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  • Java EE javax.xml.bind.MarshalException

    - by sandeep
    Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. WARNING: invocation error on ejb endpoint Login_webservice at /Login_webserviceService/Login_webservice : javax.xml.bind.MarshalException - with linked exception: [javax.xml.bind.JAXBException: class JPA.Cantable nor any of its super class is known to this context.] javax.xml.ws.WebServiceException: javax.xml.bind.MarshalException - with linked exception: [javax.xml.bind.JAXBException: class JPA.Cantable nor any of its super class is known to this context.] at com.sun.xml.ws.message.jaxb.JAXBMessage.writePayloadTo(JAXBMessage.java:325) at com.sun.xml.ws.message.AbstractMessageImpl.writeTo(AbstractMessageImpl.java:142) at com.sun.xml.ws.encoding.StreamSOAPCodec.encode(StreamSOAPCodec.java:109) at com.sun.xml.ws.encoding.SOAPBindingCodec.encode(SOAPBindingCodec.java:278) at com.sun.xml.ws.transport.http.HttpAdapter.encodePacket(HttpAdapter.java:380) at com.sun.xml.ws.transport.http.HttpAdapter.access$100(HttpAdapter.java:92) at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:525) at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:285) at com.sun.xml.ws.transport.http.servlet.ServletAdapter.handle(ServletAdapter.java:143) at org.glassfish.webservices.Ejb3MessageDispatcher.handlePost(Ejb3MessageDispatcher.java:116) at org.glassfish.webservices.Ejb3MessageDispatcher.invoke(Ejb3MessageDispatcher.java:87) at org.glassfish.webservices.EjbWebServiceServlet.dispatchToEjbEndpoint(EjbWebServiceServlet.java:196) at org.glassfish.webservices.EjbWebServiceServlet.service(EjbWebServiceServlet.java:127) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) Here is my code: Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

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  • Canceling BackgroundWorker within the Thread

    - by Mike Wills
    I have a longer running multi-step process using BackgroundWorker and C#. I need to be sure that each step is completed successfully before moving on to the next step. I have seen many references to letting the BackgroundWorker catch errors and canceling from clicking on a Cancel button, but I want to check for an error myself and then gracefully end the process. Do I treat it just like someone clicked the cancel button, or is there another way?

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  • Is it a good way to close a thread?

    - by Roman
    I have a short version of the question: I start a thread like that: counter.start();, where counter is a thread. At the point when I want to stop the thread I do that: counter.interrupt() In my thread I periodically do this check: Thread.interrupted(). If it gives true I return from the thread and, as a consequence, it stops. And here are some details, if needed: If you need more details, they are here. From the invent dispatch thread I start a counter thread in this way: public static void start() { SwingUtilities.invokeLater(new Runnable() { public void run() { showGUI(); counter.start(); } }); } where the thread is defined like that: public static Thread counter = new Thread() { public void run() { for (int i=4; i>0; i=i-1) { updateGUI(i,label); try {Thread.sleep(1000);} catch(InterruptedException e) {}; } // The time for the partner selection is over. SwingUtilities.invokeLater(new Runnable() { public void run() { frame.remove(partnerSelectionPanel); frame.add(selectionFinishedPanel); frame.invalidate(); frame.validate(); } }); } }; The thread performs countdown in the "first" window (it shows home much time left). If time limit is over, the thread close the "first" window and generate a new one. I want to modify my thread in the following way: public static Thread counter = new Thread() { public void run() { for (int i=4; i>0; i=i-1) { if (!Thread.interrupted()) { updateGUI(i,label); } else { return; } try {Thread.sleep(1000);} catch(InterruptedException e) {}; } // The time for the partner selection is over. if (!Thread.interrupted()) { SwingUtilities.invokeLater(new Runnable() { public void run() { frame.remove(partnerSelectionPanel); frame.add(selectionFinishedPanel); frame.invalidate(); frame.validate(); } }); } else { return; } } };

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  • Android: Memory leak due to AsyncTask

    - by Manu
    Hello, I'm stuck with a memory leak that I cannot fix. I identified where it occurs, using the MemoryAnalizer but I vainly struggle to get rid of it. Here is the code: public class MyActivity extends Activity implements SurfaceHolder.Callback { ... Camera.PictureCallback mPictureCallbackJpeg = new Camera.PictureCallback() { public void onPictureTaken(byte[] data, Camera c) { try { // log the action Log.e(getClass().getSimpleName(), "PICTURE CALLBACK JPEG: data.length = " + data); // Show the ProgressDialog on this thread pd = ProgressDialog.show(MyActivity.this, "", "Préparation", true, false); // Start a new thread that will manage the capture new ManageCaptureTask().execute(data, c); } catch(Exception e){ AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this); ... dialog.create().show(); } } class ManageCaptureTask extends AsyncTask<Object, Void, Boolean> { protected Boolean doInBackground(Object... args) { Boolean isSuccess = false; // initialize the bitmap before the capture ((myApp) getApplication()).setBitmapX(null); try{ // Check if it is a real device or an emulator TelephonyManager telmgr = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE); String deviceID = telmgr.getDeviceId(); boolean isEmulator = "000000000000000".equalsIgnoreCase(deviceID); // get the bitmap if (isEmulator) { ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeFile(imageFileName)); } else { ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length)); } ((myApp) getApplication()).setImageForDB(ImageTools.resizeBmp(((myApp) getApplication()).getBmp())); // convert the bitmap into a grayscale image and display it in the preview ((myApp) getApplication()).setImage(makeGrayScale()); isSuccess = true; } catch (Exception connEx){ errorMessageFromBkgndThread = getString(R.string.errcapture); } return isSuccess; } protected void onPostExecute(Boolean result) { // Pass the result data back to the main activity if (MyActivity.this.pd != null) { MyActivity.this.pd.dismiss(); } if (result){ ((ImageView) findViewById(R.id.apercu)).setImageBitmap(((myApp) getApplication()).getBmp()); ((myApp) getApplication()).setBitmapX(null); } else{ // there was an error ErrAlert(); } } } }; private void ErrAlert(){ // notify the user about the error AlertDialog.Builder dialog = new AlertDialog.Builder(this); ... dialog.create().show(); } } MemoryAnalyzer indicated the memory leak at: ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length)); I am grateful for any suggestion, thank you in advance.

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  • Web request timeout in c#

    - by victor_foster
    I am trying to make a web service request call to a third part web site who's server is a little unreliable. Is there a way I can set a timeout on a request to this site? Something like this pseudo code: try for 1 minute { // Make web request here using (WebClient client new WebClient())...etc. } catch { }

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  • To get which function threw exception in javascript

    - by uzay95
    I am trying to create a Exception class to get and send errors from client to server. I want to catch exception in javascript function and push the details to the web service to write to database. But i couldn't get how to get which function/line throwed this exception. Is there any way to solve this?

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  • AccessControlException: access denied - caller function failed to load properties file

    - by Michael Mao
    Hi all: I am having a jar archive environment which is gonna call my class in a folder like this: java -jar "emarket.jar" ../tournament 100 My compiled class is deployed into the ../tournament folder, this command runs well. After I changed my code to load a properties file, it gets the following exception message: Exception in thread "main" java.security.AccessControlException: access denied (java.io.FilePermission agent.properties read) at java.security.AccessControlContext.checkPermission(Unknown Source) at java.security.AccessController.checkPermission(Unknown Source) at java.lang.SecurityManager.checkPermission(Unknown Source) at java.lang.SecurityManager.checkRead(Unknown Source) at java.io.FileInputStream.<init>(Unknown Source) at java.io.FileInputStream.<init>(Unknown Source) at Agent10479475.getPropertiesFromConfigFile(Agent10479475.java:110) at Agent10479475.<init>(Agent10479475.java:100) at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at java.lang.Class.newInstance0(Unknown Source) at java.lang.Class.newInstance(Unknown Source) at emarket.client.EmarketSandbox.instantiateClientObjects(EmarketSandbox.java:92) at emarket.client.EmarketSandbox.<init>(EmarketSandbox.java:27) at emarket.client.EmarketSandbox.main(EmarketSandbox.java:166) I am wondering why this security checking will fail. I issue the getPropertitiesFromConfigFile() function inside my class's default constructor, like this: public class Agent10479475 extends AbstractClientAgent { //default constructor public Agent10479475() { //set all properties to their default values in constructor FT_THRESHOLD = 400; FT_THRESHOLD_MARGIN = 50; printOut("Now loading properties from a config file...", ""); getPropertiesFromConfigFile(); printOut("Finished loading",""); } private void getPropertiesFromConfigFile() { Properties props = new Properties(); try { props.load(new FileInputStream("agent.properties")); FT_THRESHOLD = Long.parseLong(props.getProperty("FT_THRESHOLD")); FT_THRESHOLD_MARGIN = Long.parseLong(props.getProperty("FT_THRESHOLD_MARGIN ")); } catch(java.io.FileNotFoundException fnfex) { printOut("CANNOT FIND PROPERTIES FILE :", fnfex); } catch(java.io.IOException ioex) { printOut("IOEXCEPTION OCCURED :", ioex); } } } My class is loading its own .properties file under the same folder. why would the Java environment complains about such a denial of access? Must I config the emarket.client.EmarketSandbox class, which is not written by me and stored inside the emarket.jar, to access my agent.properties file? Any hints or suggestions is much appreciated. Many thanks in advance.

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  • android zxing intentintegrator

    - by cristi _b
    I've written the following code that works fine if you decide to scan a QR code (using zxing) and store it in private storage but in case you decide to cancel scanning, it crashes and the file previously stored content disappears. I think it might be a design error, not sure why. Below is relevant code ... /** * menu generation */ @Override public boolean onCreateOptionsMenu(Menu menu) { MenuInflater inflater = getMenuInflater(); inflater.inflate(R.menu.menu, menu); return true; } /** * menu handling */ @Override public boolean onOptionsItemSelected(MenuItem item) { Context context = getApplicationContext(); Toast toast = Toast.makeText(context, "", Toast.LENGTH_LONG); toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); switch (item.getItemId()) { case R.id.qrScan: IntentIntegrator integrator = new IntentIntegrator(this); integrator.initiateScan(); return true; case R.id.qrReset: File dir = getFilesDir(); File file = new File(dir, qrCodeFile); boolean deleted = file.delete(); return true; case R.id.appClose: this.finish(); return true; default: return super.onOptionsItemSelected(item); } } ... public void onActivityResult(int requestCode, int resultCode, Intent intent) { IntentResult scanResult = IntentIntegrator.parseActivityResult(requestCode, resultCode, intent); Context context = getApplicationContext(); Toast toast = Toast.makeText(context, "", Toast.LENGTH_SHORT); if (scanResult != null) { FileOutputStream fos = null; CharSequence text = scanResult.getContents(); try { fos = openFileOutput(qrCodeFile, Context.MODE_PRIVATE); try { fos.write(text.toString().getBytes()); fos.close(); toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Code saved"); toast.show(); } catch (IOException ex) { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Invalid code"); toast.show(); Logger.getLogger(MainActivity.class.getName()).log(Level.SEVERE, null, ex); } } catch (FileNotFoundException ex) { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Error while saving"); toast.show(); Logger.getLogger(MainActivity.class.getName()).log(Level.SEVERE, null, ex); } } else { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Invalid code"); toast.show(); } }

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  • how to make IXMLHTTPRequest work over HTTPS, client being WinCE

    - by siddharth
    hi, i am creating a client, which uploads to and dowloads from WinCE client. the code works properly for HTTP but not for HTTPS. Can any one help me about the changes that needs to be done. Code of client on PC : private void btnUpload_Click(object sender, EventArgs e) { try { MSXML2.DOMDocument xmlDOM = new DOMDocumentClass(); xmlDOM.load(txtUpload.Text); MSXML2.IXMLHTTPRequest x = new XMLHTTPClass(); x.open("POST", "http://192.168.1.12/server.asp?cmd=1", false, "", ""); x.send(xmlDOM); string result = x.responseText; if (x.status == 200) { MessageBox.Show(result); MessageBox.Show("upload file successfully"); } else { MessageBox.Show("upload file unsuccessful"); MessageBox.Show(x.status.ToString() + "\n" + x.statusText); } } catch(Exception ex) { MessageBox.Show(ex.Message + "\n" + ex.Data); } } private void btnDownload_Click(object sender, EventArgs e) { try { HttpWebRequest WebReq = (HttpWebRequest)WebRequest.Create("http://192.168.1.12/server.asp?cmd=2"); WebReq.Method = "GET"; HttpWebResponse WebResp = null; WebResp = (HttpWebResponse)WebReq.GetResponse(); Stream myResponseStream = WebResp.GetResponseStream(); StreamReader myStreamReader = new StreamReader(myResponseStream); string s = myStreamReader.ReadToEnd(); MessageBox.Show(s); StreamWriter SW; SW = File.CreateText(txtDownload.Text); SW.WriteLine(s); SW.Close(); MessageBox.Show(@"save file at" + txtDownload.Text); myStreamReader.Close(); myResponseStream.Close(); WebResp.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message + "\n" + ex.Data); } The client asp page that acts according to the command is : On Error Resume Next Response.Expires = 0 Dim cmd cmd = Request.QueryString("cmd") if cmd = "2" Then Dim xml_dom1 set xml_dom1 = CreateObject("MSXML2.DOMDocument") xml_dom1.load("\Windows\Config.xml") '(Server.MapPath("Config.xml")) Response.Write(xml_dom1.xml) set xml_dom1 = nothing end if if cmd = "1" Then dim xml_dom set xml_dom = CreateObject("MSXML2.DOMDocument") xml_dom.load(request) xml_dom.save("\Windows\Config.xml") set xml_dom = Nothing end if If err.number < 0 Then Response.Write(err.Description) Response.Write(err.number) End If

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  • how to rename filename in sdcard with android application?

    - by Addy
    In my Android application, I want to rename the file name at runtime. How can I do it? This is my code: String[] command = {" mv", "sun moon.jpg"," sun_moon,jpg"}; try { Process process = Runtime.getRuntime().exec(command); } catch (IOException e) { Toast.makeText(this, ""+e, Toast.LENGTH_LONG).show(); } I also used renameTo(File f) method but its also not working..

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  • How to add an XML parameter to a stored procedure in C#?

    - by salvationishere
    I am developing a C# web application in VS 2008 which interacts with my Adventureworks database in my SQL Server 2008. Now I am trying to add new records to one of the tables which has an XML column in it. How do I do this? This is the error I'm getting: System.Data.SqlClient.SqlException was caught Message="XML Validation: Text node is not allowed at this location, the type was defined with element only content or with simple content. Location: /" Source=".Net SqlClient Data Provider" ErrorCode=-2146232060 Class=16 LineNumber=22 Number=6909 Procedure="AppendDataC" Server="." State=1 StackTrace: at System.Data.SqlClient.SqlConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj) at System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj) at System.Data.SqlClient.SqlCommand.FinishExecuteReader(SqlDataReader ds, RunBehavior runBehavior, String resetOptionsString) at System.Data.SqlClient.SqlCommand.RunExecuteReaderTds(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, Boolean async) at System.Data.SqlClient.SqlCommand.RunExecuteReader(CommandBehavior cmdBehavior, RunBehavior runBehavior, Boolean returnStream, String method, DbAsyncResult result) at System.Data.SqlClient.SqlCommand.InternalExecuteNonQuery(DbAsyncResult result, String methodName, Boolean sendToPipe) at System.Data.SqlClient.SqlCommand.ExecuteNonQuery() at ADONET_namespace.ADONET_methods.AppendDataC(DataRow d, Hashtable ht) in C:\Documents and Settings\Admin\My Documents\Visual Studio 2008\Projects\AddFileToSQL\AddFileToSQL\ADONET methods.cs:line 212 InnerException: And this is a portion of my code in C#: try { SqlConnection conn2 = new SqlConnection(connString); SqlCommand cmd = conn2.CreateCommand(); cmd.CommandText = "dbo.AppendDataC"; cmd.CommandType = CommandType.StoredProcedure; cmd.Connection = conn2; ... sqlParam10.SqlDbType = SqlDbType.VarChar; SqlParameter sqlParam11 = cmd.Parameters.AddWithValue("@" + ht["@col11"], d[10]); sqlParam11.SqlDbType = SqlDbType.VarChar; SqlParameter sqlParam12 = cmd.Parameters.AddWithValue("@" + ht["@col12"], d[11]); sqlParam12.SqlDbType = SqlDbType.Xml; ... conn2.Open(); cmd.ExecuteNonQuery(); //This is the line it fails on and then jumps //to the Catch statement conn2.Close(); errorMsg = "The Person.Contact table was successfully updated!"; } catch (Exception ex) { Right now in my text input MDF file I have the XML parameter as: '<Products><id>3</id><id>6</id><id>15</id></Products>' Is this valid format for XML?

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  • Blob object not working properly even though the class is seralized

    - by GustlyWind
    I have class which is seralized and does convert a very large amount of data object to blob to save it to database.In the same class there is decode method to convert blob to the actual object.Following is the code for encode and decode of the object. private byte[] encode(ScheduledReport schedSTDReport) { byte[] bytes = null; try { ByteArrayOutputStream bos = new ByteArrayOutputStream(); ObjectOutputStream oos = new ObjectOutputStream(bos); oos.writeObject(schedSTDReport); oos.flush(); oos.close(); bos.close(); //byte [] data = bos.toByteArray(); //ByteArrayOutputStream baos = new ByteArrayOutputStream(); //GZIPOutputStream out = new GZIPOutputStream(baos); //XMLEncoder encoder = new XMLEncoder(out); //encoder.writeObject(schedSTDReport); //encoder.close(); bytes = bos.toByteArray(); //GZIPOutputStream out = new GZIPOutputStream(bos); //out.write(bytes); //bytes = bos.toByteArray(); } catch (Exception e) { _log.error("Exception caught while encoding/zipping Scheduled STDReport", e); } decode(bytes); return bytes; } /* * Decode the report definition blob back to the * ScheduledReport object. */ private ScheduledReport decode(byte[] bytes) { ByteArrayInputStream bais = new ByteArrayInputStream(bytes); ScheduledReport sSTDR = null; try { ObjectInputStream ois = new ObjectInputStream(bais); //GZIPInputStream in = new GZIPInputStream(bais); //XMLDecoder decoder = new XMLDecoder(in); sSTDR = (ScheduledReport)ois.readObject();//decoder.readObject(); //decoder.close(); } catch (Exception e) { _log.error("IOException caught while decoding/unzipping Scheduled STDReport", e); } return sSTDR; } The problem here is whenver I change something else in this class means any other method,a new class version is created and so the new version the class is unable to decode the originally encoded blob object. The object which I am passing for encode is also seralized object but this problem exists. Any ideas thanks

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  • A lock could not obtained within the time requested issue

    - by Wayne Daly
    The title is the error I'm getting, when I click load my program freezes. I assume its because I'm doing a statement inside a statement, but from what I see its the only solution to my issue. By loading I want to just repopulate the list of patients, but to do so I need to do their conditions also. The code works, the bottom method is what I'm trying to fix. I think the issue is that I have 2 statements open but I am not sure. load: public void DatabaseLoad() { try { String Name = "Wayne"; String Pass= "Wayne"; String Host = "jdbc:derby://localhost:1527/Patients"; Connection con = DriverManager.getConnection( Host,Name, Pass); PatientList.clear(); Statement stmt8 = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL8 = "SELECT * FROM PATIENTS"; ResultSet rs8 = stmt8.executeQuery( SQL8 ); ArrayList<PatientCondition> PatientConditions1 = new ArrayList(); while(rs8.next()) { PatientConditions1 = LoadPatientConditions(); } Statement stmt = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL = "SELECT * FROM PATIENTS"; ResultSet rs = stmt.executeQuery( SQL ); while(rs.next()) { int id = (rs.getInt("ID")); String name = (rs.getString("NAME")); int age = (rs.getInt("AGE")); String address = (rs.getString("ADDRESS")); String sex = (rs.getString("SEX")); String phone = (rs.getString("PHONE")); Patient p = new Patient(id, name, age, address, sex, phone, PatientConditions1); PatientList.add(p); } UpdateTable(); UpdateAllViews(); DefaultListModel PatientListModel = new DefaultListModel(); for (Patient s : PatientList) { PatientListModel.addElement(s.getAccountNumber() + "-" + s.getName()); } PatientJList.setModel(PatientListModel); } catch(SQLException err) { System.out.println(err.getMessage()); } } This is the method that returns the arraylist of patient conditions public ArrayList LoadPatientConditions() { ArrayList<PatientCondition> PatientConditionsTemp = new ArrayList(); try { String Name = "Wayne"; String Pass= "Wayne"; String Host = "jdbc:derby://localhost:1527/Patients"; Connection con = DriverManager.getConnection( Host,Name, Pass); Statement stmt = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL = "SELECT * FROM PATIENTCONDITIONS"; ResultSet rs5 = stmt.executeQuery( SQL ); int e = 0; while(rs5.next()) { e++; String ConName = (rs5.getString("CONDITION")); PatientCondition k = new PatientCondition(e,ConName); PatientConditionsTemp.add(k); } } catch(SQLException err) { System.out.println(err.getMessage()); } return PatientConditionsTemp; }

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  • Display\Capture InnerException Message

    - by madlan
    I was using the following to provide more information on a common exception that can occour in a piece of my code, the only problem is this errors if an exception is generated that has no InnerException message. Catch ex As Exception 'MessageBox.Show(ex.Message) 'If there is no InnerException. MessageBox.Show(ex.InnerException.InnerException.Message) End Try Is there a better method of doing this?

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  • Vaadin: Downloaded file has whole path as file name

    - by javydreamercsw
    I have a download action implemented on my Vaadin application but for some reason the downloaded file has the original file's full path as the file name. Any idea? You can see the code on this post. Edit: Here's the important part of the code: package com.bluecubs.xinco.core.server.vaadin; import com.bluecubs.xinco.core.server.XincoConfigSingletonServer; import com.vaadin.Application; import com.vaadin.terminal.DownloadStream; import com.vaadin.terminal.FileResource; import java.io.*; import java.net.URLEncoder; import java.util.UUID; import java.util.logging.Level; import java.util.logging.Logger; import java.util.zip.CRC32; import java.util.zip.CheckedInputStream; /** * * @author Javier A. Ortiz Bultrón<[email protected]> */ public class FileDownloadResource extends FileResource { private final String fileName; private File download; private File newFile; public FileDownloadResource(File sourceFile, String fileName, Application application) { super(sourceFile, application); this.fileName = fileName; } protected void cleanup() { if (newFile != null && newFile.exists()) { newFile.delete(); } if (download != null && download.exists() && download.listFiles().length == 0) { download.delete(); } } @Override public DownloadStream getStream() { try { //Copy file to directory for downloading InputStream in = new CheckedInputStream(new FileInputStream(getSourceFile()), new CRC32()); download = new File(XincoConfigSingletonServer.getInstance().FileRepositoryPath + System.getProperty("file.separator") + UUID.randomUUID().toString()); newFile = new File(download.getAbsolutePath() + System.getProperty("file.separator") + fileName); download.mkdirs(); OutputStream out = new FileOutputStream(newFile); newFile.deleteOnExit(); download.deleteOnExit(); byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); out.close(); final DownloadStream ds = new DownloadStream( new FileInputStream(newFile), getMIMEType(), fileName); ds.setParameter("Content-Disposition", "attachment; filename=" + URLEncoder.encode(fileName, "utf-8")); ds.setCacheTime(getCacheTime()); return ds; } catch (final FileNotFoundException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } catch (IOException ex) { Logger.getLogger(FileDownloadResource.class.getName()).log(Level.SEVERE, null, ex); return null; } } } I already debugged and verified that fileName only contains the file's name not the whole path.

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  • How to get Alfresco login ticket without user password, but with impersonating user with user principal name (UPN)

    - by dok
    I'm writing a DLL that has function for getting Alfresco login ticket without using user password, using only a user principal name (UPN). I’m calling alfresco REST API service /wcservice. I use NTLM in Alfresco. I’m impersonating users using WindowsIdentity constructor as explained here http://msdn.microsoft.com/en-us/library/ms998351.aspx#paght000023_impersonatingbyusingwindowsidentity. I checked and user is properly impersonated (I checked WindowsIdentity.GetCurrent().Name property). After impersonating a user, I try to make HttpWebRequest and set its credentials with CredentialsCache.DefaultNetworkCredentials. I get the error: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() When I use new NetworkCredential("username", "P@ssw0rd") to set request credentials, I get Alfresco login ticket (HttpStatusCode.OK, 200). Is there any way that I can get Alfresco login ticket without user password? Here is the code that I'm using: private string GetTicket(string UPN) { WindowsIdentity identity = new WindowsIdentity(UPN); WindowsImpersonationContext context = null; try { context = identity.Impersonate(); MakeWebRequest(); } catch (Exception e) { return e.Message + Environment.NewLine + e.StackTrace; } finally { if (context != null) { context.Undo(); } } } private string MakeWebRequest() { string URI = "http://alfrescoserver/alfresco/wcservice/mg/util/login"; HttpWebRequest request = WebRequest.Create(URI) as HttpWebRequest; request.CookieContainer = new CookieContainer(1); //request.Credentials = new NetworkCredential("username", "p@ssw0rd"); // It works with this request.Credentials = CredentialCache.DefaultNetworkCredentials; // It doesn’t work with this //request.Credentials = CredentialCache.DefaultCredentials; // It doesn’t work with this either try { using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { StreamReader sr = new StreamReader(response.GetResponseStream()); return sr.ReadToEnd(); } } catch (Exception e) { return (e.Message + Environment.NewLine + e.StackTrace); } } Here are records from Alfresco stdout.log (if it helps in any way): 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,550 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.526239ms 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] New NTLM auth request from 10.**.**.** (10.**.**.**:1229) 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,566 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.400909ms 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Received type1 [Type1:0xe20882b7,Domain:<NotSet>,Wks:<NotSet>] 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Client domain null 17:18:04,675 DEBUG [app.servlet.NTLMAuthenticationFilter] Sending NTLM type2 to client - [Type2:0x80000283,Target:AlfrescoServerA,Ch:197e2631cc3f9e0a]

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  • Single console in eclipse for both Server and Client

    - by rits
    I am building a client server application using Java Sockets (in Windows XP). For that I need different consoles for both Client and Server(for Input and Output operations). But in eclipse both share a single console. Is there any plugin or some sort of cheat through which I can do this. After googling I got this, http://dev.eclipse.org/newslists/news.eclipse.newcomer/msg17138.html But, this seems to be only for write operations, not read operations. Also, I tried the following to launch application manually, but even this is not working........ package mypack; import java.io.BufferedOutputStream; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.OutputStream; import java.io.PrintStream; public class MySystem { public static void changeStream(String mainFile) throws IOException{ File temp = new File(".") ; String parentPath = temp.getCanonicalPath() ; System.out.println(parentPath); //creation of batch file starts here try{ File f = new File(parentPath + "\\a.bat") ; System.out.println("Created : " + f.createNewFile()); //f.deleteOnExit() ; FileOutputStream fos = new FileOutputStream(f) ; String str = "java " + mainFile ; String batchCommand="@echo off\n"+str+"\npause\nexit"; char arr[] = batchCommand.toCharArray() ; System.out.println(str) ; for(int i = 0 ; i < arr.length ; i++){ fos.write(arr[i]) ; } fos.close() ; } catch(Exception e){ } //creation of batch file ends here //execution of batch file starts here try{ Runtime r = Runtime.getRuntime() ; System.out.println(parentPath + "\\a.bat") ; Process p = r.exec(new String[]{"cmd","/k","start a.bat"},null,new File(parentPath)) ; OutputStream os = (OutputStream)p.getOutputStream() ; System.setOut( new PrintStream(os) ) ; System.out.println("Hello"); } catch(Exception e){ e.printStackTrace(); } //execution of batch file ends here } public static void main(String[] args) throws IOException { MySystem.changeStream("MySystem") ; } }

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  • Trying to write a loop that uses an OutputStream to write to a text file.

    - by Steve McLain
    I'm not a java programmer, I'm a VB programmer. I am doing this as part of an assignment, however, I'm not asking for help on something assignment related. I'd like to figure out how to get the OutputStreamWriter to work properly in this instance. I just want to capture the values I'm generating and place them into a text document. The file is generated, but only one entry exists, not the 40 I'm expecting. I could do this in a heartbeat with VB, but java feels very strange to me right now. Your help is appreciated. Thanks, Steve Here's the code: public static void main(String[] args){ long start, end; double result,difference; try {//OutputStream code assistance from http://tutorials.jenkov.com/java-io/outputstreamwriter.html OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for n^2. start = System.nanoTime(); //Add code to call method to calculate n^2 result = mN2(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } try { OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for 2^n. start = System.nanoTime(); //Add code to call method to calculate 2^n result = m2N(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } } //Calculate N^2 public static double mN2(double n) { n = n*n; return n; } //Calculate 2N public static double m2N (double n) { n = 2*n; return n; }

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  • asp.net cannot update database

    - by tom
    string ConnectionString = WebConfigurationManager.ConnectionStrings["dbnameConnectionString"].ConnectionString; SqlConnection myConnection = new SqlConnection(ConnectionString); myConnection.Open(); try { string qry = "UPDATE customers SET firstname=@firstname WHERE cid=1"; SqlCommand insertQuery = new SqlCommand(qry, myConnection); insertQuery.Parameters.Add(new SqlParameter("@firstname", txtFirstname.Text)); insertQuery.ExecuteNonQuery(); myConnection.Close(); } catch (Exception ee) { } Any suggestions?

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  • javaEE javax.xml.bind.MarshalException

    - by sandeep
    Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. Here is my code: Errors WARNING: invocation error on ejb endpoint Login_webservice at /Login_webserviceService/Login_webservice : javax.xml.bind.MarshalException - with linked exception: [javax.xml.bind.JAXBException: class JPA.Cantable nor any of its super class is known to this context.] javax.xml.ws.WebServiceException: javax.xml.bind.MarshalException - with linked exception: [javax.xml.bind.JAXBException: class JPA.Cantable nor any of its super class is known to this context.] at com.sun.xml.ws.message.jaxb.JAXBMessage.writePayloadTo(JAXBMessage.java:325) at com.sun.xml.ws.message.AbstractMessageImpl.writeTo(AbstractMessageImpl.java:142) at com.sun.xml.ws.encoding.StreamSOAPCodec.encode(StreamSOAPCodec.java:109) at com.sun.xml.ws.encoding.SOAPBindingCodec.encode(SOAPBindingCodec.java:278) at com.sun.xml.ws.transport.http.HttpAdapter.encodePacket(HttpAdapter.java:380) at com.sun.xml.ws.transport.http.HttpAdapter.access$100(HttpAdapter.java:92) at com.sun.xml.ws.transport.http.HttpAdapter$HttpToolkit.handle(HttpAdapter.java:525) at com.sun.xml.ws.transport.http.HttpAdapter.handle(HttpAdapter.java:285) at com.sun.xml.ws.transport.http.servlet.ServletAdapter.handle(ServletAdapter.java:143) at org.glassfish.webservices.Ejb3MessageDispatcher.handlePost(Ejb3MessageDispatcher.java:116) at org.glassfish.webservices.Ejb3MessageDispatcher.invoke(Ejb3MessageDispatcher.java:87) at org.glassfish.webservices.EjbWebServiceServlet.dispatchToEjbEndpoint(EjbWebServiceServlet.java:196) at org.glassfish.webservices.EjbWebServiceServlet.service(EjbWebServiceServlet.java:127) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

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  • Troubleshooting Facebook's graph.put_object that returns error 400

    - by TimLeung
    I am using Facebook Python's SDK along with Google App Engine, and making a call to do a checkin: graph.put_object("me", "checkins", message="Hello, world", place="165039136840558", coordinates='{"latitude":"38.2454064", "longitude":"-122.0434404"}') However, this throws an error 400 Bad Request and I don't seem to be able to try catch it so I can have the important information. On a bad request, Facebook should return, an object like below which can help troubleshoot and address the issue, but I am not sure how I can retrieve this object: { "error": { "type" : "OAuthException", "message" : "An active access token must be used to query information about the current user." } }

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  • How to add Listview in tab activity?

    - by sandip armal
    I have one "SubjectTabActivity" and i need to show listview on this activity. But when i want to implement ListActivity it doesn't show listActivity. I have two(addchapter,addsubject) xml file with "SubjectTabActivity". and i need to show my database item il list view in respective xml file. but i don't understand how to do that? How to add Listactivity in TabActivity?. Please give me any reference or code. Thanks in advance.. Here is my reference code. public class MasterMainActivity extends TabActivity { LayoutInflater layoutInflater = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.master); Intent intent=getIntent(); setResult(RESULT_OK, intent); layoutInflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE); TabHost tabHost = getTabHost(); TabHost.TabSpec tab1spec = tabHost.newTabSpec("tabOneSpec"); ImageView imgView = new ImageView(this); imgView.setBackgroundResource(R.drawable.subject); tab1spec.setIndicator("Subject", imgView.getBackground()); tab1spec.setContent(new TabContentLayout()); TabHost.TabSpec tab2spec = tabHost.newTabSpec("tabTwoSpec"); tab2spec.setContent(new TabContentLayout()); ImageView imgView1 = new ImageView(this); imgView1.setBackgroundResource(R.drawable.chapter); tab2spec.setIndicator("Chapter", imgView1.getBackground()); tabHost.addTab(tab1spec); tabHost.addTab(tab2spec); } private class TabContentLayout implements TabHost.TabContentFactory { @Override public View createTabContent(String tag) { View view = null; if(tag.equals("tabOneSpec")) { try { //static final String[] FRUITS = new String[] { "Apple", "Avocado", "Banana", // "Blueberry", "Coconut", "Durian", "Guava", "Kiwifruit", //"Jackfruit", "Mango", "Olive", "Pear", "Sugar-apple" }; view = (LinearLayout) layoutInflater.inflate(R.layout.subjecttabview, null); //setListAdapter(new ArrayAdapter<String>(this, R.layout.subjecttabview,FRUITS)); } catch(Exception e) { e.printStackTrace(); } } if(tag.equals("tabTwoSpec")) { try { view = (LinearLayout) layoutInflater.inflate(R.layout.chaptertabview, null); } catch(Exception e) { e.printStackTrace(); } } return view; } } How to add ListActivity in this TabActivity

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