I asked this yesterday, after the input given I'm still having trouble implementing..
- by Josh
I'm not sure how to fix this or what I did wrong, but whenever I enter in a value it just closes out the run prompt.
So, seems I do have a problem somewhere in my coding. Whenever I run the program and input a variable, it always returns the same answer.."The content at location 76 is 0."
On that note, someone told me that "I don't know, but I suspect that Program A incorrectly has a fixed address being branched to on instructions 10 and 11." - mctylr but I'm not sure how to fix that..
I'm trying to figure out how to incorporate this idea from R Samuel Klatchko.. I'm still not sure what I'm missing but I can't get it to work..
const int OP_LOAD = 3;
const int OP_STORE = 4;
const int OP_ADD = 5;
...
const int OP_LOCATION_MULTIPLIER = 100;
mem[0] = OP_LOAD * OP_LOCATION_MULTIPLIER + ...;
mem[1] = OP_ADD * OP_LOCATION_MULTIPLIER + ...;
operand = memory[ j ] % OP_LOCATION_MULTIPLIER;
operation = memory[ j ] / OP_LOCATION_MULTIPLIER;
I'm new to programming, I'm not the best, so I'm going for simplicity. Also this is an SML program. Anyway, this IS a homework assignment and I'm wanting a good grade on this. So I was looking for input and making sure this program will do what I'm hoping they are looking for. Anyway, here are the instructions: Write SML (Simpletron Machine language) programs to accomplish each of the following task:
A) Use a sentinel-controlled loop to read positive number s and compute and print their sum. Terminate input when a neg number is entered.
B) Use a counter-controlled loop to read seven numbers, some positive and some negative, and compute + print the avg.
C) Read a series of numbers, and determine and print the largest number. The first number read indicates how many numbers should be processed.
Without further a due, here is my program. All together.
int main()
{
const int READ = 10;
const int WRITE = 11;
const int LOAD = 20;
const int STORE = 21;
const int ADD = 30;
const int SUBTRACT = 31;
const int DIVIDE = 32;
const int MULTIPLY = 33;
const int BRANCH = 40;
const int BRANCHNEG = 41;
const int BRANCHZERO = 41;
const int HALT = 43;
int mem[100] = {0}; //Making it 100, since simpletron contains a 100 word mem.
int operation; //taking the rest of these variables straight out of the book seeing as how they were italisized.
int operand;
int accum = 0; // the special register is starting at 0
int j;
// This is for part a, it will take in positive variables in a sent-controlled loop and compute + print their sum. Variables from example in text.
memory [0] = 1010;
memory [01] = 2009;
memory [02] = 3008;
memory [03] = 2109;
memory [04] = 1109;
memory [05] = 4300;
memory [06] = 1009;
j = 0; //Makes the variable j start at 0.
while ( true )
{
operand = memory[ j ]%100; // Finds the op codes from the limit on the memory (100)
operation = memory[ j ]/100;
//using a switch loop to set up the loops for the cases
switch ( operation ){
case 10: //reads a variable into a word from loc. Enter in -1 to exit
cout <<"\n Input a positive variable: ";
cin >> memory[ operand ]; break;
case 11: // takes a word from location
cout << "\n\nThe content at location " << operand << "is " << memory[operand]; break;
case 20:// loads
accum = memory[ operand ]; break;
case 21: //stores
memory[ operand ] = accum; break;
case 30: //adds
accum += mem[operand]; break;
case 31: // subtracts
accum-= memory[ operand ]; break;
case 32: //divides
accum /=(memory[ operand ]); break;
case 33: // multiplies
accum*= memory [ operand ]; break;
case 40: // Branches to location
j = -1; break;
case 41: //branches if acc. is < 0
if (accum < 0)
j = 5;
break;
case 42: //branches if acc = 0
if (accum == 0)
j = 5;
break;
case 43: // Program ends
exit(0); break;
}
j++;
}
return 0;
}
