOutlet UITabBar *theTabBar; } I implemented the following method Which gets called whenever any of my 4 UITabBarItems get tapped. I tried just doing something really simple: - (void)tabBar:(UITabBar *)tabBar didSelectItem:(UITabBarItem *)item { tabBar.selectedItem = [tabBar.items objectAtIndex:0]; return; } In theory, it should always stay selected on my first tab and it works perfectly when I just tap any UITabBarItem (nothing happens, the first one always stays selected). But when I touch a UITabBarItem and hold it (not taking my finger off) the selection changes anyway ! Debugging, everything gets called properly. It's like changing the selectedItem property doesn't have any effect is the user still has the item "down" (with his finger on it). What would be a good workaround? I tried overloading UITabBar and messing with touchesBegan and touchesEnd but they don't even get called. Same with UITabBarItem. Oh and please don't suggest using a UITabBarController as it is not flexible enough for my application. So frustrating....thanks!

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  • Android custom media controller using vidtry

    - by Mathias Lin
    I want to use a custom media controller in my Android app and therefore looking at the vidtry code (http://github.com/commonsguy/vidtry), especially Player.java: The sample works fine as it comes. But I want the sample to play the fixed video automatically on app startup (so I don't want to enter a URL). I added: @Override public void onStart() { super.onStart(); address.setText("/sdcard/mydata/category/1/video_agkkr6me.mp4"); go.setEnabled(true); onGo.onClick(go); } Strange thing here is that if I run the app, the audio of the video plays but the image doesn't show. Everything else works fine (progress bar, etc.). I can't figure out the difference between the manual click on the go-button and the programmatic one. I looked at the code and didn't see any difference that might occur between manual and programmatic click. I checked if any elements (esp. surface) might be hidden, but it's not. I even tried a surface.setVisibility(View.INVISIBLE); surface.setVisibility(View.VISIBLE); in case some issue with the redrawing, but no difference. The video image does show when I manually hit the go button, but just not on start up automatically.

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  • How Can i reload data in tableview in view controller in iphone

    - by Pugal Devan
    Hi, I am new to iphone development. I have created 5 buttons in the view. On clicking the buttons it navigates to the corresponding views. On clicking the "News" button it navigates and displayed the parsing details in the table view.(This table view, I have created View controller and added table view using Interface Builder and i have set all the properties.) and i go to another button and comes back to the "News" button, every time parsing will happened.How to avoid the multiple parsing when i come back to the button. i have tried this one and my code is, - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; static int i; if(i == 0) { NSString * path = @"http://www.AAAAAAAAAAAAAAAA.com"; [self parseXMLFileAtURL:path]; i++; } [self.newsTable reloadData]; } } Now the parsing is happened only time but the datas are doesnt displayed. My problem is the tableview doesnot reload. newsTable is the instance of the Tableview. How can i achieve this. Please help me out. Thanks.

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  • Implement System.Web.Caching.Cache Object in a controller to cache specific query

    - by Julien
    Hello World! I'm Julien and I have a question is it correct to implement my caching object like this in my controller : public class HomeController : BaseController { public static Cache cachingControl = new Cache(); ... And I Use it like this : public ActionResult Home() { IndexViewData view = new IndexViewData(); view.UserId = UserId; if (cachingControl.Get("viewHome") != null) { view = (IndexViewData)cachingControl.Get("viewHome"); } else { view.allAdsList = AllAds(5000, 0); if (Request.QueryString["voirTous"] != null) view.loadGeneral(true); else view.loadGeneral(false); cachingControl.Insert("viewHome", view); } view.adsList = SetupSearch(5, false, 0); return View(view); } But When I Call this line : if (cachingControl.Get("viewHome") != null) { They trow me the error NullErrorException But I know it can be null this is why i'm put this condition to Do you have an alternative or a tips for me thank you! P.S.: I Know that the code is weird :P but I must to support it ... Julien

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  • iphone cannot rotate views in TabBar controller

    - by Luc
    Hello, I am working on an application that consists of a TabBar controller. Within on of its tab, I have a subclass of UITableViewController, within this list I have a Core-plot graph in the first cell and some other data in the 4 following cells. When I return YES in the shouldAutorotateToInterfaceOrientation method, I would expect the autoresizing of the list view to happen, but... nothing. When I add some log in the willRotateToInterfaceOrientation method, they are not displayed. Is there something I missed ? Thanks a lot, Luc // Override to allow orientations other than the default portrait orientation. - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { // Return YES for supported orientations //return (interfaceOrientation == UIInterfaceOrientationPortrait); NSLog(@"Orientation"); return YES; } - (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration { [super willRotateToInterfaceOrientation:toInterfaceOrientation duration:duration]; NSLog(@"Rotating"); if (toInterfaceOrientation == UIInterfaceOrientationLandscapeRight) { NSLog(@"view land:%@", self.view); } if (toInterfaceOrientation == UIInterfaceOrientationPortrait) { NSLog(@"view portrait:%@", self.view); } }

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  • Nav Controller, UITableViewController, UITextField to become firstResponder?

    - by Daniel Granger
    I have a core data application which uses a navigation controller to drill down to a detail view and then if you edit one of the rows of data in the detail view you get taken to an Edit View for the that single line, like in Apples CoreDataBooks example! The edit view is a UITableviewController which creates its table with a single section single row and a UITextfield in the cell, programatically. What I want to happen is when you select a row to edit and the edit view is pushed onto the nav stack and the edit view is animated moving across the screen, I want the textfield to be selected as firstResponder so that the keyboard is already showing as the view moves across the screen to take position. Like in the Contacts app or in the CoreDataBooks App. I currently have the following code in my app which causes the view to load and then you see the keyboard appear (which isn't what I want, I want the keyboard to already be there) - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; [theTextField becomeFirstResponder]; } You can't put this in -viewWillAppear as the textfield hasn't been created yet so theTextField is nil. In the CoreDataBooks App where they achieve what i want they load there tableview from a nib so they use the same code but in -viewWillAppear as the textfield has already been created! Is there anyway of getting around this without creating a nib, I want to keep the implementation programatic to enable greater flexibility. Many Thanks

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  • .net mvc pass dictionary data from view to controller

    - by Wei Ma
    A while ago, I was trying to pass a dictionary data from my view to my controller. And I was able to do so after googling on the net(remember it was one of scott hanselman's posts). The solution I had was something like <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties["+index+"].Key"%>"/> <input type="hidden" name="<%="properties["+index+"].Value"%>"/> <%}%> public ActionResult Process(IDictionary<string,string> properties) { doSomething(); return View(); } The code worked for awhile and then I did some refactoring and got rid of this chunk of code. Today, I ran into a situation in which I would like to pass a dictionary again. But no matter how hard I try, the properties parameter received by the action was always null. I tried the above code and <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties.Keys["+index+"]"%>"/> <input type="hidden" name="<%="properties.Values["+index+"]"%>"/> <%}%> Neither code worked. I googled again but couldn't find the post that helped me before. Can someone point out what I did wrong? thanks a million.

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  • Backbone Model fetched from Lithium controller is not loaded properly in bb Model

    - by Nilesh Kale
    I'm using backbone.js and Lithium. I'm fetching a model from the server by passing in a _id that is received as a hidden parameter on the page. The database MongoDB has stored the data correctly and can be viewed from console as: { "_id" : ObjectId("50bb82694fbe3de417000001"), "holiday_name" : "SHREE15", "description": "", "star_rating" : "3", "holiday_type" : "family", "rooms" : "1", "adults" : "2", "child" :"0", "emails" : "" } The Lithium Model class is so: class Holidays extends \lithium\data\Model { public $validates = array( 'holiday_name' => array( array( 'notEmpty', 'required' => true, 'message' => 'Please key-in a holiday name! (eg. Family trip for summer holidays)' ))); } The backbone Holiday model is so: window.app.IHoliday = Backbone.Model.extend({ urlRoot: HOLIDAY_URL, idAttribute: "_id", id: "_id", // Default attributes for the holiday. defaults: { }, // Ensure that each todo created has `title`. initialize: function(props) { }, The code for backbone/fetch is: var Holiday = new window.app.IHoliday({ _id: holiday_id }); Holiday.fetch( { success: function(){ alert('Holiday fetched:' + JSON.stringify(Holiday)); console.log('HOLIDAY Fetched: \n' + JSON.stringify(Holiday)); console.log('Holiday name:' + Holiday.get('holiday_name')); } } ); Lithium Controller Code is: public function load($holiday_id) { $Holiday = Holidays::find($holiday_id); return compact('Holiday'); } PROBLEM: The output of the backbone model fetched from server is as below and the Holiday model is not correctly 'formed' when data returns into backbone Model: HOLIDAY Fetched: {"_id":"50bb82694fbe3de417000001","Holiday":{"_id":"50bb82694fbe3de417000001","holiday_name":"SHREE15","description":"","star_rating":"3","holiday_type":"family","rooms":"1","adults":"2","child":"0","emails":""}} iplann...view.js (line 68) Holiday name:undefined Clearly there is some issue when the data is passed/translated from Lithium and loaded up as a model into backbone Holiday model. Is there something very obviously wrong in my code?

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  • Java JSP/Servlet: controller servlet throwing the famous stack overflow

    - by NoozNooz42
    I've read several docs and I don't get it: I know I'm doing something wrong but I don't understand what. I've got a website that is entirely dynamically generated: there's hardly any static content at all. So, trying to understand JSP/Servlet, I've written my own "front controller" intercepting every single query, it looks like this: <servlet-mapping> <servlet-name>defaultservlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> Basically I want any user request, like: example.org example.org/bar example.org/foo.html to all go through a default servlet which I've written. The servlet then examines the URI and find to which .jsp the request must be dispatched, and then does, after having set all the attributes correctly, a: RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/WEB-INF/jsp/index.jsp"); dispatcher.forward(req, resp); When I'm using a url-pattern (in web.xml) like, say, *.html, everything works fine. But when I change it to /* (to really intercept everything), I enter an endless loop and it ends up with a... StackOverflow :) When the request is dispatched, is the URI ".../WEB-INF/jsp/index.jsp" itself matched by the web.xml filter /* that I set? How should I do if I want to intercept everything using a /* url-pattern and yet be able to dispatch/forward/? I'm not asking about specs/Javadocs here: I'm really confused about the bigger picture and I'd need some explanation as to what could be going on. Am I not supposed to intercept really everything? If I can intercept everything, what should I be aware of regarding forwarding/dispatching?

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