Search Results

Search found 2960 results on 119 pages for 'println'.

Page 85/119 | < Previous Page | 81 82 83 84 85 86 87 88 89 90 91 92  | Next Page >

  • How to stop Interruptible Threads in Java

    - by Dr.Lesh
    I have a Java application that I CAN'T EDIT that starts a Thread wich has this run method: public void run(){ while(true){ System.out.println("Something"); } } And at a certain moment I wanna stop it, but if I use thread.interrupt(); it won't work. If I use thread.stop(); it works, but this method is deprecated and its use is discouraged because soon it will be removed from JVM. Does anyone knows how to do it? Thank you.

    Read the article

  • Simple Question:Output of below Java program

    - by Abhishek Jain
    public class abc1 { private String s; public abc1(String s){this.s=s;} public static void main(String args[]) { HashSet<Object> hs=new HashSet<Object>(); abc1 a1= new abc1("abc"); abc1 a2= new abc1("abc"); String s1= new String("abc"); String s2= new String("abc"); hs.add(a1); hs.add(a2); hs.add(s1); hs.add(s2); System.out.println(hs.size()); } } Why above program output is 3?

    Read the article

  • Java regex skipping matches

    - by Mihail Burduja
    I have some text; I want to extract pairs of words that are not separated by punctuation. Thi is the code: //n-grams Pattern p = Pattern.compile("[a-z]+"); if (n == 2) { p = Pattern.compile("[a-z]+ [a-z]+"); } if (n == 3) { p = Pattern.compile("[a-z]+ [a-z]+ [a-z]+"); } Matcher m = p.matcher(text.toLowerCase()); ArrayList<String> result = new ArrayList<String>(); while (m.find()) { String temporary = m.group(); System.out.println(temporary); result.add(temporary); } The problem is that it skips some matches. For example "My name is James", for n = 3, must match "my name is" and "name is james", but instead it matches just the first. Is there a way to solve this?

    Read the article

  • making a jar file for console

    - by user472221
    Hi I have a program without a GUI and I use console! So first I read a line from a user from console BufferedReader userReader = new BufferedReader(new InputStreamReader(System.in)); and then I will write an answer for the user in the console! System.out.println("Server:"+output); I want to create a jar file for it ! but how can i show my console in jar file with out using GUI? please help me thanks.

    Read the article

  • How does array class work in Java?

    - by oks16
    In Java, array is a class and extends Object. I am curious to know about this special array class. I don't find the class definition anywhere. Doing a getClass().getName() gives strange result. String[] array = new String[]{"one","two"}; System.out.println(array.getClass().getName()); // prints [Ljava.lang.String; I want to understand how array works under the hood. Is the array class definition hardcoded in the JVM? Any resources, books, links on this will be helpful. Thank you.

    Read the article

  • Button.setOnClickListener doesn't work?

    - by user164589
    Hi guys, I am trying to make a button using programmable way. My code is : Button mybutton = new Button(this); mybutton.setText("My Button"); linearLayout.addView(mybutton, 3); mybutton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Log.println(Log.ERROR, "MyApp", "Clicked on the button."); } }); But its setOnClickListener doesn't work. What is wrong for me ? Please help. Thanks.

    Read the article

  • java for loop not working

    - by Steve
    I hope this isn't a stupid question but I have looked up every example I can find and it still seems like I have this code right and it still isn't working... I enter one number and it moves on to the next line of code instead of looping. I'm using this to fill an array with user input numbers. I appreciate any help, thanks. for(i=0; i<9; i++); { System.out.println ("Please enter a number:"); Num[i] = keyboard.nextDouble(); Sum += Num[i]; Product *= Num[i]; }

    Read the article

  • Spring MVC simple case

    - by coure2011
    Trying to understand a sample code... I am returning a modelview successfully from my AthuenticationController like this modelAndView = new ModelAndView("redirect:/home/"); .... return modelAndView; and my browser url is changed to /home/ but its showing a 404 page I have a HomePageController and it has methods @RequestMapping(method = RequestMethod.GET) public String loadHome and @RequestMapping(method = RequestMethod.GET, value = "/main") public String reloadHome but System.out.println("Message") is not executing in any of the above methods. When authenticated I want to load a home.jsp page? It is in WEB-INF/jsp/...

    Read the article

  • Reading a simple Avro file from HDFS

    - by John Galt... who
    I am trying to do a simple read of an Avro file stored in HDFS. I found out how to read it when it is on the local file system.... FileReader reader = DataFileReader.openReader(new File(filename), new GenericDatumReader()); for (GenericRecord datum : fileReader) { String value = datum.get(1).toString(); System.out.println("value = " value); } reader.close(); My file is in HDFS, however. I cannot give the openReader a Path or an FSDataInputStream. How can I simply read an Avro file in HDFS? EDIT: I got this to work by creating a custom class (SeekableHadoopInput) that implements SeekableInput. I "stole" this from "Ganglion" on github. Still, seems like there would be a Hadoop/Avro integration path for this. Thanks

    Read the article

  • Java: PriorityQueue returning incorrect ordering from custom comparator??

    - by Michael Simpson
    I've written a custom comparator to compare my node classes, but the java priority queue is not returning my items in the correct order. Here is my comparator: public int compare(Node n1, Node n2){ if (n1.getF() > n2.getF()){ return +1; } else if (n1.getF() < n2.getF()){ return -1; } else { // equal return 0; } } Where getF returns a double. However after inserting several Nodes into the priority queue, I print them out using: while(open.size() > 0) { Node t = (Node)(open.remove()); System.out.println(t.getF()); } Which results in: 6.830951894845301 6.830951894845301 6.0 6.0 5.242640687119285 7.4031242374328485 7.4031242374328485 8.071067811865476 Any ideas why this is so? Is my comparator wrong? Thanks. Mike

    Read the article

  • Velocity templates seem to fail with UTF-8

    - by steve
    Hi, i have been trying to use a velocity Template with the following content: Sübjäct $item everything works fine except the translation of the tow unicode characters. The result string printed on the commandline looks like: Sübjäct foo I searched the velocity website and the web an this issue, and came uo with differnt font encoding options, which i added to my code. But those won't help. This is the actuall code: velocity.setProperty("file.resource.loader.path", absPath); velocity.setProperty("input.encoding", "UTF-8"); velocity.setProperty("output.encoding", "UTF-8"); Template t = velocity.getTemplate("subject.vm"); t.setEncoding("UTF-8"); StringWriter sw = new StringWriter(); t.merge(null, sw); System.out.println(sw.getBuffer()); Can anyone give me some hints, how to fix this issue?

    Read the article

  • Java Swing- Create a function to add elements to JScrollPanel

    - by battousai622
    I want to create a function so that i can call add JLabel's, etc inside the JScrollPanel. I am not sure what the command is in NetBeans. I tried doing JScrollPanel - events - container - componentAdded to create the code below. But nothing shows up when i add code to that function. private void initComponents() { scrollPanel = new javax.swing.JScrollPane(); scrollPanel.addContainerListener(new java.awt.event.ContainerAdapter() { public void componentAdded(java.awt.event.ContainerEvent evt) { scrollPanelComponentAdded(evt); } } private void scrollPanelComponentAdded(java.awt.event.ContainerEvent evt) { System.out.println("main"); } Any help would be great, thanks.

    Read the article

  • How do I get the name of the test method that was ran in a testng tear down method?

    - by Zachary Spencer
    Basically I have a tear down method that I want to log to the console which test was just ran. How would I go about getting that string? I can get the class name, but I want the actual method that was just executed. Class testSomething() { @AfterMethod public void tearDown() { system.out.println('The test that just ran was....' + getTestThatJustRanMethodName()'); } @Test public void testCase() { assertTrue(1==1); } } should output to the screen: "The test that just ran was.... testCase" However I don't know the magic that getTestThatJustRanMethodName should actually be.

    Read the article

  • null pointer exception on list.add

    - by Eric
    I've been working on this one error for a few hours so I thought I'd pick the brains of some pros. I am getting a null pointer exception at the modelData.add(i, es) method. I know from debugging that es isn't null. I'm really confused, thanks. public class EventTableModel extends AbstractTableModel { //private int rowCount = 0; protected List<EventSeat> modelData; private static final int COLUMN_COUNT = 3; private Event e; Event j = GUIpos.m; int i = 1; public EventTableModel(Event e) { this.e = e; try { System.out.println(modelData); for (EventSeat es : e.getEventSeats()) { modelData.add(i, es); i++; } } catch (DataException ex) { Logger.getLogger(EventTableModel.class.getName()).log(Level.SEVERE, null, ex); } }

    Read the article

  • Compute hex color code for an arbitrary string

    - by user222164
    Heading Is there a way to map an arbitrary string to a HEX COLOR code. I tried to compute the HEX number for string using string hashcode. Now I need to convert this hex number to six digits which are in HEX color code range. Any suggestions ? String [] programs = {"XYZ", "TEST1", "TEST2", "TEST3", "SDFSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS"}; for(int i = 0; i < programs.length; i++) { System.out.println( programs[i] + " -- " + Integer.toHexString(programs[i].hashCode())); }

    Read the article

  • Casting Class into String and Vice Versa in JAVA

    - by topgun_ivard
    I have a program in which I need to store a Class object into memory by casting it into String. Is it possible to convert the String back into the original Class so that I can use that class variables? I am doing this in JAVA. Example: test.java class hello{ public String h1; public String h2; } public class test { public static void main(String[] args) { hello h = new hello(); h.h1 = "hello"; h.h2 = "world"; String s = h.toString(); System.out.println("Print s : "+s); // Now I need to convert String s into type hello so that // I can do this: // (hello)s.h1; // (hello)s.h2; } } NOTE: this is not a homework, this is a personal project and I would be grateful if anyone can help! Thanks! Ivar

    Read the article

  • Regular expression to truncate a String

    - by user470184
    To truncate a String here is what I'm using : String test1 = "this is test truncation 1.pdf"; String p1 = test1.substring(0, 10) + "..."; System.out.println(p1); The output is 'this is te...' How can I access the file name extension so that output becomes : 'this is te... pdf' I could use substring method to access the last three characters but other file extensions could be 4 chars in length such as .aspx Is there a regular expression I can use so that "this is test truncation 1.pdf" becomes "this is te... pdf"

    Read the article

  • @Secured not working

    - by user3640507
    I am new to spring and trying to implement Role based authorization with the help of @Secured annotation. I have a method which is specifically for ADMIN and I have written @Secured ("ROLE_ADMIN") to secure it. @Secured ("ROLE_ADMIN") public void HelloUser(String name) { System.out.println("Hello ADMIN"); } Now when I call this method by creating a class object it gets called eventhough user dont have ADMIN authority But when I dont create an object and use @autowired annotation instead then it works i.e User is not allowed to access this method. In my security.xml as well as servlet.xml I have added <global-method-security secured-annotations="enabled" /> Can some one please tell me where I am going wrong or is this the natural behaviour in spring ?

    Read the article

  • Java SWING- Create a function to add elements to JScrollPanel ??? PLEASE

    - by battousai622
    I want to create a function so that i can call add JLables, ect inside the JScrollPanel. Im not sure what the command is in netbeans. I tried doing JScrollPanel - events - container - componentAdded to create the code below. But nothing shows up when i add code to that function. Any help would be great please! =] private void initComponents() { scrollPanel = new javax.swing.JScrollPane(); scrollPanel.addContainerListener(new java.awt.event.ContainerAdapter() { public void componentAdded(java.awt.event.ContainerEvent evt) { scrollPanelComponentAdded(evt); } } private void scrollPanelComponentAdded(java.awt.event.ContainerEvent evt) { System.out.println("main"); }

    Read the article

  • Need help: input int from console and pass it into method in different class

    - by christophe
    i'm a beginner, Need help, Please!!! I want to read number "a" from console and then store them in variable to use as passing to a different class (different .java file). How do i code the 2 classes? thanks public class PassedInMethod{ private int a; . public PAssMethod(int a) { a = a; // TODO: where to get the a? System.out.println("a was passed in!"+a); } public class Mainclass{ public static void main( String args[] ){ Scanner input = new Scanner( System.in ); int a; System.out.print( "Enter your nember: " ); a = input.nextInt(); PassedInMethod(int a); }

    Read the article

  • can this keyword be used in an abstract class in java

    - by Reddy
    I tried with below example, it is working fine. I expected it to pick sub-class's value since object won't be created for super class (as it is abstract). But it is picking up super class's field value only. Please help me understand what is the concepts behind this? abstract class SuperAbstract { private int a=2; public void funA() { System.out.println("In SuperAbstract: this.a "+a); } } class SubClass extends SuperAbstract { private int a=34; } I am calling new SubClass.funA(); I am expecting it to print 34, but it is printing 2.

    Read the article

  • can the keyword 'this' be used in an abstract class in java

    - by Reddy
    I tried with below example, it is working fine. I expected it to pick sub-class's value since object won't be created for super class (as it is abstract). But it is picking up super class's field value only. Please help me understand what is the concepts behind this? abstract class SuperAbstract { private int a=2; public void funA() { System.out.println("In SuperAbstract: this.a "+a); } } class SubClass extends SuperAbstract { private int a=34; } I am calling new SubClass.funA(); I am expecting it to print 34, but it is printing 2.

    Read the article

  • Java Disabled JLabel Reports Mouse Clicked

    - by ikurtz
    colLabels[i].addMouseListener(new MyAdapter()); private class MyAdapter extends MouseAdapter { @Override public void mouseClicked(MouseEvent event) { ColJLabel colJLabel = (ColJLabel)event.getComponent(); System.out.println(colJLabel.ColID); setColumnHeader(false); } } colLabels[i].setEnabled(flag); The situation is this: Mouse clicks are trapped correctly but when i have the JLabel (ColJLabel) control disabled it still reports mouse clicks. How can I make so that mouse clicks are only reported when the control is enabled? Thanks.

    Read the article

  • set arraylist element as null

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

    Read the article

  • Reading http file on url

    - by Nkunzis
    I am trying to read an xml file on an http url. "Unexpected end of file from server" keeps on coming . the page is password protected, I would like to know if I am properly giving in my url authentication details. I tried with non protected pages and I can read them properly. Here is my code: URL url = new URL("http://username:[email protected]:0000/test.xml"); URLConnection yc = url.openConnection(); BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream())); String inputLine; while ((inputLine = in.readLine()) != null) System.out.println(inputLine); in.close();

    Read the article

< Previous Page | 81 82 83 84 85 86 87 88 89 90 91 92  | Next Page >