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  • Exit SSH from the script

    - by Kimi
    I Want to exit ssh: Does the below line work: ssh -f -T ${USAGE_2_USER}@${USAGE_2_HOST} Or do i need to write it some other way . Please tell should I use exit with ssh an how?

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  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

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  • awk output to a file

    - by Harish
    I need help in moving the contents printed by awk to a text file. THis is a continuation of previous quesion I have to move all the contents into the same file so it is appending. To be specific nawk -v file="$FILE" 'BEGIN{RS=";"} /select/{ gsub(/.*select/,"select");gsub(/\n+/,"");print file,$0;} /update/{ gsub(/.*update/,"update");gsub(/\n+/,"");print file,$0;} /insert/{ gsub(/.*insert/,"insert");gsub(/\n+/,"");print file,$0;} ' "$FILE" How to get the print results to a text file appended one after the other in the same file?

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  • git filter-branch chmod

    - by Evan Purkhiser
    I accidental had my umask set incorrectly for the past few months and somehow didn't notice. One of my git repositories has many files marked as executable that should be just 644. This repo has one main master branch, and about 4 private feature branches (that I keep rebased on top of the master). I've corrected the files in my master branch by running find -type f -exec chmod 644 {} \; and committing the changes. I then rebased my feature branches onto master. The problem is there are newly created files in the feature branches that are only in that branch, so they weren't corrected by my massive chmod commit. I didn't want to create a new commit for each feature branch that does the same thing as the commit I made on master. So I decided it would be best to go back through to each commit where a file was made and set the permissions. This is what I tried: git filter-branch -f --tree-filter 'chmod 644 `git show --diff-filter=ACR --pretty="format:" --name-only $GIT_COMMIT`; git add .' master.. It looked like this worked, but upon further inspection I noticed that the every commit after a commit containing a new file with the proper permissions of 644 would actually revert the change with something like: diff --git a b old mode 100644 new mode 100755 I can't for the life of me figure out why this is happening. I think I must be mis-understanding how git filter-branch works. My Solution I've managed to fix my problem using this command: git filter-branch -f --tree-filter 'FILES="$FILES "`git show --diff-filter=ACMR --pretty="format:" --name-only $GIT_COMMIT`; chmod 644 $FILES; true' development.. I keep adding onto the FILES variable to ensure that in each commit any file created at some point has the proper mode. However, I'm still not sure I really understand why git tracks the file mode for each commit. I had though that since I had fixed the mode of the file when it was first created that it would stay that mode unless one of my other commits explicit changed it to something else. That did not appear to the be the case. The reason I thought that this would work is from my understanding of rebase. If I go back to HEAD~5 and change a line of code, that change is propagated through, it doesn't just get changed back in HEAD~4.

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  • Unknown error in Producer/Consumer program, believe it to be an infinite loop.

    - by ray2k
    Hello, I am writing a program that is solving the producer/consumer problem, specifically the bounded-buffer version(i believe they mean the same thing). The producer will be generating x number of random numbers, where x is a command line parameter to my program. At the current moment, I believe my program is entering an infinite loop, but I'm not sure why it is occurring. I believe I am executing the semaphores correctly. You compile it like this: gcc -o prodcon prodcon.cpp -lpthread -lrt Then to run, ./prodcon 100(the number of randum nums to produce) This is my code. typedef int buffer_item; #include <stdlib.h> #include <stdio.h> #include <pthread.h> #include <semaphore.h> #include <unistd.h> #define BUFF_SIZE 10 #define RAND_DIVISOR 100000000 #define TRUE 1 //two threads void *Producer(void *param); void *Consumer(void *param); int insert_item(buffer_item item); int remove_item(buffer_item *item); int returnRandom(); //the global semaphores sem_t empty, full, mutex; //the buffer buffer_item buf[BUFF_SIZE]; //buffer counter int counter; //number of random numbers to produce int numRand; int main(int argc, char** argv) { /* thread ids and attributes */ pthread_t pid, cid; pthread_attr_t attr; pthread_attr_init(&attr); pthread_attr_setscope(&attr, PTHREAD_SCOPE_SYSTEM); numRand = atoi(argv[1]); sem_init(&empty,0,BUFF_SIZE); sem_init(&full,0,0); sem_init(&mutex,0,0); printf("main started\n"); pthread_create(&pid, &attr, Producer, NULL); pthread_create(&cid, &attr, Consumer, NULL); printf("main gets here"); pthread_join(pid, NULL); pthread_join(cid, NULL); printf("main done\n"); return 0; } //generates a randum number between 1 and 100 int returnRandom() { int num; srand(time(NULL)); num = rand() % 100 + 1; return num; } //begin producing items void *Producer(void *param) { buffer_item item; int i; for(i = 0; i < numRand; i++) { //sleep for a random period of time int rNum = rand() / RAND_DIVISOR; sleep(rNum); //generate a random number item = returnRandom(); //acquire the empty lock sem_wait(&empty); //acquire the mutex lock sem_wait(&mutex); if(insert_item(item)) { fprintf(stderr, " Producer report error condition\n"); } else { printf("producer produced %d\n", item); } /* release the mutex lock */ sem_post(&mutex); /* signal full */ sem_post(&full); } return NULL; } /* Consumer Thread */ void *Consumer(void *param) { buffer_item item; int i; for(i = 0; i < numRand; i++) { /* sleep for a random period of time */ int rNum = rand() / RAND_DIVISOR; sleep(rNum); /* aquire the full lock */ sem_wait(&full); /* aquire the mutex lock */ sem_wait(&mutex); if(remove_item(&item)) { fprintf(stderr, "Consumer report error condition\n"); } else { printf("consumer consumed %d\n", item); } /* release the mutex lock */ sem_post(&mutex); /* signal empty */ sem_post(&empty); } return NULL; } /* Add an item to the buffer */ int insert_item(buffer_item item) { /* When the buffer is not full add the item and increment the counter*/ if(counter < BUFF_SIZE) { buf[counter] = item; counter++; return 0; } else { /* Error the buffer is full */ return -1; } } /* Remove an item from the buffer */ int remove_item(buffer_item *item) { /* When the buffer is not empty remove the item and decrement the counter */ if(counter > 0) { *item = buf[(counter-1)]; counter--; return 0; } else { /* Error buffer empty */ return -1; } }

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  • Too many open files in one of my java routine.

    - by Irfan Zulfiqar
    I have a multithreaded code that has to generated a set of objects and write them to a file. When I run it I sometime get "Too many open files" message in Exception. I have checked the code to make sure that all the file streams are being closed properly. Here is the stack trace. When I do ulimit -a, open files allowed is set to 1024. We think increasing this number is not a viable option / solution. [java] java.io.FileNotFoundException: /export/event_1_0.dtd (Too many open files) [java] at java.io.FileInputStream.open(Native Method) [java] at java.io.FileInputStream.<init>(FileInputStream.java:106) [java] at java.io.FileInputStream.<init>(FileInputStream.java:66) [java] at sun.net.www.protocol.file.FileURLConnection.connect(FileURLConnection.java:70) [java] at sun.net.www.protocol.file.FileURLConnection.getInputStream(FileURLConnection.java:161) [java] at java.net.URL.openStream(URL.java:1010) Now what we have identified so far by looking closely at the list of open files is that the VM is opening same class file multiple times. /export/BaseEvent.class 236 /export/EventType1BaseEvent.class 60 /export/EventType2BaseEvent.class 48 /export/EventType2.class 30 /export/EventType1.class 14 Where BaseEvent is partent of all the classes and EventType1 ant EventType2 inherits EventType1BaseEvent and EventType2BaseEvent respectively. Why would a class loader load the same class file 200+ times. It seems it is opening up the base class as many time it create any child instance. Is this normal? Can it be handler any other way apart from increasing the number of open files?

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  • How to use parallel execution in a shell script?

    - by eSKay
    I have a C shell script that does something like this: #!/bin/csh gcc example.c -o ex gcc combine.c -o combine ex file1 r1 <-- 1 ex file2 r2 <-- 2 ex file3 r3 <-- 3 #... many more like the above combine r1 r2 r3 final \rm r1 r2 r3 Is there some way I can make lines 1, 2 and 3 run in parallel instead of one after the another?

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  • Bash: using commands as parameters (specifically cd, dirname and find)

    - by sixtyfootersdude
    This command and output: % find . -name file.xml 2> /dev/null ./a/d/file.xml % So this command and output: % dirname `find . -name file.xml 2> /dev/null` ./a/d % So you would expect that this command: % cd `dirname `find . -name file.xml 2> /dev/null`` Would change the current directory to ./a/d. Strangely this does not work. When I type cd ./a/d. The directory change works. However I cannot find out why the above does not work...

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  • How to feed data over STDIN to multiple external commands in ruby.

    - by Erik
    This question is a bit like my previous (answered) question: How to run multiple external commands in the background in ruby. But, in this case I am looking for a way to feed ruby strings over STDIN to external processes, something like this (the code below is not valid but illustrates my goal): #!/usr/bin/ruby str1 = 'In reality a relatively large string.....' str2 = 'Another large string' str3 = 'etc..' spawn 'some_command.sh', :stdin => str1 spawn 'some_command.sh', :stdin => str2 spawn 'some_command.sh', :stdin => str3 Process.waitall

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  • In terminal, merging multiple folders into one.

    - by Josh Pinter
    I have a backup directory created by WDBackup (western digital external HD backup util) that contains a directory for each day that it backed up and the incremental contents of just what was backed up. So the hierarchy looks like this: 20100101 My Documents Letter1.doc My Music Best Songs Every First Songs.mp3 My song.mp3 # modified 20100101 20100102 My Documents Important Docs Taxes.doc My Music My Song.mp3 # modified 20100102 ...etc... Only what has changed is backed up and the first backup that was ever made contains all the files selected for backup. What I'm trying to do now is incrementally copy, while keeping the folder structure, from oldest to newest, each of these dated folders into a 'merged' folder so that it overrides the older content and keeps the new stuff. As an example, if just using these two example folders, the final merged folder would look like this: Merged My Documents Important Docs Taxes.doc Letter1.doc My Music Best Songs Every First Songs.mp3 My Song.mp3 # modified 20100102 Hope that makes sense. Thanks, Josh

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  • HPUX setacl leaves uid behind

    - by Woot4Moo
    I have a shell script that I execute after uninstalling a web application. The script is meant to clean up permissions that were needed during the execution of the application. find /opt/path -exec setacl -d user:myUser{} ';' After this executes and the acl is removed I am left with an acl that looks as follows user:101:--- /opt/path How can I properly call setacl to remove the user without leaving behind a uid?

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  • What do programs see when ZFS can't deliver uncorrupted data?

    - by Jay Kominek
    Say my program attempts a read of a byte in a file on a ZFS filesystem. ZFS can locate a copy of the necessary block, but cannot locate any copy with a valid checksum (they're all corrupted, or the only disks present have corrupted copies). What does my program see, in terms of the return value from the read, and the byte it tried to read? And is there a way to influence the behavior (under Solaris, or any other ZFS-implementing OS), that is, force failure, or force success, with potentially corrupt data?

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  • generate sha256 with openssl and C++

    - by Stanislav Palatnik
    Hello, I'm looking to create a hash with sha256 using openssl and C++. I know there's a similar post about this here: http://stackoverflow.com/questions/918676/generate-sha-hash-in-openssl, but I'm looking to specifically create sha256. UPDATE: Seems to be a problem witht he include paths. It can't find any openssl functions even though I included #include "openssl/sha.h" and I included the paths in my build -I/opt/ssl/include/ -L/opt/ssl/lib/ -lcrypto

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  • Search and replace

    - by zx
    Hi, I have a really large SQL dump around 400MB. It's in the following format, "INSERT INTO user VALUES('USERID', 'USERNAME', 'PASSWORD', '0', '0', 'EMAIL', 'GENDER', 'BIRTHDAY', '182', '13', '640', 'Married', 'Straight', '', 'Yes', 'Yes', '1146411153', '1216452123', '1149440844', '0', picture', '1', '0', '0', 'zip', '0', '', '0', '', '', '0')" Is there anyway I can just get the email and password out from that, I want to import the users into another table. Anyone know how I can do this and just get email-password stripped out from that content? Thank you in advance

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  • git crlf configuration in mixed environment

    - by Jonas Byström
    I'm running a mixed environment, and keep a central, bare repository where I pull and push most of my stuff. This centralized repository runs on Linux, and I check out to Windows XP/7, Mac and Linux. In all repositories I put the following line in my .git/config: [core] autocrlf = true I don't have the flag safecrlf=true anywhere. First time when I modify stuff on my one Windows machine (XP) there is no problem and when I look at the diff, it looks fine. But when I do the same on the other Windows machine (7), all lines are shown as changed but local line endings are \r\n as expected (when checked in a hex editor). The same applies to a MacOSX can. Sometimes I get the feeling that the different systems wrestle on line endings, but I can't be sure (I'm loosing track of all the times I change specific files). I didn't use to have the autocrlf set, but set the flag many months back. Could that be causing my current problems? Do I need to clone everything again to loose some old baggage? Or are there other things that needs configuring too? I tried git checkout -- . about a million times, but with no success.

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  • Editing Multiple files in vi with Wildcards

    - by Alan Storm
    When using the programmers text editor vi, I'll often using a wildcard search to be lazy about the file I want to edit vi ThisIsAReallLongFi*.txt When this matches a single file it works great. However, if it matches multiple files vi does something weird. First, it opens the first file for editing Second, when I :wq out of the file, I get a message the bottom of the terminal that looks like this E173: 4 more files to edit Hit ENTER or type command to continue When I hit enter, it returns me to edit mode in the file I was just in. The behavior I'd expect here would be that vi would move on to the next file to edit. So, What's the logic behind vi's behavior here Is there a way to move on and edit the next file that's been matched? And yes, I know about tab completion, this question is based on curiosity and wanting to understand the shell better.

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