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  • The Breakpoint with Paul Irish and Addy Osmani—Episode 2

    The Breakpoint with Paul Irish and Addy Osmani—Episode 2 Ask and vote for questions at: goo.gl Addy Osmani and the (real) Paul Irish return for the second live episode of the Breakpoint - a new show focusing on developer tooling and workflow. This week they'll be showing us brand new SASS, feature inspection and console features in the Chrome Developer Tools. If you want your to stay on the bleeding edge of tooling, you won't want to miss it. From: GoogleDevelopers Views: 0 0 ratings Time: 00:00 More in Science & Technology

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  • The Breakpoint Ep 3: The Sourcemap Spectacular with Paul Irish and Addy Osmani

    The Breakpoint Ep 3: The Sourcemap Spectacular with Paul Irish and Addy Osmani Ask and vote for questions at goo.gl Take Coffeescript to Javascript to Minified and all the way back with source maps. In addition to a new Coffeescript sourcemap workflow, we'll cover the latest sourcemap updates so you can understand how to dramatically improve your debugging experience. Finally, Paul and Addy will be joined by special guest—Yeoman core contributor Sindre Sorhus—to discuss what big new changes are coming to the project. From: GoogleDevelopers Views: 0 0 ratings Time: 01:00:00 More in Science & Technology

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  • Regular expression, excluding .. in suffix of email addy

    - by user1754700
    This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

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  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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  • How do I draw a dotted or dashed line?

    - by Gagege
    I'm trying to draw a dashed or dotted line by placing individual segments(dashes) along a path and then separating them. The only algorithm I could come up with for this gave me a dash length that was variable based on the angle of the line. Like this: private function createDashedLine(fromX:Float, fromY:Float, toX:Float, toY:Float):Sprite { var line = new Sprite(); var currentX = fromX; var currentY = fromY; var addX = (toX - fromX) * 0.0075; var addY = (toY - fromY) * 0.0075; line.graphics.lineStyle(1, 0xFFFFFF); var count = 0; // while line is not complete while (!lineAtDestination(fromX, fromY, toX, toY, currentX, currentY)) { /// move line draw cursor to beginning of next dash line.graphics.moveTo(currentX, currentY); // if dash is even if (count % 2 == 0) { // draw the dash line.graphics.lineTo(currentX + addX, currentY + addY); } // add next dash's length to current cursor position currentX += addX; currentY += addY; count++; } return line; } This just happens to be written in Haxe, but the solution should be language neutral. What I would like is for the dash length to be the same no matter what angle the line is. As is, it's just adding 75 thousandths of the line length to the x and y, so if the line is and a 45 degree angle you get pretty much a solid line. If the line is at something shallow like 85 degrees then you get a nice looking dashed line. So, the dash length is variable, and I don't want that. How would I make a function that I can pass a "dash length" into and get that length of dash, no matter what the angle is? If you need to completely disregard my code, be my guest. I'm sure there's a better solution.

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  • C#, Asp.net Uploading files to file server...

    - by Imcl
    Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } I also used:- File.Copy(filePath, "\\192.168.1.3\upload\"); The following line doesnt execute... byte[] arrReturn = client.UploadFile(addy, filePath); tried changing it to:- byte[] arrReturn = client.UploadFile("\\192.168.1.3\upload\", filePath); IT still doesnt work...Any solution to it?? I basically want to transfer a file from the client to the file storage server without actually loggin into the server so that the client cannot access the storage location on the server directly...

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  • Faith and Godaddy [closed]

    - by yuval
    Let's remove the capitalizations from the name GoDaddy - the hosting company: godaddy. Now let's look at the spacing a little differently: god addy, and capitalize: God Addy: God Addy: The address of God Did anybody notice this? How many negative votes will this question get? How long until someone closes the discussion on this question? All of this and more... NOW! Someone favorited this! woo! In addition to my serious and intelligent previous question: Who came first, the chicken or the egg?

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  • ASP.NET file transfer from local machine to another machine

    - by Imcl
    I basically want to transfer a file from the client to the file storage server without actual login to the server so that the client cannot access the storage location on the server directly. I can do this only if i manually login to the storage server through windows login. I dont want to do that. This is a Web-Based Application. Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } The following line doesn't execute... byte[] arrReturn = client.UploadFile(addy, filePath); This is the error I get: An exception occurred during a WebClient request

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  • MsChart : Partial view error

    - by Poomjai
    Hi I have a problem when i using Mschart on my MVC project, when i use the first index page of project to render for the partial view name index2 the code is <% Html.RenderPartial("Index2"); %> But when i run it the error is occur which the message is CS0029: Cannot implicitly convert type 'ASP.views_home_index2_ascx' to 'System.Web.UI.Page' -it said that the problem line of code is : // Render chart control Line 52: Chart2.Page = this; << At here Line 53: HtmlTextWriter writer = new HtmlTextWriter(Page.Response.Output); Line 54: Chart2.RenderControl(writer); But when i put all of code in Index2.ascx to the index.aspx and not to render the partial view it work fine Code of Index2.ascx is <% System.Web.UI.DataVisualization.Charting.Chart Chart2 = new System.Web.UI.DataVisualization.Charting.Chart(); Chart2.Width = 412; Chart2.Height = 296; Chart2.RenderType = RenderType.ImageTag; Chart2.Palette = ChartColorPalette.BrightPastel; Title t = new Title("No Code Behind Page", Docking.Top, new System.Drawing.Font("Trebuchet MS", 14, System.Drawing.FontStyle.Bold), System.Drawing.Color.FromArgb(26, 59, 105)); Chart2.Titles.Add(t); Chart2.ChartAreas.Add("Series 1"); Chart2.Series.Add("Series 1"); // add points to series 1 Chart2.Series["Series 1"].Points.AddY(3); Chart2.Series["Series 1"].Points.AddY(4); Chart2.Series["Series 1"].Points.AddY(5); Chart2.BorderSkin.SkinStyle = BorderSkinStyle.Emboss; Chart2.BorderColor = System.Drawing.Color.FromArgb(26, 59, 105); Chart2.BorderlineDashStyle = ChartDashStyle.Solid; Chart2.BorderWidth = 2; Chart2.Legends.Add("Legend1"); // Render chart control Chart2.Page = this; HtmlTextWriter writer = new HtmlTextWriter(Page.Response.Output); Chart2.RenderControl(writer); %

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  • C# ASP.NET FILE TRANSFER FROM LOCAL MACHINE TO ANOTHER MACHINE

    - by Imcl
    I basically want to transfer a file from the client to the file storage server without actual login to the server so that the client cannot access the storage location on the server directly. I can do this only if i manually login to the storage server through windows login. I dont want to do that. This is a Web-Based Application. Using the link below, I wrote a code for my application. I am not able to get it right though, Please refer the link and help me ot with it... http://stackoverflow.com/questions/263518/c-uploading-files-to-file-server The following is my code:- protected void Button1_Click(object sender, EventArgs e) { filePath = FileUpload1.FileName; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.3\\upload\\"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } } The following line doesn't execute... byte[] arrReturn = client.UploadFile(addy, filePath); THIS IS THE ERROR I GET :- "An exception occurred during a WebClient request"

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  • problem in display image with loadDataWithBaseURL() in Android

    - by Addy
    Hi. In my Application, I display data in webview but it can't display the images in the webview. I used loadDatawithBaseURL() method. This is my code.. webview.loadDataWithBaseURL("file:///059600656X/", data, "text/html", "UTF-8", "about:blank"); // here data is a string object which contain html parsing data. I think it cant find the images in given directory. Can Anybody help me?

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  • Android: problem retrieving bitmap from database

    - by Addy
    When I'm retrieving image from the sqlite database my Bitmap object bm return null value can any one help me..? I found problem in my database.. When I store the byte array in blob data type in database table that time the size of the byte array was 2280.. But when i retrieved that blob data type using select query I get the byte array within size 12. My code is: // Inserting data in database byte[] b; ByteArrayOutputStream baos = new ByteArrayOutputStream(); Bitmap bm = BitmapFactory.decodeResource(getResources(),R.drawable.icon); bm.compress(Bitmap.CompressFormat.PNG, 100, baos); //bm is the bitmap object b = baos.toByteArray(); //here b size is 2280 baos.close(); try { mDB = this.openOrCreateDatabase(MY_DATABASE_NAME, MODE_PRIVATE, null); mDB.execSQL("CREATE TABLE IF NOT EXISTS " + MY_DATABASE_TABLE + " (PICTURE BLOB);"); mDB.execSQL("INSERT INTO " + MY_DATABASE_TABLE + " (PICTURE)" + " VALUES ('"+b+"');"); } catch(Exception e) { Log.e("Error", "Error", e); } finally { if(mDB != null) mDB.close(); } // Retriving data from database byte[] b1; Bitmap bm; mDB = this.openOrCreateDatabase(MY_DATABASE_NAME, MODE_PRIVATE, null); try { mDB.execSQL("CREATE TABLE IF NOT EXISTS " + MY_DATABASE_TABLE + " (PICTURE BLOB);"); Cursor c = mDB.rawQuery("SELECT * FROM " + MY_DATABASE_TABLE + ";", null); c.moveToFirst(); if (c != null) { do { b1=c.getBlob(0)); //here b1 size is 12 bm=BitmapFactory.decodeByteArray(b1, 0, b1.length); }while(c.moveToNext()); }

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  • how to rename filename in sdcard with android application?

    - by Addy
    In my Android application, I want to rename the file name at runtime. How can I do it? This is my code: String[] command = {" mv", "sun moon.jpg"," sun_moon,jpg"}; try { Process process = Runtime.getRuntime().exec(command); } catch (IOException e) { Toast.makeText(this, ""+e, Toast.LENGTH_LONG).show(); } I also used renameTo(File f) method but its also not working..

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  • unable to load library at runtime in android application

    - by Addy
    Hi. I m working on android application in which I used JNI for native c code. I build this application on android 2.0 version and ndkr3. and its work fine. Now when I changed the android sdk version 1.5 and api version 3 I faced problem of unable to open library libtest_demo.so. 05-13 16:54:23.603: INFO/dalvikvm(1211): Unable to dlopen(/data/data/org.abc.test_demo/lib/libtest_demo.so): Cannot find library I put the libtest_demo.so file at the same place /data/data/org.abc.test_demo/lib/libtest_demo.so but still problem arise. please help me..

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  • Trouble with speed and vectors

    - by Eegabooga
    I'm working on adding bullets to my game. Right now I can shoot bullets in the direction that I would like from a ship by getting the ship's angle: int speed = 5; int dx = -(cos(degreesToRadians(ship.angle)) * speed); // rate of change in the x direction int dy = -(sin(degreesToRadians(ship.angle)) * speed); // rate of change in the y direction bulletPosition.addX(dx); // addX(dx) is simply bulletPosition.x += dx bulletPosition.addY(dy); The ship is pretty much the exact same thing, except I use the += operator: int dx += -(cos(degreesToRadians(angle)) * 0.15) int dy += -(sin(degreesToRadians(angle)) * 0.15); shipPosition.addX(dx); shipPosition.addY(dy); I would like to be able to add the ship's velocity to the bullet's velocity, but I'm a little confused as to how should get the speed from the ship's vector. I thought that adding the ship's dx to the bullet's dx like int dx = -(cos(degreesToRadians(ship.angle)) * speed * dx) would work because I'm adding the rate of change of the ship to the rate of change of the bullet, but that doesn't work. So here's the final question: How can I get the speed of my ship and apply it to my bullet's speed? Thanks in advance for all help :)

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  • upload file from window application to Remote Web Server

    - by user208466
    string filePath = "C:\\test\\564.flv"; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.28\\Files\\test.flv"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } i am get this error "The remote server returned an error: (405) Method Not Allowed." what should i doo ??

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  • Uploading files to server

    - by Shivkumar
    I am trying to upload a file from my Windows application to the server into a particular Folder using C#. However, I am getting an exception: "An exception occurred during a WebClient request". Here is my code: for (int i = 0; i < dtResponseAttach.Rows.Count; i++) { string filePath = dtResponseAttach.Rows[i]["Response"]; WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(); Uri addy = new Uri("http://192.168.1.4/people/Attachments/"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } What could be the reason for this exception?

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  • The Breakpoint Ep. 4 —The Tour De Timeline

    The Breakpoint Ep. 4 —The Tour De Timeline Ask and vote for questions at: goo.gl The DevTools' Timeline shows the heartbeat and health of your application's performance. In this episode we'll do a deep deep dive into how to uncover the cost of internal browser operations like parsing HTML, decoding images, invalidating layout geometry and painting to screen. Paul and Addy will show you how best to approach improving the performance of your CSS and JS. From: GoogleDevelopers Views: 0 0 ratings Time: 01:00:00 More in Science & Technology

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  • The best Drupal and JavaScript developer?

    - by hakanito
    I've read a lot of JS articles and books by Nicholas Zakas and Addy Osmani, in my opinion evangelists in the field. But I am also a Drupal developer, and these guys are not. Many of the techniques they're talking about such as AMD and RequireJS are great, but it's hard to know how to integrate them when it comes to Drupal (and do it right, ofc). So my question is if there are any recognized developer/s out there with strong JavaScript AND Drupal experience?

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  • Debunking Dart Myths For Web Developers

    Debunking Dart Myths For Web Developers Addy Osmani interviews Seth Ladd to learn more about Dart. Join this episode to discover how Dart relates to JavaScript, who the intended audience for Dart is, and what Dart's motivations are. If you're curious what Dart is all about, and if it wants to replace JavaScript, this is the episode for you! From: GoogleDevelopers Views: 0 1 ratings Time: 00:00 More in Science & Technology

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  • Better why of looping to detect change.

    - by Dremation
    As of now I'm using a while(true) method to detect changes in memory. The problem with this is it's kill the applications performance. I have a list of 30 pointers that need checked as rapidly as possible for changes, without sacrificing a huge performance loss. Anyone have ideas on this? memScan = new Thread(ScanMem); public static void ScanMem() { int i = addy.Length; while (true) { Thread.Sleep(30000); //I do this to cut down on cpu usage for (int j = 0; j < i; j++) { string[] values = addy[j].Split(new char[] { Convert.ToChar(",") }); //MessageBox.Show(values[2]); try { if (Memory.Scanner.getIntFromMem(hwnd, (IntPtr)Convert.ToInt32(values[0], 16), 32).ToString() != values[1].ToString()) { //Ok, it changed lets do our work //work if (Globals.Working) return; SomeFunction("Results: " + values[2].ToString(), "Memory"); Globals.Working = true; }//end if }//end try catch { } }//end for }//end while }//end void

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  • C# Uploading files to file server

    - by JustFoo
    Hello All, Currently I have an application that receives an uploaded file from my web application. I now need to transfer that file to a file server which happens to be located on the same network (however this might not always be the case). I was attempting to use the webclient class in C# .NET. string filePath = "C:\\test\\564.flv"; try { WebClient client = new WebClient(); NetworkCredential nc = new NetworkCredential(uName, password); Uri addy = new Uri("\\\\192.168.1.28\\Files\\test.flv"); client.Credentials = nc; byte[] arrReturn = client.UploadFile(addy, filePath); Console.WriteLine(arrReturn.ToString()); } catch (Exception ex) { Console.WriteLine(ex.Message); } The machine located at 192.168.1.28 is a file server and has a share c:\Files. As of right now I am receiving an error of Login failed bad user name or password, but I can open explorer and type in that path login successfully. I can also login using remote desktop, so I know the user account works. Any ideas on this error? Is it possible to transfer a file directly like that? With the webclient class or maybe some other class? Thanks

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