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• Mysql performance problem & Failed DIMM

  - by murdoch

  Hi I have a dedicated mysql database server which has been having some performance problems recently, under normal load the server will be running fine, then suddenly out of the blue the performance will fall off a cliff. The server isn't using the swap file and there is 12GB of RAM in the server, more than enough for its needs. After contacting my hosting comapnies support they have discovered that there is a failed 2GB DIMM in the server and have scheduled to replace it tomorow morning. My question is could a failed DIMM result in the performance problems I am seeing or is this just coincidence? My worry is that they will replace the ram tomorrow but the problems will persist and I will still be lost of explanations so I am just trying to think ahead. The reason I ask is that there is plenty of RAM in the server, more than required and simply missing 2GB should be a problem, so if this failed DIMM is causing these performance problems then the OS must be trying to access the failed DIMM and slowing down as a result. Does that sound like a credible explanation? This is what DELLs omreport program says about the RAM, notice one dimm is "Critical" Memory Information Health : Critical Memory Operating Mode Fail Over State : Inactive Memory Operating Mode Configuration : Optimizer Attributes of Memory Array(s) Attributes : Location Memory Array 1 : System Board or Motherboard Attributes : Use Memory Array 1 : System Memory Attributes : Installed Capacity Memory Array 1 : 12288 MB Attributes : Maximum Capacity Memory Array 1 : 196608 MB Attributes : Slots Available Memory Array 1 : 18 Attributes : Slots Used Memory Array 1 : 6 Attributes : ECC Type Memory Array 1 : Multibit ECC Total of Memory Array(s) Attributes : Total Installed Capacity Value : 12288 MB Attributes : Total Installed Capacity Available to the OS Value : 12004 MB Attributes : Total Maximum Capacity Value : 196608 MB Details of Memory Array 1 Index : 0 Status : Ok Connector Name : DIMM_A1 Type : DDR3-Registered Size : 2048 MB Index : 1 Status : Ok Connector Name : DIMM_A2 Type : DDR3-Registered Size : 2048 MB Index : 2 Status : Ok Connector Name : DIMM_A3 Type : DDR3-Registered Size : 2048 MB Index : 3 Status : Critical Connector Name : DIMM_B1 Type : DDR3-Registered Size : 2048 MB Index : 4 Status : Ok Connector Name : DIMM_B2 Type : DDR3-Registered Size : 2048 MB Index : 5 Status : Ok Connector Name : DIMM_B3 Type : DDR3-Registered Size : 2048 MB the command free -m shows this, the server seems to be using more than 10GB of ram which would suggest it is trying to use the DIMM total used free shared buffers cached Mem: 12004 10766 1238 0 384 4809 -/+ buffers/cache: 5572 6432 Swap: 2047 0 2047 iostat output while problem is occuring avg-cpu: %user %nice %system %iowait %steal %idle 52.82 0.00 11.01 0.00 0.00 36.17 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 47.00 0.00 576.00 0 576 sda1 0.00 0.00 0.00 0 0 sda2 1.00 0.00 32.00 0 32 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 46.00 0.00 544.00 0 544 avg-cpu: %user %nice %system %iowait %steal %idle 53.12 0.00 7.81 0.00 0.00 39.06 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 49.00 0.00 592.00 0 592 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 49.00 0.00 592.00 0 592 avg-cpu: %user %nice %system %iowait %steal %idle 56.09 0.00 7.43 0.37 0.00 36.10 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 232.00 0.00 64520.00 0 64520 sda1 0.00 0.00 0.00 0 0 sda2 159.00 0.00 63728.00 0 63728 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 73.00 0.00 792.00 0 792 avg-cpu: %user %nice %system %iowait %steal %idle 52.18 0.00 9.24 0.06 0.00 38.51 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 49.00 0.00 600.00 0 600 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 49.00 0.00 600.00 0 600 avg-cpu: %user %nice %system %iowait %steal %idle 54.82 0.00 8.64 0.00 0.00 36.55 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 100.00 0.00 2168.00 0 2168 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 100.00 0.00 2168.00 0 2168 avg-cpu: %user %nice %system %iowait %steal %idle 54.78 0.00 6.75 0.00 0.00 38.48 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 84.00 0.00 896.00 0 896 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 84.00 0.00 896.00 0 896 avg-cpu: %user %nice %system %iowait %steal %idle 54.34 0.00 7.31 0.00 0.00 38.35 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 81.00 0.00 840.00 0 840 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 81.00 0.00 840.00 0 840 avg-cpu: %user %nice %system %iowait %steal %idle 55.18 0.00 5.81 0.44 0.00 38.58 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 317.00 0.00 105632.00 0 105632 sda1 0.00 0.00 0.00 0 0 sda2 224.00 0.00 104672.00 0 104672 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 93.00 0.00 960.00 0 960 avg-cpu: %user %nice %system %iowait %steal %idle 55.38 0.00 7.63 0.00 0.00 36.98 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 74.00 0.00 800.00 0 800 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 74.00 0.00 800.00 0 800 avg-cpu: %user %nice %system %iowait %steal %idle 56.43 0.00 7.80 0.00 0.00 35.77 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 72.00 0.00 784.00 0 784 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 72.00 0.00 784.00 0 784 avg-cpu: %user %nice %system %iowait %steal %idle 54.87 0.00 6.49 0.00 0.00 38.64 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 80.20 0.00 855.45 0 864 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 80.20 0.00 855.45 0 864 avg-cpu: %user %nice %system %iowait %steal %idle 57.22 0.00 5.69 0.00 0.00 37.09 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 33.00 0.00 432.00 0 432 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 33.00 0.00 432.00 0 432 avg-cpu: %user %nice %system %iowait %steal %idle 56.03 0.00 7.93 0.00 0.00 36.04 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 41.00 0.00 560.00 0 560 sda1 0.00 0.00 0.00 0 0 sda2 2.00 0.00 88.00 0 88 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 39.00 0.00 472.00 0 472 avg-cpu: %user %nice %system %iowait %steal %idle 55.78 0.00 5.13 0.00 0.00 39.09 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 29.00 0.00 392.00 0 392 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 29.00 0.00 392.00 0 392 avg-cpu: %user %nice %system %iowait %steal %idle 53.68 0.00 8.30 0.06 0.00 37.95 Device: tps Blk_read/s Blk_wrtn/s Blk_read Blk_wrtn sda 78.00 0.00 4280.00 0 4280 sda1 0.00 0.00 0.00 0 0 sda2 0.00 0.00 0.00 0 0 sda3 0.00 0.00 0.00 0 0 sda4 0.00 0.00 0.00 0 0 sda5 78.00 0.00 4280.00 0 4280

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• Building a Flash Platformer

  - by Jonathan O

  I am basically making a game where the whole game is run in the onEnterFrame method. This is causing a delay in my code that makes debugging and testing difficult. Should programming an entire platformer in this method be efficient enough for me to run hundreds of lines of code? Also, do variables in flash get updated immediately? Are there just lots of threads listening at the same time? Here is the code... stage.addEventListener(Event.ENTER_FRAME, onEnter); function onEnter(e:Event):void { //Jumping if (Yoshi.y > groundBaseLevel) { dy = 0; canJump = true; onGround = true; //This line is not updated in time } if (Key.isDown(Key.UP) && canJump) { dy = -10; canJump = false; onGround = false; //This line is not updated in time } if(!onGround) { dy += gravity; Yoshi.y += dy; } //limit screen boundaries //character movement if (! Yoshi.hitTestObject(Platform)) //no collision detected { if (Key.isDown(Key.RIGHT)) { speed += 4; speed *= friction; Yoshi.x = Yoshi.x + movementIncrement + speed; Yoshi.scaleX = 1; Yoshi.gotoAndStop('Walking'); } else if (Key.isDown(Key.LEFT)) { speed -= 4; speed *= friction; Yoshi.x = Yoshi.x - movementIncrement + speed; Yoshi.scaleX = -1; Yoshi.gotoAndStop('Walking'); } else { speed *= friction; Yoshi.x = Yoshi.x + speed; Yoshi.gotoAndStop('Still'); } } else //bounce back collision detected { if(Yoshi.hitTestPoint(Platform.x - Platform.width/2, Platform.y - Platform.height/2, false)) { trace('collision left'); Yoshi.x -=20; } if(Yoshi.hitTestPoint(Platform.x, Platform.y - Platform.height/2, false)) { trace('collision top'); onGround=true; //This update is not happening in time speed = 0; } } }

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• USB external drive is not recognized by any OS, how to troubleshoot in Ubuntu?

  - by Breno

  First of all I would like to inform you that I saw a question similar to mine but the error was different, so here's my problem... I have an external HD samsung s2 model of 500GB and a day to day just stopped working, tried in other systems (windows and mac) however are not recognized. In the windows device manager when I insert the usb it states that the device in question are not working properly. Well, in the logs of my ubuntu 4.12 I see the following message when I insert my usb device in: [ 2967.560216] usb 7-2: new full-speed USB device number 2 using uhci_hcd [ 2967.680182] usb 7-2: device descriptor read/64, error -71 [ 2967.904176] usb 7-2: device descriptor read/64, error -71 [ 2968.120227] usb 7-2: new full-speed USB device number 3 using uhci_hcd [ 2968.240207] usb 7-2: device descriptor read/64, error -71 [ 2968.464063] usb 7-2: device descriptor read/64, error -71 [ 2968.680087] usb 7-2: new full-speed USB device number 4 using uhci_hcd [ 2969.092085] usb 7-2: device not accepting address 4, error -71 [ 2969.208155] usb 7-2: new full-speed USB device number 5 using uhci_hcd [ 2969.624076] usb 7-2: device not accepting address 5, error -71 [ 2969.624118] hub 7-0:1.0: unable to enumerate USB device on port 2 [ 4520.240340] usb 7-1: new full-speed USB device number 6 using uhci_hcd [ 4520.364079] usb 7-1: device descriptor read/64, error -71 [ 4520.588109] usb 7-1: device descriptor read/64, error -71 [ 4520.804140] usb 7-1: new full-speed USB device number 7 using uhci_hcd [ 4520.924136] usb 7-1: device descriptor read/64, error -71 [ 4521.148083] usb 7-1: device descriptor read/64, error -71 [ 4521.364105] usb 7-1: new full-speed USB device number 8 using uhci_hcd [ 4521.776237] usb 7-1: device not accepting address 8, error -71 [ 4521.888206] usb 7-1: new full-speed USB device number 9 using uhci_hcd [ 4522.296102] usb 7-1: device not accepting address 9, error -71 [ 4522.296150] hub 7-0:1.0: unable to enumerate USB device on port 1 [ 4749.036104] usb 7-2: new full-speed USB device number 10 using uhci_hcd [ 4749.156209] usb 7-2: device descriptor read/64, error -71 [ 4749.380215] usb 7-2: device descriptor read/64, error -71 [ 4749.596206] usb 7-2: new full-speed USB device number 11 using uhci_hcd [ 4749.716409] usb 7-2: device descriptor read/64, error -71 [ 4749.940110] usb 7-2: device descriptor read/64, error -71 [ 4750.156257] usb 7-2: new full-speed USB device number 12 using uhci_hcd [ 4750.572150] usb 7-2: device not accepting address 12, error -71 [ 4750.684215] usb 7-2: new full-speed USB device number 13 using uhci_hcd [ 4751.100182] usb 7-2: device not accepting address 13, error -71 [ 4751.100224] hub 7-0:1.0: unable to enumerate USB device on port 2 Here is my system: Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 002 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 006 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 007 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 008 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 005 Device 002: ID 08ff:2810 AuthenTec, Inc. AES2810 00:00.0 Host bridge: Intel Corporation Mobile 4 Series Chipset Memory Controller Hub (rev 07) 00:02.0 VGA compatible controller: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller (rev 07) 00:02.1 Display controller: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller (rev 07) 00:1a.0 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #4 (rev 02) 00:1a.1 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #5 (rev 02) 00:1a.2 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #6 (rev 02) 00:1a.7 USB controller: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #2 (rev 02) 00:1b.0 Audio device: Intel Corporation 82801I (ICH9 Family) HD Audio Controller (rev 02) 00:1c.0 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 1 (rev 02) 00:1c.1 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 2 (rev 02) 00:1c.4 PCI bridge: Intel Corporation 82801I (ICH9 Family) PCI Express Port 5 (rev 02) 00:1d.0 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #1 (rev 02) 00:1d.1 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #2 (rev 02) 00:1d.2 USB controller: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #3 (rev 02) 00:1d.7 USB controller: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #1 (rev 02) 00:1e.0 PCI bridge: Intel Corporation 82801 Mobile PCI Bridge (rev 92) 00:1f.0 ISA bridge: Intel Corporation ICH9M LPC Interface Controller (rev 02) 00:1f.2 IDE interface: Intel Corporation 82801IBM/IEM (ICH9M/ICH9M-E) 2 port SATA Controller [IDE mode] (rev 02) 00:1f.3 SMBus: Intel Corporation 82801I (ICH9 Family) SMBus Controller (rev 02) 00:1f.5 IDE interface: Intel Corporation 82801IBM/IEM (ICH9M/ICH9M-E) 2 port SATA Controller [IDE mode] (rev 02) 02:01.0 CardBus bridge: Ricoh Co Ltd RL5c476 II (rev ba) 02:01.1 FireWire (IEEE 1394): Ricoh Co Ltd R5C832 IEEE 1394 Controller (rev 04) 02:01.2 SD Host controller: Ricoh Co Ltd R5C822 SD/SDIO/MMC/MS/MSPro Host Adapter (rev 21) 09:00.0 Ethernet controller: Broadcom Corporation NetXtreme BCM5756ME Gigabit Ethernet PCI Express 0c:00.0 Network controller: Broadcom Corporation BCM4312 802.11b/g LP-PHY (rev 01) Does anyone have any clue what would be the problem?

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• Page allocation failures on iSCSI storage

  - by Dave

  We have a CentOS 6.3 iscsi server (16GB RAM) running on Infiniband bus (ipoib). When the load is high I can see multiple errors: Sep 3 23:22:20 stor4 kernel: tgtd: page allocation failure. order:2, mode:0x20 Sep 3 23:22:20 stor4 kernel: Pid: 3637, comm: tgtd Not tainted 2.6.32 #1 Sep 3 23:22:20 stor4 kernel: Call Trace: Sep 3 23:22:20 stor4 kernel: [] ? __alloc_pages_nodemask+0x77f/0x940 Sep 3 23:22:20 stor4 kernel: [] ? kmem_getpages+0x62/0x170 Sep 3 23:22:20 stor4 kernel: [] ? fallback_alloc+0x1ba/0x270 Sep 3 23:22:20 stor4 kernel: [] ? cache_grow+0x2cf/0x320 Sep 3 23:22:20 stor4 kernel: [] ? ____cache_alloc_node+0x99/0x160 Sep 3 23:22:20 stor4 kernel: [] ? pskb_expand_head+0x64/0x270 Sep 3 23:22:20 stor4 kernel: [] ? __kmalloc+0x189/0x220 Sep 3 23:22:20 stor4 kernel: [] ? pskb_expand_head+0x64/0x270 Sep 3 23:22:20 stor4 kernel: [] ? __pskb_pull_tail+0x2aa/0x360 Sep 3 23:22:20 stor4 kernel: [] ? tcp_init_tso_segs+0x37/0x50 Sep 3 23:22:20 stor4 kernel: [] ? dev_queue_xmit+0x4bb/0x6f0 Sep 3 23:22:20 stor4 kernel: [] ? neigh_connected_output+0xbd/0x100 Sep 3 23:22:20 stor4 kernel: [] ? ip_finish_output+0x237/0x310 Sep 3 23:22:20 stor4 kernel: [] ? ip_output+0xb8/0xc0 Sep 3 23:22:20 stor4 kernel: [] ? __ip_local_out+0x9f/0xb0 Sep 3 23:22:20 stor4 kernel: [] ? ip_local_out+0x25/0x30 Sep 3 23:22:20 stor4 kernel: [] ? ip_queue_xmit+0x190/0x420 Sep 3 23:22:20 stor4 kernel: [] ? sock_aio_write+0x167/0x180 Sep 3 23:22:20 stor4 kernel: [] ? tcp_transmit_skb+0x3fe/0x7b0 Sep 3 23:22:20 stor4 kernel: [] ? tcp_write_xmit+0x1fb/0xa20 Sep 3 23:22:20 stor4 kernel: [] ? __tcp_push_pending_frames+0x30/0xe0 Sep 3 23:22:20 stor4 kernel: [] ? tcp_push_pending_frames+0x33/0x40 Sep 3 23:22:20 stor4 kernel: [] ? do_tcp_setsockopt+0x3d6/0x480 Sep 3 23:22:20 stor4 kernel: [] ? tcp_setsockopt+0x2a/0x30 Sep 3 23:22:20 stor4 kernel: [] ? sock_common_setsockopt+0x14/0x20 Sep 3 23:22:20 stor4 kernel: [] ? sys_setsockopt+0x7f/0xe0 Sep 3 23:22:20 stor4 kernel: [] ? system_call_fastpath+0x16/0x1b Sep 3 23:22:20 stor4 kernel: Mem-Info: Sep 3 23:22:20 stor4 kernel: Node 0 DMA per-cpu: Sep 3 23:22:20 stor4 kernel: CPU 0: hi: 0, btch: 1 usd: 0 Sep 3 23:22:20 stor4 kernel: CPU 1: hi: 0, btch: 1 usd: 0 Sep 3 23:22:20 stor4 kernel: CPU 2: hi: 0, btch: 1 usd: 0 Sep 3 23:22:20 stor4 kernel: CPU 3: hi: 0, btch: 1 usd: 0 Sep 3 23:22:20 stor4 kernel: Node 0 DMA32 per-cpu: Sep 3 23:22:20 stor4 kernel: CPU 0: hi: 186, btch: 31 usd: 183 Sep 3 23:22:20 stor4 kernel: CPU 1: hi: 186, btch: 31 usd: 23 Sep 3 23:22:20 stor4 kernel: CPU 2: hi: 186, btch: 31 usd: 183 Sep 3 23:22:20 stor4 kernel: CPU 3: hi: 186, btch: 31 usd: 181 Sep 3 23:22:20 stor4 kernel: Node 0 Normal per-cpu: Sep 3 23:22:20 stor4 kernel: CPU 0: hi: 186, btch: 31 usd: 171 Sep 3 23:22:20 stor4 kernel: CPU 1: hi: 186, btch: 31 usd: 29 Sep 3 23:22:20 stor4 kernel: CPU 2: hi: 186, btch: 31 usd: 32 Sep 3 23:22:20 stor4 kernel: CPU 3: hi: 186, btch: 31 usd: 32 Sep 3 23:22:20 stor4 kernel: active_anon:1875 inactive_anon:2473 isolated_anon:0 Sep 3 23:22:20 stor4 kernel: active_file:1243637 inactive_file:2505055 isolated_file:0 Sep 3 23:22:20 stor4 kernel: unevictable:0 dirty:268338 writeback:0 unstable:0 Sep 3 23:22:20 stor4 kernel: free:86050 slab_reclaimable:132377 slab_unreclaimable:23744 Sep 3 23:22:20 stor4 kernel: mapped:1293 shmem:222 pagetables:720 bounce:0 Sep 3 23:22:20 stor4 kernel: Node 0 DMA free:15732kB min:124kB low:152kB high:184kB active_anon:0kB inactive_anon:0kB active_file:0kB inactive_file:0kB unevictable:0kB isolated(anon):0kB isolated(file):0kB present:15332kB mlocked:0kB dirty:0kB writeback:0kB mapped:0kB shmem:0kB slab_reclaimable:0kB slab_unreclaimable:0kB kernel_stack:0kB pagetables:0kB unstable:0kB bounce:0kB writeback_tmp:0kB pages_scanned:0 all_unreclaimable? yes Sep 3 23:22:20 stor4 kernel: lowmem_reserve[]: 0 2172 16060 16060 Sep 3 23:22:20 stor4 kernel: Node 0 DMA32 free:107544kB min:18268kB low:22832kB high:27400kB active_anon:468kB inactive_anon:2364kB active_file:566208kB inactive_file:976112kB unevictable:0kB isolated(anon):0kB isolated(file):0kB present:2224900kB mlocked:0kB dirty:96816kB writeback:0kB mapped:908kB shmem:12kB slab_reclaimable:176940kB slab_unreclaimable:968kB kernel_stack:64kB pagetables:192kB unstable:0kB bounce:0kB writeback_tmp:0kB pages_scanned:0 all_unreclaimable? no Sep 3 23:22:20 stor4 kernel: lowmem_reserve[]: 0 0 13887 13887 Sep 3 23:22:20 stor4 kernel: Node 0 Normal free:220924kB min:116772kB low:145964kB high:175156kB active_anon:7032kB inactive_anon:7528kB active_file:4408340kB inactive_file:9044108kB unevictable:0kB isolated(anon):0kB isolated(file):0kB present:14220800kB mlocked:0kB dirty:976536kB writeback:0kB mapped:4264kB shmem:876kB slab_reclaimable:352568kB slab_unreclaimable:94008kB kernel_stack:2048kB pagetables:2688kB unstable:0kB bounce:0kB writeback_tmp:0kB pages_scanned:0 all_unreclaimable? no Sep 3 23:22:20 stor4 kernel: lowmem_reserve[]: 0 0 0 0 Sep 3 23:22:20 stor4 kernel: Node 0 DMA: 1*4kB 0*8kB 1*16kB 1*32kB 1*64kB 0*128kB 1*256kB 0*512kB 1*1024kB 1*2048kB 3*4096kB = 15732kB Sep 3 23:22:20 stor4 kernel: Node 0 DMA32: 16305*4kB 4381*8kB 353*16kB 8*32kB 1*64kB 1*128kB 0*256kB 1*512kB 1*1024kB 0*2048kB 0*4096kB = 107900kB Sep 3 23:22:20 stor4 kernel: Node 0 Normal: 14548*4kB 14808*8kB 2420*16kB 31*32kB 5*64kB 0*128kB 0*256kB 0*512kB 0*1024kB 0*2048kB 1*4096kB = 220784kB Sep 3 23:22:20 stor4 kernel: 3748822 total pagecache pages Sep 3 23:22:20 stor4 kernel: 0 pages in swap cache Sep 3 23:22:20 stor4 kernel: Swap cache stats: add 0, delete 0, find 0/0 Sep 3 23:22:20 stor4 kernel: Free swap = 975864kB Sep 3 23:22:20 stor4 kernel: Total swap = 975864kB Sep 3 23:22:20 stor4 kernel: 4194303 pages RAM Sep 3 23:22:20 stor4 kernel: 126915 pages reserved Sep 3 23:22:20 stor4 kernel: 3753534 pages shared Sep 3 23:22:20 stor4 kernel: 213500 pages non-shared TCP stack and VM config: net.core.rmem_max = 83886080 net.core.wmem_max = 83886080 net.core.rmem_default = 65536 net.core.wmem_default = 65536 net.ipv4.tcp_rmem = 40960 1048560 4194304 net.ipv4.tcp_wmem = 40960 196608 4194304 net.ipv4.tcp_mem = 16388608 16388608 16388608 vm.min_free_kbytes=135168 Additional tweaks: /sbin/blockdev --setra 16384 /dev/sdb echo 2048 /sys/block/sdb/queue/nr_requests Where might the problem be? Thank you.

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• How can I move along an angled collision at a constant speed?

  - by Raven Dreamer

  I have, for all intents and purposes, a Triangle class that objects in my scene can collide with (In actuality, the right side of a parallelogram). My collision detection and resolution code works fine for the purposes of preventing a gameobject from entering into the space of the Triangle, instead directing the movement along the edge. The trouble is, the maximum speed along the x and y axis is not equivalent in my game, and moving along the Y axis (up or down) should take twice as long as an equivalent distance along the X axis (left or right). Unfortunately, these speeds apply to the collision resolution too, and movement along the blue path above progresses twice as fast. What can I do in my collision resolution to make sure that the speedlimit for Y axis movement is obeyed in the latter case? Collision Resolution for this case below (vecInput and velocity are the position and velocity vectors of the game object): // y = mx+c lowY = 2*vecInput.x + parag.rightYIntercept ; ... else { // y = mx+c // vecInput.y = 2(x) + RightYIntercept // (vecInput.y - RightYIntercept) / 2 = x; //if velocity.Y (positive) greater than velocity.X (negative) //pushing from bottom, so push right. if(velocity.y > -1*velocity.x) { vecInput = new Vector2((vecInput.y - parag.rightYIntercept)/2, vecInput.y); Debug.Log("adjusted rightwards"); } else { vecInput = new Vector2( vecInput.x, lowY); Debug.Log("adjusted downwards"); } }

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• Why does my game loop speed vary on different platforms with the same hardware?

  - by Sri Harsha Chilakapati

  I've got a serious issue with my game loop. This loop varies in time with the platform and with the same hardware. This is a list of FPS achieved: - Windows ======= 140 to 150 - Linux ======= 120 to 125 - Windows(WINE) ======= 125 to 135 And since my game loop is fixed timestep, the speed of the game is not stable. Here's my game loop. public final void run() { // Initialize the resources Map.initMap(); initResources(); // Start the timer GTimer.startTimer(); GTimer.refresh(); long elapsedTime = 0; // The game loop while (running) { // Update the game update(elapsedTime); if (state == GameState.GAME_PLAYING) { Map.updateObjects(elapsedTime); } // Show or hide the cursor if (Global.HIDE_CURSOR) { setCursor(GInput.INVISIBLE_CURSOR); } else { setCursor(Cursor.getDefaultCursor()); } // Repaint the game and sync repaint(); elapsedTime = GTimer.sync(); Toolkit.getDefaultToolkit().sync(); } } The timer package How could I improve it?

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• Why load increase ,ssd iops increase but cpu iowait decrease?

  - by mq44944

  There is a strange thing on my server which has a mysql running on it. The QPS is more than 4000 but TPS is less than 20. The server load is more than 80 and cpu usr is more than 86% but iowait is less than 8%. The disk iops is more than 16000 and util of disk is more than 99%. When the QPS decreases, the load decreases, the cpu iowait increases. I can't catch this! root@mypc # dmidecode | grep "Product Name" Product Name: PowerEdge R510 Product Name: 084YMW root@mypc # megacli -PDList -aALL |grep "Inquiry Data" Inquiry Data: SEAGATE ST3600057SS ES656SL316PT Inquiry Data: SEAGATE ST3600057SS ES656SL30THV Inquiry Data: ATA INTEL SSDSA2CW300362CVPR201602A6300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR2044037K300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204402PX300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204403WN300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR202000HU300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR202001E7300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204402WE300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204404E5300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204401QF300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR20450001300EGN the mysql data files lie on the ssd disks which are organizaed using RAID 10. root@mypc # megacli -LDInfo -L1 -a0 Adapter 0 -- Virtual Drive Information: Virtual Disk: 1 (Target Id: 1) Name: RAID Level: Primary-1, Secondary-0, RAID Level Qualifier-0 Size:1427840MB State: Optimal Stripe Size: 64kB Number Of Drives:2 Span Depth:5 Default Cache Policy: WriteThrough, ReadAheadNone, Direct, No Write Cache if Bad BBU Current Cache Policy: WriteThrough, ReadAheadNone, Direct, No Write Cache if Bad BBU Access Policy: Read/Write Disk Cache Policy: Disk's Default Exit Code: 0x00 -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:05:29|79.80 64.49 42.00| 82 7 6 5| 0 0|16421.1 10.6262705.9 85.2 8.3 0.5 0.1 99.5| 0 0 0 3968 0| 495482 96.58| 09:05:30|79.80 64.49 42.00| 79 7 8 6| 0 0|15907.4 230.6254409.7 6357.5 8.4 0.5 0.1 98.5| 0 0 0 4195 0| 496434 96.68| 09:05:31|81.34 65.07 42.31| 81 7 7 5| 0 0|16198.7 8.6259029.2 99.8 8.1 0.5 0.1 99.3| 0 0 0 4220 0| 508983 96.70| 09:05:32|81.34 65.07 42.31| 82 7 5 5| 0 0|16746.6 8.7267853.3 92.4 8.5 0.5 0.1 99.4| 0 0 0 4084 0| 503834 96.54| 09:05:33|81.34 65.07 42.31| 81 7 6 5| 0 0|16498.7 9.6263856.8 92.3 8.0 0.5 0.1 99.3| 0 0 0 4030 0| 507051 96.60| 09:05:34|81.34 65.07 42.31| 80 8 7 6| 0 0|16328.4 11.5261101.6 95.8 8.1 0.5 0.1 98.3| 0 0 0 4119 0| 504409 96.63| 09:05:35|81.31 65.33 42.52| 82 7 6 5| 0 0|16374.0 8.7261921.9 92.5 8.1 0.5 0.1 99.7| 0 0 0 4127 0| 507279 96.66| 09:05:36|81.31 65.33 42.52| 81 8 6 5| 0 0|16496.2 8.6263832.0 84.5 8.5 0.5 0.1 99.2| 0 0 0 4100 0| 505054 96.59| 09:05:37|81.31 65.33 42.52| 82 8 6 4| 0 0|16239.4 9.6259768.8 84.3 8.0 0.5 0.1 99.1| 0 0 0 4273 0| 510621 96.72| 09:05:38|81.31 65.33 42.52| 81 7 6 5| 0 0|16349.6 8.7261439.2 81.4 8.2 0.5 0.1 98.9| 0 0 0 4171 0| 510145 96.67| 09:05:39|81.31 65.33 42.52| 82 7 6 5| 0 0|16116.8 8.7257667.6 96.5 8.0 0.5 0.1 99.1| 0 0 0 4348 0| 513093 96.74| 09:05:40|79.60 65.24 42.61| 79 7 7 7| 0 0|16154.2 242.9258390.4 6388.4 8.5 0.5 0.1 99.0| 0 0 0 4033 0| 507244 96.70| 09:05:41|79.60 65.24 42.61| 79 7 8 6| 0 0|16583.1 21.2265129.6 173.5 8.2 0.5 0.1 99.1| 0 0 0 3995 0| 501474 96.57| 09:05:42|79.60 65.24 42.61| 81 8 6 5| 0 0|16281.0 9.7260372.2 69.5 8.3 0.5 0.1 98.7| 0 0 0 4221 0| 509322 96.70| 09:05:43|79.60 65.24 42.61| 80 7 7 6| 0 0|16355.3 8.7261515.5 104.3 8.2 0.5 0.1 99.6| 0 0 0 4087 0| 502052 96.62| -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:05:44|79.60 65.24 42.61| 83 7 5 4| 0 0|16469.4 11.6263387.0 138.8 8.2 0.5 0.1 98.7| 0 0 0 4292 0| 509979 96.65| 09:05:45|79.07 65.37 42.77| 80 7 6 6| 0 0|16659.5 9.7266478.7 85.0 8.4 0.5 0.1 98.5| 0 0 0 3899 0| 496234 96.54| 09:05:46|79.07 65.37 42.77| 78 7 7 8| 0 0|16752.9 8.7267921.8 97.1 8.4 0.5 0.1 98.9| 0 0 0 4126 0| 508300 96.57| 09:05:47|79.07 65.37 42.77| 82 7 6 5| 0 0|16657.2 9.6266439.3 84.3 8.3 0.5 0.1 98.9| 0 0 0 4086 0| 502171 96.57| 09:05:48|79.07 65.37 42.77| 79 8 6 6| 0 0|16814.5 8.7268924.1 77.6 8.5 0.5 0.1 99.0| 0 0 0 4059 0| 499645 96.52| 09:05:49|79.07 65.37 42.77| 81 7 6 5| 0 0|16553.0 6.8264708.6 42.5 8.3 0.5 0.1 99.4| 0 0 0 4249 0| 501623 96.60| 09:05:50|79.63 65.71 43.01| 79 7 7 7| 0 0|16295.1 246.9260475.0 6442.4 8.7 0.5 0.1 99.1| 0 0 0 4231 0| 511032 96.70| 09:05:51|79.63 65.71 43.01| 80 7 6 6| 0 0|16568.9 8.7264919.7 104.7 8.3 0.5 0.1 99.7| 0 0 0 4272 0| 517177 96.68| 09:05:53|79.63 65.71 43.01| 79 7 7 6| 0 0|16539.0 8.6264502.9 87.6 8.4 0.5 0.1 98.9| 0 0 0 3992 0| 496728 96.52| 09:05:54|79.63 65.71 43.01| 79 7 7 7| 0 0|16527.5 11.6264363.6 92.6 8.5 0.5 0.1 98.8| 0 0 0 4045 0| 502944 96.59| 09:05:55|79.63 65.71 43.01| 80 7 7 6| 0 0|16374.7 12.5261687.2 134.9 8.6 0.5 0.1 99.2| 0 0 0 4143 0| 507006 96.66| 09:05:56|76.05 65.20 42.96| 77 8 8 8| 0 0|16464.9 9.6263314.3 111.9 8.5 0.5 0.1 98.9| 0 0 0 4250 0| 505417 96.64| 09:05:57|76.05 65.20 42.96| 79 7 6 7| 0 0|16460.1 8.8263283.2 93.4 8.3 0.5 0.1 98.8| 0 0 0 4294 0| 508168 96.66| 09:05:58|76.05 65.20 42.96| 80 7 7 7| 0 0|16176.5 9.6258762.1 127.3 8.3 0.5 0.1 98.9| 0 0 0 4160 0| 509349 96.72| 09:05:59|76.05 65.20 42.96| 75 7 9 10| 0 0|16522.0 10.7264274.6 93.1 8.6 0.5 0.1 97.5| 0 0 0 4034 0| 492623 96.51| -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:06:00|76.05 65.20 42.96| 79 7 7 7| 0 0|16369.6 21.2261867.3 262.5 8.4 0.5 0.1 98.9| 0 0 0 4305 0| 494509 96.59| 09:06:01|75.33 65.23 43.09| 73 6 9 12| 0 0|15864.0 209.3253685.4 6238.0 10.0 0.6 0.1 98.7| 0 0 0 3913 0| 483480 96.62| 09:06:02|75.33 65.23 43.09| 73 7 8 12| 0 0|15854.7 12.7253613.2 93.6 11.0 0.7 0.1 99.0| 0 0 0 4271 0| 483771 96.64| 09:06:03|75.33 65.23 43.09| 75 7 9 9| 0 0|16074.8 8.7257104.3 81.7 8.1 0.5 0.1 98.5| 0 0 0 4060 0| 480701 96.55| 09:06:04|75.33 65.23 43.09| 76 7 8 9| 0 0|16221.7 9.7259500.1 139.4 8.1 0.5 0.1 97.6| 0 0 0 3953 0| 486774 96.56| 09:06:05|74.98 65.33 43.24| 78 7 8 8| 0 0|16330.7 8.7261166.5 85.3 8.2 0.5 0.1 98.5| 0 0 0 3957 0| 481775 96.53| 09:06:06|74.98 65.33 43.24| 75 7 9 9| 0 0|16093.7 11.7257436.1 93.7 8.2 0.5 0.1 99.2| 0 0 0 3938 0| 489251 96.60| 09:06:07|74.98 65.33 43.24| 75 7 5 13| 0 0|15758.9 19.2251989.4 188.2 14.7 0.9 0.1 99.7| 0 0 0 4140 0| 494738 96.70| 09:06:08|74.98 65.33 43.24| 69 7 10 15| 0 0|16166.3 8.7258474.9 81.2 8.9 0.5 0.1 98.7| 0 0 0 3993 0| 487162 96.58| 09:06:09|74.98 65.33 43.24| 74 7 9 10| 0 0|16071.0 8.7257010.9 93.3 8.2 0.5 0.1 99.2| 0 0 0 4098 0| 491557 96.61| 09:06:10|70.98 64.66 43.14| 71 7 9 12| 0 0|15549.6 216.1248701.1 6188.7 8.3 0.5 0.1 97.8| 0 0 0 3879 0| 480832 96.66| 09:06:11|70.98 64.66 43.14| 71 7 10 13| 0 0|16233.7 22.4259568.1 257.1 8.2 0.5 0.1 99.2| 0 0 0 4088 0| 493200 96.62| 09:06:12|70.98 64.66 43.14| 78 7 8 7| 0 0|15932.4 10.6254779.5 108.1 8.1 0.5 0.1 98.6| 0 0 0 4168 0| 489838 96.63| 09:06:13|70.98 64.66 43.14| 71 8 9 12| 0 0|16255.9 11.5259902.3 103.9 8.3 0.5 0.1 98.0| 0 0 0 3874 0| 481246 96.52| 09:06:14|70.98 64.66 43.14| 60 6 16 18| 0 0|15621.0 9.7249826.1 81.9 8.0 0.5 0.1 99.3| 0 0 0 3956 0| 480278 96.65|

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• How to force two process to run on the same CPU?

  - by kovan

  Context: I'm programming a software system that consists of multiple processes. It is programmed in C++ under Linux. and they communicate among them using Linux shared memory. Usually, in software development, is in the final stage when the performance optimization is made. Here I came to a big problem. The software has high performance requirements, but in machines with 4 or 8 CPU cores (usually with more than one CPU), it was only able to use 3 cores, thus wasting 25% of the CPU power in the first ones, and more than 60% in the second ones. After many research, and having discarded mutex and lock contention, I found out that the time was being wasted on shmdt/shmat calls (detach and attach to shared memory segments). After some more research, I found out that these CPUs, which usually are AMD Opteron and Intel Xeon, use a memory system called NUMA, which basically means that each processor has its fast, "local memory", and accessing memory from other CPUs is expensive. After doing some tests, the problem seems to be that the software is designed so that, basically, any process can pass shared memory segments to any other process, and to any thread in them. This seems to kill performance, as process are constantly accessing memory from other processes. Question: Now, the question is, is there any way to force pairs of processes to execute in the same CPU?. I don't mean to force them to execute always in the same processor, as I don't care in which one they are executed, altough that would do the job. Ideally, there would be a way to tell the kernel: If you schedule this process in one processor, you must also schedule this "brother" process (which is the process with which it communicates through shared memory) in that same processor, so that performance is not penalized.

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• How to limit speed with BMW JSDK on 116i?

  - by lexicore

  I'm experimenting with the BMW Java SDK on the new BMW 116i Innovation Package. Basic things like turning the lights on and off, starting and stopping the motor work fine. What I'm trying to do now is that to write a carlet which would limit the speed to the maximum configured in the driver profile. Driver identity will be detected as usual via RFID reader. My problem is that though I can read the speed from the tachometer, I can't really limit the speed. Here's what I've got working so far: public class SpeenControllingCarlet extends GenericCarlet { public void start(final VehicleModel model) throws CarletException { RfidReader rfidReader = (RfidReader) model .getDevice(Devices.DRIVER_RFID_READER); Rfid rfid = rfidReader.getRfid(); DriverProfile driverProfile = model.getDriverProfileRegistry() .getDriverProfile(rfid.toString()); if (driverProfile == null) { return; } final Double maxAllowedSpeed = Double.valueOf(driverProfile .getCustomAttribute("maxAllowedSpeed", "190")); Tachometer tachometer = (Tachometer) mode.getDevice(Devices.TACHOMETER); tachometer.addSpeedListener(new SpeedListener() { public void onSpeedChanged(SpeedChangedEvent speedChangedEvent) { if (speedChangedEvent.getCurrentSpeed() > maxAllowedSpeed) { Horn horn = (Horn) mode.getDevice(Devices.HORN); horn.beep(440, 2000); } } }); } } This will just beep for two seconds if the driver goes faster than the driver profile allows. My question is - is there a possibility to actually limit the speed (not just silly beeping)?

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• When using Direct3D, how much math is being done on the CPU?

  - by zirgen

  Context: I'm just starting out. I'm not even touching the Direct3D 11 API, and instead looking at understanding the pipeline, etc. From looking at documentation and information floating around the web, it seems like some calculations are being handled by the application. That, is, instead of simply presenting matrices to multiply to the GPU, the calculations are being done by a math library that operates on the CPU. I don't have any particular resources to point to, although I guess I can point to the XNA Math Library or the samples shipped in the February DX SDK. When you see code like mViewProj = mView * mProj;, that projection is being calculated on the CPU. Or am I wrong? If you were writing a program, where you can have 10 cubes on the screen, where you can move or rotate cubes, as well as viewpoint, what calculations would you do on the CPU? I think I would store the geometry for the a single cube, and then transform matrices representing the actual instances. And then it seems I would use the XNA math library, or another of my choosing, to transform each cube in model space. Then get the coordinates in world space. Then push the information to the GPU. That's quite a bit of calculation on the CPU. Am I wrong? Am I reaching conclusions based on too little information and understanding? What terms should I Google for, if the answer is STFW? Or if I am right, why aren't these calculations being pushed to the GPU as well?

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• How to get wireless (Alfa) operate in full power and speed up wireless Internet?

  - by MahboobeAlam

  I am using Wireless to connect to the internet (router). My laptop has Atheros wireless (AR 242x/542x) adapter but the router is a little bit far-away from my room so I have to use an external wireless adapter i.e. Alfa (Realtek 8187) for connectivity. However, since I have started using Ubuntu I noticed that Alfa is not working in full power, internet speed in Ubuntu is much slower than in Windows on my laptop. When I am using Windows 7 the LED (bulb) on Alfa blinks as it should, but when in Ubuntu, it doesn't blink rather it is on but very dim. Connection using Atheros adapter is also the same (slow)... I have tried 4 methods (I found on the Internet) to troubleshoot this matter but no success. It seems to me that Ubuntu/Linux is not letting these wireless adapters to operate in full strength. iwconfig shows that power management is off for both. So what's the problem? Details: ifconfig eth0 Link encap:Ethernet HWaddr 00:1f:16:1e:36:ec UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) Interrupt:45 Base address:0x6000 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:1657 errors:0 dropped:0 overruns:0 frame:0 TX packets:1657 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:241697 (241.6 KB) TX bytes:241697 (241.6 KB) wlan0 Link encap:Ethernet HWaddr 00:22:5f:9b:24:b5 inet6 addr: fe80::222:5fff:fe9b:24b5/64 Scope:Link UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:715460 errors:0 dropped:0 overruns:0 frame:0 TX packets:694246 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:493539292 (493.5 MB) TX bytes:235159393 (235.1 MB) wlan1 Link encap:Ethernet HWaddr 00:c0:ca:42:14:62 inet addr:192.168.100.102 Bcast:192.168.100.255 Mask:255.255.255.0 inet6 addr: fe80::2c0:caff:fe42:1462/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:171053 errors:0 dropped:0 overruns:0 frame:0 TX packets:181363 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:74094659 (74.0 MB) TX bytes:59474204 (59.4 MB) iwconfig lo no wireless extensions. eth0 no wireless extensions. wlan0 IEEE 802.11bg ESSID:off/any Mode:Managed Access Point: Not-Associated Tx-Power=20 dBm Retry long limit:7 RTS thr:off Fragment thr:off Power Management:off wlan1 IEEE 802.11bg ESSID:"Zia" Mode:Managed Frequency:2.412 GHz Access Point: 00:0D:F0:9C:A6:18 Bit Rate=54 Mb/s Tx-Power=20 dBm Retry long limit:7 RTS thr:off Fragment thr:off Power Management:off Link Quality=70/70 Signal level=-31 dBm Rx invalid nwid:0 Rx invalid crypt:0 Rx invalid frag:0 Tx excessive retries:204 Invalid misc:6610 Missed beacon:0

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• Why would more CPU cores on virtual machine slow compile times?

  - by Sid

  [edit#2] If anyone from VMWare can hit me up with a copy of VMWare Fusion, I'd be more than happy to do the same as a VirtualBox vs VMWare comparison. Somehow I suspect the VMWare hypervisor will be better tuned for hyperthreading (see my answer too) I'm seeing something curious. As I increase the number of cores on my Windows 7 x64 virtual machine, the overall compile time increases instead of decreasing. Compiling is usually very well suited for parallel processing as in the middle part (post dependency mapping) you can simply call a compiler instance on each of your .c/.cpp/.cs/whatever file to build partial objects for the linker to take over. So I would have imagined that compiling would actually scale very well with # of cores. But what I'm seeing is: 8 cores: 1.89 sec 4 cores: 1.33 sec 2 cores: 1.24 sec 1 core: 1.15 sec Is this simply a design artifact due to a particular vendor's hypervisor implementation (type2:virtualbox in my case) or something more pervasive across more VMs to make hypervisor implementations more simpler? With so many factors, I seem to be able to make arguments both for and against this behavior - so if someone knows more about this than me, I'd be curious to read your answer. Thanks Sid [edit:addressing comments] @MartinBeckett: Cold compiles were discarded. @MonsterTruck: Couldn't find an opensource project to compile directly. Would be great but can't screwup my dev env right now. @Mr Lister, @philosodad: Have 8 hw threads, using VirtualBox, so should be 1:1 mapping without emulation @Thorbjorn: I have 6.5GB for the VM and a smallish VS2012 project - it's quite unlikely that I'm swapping in/out trashing the page file. @All: If someone can point to an open source VS2010/VS2012 project, that might be a better community reference than my (proprietary) VS2012 project. Orchard and DNN seem to need environment tweaking to compile in VS2012. I really would like to see if someone with VMWare Fusion also sees this (for VMWare vs VirtualBox compartmentalization) Test details: Hardware: Macbook Pro Retina CPU : Core i7 @ 2.3Ghz (quad core, hyper threaded = 8 cores in windows task manager) Memory : 16 GB Disk : 256GB SSD Host OS: Mac OS X 10.8 VM type: VirtualBox 4.1.18 (type 2 hypervisor) Guest OS: Windows 7 x64 SP1 Compiler: VS2012 compiling a solution with 3 C# Azure projects Compile times measure by VS2012 plugin called 'VSCommands' All tests run 5 times, first 2 runs discarded, last 3 averaged

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• Adatbázis szerver konszolidáció Oracle technológiákkal - eroforrás allokálás

  - by Lajos Sárecz

  Szerver konszolidációnál alapmegoldás a virtualizáció, pedig az Oracle Database rendelkezik olyan képességekkel, melyekkel a virtualizáció elonyeit élvezhetjük, ám teljesítményben felülmúljuk azt. Több adatbázis konszolidációját meg lehet oldani egy nagy szerveren, vagy egy több szerverbol álló klaszteren. Bármelyik megoldást is választjuk (ezek elonyeivel és hátrányaival most nem foglalkozok), az egyik legfontosabb megoldandó probléma, hogy biztonsággal el tudjuk oket szeparálni akár adatbiztonsági, akár eroforrás kezelési szempontból. A szoftveres és hardveres virtualizációk lehetové teszik, hogy a szerver eroforrásait több virtuális szerver között felosszuk, ezáltal elszeparálhatók a párhuzamosan futó adatbázis példányok. Ezek a megoldások általában költségesek, plusz adminisztrációt jelentenek és teljesítmény csökkenést okoznak. Az alábbiakban röviden összeszedem, hogy az Oracle Database milyen eroforrás szeparációs technológiákkal rendelkezik, melyek jól használhatók adatbázis konszolidáció esetén: Adatbázis szolgáltatások: Azt talán minden Oracle adatbázis-kezelovel foglalkozó szakérto tudja, hogy akliensek az adatbázist az adatbázis szolgáltatás nevével érik el. Alapértelmezetten minden adatbázis egyetlen szolgáltatással rendelkezik, mely automatikusan a 'global database name' paraméterrel megegyezo nevet kapja az adatbázis létrehozásakor. Ugyanakkor egy adatbázishoz több szolgáltatás név is rendelheto. A szolgáltatásokkal csoportosíthatók a különbözo feladatokat végrehajtó kliensek, és a szolgáltatásokhoz rendelhetjük hogy melyik kliens csoportnak mennyi rendszer eroforrást allokálunk. Klaszteres adatbázisok (RAC) esetén egy szolgáltatás több adatbázis példányhoz (szerverhez) kapcsolódhat, amivel valós terheléstol függo terhelés elosztás valósítható meg (itt már szerepet kap egyébként a Resource Manager is, lásd késobb). Az alkalmazás számára irrelevánssá válik, hogy az adott szolgáltatást mely szerver szolgálja ki. A szolgáltatásokhoz kapcsolódó eroforrások menet közben dinamikusan bovíthetok, de kezelik a kieso eroforrások hiányát is (failover). Database Resource Manager: Az Oracle Database Resource Manager az adatbázis szintjén kezeli az eroforrásokat, a CPU használatot szabályozza az adatbázis terhelés kontrolljával. A Resource Manager egy CPU-n adott pillanatban csak egyetlen Oracle processz futtatását engedélyezi, miközben a többit várakoztatja (ahogy az egy operációs rendszer ütemezojében is muködik). A Resource Manager csak akkor lép muködésbe, amikor a CPU terhelése eléri a 100%-ot. Ekkor a Resource Plan-nek megfeleloen korlátozhatja az egyes eroforrás csoportok számára elérheto eroforrás (CPU) mennyiségét. Instance Caging: A Resource Manager részeként az Oracle Database 11gR2-tol elérheto Instance Caging technológiával virtualizáció és operációs rendszer szintu eroforrás felosztás nélkül az adatbázis példány szintjén lehet szabályozni az allokált CPU számot. Erre akkor lehet szükség, ha egy szerveren több példány futtatására van szükség. A Resource Manager bekapcsolásával és a cpu_count paraméter beállításával lehet adatbázis példányonként aktiválni az Instance Caging funkcionalitást. A cpu_count egy dinamikus paraméter, célszeru arra az értékre állítani, ahány CPU-t az adott adatbázis példány maximálisan igényelhet. Lehetoség van túlméretezni a példányok számára rendelkezésre álló processzorok számát. Például egy 4 CPUs- szerver esetében ha van 3 példányunk, mindháromnak adhatunk 3 CPU-t. Azonban ha mindegyik terhelés alatt van, akkor a példány számára maximum allokált CPU szám osztva összes allokált CPU számmal arányban részesül a processzorból, ami a példában 33,33%, azaz 1,33 CPU. Input Output Resource Manager (IORM):Nem csak a processzorok használatát szabályozhatjuk, lehetoség van a megosztott storage eroforrásainak felosztására is. Az Input Output Resorce Manager (IORM) alkalmazásával storage szinten tudjuk szabályozni az adatbázisok közötti és azokon belüli minimális I/O szinteket. Database Vault: Ugyanazon adatbázisba konszolidált alkalmazások esetén a rendszergazda szerepkörök szeparálása lehetséges az Oracle Database Vault technológiával. Ezzel elérheto az, hogy biztonságosan konszolidáljuk adatbázisainkat úgy, hogy minden adminisztrátor csak a hozzá tartozó adatokat, objektumokat lássa, módosíthassa.

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• How does a hard drive compare to Flash memory working as a hard drive in terms of speed?

  - by Jian Lin

  Some experiment I did with hard drive read/write speed was 10MB/s write and 40MB/s read, and with a USB Flash drive, it can be 5MB/s write and 10MB/s read. Also, if I put a virtual hard drive .vhd file in a hard drive or in a USB Flash drive and try a Virtual Machine using it, the one using the hard drive is quite fast, while the one using the USB Flash drive is close to not usable. So I wonder some early netbooks use 4GB or 8GB flash memory as the hard drive, and even the Apple Mac Air has an option of using flash memory instead of a hard drive. But in those situation, will the speed be slower than using a hard drive, like in the case of a USB Flash drive?

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• How to compare speed of graphics cards in Windows desktop environment?

  - by Al Kepp

  I use Windows 7 and Intel Core i3 CPU with integrated graphics. My problem is that it eats valuable system RAM for display. I can replace it with an old PCIe Radeon X700, so all system RAM will be usable for applications. The question is if an old Radeon X700 is comparable in W7 desktop speed to a new integrated i3 graphics. Are there any test programs which compare the speed of graphic cards in Windows 7 desktop environment (i.e. no Direct3D games, just Windows desktop)? (According to Tomshardware, Radeon X700 is probably even faster than Core i3 in 3D. But there are no native WDDM 1.1 W7 drivers for X700, only WDDM 1.0 Vista drivers are available.)

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• When to increase AWS RDS MySQL Server instance to larger CPU/RAM?

  - by rksprst

  I'm wondering at what stage do I need to increase the image for the RDS MySQL server to a larger CPU/RAM instance. The CPU utilization graph is near 0. The Avg Free Memory is around 150MB. The Avg Swap Usage is 420MB. Read Latency is 0-20ms/op it spikes up randomly. Avg write latency is on average 5ms/op but spikes up to 10-20ms/op. Are there some common rules here that I should follow? Thanks!

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• AWStats on Plesk consumes all of CPU and crashes server - how do you disable plesk.

  - by columbo

  Hello, I have Plesk 9.0.1 running on a Red Hat server. Every week or so at about 4:10am the server locks up. At this time the server CPU usage shhots from 4% to 90% at the same time as a mass of awstats.pl processes start (I can't see how many as my datat only shows the top 30 processes, but all of these are awstats.pl). I turned off awstats through the Plesk control panel for all but 5 domains but I still get 90% CPU usage and at least 30 instances of awstats.pl happening at 4:10am as usual. Does anyone know why this may be? Does anyone know how to disable awstats (I have stats covered using piwik)? Thanks

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• Rough estimate for speed advantage of SAN-via-fibre to san-via-iSCSI when using VMware vSphere

  - by Dirk Paessler

  We are in the process of setting up two virtualization servers (DELL R710, Dual Quadcore Xeon CPUs at 2.3 Ghz, 48 GB RAM) for VMware VSphere with storage on a SAN (DELL Powervault MD3000i, 10x 500 GB SAS drives, RAID 5) which will be attached via iSCSI on a Gbit Ethernet Switch (DELL Powerconnect 5424, they call it "iSCSI-optimized"). Can anyone give an estimate how much faster a fiber channel based solution would be (or better "feel")? I don't mean the nominal speed advantage, I mean how much faster will virtual machines effectively work? Are we talking twice the speed, five times, 10 times faster? Does it justify the price? PS: We are not talking about heavily used database servers or exchange servers. Most of the virtualized servers run below 3-5% average CPU load.

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• SQL SERVER – #TechEdIn – Presenting Tomorrow on Speed Up! – Parallel Processes and Unparalleled Performance at TechEd India 2012

  - by pinaldave

  Performance tuning is always a very hot topic when it is about SQL Server. SQL Server Performance Tuning is a very challenging subject that requires expertise in Database Administration and Database Development. I always have enjoyed talking about SQL Server Performance tuning subject. However, in India, it’s actually the very first time someone is presenting on this interesting subject, so this time I had the biggest challenge to present this session. Frequently enough, we get these two kind of questions: How to turn off parallelism as it is reducing performance? How to turn on parallelism as I want more performance? The reality is that not everyone knows what exactly is needed by their system. In this session, I have attempted to answer this very question. I’ve decided to provide a balanced view but stay away from theory, which leads us to say “It depends”. The session will have a clear message about this towards its end. Deck Details Slides: 45+ Demos: 7+ Bonus Quiz: 5 Images: 10+ Session delivery time: 52 Mins + 8 Mins of Q & A I have presented this session a couple of times to my friends and so far have received good feedback. Oftentimes, when people hear that I am going to present 45 slides, they all say it is too much to cover. However, when I am done with the session the usual reaction is that I truly gave justice to those slides. Action Item Here are a few of the action items for all of those who are going to attend this session: If you want to attend the session, just come early. There’s a good chance that you may not get a seat because right before me, there is a session from SQL Guru Vinod Kumar. He performs a powerful delivery of million concepts in just a little time. Quiz. I will be asking few questions during the session as well as before the session starts. If you get the correct answer, I will give unique learning material for you. You may not want to miss this learning opportunity at any cosst. Session Details Title: Speed Up! – Parallel Processes and Unparalleled Performance (Add to Calendar) Abstract: “More CPU, More Performance” – A  very common understanding is that usage of multiple CPUs can improve the performance of the query. To get a maximum performance out of any query, one has to master various aspects of the parallel processes. In this deep-dive session, we will explore this complex subject with a very simple interactive demo. Attendees will walk away with proper understanding of CX_PACKET wait types, MAXDOP, parallelism threshold and various other concepts. Date and Time: March 23, 2012, 12:15 to 13:15 Location: Hotel Lalit Ashok - Kumara Krupa High Grounds, Bengaluru – 560001, Karnataka, India. Add to Calendar Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Interview Questions and Answers, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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• How to convert a MKV video to a less CPU intensive video format?

  - by marco.ragogna

  I have a couple of videos at 1920x800 that use the MKV format (4.7 GB). A friend of mine has an old PC that has some problems playing them; the CPU is working at nearly 100%. Is it possible to convert these videos to a less CPU intensive video format? The final size is not a problem, it can also double or more. Into which format should I convert it and which software for Windows should I use (better if free)? Thank you in advance.

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• How can you control the speed of fan that comes with the Antec Sonata III case from the outside?

  - by Emil Lerch

  The Antec Sonata III case comes with a nice 120mm fan that has a 3 speed switch. Most of the time the fan is fine on low, but for games or other taxing workloads I need to switch it to medium or high. Opening the case every time I want to change the setting is kind of a pain. Has anyone figured out a way to control the speed from the outside of the case without going nuclear (e.g. cutting holes in the case)? Other than this annoyance I like the case and the fan that comes with it.

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• SQL Server 2008 CPU usage goes to 100% - troubleshooting help needed?

  - by Ali

  I have a fairly powerful database server having SQL Server 2008 R2 installed. There is only one database on it which is being accessed from 2 servers (around 5/6 applications). The problem is as soon as applications start pointing to the database, system's CPU usage goes upto 100% with sqlserver itself using 95+%. I have checked profiler, there aren't any heavy queries running there. I have checked active connections, they are hardly 150. Still CPU usage is around 100% and applications are experiencing slow response/connection to database server are getting refused. Database grus, I really need some ideas here. Thanks.

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• Why is cpu power management not working in Server 2012 with Hyper-V?

  - by Roland

  We've been using Server2008R2 with Hyper-V for a couple of years now and chose it at the time because of its ability to make use of Intel SpeedStep and AMD PowerNow! Now with Server 2012 and Hyper-V V3, all power management abilities seem to be gone. The CPUs are always at full speed and our servers need twice the energy as before while idling. (Yes, the CPU P-states are enabled in the BIOS) Is this by design? Is there a workaround to enable cpu power management again? Despite the great new features of Hyper-V 3, this would be a show-stopper for us since we are very concerned about energy consumption.

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• How to control fan speed on Compaq Presario under Ubuntu?

  - by Josh

  I have a Compaq Presario R4000 running Ubuntu Linux 9.10 karmic. The system runs very hot and one of the fans is wither never running or always running at the slowest speed. For a while I thought the fan was dead but I just updated the BIOS (Phoenix BIOS) and during the update, that fan suddenly kicked in at full speed! How can I get that fan to spin up during normal usage? I have tried sensores-detect but all it found was k8temp, no fans... (SpeedFan under windows found no fans either)

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• Viewport / Camera Calculation in 2D Game

  - by Dave

  we have a 2D game with some sprites and tiles and some kind of camera/viewport, that "moves" around the scene. so far so good, if we wouldn't had some special behaviour for your camera/viewport translation. normally you could stick the camera to your player figure and center it, resulting in a very cheap, undergraduate, translation equation, like : vec_translation -/+= speed (depending in what keys are pressed. WASD as default.) buuuuuuuuuut, we want our player figure be able to actually reach the bounds, when the viewport/camera has reached a maximum translation. we came up with the following solution (only keys a and d are the shown here, the rest is just adaption of calculation or maybe YOUR super-cool and elegant solution :) ): if(keys[A]) { playerX -= speed; if(playerScreenX <= width / 2 && tx < 0) { playerScreenX = width / 2; tx += speed; } else if(playerScreenX <= width / 2 && (tx) >= 0) { playerScreenX -= speed; tx = 0; if(playerScreenX < 0) playerScreenX = 0; } else if(playerScreenX >= width / 2 && (tx) < 0) { playerScreenX -= speed; } } if(keys[D]) { playerX += speed; if(playerScreenX >= width / 2 && (-tx + width) < sceneWidth) { playerScreenX = width / 2; tx -= speed; } if(playerScreenX >= width / 2 && (-tx + width) >= sceneWidth) { playerScreenX += speed; tx = -(sceneWidth - width); if(playerScreenX >= width - player.width) playerScreenX = width - player.width; } if(playerScreenX <= width / 2 && (-tx + width) < sceneWidth) { playerScreenX += speed; } } i think the code is rather self explaining: keys is a flag container for currently active keys, playerX/-Y is the position of the player according to world origin, tx/ty are the translation components vital to background / npc / item offset calculation, playerOnScreenX/-Y is the actual position of the player figure (sprite) on screen and width/height are the dimensions of the camera/viewport. this all looks quite nice and works well, but there is a very small and nasty calculation error, which in turn sums up to some visible effect. let's consider following piece of code: if(playerScreenX <= width / 2 && tx < 0) { playerScreenX = width / 2; tx += speed; } it can be translated into plain english as : if the x position of your player figure on screen is less or equal the half of your display / camera / viewport size AND there is enough space left LEFT of your viewport/camera then set players x position on screen to width half, increase translation (because we subtract the translation from something we want to move). easy, right?! doing this will create a small delta between playerX and playerScreenX. after so much talking, my question appears now here at the bottom of this document: how do I stick the calculation of my player-on-screen to the actual position of the player AND having a viewport that is not always centered aroung the players figure? here is a small test-case in processing: http://pastebin.com/bFaTauaa thank you for reading until now and thank you in advance for probably answering my question.

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