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  • In iTextSharp, can we set the vertical position of the pdfwriter?

    - by Pandincus
    Hello, I've recently started using iTextSharp to generate PDF reports from data. It works quite nicely. In one particular report, I need a section to always appear at the bottom of the page. I'm using the PdfContentByte to create a dashed line 200f from the bottom: cb.MoveTo(0f, 200f); cb.SetLineDash(8, 4, 0); cb.LineTo(doc.PageSize.Width, 200f); cb.Stroke(); Now I'd like to insert content below that line. However, (as expected) the PdfContentByte methods don't change the vertical position of the PdfWriter. New paragraphs, for example, appear earlier in the page. // appears wherever my last content was, NOT below the dashed line doc.Add(new Paragraph("test", _myFont)); Is there some way to instruct the pdfwriter that I'd like to advance the vertical position to below the dashed line now, and continue inserting content there? There is a GetVerticalPosition() method -- it'd be nice if there was a corresponding Setter :-). // Gives me the vertical position, but I can't change it var pos = writer.GetVerticalPosition(false); So, is there any way to set the writer's position by hand? Thanks!

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  • Item rendered via a DataTemplate with any Background Brush renders selection coloring behind item.

    - by Mike L
    I have a ListBox which uses a DataTemplate to render databound items. The XAML for the datatemplate is as follows: <DataTemplate x:Key="NameResultTemplate"> <WrapPanel x:Name="PersonResultWrapper" Margin="0" Orientation="Vertical" Background="{Binding Converter={StaticResource NameResultToColor}, Mode=OneWay}" > <i:Interaction.Triggers> <i:EventTrigger EventName="MouseDown"> <cmd:EventToCommand x:Name="SelectPersonEventCommand" Command="{Binding Search.SelectedPersonCommand, Mode=OneWay, Source={StaticResource Locator}}" CommandParameter="{Binding Mode=OneWay}" /> </i:EventTrigger> </i:Interaction.Triggers> <TextBlock x:Name="txtPersonName" TextWrapping="Wrap" Margin="0" VerticalAlignment="Top" Text="{Binding PersonName}" FontSize="24" Foreground="Black" /> <TextBlock x:Name="txtAgencyName" TextWrapping="Wrap" Text="{Binding AgencyName}" HorizontalAlignment="Left" VerticalAlignment="Bottom" Margin="0" FontStyle="Italic" Foreground="Black" /> <TextBlock x:Name="txtPIDORI" TextWrapping="Wrap" Text="{Binding PIDORI}" HorizontalAlignment="Left" VerticalAlignment="Bottom" Margin="0" FontStyle="Italic" Foreground="Black" /> <TextBlock x:Name="txtDescriptors" TextWrapping="Wrap" Text="{Binding DisplayDescriptors}" Margin="0" VerticalAlignment="Top" Foreground="Black"/> <Separator Margin="0" Width="400" /> </WrapPanel> </DataTemplate> Note that there is a value converter called NameResultToColor which changes the background brush of the rendered WrapPanel to gradient brush depending on certain scenarios. All of this works as I'd expect, except when you click on any of the rendered ListBox items. When you click one, there is only the slightest sign of the selection coloring (the default bluish color). I can see a trace bit of it underneath my gradient-brushed item. If I reset the background brush to "no brush" then the selection rendering works properly. If I set the background brush to a solid color, it also fails to render as I'd expect. How can I get the selection coloring to be on top? What is trumping the selection rendering?

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  • Using the Apple Scripting bridge with Mail to send an attachment causes the message background to go

    - by Naym
    Hello, When I use the Apple Scripting Bridge to send a message with an attachment the background of the message is set to black which is a problem because the text is also black. The code in question is: MailApplication *mail = [SBApplication applicationWithBundleIdentifier:@"com.apple.Mail"]; /* create a new outgoing message object */ MailOutgoingMessage *emailMessage = [[[mail classForScriptingClass:@"outgoing message"] alloc] initWithProperties: [NSDictionary dictionaryWithObjectsAndKeys: emailSubject, @"subject", [self composeEmailBody], @"content", nil]]; /* add the object to the mail app */ [[mail outgoingMessages] addObject: emailMessage]; /* set the sender, show the message */ emailMessage.sender = [NSString stringWithFormat:@"%@ <%@>",[[[mail accounts] objectAtIndex:playerOptions.mailAccount] fullName],[[[[mail accounts] objectAtIndex:playerOptions.mailAccount] emailAddresses] objectAtIndex:0]]; emailMessage.visible = YES; /* create a new recipient and add it to the recipients list */ MailToRecipient *theRecipient = [[[mail classForScriptingClass:@"to recipient"] alloc] initWithProperties: [NSDictionary dictionaryWithObjectsAndKeys: opponentEmail, @"address", nil]]; [emailMessage.toRecipients addObject: theRecipient]; /* add an attachment, if one was specified */ if ( [playerInfo.gameFile length] > 0 ) { /* create an attachment object */ MailAttachment *theAttachment = [[[mail classForScriptingClass:@"attachment"] alloc] initWithProperties: [NSDictionary dictionaryWithObjectsAndKeys: playerInfo.gameFile, @"fileName", nil]]; /* add it to the list of attachments */ [[emailMessage.content attachments] addObject: theAttachment]; } /* send the message */ [emailMessage send]; The actual change to the background colour occurs on the second last line, which is: [[emailMessage.content attachments] addObject: theAttachment]; The code sections above are essentially lifted from the SBSendMail example code from Apple. At this stage I've really only made the changes necessary to integrate with the data from my application. If I build and run the SBSendMail example after freshly downloading it from Apple the message background is also changed to black with execution of the same line. It does not appear to matter which type of file is attached, where it is located, or on which computer or operating system is used. This could be a bug in Apple's scripting bridge but has anyone come across this problem and found a solution? ALternatively does anyone know if the background colour of a MailOutgoingMessage instance can be changed with the scripting bridge? Thanks for any assistance with this, Naym.

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  • Does Internet Explorer 7 have a CSS parsing issue with the "background-image" property?

    - by user312003
    Having CSS layout issues with Internet Explorer 7 (big surprise). Upon using the Developer Tools to inspect the CSS, I discovered that some properties defined in the stylesheet are not appearing in the parsed CSS structure... THEN I saw THIS being shown as the parsed value for the background-image property: background-image : url(/trunk/httpdocs/images/layout/HCBL_Homepage_01.jpg); WIDTH: 1200px; pretty much obliterating the width that was defined property. The actual code in the CSS file for this element: div#header { width: 1200px; height: 100px; margin-left: auto; margin-right: auto; background-image: url('/trunk/httpdocs/images/layout/HCBL_Homepage_01.jpg'); background-repeat: no-repeat; } If anyone could offer any insight, or provide a link describing this problem (and maybe a workaround...) I would be very appreciative. Also, I am only interested in this from a parsing of the stylesheet and CSS syntax perspective. I am not concerned with rendering and display issues at the moment; I simply want to get IE 7 (and I have a feeling IE 6 will have similar issues) to recognize and parse ALL of the CSS properties that have been defined in the stylesheet. Thanks in advance guys!

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  • How do you pass a BitmapImage from a background thread to the UI thread in WPF?

    - by DanM
    I have a background thread that generates a series of BitmapImage objects. Each time the background thread finishes generating a bitmap, I would like to show this bitmap to the user. The problem is figuring out how to pass the BitmapImage from the background thread to the UI thread. This is an MVVM project, so my view has an Image element: <Image Source="{Binding GeneratedImage}" /> My view-model has a property GeneratedImage: private BitmapImage _generatedImage; public BitmapImage GeneratedImage { get { return _generatedImage; } set { if (value == _generatedImage) return; _generatedImage= value; RaisePropertyChanged("GeneratedImage"); } } My view-model also has the code that creates the background thread: public void InitiateGenerateImages(List<Coordinate> coordinates) { ThreadStart generatorThreadStarter = delegate { GenerateImages(coordinates); }; var generatorThread = new Thread(generatorThreadStarter); generatorThread.ApartmentState = ApartmentState.STA; generatorThread.IsBackground = true; generatorThread.Start(); } private void GenerateImages(List<Coordinate> coordinates) { foreach (var coordinate in coordinates) { var backgroundThreadImage = GenerateImage(coordinate); // I'm stuck here...how do I pass this to the UI thread? } } I'd like to somehow pass backgroundThreadImage to the UI thread, where it will become uiThreadImage, then set GeneratedImage = uiThreadImage so the view can update. I've looked at some examples dealing with the WPF Dispatcher, but I can't seem to come up with an example that addresses this issue. Please advise.

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  • Position a div relative to a top-level container?

    - by Seifeddine Dridi
    I'm trying to model an HTML document which only contains div elements positioned in absolute. For each div, properties left and top are precalculated wrt. the top-level div, but a problem occurs with nested divs since according to the CSS standard an element is positioned relative to its first ancestral element whose positioning is either relative or absolute. Does anyone know any workaround? EDIT: small code snippet that demonstrates the problem <html> <body style="background-color: #444444"> <div style="position: relative; background-color: white;"> <div style="position: absolute; background-color: red; width: 4cm; height: 3cm; top: 1cm">div 1 <div style="position: absolute; background-color: green; top: 4cm"> div 1.1</div> </div> </div> </body> </html> The green div is expected to be positioned right after the red div, instead there is a gap of 1cm in between.

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  • CSS: auto height on containing div, 100% height on background div inside containing div.

    - by user47831
    The problem, is that I have a content div which stretches its container height-wise (container and content div have auto height). I want the background container, which is a sister div of the content div to stretch to fill the container. The background container contains divs to break the background into chunks. The background and container divs have 100% width, the content container doesn't. HTML: <div id="container"> <div id="content"> Some long content here .. </div> <div id="backgroundContainer"> <div id="someDivToShowABackground"/> <div id="someDivToShowAnotherBackground"/> </div> </div> CSS: #container { height:auto; width:100%; } #content { height: auto; width:500px; margin-left:auto; margin-right:auto; } #backgroundContainer { height:100%;??? I want this to be the same height as container, but 100% makes it the height of the viewport. }`

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  • CSS: auto height on containing div, 100% height on background div inside containing div.

    - by user47831
    The problem, is that I have a content div which stretches its container height-wise (container and content div have auto height). I want the background container, which is a sister div of the content div to stretch to fill the container. The background container contains divs to break the background into chunks. The background and container divs have 100% width, the content container doesn't. HTML: <div id="container"> <div id="content"> Some long content here .. </div> <div id="backgroundContainer"> <div id="someDivToShowABackground"/> <div id="someDivToShowAnotherBackground"/> </div> </div> CSS: container ` container { height:auto; width:100%; } content { height: auto; width:500px; margin-left:auto; margin-right:auto; } backgroundContainer { height:100%;??? I want this to be the same height as container, but 100% makes it the height of the viewport. }`

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  • How do I get my Nvidia monitor position settings (in Linux) to persist after a restart?

    - by machineghost
    I have two monitors, and I run them both in Linux using the proprietary Nvidia drivers with "TwinView". I just installed Linux Mint 13, and since the install after every reboot my monitors come up in the wrong position (the computer thinks the left monitor is on the right). After boot-up I can run the Nvidia config and fix the monitors' position, and I can even save the configuration file successfully. But as soon as I restart again, the monitors re-appear switched. Does anyone have any idea what might be causing this (and more importantly, how I can solve it?)

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  • How to change Windows 8 Start Background Image and Color Scheme?

    - by Lukas Schmelzeisen
    I want to change the style of the Windows 8 Start Screen: Under Charmsbar > Settings > More PC Settings > Personalize > Start Screen you can choose out of 20 predefined background images and between 25 predefined color schemes: How can you specify your own custom Windows 8 Start Background Image and Color Scheme? There were multiple Tools for the preview version like Windows 8 UI Tweaker or My WCP Start Screen Customizer, however none of them seem to work in the final release version of Windows 8.

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  • How to tell Vim to extend the background color to the whole screen?

    - by chiborg
    I have an issue with the Vim color schemes: The background color does not fill the whole screen. For example, in the "blue" color scheme the whole screen should turn blue. Instead, the blue background only extends to the end of each line. Is this a setting in the console I'm missing or is this an issue with my vim default settings? I'm only having this issue with Ubuntu 10.10. echo $TERM outputs xterm-color. [Update]: To eliminate error sources my minimal ~/.vimrc looks like this: filetype plugin on colorscheme blue syntax on /etc/vim/vimrc contains the unchanged defaults of Ubuntu

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  • Is there DBus command to set position of KDE panel?

    - by Liss
    I have single vertical KDE panel. When I switch from single monitor X screen back to triple monitor X screen (with xrandr) my KDE panel ends up on the right edge of middle monitor, instead of right edge of right monitor. Also, many windows are in wrong place after the switch, but I have a script which restores geometry of all windows (as is used to be in triple monitor state before I switched to single monitor mode), so this is not a problem. Unfortunately, it does not work for KDE panel - it stays in the wrong place. I guess I need to use DBus to restore KDE panel position (programmatically move it to right edge of right screen), I tried googling, but it seems it is not very well documented. Is there DBus command to set position of KDE panel?

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  • How to embed word doc as background picture of an Access report using .EMF or equivalent ?

    - by iDevlop
    My company's standard paper has logo, address and all the details in the right margin with a vertical blue line. I have that as a word template. I want to have the same thing as the background of my Invoices report. I managed to do that 5 years ago by saving to EMF format (vector format, prints out nicely) and putting the file as the background of the report. Now my company is moving, and I need to change the address on my invoices, but I can't find out how I did to convert the word doc to EMF. Any suggestion ? By EMF or another process, but I want to avoid BMP, which is huge and does not print nicely. Thanks !

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  • Open application in background without losing current window focus. Fedora 17, Gnome 3

    - by Ishan
    I'm running a script in the background which loads an image with feh depending on which application is currently in focus. However, whenever the script opens the image, window focus is lost to feh. I was able to circumvent this by using xdotool to switch back to the application that was originally in focus, but this introduces a short annoying period of time where the focus is switched from feh to the application. My question is this: is there any way to launch feh in the background such that window focus is NOT lost? System: Fedora 17, Gnome 3, Bash Thanks a ton!

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  • How to keep memory consumption below 500 MB or less than 25 processes at background on netbook?

    - by overmann
    I bought a netbook yesterday, (I'm loving it) but I will never understand why they need to be a lot of processes running on background. I worry about other users who have no idea about it and continue using their computers with occasional choppiness due to 70 processes on background occupying most of the memory I'd like to keep my memory consumption below 500MB (I have 1 GB) is this possible? What are your ideas for this to work? I always run Microsoft Security Essentials at startup and real time protection, how many features can I disable to reach my goal memory usage?

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  • Set one background to stretch across multi-monitor display?

    - by John Isaacks
    I have two monitors and my coworker has three. We were wondering if there was a way to set a single background image to stretch across all the monitors. Right now it's the same image but repeated, so it looks like the same image three times in a row. I would like it to be so that the three images/screens combine to show one image if that makes sense. If I can't set one image to stretch across the screens like that, is there a way to set a different background for each screen? Edit: I just wanted to clarify: I am not talking about one image stretching from his monitors to mine, just stretching across our own monitors.

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  • How to run wireshark on the background without the GUI?

    - by user60968
    Hello everybody, I am trying to run Wireshark on Mac OS X, on the background. I did install the command line utilities, and so I am able to start wireshark and capture packet using the command line. The only thing I want now is to run it on the background, without even having the X11 icon on the task bar and see the window of wireshark. I believe it is possible but can't find anything on the doc of Wireshark. Maybe another way would be to find a trick to hide an icon on Mac OS X... If anybody already did that or have an idea... Thank you Please excuse my English which is not perfect at all

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  • WPF wrappanel item alignment problem when scrolling

    - by Jayho
    Someone help me out pls. I set a wrapPanel in a listbox itemPanelTemplate, Also, I already set the ScrollViewer.CanContentScroll="True". But why the listbox items are not scrolling up/down by ITEM one by one? The scroll style is still by PIXEL. Is anyone help me? <Grid> <ListBox x:Name="testListbox" ScrollViewer.CanContentScroll="True"> <ListBox.ItemsPanel> <ItemsPanelTemplate> <WrapPanel Width="200" ScrollViewer.CanContentScroll="True"/> </ItemsPanelTemplate> </ListBox.ItemsPanel> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> <ListBoxItem Background="LimeGreen" BorderBrush="Black" BorderThickness="3" ScrollViewer.CanContentScroll="True"> <Image Height="50" Width="80" ScrollViewer.CanContentScroll="True"/> </ListBoxItem> </ListBox> </Grid>

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  • center menu within the 960 grid

    - by Kyle Monti
    I have been working on 960 grid,(http://960.gs/) and I used an old style menu i've used in the past from a few years ago and for some reason with the 960 grid, the menu is floating left and I want it centered. ul#menu { width:940px; height:61px; background: url(../images/menu_bg.png) no-repeat; list-style:none; padding-top:0; padding-left:0; margin: 0; } ul#menu li { float:left; } ul#menu li a { background: url(../images/menu_splice_color.png) no-repeat scroll top left; display:block; height:61px; position:relative; } ul#menu li a.shel { width:135px; } ul#menu li a.golf { width:84px; background-position:-135px 0px; } ul#menu li a.pro { width:119px; background-position:-219px 0px; } ul#menu li a.event { width:94px; background-position:-338px 0px; } ul#menu li a.member { width:148px; background-position:-432px 0px; } ul#menu li a.bistro { width:91px; background-position:-580px 0px; } ul#menu li a.contact { width:115px; background-position:-671px 0px; } ul#menu li a span { background: url(../images/menu_splice_color.png) no-repeat scroll bottom left; display:block; position:absolute; top:0; left:0px; height:100%; width:100%; z-index:100; } ul#menu li a.shel span { background-position:0px -61px; } ul#menu li a.golf span { background-position:-135px -61px; } ul#menu li a.pro span { background-position:-219px -61px; } ul#menu li a.events span { background-position:-338px -61px; } ul#menu li a.member span { background-position:-432px -61px; } ul#menu li a.bistro span { background-position:-580px -61px; } ul#menu li a.contact span { background-position:-672px -61px; } and my generic html markup is <div class="container_16"> <!-- Navigation Start --> <div class="grid_16"> <ul id="menu"> <li><a href="#" class="shel"><span></span></a></li> <li><a href="#" class="golf"><span></span></a></li> <li><a href="#" class="pro"><span></span></a></li> <li><a href="#" class="events"><span></span></a></li> <li><a href="#" class="member"><span></span></a></li> <li><a href="#" class="bistro"><span></span></a></li> <li><a href="#" class="contact"><span></span></a></li> </ul> </div> <div class="clear"></div> </div> And I use jquery animations to roll over the images. $(function() { $("ul#menu span").css("opacity","0"); $("ul#menu span").hover(function () { $(this).stop().animate({ opacity: 1 }, "slow"); }, function () { $(this).stop().animate({ opacity: 0 }, "slow"); }); });

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  • Finetuning movement based on gradual rotation towards a target

    - by A.B.
    I have an object which moves towards a target destination by gradually adjusting its facing while moving forwards. If the target destination is in a "blind spot", then the object is incapable of reaching it. This problem is ilustrated in the picture below. When the arrow is ordered to move to point A, it will only end up circling around it (following the red circle) because it is not able to adjust its rotation quickly enough. I'm interested in a solution where the movement speed is multiplied by a number from 0.1 to 1 in proportion to necessity. The problem is, how do I calculate whether it is necessary in the first place? How do I calculate an appropriate multiplier that is neither too small nor too large? void moveToPoint(sf::Vector2f destination) { if (destination == position) return; auto movement_distance = distanceBetweenPoints(position, destination); desired_rotation = angleBetweenPoints(position, destination); /// Check whether rotation should be adjusted if (rotation != desired_rotation) { /// Check whether the object can achieve the desired rotation within the next adjustment of its rotation if (Radian::isWithinDistance(rotation, desired_rotation, rotation_speed)) { rotation = desired_rotation; } else { /// Determine whether to increment or decrement rotation in order to achieve desired rotation if (Radian::convert(desired_rotation - rotation) > 0) { /// Increment rotation rotation += rotation_speed; } else { /// Decrement rotation rotation -= rotation_speed; } } } if (movement_distance < movement_speed) { position = destination; } else { position.x = position.x + movement_speed*cos(rotation); position.y = position.y + movement_speed*sin(rotation); } updateGraphics(); }

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  • Applications: The mathematics of movement, Part 1

    - by TechTwaddle
    Before you continue reading this post, a suggestion; if you haven’t read “Programming Windows Phone 7 Series” by Charles Petzold, go read it. Now. If you find 150+ pages a little too long, at least go through Chapter 5, Principles of Movement, especially the section “A Brief Review of Vectors”. This post is largely inspired from this chapter. At this point I assume you know what vectors are, how they are represented using the pair (x, y), what a unit vector is, and given a vector how you would normalize the vector to get a unit vector. Our task in this post is simple, a marble is drawn at a point on the screen, the user clicks at a random point on the device, say (destX, destY), and our program makes the marble move towards that point and stop when it is reached. The tricky part of this task is the word “towards”, it adds a direction to our problem. Making a marble bounce around the screen is simple, all you have to do is keep incrementing the X and Y co-ordinates by a certain amount and handle the boundary conditions. Here, however, we need to find out exactly how to increment the X and Y values, so that the marble appears to move towards the point where the user clicked. And this is where vectors can be so helpful. The code I’ll show you here is not ideal, we’ll be working with C# on Windows Mobile 6.x, so there is no built-in vector class that I can use, though I could have written one and done all the math inside the class. I think it is trivial to the actual problem that we are trying to solve and can be done pretty easily once you know what’s going on behind the scenes. In other words, this is an excuse for me being lazy. The first approach, uses the function Atan2() to solve the “towards” part of the problem. Atan2() takes a point (x, y) as input, Atan2(y, x), note that y goes first, and then it returns an angle in radians. What angle you ask. Imagine a line from the origin (0, 0), to the point (x, y). The angle which Atan2 returns is the angle the positive X-axis makes with that line, measured clockwise. The figure below makes it clear, wiki has good details about Atan2(), give it a read. The pair (x, y) also denotes a vector. A vector whose magnitude is the length of that line, which is Sqrt(x*x + y*y), and a direction ?, as measured from positive X axis clockwise. If you’ve read that chapter from Charles Petzold’s book, this much should be clear. Now Sine and Cosine of the angle ? are special. Cosine(?) divides x by the vectors length (adjacent by hypotenuse), thus giving us a unit vector along the X direction. And Sine(?) divides y by the vectors length (opposite by hypotenuse), thus giving us a unit vector along the Y direction. Therefore the vector represented by the pair (cos(?), sin(?)), is the unit vector (or normalization) of the vector (x, y). This unit vector has a length of 1 (remember sin2(?) + cos2(?) = 1 ?), and a direction which is the same as vector (x, y). Now if I multiply this unit vector by some amount, then I will always get a point which is a certain distance away from the origin, but, more importantly, the point will always be on that line. For example, if I multiply the unit vector with the length of the line, I get the point (x, y). Thus, all we have to do to move the marble towards our destination point, is to multiply the unit vector by a certain amount each time and draw the marble, and the marble will magically move towards the click point. Now time for some code. The application, uses a timer based frame draw method to draw the marble on the screen. The timer is disabled initially and whenever the user clicks on the screen, the timer is enabled. The callback function for the timer follows the standard Update and Draw cycle. private double totLenToTravelSqrd = 0; private double startPosX = 0, startPosY = 0; private double destX = 0, destY = 0; private void Form1_MouseUp(object sender, MouseEventArgs e) {     destX = e.X;     destY = e.Y;     double x = marble1.x - destX;     double y = marble1.y - destY;     //calculate the total length to be travelled     totLenToTravelSqrd = x * x + y * y;     //store the start position of the marble     startPosX = marble1.x;     startPosY = marble1.y;     timer1.Enabled = true; } private void timer1_Tick(object sender, EventArgs e) {     UpdatePosition();     DrawMarble(); } Form1_MouseUp() method is called when ever the user touches and releases the screen. In this function we save the click point in destX and destY, this is the destination point for the marble and we also enable the timer. We store a few more values which we will use in the UpdatePosition() method to detect when the marble has reached the destination and stop the timer. So we store the start position of the marble and the square of the total length to be travelled. I’ll leave out the term ‘sqrd’ when speaking of lengths from now on. The time out interval of the timer is set to 40ms, thus giving us a frame rate of about ~25fps. In the timer callback, we update the marble position and draw the marble. We know what DrawMarble() does, so here, we’ll only look at how UpdatePosition() is implemented; private void UpdatePosition() {     //the vector (x, y)     double x = destX - marble1.x;     double y = destY - marble1.y;     double incrX=0, incrY=0;     double distanceSqrd=0;     double speed = 6;     //distance between destination and current position, before updating marble position     distanceSqrd = x * x + y * y;     double angle = Math.Atan2(y, x);     //Cos and Sin give us the unit vector, 6 is the value we use to magnify the unit vector along the same direction     incrX = speed * Math.Cos(angle);     incrY = speed * Math.Sin(angle);     marble1.x += incrX;     marble1.y += incrY;     //check for bounds     if ((int)marble1.x < MinX + marbleWidth / 2)     {         marble1.x = MinX + marbleWidth / 2;     }     else if ((int)marble1.x > (MaxX - marbleWidth / 2))     {         marble1.x = MaxX - marbleWidth / 2;     }     if ((int)marble1.y < MinY + marbleHeight / 2)     {         marble1.y = MinY + marbleHeight / 2;     }     else if ((int)marble1.y > (MaxY - marbleHeight / 2))     {         marble1.y = MaxY - marbleHeight / 2;     }     //distance between destination and current point, after updating marble position     x = destX - marble1.x;     y = destY - marble1.y;     double newDistanceSqrd = x * x + y * y;     //length from start point to current marble position     x = startPosX - (marble1.x);     y = startPosY - (marble1.y);     double lenTraveledSqrd = x * x + y * y;     //check for end conditions     if ((int)lenTraveledSqrd >= (int)totLenToTravelSqrd)     {         System.Console.WriteLine("Stopping because destination reached");         timer1.Enabled = false;     }     else if (Math.Abs((int)distanceSqrd - (int)newDistanceSqrd) < 4)     {         System.Console.WriteLine("Stopping because no change in Old and New position");         timer1.Enabled = false;     } } Ok, so in this function, first we subtract the current marble position from the destination point to give us a vector. The first three lines of the function construct this vector (x, y). The vector (x, y) has the same length as the line from (marble1.x, marble1.y) to (destX, destY) and is in the direction pointing from (marble1.x, marble1.y) to (destX, destY). Note that marble1.x and marble1.y denote the center point of the marble. Then we use Atan2() to get the angle which this vector makes with the positive X axis and use Cosine() and Sine() of that angle to get the unit vector along that same direction. We multiply this unit vector with 6, to get the values which the position of the marble should be incremented by. This variable, speed, can be experimented with and determines how fast the marble moves towards the destination. After this, we check for bounds to make sure that the marble stays within the screen limits and finally we check for the end condition and stop the timer. The end condition has two parts to it. The first case is the normal case, where the user clicks well inside the screen. Here, we stop when the total length travelled by the marble is greater than or equal to the total length to be travelled. Simple enough. The second case is when the user clicks on the very corners of the screen. Like I said before, the values marble1.x and marble1.y denote the center point of the marble. When the user clicks on the corner, the marble moves towards the point, and after some time tries to go outside of the screen, this is when the bounds checking comes into play and corrects the marble position so that the marble stays inside the screen. In this case the marble will never travel a distance of totLenToTravelSqrd, because of the correction is its position. So here we detect the end condition when there is not much change in marbles position. I use the value 4 in the second condition above. After experimenting with a few values, 4 seemed to work okay. There is a small thing missing in the code above. In the normal case, case 1, when the update method runs for the last time, marble position over shoots the destination point. This happens because the position is incremented in steps (which are not small enough), so in this case too, we should have corrected the marble position, so that the center point of the marble sits exactly on top of the destination point. I’ll add this later and update the post. This has been a pretty long post already, so I’ll leave you with a video of how this program looks while running. Notice in the video that the marble moves like a bot, without any grace what so ever. And that is because the speed of the marble is fixed at 6. In the next post we will see how to make the marble move a little more elegantly. And also, if Atan2(), Sine() and Cosine() are a little too much to digest, we’ll see how to achieve the same effect without using them, in the next to next post maybe. Ciao!

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  • HLSL How to flip geometry horizontally

    - by cubrman
    I want to flip my asymmetric 3d model horizontally in the vertex shader alongside an arbitrary plane parallel to the YZ plane. This should switch everything for the model from the left hand side to the right hand side (like flipping it in Photoshop). Doing it in pixel shader would be a huge computational cost (extra RT, more fullscreen samples...), so it must be done in the vertex shader. Once more: this is NOT reflection, i need to flip THE WHOLE MODEL. I thought I could simply do the following: Turn off culling. Run the following code in the vertex shader: input.Position = mul(input.Position, World); // World[3][0] holds x value of the model's pivot in the World. if (input.Position.x <= World[3][0]) input.Position.x += World[3][0] - input.Position.x; else input.Position.x -= input.Position.x - World[3][0]; ... The model is never drawn. Where am I wrong? I presume that messes up the index buffer. Can something be done about it? P.S. it's INSANELY HARD to format code here. Thanks to Panda I found my problem. SOLUTION: // Do thins before anything else in the vertex shader. Position.x *= -1; // To invert alongside the object's YZ plane.

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  • Change collision action

    - by PatrickR
    I have a collision detection and its working fine, the problem is, that whenever my "bird" is hitting a "cloud", the cloud dissapers and i get some points. The same happens for the "sol" which it should, but not with the clouds. How can this be changed ? ive tryed a lot, but can seem to figger it out. Collision Code - (void)update:(ccTime)dt { bird.position = ccpAdd(bird.position, skyVelocity); NSMutableArray *projectilesToDelete = [[NSMutableArray alloc] init]; for (CCSprite *bird in _projectiles) { bird.anchorPoint = ccp(0, 0); CGRect absoluteBox = CGRectMake(bird.position.x, bird.position.y, [bird boundingBox].size.width, [bird boundingBox].size.height); NSMutableArray *targetsToDelete = [[NSMutableArray alloc] init]; for (CCSprite *cloudSprite in _targets) { cloudSprite.anchorPoint = ccp(0, 0); CGRect absoluteBox = CGRectMake(cloudSprite.position.x, cloudSprite.position.y, [cloudSprite boundingBox].size.width, [cloudSprite boundingBox].size.height); if (CGRectIntersectsRect([bird boundingBox], [cloudSprite boundingBox])) { [targetsToDelete addObject:cloudSprite]; } } for (CCSprite *solSprite in _targets) { solSprite.anchorPoint = ccp(0, 0); CGRect absoluteBox = CGRectMake(solSprite.position.x, solSprite.position.y, [solSprite boundingBox].size.width, [solSprite boundingBox].size.height); if (CGRectIntersectsRect([bird boundingBox], [solSprite boundingBox])) { [targetsToDelete addObject:solSprite]; score += 50/2; [scoreLabel setString:[NSString stringWithFormat:@"%d", score]]; } } // NÅR SKYEN BLIVER RAMT AF FUGLEN for (CCSprite *cloudSprite in targetsToDelete) { //[_targets removeObject:cloudSprite]; //[self removeChild:cloudSprite cleanup:YES]; } // NÅR SOLEN BLIVER RAMT AF FUGLEN for (CCSprite *solSprite in targetsToDelete) { [_targets removeObject:solSprite]; [self removeChild:solSprite cleanup:YES]; } if (targetsToDelete.count > 0) { [projectilesToDelete addObject:bird]; } [targetsToDelete release]; } // NÅR FUGLEN BLIVER RAMT AF ALT ANDET for (CCSprite *bird in projectilesToDelete) { //[_projectiles removeObject:bird]; //[self removeChild:bird cleanup:YES]; } [projectilesToDelete release]; }

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  • Finding the shorter turning direction towards a target

    - by A.B.
    I'm trying to implement a type of movement where the object gradually faces the target. The problem I've run into is figuring out which turning direction is faster. The following code works until the object's orientation crosses the -PI or PI threshold, at which point it will start turning into the opposite direction void moveToPoint(sf::Vector2f destination) { if (destination == position) return; auto distance = distanceBetweenPoints(position, destination); auto direction = angleBetweenPoints(position, destination); /// Decides whether incrementing or decrementing orientation is faster /// the next line is the problem if (atan2(sin(direction - rotation), cos(direction - rotation)) > 0 ) { /// Increment rotation rotation += rotation_speed; } else { /// Decrement rotation rotation -= rotation_speed; } if (distance < movement_speed) { position = destination; } else { position.x = position.x + movement_speed*cos(rotation); position.y = position.y + movement_speed*sin(rotation); } updateGraphics(); } 'rotation' and 'rotation_speed' are implemented as custom data type for radians which cannot have values lower than -PI and greater than PI. Any excess or deficit "wraps around". For example, -3.2 becomes ~3.08.

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  • How to do a multishot in xna?

    - by DeVonte
    I am trying to simulate a gun in which shoots multiple bullets at the same time(similar to a spread out shot). I am thinking I have to create another bullet array then do the same as I have below but in a different direction. Here is what I have so far: foreach (GameObject bullet in bullets) { // Find a bullet that isn't alive if (!bullet.alive) { //And set it to alive bullet.alive = true; if (flip == SpriteEffects.FlipHorizontally) //Facing right { float armCos = (float)Math.Cos(arm.rotation - MathHelper.PiOver2); float armSin = (float)Math.Sin(arm.rotation - MathHelper.PiOver2); // Set the initial position of our bullets at the end of our gun arm // 42 is obtained by taking the width of the Arm_Gun texture / 2 // and subtracting the width of the Bullet texture / 2. ((96/2)=(12/2)) bullet.position = new Vector2( arm.position.X + 42 * armCos, arm.position.Y + 42 * armSin); // And give it a velocity of the direction we're aiming. // Increae/decrease speed by changeing 15.0f bullet.Velocity = new Vector2( (float)Math.Cos(arm.rotation - MathHelper.PiOver4 + MathHelper.Pi + MathHelper.PiOver2), (float)Math.Sin(arm.rotation - MathHelper.PiOver4 + MathHelper.Pi + MathHelper.PiOver2)) * 15.0f; } else //Facing left { float armCos = (float)Math.Cos(arm.rotation + MathHelper.PiOver2); float armSin = (float)Math.Sin(arm.rotation + MathHelper.PiOver2); //Set the initial position of our bullet at the end of our gun arm //42 is obtained be taking the width of the Arm_Gun texture / 2 //and subtracting the width of the Bullet texture / 2. ((96/2)-(12/2)) bullet.position = new Vector2( arm.position.X - 42 * armCos, arm.position.Y - 42 * armSin); //And give it a velocity of the direction we're aiming. //Increase/decrease speed by changing 15.0f bullet.Velocity = new Vector2( -armCos, -armSin) * 15.0f; } return; }// End if }// End foreach

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