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  • query excuting problem

    - by srini-r85
    hi, i tried to execute following query in php script. $db_selected = mysql_select_db("lumiinc1_sndemo1", $con); if ($db_selected) { echo "database connected"; } else { die ("Can\'t use db : " . mysql_error()); } $sql = "INSERT INTO `markers` ( `name`, `address`, `lat`, `lng`, `id` ) SELECT `name`, `street`, `latitude`, `longitude`, `lid` FROM `location` WHERE NOT EXISTS ( SELECT * FROM `markers` WHERE `location`.`lid` = `markers`.`id` )"; $result = mysql_query($sql); if ($result) { echo "Query executed OK"; } else { die("Invalid query: " . mysql_error()); } script does not show any error.also query executed.but i didn't get my expected result.at the same i try this query in phpmyAdmin i got my expected result. i dont know the cause of this problem. plz any one find the problem . thanks

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  • Extract multiple values from one column in MySql

    - by Neil
    I've noticed that MySql has an extensive search capacity, allowing both wildcards and regular expressions. However, I'm in somewhat in a bind since I'm trying to extract multiple values from a single string in my select query. For example, if I had the text "<span>Test</span> this <span>query</span>", perhaps using regular expressions I could find and extract values "Test" or "query", but in my case, I have potentially n such strings to extract. And since I can't define n columns in my select statement, that means I'm stuck. Is there anyway I could have a list of values (ideally separated by commas) of any text contained with span tags? In other words, if I ran this query, I would get "Test,query" as the value of spanlist: select <insert logic here> as spanlist from HtmlPages ...

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  • Rails 3 query in multiple date ranges

    - by NeoRiddle
    Suppose we have some date ranges, for example: ranges = [ [(12.months.ago)..(8.months.ago)], [(7.months.ago)..(6.months.ago)], [(5.months.ago)..(4.months.ago)], [(3.months.ago)..(2.months.ago)], [(1.month.ago)..(15.days.ago)] ] and a Post model with :created_at attribute. I want to find posts where created_at value is in this range, so the goal is to create a query like: SELECT * FROM posts WHERE created_at BETWEEN '2011-04-06' AND '2011-08-06' OR BETWEEN '2011-09-06' AND '2011-10-06' OR BETWEEN '2011-11-06' AND '2011-12-06' OR BETWEEN '2012-01-06' AND '2012-02-06' OR BETWEEN '2012-02-06' AND '2012-03-23'; If you have only one range like this: range = (12.months.ago)..(8.months.ago) we can do this query: Post.where(:created_at => range) and query should be: SELECT * FROM posts WHERE created_at BETWEEN '2011-04-06' AND '2011-08-06'; Is there a way to make this query using a notation like this Post.where(:created_at => range)? And what is the correct way to build this query? Thank you

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  • mysql_real_escape_string and search data in mySql DB

    - by ryrysz
    I have problem with php function : mysql_real_escape_string My test string: @,&!#$%^*()_+' "\/ I add this data to mySql database, like that (in short): $str = mysql_real_escape_string($str); $sql = "INSERT INTO table(company) VALUES('".$str. "')"; In DB is stored as: @,&!#$%^*()_+\' \"\\/ But problem is with find this data by SELECT statement. I want find, company where name is like ' " My SELECT's: SELECT company FROM table WHERE company LIKE '%\' "%'; SELECT company FROM table WHERE company LIKE '%\\' \\"%'; ; not working. This works: SELECT `company` FROM `table` WHERE `company` LIKE '%\\\' \\\\"%'; and SELECT `company` FROM `table` WHERE `company` LIKE '%\\\\\\\' \\\\\\\"%' But I dont know why this work :(. My questions are: why must add so many slashes ? how I can make correct query in PHP: $query = '\' "'; '%'.mysql_real_escape_string($query).'%' result is : '%\' \"%' '%'.mysql_real_escape_string(mysql_real_escape_string($query)).'%' result is : '%\\\' \\\"%' '%'.mysql_real_escape_string(mysql_real_escape_string(mysql_real_escape_string($query))).'%' result is : '%\\\\\\\' \\\\\\\"%' Only last one works good.

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  • mysql reference result from subquery

    - by iamrohitbanga
    this is what i am doing update t1 set x=a,y=b where a and b are obtained from (select query here) i know the select query the select query returns multiple results which are the same when i use group by or distinct query execution slows down considerably a and b are forward references so mysql reports an error i want to set a equal to the value obtained in the first row and b equal to the value obtained in the first row for the respective columns, to avoid group by. i don't know how to refer to the first result from the select query. how can i achieve all this?

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  • if specific row = null, execute query

    - by fusion
    how do i check if the value of a column is null, and only then execute the query? for example: col1 col2 col3 01 abc i run a query which first checks if the record exists or not; if it exists, it should execute the update query and if it doesn't exist, it executes the insert query. how do i check if col3 is null and if it is null, it should execute the update query. . $sql = "SELECT uid FROM `users` WHERE uid = '" . $user_id . "'"; $result = mysql_query($sql,$conn) or die('Error:' .mysql_error()); $totalrows = mysql_num_rows($result); if($totalrows < 1) { insertUser($user_id,$sk, $conn); } else { updateSessionKey($user_id,$sk,$conn); }

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  • The case of the mysterious MySQL caching across restarts

    - by shanusmagnus
    I found a very slow MySQL query in my web app. The weird thing is that the query is only slow the first time it's executed, despite the fact that the query_cache is set to its default (query_cache_size 0) like so: mysql> show variables like 'query%'; +------------------------------+---------+ | Variable_name | Value | +------------------------------+---------+ | query_alloc_block_size | 8192 | | query_cache_limit | 1048576 | | query_cache_min_res_unit | 4096 | | query_cache_size | 0 | | query_cache_type | ON | | query_cache_wlock_invalidate | OFF | | query_prealloc_size | 8192 | +------------------------------+---------+ The even weirder thing is that this speedup persists even after the MySQL server has been stopped and restarted (I'm using OSX, and perform this restart using the system preferences pane.) The only way I can re-create the poor performance of the initial query is by rebooting the system. So my question is: how is this happening? Obviously some sort of caching at work, but where? And how does it persist across database restarts? This query is mediated through our web app, which comes via PHP/Apache, but there are no extra bells and whistles, and the curious caching also persists across Apache restarts. Help?

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  • Unable to initialize provider. Missing or incorrect schema. for MySql.Web connector

    - by Jreeter
    Hey guys and gals running into a little issue here.. I'm trying to use MySql Connector 6.2.2.0 for membership and role providers.. The issue I'm having is: Unable to initialize provider. Missing or incorrect schema. <authentication mode="Forms"/> <roleManager defaultProvider="MySqlRoleProvider" enabled="true" cacheRolesInCookie="true" cookieName=".ASPROLES" cookieTimeout="30" cookiePath="/" cookieRequireSSL="false" cookieSlidingExpiration="true" cookieProtection="All" > <providers> <clear /> <add name="MySqlRoleProvider" type="MySql.Web.Security.MySQLRoleProvider, MySql.Web, Version=6.2.2.0,Culture=neutral, PublicKeyToken=c5687fc88969c44d" connectionStringName="mySQL" applicationName="capcafe" writeExceptionsToEventLog="true" /> </providers> </roleManager> <membership defaultProvider="MySqlMembershipProvider"> <providers> <add connectionStringName="mySQL" applicationName="capcafe" minRequiredPasswordLength="5" requiresQuestionAndAnswer="false" requiresUniqueEmail="false" minRequiredNonalphanumericCharacters="0" name="MySqlMembershipProvider" type="MySql.Web.Security.MySQLMembershipProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" /> </providers> </membership> Here is the line it doesn't seem to like: Line 57: type="MySql.Web.Security.MySQLRoleProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" I have both MySql.Web and MySql.Data referenced and in my bin! Any help resolving this issue will be very much appreciated

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  • Long connection times from PHP to MySQL on EC2

    - by Erik Giberti
    I'm having an intermittent issue connecting to a database slave with InnoDB. Intermittently I get connections taking longer than 2 seconds. These servers are hosted on Amazon's EC2. The app server is PHP 5.2/Apache running on Ubuntu. The DB slave is running Percona's XtraDB 5.1 on Ubuntu 9.10. It's using an EBS Raid array for the data storage. We already use skip name resolve and bind to address 0.0.0.0. This is a stub of the PHP code that's failing $tmp = mysqli_init(); $start_time = microtime(true); $tmp-options(MYSQLI_OPT_CONNECT_TIMEOUT, 2); $tmp-real_connect($DB_SERVERS[$server]['server'], $DB_SERVERS[$server]['username'], $DB_SERVERS[$server]['password'], $DB_SERVERS[$server]['schema'], $DB_SERVERS[$server]['port']); if(mysqli_connect_errno()){ $timer = microtime(true) - $start_time; mail($errors_to,'DB connection error',$timer); } There's more than 300Mb available on the DB server for new connections and the server is nowhere near the max allowed (60 of 1,200). Loading on both servers is < 2 on 4 core m1.xlarge instances. Some highlights from the mysql config max_connections = 1200 thread_stack = 512K thread_cache_size = 1024 thread_concurrency = 16 innodb-file-per-table innodb_additional_mem_pool_size = 16M innodb_buffer_pool_size = 13G Any help on tracing the source of the slowdown is appreciated. [EDIT] I have been updating the sysctl values for the network but they don't seem to be fixing the problem. I made the following adjustments on both the database and application servers. net.ipv4.tcp_window_scaling = 1 net.ipv4.tcp_sack = 0 net.ipv4.tcp_timestamps = 0 net.ipv4.tcp_fin_timeout = 20 net.ipv4.tcp_keepalive_time = 180 net.ipv4.tcp_max_syn_backlog = 1280 net.ipv4.tcp_synack_retries = 1 net.core.rmem_max = 16777216 net.core.wmem_max = 16777216 net.ipv4.tcp_rmem = 4096 87380 16777216 net.ipv4.tcp_wmem = 4096 87380 16777216 [EDIT] Per jaimieb's suggestion, I added some tracing and captured the following data using time. This server handles about 51 queries/second at this the time of day. The connection error was raised once (at 13:06:36) during the 3 minute window outlined below. Since there was 1 failure and roughly 9,200 successful connections, I think this isn't going to produce anything meaningful in terms of reporting. Script: date /root/database_server.txt (time mysql -h database_Server -D schema_name -u appuser -p apppassword -e '') /dev/null 2 /root/database_server.txt Results: === Application Server 1 === Mon Feb 22 13:05:01 EST 2010 real 0m0.008s user 0m0.001s sys 0m0.000s Mon Feb 22 13:06:01 EST 2010 real 0m0.007s user 0m0.002s sys 0m0.000s Mon Feb 22 13:07:01 EST 2010 real 0m0.008s user 0m0.000s sys 0m0.001s === Application Server 2 === Mon Feb 22 13:05:01 EST 2010 real 0m0.009s user 0m0.000s sys 0m0.002s Mon Feb 22 13:06:01 EST 2010 real 0m0.009s user 0m0.001s sys 0m0.003s Mon Feb 22 13:07:01 EST 2010 real 0m0.008s user 0m0.000s sys 0m0.001s === Database Server === Mon Feb 22 13:05:01 EST 2010 real 0m0.016s user 0m0.000s sys 0m0.010s Mon Feb 22 13:06:01 EST 2010 real 0m0.006s user 0m0.010s sys 0m0.000s Mon Feb 22 13:07:01 EST 2010 real 0m0.016s user 0m0.000s sys 0m0.010s [EDIT] Per a suggestion received on a LinkedIn question, I tried setting the back_log value higher. We had been running the default value (50) and increased it to 150. We also raised the kernel value /proc/sys/net/core/somaxconn (maximum socket connections) to 256 on both the application and database server from the default 128. We did see some elevation in processor utilization as a result but still received connection timeouts.

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  • Unable to access MySQL from MyPHPAdmin after setting root password in EasyPHP{WAMP}

    - by Codex
    Am a new starter with WAMP and trying to play around my way using the EasyPHP setup. After successful setup on intial launch of MySQL, the page prompted me to set up ROOT password for security reasons. On setting the password, am no longer able to access MySQL. The error is : Error MySQL said: Documentation 1045 - Access denied for user 'root'@'localhost' (using password: NO) Looked up on the net and tried the following options in the config.inc.php from the phpmyadmin foler: 1] Set the authetication to "http" so that it prompts to enter the username and password /* Authentication type */ $cfg['Servers'][$i]['auth_type'] = 'http'; 2] Set up the correct password in the config file $cfg['Servers'][$i]['password'] = 'myPwd'; None of them worked. Can anyone suggest a workaround to access MySQL? Am not fussed about not being able to use the root account but would like to CRUD on the database using other username. Thanks in advance.

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  • Mysql- “FLUSH TABLES WITH READ LOCK” started automatically

    - by mingyeow
    I would like to understand how this happened. I was running a query that would take a long time, but should not lock up any table. However, my dbs were practically down - it seems like it was being locked up by "FLUSH TABLES WITH READ LOCK" 03:21:31 select type_id, count(*) from guid_target_infos group by type_id 02:38:11 select type_id, count(*) from guid_infos group by type_id 02:24:29 FLUSH TABLES WITH READ LOCK But i did not start this command. can someone tell me why it was started automatically?

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  • Mysql server update cause error in php myadmin.

    - by Avinash
    Hi I have updated my mysql server from 5.0 to 5.1.x. before it works fine, but after upgrading its displaying error in my phpmyadmin. Error is as below: "Your PHP MySQL library version 5.0.51a differs from your MySQL server version 5.1.45. This may cause unpredictable behavior." I am not getting what to do with this. Hope i am clear to all. Thanks in advance Avinash

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  • mysql query using jdbc

    - by S.PRATHIBA
    Hi all, I need to retrieve the last 20 values from my database.For example I have the following table Service_ID Service_Type consumer_feedback | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 37 | Printer | 0 | | 39 | Printer | -1 | | 39 | Printer | 0 | | 40 | Printer | 0 | I need to retrieve last 10 values from the table.I need to do the operation using jdbc.I have attached the sample code.Kindly help me. import java.io.; import java.sql.; public class CountRows2 { public static void main(String[] args) { System.out.println("Count number of rows in a specific table!"); Connection con = null; int count = 0; try{ Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection ("jdbc:mysql://localhost:3306/prathi","root","mysql"); try{ Statement st = con.createStatement(); ResultSet res1 = st.executeQuery("SELECT COUNT(*) FROM consumer1" ); while (res1.next()){ count = res1.getInt(1); } System.out.println("Number of column:"+count); } catch (SQLException s){ System.out.println("SQL statement is not executed!"); } } catch (Exception e){ e.printStackTrace(); } try{ Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection ("jdbc:mysql://localhost:3306/prathi","root","mysql"); try{ Statement st = con.createStatement(); ResultSet res1 = st.executeQuery("SELECT * FROM consumer1 LIMIT count-10,10"); while (res1.next()){ int Service = res1.getInt(1); String s1 = res1.getString(2); int feedback=res1.getInt(3); } System.out.println("Service" + " " +"s1" + " " +"feedback"); } catch (SQLException s){ System.out.println("SQL statement is not executed!"); } } catch (Exception e){ e.printStackTrace(); } } } I am getting the output as: C:javac CountRows2.java C:java CountRows2 Count number of rows in a specific table! Number of column:558 SQL statement is not executed! Thanks a lot....

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  • 'undefined method init for Mysql:Class'

    - by sscirrus
    I've been having problems with a MySQL Server installation that got messed up after a power outage. Configuration Intel i5 Mac running OS X 10.6.5 Ruby 1.9.2 installed Rails 3.0.1 installed MySQL Server (finally) installed and running I completely reinstalled MySQL, which deleted the local development/test/production databases. So, I have run create database development; in MySQL to get the dev database ready for a migration. Current Goal Run rake db:migrate to get my databases back again. (I cannot currently access my databases or Mysql at all from Rails.) Error Using the gem 'mysql', '2.8.1' and run rake db:migrate, I get the error: rake aborted! undefined method 'init' for Mysql:Class Stack Trace: /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/mysql_adapter.rb:30:in 'mysql_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:230:in 'new_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:238:in 'checkout_new_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:194:in 'block (2 levels) in checkout' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:190:in 'loop' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:190:in 'block in checkout' /Users/sscirrus/.rvm/rubies/ruby-1.9.2-p0/lib/ruby/1.9.1/monitor.rb:201:in 'mon_synchronize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:189:in 'checkout' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:96:in 'connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:318:in 'retrieve_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_specification.rb:97:in 'retrieve_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_specification.rb:89:in 'connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:486:in 'initialize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:433:in 'new' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:433:in 'up' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:415:in 'migrate' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/railties/databases.rake:142:in 'block (2 levels) in <top (required)>' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:636:in 'call' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:636:in 'block in execute' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:631:in 'each' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:631:in 'execute' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:597:in 'block in invoke_with_call_chain' /Users/sscirrus/.rvm/rubies/ruby-1.9.2-p0/lib/ruby/1.9.1/monitor.rb:201:in 'mon_synchronize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:590:in 'invoke_with_call_chain' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:583:in 'invoke' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2051:in 'invoke_task' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'block (2 levels) in top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'each' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'block in top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2068:in 'standard_exception_handling' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2023:in 'top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2001:in 'block in run' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2068:in 'standard_exception_handling' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:1998:in 'run' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/bin/rake:31:in '<top (required)>' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/bin/rake:19:in 'load' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/bin/rake:19:in '<main>'

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  • mysql query to dynamically convert row data to columns

    - by Anirudh Goel
    I am working on a pivot table query. The schema is as follows Sno, Name, District The same name may appear in many districts eg take the sample data for example 1 Mike CA 2 Mike CA 3 Proctor JB 4 Luke MN 5 Luke MN 6 Mike CA 7 Mike LP 8 Proctor MN 9 Proctor JB 10 Proctor MN 11 Luke MN As you see i have a set of 4 distinct districts (CA, JB, MN, LP). Now i wanted to get the pivot table generated for it by mapping the name against districts Name CA JB MN LP Mike 3 0 0 1 Proctor 0 2 2 0 Luke 0 0 3 0 i wrote the following query for this select name,sum(if(District="CA",1,0)) as "CA",sum(if(District="JB",1,0)) as "JB",sum(if(District="MN",1,0)) as "MN",sum(if(District="LP",1,0)) as "LP" from district_details group by name However there is a possibility that the districts may increase, in that case i will have to manually edit the query again and add the new district to it. I want to know if there is a query which can dynamically take the names of distinct districts and run the above query. I know i can do it with a procedure and generating the script on the fly, is there any other method too? I ask so because the output of the query "select distinct(districts) from district_details" will return me a single column having district name on each row, which i will like to be transposed to the column.

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  • An abundance of LINQ queries and expressions using both the query and method syntax.

    - by nikolaosk
    In this post I will be writing LINQ queries against an array of strings, an array of integers.Moreover I will be using LINQ to query an SQL Server database. I can use LINQ against arrays since the array of strings/integers implement the IENumerable interface. I thought it would be a good idea to use both the method syntax and the query syntax. There are other places on the net where you can find examples of LINQ queries but I decided to create a big post using as many LINQ examples as possible. We...(read more)

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  • Problem in importing database in MySQL

    - by Krt_Malta
    I have a .sql file with some database backups inside. Now I want to restore them back to MySQL. How can I this using command line of MySqL please? I found this: mysql -u username -p -h localhost database_name < dumpfile.sql but I don't know what username should be, what database_name should be and how I could browse to a .sql file in another folder.

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  • [RESTful] Calculation with RESTful web service with MySQL database : )

    - by Dobby
    Dears, I am now making some RESTful web service with MySQL database. I used NetBeans to create the resources of RESTful service with MySQL, and now I can now using GET and POST/PUT to list and add/modify data entities in the MySQL server. Currently, I wish to make some calculations right after a client makes the POST activities, then the posted data with calculated results will be inserted into the MySQL database. I am very new to this, I guess I need to add some functions and call them to calculate but I don't know where and how to do that : ( Could any one help me on this issue? Thanks a lot in advance! : ) Best! Dobby

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  • cakephp paginate using mysql SQL_CALC_FOUND_ROWS

    - by michael
    I'm trying to make Cakephp paginate take advantage of the SQL_CALC_FOUND_ROWS feature in mysql to return a count of total rows while using LIMIT. Hopefully, this can eliminate the double query of paginateCount(), then paginate(). http://dev.mysql.com/doc/refman/5.0/en/information-functions.html#function_found-rows I've put this in my app_model.php, and it basically works, but it could be done better. Can someone help me figure out how to override paginate/paginateCount so it executes only 1 SQL stmt? /** * Overridden paginateCount method, to using SQL_CALC_FOUND_ROWS */ public function paginateCount($conditions = null, $recursive = 0, $extra = array()) { $options = array_merge(compact('conditions', 'recursive'), $extra); $options['fields'] = "SQL_CALC_FOUND_ROWS `{$this->alias}`.*"; Q: how do you get the SAME limit value used in paginate()? $options['limit'] = 1; // ideally, should return same rows as in paginate() Q: can we somehow get the query results to paginate directly, without the extra query? $cache_results_from_paginateCount = $this->find('all', $options); /* * note: we must run the query to get the count, but it will be cached for multiple paginates, so add comment to query */ $found_rows = $this->query("/* do not cache for {$this->alias} */ SELECT FOUND_ROWS();"); $count = array_shift($found_rows[0][0]); return $count; } /** * Overridden paginate method */ public function paginate($conditions, $fields, $order, $limit, $page = 1, $recursive = null, $extra = array()) { $options = array_merge(compact('conditions', 'fields', 'order', 'limit', 'page', 'recursive'), $extra); Q: can we somehow get $cache_results_for_paginate directly from paginateCount()? return $cache_results_from_paginateCount; // paginate in only 1 SQL stmt return $this->find('all', $options); // ideally, we could skip this call entirely }

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  • Oracle Announces New Oracle VM Template for MySQL Enterprise Edition

    - by Zeynep Koch
     Oracle announces new Oracle VM template for MySQL Enterprise Edition enabling more efficient and lower cost deployments of virtualized MySQL environments. Here are some of the details and benefits: The new Oracle VM Template for MySQL helps eliminate manual configuration efforts and risks by providing a pre-installed, pre-configured and certified software stack that includes Oracle VM Server for x86, Oracle Linux with the Unbreakable Enterprise Kernel and MySQL Enterprise Edition. By pre-integrating the world’s most popular open source database with Oracle Linux and Oracle Virtualization technologies, enterprise users and ISVs can quickly and easily deploy and manage a virtualized MySQL database server for Web and cloud-based applications. Backed by Oracle’s world-class support organization and the result of extensive integration and quality assurance testing, the Oracle VM Template for MySQL Enterprise Edition further demonstrates Oracle’s investment in MySQL and allows users to benefit from a single point of contact for 24/7 technical support for all pre-configured components. Read more in this white paper. 

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  • How to Connect Crystal Reports to MySQL directly by C# code without DSN or a DataSet

    - by Yanko Hernández Alvarez
    How can I connect a Crystal Report (VS 2008 basic) to a MySQL DB without using a DSN or a preload DataSet using C#? I need install the program on several places, so I must change the connection parameters. I don't want to create a DSN on every place, nor do I want to preload a DataSet and pass it to the report engine. I use nhibernate to access the database, so to create and fill the additional DS would take twice the work and additional maintenance later. I think the best option would be to let the crystal reports engine to connect to MySQL server by itself using ODBC. I managed to create the connection in the report designer (VS2008) using the Database Expert, creating an ODBC(RDO) connection and entering this connection string "DRIVER={MySQL ODBC 5.1 Driver};SERVER=myserver.mydomain" and in the "Next" page filling the "User ID", "Password" and "Database" parameters. I didn't fill the "Server" parameter. It worked. As a matter of fact, if you use the former connection string, it doesn't matter what you put on the "Server" parameter, it seems the parameter is unused. On the other hand, if you use "DRIVER={MySQL ODBC 5.1 Driver}" as a connection string and later fill the "Server" parameter with the FQDN of the server, the connection doesn't work. How can I do that by code? All the examples I've seen till now, use a DSN or the DataSet method. I saw the same question posted but for PostgreSQL and tried to adapt it to mysql, but so far, no success. The first method: Rp.Load(); Rp.DataSourceConnections[0].SetConnection("DRIVER={MySQL ODBC 5.1 Driver};SERVER=myserver.mydomain", "database", "user", "pass"); Rp.ExportToDisk(ExportFormatType.PortableDocFormat, "report.pdf"); raise an CrystalDecisions.CrystalReports.Engine.LogOnException during ExportToDisk Message="Logon failed.\nDetails: IM002:[Microsoft][ODBC Driver Manager] Data source name not found and no default driver specified.\rError in File temporal file path.rpt:\nUnable to connect: incorrect log on parameters. the InnerException is an System.Runtime.InteropServices.COMException with the same message and no InnerException The "no default driver specified" makes me wonder if the server parameter is unused here too (see above). In that case: How can I specify the connection string? I haven't tried the second method because it doesn't apply. Does anybody know the solution?

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  • MySQL installation question.

    - by srtriage
    I am far from a DBA and have a question. Recently I installed MySQL. On my machine C:\ is a 50GB partition of two mirrored 10k SAS drives. The remaining space on those drives is allocated to D:. I also have a SSD mounted as E:. When I installed MySQL, I installed it to E:\ assuming that that is where the database information would be held since I had installed it there. I am now seeing C:\ProgramData\MySQL\MySQL Server 5.1\data\peq, peq being the name of my main database. Is my database being stored in C:\ and if so, how do I fix it to store the DB on the SSD?

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