Search Results

Search found 3437 results on 138 pages for 'append'.

Page 87/138 | < Previous Page | 83 84 85 86 87 88 89 90 91 92 93 94  | Next Page >

  • JQuery Remove() doesn't work

    - by Xander Guerin
    I have a DIV element inside another as follows: <div id="filters"> <div class="filterData">hello</div> </div> and I'm trying to remove the element: $("#filters").remove('.filterData'); Problem is, it doesn't. I've tested on other elements on my page and it works. The thing is, I cannot append to it, show or hide it, use .empty. I've also changed it to be a DIV with 'filterData' as the ID and told JQuery to remove it but it refuses to... Has anyone had a stuborn element like this before? EDIT: I'm also trying to remove it inside a $(document).ready function so I have no idea.

    Read the article

  • appending text to all files that starts with a string

    - by learner135
    How do I append a string to all the files in a directory that starts with a particular string? I tried, cat mysig >> F* But instead of appending contents of mysig to all files starting with F, it creates a file named "F*". Obviously wildcard doesn't seem to work. Any alternatives? Thanks in advance. Edit: Also how do I delete this newly created file "F*" safely?. Using rm F* would delete all the files starting with F which I wouldn't want.

    Read the article

  • How can I create an ODBC connection to SAS?

    - by Chris B.
    I'm writing a program that needs to access SAS data. I've downloaded the ODBC drivers for SAS and installed them, but I need to be able to create ODBC connections on the fly, programmatically. The following code (in Python) seems like it should work: import ctypes ODBC_ADD_DSN = 1 def add_dsn(name, driver, **kw): nul, attrib = chr(0), [] kw['DSN'] = name for attr, val in kw.iteritems(): attrib.append('%s=%s' % (attr, val)) return ctypes.windll.ODBCCP32.SQLConfigDataSource(0, ODBC_ADD_DSN, driver, nul.join(attrib)) == 1 print add_dsn('SAS Test', 'SAS', description = 'Testing SAS') But it pops up the SAS ODBC configuration dialog, sets the datasource name, and waits for the user to enter the information and dismiss the dialog. How can I avoid that?

    Read the article

  • javascript validate zip regular expression

    - by phil
    It's not working. Probably it's syntax error, but I can't figure it out. <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <script> pattern=/^[0-9]{5}$/; if (!pattern.test($('#zip').val)) {$('#zip').append($('<p>',{html: zip is invalid}));} </script> zip (US only): <input type="text" name='zip' id='zip' maxlength="5">

    Read the article

  • JQuery Optimization: Is there any way to speed up the rendering of the FlexSelect control?

    - by Sephrial
    Greetings, I am new to jQuery, and I have a performance problem with the FlexSelect control where it takes about 5 seconds to render the dropdown control (in the renderDropdown() function). The dropdown list contains about 5000 element. I believe all the runtime is attributed to the following block of code: var list = this.dropdownList.html(""); $.each(this.results, function() { list.append($("<li/>").html(this.name)); }); Question: Are there any alternatives that would build this list of elements in a more inefficient manner?

    Read the article

  • return char1 + char2? Isn't it possible?

    - by pocoa
    I'm trying to return a string from a function. Which basically adds some chars together and return the string representation. string toString() { char c1, c2, c3; // some code here return c1 + c2; // Error: invalid conversion from `char' to `const char*' } it is possible to return boolean values like return c1 == 'x'. Isn't it possible to return string values? I know that it is possible to it like this: string result; result.append(c1, c2); return result; I'm new to C++ so I thought that there must be more elegant solution around.

    Read the article

  • Java: How to I change the color of a specific line or row of string in a Text area?

    - by Kevin
    Hi all, the one way I could change the color is by setForground(). However when there are multiple lines of code it makes everything green or black. Is there another method or any way of solving this problem? Thanks! int key = evt.getKeyCode(); if (key == KeyEvent.VK_ENTER) { String tb1EnterdValue = tb1.getText().toString(); if((tb1EnterdValue.equals("yes")) ) { TextArea1.setForeground(Color.green); else { TextArea1.setForeground(Color.lightGray); } this.TextArea1.append(">"+tb1EnterdValue+newline); this.tb1.setText("");

    Read the article

  • Vim, how to scroll to bottom of a named buffer

    - by Gavin Black
    I have a vim-script which splits output to a new window, using the following command: below split +view foo I've been trying to find a way from an arbitrary buffer to scroll to the bottom of foo, or a setting to keep it defaulted to showing the bottom lines of the buffer. I'm doing most of this inside of a python block of vim script. So I have something like: python << endpython import vim import time import thread import sys def myfunction(string,sleeptime,*args): outpWindow = vim.current.window while 1: outpWindow.buffer.append("BAR") #vim.command("SCROLL TO BOTTOM OF foo") time.sleep(sleeptime) #sleep for a specified amount of time. vim.command('below split +view foo') thread.start_new_thread(myfunction,("Thread No:1",2)) endpython And need to find something to put in for vim.command("SCROLL TO BOTTOM of foo") line

    Read the article

  • Is there a faster way to download a page from the net to a string?

    - by cphil5
    I have tried other methods to download info from a URL, but needed a faster one. I need to download and parse about 250 separate pages, and would like the app to not appear ridiculously slow. This is the code I am currently using to retrieve a single page, any insight would be great. try { URL myURL = new URL("http://www.google.com"); URLConnection ucon = myURL.openConnection(); InputStream inputStream = ucon.getInputStream(); BufferedInputStream bufferedInputStream = new BufferedInputStream(inputStream); ByteArrayBuffer byteArrayBuffer = new ByteArrayBuffer(50); int current = 0; while ((current = bufferedInputStream.read()) != -1) { byteArrayBuffer.append((byte) current); } tempString = new String(byteArrayBuffer.toByteArray()); } catch (Exception e) { Log.i("Error",e.toString()); }

    Read the article

  • JQuery Buttonset - Add button

    - by leaf dev
    I am looking for a way to add a button to a JQuery buttonset at runtime with javascript. if(response.success) { var menuItem = document.createElement('a'); $(menuItem).attr('href', response.href); $(menuItem).attr('category-id', response.id); $(menuItem).text(title); $("#menu-buttonset").append(menuItem); } I am adding the hyperlink to the div container of the buttonset using javascript, and then re-calling buttonset() on the container. $("#menu-buttonset").buttonset(); This however does not seem to rebuild the buttonset as I expected. I am not seeing any function in the JQuery API for this either. Can anyone provide some insight?

    Read the article

  • show the list of usernames inside a div

    - by Mr_Green
    I am new to jQuery. In my project, I created one Class User in which the code is as shown below: static ConcurrentDictionary<string, User> _users = new ConcurrentDictionary<string, User>(); // // some function to add values to _users list // public List<User> GetConnectedUsers() { return _users.Values.ToList(); } I want to show this list of values in div #showUsernames. How to do this by using jQuery? I tried the below which is not showing anything /*display your contacts*/ $('#showUsernames').append(function(){ chat.server.getConnectedUsers(); }); where chat.server(signalr) calls the server-side code(Chat class).. I think the solution has nothing to do with signalr. If the above description is not enough then you can go through my code here

    Read the article

  • Create a select tag with some options grouped and others not grouped

    - by dontangg
    I'm using Rails 3. I want to create a select tag with some options grouped and others not grouped. Options would look something like this: Income Auto Fuel Maintenance Home Maintenance Mortgage In this example, Income is not a group, but Auto and Home are. I see three helper methods grouped_options_for_select and grouped_collection_select, option_groups_from_collection_for_select. Is there a way to use a helper to do this or will I have to generate the HTML myself? I imagine I could use two different helpers to create the options and just append the results of both.

    Read the article

  • Backbone: rendering syntax

    - by ksol
    We're using Backbone.js in one of my team's projects, and this is the first time I use it. I've seen many times this kind of code (it's coffeescript, but clear enough I think. @ means this.) clients_view = new Homespa.Views.Orders.Clients.SectionView(collection: @options.clients) @$("#clients-section").html(clients_view.render().el) clients_search_view = new Homespa.Views.Orders.Clients.SearchView @$("#clients_search_modal").html(clients_search_view.render().el) Isn't there a better way to do this? I would expect to just call render on my view, and then everything's good, I shouldn't have to get the html and append/replace it by hand. Thanks for you time !

    Read the article

  • how to find last version no from a list<> in C#

    - by Rohit
    I have a entity class RenderingTemplates. Inside this i have a property List which holds all versions of rendering template. RenderingTemplateVersion has a property VersionName which stores version name as "Version 1.0". I am creating a new version and want to find last version no.so that i can append it by 1 and make new VersionName as "Version 2.0". To accomplish this i have LatestVersion = template.RenderingTemplateVersionList.OrderByDescending(e => e.VersionName.Split(new char[] { ' ', '.' })[1]).First() LatestVersion is a integer. How to convert this to integer.Please help or suggest some other way.

    Read the article

  • Prolog: find all numbers of unique digits that can be formed from a list of digits

    - by animo
    The best thing I could come up with so far is this function: numberFromList([X], X) :- digit(X), !. numberFromList(List, N) :- member(X, List), delete(List, X, LX), numberFromList(LX, NX), N is NX * 10 + X. where digit/1 is a function verifying if an atom is a decimal digit. The numberFromList(List, N) finds all the numbers that can be formed with all digits from List. E.g. [2, 3] -> 23, 32. but I want to get this result: [2, 3] -> 2, 3, 23, 32 I spent a lot of hours thinking about this and I suspect you might use something like append(L, _, List) at some point to get lists of lesser length. I would appreciate any contribution.

    Read the article

  • Accessing the next 3 element values in a Map knowing the key.

    - by Rachel
    I have java.util.LinkedHashMap with Integer as Key and Character as Value. I know the key of the element i want to access. In addition to the element value for the key, i also want to retrieve the next 3 element values so that i can append all the 4 element values and form a string with 4 chars. I am asking for something like how we will do in a java.util.List. Is this feasible by any means in a Map/ordered map? Please suggest any other data structure that can help me achieve this. I am using Java 6.

    Read the article

  • Can a function defined in a bookmarklet be called from a page-level script?

    - by Soviut
    I have a bookmarklet that needs to open a new window/tab. In order to avoid the popup blocker, I need to call the window.open() method directly in the bookmarklet ie: at the browser-level. However, I want to keep the bookmarklet updatable by loading external Javascript files. To do this, the bookmarklet needs to append script nodes to the DOM. If i were to put window.open() code in one of these externally loaded scripts, the popup blocker would block it since its page-level. What I want to know is if I can create a wrapper function around window.open() in my bookmarklet, then call it from the externally loaded script? What is the scope and what are the permissions on a wrap such as this?

    Read the article

  • onchange on dropdownlist

    - by Abu Hamzah
    my qeustion is continuation of what i have asked see the link. http://stackoverflow.com/questions/2640001/load-country-state-city i have expand to load my drop downs list from db and i just need a way to wire onchange method in my first dropdownlist and second, please see the code. appreciate any help. $(document).ready(function() { var options = { type: "POST", url: "SearchPage.aspx/LoadCountry", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg) { var returnedArray = msg.d; list = $("#country"); for (var i = 0; i { list.append("" + returnedArray[i].Name + ""); } error : function(msg) { debugger } } }; $.ajax(options); }); how would i do for STATE dropdownlist ?

    Read the article

  • How to add jquery lightbox to content added to page via ajax?

    - by laurenmichell
    I am loading a gallery onto a page using the Instagram API. The AJAX looks something like this $.ajax ({ type: 'GET', dataType: 'jsonp', cache: false, url: 'https://api.instagram.com/v1/tags/food/media/recent?client_id='+instagramCID, success: function(data) { for (i in data.data) { $('.instagram').append('<div class="instagram-placeholder"><a href="' + data.data[i].images.standard_resolution.url + '" title="Photo via '+ data.data[i].user.username +' on Instagram" rel="lightbox[gallery]"><img class="instagram-image" src="' + data.data[i].images.thumbnail.url +'"/></a></div>'); } } }); The HTML renders something like this after the AJAX has loaded the content to the page: <a href="http://distilleryimage1.instagram.com/5184cfc4754211e181bd12313817987b_7.jpg" title="Photo via washingtonwoman on Instagram" rel="lightbox[gallery]"><img class="instagram-image" src="http://distilleryimage1.instagram.com/5184cfc4754211e181bd12313817987b_5.jpg"></a> I know I need to load lightbox after the dynamic content is added to the page, but can't seem to figure out how to do that. All the other advice I've tried from stackoverflow has created crazy recursiveness that has crashed my browser. Using this jquery lightbox plugin: http://leandrovieira.com/projects/jquery/lightbox/

    Read the article

  • Is it possible to add two nodes at a time dynamically to a treeview

    - by Dorababu
    I am having a tree-view on my main form with initially some nodes as follows ACH |-> some.txt |->FileHeader |->BatchHeader Now at this point i will have to add 2 child nodes at a time to BatchHeader. This nodes i will pass as strings from child forms My sample code that i added some nodes is as follows public void loadingDatafrom(string filename, bool str) { if (Append.oldbatchcontrol != filename) { if (tvwACH.SelectedNode.Text == "FileHeader") { tvwACH.SelectedNode.Nodes.Add(filename); } if (tvwACH.SelectedNode.Text == "BatchHeader" && filecontrolvariables.m_gridclick == false) { tvwACH.SelectedNode.Nodes.Add(filename); **I got this idea tvwach.SelectedNode.Lastnode.Nodes.Add("Node");** } } } Can any one give an idea to add 2 nodes as child to the existing node ..

    Read the article

  • when to use StringBuilder in java

    - by kostja
    It is supposed to be generally preferable to use a StringBuilder for String concatenation in Java. Is it always the case? What i mean is : Is the overhead of creating a StringBuilder object, calling the append() method and finally toString() smaller then concatenating existing Strings with + for 2 Strings already or is it only advisable for more Strings? If there is such a threshold, what does it depend on (the String length i suppose, but in which way)? And finally - would you trade the readability and conciseness of the + concatenation for the performance of the StringBuilder in smaller cases like 2, 3, 4 Strings?

    Read the article

  • Jquery help needed- infinite loop?

    - by ilkin
    Hi all, i have a problem with this code: var par = []; $('a[name]').each(function() { if (($(this).attr('name')).indexOf("searchword") == -1) { par.push($(this).attr('name')); $('.content').empty(); for (var i = 0; i < par.length; i++) { $(".content").append('<a id="par" href="#' + par[i] + '">' + par[i] + '</a><br />'); } } }); It causes ie and firefox to popup the warning window "Stop running this script". But it happens only when there is a very very large amount of data on page. Any ideas how to fix it?

    Read the article

  • jquery dynamically genearate element id in a loop

    - by phil
    This is a loop in a function intending to create elements <li> and give each <li> an unique id. But it's not working. I suspect it's a simple syntax error with the use of quote in .attr(). But I can't get a straight answer from Google. for (i=0;i<array.length;i++) { //create HTML element of tag li $('#suggest').append("<li></li>"); $("li").attr("id",'li'+i); $('#li'+i).html(array[i]); }

    Read the article

  • For improving the join of two wave files

    - by kaki
    i want to get the values of the last 30 frames of the first wav file and first thirty frames of the second wave file in integer format and stored in a list or array. i have written the code for joining but during this manupalation i am getting in byte format and tried to convert it to integer but couldn't. as told before i want to get the frame detail of 1st 30 and last 30 in integer format,and by performing other operations join can be more successful looking for your help in this,please... thanking you, import wave m=['C:/begpython/S0001_0002.wav', 'C:/begpython/S0001_0001.wav'] i=1 a=m[i] infiles = [a] outfile = "C:/begpython/S0001_00367.wav" data= [] data1=[] for infile in infiles: w = wave.open(infile, 'rb') data1=[w.getnframes] #print w.readframes(100) data.append( [w.getparams(), w.readframes(w.getnframes())] ) #print w.readframes(1) #data1 = [ord(character) for character in data1] #print data1 #data1 = ''.join(chr(character) for character in data1) w.close() print data output = wave.open(outfile, 'wb') output.setparams(data[0][0]) output.writeframes(data[0][1]) output.writeframes(data[1][1]) output.writeframes(data[2][1]) output.close()

    Read the article

  • List in a Python class shares the same object over 2 different instances?

    - by zfranciscus
    I created a class: class A: aList = [] now I have function that instantiate this class and add items into the aList. note: there are 2 items for item in items: a = A(); a.aList.append(item); I find that the first A and the second A object has the same number of items in their aList. I would expect that the first A object will have the first item in its list and the second A object will have the second item in its aList. Can anyone explain how this happens ? PS: I manage to solve this problem by moving the aList inside a constructor : def __init__(self): self.aList = []; but I am still curious about this behavior

    Read the article

< Previous Page | 83 84 85 86 87 88 89 90 91 92 93 94  | Next Page >