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  • File Upload with HttpWebRequest doesn't post the file

    - by Sri Kumar
    Hello All, Here is my code to post the file. I use asp fileupload control to get the file stream. HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx"); requestToSender.Method = "POST"; requestToSender.ContentType = "multipart/form-data"; requestToSender.KeepAlive = true; requestToSender.Credentials = System.Net.CredentialCache.DefaultCredentials; requestToSender.ContentLength = BtnUpload.PostedFile.ContentLength; BinaryReader binaryReader = new BinaryReader(BtnUpload.PostedFile.InputStream); byte[] binData = binaryReader.ReadBytes(BtnUpload.PostedFile.ContentLength); Stream requestStream = requestToSender.GetRequestStream(); requestStream.Write(binData, 0, binData.Length); requestStream.Close(); HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse(); string fromSender = string.Empty; using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream())) { fromSender = responseReader.ReadToEnd(); } XMLString.Text = fromSender; In the page load of CrossPage.aspx i have the following code NameValueCollection postPageCollection = Request.Form; foreach (string name in postPageCollection.AllKeys) { Response.Write(name + " " + postPageCollection[name]); } HttpFileCollection postCollection = Request.Files; foreach (string name in postCollection.AllKeys) { HttpPostedFile aFile = postCollection[name]; aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName)); } string strxml = "sample"; Response.Clear(); Response.Write(strxml); I don't get the file in Request.Files. The byte array is created. What was wrong with my HttpWebRequest?

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  • Trouble converting an MP3 file to a WAV file using Naudio

    - by WebDevHobo
    Naudio Library: http://naudio.codeplex.com/ I'm trying to convert an MP3 file to a WAV file, but I've run in to a small error. I know what's going wrong, but I don't really know how to go about fixing it. Here's the piece of code I'm running: private void button1_Click(object sender, EventArgs e) { using(Mp3FileReader reader = new Mp3FileReader(@"path\to\MP3")) { using(WaveFileWriter writer = new WaveFileWriter(@"C:\test.wav", new WaveFormat())) { int counter = 0; while(reader.Read(test, counter, test.Length + counter) != 0) { writer.WriteData(test, counter, test.Length + counter); counter += 512; } } } } reader.Read() goes into the Mp3FileReader class, and the method looks like this: public override int Read(byte[] sampleBuffer, int offset, int numBytes) { if (numBytes % waveFormat.BlockAlign != 0) //throw new ApplicationException("Must read complete blocks"); numBytes -= (numBytes % waveFormat.BlockAlign); return mp3Stream.Read(sampleBuffer, offset, numBytes); } mp3Stream is an object of the Stream class. The problem is: I'm getting an ArgumentException. MSDN says that this is because the sum of offset and numBytes is greater than the length of sampleBuffer. Documentation: http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx This happens because I increase the counter every time, but the size of the byte array test remains the same. What I've been wondering is: do I need to increase the size of the array dynamically, or do I need to find out the needed size at the beginning and set it right away? And also, instead of 512, the method in Mp3FileReader returns 365 the first time. Which is the size of a whole block. But I'm writing the full 512. I'm basically just using the read to check if I'm not at the end of the file yet. Do I need to catch the return value and do something with that, or am I good here?

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  • IE7 issue - cannot download streamed file when Automatic prompting for file downloads is disabled

    - by Jai ganesh K
    Hi, My application is J2EE (JSP/Servlet) based. I encounter an issue when i try to open a new window (pop-up) from JSP and call a Servlet action (e.g. Streamer.do) which streams a PDF file inside that pop-up. Problem: While IE 7 - Tools - Internet Options - Security - Custom Level - Downloads - Automatic prompting for file downloads is Disabled and while pop-up window get opened, I am unable to download the file (Save/Open prompt is not comming up). In contrast, when I enable this option, I am able to download. But this option sometimes would be disabled in some environments. While testing this in Mozilla Firefox 3.0/3/5/IE6 it is working fine without any settings change. When i check it to enable i then get the Save/Open prompt to work correctly. This should be problem with IE7. Can anybody help us with Javascript or any working settings which doesnt care whether the "Automatic prompting for downloads" option in IE7 is enabled. Any help in this would be much appreciated. Regards! Jai

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  • Pentaho - Reporting Tool - Is the .prpt file (report template file) contains datasource information

    - by Yatendra Goel
    I am new Pentaho Reporting Tool. I have the following question: When I created a report using Pentaho Report Designer, it output a report file having .prpt extension. After that I found an example on internet where the following code were used to display the report in html format:| protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ResourceManager manager = new ResourceManager(); manager.registerDefaults(); String reportPath = "file:" + this.getServletContext().getRealPath("sampleReport.prpt"); try { Resource res = manager.createDirectly(new URL(reportPath), MasterReport.class); MasterReport report = (MasterReport) res.getResource(); HtmlReportUtil.createStreamHTML(report, response.getOutputStream()); } catch (Exception e) { e.printStackTrace(); } } And the report got printed successfully. So as we haven't specified any datasource information here, I think that the .prpt file contains that information in it. If that's true than Isn't Jasper is better Reporting tool than Pentaho because when we display Jasper reports, we have to provide datasource details also so in that way our report is flexible and is not bound to any particular database.

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  • Django/jQuery - read file and pass to browser as file download prompt

    - by danspants
    I've previously asked a question regarding passing files to the browser so a user receives a download prompt. However these files were really just strings creatd at the end of a function and it was simple to pass them to an iframe's src attribute for the desired effect. Now I have a more ambitious requirement, I need to pass pre existing files of any format to the browser. I have attempted this using the following code: def return_file(request): try: bob=open(urllib.unquote(request.POST["file"]),"rb") response=HttpResponse(content=bob,mimetype="application/x-unknown") response["Content-Disposition"] = "attachment; filename=nothing.xls" return HttpResponse(response) except: return HttpResponse(sys.exc_info()) With my original setup the following jQuery was sufficient to give the desired download prompt: jQuery('#download').attr("src","/return_file/"); However this won't work anymore as I need to pass POST values to the function. my attempt to rectify that is below, but instead of a download prompt I get the file displayed as text. jQuery.get("/return_file/",{"file":"c:/filename.xls"},function(data) { jQuery(thisButton).children("iframe").attr("src",data); }); Any ideas as to where I'm going wrong? Thanks!

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  • Need a way to determine if a file is done being written to.

    - by Khorkrak
    The situation I'm in is this - there's a process that's writing to a file, sometimes the file is rather large say 400 - 500MB. I need to know when it's done writing. How can I determine this? If I look in the directory I'll see it there but it might not be done being written. Plus this needs to be done remotely - as in on the same internal LAN but not on the same computer and typically the process that wants to know when the file writing is done is running on a Linux box with a the process that's writing the file and the file itself on a windows box. No samba isn't an option. xmlrpc communication to a service on that windows box is an option as well as using snmp to check if that's viable. Ideally Works on either Linux or Windows - meaning the solution is OS independent. Works for any type of file. Good enough: Works just on windows but can be done through some library or whatever that can be accessed with Python. Works only for PDF files. Current best idea is to periodically open the file in question from some process on the windows box and look at the last bytes checking for the PDF end tag and accounting for the eol differences because the file may have been created on Linux or Windows.

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  • Deploy an hta file in an exe or msi file

    - by rjmunro
    I've written an HTA file frontend for our web app that allows the web app to run without web browser status bars etc, and allows it to access the local system for certain tasks. I need a way to deploy this to customers. I need an installer to supply an hta file, an ico file, and add a link to them in the start menu and on the users desktop. I looked at building an installer with NSIS, but I couldn't figure out how to assign the icon to the shortcuts - The icon had to be a standard HTA one. Can this be done with NSIS, or should I be using another installer? P.s. I've got no particular preference for NSIS, it's just something I once used a very long time ago. When I download stuff, I think I prefer them to be msi files that launch with windows installer (it feels more like downloading a .rpm or .deb on linux which I am used to) but I know nothing about how those are created. I'm a web/linux guy who knows very little about windows programming.

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  • Reading a binary file in perl: Bad File Descriptor

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • Saving temporary file name after uploading file with uplodify

    - by mIRU
    I have this script if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__).$_POST['folder'] . '/'; $pathinfoFile = pathinfo($_FILES['Filedata']['name']); $targetFile = str_replace('//','/',$targetPath) .uniqid().'.'.$pathinfoFile['extension']; move_uploaded_file($tempFile,$targetFile); } this script is from uplodify , modified for saving the file with unique name , i need after user will upload the file , this unique name and original name , to save temporary , when user will submit the form , this temporary variables i will insert in database , the problem is that in firebug console , i can not see all the actions of this script , and i can not understand the way how to fix it, I tried to save in $_SESSION but i have problems , is not saving , i found why is not working with $_SESSION , http://uploadify.com/forum/viewtopic.php?f=5&t=43 , i tried the solution from forum but without result , exist a more easy way to solve this problem ? , or what is better way to do it ? . Sorry for so silly question , i ran out of ideas . Thanks a lot for helping me , and sorry again for my English

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  • Java - Reading a csv file line by line - stuck with weird non-existent characters being read!

    - by rockit
    hello fellow java developers. I'm having a very strange issue. I'm trying to read a csv file line by line. Im at the point where Im just testing out the reading of the lines. ONly each time that I read a line, the line contains square characters between each character of text. I even saved the file as a txt file in wordpad and notepad with no change. Thus I must be doing something stupid... I have a csv file, standard csv file, yes a text file with commas in it. I try to read a line of text, but the text is all f-ed up and cannot find the phrase within the text. Any advice? code below. //open csv File filReadMe = new File(strRoot + "data2.csv"); BufferedReader brReadMe = new BufferedReader(new InputStreamReader(new FileInputStream(filReadMe))); String strLine = brReadMe.readLine(); //for all lines while (strLine != null){ //if line contains "(see also" if (strLine.toLowerCase().contains("(see also")){ //write line from "(see also" to ")" int iBegin = strLine.toLowerCase().indexOf("(see also"); String strTemp = strLine.substring(iBegin); int iLittleEnd = strTemp.indexOf(")"); System.out.println(strLine.substring(iBegin, iBegin + iLittleEnd)); } //update line strLine = brReadMe.readLine(); } //end for brReadMe.close();

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  • Short file names versus long file names in Windows

    - by normski
    I have some code which gets the short name from a file path, using GetShortNameW(), and then later retrieves the long name view GetLongNameA(). The original file is of the form "C:/ProgramData/My Folder/File.ext" However, following conversion to short, then back to long, the filename becomes "C:/Program Files/My Folder/Filename.ext". The short name is of the form "C:/PROGRA~2/MY_FOL~1/FIL~1.EXT" The short name is being incorrectly resolved. The code compiles using VS 2005 on Windows 7 (I cannot upgrade the project to VS2008) Does anybody have any idea why this might be happening? DWORD pathLengthNeeded = ::GetShortPathNameW(aRef->GetFilePath().c_str(), NULL, 0); if(pathLengthNeeded != 0) { WCHAR* shortPath = new WCHAR[pathLengthNeeded]; DWORD newPathNameLength = ::GetShortPathNameW(aRef->GetFilePath().c_str(), shortPath, pathLengthNeeded); if(newPathNameLength != 0) { UI_STRING unicodePath(shortPath); std::string asciiPath = StringFromUserString(unicodePath); pathLengthNeeded = ::GetLongPathNameA(asciiPath.c_str(),NULL, 0); if(pathLengthNeeded != 0) {// convert it back to a long path if possible. For goodness sake can't we use Unicode throughout?F char* longPath = new char[pathLengthNeeded]; DWORD newPathNameLength = ::GetLongPathNameA(asciiPath.c_str(), longPath, pathLengthNeeded); if(newPathNameLength != 0) { std::string longPathString(longPath, newPathNameLength); asciiPath = longPathString; } delete [] longPath; } SetFullPathName(asciiPath); } delete [] shortPath; }

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  • open program once with multiple files as arguments from explorer

    - by Jonathan
    I have a program that works when, a file is opened with it using the right click menu in explorer. But if I select multiple files and then right click and open with my program then it opens multiple instances of my program, instead of just passing the multiple files as arguments to a single instance. The program is written in vb.net but is not a windows form, it is just a module, so I can to tick the Single instance option in the properties in Visual Studio. So how do I open multiple files from explorer context menu in a single instance.

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  • Unable to delete a file using bash script

    - by user3719091
    I'm having problems removing a file in a bash script. I saw the other post with the same problem but none of those solutions solved my problem. The bash script is an OP5 surveillance check and it calls an Expect process that saves a temporary file to the local drive which the bash script reads from. Once it has read the file and checked its status I would like to remove the temporary file. I'm pretty new to scripting so my script may not be as optimal as it can be. Either way it does the job except removing the file once it's done. I will post the entire code below: #!/bin/bash #GET FLAGS while getopts H:c:w: option do case "${option}" in H) HOSTADDRESS=${OPTARG};; c) CRITICAL=${OPTARG};; w) WARNING=${OPTARG};; esac done ./expect.vpn.check.sh $HOSTADDRESS #VARIABLES VPNCount=$(grep -o '[0-9]\+' $HOSTADDRESS.op5.vpn.results) # Check if the temporary results file exists if [ -f $HOSTADDRESS.op5.vpn.results ] then # If the file exist, Print "File Found" message echo Temporary results file exist. Analyze results. else # If the file does NOT exist, print "File NOT Found" message and send message to OP5 echo Temporary results file does NOT exist. Unable to analyze. # Exit with status Critical (exit code 2) exit 2 fi if [[ "$VPNCount" > $CRITICAL ]] then # If the amount of tunnels exceeds the critical threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the critical threshold - ($VPNCount)" # Exit with status Critical (exit code 2) exit 2 elif [[ "$VPNCount" > $WARNING ]] then # If the amount of tunnels exceeds the warning threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the warning threshold - ($VPNCount)" # Exit with status Warning (exit code 1) exit 1 else # The amount of tunnels do not exceed the warning threshold. # Print an OK message echo OK - $VPNCount # Exit with status OK exit 0 fi #Clean up temporary files. rm -f $HOSTADDRESS.op5.vpn.results I have tried the following solutions: Create a separate variable called TempFile that specifies the file. And specify that in the rm command. I tried creating another if statement similar to the one I use to verify that file exist and then rm the filename. I tried adding the complete name of the file (no variables, just plain text of the file) I can: Remove the file using the full name in both a separate script and directly in the CLI. Is there something in my script that locks the file that prevents me from removing it? I'm not sure what to try next. Thanks in advance!

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  • How to copy file preserving directory path in Linux?

    - by gasan
    I have Eclipse projects and ".project" file in them, the directory structure looks like 'myProject/.project'. I want to copy these '.project' files to another directory, but I want the enclosing directory name to be preserved. Let's say I have 'a/myProject/.project', I want to copy 'myProject/.project' to 'b', so it be 'b/myProject/.project', but 'b/myProject' doesn't exist. When I try in a: cp -r ./myProject/.project ../b it copies only '.project' file itself, without 'myProject' directory. Please advise.

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  • File association error while trying to browse to a network share in explorer or from run?

    - by ChrisFletcher
    I'm getting the below error message while trying to browse to a local share on a Windows Server 2003 machine: Windows cannot find ### this file does not have a program associated with it for performing this action. Create an Association in the folder options control panel The server is on the network, has an assigned IP address, can access the internet and is otherwise functioning normally. I realise this message can occur when opening a document or file which has no application associated with it, but I'm trying to access a share. What's going on here?

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  • SSSD Authentication

    - by user24089
    I just built a test server running OpenSuSE 12.1 and am trying to learn how configure sssd, but am not sure where to begin to look for why my config cannot allow me to authenticate. server:/etc/sssd # cat sssd.conf [sssd] config_file_version = 2 reconnection_retries = 3 sbus_timeout = 30 services = nss,pam domains = test.local [nss] filter_groups = root filter_users = root reconnection_retries = 3 [pam] reconnection_retries = 3 # Section created by YaST [domain/mose.cc] access_provider = ldap ldap_uri = ldap://server.test.local ldap_search_base = dc=test,dc=local ldap_schema = rfc2307bis id_provider = ldap ldap_user_uuid = entryuuid ldap_group_uuid = entryuuid ldap_id_use_start_tls = True enumerate = False cache_credentials = True chpass_provider = krb5 auth_provider = krb5 krb5_realm = TEST.LOCAL krb5_kdcip = server.test.local server:/etc # cat ldap.conf base dc=test,dc=local bind_policy soft pam_lookup_policy yes pam_password exop nss_initgroups_ignoreusers root,ldap nss_schema rfc2307bis nss_map_attribute uniqueMember member ssl start_tls uri ldap://server.test.local ldap_version 3 pam_filter objectClass=posixAccount server:/etc # cat nsswitch.conf passwd: compat sss group: files sss hosts: files dns networks: files dns services: files protocols: files rpc: files ethers: files netmasks: files netgroup: files publickey: files bootparams: files automount: files ldap aliases: files shadow: compat server:/etc # cat krb5.conf [libdefaults] default_realm = TEST.LOCAL clockskew = 300 [realms] TEST.LOCAL = { kdc = server.test.local admin_server = server.test.local database_module = ldap default_domain = test.local } [logging] kdc = FILE:/var/log/krb5/krb5kdc.log admin_server = FILE:/var/log/krb5/kadmind.log default = SYSLOG:NOTICE:DAEMON [dbmodules] ldap = { db_library = kldap ldap_kerberos_container_dn = cn=krbContainer,dc=test,dc=local ldap_kdc_dn = cn=Administrator,dc=test,dc=local ldap_kadmind_dn = cn=Administrator,dc=test,dc=local ldap_service_password_file = /etc/openldap/ldap-pw ldap_servers = ldaps://server.test.local } [domain_realm] .test.local = TEST.LOCAL [appdefaults] pam = { ticket_lifetime = 1d renew_lifetime = 1d forwardable = true proxiable = false minimum_uid = 1 clockskew = 300 external = sshd use_shmem = sshd } If I log onto the server as root I can su into an ldap user, however if I try to console locally or ssh remotely I am unable to authenticate. getent doesn't show the ldap entries for users, Im not sure if I need to look at LDAP, nsswitch, or what: server:~ # ssh localhost -l test Password: Password: Password: Permission denied (publickey,keyboard-interactive). server:~ # su test test@server:/etc> id uid=1000(test) gid=100(users) groups=100(users) server:~ # tail /var/log/messages Nov 24 09:36:44 server login[14508]: pam_sss(login:auth): system info: [Client not found in Kerberos database] Nov 24 09:36:44 server login[14508]: pam_sss(login:auth): authentication failure; logname=LOGIN uid=0 euid=0 tty=/dev/ttyS1 ruser= rhost= user=test Nov 24 09:36:44 server login[14508]: pam_sss(login:auth): received for user test: 4 (System error) Nov 24 09:36:44 server login[14508]: FAILED LOGIN SESSION FROM /dev/ttyS1 FOR test, System error server:~ # vi /etc/pam.d/common-auth auth required pam_env.so auth sufficient pam_unix2.so auth required pam_sss.so use_first_pass server:~ # vi /etc/pam.d/sshd auth requisite pam_nologin.so auth include common-auth account requisite pam_nologin.so account include common-account password include common-password session required pam_loginuid.so session include common-session session optional pam_lastlog.so silent noupdate showfailed

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  • My rundll32.exe file is corrupt, how do I fix it?

    - by wahle509
    The other day I got a virus on my laptop (Windows XP), but Adaware found it and removed it. Not soon enough though, because it corrupted my rundll32.exe file. Now I can't run almost any application and I have tried to install a couple programs to fix my registry, but I can't even run the install file. What other options do I have besides re-installing my OS?

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  • Run a batch file before user logs into Windows 2003 R2?

    - by Sid
    I have an Amazon EC2 machine (Windows Server 2003 R2) where I want to run a script (.bat file) when the Windows Server 2003 R2 machine boots up. This need to run BEFORE any user logs in. Ideally I'd like to extend the same work-around on my Windows Server 2008 R2 instances too - but Windows Server 2003 R2 is critical for me as of now. Purely as FYI, the .bat file updates the DDNS records so the EC2 machine doesn't need to consume static IPs.

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  • Where does Mac OS X store file association information?

    - by Mehrdad
    I know there is a system preferences pane to manually modify the file associations in Mac OS X Leopard. However, I'm curious where does Leopard actually store these information? UPDATE: as I said, I'm not interested in methods to change them. I want to know the configuration file or database (like registry in Windows) where those mappings are stored.

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  • Windows 2008 R2 RDS - Double Login

    - by colo_joe
    Issue: Double logins when connecting to RemoteApps or Remote Desktop Environment: Gateway = 1 server 2008 R2 - Roles = Gateway, Session Broker, Connection Mgr, Session Host Configuration server Session hosts = 2 servers 2008 R2 - Roles = App Manager and Session host configuration Testing: I can get to the url http://RDS.domain.com/rdweb - I get prompted for authentication (1) Pass authentication, get list of remote apps. Click on remoteapps or remote desktop, get prompted for authentication again (2). Pass authentication, I get access to app or RDP. Done so far. On session host Signed rdp files with cert. Added the following to the custom RDP settings: Authenticaton level:i:0 = If server authentication fails, connect to the computer without warning (Connect and don’t warn me). prompt for credentials on client:i:1 = RDC will prompt for credentials when connecting to a server that does not support server authentication. enablecredsspsupport:i:1 = RDP will use CredSSP, if the operating system supports CredSSP. Edited the javascript file as found in http://support.microsoft.com/kb/977507 Added Connection ID, and added Web Access server to TS Web Access Computers group on the Session host servers, and Signed apps as found in hxxp://blogs.msdn.com/b/rds/archive/2009/08/11/introducing-web-single-sign-on-for-remoteapp-and-desktop-connections.aspx Note: This double login happens internally and externally.

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  • Anyone know a good web-based file upload package?

    - by Ted Wexler
    Basically, what I'm looking for is a place for either one of our end users to be able to upload a file to this package, after either receiving a code from one of our support engineers or vice-versa(our engineers upload a file and send a code/link/something to end user) I've spent a bunch of time googling this, I found this: http://turin.nss.udel.edu/programming/dropbox2/, but the code there scares me, and it also doesn't render properly using PHP 5.3(uses short tags, who knows what else.) Does anyone have any recommendations?

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