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  • Are has collisions with different file sizes just as likely as same file size?

    - by rwmnau
    I'm hashing a large number of files, and to avoid hash collisions, I'm also storing a file's original size - that way, even if there's a hash collision, it's extrememly unlikely that the file sizes will also be identical. Is this sound (a hash collision is equally likely to be of any size), or do I need another piece of information (if a collision is more likely to also be the same length as the original). Or, more generally: Is every file just as likely to produce a particular hash, regardless of original file size?

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  • Directory file size calculation - how to make it faster?

    - by Xinxua
    Using C#, I am finding the total size of a directory. The logic is this way : Get the files inside the folder. Sum up the total size. Find if there are sub directories. Then do a recursive search. I tried one another way to do this too : Using FSO (obj.GetFolder(path).Size). There's not much of difference in time in both these approaches. Now the problem is, I have tens of thousands of files in a particular folder and its taking like atleast 2 minute to find the folder size. Also, if I run the program again, it happens very quickly (5 secs). I think the windows is caching the file sizes. Is there any way I can bring down the time taken when I run the program first time??

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  • Struct size containing vector<T> different sizes between DLL and EXE..

    - by Michael Peddicord
    I have this situation where an EXE program imports a DLL for a single function call. It works by passing in a custom structure and returning a different custom structure. Up till now it's worked fine until I wanted one of the structs data members to be a vector < MyStruct When I do a sizeof(vector< MyStruct ) in my program I get a size of 20 but when I do it from inside the DLL I get a size of 24. This size inconsistency is causing a ESP pointer error. Can anyone tell me why a Vector < MyStruct would be a different size in the DLL than in the program? I have reverified that my structs in both the DLL and the Program are identical. I would appreciate any help on the subject. Thank you.

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  • How to double the size of 8x8 Grid whilst keeping the relative position of certain tiles intact?

    - by ke3pup
    Hi guys I have grid size of size 8x8 , total of 64 Tiles. i'm using this Grid to implement java search algorithms such as BFS and DFS. The Grid has given forbidden Tiles (meaning they can't be traversed or be neighbour of any other tile) and Goal and Start tile. for example Tile 19,20,21,22 and 35, 39 are forbidden and 14 an 43 are the Goal and start node when the program runs. My question is , How can i double the size of the grid, to 16x16 whilst keeping the Relative position of forbidden tiles as well as the Relative position of start and goal Tiles intact? On paper i know i can do this by adding 4 rows and columns to all size but in coding terms i don't know how to make it work? Can someone please give any sort of hints?

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  • How to get size of file uploaded to SQL-Server?

    - by MadBoy
    Is there a way to tell how to get a file size that is uploaded to database? SELECT [ID] ,[File] FROM [dbo].[Reports] I would like to be able to tell user the size of File which is VarBinary(max) field in MS SQL 2005/2008. How to do that? Maybe the only way to do is to create another column and when inserting file i should also insert it's size in additional column?

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  • How to obtain the correct physical size of the monitor?

    - by KindDragon
    How can I get the size of the display in centimeters or inches? This code does not always works correctly: HDC hdc = CreateDC(_T("DISPLAY"),dd.DeviceName,NULL,NULL); int width = GetDeviceCaps(hdc, HORZSIZE); int height = GetDeviceCaps(hdc, VERTSIZE); ReleaseDC(0, hdc) Especially for multi-monitor configuration. Update: I need to get the size just for ordinary monitors, which have a constant physical size.

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  • How to get size of file in visual c++?

    - by karikari
    Below is my code. My problem is, my destination file always has a lot more strings than the originating file. Then, inside the for loop, instead of using i < sizeof more, I realized that I should use i < sizeof file2 . Now my problem is, how to get the size of file2? int i = 0; FILE *file2 = fopen(LOG_FILE_NAME,"r"); wfstream file3 (myfile, ios_base::out); // char more[1024]; char more[SIZE-OF-file2]; for(i = 0; i < SIZE-OF-file2 ; i++) { fgets(more, SIZE-OF-file2, file2); file3 << more; } fclose(file2); file3.close();

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  • Regular Expression to get the size value of a CSS property?

    - by thiesdiggity
    I wrote a regular expression to get the size from a CSS property: /(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i but for some reason its not working as intended. For example, when I run the following: preg_match_all('/(([+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i', "border-bottom:1px solid #99999;", $matches); It outputs: 1px 99999; But I only want the 1px value returned. I understand why its returning the above but can't seem to figure out how to only return the size and not the color value. I tried using the following negative lookbehind but it's not working either: /(((?<!#\d{3}|#\d{6})[+-]?\d*\.?\d+(\s)*(px|em|ex|pt|in|pc|mm|cm)?)|thin|medium|thick)(\s|;|$)/i I want to use preg_match_all for those CSS properties that can have multiple size values (i.e. margin). Anyone have any ideas how to get this regex to return only the size values? Thanks for your help!

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  • Need data on disk drive management by OS: getting base I/O unit size, “sync” option, Direct Memory A

    - by Richard T
    Hello All, I want to ensure I have done all I can to configure a system's disks for serious database use. The three areas I know of (any others?) to be concerned about are: I/O size: the database engine and disk's native size should either match, or the database's native I/O size should be a multiple of the disk's native I/O size. Disks that are capable of Direct Memory Access (eg. IDE) should be configured for it. When a disk says it has written data persistently, it must be so! No keeping it in cache and lying about it. I have been looking for information on how to ensure these are so for CENTOS and Ubuntu, but can't seem to find anything at all! I want to be able to check these things and change them if needed. Any and all input appreciated.

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  • Screen Casting using ffmpeg (too fast)

    - by rowman
    I can use ffmpeg to make screen casts: ffmpeg -f x11grab -s 1280x800 -i :0.0 -c:v libx264 -framerate 30 -r 30 -crf 18 out.mkv However the output comes out to be too fast paced. It also happens with GTK RecordMyDesktop if I enable the encode on the fly. So, the questions is how to get a normal video pace. Also in order to capture the sound with ffmpeg what option should be used? FFmpeg Output: ffmpeg -f x11grab -s 1280x800 -r 30 -i :0.0 -c:v libx264 -framerate 30 -r 30 -crf 18 out.mkv ffmpeg version N-35162-g87244c8 Copyright (c) 2000-2012 the FFmpeg developers built on Oct 7 2012 15:56:19 with gcc 4.6 (Ubuntu/Linaro 4.6.3-1ubuntu5) configuration: --enable-gpl --enable-libfaac --enable-libfdk-aac --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-librtmp --enable-libtheora --enable-libvorbis --enable-libvpx --enable-x11grab --enable-libx264 --enable-nonfree --enable-version3 libavutil 51. 73.102 / 51. 73.102 libavcodec 54. 64.100 / 54. 64.100 libavformat 54. 29.105 / 54. 29.105 libavdevice 54. 3.100 / 54. 3.100 libavfilter 3. 19.102 / 3. 19.102 libswscale 2. 1.101 / 2. 1.101 libswresample 0. 16.100 / 0. 16.100 libpostproc 52. 1.100 / 52. 1.100 [x11grab @ 0xab896a0] device: :0.0 -> display: :0.0 x: 0 y: 0 width: 1280 height: 800 [x11grab @ 0xab896a0] shared memory extension found [x11grab @ 0xab896a0] Estimating duration from bitrate, this may be inaccurate Input #0, x11grab, from ':0.0': Duration: N/A, start: 1350136942.608988, bitrate: 983040 kb/s Stream #0:0: Video: rawvideo (BGR[0] / 0x524742), bgr0, 1280x800, 983040 kb/s, 30 tbr, 1000k tbn, 30 tbc [libx264 @ 0xab87320] using cpu capabilities: MMX2 SSE2Fast SSSE3 Cache64 SlowCTZ SlowAtom [libx264 @ 0xab87320] profile High 4:4:4 Predictive, level 3.2, 4:4:4 8-bit [libx264 @ 0xab87320] 264 - core 128 r2 198a7ea - H.264/MPEG-4 AVC codec - Copyleft 2003-2012 - http://www.videolan.org/x264.html - options: cabac=1 ref=3 deblock=1:0:0 analyse=0x3:0x113 me=hex subme=7 psy=1 psy_rd=1.00:0.00 mixed_ref=1 me_range=16 chroma_me=1 trellis=1 8x8dct=1 cqm=0 deadzone=21,11 fast_pskip=1 chroma_qp_offset=4 threads=6 lookahead_threads=1 sliced_threads=0 nr=0 decimate=1 interlaced=0 bluray_compat=0 constrained_intra=0 bframes=3 b_pyramid=2 b_adapt=1 b_bias=0 direct=1 weightb=1 open_gop=0 weightp=2 keyint=250 keyint_min=25 scenecut=40 intra_refresh=0 rc_lookahead=40 rc=crf mbtree=1 crf=18.0 qcomp=0.60 qpmin=0 qpmax=69 qpstep=4 ip_ratio=1.40 aq=1:1.00 Output #0, matroska, to 'out.mkv': Metadata: encoder : Lavf54.29.105 Stream #0:0: Video: h264, yuv444p, 1280x800, q=-1--1, 1k tbn, 30 tbc Stream mapping: Stream #0:0 -> #0:0 (rawvideo -> libx264) Press [q] to stop, [?] for help frame= 10 fps=0.0 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 19 fps= 17 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 28 fps= 17 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 37 fps= 17 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 45 fps= 16 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 47 fps= 14 q=0.0 size= 1kB time=00:00:00.00 bitrate= 0.0kbits/sframe= 52 fps= 13 q=24.0 size= 257kB time=00:00:00.00 bitrate=2101632.0kbiframe= 55 fps= 12 q=24.0 size= 257kB time=00:00:00.10 bitrate=20808.2kbitsframe= 59 fps= 11 q=24.0 size= 289kB time=00:00:00.23 bitrate=10145.0kbitsframe= 64 fps= 11 q=24.0 size= 289kB time=00:00:00.40 bitrate=5894.7kbits/frame= 70 fps= 11 q=24.0 size= 289kB time=00:00:00.60 bitrate=3933.1kbits/frame= 72 fps= 10 q=24.0 size= 289kB time=00:00:00.66 bitrate=3549.2kbits/frame= 77 fps=9.8 q=24.0 size= 289kB time=00:00:00.83 bitrate=2837.7kbits/frame= 80 fps=9.6 q=24.0 size= 289kB time=00:00:00.93 bitrate=2533.5kbits/frame= 85 fps=9.3 q=24.0 size= 289kB time=00:00:01.10 bitrate=2146.9kbits/frame= 89 fps=9.3 q=24.0 size= 289kB time=00:00:01.23 bitrate=1917.1kbits/frame= 92 fps=9.1 q=24.0 size= 289kB time=00:00:01.33 bitrate=1773.3kbits/frame= 96 fps=9.0 q=24.0 size= 289kB time=00:00:01.46 bitrate=1612.4kbits/frame= 99 fps=8.8 q=24.0 size= 321kB time=00:00:01.56 bitrate=1676.8kbits/frame= 104 fps=8.7 q=24.0 size= 321kB time=00:00:01.73 bitrate=1515.2kbits/frame= 109 fps=5.3 q=24.0 Lsize= 1093kB time=00:00:03.56 bitrate=2511.5kbits/s video:1092kB audio:0kB subtitle:0 global headers:0kB muxing overhead 0.120198% [libx264 @ 0xab87320] frame I:3 Avg QP:18.93 size:142610 [libx264 @ 0xab87320] frame P:43 Avg QP:20.79 size: 15751 [libx264 @ 0xab87320] frame B:63 Avg QP:23.75 size: 195 [libx264 @ 0xab87320] consecutive B-frames: 21.1% 1.8% 11.0% 66.1% [libx264 @ 0xab87320] mb I I16..4: 50.0% 21.1% 28.9% [libx264 @ 0xab87320] mb P I16..4: 6.1% 0.9% 3.2% P16..4: 5.5% 1.2% 0.6% 0.0% 0.0% skip:82.5% [libx264 @ 0xab87320] mb B I16..4: 0.4% 0.1% 0.0% B16..8: 2.9% 0.1% 0.0% direct: 0.0% skip:96.5% L0:40.7% L1:57.0% BI: 2.3% [libx264 @ 0xab87320] 8x8 transform intra:14.5% inter:46.1% [libx264 @ 0xab87320] coded y,u,v intra: 33.5% 24.1% 25.4% inter: 0.9% 0.4% 0.4% [libx264 @ 0xab87320] i16 v,h,dc,p: 70% 26% 1% 3% [libx264 @ 0xab87320] i8 v,h,dc,ddl,ddr,vr,hd,vl,hu: 11% 21% 30% 5% 7% 5% 7% 4% 10% [libx264 @ 0xab87320] i4 v,h,dc,ddl,ddr,vr,hd,vl,hu: 32% 35% 12% 2% 4% 3% 4% 3% 5% [libx264 @ 0xab87320] Weighted P-Frames: Y:0.0% UV:0.0% [libx264 @ 0xab87320] ref P L0: 57.0% 5.6% 26.8% 10.6% [libx264 @ 0xab87320] ref B L0: 69.4% 22.6% 8.0% [libx264 @ 0xab87320] ref B L1: 93.7% 6.3% [libx264 @ 0xab87320] kb/s:2460.40

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  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

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  • What effect does RAID stripe size have on read-ahead settings?

    - by stbrody
    I'm trying to figure out the correct read-ahead values to set on a RAID10 array, and I'm wondering if the RAID stripe size should factor into my considerations. I've heard conflicting information about this in the past. I once heard that you should always set your read-ahead value to a multiple of the RAID stripe size, and never below the stripe size, because that is the minimum amount of data the RAID controller will ever try to read at once. Someone else told me, however, that setting read-ahead below the stripe size is fine, and can, in fact, increase the amount of parallel reads you can do across devices in the array, increasing performance and decreasing load on the array. So which is it? Do read-ahead settings that aren't multiples of the stripe size make sense or not?

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  • Difference between tcp recv buffer and tcp receive window size?

    - by pradeepchhetri
    The command shows the tcp receive buffer size in bytes. $ cat /proc/sys/net/ipv4/tcp_rmem 4096 87380 4001344 where the three values signifies the min, default and max values respectively. Then I tried to find the tcp window size using tcpdump command. $ sudo tcpdump -n -i eth0 'tcp[tcpflags] & (tcp-syn|tcp-ack) == tcp-syn and port 80 and host google.com' tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on eth0, link-type EN10MB (Ethernet), capture size 65535 bytes 16:15:41.465037 IP 172.16.31.141.51614 > 74.125.236.73.80: Flags [S], seq 3661804272, win 14600, options [mss 1460,sackOK,TS val 4452053 ecr 0,nop,wscale 6], length 0 I got the window size to be 14600 which is 10 times the size of MSS. Can anyone please tell me the relationship between the two.

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  • How is the MTU is 65535 in UDP but ethernet does not allow frame size more than 1500 bytes

    - by nikku
    I am using a fast ethernet of 100 Mbps, whose frame size is less than 1500 bytes (1472 bytes for payload as per my textbook). In that, I was able to send and receive a UDP packet of message size 65507 bytes, which means the packet size was 65507 + 20 (IP Header) + 8 (UDP Header) = 65535. If the frame's payload size itself is maximum of 1472 bytes (as per my textbook), how can the packet size of IP be greater than that which here is 65535? I used sender code as char buffer[100000]; for (int i = 1; i < 100000; i++) { int len = send (socket_id, buffer, i); printf("%d\n", len); } Receiver code as while (len = recv (socket_id, buffer, 100000)) { printf("%d\n". len); } I observed that send returns -1 on i > 65507 and recv prints or receives a packet of maximum of length 65507.

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  • Why does Farseer 2.x store temporaries as members and not on the stack? (.NET)

    - by Andrew Russell
    UPDATE: This question refers to Farseer 2.x. The newer 3.x doesn't seem to do this. I'm using Farseer Physics Engine quite extensively at the moment, and I've noticed that it seems to store a lot of temporary value types as members of the class, and not on the stack as one might expect. Here is an example from the Body class: private Vector2 _worldPositionTemp = Vector2.Zero; private Matrix _bodyMatrixTemp = Matrix.Identity; private Matrix _rotationMatrixTemp = Matrix.Identity; private Matrix _translationMatrixTemp = Matrix.Identity; public void GetBodyMatrix(out Matrix bodyMatrix) { Matrix.CreateTranslation(position.X, position.Y, 0, out _translationMatrixTemp); Matrix.CreateRotationZ(rotation, out _rotationMatrixTemp); Matrix.Multiply(ref _rotationMatrixTemp, ref _translationMatrixTemp, out bodyMatrix); } public Vector2 GetWorldPosition(Vector2 localPosition) { GetBodyMatrix(out _bodyMatrixTemp); Vector2.Transform(ref localPosition, ref _bodyMatrixTemp, out _worldPositionTemp); return _worldPositionTemp; } It looks like its a by-hand performance optimisation. But I don't see how this could possibly help performance? (If anything I think it would hurt by making objects much larger).

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  • Are local variables in Fortran 77 static or stack dynamic?

    - by mm2887
    For my programming languages class one hw problem asks: Are local variables in FORTRAN static or stack dynamic? Are local variables that are INITIALIZED to a default value static or stack dynamic? Show me some code with an explanation to back up your answer. Hint: The easiest way to check this is to have your program test the history sensitivity of a subprogram. Look at what happens when you initialize the local variable to a value and when you don’t. You may need to call more than one subprogram to lock in your answer with confidence. I wrote a few subroutines: - create a variable - print the variable - initialize the variable to a value - print the variable again Each successive call to the subroutine prints out the same random value for the variable when it is uninitialized and then it prints out the initialized value. What is this random value when the variable is uninitialized? Does this mean Fortran uses the same memory location for each call to the subroutine or it dynamically creates space and initializes the variable randomly? My second subroutine also creates a variable, but then calls the first subroutine. The result is the same except the random number printed of the uninitialized variable is different. I am very confused. Please help! Thank you so much.

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