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  • Run totally silent rsync?

    - by jackr
    I have a cronjob that runs hourly, and is totally silent unless something goes wrong. Well ... almost ... A part of the job is rsync --del -Cacqrz public/. [email protected]:/target/path This always prints "logged in". How can I make it stop? (Short of 'grep -v' ;-) I don't get the "logged in" message if I do things like ssh [email protected] ls The transport is, of course, ssh (using keys). Source host is either OSX or Ubuntu (tried both, same behavior). Target host is Linux of some flavor.

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  • Run command on init and restart on errors

    - by chersanya
    I have internet access on my PC through proxy through SSH, so every time I need to execute ssh -L PORT:SERVER:PORT LOGIN@SERVER and then type a password. After each network failure or reconnect this command has to be executed again. I've got bored of it and look for a way to do this automatically: first run this after boot (it doesn't seem to be a problem - put this command in some init file and that's all) and then rerun it (if possible, then type password) on each network failure. Is it possible, and how? OS Linux (Debian)

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  • cygwin Xserver losing connection

    - by gt6989b
    I am running Xserver on cygwin (on top on Windows 7), and then using xterm to remote to linux via ssh -X, and run remote applications there, like konsole, emacs and others. Initially all works fine, e.g. executing emacs pops up the correctly working window on my Windows 7 box. But if I try to run the same emacs some time (like an hour) later, I get a linux message Display localhost:10.0 unavailable, simulating -nw and emacs runs in-line. I have checked and the Xserver seems still up and running ok. Indeed, if I exit out to the original cygwin and reconnect to Linux by ssh -X again, it works just fine. Would you know what is happening and how can it be fixed? Why is my Xserver connection being dropped? Thank you very much.

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  • Remote desktop into a linux machine, is this possible?

    - by fire
    I have a VPS by my host running on a linux server, and they have given me SSH access. Is it possible to remote desktop into the server, like you can on Windows, so that I can physcially click on things rather than having to use SSH commands? Surely this must be running on Fedora or Ubuntu etc. so there is some type of OS. You would probably have to install something on the servers end I suppose but just want to know if its possible and what the options are. And before you say "why not ask your host" I find superuser responses are usually much quicker :-)

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  • Wait for linux machine to be rebooted

    - by Theo
    I have a small script to install on my remote machine an update. I would like to reboot the machine remotely and if it is rebooted, continue with some more commands. What I currently do is: ssh root@myMachine << COMMANDS_ISSUED ###... Tasks init 6 COMMANDS_ISSUED sleep 180s ssh root@myMachine << POST_REBOOT_COMMANDS ###.... More stuff POST_REBOOT_COMMANDS Is there a more elegant way to do it? Like pinging the machine all 5 seconds up to a maximum of 4 minutes? I play with a few linux machines which have different boot up times and if my script would continue immediately after reboot, this could safe quite some time for me. (Note: I don't want to parallelize execution over all machines as I want to see for each machine if everything worked fine)

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  • Do we need to adopt a black-box asset our project is inheriting from its predecessor?

    - by Tom Anderson
    Our client has an eCommerce site which was developed by an in-house team, and is now showing its age. I work for a firm brought in as external contractors to build a replacement. Part of the current site is a Flash viewer applet which displays media about the product - zoom-able images, 360-degree views, movies, and so on. We need to show the same media the current site does, so we are simply reusing the viewer. The viewer is embedded on a page in the usual way, and told what media to show by means of an XML file it loads from our server, which is pretty simple for us to generate. We've got this working; it was pretty straightforward. But what else do we need to do? The thing is, as far as we're concerned, the viewer is a binary blob which is served from the client's content-distribution network. We embed it, feed it some XML, and it does its job, but we have no power over its internals. It's completely opaque to us - a black box. We can use it to do what it does, but we can't change it, so if we ever need to do something different, we're stuffed. We're building this site for the client, and when we're done, we'll hand it over for them to maintain. We won't be doing the maintenance ourselves. There's a small team within the client who are working as part of our team, and who will be the ones doing the maintenance. That team only includes one person from the team that built the old site, and it's not someone who knows the image viewer. The people who do know the image viewer are not slated to join our team when our system replaces theirs - they'll be moved to other projects. The documentation on the viewer is extremely thin, and as far as i know doesn't cover the internals at all. My worry is that if someone doesn't take some positive action, all knowledge of the internal workings of the viewer - even down to where the source code for it is - will be lost. It's possible it already has been. Is this something to worry about? If so, whose job is it to worry about it? What should they do about it once they've got worried?

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  • How can I write byte[] to socket outputstream and specify the end of file?

    - by Christopher Francisco
    I've googled 2 days straight and I can't find how to do this. I have an open stream between client and server, and client will send a JSON string (encrypted to bytes) to the server each 3 to 5 seconds. How can I write to the Socket OutputStream so that I can read each JSON string in the server. I'm guessing I need to specify some kind of end of file or something, but can't find any info on how to achieve this.

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  • What is the historical basis of using Javascript in web programming?

    - by rd108
    I come from a scientific biology background where we also use Python a lot. Now that I've begun to start with Web development, I've consistently found myself wondering just why it is that JavaScript is the primary client-side language on the Web. Is JavaScript's predominance a historical accident or something else? Also, I'm curious if there are any hurdles to integrating Python into client-side scripting?

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  • freeFTPd and scp/sshfs

    - by singpolyma
    When I connect to freeFTPd using the CLI 'sftp' client from my Ubuntu system, it works find. Unfortunately, that client sucks at downloading whole directory trees. So I tried to use scp and I get "exec request failed on channel 0" So I tried sshfs. I can browse the directory structure, but it lists the files and says they do not exist. The freeFTPd server logs have no useful information.

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  • Certain SFTP user cannot connect

    - by trobrock
    I have my Ubuntu Server set up so users with the group of sftponly can connect with sftp, but have a shell of /bin/false, and they connect to their home directories. This is working fine with three of the user accounts I have. But I added a new user account today the same way that I added the others and it will not successfully connect. sftp -vvv user@hostname debug1: Next authentication method: password user@hostname's password: debug3: packet_send2: adding 48 (len 73 padlen 7 extra_pad 64) debug2: we sent a password packet, wait for reply debug1: Authentication succeeded (password). debug2: fd 5 setting O_NONBLOCK debug3: fd 6 is O_NONBLOCK debug1: channel 0: new [client-session] debug3: ssh_session2_open: channel_new: 0 debug2: channel 0: send open debug1: Requesting [email protected] debug1: Entering interactive session. debug1: channel 0: free: client-session, nchannels 1 debug3: channel 0: status: The following connections are open: #0 client-session (t3 r-1 i0/0 o0/0 fd 5/6 cfd -1) debug3: channel 0: close_fds r 5 w 6 e 7 c -1 debug1: fd 0 clearing O_NONBLOCK debug3: fd 1 is not O_NONBLOCK Connection to hostname closed by remote host. Transferred: sent 2176, received 1848 bytes, in 0.0 seconds Bytes per second: sent 127453.3, received 108241.6 debug1: Exit status -1 Connection closed For a successful user: sftp -vvv good_user@hostname debug1: Next authentication method: password good_user@hostname's password: debug3: packet_send2: adding 48 (len 63 padlen 17 extra_pad 64) debug2: we sent a password packet, wait for reply debug1: Authentication succeeded (password). debug2: fd 5 setting O_NONBLOCK debug3: fd 6 is O_NONBLOCK debug1: channel 0: new [client-session] debug3: ssh_session2_open: channel_new: 0 debug2: channel 0: send open debug1: Requesting [email protected] debug1: Entering interactive session. debug2: callback start debug2: client_session2_setup: id 0 debug1: Sending subsystem: sftp debug2: channel 0: request subsystem confirm 1 debug2: fd 3 setting TCP_NODELAY debug2: callback done debug2: channel 0: open confirm rwindow 0 rmax 32768 debug2: channel 0: rcvd adjust 2097152 debug2: channel_input_status_confirm: type 99 id 0 debug2: subsystem request accepted on channel 0 debug2: Remote version: 3 debug2: Server supports extension "[email protected]" revision 1 debug2: Server supports extension "[email protected]" revision 2 debug2: Server supports extension "[email protected]" revision 2 debug3: Sent message fd 3 T:16 I:1 debug3: SSH_FXP_REALPATH . -> / sftp> I cannot figure out why one user will work and the other wont, I have restart the ssh service after adding the user. I have even removed the user and added them again to be sure I am adding it correctly.

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  • Create an image of a CentOS system

    - by Grant unwin
    I provide a server (and site) to a client via Rackspace Cloud Hosting, and my client wants to now host the entire thing within his own account. Since it's not possible to just transfer the ownership, I need to somehow create an image of the machine via SSH which I can then use on a new server. Is this possible, and does anyone know of a way of doing this. Note I am talking about virtualised machines here, but I only have access to the virtualised partition and not the system as a whole.

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  • Key based authentication (SFTP) failed

    - by rahularyansharma
    I created a pair or RSA keys using Putty key generator, The Public key is attached set on the server side. The private key at windows client machine and being used with pageant and FileZila and working fine. Now Problem is that when I want to connect same sftp through PSFTP commandline tool, it failes. if possible please provide steps to setup ssh key on windows client to access sftp using psftp or direct through batch file.

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  • Eventlet client-server

    - by johannix
    I'm trying to setup a server-client interraction: Server gets a string from client Server returns data to client I got this working with socket.send and socket.recv, but was wondering how to get it working with files through socket.makefile. I've got most of the pieces working, but don't know how to force each of the pieces to read at the appropriate time. So what it looks like is happening is that both the client and server are reading on the socket at the same time. Any ideas on how to let the server complete the original read before the client starts waiting for its information? Below are the core pieces that reproduce the read lock. Server: def handle(green_socket): file_handler = green_socket.makefile('rw') print 'before server read' lines = file_handler.readlines() print "readlines: %s" % (lines) print '** Server started **' server = eventlet.listen((HOST, PORT)) pool = eventlet.GreenPool() while True: new_sock, address = server.accept() pool.spawn_n(handle, new_sock) Client: from eventlet.green import socket green_socket = eventlet.connect((HOST, PORT)) file_handler = green_socket.makefile('rw') print 'before write' file_handler.writelines('client message') file_handler.flush() print 'before client read' lines = file_handler.readlines()

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  • How does real-time collaboration with multiple clients work in a system using operation transformati

    - by Saikat Chakrabarti
    I just finished reading High-Latency, Low-Bandwidth Windowing in the Jupiter Collaboration System and I mostly followed everything until part 6: global consistency. This part describes how the system described in the paper can be extended to accomodate for multiple clients connected to the server. However, the explanation is very short and essentially says the system will work if the central server merely forwards client messages to all the other clients. I don't really understand how this works though. What state vector would be sent in the message that is sent to all the other clients? Does the server maintain separate state vectors for each client? Does it maintain a separate copy of the widgets locally for each client? The simple example I can think of is this setup: imagine client A, server, and client B with client A and client B both connected to the server. To start, all three have the state object "ABCD". Then, client A sends the message "insert character F at position 0" at the same time client B sends the message "insert character G at position 0" to the server. It seems like simply relaying client A's message to client B and vice versa doesn't actually handle this case. So what exactly does the server do?

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  • Web Service Client in JBOSS 5.1 with JDK6

    - by dcp
    This is a continuation of the question here: http://stackoverflow.com/questions/2435286/jboss-does-app-have-to-be-compiled-under-same-jdk-as-jboss-is-running-under It's different enough though that it required a new question. I am trying to use jdk6 to run JBOSS 5.1, and I downloaded the JDK6 version of JBOSS 5.1. This works fine and my EAR application deploys fine. However, when I want to run a web service client with code like this: public static void main(String[] args) throws Exception { System.out.println("creating the web service client..."); TestClient client = new TestClient("http://localhost:8080/tc_test_project-tc_test_project/TestBean?wsdl"); Test service = client.getTestPort(); System.out.println("calling service.retrieveAll() using the service client"); List<TestEntity> list = service.retrieveAll(); System.out.println("the number of elements in list retrieved using the client is " + list.size()); } I get the following exception: javax.xml.ws.WebServiceException: java.lang.UnsupportedOperationException: setProperty must be overridden by all subclasses of SOAPMessage at org.jboss.ws.core.jaxws.client.ClientImpl.handleRemoteException(ClientImpl.java:396) at org.jboss.ws.core.jaxws.client.ClientImpl.invoke(ClientImpl.java:302) at org.jboss.ws.core.jaxws.client.ClientProxy.invoke(ClientProxy.java:170) at org.jboss.ws.core.jaxws.client.ClientProxy.invoke(ClientProxy.java:150) Now, here's the really interesting part. If I change the JDK that my the code above is running under from JDK6 to JDK5, the exception above goes away! It's really strange. The only way I found for the code above to run under JDK6 was to take the JBOSS_HOME/lib/endorsed folder and copy it to JDK6_HOME/lib. This seems like it shouldn't be necessary, but it is. Is there any other way to make this work other than using the workaround I just described?

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  • How to connect remote EJB module from application client

    - by Zeck
    Hi guys, I have a EJB module in remote Glassfish server and application client in my computer. I want to connect from the application client to the remote EJB. Here is the my EJB interface: @Remote public interface BookEJBRemote { public String getTitle(); } Here is the my ejb: @Stateless public class BookEJB implements BookEJBRemote { @Override public String getTitle() { return "Twenty Thousand Leagues Under the Sea"; } } I have several questions : Can I use Dependency Injection in the remote application client to connect to the ejb? If so what can i do to achieve this. Do i need to configure in the sun-ejb-jar.xml and sun-application-client.xml? In other words, if i use DI like @EJB MyEJBRemote ejb; How application client container know what ejb to be injected? Where should i specify the information? How can i run the application client? I tried to run package-appclient in the glassfish server to get appclient.jar and copy it to my computer. Then i type appclient.jar -client myAppClient.jar . It didn't work. How do i point the target server? if i cannot use DI in the client then i guess i have to use JNDI lookup. Do i need to configure jndi name in sun-ejb-jar.xml or in the sun-application-client.xml? No matter how i try i never manage to run application client ? Can you guys put some working example? And thank you for every advises and examples?

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  • Message driven bean not responding until client method is complete

    - by poijoi
    Hi, I have a MDB deployed on Jboss 4.2.2 and a client on the same server that produces messages and expects a reply from the MDB via a temporary queue created before the message is sent. When I run the client, I see that it creates the message, puts it in the queue and waits for the reply (no problem so far) ... but when I check in the logs I see that the timeout is reached and no response is received. When the timeout occurs and the client's method is complete the MDB starts processing the message that should have been processed the moment the client put it in the queue. As a consequence of this timing issue, when the MDB tries to reply to the temp queue, it fails since the client is already gone. If I run the same client from a remote server, I have no problem... The MDB picks up the message from the queue right away and the client receives its response right after the processing is complete. I'm using container managed transactions. I suspect it has something to do with that... I think the client's "send message/receive reply" might be all be considered a transaction before it commits to put the message in the queue... but I'm not sure if this is correct. If this is the case, why did I not see the same behavior from the remote client? is client managed transaction the default setting and that's what my remote server was using? Any idea how to fix this? Thanks in advance! PJ

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  • Getting unhandled error and connection get lost when a client tries to communicate with chat server in twisted

    - by user2433888
    from twisted.internet.protocol import Protocol,Factory from twisted.internet import reactor class ChatServer(Protocol): def connectionMade(self): print "A Client Has Connected" self.factory.clients.append(self) print"clients are ",self.factory.clients self.transport.write('Hello,Welcome to the telnet chat to sign in type aim:YOUR NAME HERE to send a messsage type msg:YOURMESSAGE '+'\n') def connectionLost(self,reason): self.factory.clients.remove(self) self.transport.write('Somebody was disconnected from the server') def dataReceived(self,data): #print "data is",data a = data.split(':') if len(a) > 1: command = a[0] content = a[1] msg="" if command =="iam": self.name + "has joined" elif command == "msg": ma=sg = self.name + ":" +content print msg for c in self.factory.clients: c.message(msg) def message(self,message): self.transport.write(message + '\n') factory = Factory() factory.protocol = ChatServer factory.clients = [] reactor.listenTCP(80,factory) print "Iphone Chat server started" reactor.run() The above code is running succesfully...but when i connect the client (by typing telnet localhost 80) to this chatserver and try to write message ,connection gets lost and following errors occurs : Iphone Chat server started A Client Has Connected clients are [<__main__.ChatServer instance at 0x024AC0A8>] Unhandled Error Traceback (most recent call last): File "C:\Python27\lib\site-packages\twisted\python\log.py", line 84, in callWithLogger return callWithContext({"system": lp}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\log.py", line 69, in callWithContext return context.call({ILogContext: newCtx}, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 118, in callWithContext return self.currentContext().callWithContext(ctx, func, *args, **kw) File "C:\Python27\lib\site-packages\twisted\python\context.py", line 81, in callWithContext return func(*args,**kw) --- --- File "C:\Python27\lib\site-packages\twisted\internet\selectreactor.py", line 150, in _doReadOrWrite why = getattr(selectable, method)() File "C:\Python27\lib\site-packages\twisted\internet\tcp.py", line 199, in doRead rval = self.protocol.dataReceived(data) File "D:\chatserverultimate.py", line 21, in dataReceived content = a[1] exceptions.IndexError: list index out of range Where am I going wrong?

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  • How i can convert client for Axis 1.4 to Axis2 in JAVA ?

    - by dahevos
    Hello, First of all i success to programming a client for an Axis 1.2 web service, but for Axis2 i don't know how i can do, and the tutorial in Apache don't really help me. Here my code : import java.net.URL; import javax.xml.namespace.QName; import org.apache.axis.client.Call; import org.apache.axis.client.Service; public class EmployeClient { public static void main(String [] args) throws Exception { Service service = new Service(); Call call = (Call)service.createCall(); String endpoint = "http://localhost:8080/axis/services/EmployeService"; call.setTargetEndpointAddress(new URL(endpoint)); call.setOperationName(new QName("getCurrentID")); String dept = "marketing"; String name = "sacha"; String position = (String)call.invoke(new Object [] {new String(dept), new String(name)}); System.out.println("Résultat de la recherche : " + position ); } } So how can i do for convert this code in Axis2 ? Thanks you very much. ps : i'm french, sorry for my bad english !

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  • Client/Server app

    - by Knowing me knowing you
    Guys could anyone tell me what's wrong am I doing here? Below are four files Client, main, Server, main. I'm getting an error on Client side after trying to fromServer.readLine(). Error: Error in Client Software caused connection abort: recv failed package client; import java.io.*; import java.net.*; import java.util.Scanner; public class Client { private PrintWriter toServer; private BufferedReader fromServer; private Socket socket; public Client( )throws IOException { socket = new Socket("127.0.0.1",3000); } public void openStreams() throws IOException { // // InputStream is = socket.getInputStream(); // OutputStream os = socket.getOutputStream(); // fromServer = new BufferedReader(new InputStreamReader(is)); // toServer = new PrintWriter(os, true); toServer = new PrintWriter(socket.getOutputStream(),true); fromServer = new BufferedReader(new InputStreamReader(socket.getInputStream())); } public void closeStreams() throws IOException { fromServer.close(); toServer.close(); socket.close(); } public void run()throws IOException { openStreams(); String msg = ""; Scanner scanner = new Scanner(System.in); toServer.println("Hello from Client."); // msg = scanner.nextLine(); while (msg != "exit") { System.out.println(">"); // msg = scanner.nextLine(); toServer.println("msg"); String tmp = fromServer.readLine(); System.out.println("Server said: " + tmp); } closeStreams(); } } package server; import java.net.*; import java.io.*; public class Server { private ServerSocket serverSocket; private Socket socket; private PrintWriter toClient; private BufferedReader fromClient; public void run() throws IOException { System.out.println("Server is waiting for connections..."); while (true) { openStreams(); processClient(); closeStreams(); } } public void openStreams() throws IOException { serverSocket = new ServerSocket(3000); socket = serverSocket.accept(); toClient = new PrintWriter(socket.getOutputStream(),true); fromClient = new BufferedReader(new InputStreamReader(socket.getInputStream())); } public void closeStreams() throws IOException { fromClient.close(); toClient.close(); socket.close(); serverSocket.close(); } public void processClient()throws IOException { System.out.println("Connection established."); String msg = fromClient.readLine(); toClient.println("Client said " + msg); } } package client; import java.io.IOException; public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // TODO code application logic here try { Client client = new Client(); client.run(); } catch(IOException e) { System.err.println("Error in Client " + e.getMessage()); } } } package server; import java.io.IOException; public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // TODO code application logic here Server server = new Server(); try { server.run(); } catch(IOException e) { System.err.println("Error in Server " + e.getMessage()); } } }

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  • UDP: Client started before Server

    - by Chris
    I have a bit of a glitch in my game just now, everything runs fine if the server is started before the client however when the client is started before the server they never connect. This is all UDP The problem happens when the client tries to call recvfrom() before the server has started, when this happens the client never finds the server and the server never finds the client. The resulted error is a wouldblock. If I stop the client using recvfrom and start the client before the server (the client is still sending data its just not receiving it) they both find each other no problem. Whats the solution for this? The way its seems just now is that the client cannot call recvfrom without a server being active or it all falls apart. Is there a check that can be done to see if data is sitting on a certain port(data the server would send)? Or is there a better way to do this? Some Code... Server Operation - UDPSocket is a class UDPSocket.Initialise(); UDPSocket.MakeNonBlocking(); UDPSocket.Bind(LOCALPORT); int n = UDPSocket.Receive(&thePacket); if (n > 0) UDPSocket.Send(&sendPacket); Client... UDP.Initialise(); UDP.MakeNonBlocking(); UDP.SetDestinationAddress(SERVERIP, SERVERPORT); serverStatus = UDP.Receive(&recvPacket); if (serverStatus > 0) { //Do some things UDP.Send(dPacket); //Try and reconnect with server } Thanks

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  • What is the meaning of client coordinates in SetWindowPos

    - by user1775315
    The documentation for SetWindowPos says the following for the X and Y parameters: X [in] Type: int The new position of the left side of the window, in client coordinates. Y [in] Type: int The new position of the top of the window, in client coordinates. By "client coordinates", does it mean that the parameters specify the position of the client area of the window, or that they specify the position of the window (not the client area) relative to the parent window's client area? Or something else?

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  • Silverlight 4 Twitter Client &ndash; Part 3

    - by Max
    Finally Silverlight 4 RC is released and also that Windows 7 Phone Series will rely heavily on Silverlight platform for apps platform. its a really good news for Silverlight developers and designers. More information on this here. You can use SL 4 RC with VS 2010. SL 4 RC does not come with VS 2010, you need to download it separately and install it. So for the next part, be ready with VS 2010 and SL4 RC, we will start using them and not With this momentum, let us go to the next part of our twitter client tutorial. This tutorial will cover setting your status in Twitter and also retrieving your 1) As everything in Silverlight is asynchronous, we need to have some visual representation showing that something is going on in the background. So what I did was to create a progress bar with indeterminate animation. The XAML is here below. <ProgressBar Maximum="100" Width="300" Height="50" Margin="20" Visibility="Collapsed" IsIndeterminate="True" Name="progressBar1" VerticalAlignment="Center" HorizontalAlignment="Center" /> 2) I will be toggling this progress bar to show the background work. So I thought of writing this small method, which I use to toggle the visibility of this progress bar. Just pass a bool to this method and this will toggle it based on its current visibility status. public void toggleProgressBar(bool Option){ if (Option) { if (progressBar1.Visibility == System.Windows.Visibility.Collapsed) progressBar1.Visibility = System.Windows.Visibility.Visible; } else { if (progressBar1.Visibility == System.Windows.Visibility.Visible) progressBar1.Visibility = System.Windows.Visibility.Collapsed; }} 3) Now let us create a grid to hold a textbox and a update button. The XAML will look like something below <Grid HorizontalAlignment="Center"> <Grid.RowDefinitions> <RowDefinition Height="50"></RowDefinition> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="400"></ColumnDefinition> <ColumnDefinition Width="200"></ColumnDefinition> </Grid.ColumnDefinitions> <TextBox Name="TwitterStatus" Width="380" Height="50"></TextBox> <Button Name="UpdateStatus" Content="Update" Grid.Row="1" Grid.Column="2" Width="200" Height="50" Click="UpdateStatus_Click"></Button></Grid> 4) The click handler for this update button will be again using the Web Client to post values. Posting values using Web Client. The code is: private void UpdateStatus_Click(object sender, RoutedEventArgs e){ toggleProgressBar(true); string statusupdate = "status=" + TwitterStatus.Text; WebRequest.RegisterPrefix("https://", System.Net.Browser.WebRequestCreator.ClientHttp);  WebClient myService = new WebClient(); myService.AllowReadStreamBuffering = true; myService.UseDefaultCredentials = false; myService.Credentials = new NetworkCredential(GlobalVariable.getUserName(), GlobalVariable.getPassword());  myService.UploadStringCompleted += new UploadStringCompletedEventHandler(myService_UploadStringCompleted); myService.UploadStringAsync(new Uri("https://twitter.com/statuses/update.xml"), statusupdate);  this.Dispatcher.BeginInvoke(() => ClearTextBoxValue());} 5) In the above code, we have a event handler which will be fired on this request is completed – !! Remember SL is Asynch !! So in the myService_UploadStringCompleted, we will just toggle the progress bar and change some status text to say that its done. The code for this will be StatusMessage is just another textblock conveniently positioned in the page.  void myService_UploadStringCompleted(object sender, UploadStringCompletedEventArgs e){ if (e.Error != null) { StatusMessage.Text = "Status Update Failed: " + e.Error.Message.ToString(); } else { toggleProgressBar(false); TwitterCredentialsSubmit(); }} 6) Now let us look at fetching the friends updates of the logged in user and displaying it in a datagrid. So just define a data grid and set its autogenerate columns as true. 7) Let us first create a data structure for use with fetching the friends timeline. The code is something like below: namespace MaxTwitter.Classes{ public class Status { public Status() {} public string ID { get; set; } public string Text { get; set; } public string Source { get; set; } public string UserID { get; set; } public string UserName { get; set; } }} You can add as many fields as you want, for the list of fields, have a look at here. It will ask for your Twitter username and password, just provide them and this will display the xml file. Go through them pick and choose your desired fields and include in your Data Structure. 8) Now the web client request for this is similar to the one we saw in step 4. Just change the uri in the last but one step to https://twitter.com/statuses/friends_timeline.xml Be sure to change the event handler to something else and within that we will use XLINQ to fetch the required details for us. Now let us how this event handler fetches details. public void parseXML(string text){ XDocument xdoc; if(text.Length> 0) xdoc = XDocument.Parse(text); else xdoc = XDocument.Parse(@"I USED MY OWN LOCAL COPY OF XML FILE HERE FOR OFFLINE TESTING"); statusList = new List<Status>(); statusList = (from status in xdoc.Descendants("status") select new Status { ID = status.Element("id").Value, Text = status.Element("text").Value, Source = status.Element("source").Value, UserID = status.Element("user").Element("id").Value, UserName = status.Element("user").Element("screen_name").Value, }).ToList(); //MessageBox.Show(text); //this.Dispatcher.BeginInvoke(() => CallDatabindMethod(StatusCollection)); //MessageBox.Show(statusList.Count.ToString()); DataGridStatus.ItemsSource = statusList; StatusMessage.Text = "Datagrid refreshed."; toggleProgressBar(false);} in the event handler, we call this method with e.Result.ToString() Parsing XML files using LINQ is super cool, I love it.   I am stopping it here for  this post. Will post the completed files in next post, as I’ve worked on a few more features in this page and don’t want to confuse you. See you soon in my next post where will play with Twitter lists. Have a nice day! Technorati Tags: Silverlight,LINQ,XLINQ,Twitter API,Twitter,Network Credentials

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  • ASP.NET MVC 3 Client-Side Validation Summary with jQuery Validation (Unobtrusive JavaScript)

    - by Soe Tun
    When we were working with ASP.NET MVC 2, we needed to write our own JavaScript to get Client-Side Validation Summary with jQuery Validation plugin. I am one of those unfortunate people still stuck with .NET Framework Runtime 2.0 and .NET Framework 3.5; meaning I am still on ASP.NET MVC 2. So I will still keep on supporting by answering any question you may have with my original code.   Long awaited ASP.NET MVC 3 has been released, and it supports Client Side Validation Summary with jQuery out-of-the-box with new features like Unobtrusive JavaScript.   1. _Layout.cshtml Template Notice that I am using Protocol Relative URLs ( i.e., '//'.  Not 'http://' or 'https://' ) to reference script files and css files and you should use it too like that! However, please note that IE7 and IE8 will download the CSS files twice so use it with judgement. <!DOCTYPE html> <html> <head> <title>@ViewBag.Title</title> <link href="@Url.Content("~/Assets/Site.css")" rel="stylesheet" type="text/css" /> <link href="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.9/themes/redmond/jquery-ui.css" rel="stylesheet" type="text/css" media="screen" /> </head> <body> @RenderBody() <script src="//ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.9/jquery-ui.min.js" type="text/javascript"></script> <script src="//ajax.microsoft.com/ajax/jQuery.Validate/1.7/jQuery.Validate.min.js" type="text/javascript"></script> <script src="//ajax.aspnetcdn.com/ajax/mvc/3.0/jquery.validate.unobtrusive.min.js" type="text/javascript"></script> </body> </html>   2. MVC View Template There are 3 things you *must* do exactly to get Client Side Validation Summary working. (1)  You must declare your Validation Summary **inside** the `Html.BeginForm()` block like below. (2)  You must pass `excludePropertyErrors: false` to the  Html.ValidationSummary()  method. @using (Html.BeginForm()) { @Html.ValidationSummary(false, "Please fix these errors."); <!-- The rest of your View Template --> }   (3)  You have to put the following two elements in the `<appSettings />` block of your Web.config file. <add key="ClientValidationEnabled" value="true"/> <add key="UnobtrusiveJavaScriptEnabled" value="true"/>   That is all you need to do.  Simple, right? I will upload a sample project for download soon.  Please let me know if you run into some issues.     P.S: Without getting into too much technical details, I just wanted to let you know what I went through to get this to work. I had to look into the ASP.NET MVC 3 RTM Source Code and the jquery.validate.unobtrusive.js source. Initially, I thought I have to hack the jquery.validate.unobtrusive.js or something to get this to work. But after digging into MVC3 RTM source, I found out how to do it.

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  • networking with ssh thru wireless

    - by nkvnkv
    I am using Ubuntu 12.04 64bit on my desktop and my laptop. Have install openssh client and server on both of them. My desktop is connected to ADSL2+ Router TD-8840 with wired connection and has 192.168.1.1 IP address. My laptop is connected to 150Mbps Wireless N Router TL-WR741ND with wireless connection and has 192.168.0.1 IP address. ADSL2+ Router TD-8840 and 150Mbps Wireless N Router TL-WR741ND are connected with a wired cable by useing blue port for on wlan on TL-WR741ND. ifconfig from desktop desktop:~$ ifconfig eth0 Link encap:Ethernet HWaddr 00:1d:92:37:1f:3d inet addr:192.168.1.101 Bcast:192.168.1.255 Mask:255.255.255.0 inet6 addr: fe80::21d:92ff:fe37:1f3d/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:57508 errors:0 dropped:0 overruns:0 frame:0 TX packets:44508 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:51547633 (51.5 MB) TX bytes:6371374 (6.3 MB) Interrupt:43 Base address:0x6000 eth1 Link encap:Ethernet HWaddr 00:23:cd:b1:ff:e4 UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) Interrupt:22 Base address:0x8400 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:109 errors:0 dropped:0 overruns:0 frame:0 TX packets:109 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:12044 (12.0 KB) TX bytes:12044 (12.0 KB) ifconfig from laptop laptop:~$ ifconfig eth0 Link encap:Ethernet HWaddr 00:a0:d1:65:2a:42 UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:334 errors:0 dropped:0 overruns:0 frame:0 TX packets:334 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:31244 (31.2 KB) TX bytes:31244 (31.2 KB) wlan0 Link encap:Ethernet HWaddr 00:19:d2:1b:19:81 inet addr:192.168.0.101 Bcast:192.168.0.255 Mask:255.255.255.0 inet6 addr: fe80::219:d2ff:fe1b:1981/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:1590 errors:0 dropped:0 overruns:0 frame:0 TX packets:1276 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:874763 (874.7 KB) TX bytes:315401 (315.4 KB) I can connect to desktop from laptop via ssh with no problem, internet connection on laptop and desktop is working fine, but when I want to connect to laptop from desktop via ssh in terminal I type ssh [email protected] and get ssh: connect to host 192.168.0.101 port 22: Connection timed out If anyone is able to point out whats wrong?

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