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  • MySQL: List rows who have one but not another many-to-many relationship

    - by Svish
    Not quite sure how to ask or define this, but can't figure it out. I have three tables like this: persons person_id, first_name, last_name hobbies hobby_id, name persons_hobbies person_id, hobby_id I need to make two lists. Persons that have both hobby A and B, and persons that have hobby A but not B. How can I write these two queries? Can't figure out how to do this with joining and all...

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  • MySQL query with JOINS and GROUP BY

    - by user1854049
    I'm building a MySQL query but I can't seem to get it right. I have four tables: - customers - orders - sales_rates - purchase_rates There is a 1:n relation 'customernr' between customers and orders. There is a 1:n relation 'ordernr' between orders and sales_rates. There is a 1:n relation 'ordernr' between orders and purchase_rates. What I would like to do is produce an output of all customers with their total purchase and sales amounts. So far I have the following query. SELECT c.customernr, c.customer_name, SUM(sr.sales_price) AS sales_price, SUM(pr.purchase_price) AS purchase_price FROM orders o, customers c, sales_rates sr, purchase_rates pr WHERE o.customernr = c.customernr AND o.ordernr = sr.ordernr AND o.ordernr = pr.ordernr GROUP BY k.bedrijfsnaam The result of the sales_price and purchase_price is far too high. I seem to be getting double counts. What am I doing wrong? Is it possible to perform this in a single query? Thank for your response!

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  • sql query help join (i think)

    - by milan
    I am having trouble figuring our how I can get results only when products.published, product_types.published, and product_cats.published = 1 but my query isn't working. Please help: SELECT `products`.`title`, `products`.`menu_id`, `products`.`short_description`, `products`.`datasheet_icon`, `products`.`datasheet`, `products`.`ordering`, `products`.`product_type_id`, CASE WHEN CHAR_LENGTH(`products`.`alias`) THEN CONCAT_WS(':', `products`.`id`, `products`.`alias`) ELSE `products`.`id` END AS slug FROM `products`, `product_cats`, `product_types` WHERE `products`.published=1 AND `product_cats`.published=1 AND `product_types`.published=1 AND `products`.`product_cat_id`='42' AND `product_types`.`id` IN (1,40,48,49,50) GROUP BY `products`.`id` ORDER BY `product_types`.`ordering`, `products`.`ordering`

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  • Join two results sets to make one result set in T-SQL

    - by Michael Kniskern
    What would be the best approach to combine the two results sets in one result set in T-SQL? SQL statment #1: SELECT COUNT(t.col1) as 'Number of Responses', t.col2 as 'Department' FROM table t WHERE col3 IS NOT NULL GROUP BY t.col1 ORDER BY t.col1 SQL Statment #1: SELECT COUNT(t.col1) as 'Total number of participants', t.col2 as 'Department' FROM table t GROUP BY t.col1 ORDER by t.col1 Desired result set Number of Responses | Total Number of participants | Department

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  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

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  • Activerecord join search

    - by VP
    Hi, i have two models: class Category has many :jobs end class Job belongs_to :category end So for sure i'm able to do c = Category.first c.jobs My question is: how can i find just categories that has at least one job?

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  • Dealing with three Windows partitions in dual boot installation

    - by Tim
    For dual-boot installation of Ubuntu after Windows. Quoted from ubuntuguide If a Windows boot partition exists as a second NTFS partition, it should be left alone. If there is a Windows recovery partition also installed, it can also be left alone as long as there are only two NTFS partitions total on the hard drive (i.e. there is no NTFS boot partition as well). If there are a total of 3 NTFS partitions on the hard drive, then the third Windows NTFS partition (the recovery partition) should be removed after creating Recovery CDs from it (see here). In the last case where Windows has three partitions, I was wondering why it says the recovery partition shall be removed? Is it possible to keep the three and create another extended partition with several logical partitions for installing Ubuntu and dual-booting the two OSes? I plan to dual-boot install Ubuntu 10.04 with existing Windows 7. Following is the layout of the current partitions of my hard drive viewed from Windows 7: So must I remove the Lenovo_Recovery (Q:) partition for the same reason you give for the first question? Thanks and regards!

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  • Can I safely delete the Ubuntu 12.04 partition and use the unallocated space for my Elementary OS?

    - by d4ryl3
    I have this setup: I've decided to switch to Elementary OS Luna (fork of Ubuntu 12.04) as my main Linux distro. Now I need to delete my Ubuntu partition so I could add capacity to my eOS which only has 10Gb. Currently my eOS is in /dev/sda9, and Ubuntu in /dev/sda8/. I forgot where my bootloader is installed, so I ran bootinfoscript, which returned this: `============================= Boot Info Summary: =============================== = Grub2 (v1.99) is installed in the MBR of /dev/sda and looks at sector 1 of the same hard drive for core.img. core.img is at this location and looks in partition 94 for . sda1: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files: /bootmgr /Boot/BCD sda2: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Windows 7 Boot files: /bootmgr /Boot/BCD /Windows/System32/winload.exe sda3: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: No errors found in the Boot Parameter Block. Operating System: Boot files: /bootmgr /boot/bcd sda4: __________________________________________ File system: Extended Partition Boot sector type: - Boot sector info: sda5: __________________________________________ File system: ntfs Boot sector type: Windows Vista/7: NTFS Boot sector info: According to the info in the boot sector, sda5 starts at sector 2048. Operating System: Boot files: sda6: __________________________________________ File system: swap Boot sector type: - Boot sector info: sda7: __________________________________________ File system: ext4 Boot sector type: Grub2 (v1.99) Boot sector info: Grub2 (v1.99) is installed in the boot sector of sda7 and looks at sector 851823520 of the same hard drive for core.img, but core.img can not be found at this location. Operating System: Boot files: /grub/grub.cfg /extlinux/extlinux.conf sda8: __________________________________________ File system: ext4 Boot sector type: Grub2 (v1.99) Boot sector info: Grub2 (v1.99) is installed in the boot sector of sda8 and looks at sector 860224256 of the same hard drive for core.img. core.img is at this location and looks for (,msdos9)/boot/grub on this drive. Operating System: Ubuntu 13.04 Boot files: /etc/fstab sda9: __________________________________________ File system: ext4 Boot sector type: - Boot sector info: Operating System: elementary OS Luna Boot files: /boot/grub/grub.cfg /etc/fstab /boot/grub/core.img` I need advice as to how to proceed. I mean, could I simply delete /dev/sda7/ and /dev/sda8/? Please help, thank you.

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  • What are the appropriate mount options for a shared NTFS partition on an SSD in a dual boot Ubuntu/Windows setup?

    - by Andreas Jonsson
    I have Ubuntu 13.10 and Windows 7 installed in dual boot on a single SSD. In addition they share an NTFS partition where I put all my data and documents. What is the optimal way to mount this NTFS partition in /etc/fstab (considering performance and minimizing wear of the SSD)? Similar questions have been asked, but I could not find answers to this particular scenario. As I understand it, the mount option 'discard' is not supported for NTFS and so should not be used (although it is recommended here). Another often quoted mount option is 'noatime'. I use it for my ext4 partitions. Does it apply to NTFS? My current /etc/fstab line is: UUID=XXXXXXXXXXXXXXXX /dos ntfs defaults,nls=utf8,uid=1000,gid=1000 0 0

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  • How large of a swap partition is needed to hibernate?

    - by Closure Cowboy
    I've read this question, but it doesn't definitively answer my question. If I want my computer to be able to hibernate, do I need to have a swap partition as large as my RAM, or will Ubuntu wisely be able to hibernate if the swap partition can fit the currently-in-use RAM? I'm about to install Ubuntu on a computer with a lot of RAM, and a relatively small hard drive, so I don't want to use more hard drive space than necessary. I wanted to avoid giving my actual specifications to keep this question more general, though I'll give them if necessary.

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  • Recovery from hell - undeleting partition overwritten by Xubuntu 12.10 installer?

    - by DaimyoKirby
    This is turning into a nightmare - following my initial recovery of my two partitions, I went to install Xubuntu 12.10 (again). At this time I had two partitions - one of ~39 GB had Zorin OS 6 installed on it, and another of ~33 GB had nothing installed, just a few files in it that I had manually backed up (moved) there. When I got to the partitioning step, I chose "Replace Zorin OS 6 with Xubuntu 12.10", along with LVM, naturally thinking that the installer wouldn't touch the second partition, since Zorin wasn't installed on it. I was dead wrong. Upon booting my newly installed Xubuntu 12.10, I found in gparted that there were only two partitions - ~255MB, which appears to have the boot stuff in it (it's flagged boot in gparted), and another of ~74 GB. Question: Is there any way to salvage my old files on the non-Zorin ext3 partition? I'm really upset I made such a dumb move (again...), and any and all help is appreciated very, very much!

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  • How do I move my LVM 250 GB root partition to a new 120GB hard disk?

    - by Dennis Schma
    I have the following situation: My current Ubuntu installation is running from an external HDD (250 GB) because I was to lazy to buy an new internal hdd. Now i've got a new internal (120GB) and i want to move everything to the internal. Installing Ubuntu new is out of disscussion because its to peronalized. Luckily (i hope so) the root partition is partitioned with LVM, so i hope i can move the partition to the smaller internal HDD. Is this possible? And where do i find help?

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  • large tmpfs /run partition - must it be so big?

    - by Stevod
    I am running Ubuntu 11.10 desktop on a couple of 8G RAM Wintel boxes. Both have been created automatically by the default installer with a 1.6GB tmpfs /run partition, where I suspect this amount of RAM could be more usefully used elsewhere in the system. I suspect that the installer takes 20% as the default, which is probably OK for boxes with lots less RAM, but seems overkill for an 8GB system. My question is - can I change its size, if so, how, and what are the risks in doing so? The /run partition does not appear in the /etc/fstab file so it must be set up elsewhere.

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  • How do I get a right outer join in L2E?

    - by Dan
    I have two tables that I set up through the VS Entity Data Model Diagram tool. I'm trying to do a right outer join and it doesn't return results from the 2nd table. I have set up a 0..1 to MANY relationship from the diagram tool. When I run a Linq-To-Entities query, it still defaults to an INNER JOIN. From my understanding of entities, if I set up the relationship using VS, when I join the tables, it should automagically figure out the join syntax based on the relationship I supply. It doesn't seem to be doing that. I am using EF v1 (not Linq-to-Sql). Query I'm running: from s in SomeTable join t in SomeOtherTable on s.ID equals t.ID select new { s.MyFieldName, t.MyOtherFieldName }

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  • How to convert full outer join query to O-R query?

    - by Kugel
    I'm converting relational database into object-relational in Oracle. I have a query that uses full outer join in the old one. Is it possible to write the same query for O-R database without explicitly using full outer join? For normal inner join it simple, I just use dot notation together with ref/deref. I'm interested in this in general so let's say the relational query is: select a.attr, b.attr from a full outer join b on (a.fk = b.pk); I want to know if it's a good idea to do it this way: select a.attr, b.attr from a_obj a full outer join b_obj b on (a.b_ref = ref(b));

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  • SQL JOIN with two or more tables as output - most efficient way?

    - by littlegreen
    I have an SQL query that executes a LEFT JOIN on another table, then outputs all results that could be coupled into a designated table. I then have a second SQL query that executes the LEFT JOIN again, then outputs the results that could not be coupled to a designated table. In code, this is something like: INSERT INTO coupledrecords SELECT b.col1, b.col2... s.col1, s.col2... FROM bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NOT NULL INSERT INTO notcoupledrecords SELECT b.col1, b.col2... bigtable AS b LEFT JOIN smallertable AS s ON criterium WHERE s.col1 IS NULL My question: I now have to execute the JOIN two times, in order to achieve what I want. I have a feeling that this is twice as slow as it could be. Is this true, and if yes, is there a way to do it more efficiently?

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  • JavaScript: String Concatenation slow performance? Array.join('')?

    - by NickNick
    I've read that if I have a for loop, I should not use string concation because it's slow. Such as: for (i=0;i<10000000;i++) { str += 'a'; } And instead, I should use Array.join(), since it's much faster: var tmp = []; for (i=0;i<10000000;i++) { tmp.push('a'); } var str = tmp.join(''); However, I have also read that string concatention is ONLY a problem for Internet Explorer and that browsers such as Safari/Chrome, which use Webkit, actually perform FASTER is using string concatention than Array.join(). I've attempting to find a performance comparison between all major browser of string concatenation vs Array.join() and haven't been able to find one. As such, what is faster and more efficient JavaScript code? Using string concatenation or Array.join()?

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  • MySQL create stored procedure fails but all internal queries succeed alone?

    - by Mark
    Hi all, I just created a simple database in MySQL, and I am learning how to write stored proc's. I'm familiar with M$SQL and as far as I can see the following should work: use mydb; -- -------------------------------------------------------------------------------- -- Routine DDL -- -------------------------------------------------------------------------------- DELIMITER // CREATE PROCEDURE mydb.doStats () BEGIN CREATE TABLE IF NOT EXISTS resultprobability ( ballNumber INT NOT NULL , probability FLOAT NULL, PRIMARY KEY (ballNumber) ); CREATE TABLE IF NOT EXISTS drawProbability ( drawDate DATE NOT NULL , ball1 INT NULL , ball2 INT NULL , ball3 INT NULL , ball4 INT NULL , ball5 INT NULL , ball6 INT NULL , ball7 INT NULL , score FLOAT NULL , PRIMARY KEY (drawDate) ); TRUNCATE TABLE resultprobability; TRUNCATE TABLE drawprobability; INSERT INTO resultprobability (ballNumber, probability) (select resultset.ballNumber ballNumber,(count(0)/(select count(0) from resultset)) probability from resultset group by resultset.ballNumber); INSERT INTO drawProbability (drawDate, ball1, ball2, ball3, ball4, ball5, ball6, ball7, score) (select distinct r.drawDate, a.ballnumber ball1, b.ballnumber ball2, c.ballnumber ball3, d.ballnumber ball4, e.ballnumber ball5, f.ballnumber ball6,g.ballnumber ball7, ((a.probability + b.probability + c.probability + d.probability + e.probability + f.probability + g.probability)/7) score from resultset r inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 1) a on a.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 2) b on b.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 3) c on c.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 4) d on d.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 5) e on e.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 6) f on f.drawdate = r.drawDate inner join (select r.drawDate, r.ballNumber, p.probability from resultset r inner join resultprobability p on p.ballNumber = r.ballNumber where r.appearence = 7) g on g.drawdate = r.drawDate order by score desc); END // DELIMITER ; instead i get the following Executed successfully in 0.002 s, 0 rows affected. Line 1, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 26 Line 6, column 1 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')) probability from resultset group by resultset.ballNumber); INSERT INTO d' at line 1 Line 31, column 51 Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ') score from resultset r inner join (select r.drawDate, r.ballNumber, p.probabi' at line 1 Line 39, column 114 Execution finished after 0.002 s, 3 error(s) occurred. What am I doing wrong? I seem to have exhausted my limited mental abilities!

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  • GPT Not mounting using "normal" GPT mounting techniques 12.04

    - by Roy Markham
    I've got two 2TB drivess: one MBR and the other GPT. sudo blckid /dev/sdb1 returns a blank. gdisk shows: Partition table scan: MBR: protective BSD: not present APM: not present GPT: present Found valid GPT with protective MBR; using GPT. Warning! Secondary partition table overlaps the last partition by 1970 blocks! You will need to delete this partition or resize it in another utility. Disk /dev/sdb: 3907027055 sectors, 1.8 TiB Logical sector size: 512 bytes Disk identifier (GUID): 38A1113D-B5E9-4B69-ABFF-ACB27AFB3DDD Partition table holds up to 128 entries First usable sector is 34, last usable sector is 3907027021 Partitions will be aligned on 8-sector boundaries Total free space is 2014 sectors (1007.0 KiB) Number Start (sector) End (sector) Size Code Name 1 34 262177 128.0 MiB 0C01 Microsoft reserved part 2 264192 3907028991 1.8 TiB 0700 Basic data partition mounting via fstab or -t gives same error when using NTFS or NTFS-3g "NTFS signature is missing" GParted says one partition is overwriting another, yet windows shows no errors at all. The drive is also mounted easily via MacOs (triple boot)

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  • Why does Python's math.factorial not play nice with threads?

    - by W1N9Zr0
    Why does math.factorial act so weird in a thread? Here is an example, it creates three threads: thread that just sleeps for a while thread that increments an int for a while thread that does math.factorial on a large number. It calls start on the threads, then join with a timeout The sleep and spin threads work as expected and return from start right away, and then sit in the join for the timeout. The factorial thread on the other hand does not return from start until it runs to the end! import sys from threading import Thread from time import sleep, time from math import factorial # Helper class that stores a start time to compare to class timed_thread(Thread): def __init__(self, time_start): Thread.__init__(self) self.time_start = time_start # Thread that just executes sleep() class sleep_thread(timed_thread): def run(self): sleep(15) print "st DONE:\t%f" % (time() - time_start) # Thread that increments a number for a while class spin_thread(timed_thread): def run(self): x = 1 while x < 120000000: x += 1 print "sp DONE:\t%f" % (time() - time_start) # Thread that calls math.factorial with a large number class factorial_thread(timed_thread): def run(self): factorial(50000) print "ft DONE:\t%f" % (time() - time_start) # the tests print print "sleep_thread test" time_start = time() st = sleep_thread(time_start) st.start() print "st.start:\t%f" % (time() - time_start) st.join(2) print "st.join:\t%f" % (time() - time_start) print "sleep alive:\t%r" % st.isAlive() print print "spin_thread test" time_start = time() sp = spin_thread(time_start) sp.start() print "sp.start:\t%f" % (time() - time_start) sp.join(2) print "sp.join:\t%f" % (time() - time_start) print "sp alive:\t%r" % sp.isAlive() print print "factorial_thread test" time_start = time() ft = factorial_thread(time_start) ft.start() print "ft.start:\t%f" % (time() - time_start) ft.join(2) print "ft.join:\t%f" % (time() - time_start) print "ft alive:\t%r" % ft.isAlive() And here is the output on Python 2.6.5 on CentOS x64: sleep_thread test st.start: 0.000675 st.join: 2.006963 sleep alive: True spin_thread test sp.start: 0.000595 sp.join: 2.010066 sp alive: True factorial_thread test ft DONE: 4.475453 ft.start: 4.475589 ft.join: 4.475615 ft alive: False st DONE: 10.994519 sp DONE: 12.054668 I've tried this on python 2.6.5 on CentOS x64, 2.7.2 on Windows x86 and the factorial thread does not return from start on either of them until the thread is done executing. I've also tried this with PyPy 1.8.0 on Windows x86, and there result is slightly different. The start does return immediately, but then the join doesn't time out! sleep_thread test st.start: 0.001000 st.join: 2.001000 sleep alive: True spin_thread test sp.start: 0.000000 sp DONE: 0.197000 sp.join: 0.236000 sp alive: False factorial_thread test ft.start: 0.032000 ft DONE: 9.011000 ft.join: 9.012000 ft alive: False st DONE: 12.763000

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  • Unallocated space with important data

    - by Chethan S.
    I used GParted to convert a primary partition to extended one after copying the data to another partition. After having the extended partition I moved the data back. To my utter shock after a restart I found out that the new extended partition did convert into "unallocated space". I tried installing testdisk. Testdisk could identify the partition as a primary partition and not the newly created extended partition. So what should I do now? I badly want the data back.

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  • Database Partitioning and Multiple Data Source Considerations

    - by Jeffrey McDaniel
    With the release of P6 Reporting Database 3.0 partitioning was added as a feature to help with performance and data management.  Careful investigation of requirements should be conducting prior to installation to help improve overall performance throughout the lifecycle of the data warehouse, preventing future maintenance that would result in data loss. Before installation try to determine how many data sources and partitions will be required along with the ranges.  In P6 Reporting Database 3.0 any adjustments outside of defaults must be made in the scripts and changes will require new ETL runs for each data source.  Considerations: 1. Standard Edition or Enterprise Edition of Oracle Database.   If you aren't using Oracle Enterprise Edition Database; the partitioning feature is not available. Multiple Data sources are only supported on Enterprise Edition of Oracle   Database. 2. Number of Data source Ids for partitioning during configuration.   This setting will specify how many partitions will be allocated for tables containing data source information.  This setting requires some evaluation prior to installation as       there are repercussions if you don't estimate correctly.   For example, if you configured the software for only 2 data sources and the partition setting was set to 2, however along came a 3rd data source.  The necessary steps to  accommodate this change are as follows: a) By default, 3 partitions are configured in the Reporting Database scripts. Edit the create_star_tables_part.sql script located in <installation directory>\star\scripts   and search for partition.  You’ll see P1, P2, P3.  Add additional partitions and sub-partitions for P4 and so on. These will appear in several areas.  (See P6 Reporting Database 3.0 Installation and Configuration guide for more information on this and how to adjust partition ranges). b) Run starETL -r.  This will recreate each table with the new partition key.  The effect of this step is that all tables data will be lost except for history related tables.   c) Run starETL for each of the 3 data sources (with the data source # (starETL.bat "-s2" -as defined in P6 Reporting Database 3.0 Installation and Configuration guide) The best strategy for this setting is to overestimate based on possible growth.  If during implementation it is deemed that there are atleast 2 data sources with possibility for growth, it is a better idea to set this setting to 4 or 5, allowing room for the future and preventing a ‘start over’ scenario. 3. The Number of Partitions and the Number of Months per Partitions are not specific to multi-data source.  These settings work in accordance to a sub partition of larger tables with regard to time related data.  These settings are dataset specific for optimization.  The number of months per partition is self explanatory, optimally the smaller the partition, the better query performance so if the dataset has an extremely large number of spread/history records, a lower number of months is optimal.  Working in accordance with this setting is the number of partitions, this will determine how many "buckets" will be created per the number of months setting.  For example, if you kept the default for # of partitions of 3, and select 2 months for each partitions you would end up with: -1st partition, 2 months -2nd partition, 2 months -3rd partition, all the remaining records Therefore with records to this setting, it is important to analyze your source db spread ranges and history settings when determining the proper number of months per partition and number of partitions to optimize performance.  Also be aware the DBA will need to monitor when these partition ranges will fill up and when additional partitions will need to be added.  If you get to the final range partition and there are no additional range partitions all data will be included into the last partition

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  • In setting up dual Boot with Windows XP and Ubuntu, which OS do I install first?

    - by markl
    I'd like to install both Ubuntu 12.04 and Windows XP on a Dell laptop, and I was thinking about using a dual boot structure, and using the bulk of my hard drive as empty hard drive space to share files between the two operating systems (so choice of file system type is very important in this set-up). The kind of partitioning structure I would like to use is Partition 1 - Ubuntu 12.04 (root) (20GB) Partition 2 - Ubuntu /home (20GB) Partition 3 : Free Space (560GB) Partition 4 : Windows XP (35GB) Partition 5 : SWAP (3GB) (Total Hardrive Capacity is ~640GB) My question is; what is the best way to go about setting up this kind this system? Should I install Windows XP first and setup the partitions, and then install Ubuntu which I believe will install the GRUB bootloader for OS booting choice or Do I install Ubuntu first, setting up the available partitions and then perform a WIndows install? Please let me know if there is anything in this setup that I have left out and should know about, including things related to setting particular partitions as logical or primary, and whether the boot partition and the filesystem partition should actually be two separate partitions.

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  • Is giving read permissions on /etc/shadow to apache user a wise decision from security point of view?

    - by Czar
    I have to use PAM authentication for DAV SVN, but when everything is configured as specified in mod_auth_pam documentation, authentication does not work. After some research I realized, that for this to work, httpd should be running under root user (which I don't like and won't implement) or apache user (under which httpd is running by default) should have permissions to read /etc/shadow file. So there is a pair of questions connected to each other which I want to ask: Is giving this permition to apache user a wise decision from security point of view? If answer to the first question is "yes", what is the correct way to do so? For now I've done following: groupadd shadow usermod -G shadow apache chmod g+r /etc/shadow Another way I can come up with is using acl: setfacl -m u:apache:r /etc/shadow Note: OS is Fedora 14 x86_64 (kernel: 2.6.35.11) httpd v2.2.17 mod_auth_pam v1.1.1

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  • problem with "select new Object ... join ... where"

    - by jacob
    Hi, I'm having a problem with an HQL query Three classes ClassOne is my BusinessObject public class ClassOne { private int id; private int status; private Set<ClassTwo> classTwos; + other fields/getters/setters/constructor etc } ClassTwo is referenced in a set of ClassOne and is kind of the history of an object of ClassOne public class ClassTwo { private int id; private int oldStatus; private int newStatus; private String message; //+ getters/setters/constructor etc } ClassThree is my DTO/VO with just one classTwo (not the whole history) public class ClassThree { private int id; private int status; private ClassTwo classTwo; public ClassThree(int pId, int pStatus, ClassTwo pClassTwo) { id=pId; status=pStatus; classTwo=pClassTwo; } //+ getters/setters etc } Now I'd like to create an HQL query like this: I'd like to get all objects of ClassThree with a certain status and if it exists the newest ClassTwo with a certain newStatus. For example: I'd like to get all the DTOs (ClassThree) of ClassOne whose status is now 1, but earlier in their history it has been 2 and I'd like to have the latest ClassTwo object which has 2 as newStatus. SELECT new ClassThree(c1.id, c1.status, c2) FROM ClassOne c1 LEFT JOIN c1.classtwos c2 (...) and (...) is where I don't know what to do, I'm not even sure if it's a join / join fetch Looked around and tried quite a lot already, but no clue. Especially with the join fetch I get some Hibernate errors like org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list. Fetching the BusinessObject like that is no problem SELECT distinct(c1) FROM ClassOne c1 LEFT OUTER JOIN FETCH c1.classtwos c2 and I get the ClassTwos as my field. Thanks in advance, Jacob P.S.: One thing might be important, ClassTwo has no reference to ClassOne!!

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