Search Results

Search found 21211 results on 849 pages for 'form validation'.

Page 87/849 | < Previous Page | 83 84 85 86 87 88 89 90 91 92 93 94  | Next Page >

  • rails: has_many :through validation?

    - by ramonrails
    Rails 2.1.0 (Cannot upgrade for now due to several constraints) I am trying to achieve this. Any hints? A project has many users through join model A user has many projects through join model Admin class inherits User class. It also has some Admin specific stuff. Admin like inheritance for Supervisor and Operator Project has one Admin, One supervisor and many operators. Now I want to 1. submit data for project, admin, supervisor and operator in a single project form 2. validate all and show errors on the project form. Project has_many :projects_users ; has_many :users, :through => :projects_users User has_many :projects_users ; has_many :projects, :through => :projects_users ProjectsUser = :id integer, :user_id :integer, :project_id :integer, :user_type :string ProjectUser belongs_to :project, belongs_to :user Admin < User # User has 'type:string' column for STI Supervisor < User Operator < User Is the approach correct? Any and all suggestions are welcome.

    Read the article

  • Changing constraints on the fly

    - by GoinOff
    Hi, I have a dijit.form.NumberTextBox input field that starts out with these parms: new dijit.form.NumberTextBox({ id: din1, style: "width:60px", constraints: { places: 0, pattern: '######' } }, din1); Everything works great..My question is I would like to change 'places' and 'pattern' parms on the fly. So I wrote this to change 'places' and 'patterns' parms: var myFldObj = dijit.byId(din1); if (myFldObj) { var myConstObj = myFldObj.attr('constraints'); if (myConstObj) { myConstObj.places = 2; myConstObj.pattern = '#####.0'; } } So, after I show the form again, I'd expect the entry field to allow 2 decimal places but the form still acts like places=0 and pattern='######'. When I check the values of 'places' and 'pattern' I get what I'd expect (2 and #####.0). My question: Can you change these values on the fly?? OR Do you have to destroy the original dijit object and recreate with new parms?? Thx!!

    Read the article

  • <input type="image"> doesnt seem to be posting.

    - by Derek Adair
    I can't figure out why... This works: <?php if($_POST['test']) echo "posted"; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="submit" name="test" /> </form> and this doesn't: <?php if($_POST['test']) echo "posted"; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="image" name="test" src="images/button.submit.png" /> </form>

    Read the article

  • Jquery validation does not stop execution of "code behind" code of asp.net button

    - by shahk26
    Hi, I have a asp.net button which has click event which basically adds data into datbase. I also have a radiobuttonlist(i.e Approve / Decline) and a textbox. If user selects decline, the textbox becomes visible. I want to run validation that when user clicks on submit button, if the decline is selected then the textbox can not blank. I have used jquery validation for that. when I click button, the message apppears next to textbox that the field is required but it does not stop the execution of code behind. i.e.It adds data into database. Here is my code. <script type="text/javascript" language="javascript"> $(function() { $('#declinediv').hide(); //////// var $radBtn = $("table.rblist input:radio"); $radBtn.click(function() { var $radChecked = $(':radio:checked'); var value = $radChecked.val(); if (value == 'Decline' || value == 'Approve') { if (value == 'Decline') $('#declinediv').show(); else $('#declinediv').hide(); } else { $('#declinediv').hide(); } }); ////////////////////////// $("#aspnetForm").validate({ rules: { <%=txtdeclinereason.UniqueID %>: { minlength: 2, required: true } }, messages: { <%=txtdeclinereason.UniqueID %>:{ required: "* Required Field *", minlength: "* Please enter atleast 2 characters *" } }, onsubmit: true }); ////////////////////////////////// $('#btnsubmit').click(function(evt){ var isValid = $("#aspnetForm").valid(); if (!isValid) { evt.preventDefault(); } }); }); function myredirect(v, m, f) { window.location.href = v; } </script> <table style="border: 1px black solid; text-align: center; vertical-align: middle" width="100%"> <tr> <td> <asp:RadioButtonList ID="rbtnlstapprover" runat="server" RepeatDirection="Horizontal" CssClass="rblist" DataTextField="username" DataValueField="emailaddress"> <asp:ListItem Text="Approve" Value="Approve" /> <asp:ListItem Text="Decline" Value="Decline" /> </asp:RadioButtonList> <asp:RequiredFieldValidator ID="RequiredFieldValidator1" runat="server" ControlToValidate="rbtnlstapprover" Text="*" ErrorMessage="Please select atleast one Approver" ValidationGroup="approvalgroup" Display="Dynamic" /> </td> </tr> <tr> <td> <div id="declinediv"> <asp:TextBox ID="txtdeclinereason" runat="server" TextMode="MultiLine" Columns="80" Rows="5" /> </div> </td> </tr> <tr> <td> <asp:Button ID="btnsubmit" runat="server" Text="Submit" CssClass="RegularButton" CausesValidation="true" ValidationGroup="approvalgroup" OnClick="btnsubmit_Click" /> </td> </tr> </table> How do I stop the execution of code behind? Thanks for your help.

    Read the article

  • ASP.NET MVC 2 AJAX dilemma: Lose Models concept or create unmanageable JavaScript

    - by Slightly Frustrated
    Hi, Ok, let's assume we are working with ASP.NET MVC 2 (latest and greatest preview) and we want to create AJAX user interface with jQuery. So what are our real options here? Option 1 - Pass Json from the Controller to the view, and then the view submits Json back to the controller. This means (in the order given): User opens some View (let's say - /Invoices/January) which has to visualize a list of data (e.g. <IEnumerable<X.Y.Z.Models.Invoice>>) Controller retrieves the Model from the repository (assuming we are using repository pattern). Controller creates a new instance of a class which we will serialize to Json. The reasaon we do this, is because the model may not be serializable (circular reference ftl) Controller populates the soon-to-be-serialized class with data Controller serializes the class to Json and passes it the view. User does some change and submits the 'form' The View submits back Json to the controller The Controller now must 'manually' validate the input, because the Json passed does not bind to a Model See, if our View is communicating to the controller via Json, we lose the Model validation, which IMHO is incredible disadvantage. In this case, forget about data annotations and stuff. Option 2 - Ok, the alternative of the first approach is to pass the Models to the Views, which is the default behavior in the template when you start a new project. We pass a strong typed model to the view The view renders the appropriate html and javascript, sticking to the model property names. This is important! The user submits the form. If we stick to the model names, when we .serialize() the form and submit it to the controller it will map to a model. There is no Json mapping. The submitted form directly binds to a strongly typed model, hence, we can use the model validation. E.g. we keep the business logic where it should be. Problem with this approach is, if we refactor some of the Models (change property names, types, etc), the javascript we wrote would become invalid. We will have to manually refactor the scripting and hope we don't miss something. There is no way you can test it either. Ok, the question is - how to write an AJAX front end, which keeps the business logic validation in the model (e.g. controller passes and receives a Model type), but in the same time doesn't screw up the javascript and html when we refactor the model?

    Read the article

  • binding nested json object value to a form field

    - by Jack
    I am building a dynamic form to edit data in a json object. First, if something like this exists let me know. I would rather not build it but I have searched many times for a tool and have found only tree like structures that require entering quotes. I would be happy to treat all values as strings. This edit functionality is for end users so it needs to be easy an not intimidating. So far I have code that generates nested tables to represent a json object. For each value I display a form field. I would like to bind the form field to the associated nested json value. If I could store a reference to the json value I would build an array of references to each value in a json object tree. I have not found a way to do that with javascript. My last resort approach will be to traverse the table after edits are made. I would rather have dynamic updates but a single submit would be better than nothing. Any ideas? // the json in files nests only a few levels. Here is the format of a simple case, { "researcherid_id":{ "id_key":"researcherid_id", "description":"Use to retrieve bibliometric data", "url_template" :[ { "name": "Author Detail", "url": "http://www.researcherid.com/rid/${key}" } ] } } $.get('file.json',make_json_form); function make_json_form(response) { dataset = $.secureEvalJSON(response); // iterate through the object and generate form field for string values. } // Then after the form is edited I want to display the raw updated json (then I want to save it but that is for another thread) // now I iterate through the form and construct the json object // I would rather have the dataset object var updated on focus out after each edit. function show_json(form_id){ var r = {}; var el = document.getElementById(form_id); table_to_json(r,el,null); $('body').html(formattedJSON(r)); }

    Read the article

  • jQuery custom validation for a selected radio selection

    - by Kaushik Gopal
    Hey peeps, This is my requirement: I have a bunch of radio box selections (types of workflows). If one of the radios are selected(i.e one particular type of workflow selected), I want to run a custom validation on that. This is what i tried, but it's not behaving well. Any help? jQuery part: $(document).ready(function() { // this part is to expand the child radio selection if particular parent workflow selected $("#concernedDirectorChoice").hide(); $("input[name^=workflowChoice]").change( function (){ if($(this).attr("class")=='chooseDir'){ $("#concernedDirectorChoice").show(); }else{ $("#concernedDirectorChoice").hide(); } }); // FORM VALIDATION $.validator.addMethod("dirRequired", function(value, element) { return this.optional(element) || ($("input[name^=rdDir:checked]").length); }, "That particular workflow requires a Director to be chosen. Please select Director"); $("#contExpInitiateForm").validate({ debug:true ,rules:{ RenewalNo: {required: true, number: true}, chooseDir: {dirRequired: true}, workflowChoice: {required: true} } ,errorPlacement: function(error, element) { $('.errorMessageBox').text(error.html()); } }); }); HTML form part: <!-- Pick type of workflow --> <table class="hr-table" > <tr> <td class="hr-table-label " colspan=2 >Pick Workflow Type</td> </tr> <tr> <td> <input type="radio" name="workflowChoice" value="1"> </input> </td> <td> Workflow 1 </td> </tr> <tr> <td> <input type="radio" name="workflowChoice" value="2" class="chooseDir"> </input> </td> <td> Workflow 2 (Dir selection required) </td> </tr> <tr> <td> <input type="radio" name="workflowChoice" value="3"> </input> </td> <td> Workflow 3 </td> </tr> </table> <!-- Pick Director for Workflow type 2 --> <table id="concernedDirectorChoice" name="concernedDirectorChoice" > <tr><td class="hr-table-label" colspan=2 > Choose Concerned Director</td></tr> <tr> <td><input type="radio" value='Dir1' name="rdDir" /></td> <td>Director 1</td> </tr> <tr> <td><input type="radio" value='Dir2' name="rdDir" /></td> <td>Director 2</td> </tr> <tr> <td><input type="radio" value='Dir3' name="rdDir" /></td> <td>Director 3</td> </tr> </table>

    Read the article

  • AdornerDecorator and tab stop issues

    - by Trev
    Hi, I am using IDataErrorInfo to validate and indicate errors in my text boxes. I am finding I have to tab once for the text box and once for the adornerdecorator. I have an error template: <ControlTemplate x:Key="ErrorTemplate"> <StackPanel KeyboardNavigation.IsTabStop="False" > <Border KeyboardNavigation.IsTabStop="False" BorderBrush="Red" BorderThickness="1" Padding="2" CornerRadius="2"> <AdornedElementPlaceholder KeyboardNavigation.IsTabStop="False" /> </Border> </StackPanel> </ControlTemplate> a textbox template: <Style x:Key="TextBoxInError" TargetType="{x:Type TextBox}"> <Setter Property="KeyboardNavigation.TabNavigation" Value="None"/> <Setter Property="FocusVisualStyle" Value="{x:Null}"/> <Setter Property="Margin" Value="0,5,0,5"/> <Setter Property="AllowDrop" Value="true"/> <Setter Property="HorizontalContentAlignment" Value="left"/> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type TextBox}"> <Grid KeyboardNavigation.IsTabStop="False" > <Border KeyboardNavigation.IsTabStop="False" x:Name="Border" Background="{DynamicResource WindowBackgroundBrush}" BorderBrush="{DynamicResource SolidBorderBrush}" BorderThickness="1" Padding="2" CornerRadius="2"> <ScrollViewer IsTabStop="False" Margin="0" x:Name="PART_ContentHost" Style="{DynamicResource SimpleScrollViewer}" Background="{TemplateBinding Background}"/> </Border> </Grid> <ControlTemplate.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors), Converter={StaticResource errorConverter}}"/> </Trigger> <Trigger Property="IsEnabled" Value="false"> <Setter Property="Foreground" Value="Gray"/> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Setter.Value> </Setter> </Style> and declare a text box like this: <AdornerDecorator KeyboardNavigation.IsTabStop="False" > <TextBox Margin="5,5,5,3" x:Name="txtName" IsEnabled="{Binding EditMode}" Validation.ErrorTemplate="{StaticResource ErrorTemplate}" Text="{Binding ApplicationName, Mode=TwoWay, ValidatesOnExceptions=True, NotifyOnValidationError=True, ValidatesOnDataErrors=True}" Height="25" MaxLength="50" MaxLines="1" Style="{StaticResource TextBoxInError}"/> </AdornerDecorator> If the adorner is round one text box as above then I tab once to leave the text box and once to leave the 'adornment' (it seems) If I have the adorner around a stackpanel of text boxes then I tab once each for the text boxes then have to go back through all the 'adornments' in turn. When tabbing through the adornments the focus goes on the red border defined in the control template.. any ideas? thanks

    Read the article

  • Disable autocomplete on textfield in Django?

    - by tau-neutrino
    Does anyone know how you can turn off autocompletion on a textfield in Django? For example, a form that I generate from my model has an input field for a credit card number. It is bad practice to leave autocompletion on. When making the form by hand, I'd add a autocomplete="off" statement, but how do you do it in Django and still retain the form validation?

    Read the article

  • FormatDate in Display Item Form Webpart

    - by H(at)Ni
    I've faced an issue that I wanted to display the date in the format of ('MMMM dd') that is retrieved from a sharepoint list in an arabic site collection. So, after googling this issue, I've found out that a possible solution to my poblem is using the function ddwrt:FormatDateTime that can be used as long as you'll include the following namespace xmlns:ddwrt="http://schemas.microsoft.com/WebParts/v2/DataView/runtime" My purpose was solved by writing this line of code in my xsl code behind for the webpart : ddwrt:FormatDateTime(string(@StartDate),3073,'MMMM dd') but that worked only if the webpart is inserted into an English site . After trying to search but in vain, I started to use my guesses that ended up doing something like that: ddwrt:FormatDateTime(ddwrt:FormatDateTime(string(@StartDate),3073,'dd/MM/yyyy'), 3073, 'MMMM dd') And the cause of the problem was that sharepoint parses the date as 'MM/dd/yyyy' which I think could be related to server regional settings, so I had to force it to parse the date in arabic-Egypt format as 'dd/MM/yyyy' in order to get the correct 'Month Day' format as expected.

    Read the article

  • MVC: Submit one form from a page with multiple forms

    - by Rob
    I'm working in an ASP.NET 3.5 MVC application where i've got a view with multiple forms in it. Form 1 contains information about products and will form a shoppingcart with a remove button. Form 2 is as below and is to be used to get the information from the shoppingcart and create an order of it. <% using (Html.BeginForm()) { %> <%=Html.Hidden(Order.ProductId", "E63EF586-F625-4C8D-B82E-E63A6FA4A63C")%> <%=Html.Hidden(Order.Amount", 1)%> <input type="submit" value="Pay" /> <%} % The first form contains a similar beginform with a foreach loop to get the information about the products from the model. When i use the submit button on the second form everything seems to be submitted and the action in the controller for the first form is trying to handle the request. That is where the error occurce because the information in the viewmodel isn't corresponding to what is being expected. The controller which is trying to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult ShowShoppingcartForm([Bind(Prefix = "Order")] MyViewmodel viewModel) { //.. } The controller which is expected to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult SaveOrder([Bind(Prefix = "Order")] MyViewmodel viewModel) { throw new NotImplementedException(); }

    Read the article

  • How to make a panel behave like a modal for the form

    - by The King
    Hi All, I have a MDI child Form which displays items that are already in the database. I use a datagridview (PostedItemsDataGrid) to display the items... I also have a Button which enables user to edit the line selected in the datagridview. There are also other controls on the form other than the two controls specified. I use a panel (Name : UpdateItemsPanel) containing various controls to edit the item selected... I want to display this form Modally... ie... When this form is active, user should not be allowed to access any controls other than the controls in the UpdateItemsPanel. I tried the following but got into other problems... If you can help me in solve either the main or one of these problems, it would be great help. I tried putting the contents of UpdateItemsPanel in a seperate form and show it as modal... The trouble was showing the update form as modal, blocks all other MDI forms also. Other problem with this 1 is, I need to position the modalform just below the PostedItemsDataGrid... I'm not sure How to do it... I tried putting the other controls in a panel and disabling the panel when updatepanel is displayed. This ofcourse, makes the (PostedItemsDataGrid) disabled and hence unable to scroll... Could you please help.... Please let me know, incase you need more info...

    Read the article

  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

    Read the article

  • how to generate number pattern in triangular form

    - by Vignesh Vicky
    I want to print this pattern like right angled triangle 0 909 89098 7890987 678909876 56789098765 4567890987654 345678909876543 23456789098765432 1234567890987654321 I wrote following code # include<stdio.h> # include<conio.h> void main() { clrscr(); int i,j,x,z,k,f=1; for ( i=10;i>=1;i--,f++) { for(j=1;j<=f;j++,k--) { k=i; if(k!=10) { printf("%d",k); } if(k==10) { printf("0"); } } for(x=1;x<f;x++,z--) { z=9; printf("%d",z); } printf("%d/n"); } getch(); } what is wrong with this code? when i check manually it seems correct but when compiled gives different pattern

    Read the article

  • Center aligned form with equal width labels

    - by James Goodwin
    I have a very simple web form which consists of labels and input fields, however I can not seem to find a way of aligning the form in the center of the page and for the labels to have an equal width so that they appear neatly next to each other, one under the other. The structure of my page is basically: <body> <div class="form"> <form method="post"> <fieldset> <label>Mobile:</label><input type="text" name="msisdn"><br/> <label>Code:</label><input type="text" name="code"><br/> <br/> <input type="image" src="submit-button.gif" alt="Submit"> <br/> <input type="checkbox" name="ts_and_cs"><label> Accept Terms and Conditions</label> <br/><br/> </fieldset> </form> </div> </body> Usually I would fix this by doing float:left on the label fields and setting a width on the labels, however for this I need the labels and input fields to be centered on the page. Also I am not able to set the width of the page (or any containing divs) as the page will be displayed on mobile devices with different screen sizes. Any suggestions as to how best style the form? Thanks

    Read the article

  • Paging problem in Data Form Webpart SP2010

    - by Patrick Olurotimi Ige
    I was working on some webpart in sharepoint designer 2010  and i decided to use the default custom paging.But i noticed the previous link page isn't working it basicalling just takes me back to the start page of the list and not the previous page after a good look i noticed micosoft is using "history.back()" which is suppose to work but it doesn't work well for paged data.Anyway before i started further investigation i found Hani Amr's solution at the right time and that did the trick.Hope that helps

    Read the article

  • HTTPS and FormAssembly

    - by Mark
    We are using a FormAssembly page to collect feedback - it's hosted within an IFrame on the side of our site's master page. The thing is, that some parts of our site are HTTPS - viewing and posting the form is ok in HTTPS, but the problem comes with the "thank you" page - we are using the configurable custom thank you page (configured within FormAssembly iteself). Is there are way we can send the desired response page up (perhaps via a hidden field within the posted form?) - this way we can send the HTTPS link for the HTTPS version of the form and the normal HTTP link for the HTTP form? Thanks!

    Read the article

  • How to use error provider at run time along with associating any control to validate

    - by Shantanu Gupta
    I am trying to create a Validation in a reusable fashion. Purpose: Make the validation control reusable. Error Provider should associate with control passed dynamically and can be set or cleared at run time. When user press OnClick event then all the controls gets validated with their own Error Providers. public bool IsFieldEmpty(ref TextBox txtControl, Boolean SetErrorProvider,string msgToShowOnError) { ErrorProvider EP = new ErrorProvider(); if (txtControl.Text == string.Empty) { if(SetErrorProvider==true) EP.SetError(txtControl, msgToShowOnError); return true; } else { if(SetErrorProvider==true) EP.Clear(); return false; } } Issue: Every time the function is called new errorprovider object gets created which i dont want. Every control should not have more than 1 error provider and i should be able to search it just like as done in asp.net to search for some control on a Page. How can I do this

    Read the article

  • looping through variable post vars and adding them to the database

    - by Neil Hickman
    I have been given the task of devising a custom forms manager that has a mysql backend. The problem I have now encountered after setting up all the front end, is how to process a form that is dynamic. For E.G Form one could contain 6 fields all with different name attributes in the input tag. Form two could contain 20 fields all with different name attributes in the input tag. How would i process the forms without using up oodles of resource.

    Read the article

  • Form submit capture into database not working

    - by kielie
    Hi guys, I have a form that has two buttons on it, one yes, one no, and at the moment I capture the clicked button into a database, but for some reason, it doesn't always capture the clicked button, I have gone through all my code and everything seems fine, here is the form <div id="mid_prompt"> <form action="refer.php" method="post" onsubmit="return submit_form()" > <div class="prompt_container" style="float: left;"> <span class="prompt_item"><input type="image" src="images/yes.jpg" alt="submit" name="refer" value="yes" /></span> </div> </form> <form action="thank_you.php" method="post" onsubmit="return submit_form()" > <div class="prompt_container" style="float: right;"> <span class="prompt_item"><input type="image" src="images/no.jpg" alt="submit" name="refer" value="no" /></span> </div> </form> </div> I am using sessions to carry the variables all the way to the end of the forms where I then write all the data to a database, I have checked my sessions and they seem to be working fine, the only one that is giving problems is the yes/no. So basically I need it to capture that yes/no everytime. Thanx in advance!

    Read the article

  • Can you open a form or window in an Outlook Addin (VSTO)

    - by dontpanic
    Hi, I am new to VSTO programming. I have created a basic addin for Outlook 2007 that monitors a folder containing XML text files which it opens and then sends them as an email, then deletes them. this all works fine. I want the user to be able to configure certain settings for the way the addin/program will operate, such as the folder that it will monitor, and other things. The logical way to do this is to create a menu item in the addin (which I have also done) that opens a windows form (or XAML window) that allows them to enter the parameters. In my addin I added a new item Windows Form, which worked, and the designer opened. However, in my addin code I cannot open the form. The Show() method normally associated with form objects is not available. Is this simply something you cannot do, or am I just doing it the wrong way? I have read about Outlook form regions, but these seemed to be attached to outlook items such as a new email, task, appointment etc... there doesnt seem to be a way to create a form region that can be opened in the main window of Outlook. Ideally, I would like to go with my original method of opening a new window from a menu item, but if this isnt possible I would like to hear other solutions. Thanks, Will.

    Read the article

  • What is the best way to identify which form has been submitted?

    - by Rupert
    Currently, when I design my forms, I like to keep the name of the submit button equal to the id of the form. Then, in my php, I just do if(isset($_POST['submitName'])) in order to check if a form has been submitted and which form has been submitted. Firstly, are there any security problems or design flaws with this method? One problem I have encountered is when I wish to overlay my forms with javascript in order to provide faster validation to the user. For example, whilst I obviously need to retain server side validation, it is more convenient for the user if an error message is displayed inline, upon blurring an input. Additionally, it would be good to provide entire form validation, upon clicking the submit button. Therefore, when the user clicks on the form's submit button, I am stopping the default action, doing my validation, and then attempting to renable the traditional submit functionality, if the validation passes. In order to do this, I am using the form.submit() method but, unfortunately, this doesn't send the submit button variable (as it should be as form.submit() can be called without any button being clicked). This means my PHP script fails to detect that the form has been submitted. What is the correct way to work around this? It seems like the standard solution is to add a hidden field into the form, upon passing validation, which has the name of form's id. Then when form.submit() is called, this is passed along in place of the submit button. However, this solution seems very ungraceful to me and so I am wondering whether I should: a) Use an alternative method to detect which form has been submitted which doesn't rely rely on passing the submit button. If so what alternative is there? Obviously, just having an extra hidden field from the start isn't any better. b) Use an alternative Javascript solution which allows me to retain my non-Javascript design. For example, is there an alternative to form.submit() which allows me to pass in extra data? c) Suck it up and just insert a hidden field using Javascript.

    Read the article

  • Should I Use Anchor, Button Or Form Submit For "Follow" Feature In Rails

    - by James
    I am developing an application in Rails 3 using a nosql database. I am trying to add a "Follow" feature similar to twitter or github. In terms of markup, I have determined that there are three ways to do this. 1) Use a regular anchor. (Github Uses This Method) <a href="/users/follow?target=Joe">Follow</a> 2) Use a button. (Twitter Uses This Method) <button href="/friendships/create/">Follow</button> 3) Use a form with a submit button. (Has some advantages for me, but I haven't see anyone do it yet.) <form method="post" id="connection_new" class="connection_new" action="/users/follow"> <input type="hidden" value="60d7b563355243796dd8496e17d36329" name="target" id="target"> <input type="submit" value="Follow" name="commit" id="connection_submit"> </form> Since I want to store the user_id in the database and not the username, options 1 and 2 will force me to do a database query to get the actual user_id, whereas option 3 will allow me to store the user_id in a hidden form field so that I don't have to do any database lookups. I can just get the id from the params hash on form submission. I have successfully got each of these methods working, but I would like to know what is the best way to do this. Which way is more semantic, secure, better for spiders, etc...? Is there a reason both twitter and github don't use forms to do this? Any guidance would be appreciated. I am leaning towards using the form method since then I don't have to query the db to get the id of the user, but I am worried that there must be a reason the big guys are just using anchors or buttons for this. I am a newb so go easy on me if I am totally missing something. Thanks!

    Read the article

  • Can not authenticate form system tools

    - by alfish
    Whenever I try to run a program from gnome, I get messages like Authenticated is required to run the Gparted Partition Editor The same goes for all programs that need root permission and I try to run from 'System tools' in my gnome-fallback. However the same user can become root in gnome terminal with no problem (I added the user to sudoers). I must mention that I've changed the user's password after OS install, so I think I need to update something but don't know what. I appreciate your hints.

    Read the article

< Previous Page | 83 84 85 86 87 88 89 90 91 92 93 94  | Next Page >