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  • Fix DB duplicate entries (MySQL bug)

    - by Silence
    I'm using MySQL 4.1. Some tables have duplicates entries that go against the constraints. When I try to group rows, MySQL doesn't recognise the rows as being similar. Example: Table A has a column "Name" with the Unique proprety. The table contains one row with the name 'Hach?' and one row with the same name but a square at the end instead of the '?' (which I can't reproduce in this textfield) A "Group by" on these 2 rows return 2 separate rows This cause several problems including the fact that I can't export and reimport the database. On reimporting an error mentions that a Insert has failed because it violates a constraint. In theory I could try to import, wait for the first error, fix the import script and the original DB, and repeat. In pratice, that would take forever. Is there a way to list all the anomalies or force the database to recheck constraints (and list all the values/rows that go against them) ? I can supply the .MYD file if it can be helpful.

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  • mailing system DB structure, need help

    - by Anna
    i have a system there user(sender) can write a note to friends(receivers), number of receivers=0. Text of the message is saved in DB and visible to sender and all receivers then they login to system. Sender can add more receivers at any time. More over any of receivers can edit the message and even remove it from DB. For this system i created 3 tables, shortly: users(userID, username, password) messages(messageID, text) list(id, senderID, receiverID, messageID) in table "list" each row corresponds to pair sender-receiver, like sender_x_ID -- receiver_1_ID -- message_1_ID sender_x_ID -- receiver_2_ID -- message_1_ID sender_x_ID -- receiver_3_ID -- message_1_ID Now the problem is: 1. if user deletes the message from table "messages" how to automatically delete all rows from table "list" which correspond to deleted message. Do i have to include some foreign keys? More important: 2. if sender has let say 3 receivers for his message1 (username1, username2 and username3) and at certain moment decides to add username4 and username5 and at the same time exclude username1 from the list of receivers. PHP code will get the new list of receivers (username2, username3, username4, username5) That means insert to table "list" sender_x_ID -- receiver_4_ID -- message_1_ID sender_x_ID -- receiver_5_ID -- message_1_ID and also delete from table "list" the row corresponding to user1 (which is not in the list or receivers any more) sender_x_ID -- receiver_1_ID -- message_1_ID which sql query to send from PHP to make it in an easy and intelligent way? Please help! Examples of sql queries would be perfect!

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • Cannot translate date formats from rails form to mysql db

    - by Steve
    I have a simple search form in rails 3 that has two date fields. I'm having a problem getting these dates into my mysql db. I've tried using the american_date gem, specifying date formats in my initializers, in the config/locales/en.yml file, and directly on the date on the date fields themselves. Currently, I'm setting the rails-approved date format in the view - <%= f.text_field :depart_date, :value=> Date.today.strftime('%Y-%m-%d') %> The dateformat in my DB is also YYYY-mm-dd, so things should be going smoothly. The console tells me that the two date fields are both class = "Date" I think I've found the disconnect. From the logs - Started POST "/searches" for 127.0.0.1 at 2013-10-30 17:43:26 -0400 Processing by SearchesController#create as HTML Parameters: {"utf8"=>"v","search"=>{"depart_date"=>"2013-10-30", "return_date"=>"2013-11-09"} ?[1m?[35m (0.0ms)?[0m BEGIN ?[1m?[36mSQL (0.0ms)?[0m ?[1mINSERT INTO `searches` (`depart_date`,`return_date`) VALUES ('2013-30-10','2013-09-11')?[0m ?[1m?[35m (2.0ms)?[0m COMMIT Note that the month and day values are switched in the insert statement. How can I prevent this from happenening?

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  • MySQL HA Events in the UK, Germany & France

    - by Bertrand Matthelié
    @font-face { font-family: "Arial"; }@font-face { font-family: "Times"; }@font-face { font-family: "Cambria"; }p.MsoNormal, li.MsoNormal, div.MsoNormal { margin: 0cm 0cm 0.0001pt; font-size: 12pt; font-family: "Times New Roman"; }a:link, span.MsoHyperlink { color: blue; text-decoration: underline; }a:visited, span.MsoHyperlinkFollowed { color: purple; text-decoration: underline; }p { margin: 0cm 0cm 0.0001pt; font-size: 10pt; font-family: "Times New Roman"; }div.Section1 { page: Section1; } Oracle is running MySQL High Availability breakfast seminars in London, Düsseldorf and Paris. During these free seminars, we will review the various options and technologies at your disposal to implement highly available & highly scalable MySQL infrastructures, as well as best practices in terms of architectures. The packed agenda will include High Availability features in MySQL 5.5, MySQL Replication, MySQL Cluster, the newly released Oracle VM Template for MySQL Enterprise Edition as well as what's new in MySQL 5.6 and MySQL Cluster 7.2, including NoSQL access methods to MySQL. There are a few places left for the seminar in London taking place tomorrow, June 29th, Register Now! Learn more and register for the event in Düsseldorf, July 13th. Learn more and register for the event in Paris, September 7th. We hope to see you there!

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  • MySQL Workbench 5.2.43 GA released

    - by Alfredo Kojima
    The MySQL developer tools team announces the availability of version 5.2.43 of the MySQL Workbench GUI tool. This version contains various fixes and minor enhancements and includes 53 resolved bugs. With this version, Fedora 15 packages are replaced with Fedora 17. Also, Gatekeeper in Mac OS X Mountain Lion is now properly handled. For a full list of issues fixed in this release, see http://dev.mysql.com/doc/workbench/en/changes-5.2.x.html Please get your copy from our Downloads site. In Windows, you can also use the MySQL Windows Installer to update Workbench. Sources and binary packages are available for several platforms, including Windows, Mac OS X and Linux. http://dev.mysql.com/downloads/workbench/ Workbench Documentation can be found here. http://dev.mysql.com/doc/workbench/en/index.html Utilities Documentation can be found here. http://dev.mysql.com/doc/workbench/en/mysql-utilities.html If you need any additional info or help please get in touch with us. Post in our forums or leave comments on our blog pages. - The MySQL Workbench Team

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  • MySQL Connector/NET 6.9.1 beta has been release

    - by Roberto Garcia
    Dear MySQL users, MySQL Connector/Net 6.9.1 a new version of the all-managed .NET driver for MySQL has been released. This is a beta release for 6.9.x and is not recommended for production environments. It is appropriate for use with MySQL server versions 5.5-5.7. It is now available in source and binary form from http://dev.mysql.com/downloads/connector/net/#downloadsandmirrorsites (note that not all mirror sites may be up to date at this point-if you can't find this version on some mirror, please try again later or choose another download site.) Changes in MySQL Connector/Net 6.9.1 (2014-05-29, Beta)    Functionality Added or Changed      * Asynchronous methods are now supported.    Bugs Fixed      * When a client refreshed a web page associated with an expired        session and if the ASP.NET project was using <SessionState ...        regenerateExpiredSessionId="true" ...>, a "duplicate entry"        exception was generated from the MySqlSessionProvider. (Bug        #18657550, Bug #70409) The documentation is available at: http://dev.mysql.com/doc/refman/5.7/en/connector-net.html Enjoy and thanks for the support! On behalf of the MySQL Connector/NET and the MySQL/ORACLE RE Team. 

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  • SQL Select - adding field to Select is changing the results

    - by nycdan
    I'm stumped by this SQL problem that I suspect will be easy pickings for someone out there. I have a table that contains rows representing several daily lists of ranked items. The relevent fields are as follows: ID, ListID, ItemID, ItemName, ItemRank, Date. I have a query that returns the items that were on a list yesterday but not today (Items Off List) as follows: Select ItemID, ListID, ItemName, convert(varchar(10),MAX(date),101) as date, COUNT(ItemName) as days_on_list From Table Group By ItemID, ListID, ItemName Having Max(date) = DATEADD("d",-1,convert(varchar(10),getdate(),101)) and ListID = 1 Order By ListID, ItemName, COUNT(ItemName) Basically I'm looking for records where the max date is yesterday. It works fine and shows the number of days each item was previously on the list (although not necessarily consecutively, but that's fine for now). The problem is when I try to add ranking to see what yesterday's rank was. I tried the following: Select ItemID, ListID, ItemName, ranking, convert(varchar(10),MAX(date),101) as date, COUNT(ItemName) as days_on_list From Table Group By ItemID, ListID, ItemName, ranking Having Max(date) = DATEADD("d",-1,convert(varchar(10),getdate(),101)) and ListID = 1 Order By ListID, ItemName, ranking, COUNT(ItemName) This returns a great deal more records than the previous query so something isn't right with it. I want the same number of records, but with the ranking included. I can get the rank by doing a self-join with a subquery and getting records where the ItemID occurs yesterday but not today - but then I don't know how to get the Count any more. Appreciation in advance for any help with this. ======== SOLVED ============== Select ItemID, ListID, ItemName, ranking, convert(varchar(10),MAX(date),101) as date, COUNT(ItemName) as days_on_list from Table T Where date = DATEADD("d",-1,convert(varchar(10),getdate(),101)) and ListID = 1 and T.ItemID Not In (select T.ItemID from Table T join Table T2 on T.ItemID = T2.ItemID and T.ListID = T2.ListID where T.date = DATEADD("d",-1,convert(varchar(10),getdate(),101)) and T2.date = convert (varchar(10),getdate(),101) and T.ListID = 1) Group by ItemID, ListID, ItemName, ranking Basically, what I did was create a subquery that finds all items that appear in both days, and finds items that appeared yesterday but are not in the set of items that appeared both days. Then I was able to do the aggregate function and grouping correctly. I would NOT be surprised if this is more convoluted than necessary but I understand it and can modify it as needed and performance doesn't seem to be an issue. Thanks everyone for the assist.

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  • change value upon select

    - by Link
    what i'm aiming is to show the other div when it selects one of the two options Full time and Part Time and if possible compute a different value for each When the user selects Part time the value of PrcA will change to PrcB this is the code i used <!====================================================================================> <script language="javascript"> <!--// function dm(amount) { string = "" + amount; dec = string.length - string.indexOf('.'); if (string.indexOf('.') == -1) return string + '.00'; if (dec == 1) return string + '00'; if (dec == 2) return string + '0'; if (dec > 3) return string.substring(0,string.length-dec+3); return string; } function calculate() { QtyA = 0; TotA = 0; PrcA = 1280; PrcB = 640; if (document.form1.qtyA.value > "") { QtyA = document.form1.qtyA.value }; document.form1.qtyA.value = eval(QtyA); TotA = QtyA * PrcA; document.form1.totalA.value = dm(eval(TotA)); Totamt = eval(TotA) ; document.form1.GrandTotal.value = dm(eval(Totamt)); } //--> </script> <!====================================================================================> <p> <label for="acct" style="margin-right:90px;"><strong>Account Type<strong><font color=red size=3> * </font></strong></label> <select name="acct" style="background-color:white;" class="validate[custom[serv]] select-input" id="acct" value=""> <option value="Full Time">Full-Time</option> <option value="Part Time">Part-Time</option> <option selected="selected" value=""></option> </select></p> <!====================================================================================> <script> $(document).ready(function() { $("input[name$='acct']").select(function() { var test = $(this).val(); $("div.desc").hide(); $("#acct" + test).show(); }); }); </script> <!====================================================================================> <p> <table><tr><td> <lable style="margin-right:91px;"># of Agent(s)<font color=red size=3> * </font></lable> </td><td> <input style="width:25px; margin-left:5px;" type="text" class="validate[custom[agnt]] text-input" name="qtyA" id="qtyA" onchange="calculate()" /> </td><td> <div id="acctFull Time" class="desc"> x 1280 = </div> <div id="acctPart Time" class="desc" style="display:none"> x 640 = </div> </td><td> $<input style="width:80px; margin-left:5px;" type="text" readonly="readonly" name="totalA" id="totalA" onchange="calculate()" /> </p> </td></tr></table> is there any way for me to achieve this?

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  • GROUP BY as a way to pick the first row from a group of similar rows, is this correct, is there any

    - by FipS
    I have a table which stores test results like this: user | score | time -----+-------+------ aaa | 90% | 10:30 bbb | 50% | 9:15 *** aaa | 85% | 10:15 aaa | 90% | 11:00 *** ... What I need is to get the top 10 users: user | score | time -----+-------+------ aaa | 90% | 11:00 bbb | 50% | 9:15 ... I've come up with the following SELECT: SELECT * FROM (SELECT user, score, time FROM tests_score ORDER BY user, score DESC, time DESC) t1 GROUP BY user ORDER BY score DESC, time LIMIT 10 It works fine but I'm not quite sure if my use of ORDER BY is the right way to pick the first row of each group of sorted records. Is there any better practice to achieve the same result? (I use MySQL 5)

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  • Multiple many-to-many JOINs in a single mysql query without Cartesian Product

    - by VWD
    At the moment I can get the results I need with two seperate SELECT statements SELECT COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID GROUP BY bl.biblioID Combining them like this however SELECT GROUP_CONCAT( CONCAT_WS( ':', al.lastName, al.firstName ) ORDER BY al.authorID ), COUNT(rl.refBiblioID) FROM biblioList bl LEFT JOIN biblio_author ba ON ba.biblioID = bl.biblioID JOIN authorList al ON al.authorID = ba.authorID LEFT JOIN refList rl ON bl.biblioID = rl.biblioID GROUP BY bl.biblioID causes the author result column to have duplicate names. How can I get the desired results from one SELECT statement without using DISTINCT? With subqueries?

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  • MYSQL, Subquery Reference in Union

    - by christian
    Is there any way to reference a subquery in a union? I am trying to do something like the following, and would like to avoid a temporary table, but the subquery will be drawn from a much larger dataset so it makes sense to only do it once.. SELECT * FROM (SELECT * FROM ads WHERE state='FL' AND city='Maitland' AND page='home' ORDER BY RAND()) AS sq WHERE spot = 'full-banner' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'leaderboard' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle1' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle2' LIMIT 1 .... etc,, It's a shame that DISTINCT can't be specified for a single column of a result set.

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  • Mysql with innodb and serializable transaction does not (always) lock rows

    - by Tobias G.
    Hello, I have a transaction with a SELECT and possible INSERT. For concurrency reasons, I added FOR UPDATE to the SELECT. To prevent phantom rows, I'm using the SERIALIZABLE transaction isolation level. This all works fine when there are any rows in the table, but not if the table is empty. When the table is empty, the SELECT FOR UPDATE does not do any (exclusive) locking and a concurrent thread/process can issue the same SELECT FOR UPDATE without being locked. CREATE TABLE t ( id INT NOT NULL AUTO_INCREMENT PRIMARY KEY, display_order INT ) ENGINE = InnoDB; SET TRANSACTION ISOLATION LEVEL SERIALIZABLE; START TRANSACTION; SELECT COALESCE(MAX(display_order), 0) + 1 from t FOR UPDATE; .. This concept works as expected with SQL Server, but not with MySQL. Any ideas on what I'm doing wrong? EDIT Adding an index on display_order does not change the behavior.

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  • Unable to initialize provider. Missing or incorrect schema. for MySql.Web connector

    - by Jreeter
    Hey guys and gals running into a little issue here.. I'm trying to use MySql Connector 6.2.2.0 for membership and role providers.. The issue I'm having is: Unable to initialize provider. Missing or incorrect schema. <authentication mode="Forms"/> <roleManager defaultProvider="MySqlRoleProvider" enabled="true" cacheRolesInCookie="true" cookieName=".ASPROLES" cookieTimeout="30" cookiePath="/" cookieRequireSSL="false" cookieSlidingExpiration="true" cookieProtection="All" > <providers> <clear /> <add name="MySqlRoleProvider" type="MySql.Web.Security.MySQLRoleProvider, MySql.Web, Version=6.2.2.0,Culture=neutral, PublicKeyToken=c5687fc88969c44d" connectionStringName="mySQL" applicationName="capcafe" writeExceptionsToEventLog="true" /> </providers> </roleManager> <membership defaultProvider="MySqlMembershipProvider"> <providers> <add connectionStringName="mySQL" applicationName="capcafe" minRequiredPasswordLength="5" requiresQuestionAndAnswer="false" requiresUniqueEmail="false" minRequiredNonalphanumericCharacters="0" name="MySqlMembershipProvider" type="MySql.Web.Security.MySQLMembershipProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" /> </providers> </membership> Here is the line it doesn't seem to like: Line 57: type="MySql.Web.Security.MySQLRoleProvider, MySql.Web, Version=6.2.2.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" I have both MySql.Web and MySql.Data referenced and in my bin! Any help resolving this issue will be very much appreciated

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  • Mysql select - improve performances

    - by realshadow
    Hey, I am working on an e-shop which sells products only via loans. I display 10 products per page in any category, each product has 3 different price tags - 3 different loan types. Everything went pretty well during testing time, query execution time was perfect, but today when transfered the changes to the production server, the site "collapsed" in about 2 minutes. The query that is used to select loan types sometimes hangs for ~10 seconds and it happens frequently and thus it cant keep up and its hella slow. The table that is used to store the data has approximately 2 milion records and each select looks like this: SELECT * FROM products_loans WHERE KOD IN("X17/Q30-10", "X17/12", "X17/5-24") AND 369.27 BETWEEN CENA_OD AND CENA_DO; 3 loan types and the price that needs to be in range between CENA_OD and CENA_DO, thus 3 rows are returned. But since I need to display 10 products per page, I need to run it trough a modified select using OR, since I didnt find any other solution to this. I have asked about it here, but got no answer. As mentioned in the referencing post, this has to be done separately since there is no column that could be used in a join (except of course price and code, but that ended very, very badly). Here is the show create table, kod and CENA_OD/CENA_DO very indexed via INDEX. CREATE TABLE `products_loans` ( `KOEF_ID` bigint(20) NOT NULL, `KOD` varchar(30) NOT NULL, `AKONTACIA` int(11) NOT NULL, `POCET_SPLATOK` int(11) NOT NULL, `koeficient` decimal(10,2) NOT NULL default '0.00', `CENA_OD` decimal(10,2) default NULL, `CENA_DO` decimal(10,2) default NULL, `PREDAJNA_CENA` decimal(10,2) default NULL, `AKONTACIA_SUMA` decimal(10,2) default NULL, `TYP_VYHODY` varchar(4) default NULL, `stage` smallint(6) NOT NULL default '1', PRIMARY KEY (`KOEF_ID`), KEY `CENA_OD` (`CENA_OD`), KEY `CENA_DO` (`CENA_DO`), KEY `KOD` (`KOD`), KEY `stage` (`stage`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 And also selecting all loan types and later filtering them trough php doesnt work good, since each type has over 50k records and the select takes too much time as well... Any ides about improving the speed are appreciated. Edit: Here is the explain +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ | 1 | SIMPLE | products_loans | range | CENA_OD,CENA_DO,KOD | KOD | 92 | NULL | 190158 | Using where | +----+-------------+----------------+-------+---------------------+------+---------+------+--------+-------------+ I have tried the combined index and it improved the performance on the test server from 0.44 sec to 0.06 sec, I cant access the production server from home though, so I will have to try it tomorrow.

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  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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  • Unable to access MySQL from MyPHPAdmin after setting root password in EasyPHP{WAMP}

    - by Codex
    Am a new starter with WAMP and trying to play around my way using the EasyPHP setup. After successful setup on intial launch of MySQL, the page prompted me to set up ROOT password for security reasons. On setting the password, am no longer able to access MySQL. The error is : Error MySQL said: Documentation 1045 - Access denied for user 'root'@'localhost' (using password: NO) Looked up on the net and tried the following options in the config.inc.php from the phpmyadmin foler: 1] Set the authetication to "http" so that it prompts to enter the username and password /* Authentication type */ $cfg['Servers'][$i]['auth_type'] = 'http'; 2] Set up the correct password in the config file $cfg['Servers'][$i]['password'] = 'myPwd'; None of them worked. Can anyone suggest a workaround to access MySQL? Am not fussed about not being able to use the root account but would like to CRUD on the database using other username. Thanks in advance.

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  • Mysql server update cause error in php myadmin.

    - by Avinash
    Hi I have updated my mysql server from 5.0 to 5.1.x. before it works fine, but after upgrading its displaying error in my phpmyadmin. Error is as below: "Your PHP MySQL library version 5.0.51a differs from your MySQL server version 5.1.45. This may cause unpredictable behavior." I am not getting what to do with this. Hope i am clear to all. Thanks in advance Avinash

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  • mysql query using jdbc

    - by S.PRATHIBA
    Hi all, I need to retrieve the last 20 values from my database.For example I have the following table Service_ID Service_Type consumer_feedback | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 36 | Printer | 1 | | 36 | Printer | 0 | | 37 | Printer | 0 | | 39 | Printer | -1 | | 39 | Printer | 0 | | 40 | Printer | 0 | I need to retrieve last 10 values from the table.I need to do the operation using jdbc.I have attached the sample code.Kindly help me. import java.io.; import java.sql.; public class CountRows2 { public static void main(String[] args) { System.out.println("Count number of rows in a specific table!"); Connection con = null; int count = 0; try{ Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection ("jdbc:mysql://localhost:3306/prathi","root","mysql"); try{ Statement st = con.createStatement(); ResultSet res1 = st.executeQuery("SELECT COUNT(*) FROM consumer1" ); while (res1.next()){ count = res1.getInt(1); } System.out.println("Number of column:"+count); } catch (SQLException s){ System.out.println("SQL statement is not executed!"); } } catch (Exception e){ e.printStackTrace(); } try{ Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection ("jdbc:mysql://localhost:3306/prathi","root","mysql"); try{ Statement st = con.createStatement(); ResultSet res1 = st.executeQuery("SELECT * FROM consumer1 LIMIT count-10,10"); while (res1.next()){ int Service = res1.getInt(1); String s1 = res1.getString(2); int feedback=res1.getInt(3); } System.out.println("Service" + " " +"s1" + " " +"feedback"); } catch (SQLException s){ System.out.println("SQL statement is not executed!"); } } catch (Exception e){ e.printStackTrace(); } } } I am getting the output as: C:javac CountRows2.java C:java CountRows2 Count number of rows in a specific table! Number of column:558 SQL statement is not executed! Thanks a lot....

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  • 'undefined method init for Mysql:Class'

    - by sscirrus
    I've been having problems with a MySQL Server installation that got messed up after a power outage. Configuration Intel i5 Mac running OS X 10.6.5 Ruby 1.9.2 installed Rails 3.0.1 installed MySQL Server (finally) installed and running I completely reinstalled MySQL, which deleted the local development/test/production databases. So, I have run create database development; in MySQL to get the dev database ready for a migration. Current Goal Run rake db:migrate to get my databases back again. (I cannot currently access my databases or Mysql at all from Rails.) Error Using the gem 'mysql', '2.8.1' and run rake db:migrate, I get the error: rake aborted! undefined method 'init' for Mysql:Class Stack Trace: /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/mysql_adapter.rb:30:in 'mysql_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:230:in 'new_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:238:in 'checkout_new_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:194:in 'block (2 levels) in checkout' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:190:in 'loop' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:190:in 'block in checkout' /Users/sscirrus/.rvm/rubies/ruby-1.9.2-p0/lib/ruby/1.9.1/monitor.rb:201:in 'mon_synchronize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:189:in 'checkout' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:96:in 'connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_pool.rb:318:in 'retrieve_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_specification.rb:97:in 'retrieve_connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/connection_adapters/abstract/connection_specification.rb:89:in 'connection' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:486:in 'initialize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:433:in 'new' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:433:in 'up' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/migration.rb:415:in 'migrate' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/activerecord-3.0.1/lib/active_record/railties/databases.rake:142:in 'block (2 levels) in <top (required)>' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:636:in 'call' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:636:in 'block in execute' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:631:in 'each' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:631:in 'execute' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:597:in 'block in invoke_with_call_chain' /Users/sscirrus/.rvm/rubies/ruby-1.9.2-p0/lib/ruby/1.9.1/monitor.rb:201:in 'mon_synchronize' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:590:in 'invoke_with_call_chain' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:583:in 'invoke' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2051:in 'invoke_task' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'block (2 levels) in top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'each' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2029:in 'block in top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2068:in 'standard_exception_handling' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2023:in 'top_level' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2001:in 'block in run' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:2068:in 'standard_exception_handling' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/lib/rake.rb:1998:in 'run' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/gems/rake-0.8.7/bin/rake:31:in '<top (required)>' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/bin/rake:19:in 'load' /Users/sscirrus/.rvm/gems/ruby-1.9.2-p0/bin/rake:19:in '<main>'

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  • Random select rows via JPA

    - by Ke
    In Mysql, SELECT id FROM table ORDER BY RANDOM() LIMIT 5 this sql can select 5 random rows. How to do this via JPA Query (Hibernate as provider, Mysql database)? Thanks.

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