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  • Restructuting XML Data

    - by Frank
    Hi! The following is an excerpt of my XML data source: <file> <ALL_INSTANCES> <instance> <ID>1</ID> <start>5.8633333333</start> <end>29.8216666667</end> <code>Player 1</code> </instance> <instance> <ID>2</ID> <start>28.4566666667</start> <end>51.1450000000</end> <code>Player 2</code> </instance> <instance> <ID>3</ID> <start>49.8383333333</start> <end>71.1150000000</end> <code>Player 3</code> </instance> <instance> <ID>4</ID> <start>72.9850000000</start> <end>95.3766666667</end> <code>Speler 1</code> </instance> </ALL_INSTANCES> I'm looking to restructure this data into something like this: <Player 1> <ID>1</ID> <start>5.8633333333</start> <end>29.8216666667</end> </Player 1> <Player 1> <ID>4</ID> <start>72.9850000000</start> <end>95.3766666667</end> </Player 1> <Player 2> <ID>2</ID> <start>28.4566666667</start> <end>51.1450000000</end> </Player 2> <Player 3> <ID>3</ID> <start>49.8383333333</start> <end>71.1150000000</end> </Player 3> Could anyone please help me to achieve this? Much appreciated! Cheers, Frank

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  • Configuring web.xml for webservices and servlet.

    - by Win Man
    Hi, I am new to Restlets. Trying to configure the web.xml (on JBoss). I have 2 entries, one for a servlet (got nothing to do with webservices) other for webservices, using Restlet. Here are the entries.. <servlet> <servlet-name>AuthenticationServlet</servlet-name> <servlet-class>com.safeid.web.server.api.servlet.AuthenticationServlet</servlet-class> <load-on-startup>2</load-on-startup> </servlet> <servlet-mapping> <servlet-name>AuthenticationServlet</servlet-name> <url-pattern>/authenticate/*</url-pattern> </servlet-mapping> <!-- Start of Entries for the REST Web Services. --> <context-param> <param-name>org.restlet.application</param-name> <param-value>com.safeid.web.server.SafeIDRouterApplication</param-value> </context-param> <servlet> <servlet-name>RestletServlet</servlet-name> <servlet-class>com.noelios.restlet.ext.servlet.ServerServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>RestletServlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> <!-- END of Entries for the REST Web Services.--> Both don't work together. In the above setup the Restlet works. However when I change the RestletServlet /* to something like <servlet-mapping> <servlet-name>RestletServlet</servlet-name> <url-pattern>/credential/*</url-pattern> </servlet-mapping> the Restlet stop working and the AuthenticationServlet works fine. What am I missing here?

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  • XML Schema for a .NET type that inherits and implements

    - by John Ruiz
    Hi, Please consider the following three .NET types: I have an interface, an abstract class, and a concrete class. My question is how to write the XML Schema to include the properties from the interface and from the abstract class. public interface IStartable { bool RequiresKey { get; set; } void Start(object key); } public abstract class Vehicle { uint WheelCount { get; set; } } public class Car : Vehicle, IStartable { public bool RequiresKey { get; set; } public string Make { get; set; } publilc string Model { get; set; } public Car() {} public void Start(object key) { // start car with key } } I don't know how to complete this schema: <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" targetNamespace="cars" xmlns="cars" xmlns:c="cars"> <!-- How do I get car to have vehicle's wheelcount AND IStartable's RequiresKey? --> <xs:element name="Car" type="c:Car" /> <xs:complexType name="Car"> <xs:complexContent> <xs:extension base="c:Vehicle"> <xs:group ref=c:CarGroup" /> </xs:extension> </xs:complexContent> </xs:complexType> <xs:group name="CarGroup"> <xs:sequence> <xs:element name="Make" type="xs:token" /> <xs:element name="Model" type="xs:token" /> </xs:sequence> </xs:group> <xs:complexType name="Vehicle"> <xs:sequence> <xs:element name="WheelCount" type="xs:unsignedInt" /> </xs:sequence> </xs:complexType> <xs:complexType name="IStartable"> <xs:sequence> <xs:element name="RequiresKey" type="xs:boolean" /> </xs:sequence> </xs:complexType> </xs:schema>

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  • Save/Load jFreechart TimeSeriesCollection chart from XML

    - by IMAnis_tn
    I'm working with this exemple wich put rondom dynamic data into a TimeSeriesCollection chart. My problem is that i can't find how to : 1- Make a track of the old data (of the last hour) when they pass the left boundary (because the data point move from the right to the left ) of the view area just by implementing a horizontal scroll bar. 2- Is XML a good choice to save my data into when i want to have all the history of the data? public class DynamicDataDemo extends ApplicationFrame { /** The time series data. */ private TimeSeries series; /** The most recent value added. */ private double lastValue = 100.0; public DynamicDataDemo(final String title) { super(title); this.series = new TimeSeries("Random Data", Millisecond.class); final TimeSeriesCollection dataset = new TimeSeriesCollection(this.series); final JFreeChart chart = createChart(dataset); final ChartPanel chartPanel = new ChartPanel(chart); final JPanel content = new JPanel(new BorderLayout()); content.add(chartPanel); chartPanel.setPreferredSize(new java.awt.Dimension(500, 270)); setContentPane(content); } private JFreeChart createChart(final XYDataset dataset) { final JFreeChart result = ChartFactory.createTimeSeriesChart( "Dynamic Data Demo", "Time", "Value", dataset, true, true, false ); final XYPlot plot = result.getXYPlot(); ValueAxis axis = plot.getDomainAxis(); axis.setAutoRange(true); axis.setFixedAutoRange(60000.0); // 60 seconds axis = plot.getRangeAxis(); axis.setRange(0.0, 200.0); return result; } public void go() { final double factor = 0.90 + 0.2 * Math.random(); this.lastValue = this.lastValue * factor; final Millisecond now = new Millisecond(); System.out.println("Now = " + now.toString()); this.series.add(new Millisecond(), this.lastValue); } public static void main(final String[] args) throws InterruptedException { final DynamicDataDemo demo = new DynamicDataDemo("Dynamic Data Demo"); demo.pack(); RefineryUtilities.centerFrameOnScreen(demo); demo.setVisible(true); while(true){ demo.go(); Thread.currentThread().sleep(1000); } } }

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  • setting up subreport in ireport using XML datasource

    - by shyam
    can anyone explain in detail(if possible with screen shorts) how to add subreport (one to many relation) this being the xml data source <addressbook> <category name="home"> <person id="1"> <LASTNAME>Davolio</LASTNAME> <FIRSTNAME>Nancy</FIRSTNAME> <hobbies> <hobby>Radio Control</hobby> <hobby>R/C Cars</hobby> <hobby>Micro R/C Cars</hobby> <hobby>Die-Cast Models</hobby> </hobbies> <email>[email protected]</email> <email>[email protected]</email> </person> <person id="2"> <LASTNAME>Fuller</LASTNAME> <FIRSTNAME>Andrew</FIRSTNAME> <email>[email protected]</email> <email>[email protected]</email> </person> <person id="3"> <LASTNAME>Leverling</LASTNAME> <FIRSTNAME>Janet</FIRSTNAME> <hobbies> <hobby>Rockets</hobby> <hobby>Puzzles</hobby> <hobby>Science Hobby</hobby> <hobby>Toy Horse</hobby> </hobbies> <email>[email protected]</email> <email>[email protected]</email> </person> </category> <category name="work"> <person id="4"> <LASTNAME>Peacock</LASTNAME> <FIRSTNAME>Margaret</FIRSTNAME> <hobbies> <hobby>Toy Horse</hobby> </hobbies> <email>[email protected]</email> </person> <person id="5"> <LASTNAME>Buchanan</LASTNAME> <FIRSTNAME>Steven</FIRSTNAME> <hobbies> </hobbies> <email>[email protected]</email> </person> <person id="6"> <LASTNAME>Suyama</LASTNAME> <FIRSTNAME>Michael</FIRSTNAME> </person> <person id="7"> <LASTNAME>King</LASTNAME> <FIRSTNAME>Robert</FIRSTNAME> </person> </category> <category name="Other"> <person id="8"> <LASTNAME>Callahan</LASTNAME> <FIRSTNAME>Laura</FIRSTNAME> <email>[email protected]</email> </person> <person id="9"> <LASTNAME>Dodsworth</LASTNAME> <email>[email protected]</email> </person> </category> </addressbook>

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  • Script to reformat XML file

    - by JonS
    Hello all, I am trying to change an XML file from one format to another and have no clue as to how to write a script for it. Can someone help, please? The source file looks like this: <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_100_1_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_100_1_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.037E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_24_108_0_000_0" fieldValueIsNull="false" fieldValueNatural="r_24_108_0_000_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> <Record> <FieldValue fieldName="rapportage_nihil" fieldValue="false" fieldValueIsNull="false" fieldValueNatural="false"/> <FieldValue fieldName="periode" fieldValue="2009-23-31" fieldValueIsNull="false" fieldValueNatural="2009-10-31 00:23:23"/> <FieldValue fieldName="formulierid" fieldValue="9001HK1V10" fieldValueIsNull="false" fieldValueNatural="9001HK1V10"/> <FieldValue fieldName="versie" fieldValue="1" fieldValueIsNull="false" fieldValueNatural="1"/> <FieldValue fieldName="frequentie" fieldValue="M" fieldValueIsNull="false" fieldValueNatural="M"/> <FieldValue fieldName="variant_type" fieldValue="Landen" fieldValueIsNull="false" fieldValueNatural="Landen"/> <FieldValue fieldName="value" fieldValue="5F" fieldValueIsNull="false" fieldValueNatural="5F"/> <FieldValue fieldName="post_value" fieldValue="0.00" fieldValueIsNull="false" fieldValueNatural="1.6049E-4"/> <FieldValue fieldName="cube" fieldValue="c01" fieldValueIsNull="false" fieldValueNatural="c01"/> <FieldValue fieldName="rij" fieldValue="r_06_000_1_010_0" fieldValueIsNull="false" fieldValueNatural="r_06_000_1_010_0"/> <FieldValue fieldName="kolom" fieldValue="c_2250_SPU" fieldValueIsNull="false" fieldValueNatural="c_2250_SPU"/> </Record> This is the format that I need as a result: <bestand registratienummer="123"> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_100_1_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_24_108_0_000_0" kolom="c_2250_SPU" /> </rapportage> <rapportage nihil="false" periode="2009-23-31" formulierid="9001HK1V10" versie="1" frequentie="M"> <variant type="Landen" value="5F" /> <post value="0.00" cube="c01" rij="r_06_000_1_010_0" kolom="c_2250_SPU" /> </rapportage> </bestand> Thanks very much!

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  • C# - Parse HTML source as XML

    - by fonix232
    I would like to read in a dynamic URL what contains a HTML file, and read it like an XML file, based on nodes (HTML tags). Is this somehow possible? I mean, there is this HTML code: <table class="bidders" cellpadding="0" cellspacing="0"> <tr class="bidRow4"> <td>kucik (automata)</td> <td class="right">9 374 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow4"> <td>macszaf (automata)</td> <td class="right">9 373 Ft</td> <td class="bidders_date">2010-06-10 18:19:52</td> </tr> <tr class="bidRow2"> <td>kucik (automata)</td> <td class="right">9 372 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow2"> <td>macszaf (automata)</td> <td class="right">9 371 Ft</td> <td class="bidders_date">2010-06-10 18:19:42</td> </tr> <tr class="bidRow0"> <td>kucik (automata)</td> <td class="right">9 370 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow0"> <td>macszaf (automata)</td> <td class="right">9 369 Ft</td> <td class="bidders_date">2010-06-10 18:19:32</td> </tr> <tr class="bidRow8"> <td>kucik (automata)</td> <td class="right">9 368 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow8"> <td>macszaf (automata)</td> <td class="right">9 367 Ft</td> <td class="bidders_date">2010-06-10 18:19:22</td> </tr> <tr class="bidRow6"> <td>kucik (automata)</td> <td class="right">9 366 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> <tr class="bidRow6"> <td>macszaf (automata)</td> <td class="right">9 365 Ft</td> <td class="bidders_date">2010-06-10 18:19:12</td> </tr> </table> I want to parse this into a ListView (or a Grid) to create rows with the data contained. All tr are different row, and all td in a given td is a column in the given row. And also I want it to be as fast as possible, as it would update itself in 5 seconds. Is there any library for this?

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  • How to Generate XML from Database

    - by Nisarg Mehta
    Hi , I am fetching data from two tables CARRIER_IFTA ,IFTA_NAME. My Select Query is like below.. SELECT t1.IFTA_LICENSE_NUMBER,t1.IFTA_BASE_STATE,t2.NAME_TYPE,t2.NAME from CARRIER_IFTA t1 inner join IFTA_NAME t2 on t1.IFTA_LICENSE_NUMBER=t2.IFTA_LICENSE_NUMBER My Data is coming in this way... IFTA_LICENSE_NUMBER IFTA_BASE_STATE NAME_TYPE NAME -------------------------------------------------------- 630908333 US LG XYZ 630908333 US MG PQR 730908344 US LG ABC Now using XSLT I want to generate XML like this <T0019> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>630908333</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>XYZ</NAME> </IFTA_NAME> <IFTA_NAME> <NAME_TYPE>MG<NAME_TYPE> <NAME>PQR</NAME> <IFTA_NAME> </IFTA_ACCOUNT> <IFTA_ACCOUNT> <IFTA_LICENSE_NUMBER>730908344</IFTA_LICENSE_NUMBER> <IFTA_BASE_STATE>US</IFTA_BASE_STATE> <IFTA_NAME> <NAME_TYPE>LG<NAME_TYPE> <NAME>ABC</NAME> </IFTA_NAME> </IFTA_ACCOUNT> </T0019> i have used below xslt but it is not giveng me desire result ... <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="/ROWSET"> <xsl:element name="T0019"> <xsl:apply-templates select="IFTAACCOUNT"/> </xsl:element> </xsl:template> <xsl:template match="IFTAACCOUNT"> <xsl:element name="IFTAACCOUNT"> <xsl:apply-templates select="IFTA_CARRIER_ID_NUMBER"/> </xsl:element> </xsl:template> <xsl:template match="IFTA_LICENSE_NUMBER"> <xsl:element name="IFTA_LICENSE_NUMBER"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IFTA_BASE_STATE"> <xsl:element name="IFTA_BASE_STATE"> <xsl:apply-templates /> </xsl:element> </xsl:template> <xsl:template match="IRP_NAME"> <IRP_NAME> <xsl:apply-templates select="NAME"/> <xsl:apply-templates select="NAME_TYPE"/> </IRP_NAME> </xsl:template> <xsl:template match="NAME"> <xsl:element name="NAME"> <xsl:value-of select="." /> </xsl:element> </xsl:template> <xsl:template match="NAME_TYPE"> <xsl:element name="NAME_TYPE"> <xsl:apply-templates /> </xsl:element> </xsl:template> </xsl:stylesheet> but it is not giving desire result ... Please help me ... Thanks in Advance...

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  • XML and XSD - use element name as replacement of xsi:type for polymorphism

    - by disown
    Taking the W3C vehicle XSD as an example: <schema xmlns="http://www.w3.org/2001/XMLSchema" targetNamespace="http://cars.example.com/schema" xmlns:target="http://cars.example.com/schema"> <complexType name="Vehicle" abstract="true"/> <complexType name="Car"> <complexContent> <extension base="target:Vehicle"/> ... </complexContent> </complexType> <complexType name="Plane"> <complexContent> <extension base="target:Vehicle"/> <sequence> <element name="wingspan" type="integer"/> </sequence> </complexContent> </complexType> </schema> , and the following definition of 'meansOfTravel': <complexType name="MeansOfTravel"> <complexContent> <sequence> <element name="transport" type="target:Vehicle"/> </sequence> </complexContent> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> With this definition you need to specify the type of your instance using xsi:type, like this: <meansOfTravel> <transport xsi:type="Plane"> <wingspan>3</wingspan> </transport> </meansOfTravel> I would just like to acheive a 'name of type' - 'name of element' mapping so that this could be replaced with just <meansOfTravel> <plane> <wingspan>3</wingspan> </plane> </meansOfTravel> The only way I could do this until now is by making it explicit: <complexType name="MeansOfTravel"> <sequence> <choice> <element name="plane" type="target:Plane"/> <element name="car" type="target:Car"/> </choice> </sequence> </complexType> <element name="meansOfTravel" type="target:MeansOfTravel"/> But this means that I have to list all possible sub-types in the 'MeansOfTravel' complex type. Is there no way of making the XML parser assume that you mean a 'Plane' if you call the element 'plane'? Or do I have to make the choice explicit? I would just like to keep my design DRY - if you have any other suggestions (like groups or so) - i would love to hear them.

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  • Control XML serialization of Dictionary<K, T>

    - by Luca
    I'm investigating about XML serialization, and since I use lot of dictionary, I would like to serialize them as well. I found the following solution for that (I'm quite proud of it! :) ). [XmlInclude(typeof(Foo))] public class XmlDictionary<TKey, TValue> { /// <summary> /// Key/value pair. /// </summary> public struct DictionaryItem { /// <summary> /// Dictionary item key. /// </summary> public TKey Key; /// <summary> /// Dictionary item value. /// </summary> public TValue Value; } /// <summary> /// Dictionary items. /// </summary> public DictionaryItem[] Items { get { List<DictionaryItem> items = new List<DictionaryItem>(ItemsDictionary.Count); foreach (KeyValuePair<TKey, TValue> pair in ItemsDictionary) { DictionaryItem item; item.Key = pair.Key; item.Value = pair.Value; items.Add(item); } return (items.ToArray()); } set { ItemsDictionary = new Dictionary<TKey,TValue>(); foreach (DictionaryItem item in value) ItemsDictionary.Add(item.Key, item.Value); } } /// <summary> /// Indexer base on dictionary key. /// </summary> /// <param name="key"></param> /// <returns></returns> public TValue this[TKey key] { get { return (ItemsDictionary[key]); } set { Debug.Assert(value != null); ItemsDictionary[key] = value; } } /// <summary> /// Delegate for get key from a dictionary value. /// </summary> /// <param name="value"></param> /// <returns></returns> public delegate TKey GetItemKeyDelegate(TValue value); /// <summary> /// Add a range of values automatically determining the associated keys. /// </summary> /// <param name="values"></param> /// <param name="keygen"></param> public void AddRange(IEnumerable<TValue> values, GetItemKeyDelegate keygen) { foreach (TValue v in values) ItemsDictionary.Add(keygen(v), v); } /// <summary> /// Items dictionary. /// </summary> [XmlIgnore] public Dictionary<TKey, TValue> ItemsDictionary = new Dictionary<TKey,TValue>(); } The classes deriving from this class are serialized in the following way: <FooDictionary xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Items> <DictionaryItemOfInt32Foo> <Key/> <Value/> </DictionaryItemOfInt32XmlProcess> <Items> This give me a good solution, but: How can I control the name of the element DictionaryItemOfInt32Foo What happens if I define a Dictionary<FooInt32, Int32> and I have the classes Foo and FooInt32? Is it possible to optimize the class above? THank you very much!

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  • Control XML serialization of generic types

    - by Luca
    I'm investigating about XML serialization, and since I use lot of dictionary, I would like to serialize them as well. I found the following solution for that (I'm quite proud of it! :) ). [XmlInclude(typeof(Foo))] public class XmlDictionary<TKey, TValue> { /// <summary> /// Key/value pair. /// </summary> public struct DictionaryItem { /// <summary> /// Dictionary item key. /// </summary> public TKey Key; /// <summary> /// Dictionary item value. /// </summary> public TValue Value; } /// <summary> /// Dictionary items. /// </summary> public DictionaryItem[] Items { get { List<DictionaryItem> items = new List<DictionaryItem>(ItemsDictionary.Count); foreach (KeyValuePair<TKey, TValue> pair in ItemsDictionary) { DictionaryItem item; item.Key = pair.Key; item.Value = pair.Value; items.Add(item); } return (items.ToArray()); } set { ItemsDictionary = new Dictionary<TKey,TValue>(); foreach (DictionaryItem item in value) ItemsDictionary.Add(item.Key, item.Value); } } /// <summary> /// Indexer base on dictionary key. /// </summary> /// <param name="key"></param> /// <returns></returns> public TValue this[TKey key] { get { return (ItemsDictionary[key]); } set { Debug.Assert(value != null); ItemsDictionary[key] = value; } } /// <summary> /// Delegate for get key from a dictionary value. /// </summary> /// <param name="value"></param> /// <returns></returns> public delegate TKey GetItemKeyDelegate(TValue value); /// <summary> /// Add a range of values automatically determining the associated keys. /// </summary> /// <param name="values"></param> /// <param name="keygen"></param> public void AddRange(IEnumerable<TValue> values, GetItemKeyDelegate keygen) { foreach (TValue v in values) ItemsDictionary.Add(keygen(v), v); } /// <summary> /// Items dictionary. /// </summary> [XmlIgnore] public Dictionary<TKey, TValue> ItemsDictionary = new Dictionary<TKey,TValue>(); } The classes deriving from this class are serialized in the following way: <XmlProcessList xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Items> <DictionaryItemOfInt32Foo> <Key/> <Value/> </DictionaryItemOfInt32XmlProcess> <Items> This give me a good solution, but: How can I control the name of the element DictionaryItemOfInt32Foo What happens if I define a Dictionary<FooInt32, Int32> and I have the classes Foo and FooInt32? Is it possible to optimize the class above? THank you very much!

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  • Xpath question Xml Xpath

    - by Ibrar Afzal
    I need an xpath expression that would return the value of I need to get the value of this node. the value to extract is my xpath expression is //rates/rate[loantype='30-Year Fixed Rate'] The issue hre is that there are three value each node has a subtype element. Beside fileter for loantype I also need to filter for subtype. I am not sure how to do it in xpath. I have the following xml 40-Year Fixed Rate A 3 5.375 1.000 5.491 0 1 40-Year Fixed Rate B 5.500 0.500 5.579 0 1 40-Year Fixed Rate C 5.625 0.000 5.667 0 1 30-Year Fixed Rate A 3 5.000 1.000 5.134 0 1 30-Year Fixed Rate B 5.125 0.500 5.215 0 1 30-Year Fixed Rate C 5.250 0.000 5.297 0 1 20-Year Fixed Rate A 3 4.875 1.000 5.055 0 1 20-Year Fixed Rate B 5.000 0.500 5.121 0 1 20-Year Fixed Rate C 5.125 0.000 5.187 0 1 15-Year Fixed Rate A 3 4.250 1.000 4.467 0 1 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 15-Year Fixed Rate C 4.500 0.000 4.570 0 1 10-Year Fixed Rate A 3 4.125 1.000 4.435 0 1 10-Year Fixed Rate B 4.250 0.500 4.454 0 1 10-Year Fixed Rate C 4.375 0.000 4.473 0 1 High-Balance 15-Year Fixed Rate D 3 4.250 1.000 4.461 0 1 High-Balance 15-Year Fixed Rate B 4.375 0.500 4.512 0 1 High-Balance 15-Year Fixed Rate C 4.500 0.000 4.563 0 1 High-Balance 30-Year Fixed Rate D 3 5.000 1.000 5.130 0 1 High-Balance 30-Year Fixed Rate B 5.125 0.500 5.211 0 1 High-Balance 30-Year Fixed Rate C 5.250 0.000 5.293 0 1 30-Year Fixed Rate Jumbo A 2 5.125 1.000 5.254 1 1 30-Year Fixed Rate Jumbo B 5.250 0.500 5.336 1 1 30-Year Fixed Rate Jumbo C 5.375 0.000 5.417 1 1 -- 15-Year Fixed Rate Jumbo A 2 5.000 1.000 5.220 1 1 15-Year Fixed Rate Jumbo B 5.125 0.500 5.270 1 1 15-Year Fixed Rate Jumbo C 5.250 0.000 5.320 1 1 -- 3/1 30-Year Adjustable Rate A 3 3.625 1.000 3.431 0 0 3/1 30-Year Adjustable Rate B 3.875 0.500 3.448 0 0 3/1 30-Year Adjustable Rate C 4.125 0.000 3.465 0 0 3/1 40-Year Adjustable Rate A 3 3.875 1.000 3.438 0 0 3/1 40-Year Adjustable Rate B 4.125 0.500 3.453 0 0 3/1 40-Year Adjustable Rate C 4.375 0.000 3.467 0 0 5/1 30-Year Adjustable Rate A 3 3.375 1.000 3.401 0 0 5/1 30-Year Adjustable Rate B 3.625 0.500 3.457 0 0 5/1 30-Year Adjustable Rate C 3.875 0.000 3.514 0 0 5/1 40-Year Adjustable Rate A 3 3.625 1.000 3.441 0 0 5/1 40-Year Adjustable Rate B 3.875 0.500 3.481 0 0 5/1 40-Year Adjustable Rate C 4.125 0.000 3.531 0 0 7/1 30-Year Adjustable Rate A 3 3.875 1.000 3.670 0 0 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 10/1 30-Year Adjustable Rate A 3 4.375 1.000 4.092 0 0 10/1 30-Year Adjustable Rate B 4.625 0.500 4.217 0 0 10/1 30-Year Adjustable Rate C 4.875 0.000 4.342 0 0 -- 2/2 ARM 30-Year (Purchase only) DH 5.250 0.000 3.709 0 0 -- High-Balance 5/1 30-Year Adjustable Rate D 3 3.375 1.000 3.366 0 0 High-Balance 5/1 30-Year Adjustable Rate B 3.625 0.500 3.404 0 0 High-Balance 5/1 30-Year Adjustable Rate C 3.875 0.000 3.454 0 0 High-Balance 7/1 30-Year Adjustable Rate D 3 3.875 1.000 3.670 0 0 High-Balance 7/1 30-Year Adjustable Rate B 4.125 0.500 3.755 0 0 High-Balance 7/1 30-Year Adjustable Rate C 4.375 0.000 3.841 0 0 3/1 30-Year Jumbo Adjustable Rate A 2 4.875 1.000 3.719 1 0 3/1 30-Year Jumbo Adjustable Rate B 5.000 0.500 3.708 1 0 3/1 30-Year Jumbo Adjustable Rate C 5.125 0.000 3.704 1 0 -- 3/1 40-Year Jumbo Adjustable Rate A 2 5.250 1.000 3.733 1 0 3/1 40-Year Jumbo Adjustable Rate B 5.375 0.500 3.727 1 0 3/1 40-Year Jumbo Adjustable Rate C 5.500 0.000 3.725 1 0 -- 5/1 30-Year Jumbo Adjustable Rate A 3 4.375 1.000 3.791 1 0 5/1 30-Year Jumbo Adjustable Rate B 4.500 0.500 3.803 1 0 5/1 30-Year Jumbo Adjustable Rate C 4.625 0.000 3.814 1 0 5/1 40-Year Jumbo Adjustable Rate A 2 5.000 1.000 3.922 1 0 5/1 40-Year Jumbo Adjustable Rate B 5.125 0.500 3.925 1 0 5/1 40-Year Jumbo Adjustable Rate C 5.250 0.000 3.936 1 0 -- 7/1 30-Year Jumbo Adjustable Rate A 3 4.950 1.000 4.261 1 0 7/1 30-Year Jumbo Adjustable Rate B 5.075 0.500 4.286 1 0 7/1 30-Year Jumbo Adjustable Rate C 5.200 0.000 4.311 1 0 2/2 ARM 30-Year Jumbo (Purchase only) DH 6.500 0.000 4.260 1 0 -- 30 Due in 7 Fixed Rate JUMBO Balloon A 6.375 1.000 6.613 1 0 30 Due in 7 Fixed Rate JUMBO Balloon B 6.500 0.500 6.625 1 0 40 due in 7 Fixed Rate offer1 5.250 0.000 5.374 0 0 1 40 Due in 7 Fixed Rate JUMBO Balloon offer2 6.500 0.000 6.625 1 0 1 Interest Only HELOC A To 80% LTV 3.250 0 1 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 75% LTV 6.000 6.000 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 75% LTV 6.00 6.153 0 2 Home Equity Loan - 7Yrs A Up to $100,000.00 Up to 80% LTV 6.250 6.250 0 2 Home Equity Loan - 7Yrs A $100,000.01 - $250,000.00 Up to 80% LTV 6.25 6.403 0 2 Home Equity Loan - 7Yrs B $100,000.01 - $250,000.00 Up to 90% LTV 6.99 7.145 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 75% LTV 6.50 6.612 0 2 Home Equity Loan - 10,15Yrs C $5,000-$250,000.00 To 80% LTV 6.75 6.863 0 2 Home Equity Loan - 10,15Yrs D $5,000-$250,000.00 Up to 90% LTV 7.50 7.614 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 75% LTV 7.50 7.566 0 2 Home Equity Loan - 20Yrs E $5,000-$250,000.00 To 80% LTV 7.75 7.817 0 2 Home Equity Loan - 20Yrs F $5,000-$250,000.00 Up to 90% LTV 8.50 8.569 0 2 Equity Edge $5,000-$25,000.00 Up to 125% LTV 12.00 12.188 Current Index 0.350 Prime Index 3.250 03/26/2010

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  • Need help with a Linq XML conditional grouping query

    - by FiveTools
    I have the following xml fragment: <BANNER ID="Banner 2" ROW_WIDTH="200"> <BANNER_TEXTS ID="BANNER_TEXTS"> <BANNER_TEXT UNDERLINE="false" SPAN_COL="1" WIDTHT="78px"></BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Years In Practice</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Internet Usage</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="4" WIDTHT="312px">Sales Reps Seen / Week</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="234px">Prescription Volume</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="3" WIDTHT="222px">Patient Load</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Total</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#60; 11 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">11-20 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">21-30 years</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Light 1-5 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Medium 6-10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">Heavy &#62;10 hrs</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">0</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-2</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">3-5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;5</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">101-150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="78px">&#62;150</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">1-100</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">101-200</BANNER_TEXT> <BANNER_TEXT UNDERLINE="true" SPAN_COL="1" WIDTHT="74px">&#62;200</BANNER_TEXT> </BANNER_TEXTS> <BANNER_TEXTS ID="COLUMN_TEXTS"> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(A)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(B)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(C)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(D)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(E)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(F)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(G)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(H)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(I)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(J)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(K)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(L)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(M)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(N)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(O)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(P)</COLUMN_TEXT> <COLUMN_TEXT UNDERLINE="false" SPAN_COL="1">(Q)</COLUMN_TEXT> </BANNER_TEXTS> </BANNER> I would like to group all the 'BANNER_TEXT' in the second sequence using the first sequence 'BANNER_TEXT' as the key (only include elements where string is not null or empty). The span_col attribute in the first 'BANNER_TEXT' sequence indicates which elements by position in the 2nd sequence are related. An example: 'Years in Practice' would be the first key and the attribute SPAN_COL=3 for that element indicates it would contain '< 11 years', '11-20 years', '21-30 years' (the first grouping of string.empty = Total would be skipped).

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  • What does a well formed XML or Schema look like for InfoPath form creation?

    - by Keith Sirmons
    Howdy, Are there any resources out there that defines how a well formed XML or Schema may look like for InfoPath? When designing a new form, there is an option to base the new form off of an existing XML document or XML Schema as the data source. I am looking for any guidelines or rules that will help me make sure the structure of the XML file I use to create the form will work the best it could work. I am creating the XML structure for another project, but we want to make sure the XML that is created would be InfoPath friendly for possible future applications. Thank you, Keith

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  • Can I use XText for a DSL involving an XML file type?

    - by Chris
    I have defined a small DSL that is mostly written in the form of different types of XML files in conjuction with some property files. This works very well but I wish to create an Eclipse Editor to make editing these files easier for beginners (I already have a working parser). The main XML file can reference some items from the .properties files and vice-versa. THe main xml file can also reference other XML files. Certain options should only be available in the main xml file based on the contents of the .properties files and based on some osgi plugins that can be added to the DSL project (the syntax is dynamic depending on context). The structure of the language is fixed but the options available in each attribute or the choice of attributes themselves changes depending on metadata contained in plugin .jar files. Questions: Does XText support dynamic syntax (validation changes depending on external factors)? Does XText support XML files / .properties files? Thank you very much for your help in advance.

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  • What are the benefits of using ORM over XML Serialization/Deserialization?

    - by Tequila Jinx
    I've been reading about NHibernate and Microsoft's Entity Framework to perform Object Relational Mapping against my data access layer. I'm interested in the benefits of having an established framework to perform ORM, but I'm curious as to the performance costs of using it against standard XML Serialization and Deserialization. Right now, I develop stored procedures in Oracle and SQL Server that use XML Types for either input or output parameters and return or shred XML depending on need. I use a custom database command object that uses generics to deserialize the XML results into a specified serializable class. By using a combination of generics, xml (de)serialization and Microsoft's DAAB, I've got a process that's fairly simple to develop against regardless of the data source. Moreover, since I exclusively use Stored Procedures to perform database operations, I'm mostly protected from changes in the data structure. Here's an over-simplified example of what I've been doing. static void main() { testXmlClass test = new test(1); test.Name = "Foo"; test.Save(); } // Example Serializable Class ------------------------------------------------ [XmlRootAttribute("test")] class testXmlClass() { [XmlElement(Name="id")] public int ID {set; get;} [XmlElement(Name="name")] public string Name {set; get;} //create an instance of the class loaded with data. public testXmlClass(int id) { GenericDBProvider db = new GenericDBProvider(); this = db.ExecuteSerializable("myGetByIDProcedure"); } //save the class to the database... public Save() { GenericDBProvider db = new GenericDBProvider(); db.AddInParameter("myInputParameter", DbType.XML, this); db.ExecuteSerializableNonQuery("mySaveProcedure"); } } // Database Handler ---------------------------------------------------------- class GenericDBProvider { public T ExecuteSerializable<T>(string commandText) where T : class { XmlSerializer xml = new XmlSerializer(typeof(T)); // connection and command code is assumed for the purposes of this example. // the final results basically just come down to... return xml.Deserialize(commandResults) as T; } public void ExecuteSerializableNonQuery(string commandText) { // once again, connection and command code is assumed... // basically, just execute the command along with the specified // parameters which have been serialized. } public void AddInParameter(string name, DbType type, object value) { StringWriter w = new StringWriter(); XmlSerializer x = new XmlSerializer(value.GetType()); //handle serialization for serializable classes. if (type == DbType.Xml && (value.GetType() != typeof(System.String))) { x.Serialize(w, value); w.Close(); // store serialized object in a DbParameterCollection accessible // to my other methods. } else { //handle all other parameter types } } } I'm starting a new project which will rely heavily on database operations. I'm very curious to know whether my current practices will be sustainable in a high-traffic situation and whether or not I should consider switching to NHibernate or Microsoft's Entity Framework to perform what essentially seems to boil down to the same thing I'm currently doing. I appreciate any advice you may have.

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  • Hierarchical Data in MySQL is as fast as XML to retrieve?

    - by ajsie
    i've got a list of all countries - states - cities (- subcities/villages etc) in a XML file and to retrieve for example a state's all cities it's really quick with XML (using xml parser). i wonder, if i put all this information in mysql, is retrieving a state's all cities as fast as with XML? cause XML is designed to store hierarchical data while relational databases like mysql are not. the list contains like 500 000 entities. so i wonder if its as fast as XML using either of: Adjacency list model Nested Set model And which one should i use? Cause (theoretically) there could be unlimited levels under a state (i heard that adjacency isn't good for unlimited child-levels). And which is fastest for this huge dataset? Thanks!

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  • How can I extract and save values from an XML file in Perl?

    - by Freddy
    Here is what I am trying to do in a Perl script: $data=""; sub loadXMLConfig() { $filename="somexml.xml" $data = $xml-XMLin($filename); } sub GetVariable() { ($FriendlyName) = @_; switch($FriendlyName) { case "My Friendly Name" {print $data-{my_xml_tag_name}} .... .... .... } } The problem is I am using Perl just because I am reading from an XML file, but I need to get these variables by a shell script. So, here is what I am using: $ perl -e 'require "scrpt.pl"; loadConfigFile(); GetVariable("My Variable")' This works exactly as expected, but I need to read the XML file every time I am getting a variable. Is there a way I could "preserve" $data across shell calls? The idea is that I read the XML file only once. If no, is there is a more simple way I could do this? These are the things I can't change: Config File is an XML Need the variables in a shell script

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  • How Do I Set XML Content-Type in Flex 3?

    - by Laxmidi
    Hi, I've got a Flex 3 project. Flex makes an ExternalCall to some Javascript. The Javascript is then turned into XML. But, my xml isn't parsing in IE. It works in all other browsers. I think that the problem is that I haven't set the XML's content-type and IE doesn't like that. So my code looks like: myReturn = '<myXMLReturn>' + myReturn + '</myXMLReturn>'; myReturn = '<?xml version="1.0" encoding="UTF-8"?>' + myReturn; xmlReturn = new XML(myReturn); How would I set: header('Content-type: application/xml'); in Actionscript? As I understand it IE requires that the Content-type be set. Is this correct? Thank you. -Laxmidi

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  • How to make a file with .pt extension, with xml syntax highlighting and vim's plugin snipmate load p

    - by Somebody still uses you MS-DOS
    I have the following in my .vimrc: au BufNewFile,BufRead *.pt set filetype=xml This is needed because although I'm editing a file with *.pt extension, it's indeed a valid xml file: setting the filetype like this I can have syntax highlighting. I'm using vim's snipmate plugin, and tried to create pt.snippets to specific needs since these files are Zope Page Templates (ZPT with TAL). Now, I have a problem: I don't want to create these snippets in xml.snippets, since they aren't really generic xml snippets, but my *.pt files are set to xml, so when I define my pt snippets they aren't loaded unless I run :set filetype=pt on my pt file on vim - but then I lose syntax highlighting. I would like to be able to have a pt file, with xml syntax highlighting, to be able to load a pt.snippets file from snipmate. How can I do it? (I would like to avoid putting my snippets in a generic snippet file, I would like it to be present only in pt.snippets to be easier to maintain.)

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  • In SQL Server, can multiple inserts be replaced with a single insert that takes an XML parameter?

    - by Mayo
    So I have an existing ASP.NET solution that uses LINQ-to-SQL to insert data into SQL Server (5 tables, 110k records total). I had read in the past that XML could be passed as a parameter to SQL Server but my google searches turn up results that store the XML directly into a table. I would rather take that XML parameter and insert the nodes as records. Is this possible? How is it done (i.e. how is the XML parameter used to insert records in T-SQL, how should the XML be formatted)? Note: I'm researching other options like SQL bulk copy and I know that SSIS would be a good alternative. I want to know if this XML approach is feasible.

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  • Loading an XML file with todays date in the filename... need to fallback to old file if one with tod

    - by arala22
    So here is my question. Using javascript/jQuery I am currently loading in an XML file that has a file name such as carousel_large_2010-06-08.xml.. the way I am doing it is checked for todays date then grabbing a file that has that date in the filename... the issue is sometimes they wont be uploading a new file for a given day so it needs to fallback to a older date that exists.. Wondering how to do it? Here is my code: // set date for xml file var currentTime = new Date(), month = currentTime.getMonth() + 1, day = currentTime.getDate(), year = currentTime.getFullYear(); if(month.toString().length == 1){ month = '0'+month.toString(); } if(day.toString().length == 1){ day = '0'+day.toString(); } var dateObject = year+"-"+month+"-"+day; // start magic $jq.ajax({ type: "GET", url: "_xml/carousel/home/carousel_large_"+dateObject+".xml", dataType: "xml", success: HPCarousels.heroCarousel.parseXML, error: function(){ alert('Error Loading XML Content'); } });

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