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  • ESX3.5 Cluster & MD3000i -- Both servers see iSCSI Targets, Only one server can use partition.

    - by GruffTech
    Alright. First and foremost, Warning. This is a bigger-then-normal question. I like to be thorough and try to eliminate all possible "easymode" answers, as well as give everyone a feel of what i've tried. I've included several images of our setup and the problem it is having.. TLDR Version: So I've followed the guides located here: ESX Deployment Guide V1 this is the guide Dell has sent me to setup two ESX3.5 servers mounting a Dell MD3000i. It doesn't work. Both servers can't use the same storage partition on the MD3000. Both servers see it, but only one server can actually use it. (that server being whatever server created the partition on the target.) Both ESX servers are members of the Host Group. Full Version I have 2 ESX3.5 Servers (10.0.7.102, also called EPI2, and 10.0.7.103, also called EPI3.) connected to a iSCSI SAN Device (Dell MD3000i). Both ESX servers can "scan" the SAN and see the LUNS. Part One: MD3000i Storage On the MD3000i, Both servers are in my host group. I have two partitions, VM1 and VM2, both 1.6TB (vmware doesn't like anything past 2tb.) And you can even see that the ESX servers are targetting the MD3000 just fine. Part Two: The ESX Servers Figure 1. So as you can see above, Both ESX Servers (10.0.7.102 and 10.0.7.103) are able to see and scan the MD3000i SAN. Figure 2. Above is the storage both servers see. I created the storage partition on EPI2 (102). I then Extended the partition to include the second LUN for a grand total of 3.27 TB of storage. When i "rescan" on 103 (the server not mounting the partition), I get the below log in log/messages. Mar 11 10:41:18 epi3 kernel: scsi1: remove-single-device 0 0 0 failed, device busy(4). being the only line that grabs my attentions. (EPI3 is the server name) Mar 11 10:41:04 epi3 vmkiscsid[5436]: Connected to Discovery Address 192.168.130.101 Mar 11 10:41:04 epi3 vmkiscsid[5437]: Connected to Discovery Address 192.168.130.102 Mar 11 10:41:04 epi3 vmkiscsid[5438]: Connected to Discovery Address 192.168.131.101 Mar 11 10:41:04 epi3 vmkiscsid[5439]: Connected to Discovery Address 192.168.131.102 Mar 11 10:41:17 epi3 kernel: scsi singledevice 2 0 0 0 Mar 11 10:41:17 epi3 kernel: Vendor: DELL Model: MD3000i Rev: 0735 Mar 11 10:41:17 epi3 kernel: Type: Direct-Access ANSI SCSI revision: 05 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Supported VPD pages for sdb : 0x0 0x80 0x83 0x85 0x86 0x87 0xc0 0xc1 0xc2 0xc3 0xc4 0xc8 0xc9 0xca 0xd0 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Device id info for sdb: 0x1 0x3 0x0 0x10 0x60 0x1 0xe4 0xf0 0x0 0x1a 0x1a 0xa2 0x0 0x0 0x15 0xe2 0x4d 0x75 0xf6 0x99 0x53 0x98 0x0 0x54 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x2c 0x74 0x2c 0x30 0x78 0x30 0x30 0x30 0x31 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x32 0x0 0x0 0x0 0x51 0x94 0x0 0x4 0x0 0x0 0x80 0x1 0x53 0xa8 0x0 0x44 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x0 0x0 0x0 0x0 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Id for sdb 0x60 0x01 0xe4 0xf0 0x00 0x1a 0x1a 0xa2 0x00 0x00 0x15 0xe2 0x4d 0x75 0xf6 0x99 0x4d 0x44 0x33 0x30 0x30 0x30 Mar 11 10:41:17 epi3 kernel: VMWARE: Unique Device attached as scsi disk sdb at scsi2, channel 0, id 0, lun 0 Mar 11 10:41:17 epi3 kernel: Attached scsi disk sdb at scsi2, channel 0, id 0, lun 0 Mar 11 10:41:17 epi3 kernel: scan_scsis starting finish Mar 11 10:41:17 epi3 kernel: SCSI device sdb: 3509329920 512-byte hdwr sectors (1797751 MB) Mar 11 10:41:17 epi3 kernel: sdb: sdb1 Mar 11 10:41:17 epi3 kernel: scan_scsis done with finish Mar 11 10:41:17 epi3 kernel: scsi singledevice 2 0 0 1 Mar 11 10:41:17 epi3 kernel: Vendor: DELL Model: MD3000i Rev: 0735 Mar 11 10:41:17 epi3 kernel: Type: Direct-Access ANSI SCSI revision: 05 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Supported VPD pages for sdc : 0x0 0x80 0x83 0x85 0x86 0x87 0xc0 0xc1 0xc2 0xc3 0xc4 0xc8 0xc9 0xca 0xd0 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Device id info for sdc: 0x1 0x3 0x0 0x10 0x60 0x1 0xe4 0xf0 0x0 0x1a 0x1a 0x86 0x0 0x0 0xd 0xb7 0x4d 0x75 0xf2 0x77 0x53 0x98 0x0 0x54 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x2c 0x74 0x2c 0x30 0x78 0x30 0x30 0x30 0x31 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x32 0x0 0x0 0x0 0x51 0x94 0x0 0x4 0x0 0x0 0x80 0x1 0x53 0xa8 0x0 0x44 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x0 0x0 0x0 0x0 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Id for sdc 0x60 0x01 0xe4 0xf0 0x00 0x1a 0x1a 0x86 0x00 0x00 0x0d 0xb7 0x4d 0x75 0xf2 0x77 0x4d 0x44 0x33 0x30 0x30 0x30 Mar 11 10:41:18 epi3 kernel: VMWARE: Unique Device attached as scsi disk sdc at scsi2, channel 0, id 0, lun 1 Mar 11 10:41:18 epi3 kernel: Attached scsi disk sdc at scsi2, channel 0, id 0, lun 1 Mar 11 10:41:18 epi3 kernel: scan_scsis starting finish Mar 11 10:41:18 epi3 kernel: SCSI device sdc: 3509329920 512-byte hdwr sectors (1797751 MB) Mar 11 10:41:18 epi3 kernel: sdc: sdc1 Mar 11 10:41:18 epi3 kernel: scan_scsis done with finish Mar 11 10:41:18 epi3 kernel: scsi1: remove-single-device 0 0 0 failed, device busy(4). Mar 11 10:41:18 epi3 kernel: scsi singledevice 1 0 0 0 Things I've Tried: Removing iSCSI targets from only 103, disabling iSCSI, rebooting, enabled iSCSI, re-adding targets, rescan. Same result. Removing partition on 102, Formatted partition on 103 instead. Same result, except flipped. 103 can use storage, 102 can not. Starting Over. Removing all iSCSI Targets on both ESX Boxes, disabling iSCSI, turning off the firewall for iSCSI, rebooting ESX. Then on the MD3000, Removed the Host Group, Removed the Host-to-Virtual Mappings, Restarted the SAN. Followed the Documentation again, same result. Both servers see the storage, but only one server can use it. Disabling and Re-enabling VMware DRS and HA. Same result. Flat-out turning off VMware DRS and HA, and doing the "start over" step to see if maybe that borked it. Same Result. I'm kinda loosing my mind here, Everything i read online says "just partition it and if the ESX boxes can see the targets, it just works".... well crap. Any ideas, any other things to try? Can anyone atleast point me in the right direction? I'm really tired of working from 1am til 4am (our maintenance hours)

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  • Partitioned Repository for WebCenter Content using Oracle Database 11g

    - by Adao Junior
    One of the biggest challenges for content management solutions is related to the storage management due the high volumes of the unstoppable growing of information. Even if you have storage appliances and a lot of terabytes, thinks like backup, compression, deduplication, storage relocation, encryption, availability could be a nightmare. One standard option that you have with the Oracle WebCenter Content is to store data to the database. And the Oracle Database allows you leverage features like compression, deduplication, encryption and seamless backup. But with a huge volume, the challenge is passed to the DBA to keep the WebCenter Content Database up and running. One solution is the use of DB partitions for your content repository, but what are the implications of this? Can I fit this with my business requirements? Well, yes. It’s up to you how you will manage that, you just need a good plan. During you “storage brainstorm plan” take in your mind what you need, such as storage petabytes of documents? You need everything on-line? There’s a way to logically separate the “good content” from the “legacy content”? The first thing that comes to my mind is to use the creation date of the document, but you need to remember that this document could receive a lot of revisions and maybe you can consider the revision creation date. Your plan can have also complex rules like per Document Type or per a custom metadata like department or an hybrid per date, per DocType and an specific virtual folder. Extrapolation the use, you can have your repository distributed in different servers, different disks, different disk types (Such as ssds, sas, sata, tape,…), separated accordingly your business requirements, separating the “hot” content from the legacy and easily matching your compliance requirements. If you think to use by revision, the simple way is to consider the dId, that is the sequential unique id for every content created using the WebCenter Content or the dLastModified that is the date field of the FileStorage table that contains the date of inclusion of the content to the DB Table using SecureFiles. Using the scenario of partitioned repository using an hierarchical separation by date, we will transform the FileStorage table in an partitioned table using  “Partition by Range” of the dLastModified column (You can use the dId or a join with other tables for other metadata such as dDocType, Security, etc…). The test scenario bellow covers: Previous existent data on the JDBC Storage to be migrated to the new partitioned JDBC Storage Partition by Date Automatically generation of new partitions based on a pre-defined interval (Available only with Oracle Database 11g+) Deduplication and Compression for legacy data Oracle WebCenter Content 11g PS5 (Could present some customizations that do not affect the test scenario) For the test case you need some data stored using JDBC Storage to be the “legacy” data. If you do not have done before, just create an Storage rule pointed to the JDBC Storage: Enable the metadata StorageRule in the UI and upload some documents using this rule. For this test case you can run using the schema owner or an dba user. We will use the schema owner TESTS_OCS. I can’t forgot to tell that this is just a test and you should do a proper backup of your environment. When you use the schema owner, you need some privileges, using the dba user grant the privileges needed: REM Grant privileges required for online redefinition. GRANT EXECUTE ON DBMS_REDEFINITION TO TESTS_OCS; GRANT ALTER ANY TABLE TO TESTS_OCS; GRANT DROP ANY TABLE TO TESTS_OCS; GRANT LOCK ANY TABLE TO TESTS_OCS; GRANT CREATE ANY TABLE TO TESTS_OCS; GRANT SELECT ANY TABLE TO TESTS_OCS; REM Privileges required to perform cloning of dependent objects. GRANT CREATE ANY TRIGGER TO TESTS_OCS; GRANT CREATE ANY INDEX TO TESTS_OCS; In our test scenario we will separate the content as Legacy, Day1, Day2, Day3 and Future. This last one will partitioned automatically using 3 tablespaces in a round robin mode. In a real scenario the partition rule could be per month, per year or any rule that you choose. Table spaces for the test scenario: CREATE TABLESPACE TESTS_OCS_PART_LEGACY DATAFILE 'tests_ocs_part_legacy.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY1 DATAFILE 'tests_ocs_part_day1.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY2 DATAFILE 'tests_ocs_part_day2.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_DAY3 DATAFILE 'tests_ocs_part_day3.dat' SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_A 'tests_ocs_part_round_robin_a.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_B 'tests_ocs_part_round_robin_b.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; CREATE TABLESPACE TESTS_OCS_PART_ROUND_ROBIN_C 'tests_ocs_part_round_robin_c.dat' DATAFILE SIZE 500K AUTOEXTEND ON NEXT 500K MAXSIZE UNLIMITED; Before start, gather optimizer statistics on the actual FileStorage table: EXEC DBMS_STATS.GATHER_TABLE_STATS(USER, 'FileStorage', cascade => TRUE); Now check if is possible execute the redefinition process: EXEC DBMS_REDEFINITION.CAN_REDEF_TABLE('TESTS_OCS', 'FileStorage',DBMS_REDEFINITION.CONS_USE_PK); If no errors messages, you are good to go. Create a Partitioned Interim FileStorage table. You need to create a new table with the partition information to act as an interim table: CREATE TABLE FILESTORAGE_Part ( DID NUMBER(*,0) NOT NULL ENABLE, DRENDITIONID VARCHAR2(30 CHAR) NOT NULL ENABLE, DLASTMODIFIED TIMESTAMP (6), DFILESIZE NUMBER(*,0), DISDELETED VARCHAR2(1 CHAR), BFILEDATA BLOB ) LOB (BFILEDATA) STORE AS SECUREFILE ( ENABLE STORAGE IN ROW NOCACHE LOGGING KEEP_DUPLICATES NOCOMPRESS ) PARTITION BY RANGE (DLASTMODIFIED) INTERVAL (NUMTODSINTERVAL(1,'DAY')) STORE IN (TESTS_OCS_PART_ROUND_ROBIN_A, TESTS_OCS_PART_ROUND_ROBIN_B, TESTS_OCS_PART_ROUND_ROBIN_C) ( PARTITION FILESTORAGE_PART_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_LEGACY LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_LEGACY RETENTION NONE DEDUPLICATE COMPRESS HIGH ), PARTITION FILESTORAGE_PART_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY1 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY1 RETENTION AUTO KEEP_DUPLICATES COMPRESS ), PARTITION FILESTORAGE_PART_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY2 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY2 RETENTION AUTO KEEP_DUPLICATES NOCOMPRESS ), PARTITION FILESTORAGE_PART_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) TABLESPACE TESTS_OCS_PART_DAY3 LOB (BFILEDATA) STORE AS SECUREFILE ( TABLESPACE TESTS_OCS_PART_DAY3 RETENTION AUTO KEEP_DUPLICATES NOCOMPRESS ) ); After the creation you should see your partitions defined. Note that only the fixed range partitions have been created, none of the interval partition have been created. Start the redefinition process: BEGIN DBMS_REDEFINITION.START_REDEF_TABLE( uname => 'TESTS_OCS' ,orig_table => 'FileStorage' ,int_table => 'FileStorage_PART' ,col_mapping => NULL ,options_flag => DBMS_REDEFINITION.CONS_USE_PK ); END; This operation can take some time to complete, depending how many contents that you have and on the size of the table. Using the DBA user you can check the progress with this command: SELECT * FROM v$sesstat WHERE sid = 1; Copy dependent objects: DECLARE redefinition_errors PLS_INTEGER := 0; BEGIN DBMS_REDEFINITION.COPY_TABLE_DEPENDENTS( uname => 'TESTS_OCS' ,orig_table => 'FileStorage' ,int_table => 'FileStorage_PART' ,copy_indexes => DBMS_REDEFINITION.CONS_ORIG_PARAMS ,copy_triggers => TRUE ,copy_constraints => TRUE ,copy_privileges => TRUE ,ignore_errors => TRUE ,num_errors => redefinition_errors ,copy_statistics => FALSE ,copy_mvlog => FALSE ); IF (redefinition_errors > 0) THEN DBMS_OUTPUT.PUT_LINE('>>> FileStorage to FileStorage_PART temp copy Errors: ' || TO_CHAR(redefinition_errors)); END IF; END; With the DBA user, verify that there's no errors: SELECT object_name, base_table_name, ddl_txt FROM DBA_REDEFINITION_ERRORS; *Note that will show 2 lines related to the constrains, this is expected. Synchronize the interim table FileStorage_PART: BEGIN DBMS_REDEFINITION.SYNC_INTERIM_TABLE( uname => 'TESTS_OCS', orig_table => 'FileStorage', int_table => 'FileStorage_PART'); END; Gather statistics on the new table: EXEC DBMS_STATS.GATHER_TABLE_STATS(USER, 'FileStorage_PART', cascade => TRUE); Complete the redefinition: BEGIN DBMS_REDEFINITION.FINISH_REDEF_TABLE( uname => 'TESTS_OCS', orig_table => 'FileStorage', int_table => 'FileStorage_PART'); END; During the execution the FileStorage table is locked in exclusive mode until finish the operation. After the last command the FileStorage table is partitioned. If you have contents out of the range partition, you should see the new partitions created automatically, not generating an error if you “forgot” to create all the future ranges. You will see something like: You now can drop the FileStorage_PART table: border-bottom-width: 1px; border-bottom-style: solid; text-align: left; border-left-color: silver; border-left-width: 1px; border-left-style: solid; padding-bottom: 4px; line-height: 12pt; background-color: #f4f4f4; margin-top: 20px; margin-right: 0px; margin-bottom: 10px; margin-left: 0px; padding-left: 4px; width: 97.5%; padding-right: 4px; font-family: 'Courier New', Courier, monospace; direction: ltr; max-height: 200px; font-size: 8pt; overflow-x: auto; overflow-y: auto; border-top-color: silver; border-top-width: 1px; border-top-style: solid; cursor: text; border-right-color: silver; border-right-width: 1px; border-right-style: solid; padding-top: 4px; " id="codeSnippetWrapper"> DROP TABLE FileStorage_PART PURGE; To check the FileStorage table is valid and is partitioned, use the command: SELECT num_rows,partitioned FROM user_tables WHERE table_name = 'FILESTORAGE'; You can list the contents of the FileStorage table in a specific partition, per example: SELECT * FROM FileStorage PARTITION (FILESTORAGE_PART_LEGACY) Some useful commands that you can use to check the partitions, note that you need to run using a DBA user: SELECT * FROM DBA_TAB_PARTITIONS WHERE table_name = 'FILESTORAGE';   SELECT * FROM DBA_TABLESPACES WHERE tablespace_name like 'TESTS_OCS%'; After the redefinition process complete you have a new FileStorage table storing all content that has the Storage rule pointed to the JDBC Storage and partitioned using the rule set during the creation of the temporary interim FileStorage_PART table. At this point you can test the WebCenter Content downloading the documents (Original and Renditions). Note that the content could be already in the cache area, take a look in the weblayout directory to see if a file with the same id is there, then click on the web rendition of your test file and see if have created the file and you can open, this means that is all working. The redefinition process can be repeated many times, this allow you test what the better layout, over and over again. Now some interesting maintenance actions related to the partitions: Make an tablespace read only. No issues viewing, the WebCenter Content do not alter the revisions When try to delete an content that is part of an read only tablespace, an error will occurs and the document will not be deleted The only way to prevent errors today is creating an custom component that checks the partitions and if you have an document in an “Read Only” repository, execute the deletion process of the metadata and mark the document to be deleted on the next db maintenance, like a new redefinition. Take an tablespace off-line for archiving purposes or any other reason. When you try open an document that is included in this tablespace will receive an error that was unable to retrieve the content, but the others online tablespaces are not affected. Same behavior when deleting documents. Again, an custom component is the solution. If you have an document “out of range”, the component can show an message that the repository for that document is offline. This can be extended to a option to the user to request to put online again. Moving some legacy content to an offline repository (table) using the Exchange option to move the content from one partition to a empty nonpartitioned table like FileStorage_LEGACY. Note that this option will remove the registers from the FileStorage and will not be able to open the stored content. You always need to keep in mind the indexes and constrains. An redefinition separating the original content (vault) from the renditions and separate by date ate the same time. This could be an option for DAM environments that want to have an special place for the renditions and put the original files in a storage with less performance. The process will be the same, you just need to change the script of the interim table to use composite partitioning. Will be something like: CREATE TABLE FILESTORAGE_RenditionPart ( DID NUMBER(*,0) NOT NULL ENABLE, DRENDITIONID VARCHAR2(30 CHAR) NOT NULL ENABLE, DLASTMODIFIED TIMESTAMP (6), DFILESIZE NUMBER(*,0), DISDELETED VARCHAR2(1 CHAR), BFILEDATA BLOB ) LOB (BFILEDATA) STORE AS SECUREFILE ( ENABLE STORAGE IN ROW NOCACHE LOGGING KEEP_DUPLICATES NOCOMPRESS ) PARTITION BY LIST (DRENDITIONID) SUBPARTITION BY RANGE (DLASTMODIFIED) ( PARTITION Vault VALUES ('primaryFile') ( SUBPARTITION FILESTORAGE_VAULT_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_VAULT_FUTURE VALUES LESS THAN (MAXVALUE) ) ,PARTITION WebLayout VALUES ('webViewableFile') ( SUBPARTITION FILESTORAGE_WEBLAYOUT_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_WEBLAYOUT_FUTURE VALUES LESS THAN (MAXVALUE) ) ,PARTITION Special VALUES ('Special') ( SUBPARTITION FILESTORAGE_SPECIAL_LEGACY VALUES LESS THAN (TO_DATE('05-APR-2012 12.00.00 AM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY1 VALUES LESS THAN (TO_DATE('06-APR-2012 07.25.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY2 VALUES LESS THAN (TO_DATE('06-APR-2012 07.55.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_DAY3 VALUES LESS THAN (TO_DATE('06-APR-2012 07.58.00 PM', 'DD-MON-YYYY HH.MI.SS AM')) LOB (BFILEDATA) STORE AS SECUREFILE , SUBPARTITION FILESTORAGE_SPECIAL_FUTURE VALUES LESS THAN (MAXVALUE) ) )ENABLE ROW MOVEMENT; The next post related to partitioned repository will come with an sample component to handle the possible exceptions when you need to take off line an tablespace/partition or move to another place. Also, we can include some integration to the Retention Management and Records Management. Another subject related to partitioning is the ability to create an FileStore Provider pointed to a different database, raising the level of the distributed storage vs. performance. Let us know if this is important to you or you have an use case not listed, leave a comment. Cross-posted on the blog.ContentrA.com

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  • Can't boot 12.04 installed alongside Windows 7

    - by PalaceChan
    I realize there are other questions like this one here, but I have visited them and tried several things and nothing is helping. One of them had a suggestion to boot the liveCD, and sudo mount /dev/sda* /mnt and to then chroot and reinstall grub. I did this and it did not help. Then on the Windows side, I downloaded a free version of easyBCD and chose to add a Grub2 Ubuntu 12.04 entry. On restart I saw this entry, but when I click on it it takes me to a Windows failed to boot error, as if it wasn't even trying to boot Ubuntu. I have booted from Ubuntu liveCD once again and have a snapshot of my GParted I ran this bootinfoscript thing from the liveCD, here are my results: It seems grub is on sda. I just want to be able to boot into my Ubuntu on startup. Boot Info Script 0.61 [1 April 2012] ============================= Boot Info Summary: =============================== = Grub2 (v1.99) is installed in the MBR of /dev/sda and looks at sector 1041658947 of the same hard drive for core.img. core.img is at this location and looks for (,gpt7)/boot/grub on this drive. sda1: __________________________________________ File system: vfat Boot sector type: Windows 7: FAT32 Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files: /efi/Boot/bootx64.efi sda2: __________________________________________ File system: Boot sector type: - Boot sector info: Mounting failed: mount: unknown filesystem type '' sda3: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Windows 7 Boot files: /bootmgr /Boot/BCD /Windows/System32/winload.exe sda4: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files: sda5: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files: /bootmgr /boot/bcd sda6: __________________________________________ File system: BIOS Boot partition Boot sector type: Grub2's core.img Boot sector info: sda7: __________________________________________ File system: ext4 Boot sector type: Grub2 (v1.99) Boot sector info: Grub2 (v1.99) is installed in the boot sector of sda7 and looks at sector 1046637581 of the same hard drive for core.img. core.img is at this location and looks for (,gpt7)/boot/grub on this drive. Operating System: Ubuntu 12.04 LTS Boot files: /boot/grub/grub.cfg /etc/fstab /boot/grub/core.img sda8: __________________________________________ File system: swap Boot sector type: - Boot sector info: ============================ Drive/Partition Info: ============================= Drive: sda _______________________________________ Disk /dev/sda: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders, total 1465149168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes Partition Boot Start Sector End Sector # of Sectors Id System /dev/sda1 1 1,465,149,167 1,465,149,167 ee GPT GUID Partition Table detected. Partition Start Sector End Sector # of Sectors System /dev/sda1 2,048 411,647 409,600 EFI System partition /dev/sda2 411,648 673,791 262,144 Microsoft Reserved Partition (Windows) /dev/sda3 673,792 533,630,975 532,957,184 Data partition (Windows/Linux) /dev/sda4 533,630,976 1,041,658,946 508,027,971 Data partition (Windows/Linux) /dev/sda5 1,412,718,592 1,465,147,391 52,428,800 Windows Recovery Environment (Windows) /dev/sda6 1,041,658,947 1,041,660,900 1,954 BIOS Boot partition /dev/sda7 1,041,660,901 1,396,174,572 354,513,672 Data partition (Windows/Linux) /dev/sda8 1,396,174,573 1,412,718,591 16,544,019 Swap partition (Linux) blkid output: ____________________________________ Device UUID TYPE LABEL /dev/loop0 squashfs /dev/sda1 B498-319E vfat SYSTEM /dev/sda3 820C0DA30C0D92F9 ntfs OS /dev/sda4 168410AB84108EFD ntfs DATA /dev/sda5 AC7A43BA7A438056 ntfs Recovery /dev/sda7 42a5b598-4d8b-471b-987c-5ce8a0ce89a1 ext4 /dev/sda8 5732f1c7-fa51-45c3-96a4-7af3bff13278 swap /dev/sr0 iso9660 Ubuntu 12.04 LTS i386 ================================ Mount points: ================================= Device Mount_Point Type Options /dev/loop0 /rofs squashfs (ro,noatime) /dev/sr0 /cdrom iso9660 (ro,noatime) =========================== sda7/boot/grub/grub.cfg: =========================== How can I get this option? When I was using easyBCD, it kept saying I had no entries at all, so I did the add entry thing for Ubuntu many times and I see several of those on boot screen now. I'd love to get rid of all those unusable options.

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  • MaxTotalSizeInBytes - Blind spots in Usage file and Web Analytics Reports

    - by Gino Abraham
    Originally posted on: http://geekswithblogs.net/GinoAbraham/archive/2013/10/28/maxtotalsizeinbytes---blind-spots-in-usage-file-and-web-analytics.aspx http://blogs.msdn.com/b/sharepoint_strategery/archive/2012/04/16/usage-file-and-web-analytics-reports-with-blind-spots.aspx In my previous post (Troubleshooting SharePoint 2010 Web Analytics), I referenced a problem that can occur when exceeding the daily partition size for the LoggingDB, which generates the ULS message “[Partition] has exceeded the max bytes”. Below, I wanted to provide some additional info on this particular issue and help identify some options if this occurs. As an aside, this post only applies if you are missing portions of Usage data - think blind spots on intermittent days or user activity regularly sparse for the afternoon/evening. If this fits your scenario - read on. But if Usage logs are outright missing, go check out my Troubleshooting post first.  Background on the problem:The LoggingDB database has a default maximum size of ~6GB. However, SharePoint evenly splits this total size into fixed sized logical partitions – and the number of partitions is defined by the number of days to retain Usage data (by default 14 days). In this case, 14 partitions would be created to account for the 14 days of retention. If the retention were halved to 7 days, the LoggingDBwould be split into 7 corresponding partitions at twice the size. In other words, the partition size is generally defined as [max size for DB] / [number of retention days].Going back to the default scenario, the “max size” for the LoggingDB is 6200000000 bytes (~6GB) and the retention period is 14 days. Using our formula, this would be [~6GB] / [14 days], which equates to 444858368 bytes (~425MB) per partition per day. Again, if the retention were halved to 7 days (which halves the number of partitions), the resulting partition size becomes [~6GB] / [7 days], or ~850MB per partition.From my experience, when the partition size for any given day is exceeded, the usage logging for the remainder of the day is essentially thrown away because SharePoint won’t allow any more to be written to that day’s partition. The only clue that this is occurring (beyond truncated usage data) is an error such as the following that gets reported in the ULS:04/08/2012 09:30:04.78    OWSTIMER.EXE (0x1E24)    0x2C98    SharePoint Foundation    Health    i0m6     High    Table RequestUsage_Partition12 has 444858368 bytes that has exceeded the max bytes 444858368It’s also worth noting that the exact bytes reported (e.g. ‘444858368’ above) may slightly vary among farms. For example, you may instead see 445226812, 439123456, or something else in the ballpark. The exact number itself doesn't matter, but this error message intends to indicates that the reporting usage has exceeded the partition size for the given day.What it means:The error itself is easy to miss, which can lead to substantial gaps in the reporting data (your mileage may vary) if not identified. At this point, I can only advise to periodically check the ULS logs for this message. Down the road, I plan to explore if [Developing a Custom Health Rule] could be leveraged to identify the issue (If you've ever built Custom Health Rules, I'd be interested to hear about your experiences). Overcoming this issue also poses a challenge, with workaround options including:Lower the retentionBecause the partition size is generally defined as [max size] / [number of retention days], the first option is to lower the number of days to retain the data – the lower the retention, the lower the divisor and thus a bigger partition. For example, halving the retention from 14 to 7 days would halve the number of partitions, but double the partition size to ~850MB (e.g. [6200000000 bytes] / [7 days] = ~850GB partitions). Lowering it to 2 days would result in two ~3GB partitions… and so on.Recreate the LoggingDB with an increased sizeThe property MaxTotalSizeInBytes is exposed by OM code for the SPUsageDefinition object and can be updated with the example PowerShell snippet below. However, updating this value has no immediate impact because this size only applies when creating a LoggingDB. Therefore, you must create a newLoggingDB for the Usage Service Application. The gotcha: this effectively deletes all prior Usage databecause the Usage Service Application can only have a single LoggingDB.Here is an example snippet to update the "Page Requests" Usage Definition:$def=Get-SPUsageDefinition -Identity "page requests" $def.MaxTotalSizeInBytes=12400000000 $def.update()Create a new Logging database and attach to the Usage Service Application using the following command: Get-spusageapplication | Set-SPUsageApplication -DatabaseServer <dbServer> -DatabaseName <newDBname> Updated (5/10/2012): Once the new database has been created, you can confirm the setting has truly taken by running the following SQL Query (be sure to replace the database name in the following query with the name provided in the PowerShell above)SELECT * FROM [WSS_UsageApplication].[dbo].[Configuration] WITH (nolock) WHERE ConfigName LIKE 'Max Total Bytes - RequestUsage'

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  • Mysql - help me optimize this query

    - by sandeepan-nath
    About the system: -The system has a total of 8 tables - Users - Tutor_Details (Tutors are a type of User,Tutor_Details table is linked to Users) - learning_packs, (stores packs created by tutors) - learning_packs_tag_relations, (holds tag relations meant for search) - tutors_tag_relations and tags and orders (containing purchase details of tutor's packs), order_details linked to orders and tutor_details. For a more clear idea about the tables involved please check the The tables section in the end. -A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is a simpler representation (not the actual) of the more complex query which I am trying to optimize:- I have used statements like explanation of parts in the query select SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches, td., u., count(distinct(od.id_od)), if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including Learning_Packs table)` LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) where some condition on Users table's fields AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN `some conditions on learning pack tables set` ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN `some conditions on webclasses tables set` ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and some conditions on Orders table's fields ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%") group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 ===================================================================== What does the above query do? Does AND logic search on the search keywords (2 in this example - "Democracy" and "Dictatorship"). Returns only those tutors for which both the keywords are present in the union of the two sets - tutors details and details of all the packs created by a tutor. To make things clear - Suppose a Tutor name "Sandeepan Nath" has created a pack "My first pack", then:- Searching "Sandeepan Nath" returns Sandeepan Nath. Searching "Sandeepan first" returns Sandeepan Nath. Searching "Sandeepan second" does not return Sandeepan Nath. ====================================================================================== The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query on heavily loaded databases is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed, but I would appreciate a better query as a solution, optimized as much as possible, displaying the same results ========================================================================================== How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. ==================================================================== The tables Most of the following tables contain many other fields which I have omitted here. CREATE TABLE IF NOT EXISTS users ( id_user int(10) unsigned NOT NULL AUTO_INCREMENT, name varchar(100) NOT NULL DEFAULT '', surname varchar(155) NOT NULL DEFAULT '', PRIMARY KEY (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ; CREATE TABLE IF NOT EXISTS tutor_details ( id_tutor int(10) NOT NULL AUTO_INCREMENT, id_user int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_tutor), KEY Users_FKIndex1 (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ; CREATE TABLE IF NOT EXISTS orders ( id_order int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY KEY (id_order), KEY Orders_FKIndex1 (id_user), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ; ALTER TABLE orders ADD CONSTRAINT Orders_ibfk_1 FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS order_details ( id_od int(10) unsigned NOT NULL AUTO_INCREMENT, id_order int(10) unsigned NOT NULL DEFAULT '0', id_author int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_od), KEY Order_Details_FKIndex1 (id_order) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ; ALTER TABLE order_details ADD CONSTRAINT Order_Details_ibfk_1 FOREIGN KEY (id_order) REFERENCES orders (id_order) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs ( id_lp int(10) unsigned NOT NULL AUTO_INCREMENT, id_author int(10) unsigned NOT NULL DEFAULT '0', PRIMARY KEY (id_lp), KEY Learning_Packs_FKIndex2 (id_author), KEY id_lp (id_lp) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ; CREATE TABLE IF NOT EXISTS tags ( id_tag int(10) unsigned NOT NULL AUTO_INCREMENT, tag varchar(255) DEFAULT NULL, PRIMARY KEY (id_tag), UNIQUE KEY tag (tag), KEY id_tag (id_tag), KEY tag_2 (tag), KEY tag_3 (tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ; CREATE TABLE IF NOT EXISTS tutors_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, KEY Tutors_Tag_Relations (id_tag), KEY id_tutor (id_tutor), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE tutors_tag_relations ADD CONSTRAINT Tutors_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, id_lp int(10) unsigned DEFAULT NULL, KEY Learning_Packs_Tag_Relations_FKIndex1 (id_tag), KEY id_lp (id_lp), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE learning_packs_tag_relations ADD CONSTRAINT Learning_Packs_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; =================================================================================== Following is the exact query (this includes classes also - tutors can create classes and search terms are matched with classes created by tutors):- select count(distinct(od.id_od)) as tutor_popularity, CASE WHEN (IF((wc.id_wc 0), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT'))), 0)) THEN 1 ELSE 0 END as 'classes_published', CASE WHEN (IF((lp.id_lp 0), (lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT'))),0)) THEN 1 ELSE 0 END as 'packs_published', td . * , u . * from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN Learning_Packs_Categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN Learning_Packs_Categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN Learning_Pack_Content as lpct on (lp.id_lp = lpct.id_lp) LEFT JOIN Webclasses_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN WebClasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN Learning_Packs_Categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN Learning_Packs_Categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) OR (t.id_tag = wtagrels.id_tag) where (u.country='IE' or u.country IN ('INT')) AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and o.order_status = 'paid' and CASE WHEN (od.id_wc 0) THEN od.can_attend_class=1 ELSE 1 END ELSE 1 END AND 1 group by td.id_tutor order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 Please note - The provided database structure does not show all the fields and tables as in this query

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  • SQL SERVER – Puzzle to Win Print Book – Write T-SQL Self Join Without Using FIRST _VALUE and LAST_VALUE

    - by pinaldave
    Last week we asked a puzzle SQL SERVER – Puzzle to Win Print Book – Functions FIRST_VALUE and LAST_VALUE with OVER clause and ORDER BY . This puzzle got very interesting participation. The details of the winner is listed here. In this puzzle we received two very important feedback. This puzzle cleared the concepts of First_Value and Last_Value to the participants. As this was based on SQL Server 2012 many could not participate it as they have yet not installed SQL Server 2012. I really appreciate the feedback of user and decided to come up something as fun and helps learn new feature of SQL Server 2012. Please read yesterday’s blog post SQL SERVER – Introduction to LEAD and LAG – Analytic Functions Introduced in SQL Server 2012 before continuing this puzzle as it is based on yesterday’s post. Yesterday I ran following query which uses functions LEAD and LAG. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: Puzzle: Now use T-SQL Self Join where same table is joined to itself and get the same result without using LEAD or LAG functions. Hint: Introduction to JOINs – Basic of JOINs Self Join A new analytic functions in SQL Server Denali CTP3 – LEAD() and LAG() Rules Leave a comment with your detailed answer by Nov 21's blog post. Open world-wide (where Amazon ships books) If you blog about puzzle’s solution and if you win, you win additional surprise gift as well. Prizes Print copy of my new book SQL Server Interview Questions Amazon|Flipkart If you already have this book, you can opt for any of my other books SQL Wait Stats [Amazon|Flipkart|Kindle] and SQL Programming [Amazon|Flipkart|Kindle]. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Join us for our WebLogic Communtiy webcast on November 2nd 2012! OOW update WebLogic & ExaLogic

    - by JuergenKress
    NOVEMBER 2nd, 2012 AT 11:00 -11:45 AM CET (BERLIN TIME) Do you want to learn the latest about WebLogic and ExaLogic? Would you like to know what did Oracle announce at Oracle OpenWorld 2012? Join us for our WebLogic Communtiy webcast on November 2nd 2012! Don't miss this unique opportunity and learn the latest announcement and product updates on WebLogic and ExaLogic portfolio. Agenda Update announced about Cloud Application Foundation ExaLogic Update Key examples from successful customer Updated Roadmap Q&A Register to Attend! To Join the Webcast (Employees and Partners) AND / OR DIAL IN If you would like to dial in to the audio portion of the Webconference. Call ID: 8000524 & Call Passcode: 333111 Austria : +43(0)19286512 Belgium: +32(0)24010528 Denmark: +4532729222 Finland: +358(0)923193923 France: +33(0)176728936 Germany: +49(0)69222216106 Ireland: +353(0)12475650 Italy: +39(0)236008198 Netherlands: +31(0)207143543 Norway: +4721033443 Spain: +34914143755 Sweden: +46(0)856619465 Switzerland: +41(0)445804003 United Kingdom: +44(0)2081181001 Please click here to find more Local Numbers. Presenters: Maciej Gruszka Senior Principal Product Manager Tel: +4 (0) 8601 156 464 E-Mail: [email protected] LinkedIn: http://pl.linkedin.com/pub/maciej-gruszka/2/169/89 Jürgen Kress WebLogic Partner Adoption EMEA Tel. +49 89 1430 1479 E-Mail: [email protected] LinkedIn: http://de.linkedin.com/in/kress Twitter: http://twitter.com/wlscommunity Delivery Format This FREE online LIVE eSeminar will be delivered over the Web. Registrations received less than 24hours prior to start time may not receive confirmation to attend. Duration: 1 hour Looking forward to your participation! WebLogic Partner Community For regular information become a member in the WebLogic Partner Community please visit: http://www.oracle.com/partners/goto/wls-emea ( OPN account required). If you need support with your account please contact the Oracle Partner Business Center. BlogTwitterLinkedInMixForumWiki Technorati Tags: WebLogic Community Webcast,webcst,OOW updates WebLogic ExaLogic,WebLogic ppt,presenation,sales,WebLogic Community,Oracle,OPN,Jürgen Kress

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  • Gparted resize of an extended partition fails with error "can't have overlapping partitions".

    - by Marcus
    I just decided to install Ubuntu 12.04 alongside Windows 7 on my Dell laptop. However I didn't do this manually but instead used the "Install Ubuntu alongside Windows 7" option during the installation. Now the partition that Ubuntu runs in has very little space and I am getting warning messages. I'm trying to use gparted 0.12.1-5 (via a live CD) to give Windows less space and give Ubuntu more. I've managed to remove 100GB from the Windows partition so I now have some unallocated space between Windows and Ubuntu. This is what it looks like inside Ubuntu (not using the live CD, since it won't let me mount a USB to save a screenshot): So first I take sda4 (extended?) and resize it to the left so it takes up all the unallocated space. Then I resize sda5 (ext4) as well so it takes up all the new space. However, when I hit apply, it fails on the first action (resizing sd4) with the error message can't have overlapping partitions. Any ideas as to why this happens? I also tried resizing sda4 by just a few MB so that it definitely didn't overlap anything, but I still got the same error message. To clarify, I am using gparted from the LiveCD, I just took the screenshot from Ubuntu. I couldn't attach the details file containing the error information from gparted because I can't mount a USB drive when I'm running from the LiveCD. I'm tried following the guide on the gparted website but it says Invalid argument or something like that. If the gparted details are needed, I may need some hints on how to solve the USB issue as well. :)

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  • How to partition Seagate FreeAgent GoFlex 2TB hard disk?

    - by balki
    Hi I bought a new Seagate 2TB external hard disk. I opened the drive's application in my virtual windows, did product registration using the application present in it. I have few questions on how best to use it. The drive by default has some files and folders - setup.exe, System Volume Information, USB 3.0 PC Card Adapter etc,. I copied all the files to my laptop. Is it safe to delete these files? It has a dash board for windows which allows to tune power options, test the drive etc. Will I be able to use the dash board if I put back all these files and mount on windows again? I want to partition and format the hard disk. Data I like to store is Around 10 to 20 GB Files - Virtual box images. Around 4GB Files - Dvd images. Other Movies and personal Files. What is the best filesystem to store very huge files like 10 to 20GB files. So that they are written and accessed fast also best uses the drive's capacity. If I leave one of the partition as ntfs and others to different files systems, will it be able to mount on windows and Will I be able to use the device's dash board? Note: I dont need any encryption for my data. Any other advice on using the hard disk is also welcome.

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  • SQL query. An unusual join. DB implemented in sqlite-3

    - by user02814
    This is essentially a question about constructing an SQL query. The db is implemented with sqlite3. I am a relatively new user of SQL. I have two tables and want to join them in an unusual way. The following is an example to explain the problem. Table 1 (t1): id year name ------------------------- 297 2010 Charles 298 2011 David 300 2010 Peter 301 2011 Richard Table 2 (t2) id year food --------------------------- 296 2009 Bananas 296 2011 Bananas 297 2009 Melon 297 2010 Coffee 297 2012 Cheese 298 2007 Sugar 298 2008 Cereal 298 2012 Chocolate 299 2000 Peas 300 2007 Barley 300 2011 Beans 300 2012 Chickpeas 301 2010 Watermelon I want to join the tables on id and year. The catch is that (1) id must match exactly, but if there is no exact match in Table 2 for the year in Table 1, then I want to choose the year that is the next (lower) available. A selection of the kind that I want to produce would give the following result id year matchyr name food ------------------------------------------------- 297 2010 2010 Charles Coffee 298 2011 2008 David Cereal 300 2010 2007 Peter Barley 301 2011 2010 Richard Watermelon To summarise, id=297 had an exact match for year=2010 given in Table 1, so the corresponding line for id=297, year=2010 is chosen from Table 2. id=298, year=2011 did not have a matching year in Table 2, so the next available year (less than 2011) is chosen. As you can see, I would also like to know what that matched year (whether exactly , or inexactly) actually was. I would very much appreciate (1) an indication (yes/no answer) of whether this is possible to do in SQL alone, or whether I need to look outside SQL, and (2) a solution, if that is not too onerous.

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  • When is the right time to join open source project for programmer?

    - by Mahesh
    Most of the newcomers in programming start with basic projects to start with programming. Most of the C++ progammers spend some time with puzzles and contests but this is not always helpful. Sometimes you've to spend some time on real projects. Starting your own open source project could be a problem in self-learning for newbie cause of lack of mentors and peers who can't look at your code and give suggestions. Open source projects can solve this problem, some projects could be best suited for new programmers. Besides everybody is newbie at some point. So i'll try and make this question a bit from beginners perspective. I tried few questions on stack overflow before asking this like How do i join & Bare minimum you need and how to get involved with open source and what level of programming etc. But this is not helping me when it comes to self-evaluating with skills. How to find that out ? How can i check what it takes to join open source project and am i really that comfortable with huge source code etc. My question is when to consider yourself comfortable joining open source programming ? I mean how will you test yourself that you're ready to take burden of big/small projects of open source ? how will you test yourself to see if you could work with version control/other programmers/tight schedule etc ?

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  • What is the difference between the "Entire Partition" and "Entire Disc"?

    - by Roman
    I want to install Ubuntu alongside my Windows 7 operation system. During installation I have three options: Install alongside the existing OS. Remove everything and install Ubuntu. Manual partitioning (advanced). The above list is not precise (I do not remember what exactly was written there and I just write options as I have understood them). I know that option 2 is not mine. So, I need to choose either 1 or 3. I do not know which one I need to choose. I want to have a possibility to manually specify space assigned to Windows and Ubuntu (for example 40% for Windows and 60% for Ubuntu). I chose the 1st option and I saw a window with the following information. Allocate drive space by dragging the drive bellow. File (48.1 GB) Ubuntu /dev/sda2 (ntfs) /dev/sda3 (ext4) 286.6 GB 241.7 GB 2 small partitions are hidden, use the advanced partitioning tool for more control. [use entire partition] [use entire disk] [Quit] [Back] [Install Now] My problem is that I do not understand what I see. In particular I can press [use entire partition] or [use entire disk] and I do not know what is the difference. Moreover, as far as I understand, I can even press [Install Now] without pressing one of the two above mentioned buttons. So, I have 3 options. What is the difference between them? The most important thing for me is not to delete the old operation system with all the data stored there.

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  • How do I partition my Hard drive to install Kubuntu?

    - by Xdflames
    I am a complete newbie to partitioning and I would like some guidance here. Can anyone explain what exactly I should be doing here? I am installing Kubuntu 12.04 on a currently Windows 7 laptop. My current Partitions say this: /dev/sda /dev/sda1 ntfs 104 MB 35 MB /dev/sda2 ntfs 319965 MB 87164 MB Basically, what I want is some guidance on what exactly to do here. All I want is a partition for my OS (Which will be Kubuntu 12.04) and a partition for all of my data. I also want to restart fresh with my hard drive, with only what I mentioned on here. I am installing Kubuntu from a flash drive (I set it up as a bootable device with Universal-USB-Installer-1.9.0.9), as I do not have any blank CDs/DVDs to burn to. What should I name my partitions? What should I set the type as? What size do they need to be? Edit: My hard drive is 320GB. Just looked it up in my BIOS. This computer will mainly be used for internet browsing and overall just messing around with the Linux OS.

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  • Windows partition UNKNOWN after Ubuntu installation attempt at dual boot - How to fix?

    - by user285645
    The idea was to install Win 7 and Ubuntu with dual boot. However, after installation, Gparted shows a /dev/sda1 as an 'unknown' filesystem and its size is 278 GB. All my windows files, data are in this partition. THen, there's /dev/sda2 with 'EXT4' filesystem (size-9.54 GB) - created during Ubuntu install. Then, there's /dev/sda3 with 'extended' filesystem (size- 10.5 GB) - created during Ubuntu install. Then, there's /dev/sda5 with 'linux swap' filesystem (size- 2 GB) - created during Ubuntu install. Then, there's /dev/sda6 with 'ext4' filesystem (size- 8.5 GB) - created during Ubuntu install. MY questions are: What exactly does this Gparted output above mean? How to recover my previous Windows 7 installation that's in /dev/sda1 (NTFS). I have some important files I need. Also, I had a PGP encryption on the disk before installing Ubuntu. Now, it just boots straight into Ubuntu... why? How to uninstall Ubuntu (the Try ubuntu and uninstall did not work. the boot-repair did not work) I have read other topics but noone has provided a proper step by step answer to how to recover my 278GB WIndows partition. The testdisk step by step procedure did not work. It says the NTFS disk is unrecognized.

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  • Is full partition encryption the only sure way to make Ubuntu safe from external access?

    - by fred.bear
    (By "external access", I mean eg. via a Live CD, or another OS on the same dual-boot machine) A friend wants to try Ubuntu. He's fed up with Vista grinding to a crawl (the kids? :), so he likes the "potential" security offered by Ubuntu, but because the computer will be multi-booting Ubuntu (primary) and 2 Vistas (one for him, if he ever needs it again, and the other one for the kids to screw up (again). However, he is concerned about any non-Ubuntu access to the Ubuntu partitions (and also to his Vista partition)... I believe TrueCrypt will do the job for his Vista, but I'd like to know what the best encryption system for Ubuntu is... If TrueCrypt works for Ubuntu, it may be the best option for him, as it would be the same look and feel for both. Ubuntu will be installed with 3 partitions; 1) root 2) home 3) swap.. Will Ubuntu's boot loader clash with TrueCrypt's encrypted partition? PS.. Is encryption a suitable solution?

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  • Dual boot :Windows 7 partition deleted after Kubuntu 14.04 install...Weird!

    - by user292152
    I've bought two new SSD's in order to install Kubuntu on one and Win 7 on the other one. Before I had Linux Mint and Win7 together one just one SSD. So first I installed win7 as recommended, and then used the guided installer of Kubuntu to install Kubuntu. I selected the second SSD, chose the option "use entire disk and install", but to my surprise after rebooting and selecting win7 boot loader from grub2, I got a prompt that my windows installation is damaged, and I need to run the repair option from the installation disk. So I booted into Kubuntu again, fired up kparted and saw that indeed my windows partition got deleted, except the recovery partition. I don't understand what happened. I am not new to this topic, and this was not my first time installing Ubuntu alongside windows. I have never ever had that problem. What can I do to make sure this won't happen again, so I won't waste another 2 hours of my life? ?? Thanks a lot !

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  • How to join a Windows Domain and Map Network Drives?

    - by AgainstClint
    I just installed the current build for Ubuntu on a partition for my work computer. I am a novice when it comes to Linux/Ubuntu, which is why I installed it along side windows. I want to learn how to operate and use Ubuntu much more than I do now, so I figured installing it and trying to do day to day functions here would be a "Thrown into the pool with sharks" way to do it, and I like that way. I did however have a few questions: We are on a Domain in Windows, is there any way to join that domain using the Ubuntu partition? We Also have 16 mapped network drives. I don't actually need ALL of them mapped for Ubuntu, but is there a way to Map at least one of them to see/use here in Ubuntu. Outlook Corporate email, how can I sign in/use it while...well, you get the idea. As I said earlier, I am VERY new to Ubuntu, i've only played around with it a bit at home and never at the office. If you could simplify it down for me a bit, that would be great.

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  • How to re-join an AD2003 domain with Samba after deleting the machine account?

    - by Guss
    During some troubleshooting I deleted the machine account for a Linux server running samba from our AD 2003 domain. We are using Kerberos for authentication, and after I deleted the machine account I tried to join the domain again using net ads join -U Administrator But I keep getting Kerberos errors like these: [2009/08/18 16:14:36, 0] libads/kerberos.c:ads_kinit_password(228) kerberos_kinit_password [email protected] failed: Client not found in Kerberos database Failed to join domain: Improperly formed account name It appears as if samba remembers that it once had an account with the AD and keeps trying to reconnect to it, but I want to create a new account from scratch. I tried to delete all the .tdb files I could find as well as everything under /var/cache/samba but to no avail - it still behaves the same. I also tried to create the machine account on the AD side, but then I get a similar error when I try to join, about failure to authenticate with the machine account - it looks like samba tries the previous machine account password and I don't know how to reset it, or even if I could figure out what samba uses - how to set it in the AD. Any help would be greatly appreciated, as at this point the only thing I can think about is to reformat and reinstall the machine, and I would really REALLY love to not do that. Thanks in advance.

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  • How can I mount dd image of a partition?

    - by Puneet Arora
    I created a dd image of a partition (containing an HFS+ FS) of one of my disks (and not the entire disk) a few days ago using the following command - dd conv=sync,noerror bs=8k if=/dev/sdc2 of=/path/to/img How can I mount it? I tried the following but it doesn't work - mount -o loop,ro -t hfsplus /path/to/img /path/to/mntDir It gives me mount: wrong fs type, bad option, bad superblock on /dev/loop1, missing codepage or helper program, or other error In some cases useful info is found in syslog - try dmesg | tail or so and dmesg | tail gives me - [5248455.568479] hfs: invalid secondary volume header [5248455.568494] hfs: unable to find HFS+ superblock [5248462.674836] hfs: invalid secondary volume header [5248462.674843] hfs: unable to find HFS+ superblock [5248550.672105] hfs: invalid secondary volume header [5248550.672115] hfs: unable to find HFS+ superblock [5248993.612026] hfs: unable to find HFS+ superblock [5248998.103385] hfs: unable to find HFS+ superblock [5249031.441359] hfs: unable to find HFS+ superblock [5249036.274864] hfs: unable to find HFS+ superblock Is there something wrong that I am doing? I tried searching on how to do this but all the results I get only talk about mounting a partition from within a full disk image, using the offset option with mount - none talk about the case where the image itself is that of a partition. Thanks. PS: I'm running 64bit Arch Linux, and the partition from the original disk /dev/sdc2 mounts fine.

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  • How to create partition when growing raid5 with mdadm.

    - by hometoast
    I have 4 drives, 2x640GB, and 2x1TB drives. My array is made up of the four 640GB partitions and the beginning of each drive. I want to replace both 640GB with 1TB drives. I understand I need to 1) fail a disk 2) replace with new 3) partition 4) add disk to array My question is, when I create the new partition on the new 1TB drive, do I create a 1TB "Raid Auto Detect" partition? Or do I create another 640GB partition and grow it later? Or perhaps the same question could be worded: after I replace the drives how to I grow the 640GB raid partitions to fill the rest of the 1TB drive? fdisk info: Disk /dev/sdb: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xe3d0900f Device Boot Start End Blocks Id System /dev/sdb1 1 77825 625129281 fd Linux raid autodetect /dev/sdb2 77826 121601 351630720 83 Linux Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xc0b23adf Device Boot Start End Blocks Id System /dev/sdc1 1 77825 625129281 fd Linux raid autodetect /dev/sdc2 77826 121601 351630720 83 Linux Disk /dev/sdd: 640.1 GB, 640135028736 bytes 255 heads, 63 sectors/track, 77825 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0x582c8b94 Device Boot Start End Blocks Id System /dev/sdd1 1 77825 625129281 fd Linux raid autodetect Disk /dev/sde: 640.1 GB, 640135028736 bytes 255 heads, 63 sectors/track, 77825 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Disk identifier: 0xbc33313a Device Boot Start End Blocks Id System /dev/sde1 1 77825 625129281 fd Linux raid autodetect Disk /dev/md0: 1920.4 GB, 1920396951552 bytes 2 heads, 4 sectors/track, 468846912 cylinders Units = cylinders of 8 * 512 = 4096 bytes Disk identifier: 0x00000000

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  • Multiboot USB (OSX only): How to customize partition name?

    - by wrk2bike
    Trying to deal with all the Mac OSX recovery disks I've got by moving them to bootable USB images. I've got a big USB drive with multiple partitions for each recovery disk, and it's easy to use Disk Utility to "restore" the recovery DVD to a partition. When I boot my target Mac while holding down the Alt key, I can see all my bootable images and they work great. Problem is, they've all got the same name: "Mac OS X Install DVD." I manage Macs of various vintages. If my target Mac needs 10.6.3 for example, my only option seems to be to try each one until I get past the "Mac OSX can't be installed on this computer" message. I originally named my partitions with the OSX revision number, but that name is replaced by the disk image name during Disk Utility restore. Is there any way to customize the name during or after Disk Utility restore? I tried making a new DVD image on disk first and renaming it, but when I restore it to my recovery partition it has the original name. EDIT: After booting to the wrong partition, and getting the "..can't be installed" message, I can open the Startup Disk menu and see the other partitions - and as I select each one, the info at the bottom indicates which OS revision is on that partition. So I know the info is in there! Just want it at the boot screen if possible.

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  • How can I extend / create a new partition from the following setup?

    - by Kiada
    I'm a little unsure what to do in this situation. When I try to create a new simple volume from the unallocated space I get an error because I already have 4 partitions. I have no option to extend either my C:\ primary partition or the E:\ logical drive. C:\ - Gaming Win7 install. D:\ - Storage Unallocated Space - Would somehow like to install OSX on a partition from this space. E:\ - Software Development Win7 install. I:\ - Ignore this. It's an external 1TB HDD. Do I have any options that do not involve formatting / losing information on either C:\ or E:\? Thank you. Link to visual disk partitioning setup image. Edit: A bit more information regarding partitions. Firstly, the image linked above is a screenshot of Windows 7 partitioning tool, easier to read than text I guess! H:\ System Reserved: 100MB NTFS C:\ 244 GB NTFS Healthy (Page File, Primary Partition) D:\ 294 GB NTFS Healthy (Primary Partition) E:\ 100 GB NTFS Healthy (Boot, Page File, Crash Dump, Logical Drive) Unallocated 292 GB Hope this helps :)

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  • STORED PROCEDURE working in my local test machine cannot be created in production environment.

    - by Marcos Buarque
    Hi, I have an SQL CREATE PROCEDURE statement that runs perfectly in my local SQL Server, but cannot be recreated in production environment. The error message I get in production is Msg 102, Level 15, State 1, Incorrect syntax near '='. It is a pretty big query and I don't want to annoy StackOverflow users, but I simply can't find a solution. If only you could point me out what settings I could check in the production server in order to enable running the code... I must be using some kind of syntax or something that is conflicting with some setting in production. This PROCEDURE was already registered in production before, but when I ran a DROP - CREATE PROCEDURE today, the server was able to drop the procedure, but not to recreate it. I will paste the code below. Thank you! =============== USE [Enorway] GO /****** Object: StoredProcedure [dbo].[Spel_CM_ChartsUsersTotals] Script Date: 03/17/2010 11:59:57 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE PROC [dbo].[Spel_CM_ChartsUsersTotals] @IdGroup int, @IdAssessment int, @UserId int AS SET NOCOUNT ON DECLARE @RequiredColor varchar(6) SET @RequiredColor = '3333cc' DECLARE @ManagersColor varchar(6) SET @ManagersColor = '993300' DECLARE @GroupColor varchar(6) SET @GroupColor = 'ff0000' DECLARE @SelfColor varchar(6) SET @SelfColor = '336600' DECLARE @TeamColor varchar(6) SET @TeamColor = '993399' DECLARE @intMyCounter tinyint DECLARE @intManagersPosition tinyint DECLARE @intGroupPosition tinyint DECLARE @intSelfPosition tinyint DECLARE @intTeamPosition tinyint SET @intMyCounter = 1 -- Table that will hold the subtotals... DECLARE @tblTotalsSource table ( IdCompetency int, CompetencyName nvarchar(200), FunctionRequiredLevel float, ManagersAverageAssessment float, SelfAssessment float, GroupAverageAssessment float, TeamAverageAssessment float ) INSERT INTO @tblTotalsSource ( IdCompetency, CompetencyName, FunctionRequiredLevel, ManagersAverageAssessment, SelfAssessment, GroupAverageAssessment, TeamAverageAssessment ) SELECT e.[IdCompetency], dbo.replaceAccentChar(e.[Name]) AS CompetencyName, (i.[LevelNumber]) AS FunctionRequiredLevel, ( SELECT ROUND(avg(CAST(ac.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData aa INNER JOIN Spel_CM_CompetenciesLevels ab ON aa.[IdCompetencyLevel] = ab.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels ac ON ab.[IdLevel] = ac.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents ad ON aa.[IdAssessmentEvent] = ad.[IdAssessmentEvent] WHERE aa.[EvaluatedUserId] = @UserId AND aa.[AssessmentType] = 't' AND aa.[IdGroup] = @IdGroup AND ab.[IdCompetency] = e.[IdCompetency] AND ad.[IdAssessment] = @IdAssessment ) AS ManagersAverageAssessment, ( SELECT bc.[LevelNumber] FROM Spel_CM_AssessmentsData ba INNER JOIN Spel_CM_CompetenciesLevels bb ON ba.[IdCompetencyLevel] = bb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels bc ON bb.[IdLevel] = bc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents bd ON ba.[IdAssessmentEvent] = bd.[IdAssessmentEvent] WHERE ba.[EvaluatedUserId] = @UserId AND ba.[AssessmentType] = 's' AND ba.[IdGroup] = @IdGroup AND bb.[IdCompetency] = e.[IdCompetency] AND bd.[IdAssessment] = @IdAssessment ) AS SelfAssessment, ( SELECT ROUND(avg(CAST(cc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData ca INNER JOIN Spel_CM_CompetenciesLevels cb ON ca.[IdCompetencyLevel] = cb.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels cc ON cb.[IdLevel] = cc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents cd ON ca.[IdAssessmentEvent] = cd.[IdAssessmentEvent] WHERE ca.[EvaluatedUserId] = @UserId AND ca.[AssessmentType] = 'g' AND ca.[IdGroup] = @IdGroup AND cb.[IdCompetency] = e.[IdCompetency] AND cd.[IdAssessment] = @IdAssessment ) AS GroupAverageAssessment, ( SELECT ROUND(avg(CAST(dc.[LevelNumber] AS float)),0) FROM Spel_CM_AssessmentsData da INNER JOIN Spel_CM_CompetenciesLevels db ON da.[IdCompetencyLevel] = db.[IdCompetencyLevel] INNER JOIN Spel_CM_Levels dc ON db.[IdLevel] = dc.[IdLevel] INNER JOIN Spel_CM_AssessmentsEvents dd ON da.[IdAssessmentEvent] = dd.[IdAssessmentEvent] WHERE da.[EvaluatedUserId] = @UserId AND da.[AssessmentType] = 'm' AND da.[IdGroup] = @IdGroup AND db.[IdCompetency] = e.[IdCompetency] AND dd.[IdAssessment] = @IdAssessment ) AS TeamAverageAssessment FROM Spel_CM_AssessmentsData a INNER JOIN Spel_CM_AssessmentsEvents c ON a.[IdAssessmentEvent] = c.[IdAssessmentEvent] INNER JOIN Spel_CM_CompetenciesLevels d ON a.[IdCompetencyLevel] = d.[IdCompetencyLevel] INNER JOIN Spel_CM_Competencies e ON d.[IdCompetency] = e.[IdCompetency] INNER JOIN Spel_CM_Levels f ON d.[IdLevel] = f.[IdLevel] -- This will link with user's assigned functions INNER JOIN Spel_CM_FunctionsCompetenciesLevels g ON a.[IdFunction] = g.[IdFunction] INNER JOIN Spel_CM_CompetenciesLevels h ON g.[IdCompetencyLevel] = h.[IdCompetencyLevel] AND e.[IdCompetency] = h.[IdCompetency] INNER JOIN Spel_CM_Levels i ON h.[IdLevel] = i.[IdLevel] WHERE (NOT c.[EndDate] IS NULL) AND a.[EvaluatedUserId] = @UserId AND c.[IdAssessment] = @IdAssessment AND a.[IdGroup] = @IdGroup GROUP BY e.[IdCompetency], e.[Name], i.[LevelNumber] ORDER BY e.[Name] ASC -- This will define the position of each element (managers, group, self and team) SELECT @intManagersPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT ManagersAverageAssessment IS NULL IF IsNumeric(@intManagersPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intGroupPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT GroupAverageAssessment IS NULL IF IsNumeric(@intGroupPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intSelfPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT SelfAssessment IS NULL IF IsNumeric(@intSelfPosition) = 1 BEGIN SELECT @intMyCounter += 1 END SELECT @intTeamPosition = @intMyCounter FROM @tblTotalsSource WHERE NOT TeamAverageAssessment IS NULL -- This will render the final table for the end user. The tabe will flatten some of the numbers to allow them to be prepared for Google Graphics. SELECT SUBSTRING( ( SELECT ( '|' + REPLACE(ma.[CompetencyName],' ','+')) FROM @tblTotalsSource ma ORDER BY ma.[CompetencyName] DESC FOR XML PATH('') ), 2, 1000) AS 'CompetenciesNames', SUBSTRING( ( SELECT ( ',' + REPLACE(ra.[FunctionRequiredLevel]*10,' ','+')) FROM @tblTotalsSource ra FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredLevel', SUBSTRING( ( SELECT ( ',' + CAST(na.[ManagersAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource na FOR XML PATH('') ), 2, 1000) AS 'ManagersAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(oa.[GroupAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource oa FOR XML PATH('') ), 2, 1000) AS 'GroupAverageAssessment', SUBSTRING( ( SELECT ( ',' + CAST(pa.[SelfAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource pa FOR XML PATH('') ), 2, 1000) AS 'SelfAssessment', SUBSTRING( ( SELECT ( ',' + CAST(qa.[TeamAverageAssessment]*10 AS nvarchar(10))) FROM @tblTotalsSource qa FOR XML PATH('') ), 2, 1000) AS 'TeamAverageAssessment', SUBSTRING( ( SELECT ( '|t++' + CAST([FunctionRequiredLevel] AS varchar(10)) + ',' + @RequiredColor + ',0,' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'FunctionRequiredAverageLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([ManagersAverageAssessment] AS varchar(10)) + ',' + @ManagersColor + ',' + CAST(@intManagersPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'ManagersLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([GroupAverageAssessment] AS varchar(10)) + ',' + @GroupColor + ',' + CAST(@intGroupPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'GroupLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([SelfAssessment] AS varchar(10)) + ',' + @SelfColor + ',' + CAST(@intSelfPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',9') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'SelfLabel', SUBSTRING( ( SELECT ( '|t++' + CAST([TeamAverageAssessment] AS varchar(10)) + ',' + @TeamColor + ',' + CAST(@intTeamPosition AS varchar(2)) + ',' + CAST(ROW_NUMBER() OVER(ORDER BY CompetencyName) - 1 AS varchar(2)) + ',10') FROM @tblTotalsSource FOR XML PATH('') ), 2, 1000) AS 'TeamLabel', (Count(src.[IdCompetency]) * 30) + 100 AS 'ControlHeight' FROM @tblTotalsSource src SET NOCOUNT OFF GO

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  • Is my computer slow due to lack of swap

    - by Kristian Jensen
    A few months ago, I installed Ubuntu 12.04 alongside with Windows 7 on my Asus EEE-PC 1015bx. It has a tendency of freezing and when trying to investigate I found that a swap partition of only 256 MB had been created. The Asus EEE-PC 1015bx is born with 1 GByte RAM only and it is not possible to add further or exchange the existing 1 GByte with a larger card. When looking at the system monitor, it looks like all swap is being utilized along with 70-75% of the RAM, even with very few applications running. Can the lack of much swap space be the reason for my computer running slowly and at times freezing? How can I add a swap partition? Or should I add a swap file instead? At the moment, I see two partitions when viewing the system monitor: one 28.6 GByte ext4 partition which must be the one containing Ubuntu and one 100 GByte fuseblk partition which I assume is the one holding Windows. It shows that I have 18.6 GByte free space on the ext4 partition. Can I "take a bite" from the ext4 partition and convert this into a swap partition? I was thinking something like 3 GBytes for swap considering my limited RAM. I hope that someone can guide me through. Thank you. 20th Oct 2012 - Further details Thank you for below answer which I find very useful. I am certainly considering switching to one of your suggested shells as I can see from the Internet that many have posted that these require much fewer resources than ubuntu. It seems to me that lubuntu is the perfect match for my very limited computer. I will have to wait a few days, though, as I am presently limited by a very slow and restricted Internet connection via satellite. But will lubuntu install as simply another shell replacing unity or will it replace ubuntu all together? Will the software that I have installed under ubuntu still be accessible in lubuntu? And can I return to ubuntu if required? Regarding the actual question of swap: When I run gparted, it shows me that there is one ntfs partition of 100 GBytes from where it boots and the before mentioned ext4 partition of 28.6 GBytes is not mentioned. Could it be that my ubuntu installation resides inside this 100 GBytes ntfs partiotion? And if so, can I take a bite of this for my swap partition? Realising that gparted is shown in Danish, I hope that you can make out what I mean. System monitoring shows below details: Once again I sincerely hope that you can help. Thank you.

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  • Ubuntu Install 11.10 doesn't recognize Windows 7 installation with new HDD

    - by arlendo
    Replaced my crashed HDD with a Seagate 2TB Sata (bought from a company who pulled it from a working computer, OS unknown) and did a fresh install of Windows 7. Windows shows 100MB boot partition (bootable NTFS) and 200GB Windows partition (NTFS), the rest is unallocated. Win7 Disk Management says the partitioning type is Master Boot Record. Win7 boots and runs fine. Ubuntu 11.10 Install procedes to Allocate Drive Space screen and should say This computer currently has Windows 7 on it. What would you like to do? Instead, it says something like Install doesn't detect any existing OS on this computer. When I click on Something else, the partition table shows only the unallocated space of 1.8TB. Ubuntu Disk Utility says Partitioning: Master Boot Record, but GParted Live says Partition Table: gpt. It was my original intention to have the Windows boot partition and application partition, then install Ubuntu 11.10 using boot, root, swap, and home partitions, and maybe another partition just for data (mostly photos). Currently, I would be happy if I could just get Ubuntu installed along with Win7. I am aware of the MBR limits of 3 Primary partitions and 1 Extended partition. I suspect that my new HDD is partitioned for GPT and that is why Ubuntu can't see the Win7 installation. Am I on the right track? I was going to use Windows Disk Management to convert GPT to MBR but I only have the one drive on my AMD-64 mini-computer and it says I have to empty the drive of all partitions before I can access the Convert command. And I can't find any bootable software that would allow me to do that conversion. Here is the result of sudo fdisk -l: ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 2000.4 GB, 2000398934016 bytes 224 heads, 19 sectors/track, 918004 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xd4a68c18 Device Boot Start End Blocks Id System /dev/sda1 * 2048 206847 102400 7 HPFS/NTFS/exFAT /dev/sda2 206848 419637247 209715200 7 HPFS/NTFS/exFAT ubuntu@ubuntu:~$ Keep in mind that I'm a definite newbie to screwing around with the inner workings of Ubuntu. I previously had Ubuntu 10.04 running with Vista and I don't remember even having to partition anything that wasn't automatic in the install. Thanks for taking a look here. My Win7 is running fine but I miss my Ubuntu.

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