Search Results

Search found 10480 results on 420 pages for 'session cookies'.

Page 86/420 | < Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >

  • How can web form content be preserved for the back button

    - by Peter Howe
    When a web form is submitted and takes the user to another page, it is quite often the case that the user will click the Back button in order to submit the form again (the form is an advanced search in my case.) How can I reliably preserve the form options selected by the user when they click Back (so they don't have to start from scratch with filling the form in again if they are only changing one of many form elements?) Do I have to go down the route of storing the form options in session data (cookies or server-side) or is there a way to get the browser to handle this for me? (Environment is PHP/JavaScript - and the site must work on IE6+ and Firefox2+)

    Read the article

  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

    Read the article

  • Android and PHP - Do I need to use sessions?

    - by jtnire
    I have created an Android App that communicates with a PHP web server. They both send JSON to each other. My App is almost finished, however there is one thing left to do: authentication. Since the user's username and password will be stored in Android SharedPreferences, is there any need to use PHP sessions, given that the user won't need to enter the username/password at every request? Since I can just send the username and password in the HTTP POST header for every request, and that I will be using SSL, is this sufficient? I guess I could add an extra field in the header called 'random' that just adds a random value, just to use as a salt so that the encrypted SSL payload will be different everytime. The reason why I don't want to use sessions is that my Android App would either have to handle cookies, or managed the storage of the session ID. If there are some serious cons to using my method above, then I'm more than happy to use sessions, however all advice is appreciated. Thanks

    Read the article

  • PHP Redirect location with htaccess

    - by Wayne
    In one of the page I have is where administrators are allowed, however, I use if the session isn't set, the header will redirect them to index.php and that method works. If I replace index.php with home which is for the htaccess which changes it to index.php but it gives an error in the browser This works: if(!isset($_SESSION['MEMBER'])){ header("Location: index.php"); } This does not work: if(!isset($_SESSION['MEMBER'])){ header("Location: home"); } htaccess: RewriteRule ^home$ index.php The error in Firefox: The page isn't redirecting properly Firefox has detected that the server is redirecting the request for this address in a way that will never complete. This problem can sometimes be caused by disabling or refusing to accept cookies. What's wrong with it? How do I get this method to work?

    Read the article

  • PHP Using session variables in array(s)

    - by Chris
    Hello, My question is how do i put these session variables into a array? I have tried countless ways but none of them work. Not really sure what to put in a array and what no and how to adress them. Currently when i fill in the form the data gets displayed in a table. Next when i press the hyperlink that takes me back to the same form, i wish to enter data again. This data should be added in a new row in the same display table. Best Regards. The code below (pardon me that it is not english). <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoFormulier</title> <body> <?php if (!empty($_POST)) { $standnaam = $_POST["standnaam"]; $oppervlakte = $_POST["oppervlakte"]; //value in the form van checkboxes op 1 zetten! $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; if (is_numeric($oppervlakte)) { $_SESSION["standnaam"]=$standnaam; $_SESSION["oppervlakte"]=$oppervlakte; $_SESSION["verdieping"]=$verdieping; $_SESSION["telefoon"]=$telefoon; $_SESSION["netwerk"]=$netwerk; header("Location:ExpoOverzicht.php"); } else { echo "<h1>Foute gegevens, Opnieuw invullen a.u.b</h1>"; } } ?> <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1"> <h1>Vul de gegevens in</h1> <table> <tr> <td>Standnaam:</td> <td><input type="text" name="standnaam" size="18"/></td> </tr> <tr> <td>Oppervlakte (in m^2):</td> <td><input type="text" name="oppervlakte" size="6"/></td> </tr> <tr> <td>Verdieping:</td> <td><input type="checkbox" name="verdieping" value="1"/></td> </tr> <tr> <td>Telefoon:</td> <td><input type="checkbox" name="telefoon" value="1"/></td> </tr> <tr> <td>Netwerk:</td> <td><input type="checkbox" name="netwerk" value="1"/></td> </tr> <tr> <td><input type="submit" name="verzenden" value="Verzenden"/></td> </tr> </table> </form> Second File: <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoOverzicht</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <link href="StyleSheetExpo.css" rel="stylesheet" type="text/css" /> </head> <body> <h1>Overzicht van de ingegeven standen in deze sessie</h1> <?php $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; $result1 = 0; $result2 = 0; $result3 = 0; $prijsCom = 0; $prijsVerdieping = 0; for ($i=1; $i <= $oppervlakte; $i++) { if($i <= 10) { $tarief1 = 1 * 100; $result1 += $tarief1; } if($i > 10 && $i <= 30) { $tarief2 = 1 * 90; $result2 += $tarief2; } if($i > 30) { $tarief3 = 1 * 80; $result3 += $tarief3; } } $prijsOpp = $result1 + $result2 + $result3; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } if(($telefoon == 1) || ($netwerk == 1)) { $prijsCom = 20; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; } $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; echo "<table class=\"tableExpo\">"; echo "<th>Standnaam</th>"; echo "<th>Oppervlakte</th>"; echo "<th>Verdieping</th>"; echo "<th>Telefoon</th>"; echo "<th>Netwerk</th>"; echo "<th>Totale prijs</th>"; echo "<tr>"; echo "<td>".$standnaam."</td>"; echo "<td>".$oppervlakte."</td>"; echo "<td>".$verdieping."</td>"; echo "<td>".$telefoon."</td>"; echo "<td>".$netwerk."</td>"; echo "<td>".$totalePrijs."</td>"; echo "</tr>"; echo "</table>"; ?> <a href="ExpoFormulier.php">Terug naar het formulier</a> </body> </html> </body> </html>

    Read the article

  • Live Chats .NET : le transcript de la deuxième session disponible, prochain rendez-vous avec les experts de Microsoft le 25 juin

    Live Chats .NET : le transcript de la deuxième session disponible prochain rendez-vous avec les experts de Microsoft le 25 juinLe 14 mai dernier, s'est tenue la deuxième session du live chat .NET sur le chat de Developpez.com. Pour rappel, les live chats .NET sont organisés en collaboration avec Microsoft. Ce sont des séances de chat en ligne avec des experts de la société sur le développement d'applications Desktop avec la plate-forme .NET et le futur des outils de développement Microsoft.Les...

    Read the article

  • How to inject a Session Bean into a Message Driven Bean?

    - by Hank
    Hi guys, I'm reasonably new to JEE, so this might be stupid.. bear with me pls :D I would like to inject a stateless session bean into a message-driven bean. Basically, the MDB gets a JMS message, then uses a session bean to perform the work. The session bean holds the business logic. Here's my Session Bean: @Stateless public class TestBean implements TestBeanRemote { public void doSomething() { // business logic goes here } } The matching interface: @Remote public interface TestBeanRemote { public void doSomething(); } Here's my MDB: @MessageDriven(mappedName = "jms/mvs.TestController", activationConfig = { @ActivationConfigProperty(propertyName = "acknowledgeMode", propertyValue = "Auto-acknowledge"), @ActivationConfigProperty(propertyName = "destinationType", propertyValue = "javax.jms.Queue") }) public class TestController implements MessageListener { @EJB private TestBean testBean; public TestController() { } public void onMessage(Message message) { testBean.doSomething(); } } So far, not rocket science, right? Unfortunately, when deploying this to glassfish v3, and sending a message to the appropriate JMS Queue, I get errors that glassfish is unable to locate the TestBean EJB: java.lang.IllegalStateException: Exception attempting to inject Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session into class mvs.test.TestController Caused by: com.sun.enterprise.container.common.spi.util.InjectionException: Exception attempting to inject Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session into class mvs.test.TestController Caused by: javax.naming.NamingException: Lookup failed for 'java:comp/env/mvs.test.TestController/testBean' in SerialContext [Root exception is javax.naming.NamingException: Exception resolving Ejb for 'Remote ejb-ref name=mvs.test.TestController/testBean,Remote 3.x interface =mvs.test.TestBean,ejb-link=null,lookup=null,mappedName=,jndi-name=mvs.test.TestBean,refType=Session' . Actual (possibly internal) Remote JNDI name used for lookup is 'mvs.test.TestBean#mvs.test.TestBean' [Root exception is javax.naming.NamingException: Lookup failed for 'mvs.test.TestBean#mvs.test.TestBean' in SerialContext [Root exception is javax.naming.NameNotFoundException: mvs.test.TestBean#mvs.test.TestBean not found]]] So my questions are: - is this the correct way of injecting a session bean into another bean (particularly a message driven bean)? - why is the naming lookup failing? Thanks for all your help! Cheers, Hank

    Read the article

  • How can I read the properties of an object that I assign to the Session in ASP.NET MVC?

    - by quakkels
    Hey all, I'm trying my hand at creating a session which stores member information which the application can use to reveal certain navigation and allow access to certain pages and member role specific functionality. I've been able to assign my MemberLoggedIn object to the session in this way: //code excerpt start... MemberLoggedIn loggedIn = new MemberLoggedIn(); if (computedHash == member.Hash) { loggedIn.ID = member.ID; loggedIn.Username = member.Username; loggedIn.Email = member.Email; loggedIn.Superuser = member.Superuser; loggedIn.Active = member.Active; Session["loggedIn"] = loggedIn; } else if (ModelState.IsValid) { ModelState.AddModelError("Password", "Incorrect Username or Password."); } return View(); That works great. I then can send the properties of Session["loggedIn"] to the View in this way: [ChildActionOnly] public ActionResult Login() { if (Session["loggedIn"] != null) ViewData.Model = Session["loggedIn"]; else ViewData.Model = null; return PartialView(); } In the Partial View I can reference the session data by using Model.Username or Model.Superuser. However, it doesn't seem to work that way in the controller or in a custom Action Filter. Is there a way to get the equivalent of Session["loggedIn"].Username?

    Read the article

  • Tomcat 4.1.X and Tomcat 5.0.X

    - by user312619
    I have a problem about tomcat, Our application designed on Tomcat 4.1.X and When I restart Tomcat 4.1.X there is no problem. But I upgrade it to Tomcat 5.0.X. Now ,when I restart Tomcat 5.0.X session is down and application redirect me to login page. Any idea?

    Read the article

  • Apache MINA reading from IoSession

    - by Aizaz
    Dear Readers, I am new to Apache MINA kindly guide me how to read from IoSession. I have stored a POJO in it. public static EchoUDPServerDiscoveryObjectResponseProperties echoProperties session.write(echoProperties);

    Read the article

  • Setting a PHP $_SESSION['var'] using jQuery

    - by mike condiff
    I need to set a PHP $_SESSION variable using the jQuery. IF the user clicks on an image I want to save a piece of information associated with that image as a session variable in php. I think I can do this by calling a php page or function and appending that piece of info to the query string. Any ideas. I have found little help through google. thanks mike

    Read the article

  • management users with Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

    Read the article

  • Rails - how can I capture the URL that directed to the current action in my app?

    - by sa125
    Hi - I need to see what page a request came from in my controller so I could be able to redirect back to it. For example, if I'm on a page showing a specific product (say /products/1) and it has a link to its vendor (/vendors/12), I want to be able to detect inside the vendors_controller that I came to that page from /products/1. Is there a simple way in Rails to achieve this, so that I could access it via params or session? thanks.

    Read the article

  • Some question about Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

    Read the article

  • Windows: How to make programs think they're not running in a terminal server session?

    - by sinni800
    I am using the program "SoftXPand 2011 Duo" by Miniframe on my Windows 7 PC. It makes two workstations out of one computer. It uses the terminal services built into Windows to create the additional session. I use two screens, two keyboards and two mice to create this "illusion" of two computers. It works quite well and I can even play two different 3D games on the two screens attached to this single machine (using a Radeon HD5770 and a Core i5 2500k with 8 Gbytes RAM). There are a few downsides to this. I just found about one that is hidden on the first look. The sessions you are in (even on the first workstation) will identify as a terminal server session! Now some programs will run with limited effects (graphical), and some won't run at all. This also resulted in some games not running at all. They just say "Cannot be run in a terminal server session" and exit. I have already proven that top modern games (DirectX 10, 11) run just as good as on the same machine without SoftXPand, so this is a pretty artificial limitation! So, can I somehow hack my current session so it doesn't look like a terminal server session anymore? I. E. #include <windows.h> #pragma comment(lib, "user32.lib") BOOL IsRemoteSession(void) { return GetSystemMetrics( SM_REMOTESESSION ); } Will return FALSE? (Not a programming question! Just an example how programs detect if they're in a terminal server session!)

    Read the article

  • Does somebody have a working sample of PHP session_set_save_handler ?

    - by susana
    PHP Version 5.1.6 All day trying..I'm breaking my head now... I understand it but can't make it work. I need to store the session data in a mysql database, cause we're balancing the request among 2 servers, so regular sessions wont work... I need to use this function ... session_set_save_handler ... and I cant make it work..any help greatly appreciated it. Thank you !

    Read the article

  • facebook auto loggin

    - by sukitha
    I want to save the login information of Facebook after closing the application. So every time when user opens application, no need to login again. Is done by saving the session object into a plist? I'm using facebook connect. Thanks for the help

    Read the article

  • iPhone SDK audioSession question.

    - by Morion
    Hi to all. In my app i record and play audio at the same time. The app is almost finished. But there is one thing, that annoying me. When audio session is set to PlayAndRecord, sounds become quiet in comparison with the same sounds with the SoloAmbient category. Is there any way to make sound louder using PlayAndRecord?

    Read the article

  • State server in webfarm scenario?

    - by Curtis White
    This is a fairly basic question about state server but assume there are 2 servers behind a load balancer. How do I configure the session state server? So, I have machine1 and machine2. I would assume that I would need to install the state server on 1 machine only and then use the internal IP to refer to that machine. Is this correct? As oppose too, I would not install state server on both machines.

    Read the article

  • Simple but good pattern for EJB

    - by Sara
    What would you suggest as a good and practical but simple pattern for a soloution with: HTML + JSP (as a view/presentation) SERVLETS (controller, request, session-handling) EJB (persistence, businesslogic) MySQL DB And is it necessary to use an own layer of DAO for persistence? I use JPA to persist objects to my DB. Should I withdraw business logic from my EJB? Sources online all tell me different things and confuses me...

    Read the article

  • is there a way to disconnect from facebook login without calling logout

    - by Joey
    Basically, I'd like to know how I can logout of my facebook session if I am in an iphone app and have connected to facebook (such that I do not have to repeatedly enter my login/password). Normally you'd disconnect in the app somewhere like in the options, but if this is not available (i.e. anything that triggers the FBSession logout method) is there some other way to do it? I'm guessing one could restore their phone to factory settings or something.

    Read the article

  • logout code in jsp.

    - by ajay
    I am using basic level authentication. and i need best logout code in JSP / servlet. I am using JSP & servlet and MS-ACCESS as backend. Is it require a session creation in JSP? please reply as soon as possible. Thanking you.....

    Read the article

  • Multiple sessions for one user?

    - by ganuke
    Hi I have host web application which is developed using java and jsp. In client side each client give five ajax calls to the server to retrieve data from the server in every 30 seconds. My problem is can one user who use one browser to log in to the system have multiple session at a time. Reason is when i use the tool to use monitor the firewall I can see more than 10 sessions are active for one IP. How this can happen? any comments

    Read the article

< Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >