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  • reverse loop for date display

    - by Michael
    Hi, I've been trying to figure this out, and can't seem to get it Here is the code.. $m= date("m"); $de= date("d"); $y= date("Y"); for($i=0; $i<=6; $i++){ echo "<br>"; echo date('m/d',mktime(0,0,0,$m,($de+$i),$y)); echo "<br>"; } That displays this 04/08 04/07 04/06 04/05 04/04 04/03 04/02 That is exactly what I want but I want it to flip around so echos it would like this 04/02 04/03 04/04 04/05 04/06 04/07 04/07 How would I do this? Thank you in advance!

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  • Can Adobe AIR display SVG?

    - by Ed Thomas
    I see that Adobe AIR uses WebKit as its render and I see that WebKit (at least the most current build) has some SVG support. Does this mean (and has anyone specifically tried) that an Adobe AIR application could render SVG on an HTML page?

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  • Desimal data Type Display scale part as zero

    - by Wael Dalloul
    I have Decimal field in SQLserver 2005 table, Price decimal(18, 4) if I write 12 it will be converted to 12.0000, if I write 12.33 it will be converted into 12.3300. Always it's putting zero to the right of the decimal point in the count of Scale Part(4). I was using these in SQL Server 2000, it was not behaving like this, in SQL Server 2000 if I put 12.5 it will be stored as 12.5 not as 12.5000 what SQLServer2005 do. My Question is how to stop SQL Server 2005 from putting zeros to the right of the decimal point?

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  • Xcode: Display Login View in applicationDidBecomeActive

    - by Patrick
    In my app I would like to show a login screen - which will be displayed when the app starts and when the app becomes active. For reference, I am using storyboards, ARC and it is a tabbed bar application. First off, I have this method which returns the topViewController. - (UIViewController *)topViewController:(UIViewController *)rootViewController { if (rootViewController.presentedViewController == nil) { return rootViewController; } if ([rootViewController.presentedViewController isMemberOfClass:[UINavigationController class]]) { UINavigationController *navigationController = (UINavigationController *)rootViewController.presentedViewController; UIViewController *lastViewController = [[navigationController viewControllers] lastObject]; return [self topViewController:lastViewController]; } UIViewController *presentedViewController = (UIViewController *)rootViewController.presentedViewController; return [self topViewController:presentedViewController]; } And I call this method here: - (void)applicationDidBecomeActive:(UIApplication *)application { if ( ... ) { // if the user needs to login PasswordViewController *passwordView = [[PasswordViewController alloc] init]; UIViewController *myView = [self topViewController:self.window.rootViewController]; [myView presentModalViewController:passwordView animated:NO]; } } To an extent this does work - I can call a method in viewDidAppear which shows an alert view to allow the user to log in. However, this is undesirable and I would like to have a login text box and other ui elements. If I do not call my login method, nothing happens and the screen stays black, even though I have put a label and other elements on the view. Does anyone know a way to resolve this? My passcode view is embedded in a Navigation Controller, but is detached from the main storyboard.

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  • display custome tile for missing tiles in google maps app

    - by Beans
    I am working with google maps in flash, and i would like to know how to serve up my own image tile for the "we have no imagery at this zoom level..." error. I dont want to serve up an entire map of images - just for the times when google has no image does the tile layer base dispatch an event? (i couldnt find any in the api) is there a method that can be overridden by extending the tilelayerbase class any help appreciated

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  • Display small form while main form is "locked"

    - by daemonsvk
    Hi there, i'm thinking about writing a WPF program that would require login and password at the app startup. I thought about small form with two textboxes as a login form. User will have to fill in his details and then the main form of the application will be unlocked. How will you solve this? Thanks for your answers, daemonsvk

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  • How to display Currency in Indian Numbering Format in PHP

    - by Somnath Muluk
    I have a question about formatting the Rupee currency (Indian Rupee - INR). For example, numbers here are represented as: 1 10 100 1,000 10,000 1,00,000 10,00,000 1,00,00,000 10,00,00,000 Refer Indian Numbering System I have to do with it PHP. I have saw this question Displaying Currency in Indian Numbering Format. But couldn't able to get it for PHP my problem. Update: How to use money_format() in indian currency format?

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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • Forms Designer Error Display HTML Source

    - by Pranay Rana
    I i am unable to see the design view of a winform app Errors are: One or more errors encountered while loading the designer. The errors are listed below. Some errors can be fixed by rebuilding your project, while others may require code changes. The event Click is read-only and cannot be changed. at System.ComponentModel.Design.EventBindingService.EventPropertyDescriptor.SetValue(Object component, Object value) at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.DeserializeAttachEventStatement(IDesignerSerializationManager manager, CodeAttachEventStatement statement) at System.ComponentModel.Design.Serialization.CodeDomSerializerBase.DeserializeStatement(IDesignerSerializationManager manager, CodeStatement statement)

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  • how to display bitmaps in listview?

    - by mary
    hi i want to show images downloaded in listview.images downloaded with function DownloadImage and are as bitmap.how to show in listview . name photoes with book_id in tabel book are aqual.i want each book has its own image. i can show in listview book_name and book_price just the problem with image book please help me class: package bookstore.category; import java.io.IOException; import java.io.InputStream; import java.net.HttpURLConnection; import java.net.URL; import java.net.URLConnection; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import org.apache.http.NameValuePair; import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject; import android.graphics.Bitmap; import android.graphics.BitmapFactory; import android.graphics.Typeface; import android.os.AsyncTask; import android.os.Bundle; import android.util.Log; import android.widget.ImageView; import android.widget.ListAdapter; import android.widget.ListView; import android.widget.SimpleAdapter; import bookstore.pack.JSONParser; import bookstore.pack.R; import android.app.Activity; import android.app.ProgressDialog; public class Computer extends Activity { Bitmap bm = null; // progress dialog private ProgressDialog pDialog; // Creating JSON Parser object JSONParser jParser = new JSONParser(); ArrayList<HashMap<String, String>> computerBookList; private static String url_books = "http://10.0.2.2/project/computer.php"; // JSON Node names private static final String TAG_SUCCESS = "success"; private static final String TAG_BOOK = "book"; private static final String TAG_BOOK_NAME = "book_name"; private static final String TAG_BOOK_PRICE = "book_price"; private static final String TAG_BOOK_ID = "book_id"; private static final String TAG_MESSAGE = "massage"; // category JSONArray JSONArray book = null; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.category); Typeface font1 = Typeface.createFromAsset(getAssets(), "font/bnazanin.TTF"); // Hashmap for ListView computerBookList = new ArrayList<HashMap<String, String>>(); new LoadBook().execute(); } class LoadBook extends AsyncTask<String, String, String> { /** * Before starting background thread Show Progress Dialog * */ @Override protected void onPreExecute() { super.onPreExecute(); pDialog = new ProgressDialog(Computer.this); pDialog.setMessage("Please wait..."); pDialog.setIndeterminate(false); pDialog.setCancelable(false); pDialog.show(); } protected String doInBackground(String... args) { // Building Parameters List<NameValuePair> params = new ArrayList<NameValuePair>(); // getting JSON string from URL JSONObject json = jParser.makeHttpRequest(url_books, "GET", params); // Check your log cat for JSON reponse Log.d("book:", json.toString()); try { // Checking for SUCCESS TAG int success = json.getInt(TAG_SUCCESS); if (success == 1) { DownloadImage("10.0.2.2/project/images/100.png"); DownloadImage("10.0.2.2/project/images/101.png"); DownloadImage("10.0.2.2/project/images/102.png"); DownloadImage("10.0.2.2/project/images/103.png"); DownloadImage("10.0.2.2/project/images/104.png"); DownloadImage("10.0.2.2/project/images/105.png"); DownloadImage("10.0.2.2/project/images/106.png"); DownloadImage("10.0.2.2/project/images/107.png"); DownloadImage("10.0.2.2/project/images/108.png"); DownloadImage("10.0.2.2/project/images/109.png"); DownloadImage("10.0.2.2/project/images/110.png"); // books found book = json.getJSONArray(TAG_BOOK); for (int i = 0; i < book.length(); i++) { JSONObject c = book.getJSONObject(i); // Storing each json item in variable String book_name = c.getString(TAG_BOOK_NAME); String book_price = c.getString(TAG_BOOK_PRICE); String book_id = c.getString(TAG_BOOK_ID); // creating new HashMap HashMap<String, String> map = new HashMap<String, String>(); // adding each child node to HashMap key => value map.put(TAG_BOOK_NAME, book_name); map.put(TAG_BOOK_PRICE, book_price); // map.put(TAG_AUTHOR_NAME, author_name); // adding HashList to ArrayList computerBookList.add(map); } return json.getString(TAG_MESSAGE); } else { System.out.println("no book found"); } } catch (JSONException e) { e.printStackTrace(); } return null; } /** * After completing background task Dismiss the progress dialog * **/ protected void onPostExecute(String file_url) { pDialog.dismiss(); // updating UI from Background Thread runOnUiThread(new Runnable() { ListView view1 = (ListView) findViewById(R.id.list_view); public void run() { ImageView iv = (ImageView) findViewById(R.id.list_image); // bm=BitmapFactory.decodeResource(getResources(), resId); //bm=BitmapFactory.decodeResource(null,R.id.list_image); // iv.setImageBitmap(bm); /* * */ /** * Updating parsed JSON data into ListView * */ ListAdapter adapter = new SimpleAdapter(Computer.this, computerBookList, R.layout.search_item, new String[] { TAG_BOOK_NAME, TAG_BOOK_PRICE }, new int[] { R.id.book_name, R.id.book_price }); view1.setAdapter(adapter); } }); } } private Bitmap DownloadImage(String URL) { Bitmap bitmap = null; InputStream in = null; try { in = OpenHttpConnection(URL); bitmap = BitmapFactory.decodeStream(in); in.close(); } catch (IOException e1) { e1.printStackTrace(); } return bitmap; } private InputStream OpenHttpConnection(String urlString) throws IOException { InputStream in = null; int response = -1; URL url = new URL(urlString); URLConnection conn = url.openConnection(); if (!(conn instanceof HttpURLConnection)) throw new IOException("Not an HTTP connection"); try { HttpURLConnection httpConn = (HttpURLConnection) conn; httpConn.setAllowUserInteraction(false); httpConn.setInstanceFollowRedirects(true); httpConn.setRequestMethod("GET"); httpConn.connect(); response = httpConn.getResponseCode(); if (response == HttpURLConnection.HTTP_OK) { in = httpConn.getInputStream(); } } catch (Exception ex) { throw new IOException("Error connecting"); } return in; } }

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  • display classes of a namespace in visual studio (C#)

    - by ericyoung7001
    I am a Java programmer, and just starting to use Visual Studio to do C# programming. In Java IDE such as Eclipse, if I do not know the classname in a package, I can just type a dot (.) after a package name, then I will get a list of all the classes in that package in the IDE. How I can configure visual studio to do the similar thing, say, if I click a namespace name in a file (for example, using System), or add a dot after the namespace, all the classes in that namespace will be displayed somewhere in the IDE?

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  • How to design websites for all display sizes

    - by katie bekell
    I like to use a lot of unique graphics on my pages, which often results in making different page sizes depending on available screen width/height. Here are two examples: http://www.uvm.edu/~areid/homesite/ - the image floats at the bottom of my screen but on a larger browser, the image floats near the middle making it look off. It looks best when the bottom of the window aligns with the bottom of the image www.stevenlebel.com - it loads two different pages depending on what monitor size is detected. This seems like a lot of redundant coding. My question is, how can I make sliced/Photoshop images transition well to different screen sizes. Does Photoshop allow you to make DIVS instead of tables? Can i make each of the slices created by Photoshop grow/shrink when the browser window size changes? If anyone has any input on creating websites like this I would be very interested to hear what they have to say. Thanks Katie

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  • how to display the grid in div tag..

    - by kumar
    <script type="text/javascript"> var showGrid = function() { $("#Grid1").load('/friends/names/fried'); }; </script> <div> <%= Html.Trirand().JQGrid(Model.OrdersGrid, "JqGrid1")%> </div> <div> </div> /////// i need to dispaly the Grid1 here? can anyone tell me? thanks

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  • Display the same prev/next usercontrol twice on a page

    - by Scott
    I haven't seen a question like this. I have a prev/next paging control on my page, one at the top and one at the bottom like this: top pager product catalog bottom pager Each pager is bound to a PagedDataSource that is exactly the same. I don't want to duplicate effort, so I am trying to figure out a way to do the processing once, but show the control twice.

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  • jQuery display text nested in paragraphs inside a div

    - by user961627
    I have HTML that looks something like this: <div class='textbox' data-title='Sometitle'> <div class='textareaedit'> <p><strong>Test sample text</strong></p> </div> </div> I'm sometimes going to have a few different <p> tags inside the textareaedit divs, and sometimes strong tags around the text inside the <p> (as in this example), and sometimes a span tag, and sometimes it's going to be without further tags inside the <p>. I want to iterate through each textbox on my page, grab its title and also the text nested inside <p> tags in textareaedit. I'm giving the output via console for testing. This is my jQuery code, but I get no output for the second console.log() line: $('.textbox').each(function() { $this = $(this); console.log($this.attr('data-title')+ ":\n"); $this.children('textareadit').children('p').each(function(){ console.log($(this).html()); // not giving any output, it's blank }); }); I tried $(this).text() as well, but no difference. You may think this example has the sample text inside <strong> tags within the <p>, but I've also tried the same example without the strong, where the text was the direct child of <p>, but it didn't make a difference. How can I capture the text?

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  • Productivity features in VS, how to display documentation

    - by drasto
    I used to program quite a lot in Java, recently I've began to work with C#. I think that most of advantages of C# (comparing to Java) are corrupted by VS. Now what really makes me crazy is intelisence. It offers only list of classes of that are already in "using". I would like to see suggestions of all classes from all libraries. Then, when I finally remember the name of class I want to use and type it manually I have to confirm "using"(by clicking pop-up(!)). This is cost me some time and makes me nervous. Most important of all then I'm choosing between methods or classes, filling parameters of methods etc. I need to see documentation of those classes, methods etc. VS displays just a small tool tip that is contains only summary what is completely unsatisfactory. It does not even contain methods return type(!) and parameters. Resharper does not solve any of these. Its suggestions are also mostly useless(it suggest actions I don't want to do). As well I'd like to see Resharper's sugestion not only when I'm on the line in task. Can somebody suggest a solution ? Maybe some addon, how to change it in settings or alike? Other productivity features or a way how to "generally" set shortcuts to be the same as in Java would be also appreciated.

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  • What kind of library to use for display of graphical objects and right click context menus

    - by Gopal
    Hi all, Goal: To develop a web based NMS interface which displays a network topology (e.g., switches, routers, links, endhosts). Each node should be 'movable' (draggable to an appropriate place manually or their best location computed algorithmically). I should be able to zoom into the network graph (say if there are many clusters of nodes and I want to concentrate on a particular cluster of nodes). I should be able to right-click any node or link and get a context menu (e.g., 'show routing table', 'show interfaces', 'show bandwidth utilization graph' etc.). The data for this network topology will be fetched by making calls to an apache based webserver where the backend scripts in python will fetch the appropriate data and send it via JSON to the web client. Question: I am assuming that some sort of javascript library/framework will be most appropriate for this - jQuery, Dojo, Moo etc. [I've never used any of these before]. Which of these would be most recommended for this sort of thing. Which would be easiest to learn (say in a months time). Thanks for any tips.

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  • I can't display my pages on ASP.NET

    - by iva123
    Hi, I'm developing a web site with asp.net on localhost, I'm beginner. I wrote a login page and it works well. However when I click a link, the server can't load the page and gives this error: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: Named Pipes Provider, error: 40 - Could not open a connection to SQL Server) Any idea?

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