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  • How to give full path name in JSP programming?

    - by sujoy
    Actually when I run a particular JSP page it run perfectly(with external style sheet) but when servlet return back the control through RequestDispatcher, the page is not displaying properly means it don't took the css file path. In my program the stylesheet is present inside css directory and the page is present inside another directory named JSP. The code which include the css in the program is- <link rel="stylesheet" href="../css/stylesheet.css" type="text/css"/>

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  • Hibernate one to one with multiple columns

    - by Erdem Emekligil
    How can i bind two columns, using @OneToOne annotation? Lets say I've 2 tables A and B. Table A: id1 (primary key) id2 (pk) other columns Table B: id1 (pk) id2 (pk) other columns In class A i want to write something like this: @OneToOne(fetch = FetchType.EAGER, targetEntity = B.class) @JoinColumn(name = "id1 and id2", referencedColumnName = "id1 and id2") private B b; Is it possible to do this using annotations? Thanks.

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  • Viewing directory containing MIME encoded email messages

    - by Mark
    I have an application which generates and sends MIME encoded messages (javax.mail.internet.MimeMessage) through an SMTP server. As part of the development process only, I'd like to be able to view these messages rather than send them (I know the sending works just fine, but there are restrictions on the domains within the dev environment which makes it a little difficult) I thought the easiest way would be to save the text for each message to a directory, then point "an app" at the directory and check them over. So the question is, what would be a good app to use? Is it as simple as configuring Outlook or another email client to do it? Thanks

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  • Android game logic problem

    - by semajhan
    I'm currently creating a game and have a problem which I think I know why it is occurring but not entirely sure and even if I knew, don't know how to solve. I have a 2D array 10 x 10 and have a "player" class that takes up a tile. Now, I have created 2 instances of the player and move them around via swiping. Around the edges I have put "walls" that the player cannot walk through and everything works fine, until I remove a wall. Once I remove a wall and move the character/player to the edge of the screen, the player cannot go any further. The problem occurs here, where the second instance of the player is not at the edge of the screen but say 2 tiles from the first instance of "player" who is at the edge. If I try moving them further into the direction of the edge, I understand that the first instance of player wouldn't move or do anything but the second instance of player should still move, but it won't. This is the code that executed when the user swipes: if (player.getArrayX() - 1 != player2.getArrayX()) { player.moveLeft(); } else if (player.getArrayX() - 1 == player2.getArrayX() && player.getArrayY() != player2.getArrayY()) { player.moveLeft(); } if (player2.getArrayX() - 1 != player.getArrayX()) { player2.moveLeft(); } else if (player2.getArrayX() - 1 == player.getArrayX() && player2.getArrayY() != player.getArrayY()) { player2.moveLeft(); } In the player class I have: public void moveLeft() { if (alive) { switch (levelMaster.getLevel1(getArrayX() - 1, getArrayY())) { case 0: break; case 1: subX(); // basically moves player left setArrayX(getArrayX() - 1); // shifts x coord of player 1 within tilemap Log.d("semajhan", "x: " + getArrayX()); break; case 9: subX(); setArrayX(getArrayX() - 1); setAlive(false); break; } } } Any help on the matter or further insight would be greatly appreciated, thanks.

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  • Deploy to web container, bundle web container or embed web container...

    - by Jason
    I am developing an application that needs to be as simple as possible to install for the end user. While the end users will likely be experience Linux users (or sales engineers), they don't really know anything about Tomcat, Jetty, etc, nor do I think they should. So I see 3 ways to deploy our applications. I should also state that this is the first app that I have had to deploy that had a web interface, so I haven't really faced this question before. First is to deploy the application into an existing web container. Since we only deploy to Suse or RedHat this seems easy enough to do. However, we're not big on the idea of multiple apps running in one web container. It makes it harder to take down just one app. The next option is to just bundle Tomcat or Jetty and have the startup/shutdown scripts launch our bundled web container. Or 3rd, embed.. This will probably provide the same user experience as the second option. I'm curious what others do when faced with this problem to make it as fool proof as possible on the end user. I've almost ruled out deploying into an existing web container as we often like to set per application resource limits and CPU affinity, which I believe would affect all apps deployed into a web container/app server and not just a specific application. Thank you.

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  • How do I find resources in a .jar on the classpath?

    - by Brabster
    If I have a collection of resource files in a directory on my classpath, I can enumerate them using ClassLoader.getResources(location). For example if I have /mydir/myresource.properties on the classpath, I can call the classloader's getResources("mydir") and get an enumeration of URLs containing myresource.properties. When I pack up the exact same resources into a .jar, I don't get anything in the enumeration of URLs when I make the call. I've only replaced the folder structure with a jar containing those folders (it's a webapp, so the jar is going into /WEB-INF/lib). I've also got a number of other calls using getResourceAsStream(location) to get other resources individually by name and they're all working fine. What's different about enumerating resources when the resources are in a .jar?

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  • How to authenticate users against a Windows AD?

    - by Potinos
    I've a JSF-Hibernate web application. I need to authenticate users against a Windows AD and the web application should only allow logins from members of group X, otherwise it should redirect to an error page. How can I configure this? Also, I would like to display the name of the logged-in user on all pages, not the name of the Windows user of the server machine. I have tried the System.property("user.name") for this, but this only returns the name of the Windows user of the server name.

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  • hibernate annotation- extending base class - values are not being set - strange error

    - by gt_ebuddy
    I was following Hibernate: Use a Base Class to Map Common Fields and openjpa inheritance tutorial to put common columns like ID, lastModifiedDate etc in base table. My annotated mappings are as follow : BaseTable : @MappedSuperclass public abstract class BaseTable { @Id @GeneratedValue @Column(name = "id") private int id; @Column(name = "lastmodifieddate") private Date lastModifiedDate; ... Person table - @Entity @Table(name = "Person ") public class Person extends BaseTable implements Serializable{ ... Create statement generated : create table Person (id integer not null auto_increment, lastmodifieddate datetime, name varchar(255), primary key (id)) ; After I save a Person object to db, Person p = new Person(); p.setName("Test"); p.setLastModifiedDate(new Date()); .. getSession().save(p); I am setting the date field but, it is saving the record with generated ID and LastModifiedDate = null, and Name="Test". Insert Statement : insert into Person (lastmodifieddate, name) values (?, ?) binding parameter [1] as [TIMESTAMP] - <null> binding parameter [2] as [VARCHAR] - Test Read by ID query : When I do hibernate query (get By ID) as below, It reads person by given ID. Criteria c = getSession().createCriteria(Person.class); c.add(Restrictions.eq("id", id)); Person person= c.list().get(0); //person has generated ID, LastModifiedDate is null select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] ReadAll query : //read all Query query = getSession().createQuery("from " + Person.class.getName()); List allPersons=query.list(); Corresponding SQL for read all select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] - Found [2] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test2] as column [person8_] But when I print out the list in console, its being more weird. it is selecting List of Person object with ID fields = all 0 (why all 0 ?) LastModifiedDate = null Name fields have valid values I don't know whats wrong here. Could you please look at it? FYI, My Hibernate-core version : 4.1.2, MySQL Connector version : 5.1.9 . In summary, There are two issues here Why I am getting All ID Fields =0 when using read all? Why the LastModifiedDate is not being inserted?

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  • Removing quotation marks in JSONObject

    - by Spike Williams
    I'm using the net.sf.json.JSONObject to create some data to be sent to a front end application, and I don't like the ways ts adding quotation marks to every field name. For example: myString = new JSONObject().put("JSON", "Hello, World!").toString(); produces the string {"JSON": "Hello, World"}. What I want it to return is {JSON: "Hello, World"} - without quotes around "JSON". What do I have to do to make that happen?

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  • What are the best settings of the H2 database for high concurrency?

    - by dexter
    There are a lot of settings that can be used in H2 database. AUTO_SERVER, MVCC, LOCK_MODE, FILE_LOCK and MULTI_THREADED. I wonder what combination works best for high concurrency setup e.g. one thread is doing INSERTs and another connection does some UPDATEs and SELECTs? I tried MVCC=TRUE;LOCK_MODE=3lFILE_LOCK=NO but whenever I do some UPDATEs in one connection, the other connection does not see it even though I commit it. By the way the connections are from different processes e.g. separate program.

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  • Instantiating spring beans in dynamically created classes.

    - by Xetius
    I am dynamically creating classes which contain spring beans, however the beans are not getting instantiated or initialised, leaving them as null. How do I make sure that a dynamically created class creates all of its spring beans properly? This is how I am dynamically creating the class: Class ctransform; try { ctransform = Class.forName(strClassName); Method handleRequestMethod = findHandleRequestMethod(ctransform); if (handleRequestMethod != null) { return (Message<?>) handleRequestMethod.invoke(ctransform.newInstance(), message); } } This leaves all spring bean objects within ctransform (of type strClassName) as null.

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  • I have a ConnectException that isn't being caught for some reason

    - by aakbari1024
    I'm working on an Android application that uses sockets. I have a function called initializeStreams() which opens the socket and attempts a connection. This function throws a ConnectException if the connection could not be established. But for some reason, in the code that calls initializeStreams(), which has a catch block for ConnectException, the log prints out its own stack trace for the exception instead of going to the catch block. The catch block is never reached at all, even though the exact exception is being thrown. Here's the code: The try block: try { initializeStreams(); /* drivesList = new ArrayList<String>(); drivesList = enumerateDrives();*/ } catch (ConnectException e) { //Log.i(TAG, "caught connect exception"); /*loadingProgress.dismiss(); retryConnection();*/ } initializeStreams(): public void initializeStreams() throws ConnectException { try { Log.i(TAG, "Attempting to connect"); requestSocket = new Socket(SERVER_ADDR, PORT); /* other code */ } catch (IOException e) { e.printStackTrace(); } I can't figure this out, so any help would be much appreciated. }

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  • Playing BG Music Across Activities in Android

    - by scarface
    Hello! First time to ask a question here at stackoverflow. Exciting! Haha. We're developing an Android game and we play some background music for our intro (we have an Intro Activity) but we want it to continue playing to the next Activity, and perhaps be able to stop or play the music again from anywhere within the application. What we're doing at the moment is play the bgm using MediaPlayer at our Intro Activity. However, we stop the music as soon as the user leaves that Activity. Do we have to use something like Services for this? Or is MediaPlayer/SoundPool enough? If anyone knows the answer, we'd gladly appreciate your sharing it with us. Thanks!

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  • How to use a delay in a swing application

    - by M.R.
    I am building a swing application. At some point, I have to start an "animation": ... jpanel1.setBackground(Color.Black); Delay(milli) jpanel1.setBackground(Color.White); ... and so on. The gui itself and all the logic behind it work.It is just this time depended color-changing that does not. I have read, that swing is not thread safe, but all the examples I found showed me how to start another thread (for example in the background) but never how to stop the current swing-gui thread.

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  • Issues regarding playing audio files in a JME midlet.

    - by Northernen
    I am making a midlet which is to be used to play out local audio files. It is obviously not working. I am getting a null reference on the "is" variable, in the code snippet shown below. 1. try{ 2. System.out.println("path: " + this.getClass()); 3. InputStream is = this.getClass().getResourceAsStream("res/01Track.wav"); 4. p1=Manager.createPlayer(is, "audio"); 5. p1.realize(); 6. p1.prefetch(); 7. p1.start(); 8. } 9. catch(Exception e){ 10. System.out.println(e.getMessage()); 11. } I assume there is something wrong with the "this.getClass().getResourceAsStream("res/01Track.wav")" bit, but I can not for the life of me figure out why, and I have tried referring to the file in 20 different ways. If I printline "this.getClass()" it gives me "path: class Mp3spiller". The absolute path to "01Track.wav" is "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller\res\01Track.wav". Am I completely wrong in thinking that I should refer relatively to "E:\Mine dokumenter\Dokumenter\workspace_mobiljava\Mp3spiller"? If anyone could point out what I am doing wrong, I would be grateful. I have basically stolen the code from a tutorial I found online, so I would have thought it would be working.

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  • problem with uploading arabic files

    - by sword101
    I am using Spring upload to upload files. When uploading an Arabic file and getting the original file name in the controller, I get something like: &#1575;&#1604;&#1605;&#1594;&#1601;&#1604;&#1610;&#1606;.png Any ideas why this problem occur?

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  • How can I intercept a Tomcat request at socket level?

    - by Miguel Pardal
    Hi, I'm doing a performance study for a web application framework running on Apache Tomcat 6. I'm trying to measure the time overhead of handling HTTP requests. What I would like to do is: / // just before first request byte is read long t1 = System.nanoTime(); // request is processed... // just after final byte is written to response long t2 = System.nanoTime(); / Then I would compute the total time (t2 - t1). Is there a way to do this? Thanks for your help!

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  • Do "if" statements affect in the time complexity analysis?

    - by FranXh
    According to my analysis, the running time of this algorithm should be N2, because each of the loops goes once through all the elements. I am not sure whether the presence of the if statement changes the time complexity? for(int i=0; i<N; i++){ for(int j=1; j<N; j++){ System.out.println("Yayyyy"); if(i<=j){ System.out.println("Yayyy not"); } } }

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  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

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