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  • Parse Nested XML tags with the same name

    - by footose
    Let's take a simple XML document: <x> <e> <e> <e>Whatever 1</e> </e> </e> <e> <e> <e>Whatever 2</e> </e> </e> <e> <e> <e>Whatever 3</e> </e> </e> </x> Using the standard org.w3c.dom, I can get the nodes in X by doing.. NodeList fullnodelist = doc.getElementsByTagName("x"); But if I want to return the next set of "e" I try to use something like .. Element element = (Element) fullnodelist.item(0); NodeList nodes = pelement.getElementsByTagName("e"); Expecting it to return "3" nodes (because there are 3 sets of "e"), but instead, it returns "9" - becuase it gets all entries with "e" apperently. This would be fine in the above case, because I could probably iterate through and find what I'm looking for. The problem I'm having is that when the XML file looks like the following: <x> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> </x> When I request the "e" value, it returns 4, instead of (what i expect) 2. Am I just not understanding how the DOM parsing works? Typically in the past I have used my own XML documents so I would never name the items like this, but unfortunately this is not my XML file and I have no choice to work like this. What I thought I would do is write a loop that "drills down" nodes so that I could group each node together... public static NodeList getNodeList(Element pelement, String find) { String[] nodesfind = Utilities.Split(find, "/"); NodeList nodeList = null; for (int i = 0 ; i <= nodesfind.length - 1; i++ ) { nodeList = pelement.getElementsByTagName( nodesfind[i] ); pelement = (Element)nodeList.item(i); } // value of the nod we are looking for return nodeList; } .. So that if you passed "s/e" into the function, it would return the 2 nodes that I'm looking for (or elements, maybe I'm using the terminology incorrect?). instead it returns all of the "e" nodes within that node. I'm using J2SE for this, so options are rather limited. I can't use any third party XML Parsers. Anyway, if anyone is still with me and has a suggestion, it would be appreciated.

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  • C++/msvc6 application crashes due to heap corruption, any hints?

    - by David Alfonso
    Hello all, let me say first that I'm writing this question after months of trying to find out the root of a crash happening in our application. I'll try to detail as much as possible what I've already found out about it. About the application It runs on Windows XP Professional SP2. It's built with Microsoft Visual C++ 6.0 with Service Pack 6. It's MFC based. It uses several external dlls (e.g. Xerces, ZLib or ACE). It has high performance requirements. It does a lot of network and hard disk I/O, but it's also cpu intensive. It has an exception handling mechanism which generates a minidump when an unhandled exception occurs. Facts about the crash It only happens on multiprocessor/multicore machines and under heavy loads of work. It happens at random (neither we nor our client have found a pattern yet). We cannot reproduce the crash on our testing lab. It only happens on some production systems (but always in multicore machines) It always ends up crashing at the same point, although the complete stack is not always the same. Let me add the stack of the crashing thread (obtained using WinDbg, sorry we don't have symbols) ChildEBP RetAddr Args to Child WARNING: Stack unwind information not available. Following frames may be wrong. 030af6c8 7c9206eb 77bfc3c9 01a80000 00224bc3 MyApplication+0x2a85b9 030af960 7c91e9c0 7c92901b 00000ab4 00000000 ntdll!RtlAllocateHeap+0xeac (FPO: [Non-Fpo]) 030af98c 7c9205c8 00000001 00000000 00000000 ntdll!ZwWaitForSingleObject+0xc (FPO: [3,0,0]) 030af9c0 7c920551 01a80898 7c92056d 313adfb0 ntdll!RtlpFreeToHeapLookaside+0x22 (FPO: [2,0,4]) 030afa8c 4ba3ae96 000307da 00130005 00040012 ntdll!RtlFreeHeap+0x1e9 (FPO: [Non-Fpo]) 030afacc 77bfc2e3 0214e384 3087c8d8 02151030 0x4ba3ae96 030afb00 7c91e306 7c80bfc1 00000948 00000001 msvcrt!free+0xc8 (FPO: [Non-Fpo]) 030afb20 0042965b 030afcc0 0214d780 02151218 ntdll!ZwReleaseSemaphore+0xc (FPO: [3,0,0]) 030afb7c 7c9206eb 02e6c471 02ea0000 00000008 MyApplication+0x2965b 030afe60 7c9205c8 02151248 030aff38 7c920551 ntdll!RtlAllocateHeap+0xeac (FPO: [Non-Fpo]) 030afe74 7c92056d 0210bfb8 02151250 02151250 ntdll!RtlpFreeToHeapLookaside+0x22 (FPO: [2,0,4]) 030aff38 77bfc2de 01a80000 00000000 77bfc2e3 ntdll!RtlFreeHeap+0x647 (FPO: [Non-Fpo]) 7c92056d c5ffffff ce7c94be ff7c94be 00ffffff msvcrt!free+0xc3 (FPO: [Non-Fpo]) 7c920575 ff7c94be 00ffffff 12000000 907c94be 0xc5ffffff 7c920579 00ffffff 12000000 907c94be 90909090 0xff7c94be *** WARNING: Unable to verify checksum for xerces-c_2_7.dll *** ERROR: Symbol file could not be found. Defaulted to export symbols for xerces-c_2_7.dll - 7c92057d 12000000 907c94be 90909090 8b55ff8b MyApplication+0xbfffff 7c920581 907c94be 90909090 8b55ff8b 08458bec xerces_c_2_7 7c920585 90909090 8b55ff8b 08458bec 04408b66 0x907c94be 7c920589 8b55ff8b 08458bec 04408b66 0004c25d 0x90909090 7c92058d 08458bec 04408b66 0004c25d 90909090 0x8b55ff8b The address MyApplication+0x2a85b9 corresponds to a call to erase() of a std::list. What I have tried so far Reviewing all the code related to the point where the crash ends happening. Trying to enable pageheap on our testing lab though nothing useful has been found by now. We have substituted the std::list for a C array and then it crashes in other part of the code (although it is related code, it's not in the code where the old list resided). Coincidentally, now it crashes in another erase, though this time of a std::multiset. Let me copy the stack contained in the dump: ntdll.dll!_RtlpCoalesceFreeBlocks@16() + 0x124e bytes ntdll.dll!_RtlFreeHeap@12() + 0x91f bytes msvcrt.dll!_free() + 0xc3 bytes MyApplication.exe!006a4fda() [Frames below may be incorrect and/or missing, no symbols loaded for MyApplication.exe] MyApplication.exe!0069f305() ntdll.dll!_NtFreeVirtualMemory@16() + 0xc bytes ntdll.dll!_RtlpSecMemFreeVirtualMemory@16() + 0x1b bytes ntdll.dll!_ZwWaitForSingleObject@12() + 0xc bytes ntdll.dll!_RtlpFreeToHeapLookaside@8() + 0x26 bytes ntdll.dll!_RtlFreeHeap@12() + 0x114 bytes msvcrt.dll!_free() + 0xc3 bytes c5ffffff() Possible solutions (that I'm aware of) which cannot be applied "Migrate the application to a newer compiler": We are working on this but It's not a solution at the moment. "Enable pageheap (normal or full)": We can't enable pageheap on production machines as this affects performance heavily. I think that's all I remember now, if I have forgotten something I'll add it asap. If you can give me some hint or propose some possible solution, don't hesitate to answer! Thank you in advance for your time and advice.

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  • Better, simpler example of 'semantic conflict'?

    - by rhubbarb
    I like to distinguish three different types of conflict from a version control system (VCS): textual syntactic semantic A textual conflict is one that is detected by the merge or update process. This is flagged by the system. A commit of the result is not permitted by the VCS until the conflict is resolved. A syntactic conflict is not flagged by the VCS, but the result will not compile. Therefore this should also be picked up by even a slightly careful programmer. (A simple example might be a variable rename by Left and some added lines using that variable by Right. The merge will probably have an unresolved symbol. Alternatively, this might introduce a semantic conflict by variable hiding.) Finally, a semantic conflict is not flagged by the VCS, the result compiles, but the code may have problems running. In mild cases, incorrect results are produced. In severe cases, a crash could be introduced. Even these should be detected before commit by a very careful programmer, through either code review or unit testing. My example of a semantic conflict uses SVN (Subversion) and C++, but those choices are not really relevant to the essence of the question. The base code is: int i = 0; int odds = 0; while (i < 10) { if ((i & 1) != 0) { odds *= 10; odds += i; } // next ++ i; } assert (odds == 13579) The Left (L) and Right (R) changes are as follows. Left's 'optimisation' (changing the values the loop variable takes): int i = 1; // L int odds = 0; while (i < 10) { if ((i & 1) != 0) { odds *= 10; odds += i; } // next i += 2; // L } assert (odds == 13579) Right's 'optimisation' (changing how the loop variable is used): int i = 0; int odds = 0; while (i < 5) // R { odds *= 10; odds += 2 * i + 1; // R // next ++ i; } assert (odds == 13579) This is the result of a merge or update, and is not detected by SVN (which is correct behaviour for the VCS). int i = 1; // L int odds = 0; while (i < 5) // R { odds *= 10; odds += 2 * i + 1; // R // next i += 2; // L } assert (odds == 13579) The assert fails because odds is 37. So my question is as follows. Is there a simpler example than this? Is there a simple example where the compiled executable has a new crash? As a secondary question, are there cases of this that you have encountered in real code? Again, simple examples are especially welcome.

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  • (PHP) User is being forced to RE-LOGIN after trying to do something on an admin page

    - by hatorade
    I have created an admin panel for a client in PHP, which requires a login. Here is the code at the top of the admin page requiring the user to be logged in: admin.php <?php session_start(); require("_lib/session_functions.php"); require("_lib/db.php"); db_connect(); //if the user has not logged in if(!isLoggedIn()) { header('Location: login_form.php'); die(); } ?> Obviously, the if statement is what catches them and forces them to log in. Here is the code on the resulting login page: login_form.php <form name="login" action="login.php" method="post"> Username: <input type="text" name="username" /> Password: <input type="password" name="password" /> <input type="submit" value="Login" /> </form> Which posts info to this controller page: login.php <?php session_start(); //must call session_start before using any $_SESSION variables include '_lib/session_functions.php'; $username = $_POST['username']; $password = $_POST['password']; include '_lib/db.php'; db_connect(); // Connect to the DB $username = mysql_real_escape_string($username); $query = "SELECT password, salt FROM users WHERE username = '$username';"; $result = mysql_query($query); if(mysql_num_rows($result) < 1) //no such user exists { header('Location: login_form.php?login=fail'); die(); } $userData = mysql_fetch_array($result, MYSQL_ASSOC); db_disconnect(); $hash = hash('sha256', $password . $userData['salt']); if($hash != $userData['password']) //incorrect password { header('Location: login_form.php?login=fail'); die(); } else { validateUser(); //sets the session data for this user } header('Location: admin.php'); ?> and the session functions page that provides login functions contains this: session_functions.php <?php function validateUser() { session_regenerate_id (); //this is a security measure $_SESSION['valid'] = 1; $_SESSION['userid'] = $username; } function isLoggedIn() { if($_SESSION['valid']) return true; return false; } function logout() { $_SESSION = array(); //destroy all of the session variables if (ini_get("session.use_cookies")) { $params = session_get_cookie_params(); setcookie(session_name(), '', time() - 42000, $params["path"], $params["domain"], $params["secure"], $params["httponly"] ); } session_destroy(); } ?> I grabbed the sessions_functions.php code of an online tutorial, so it could be suspicious. Any ideas why the user logs in to the admin panel, tries to do something, is forced to re-login, and THEN is allowed to do stuff like normal in the admin panel?

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  • Help needed with Flash AS2 to AS3 conversion, having major problems...

    - by Mat
    Hi all, I have a project i need to update form AS2 to AS3 as i need some of the new functions available for vertical centering of text. My current AS2 code on the time line is as follows. var dataField = _root.dataField; var dataType = _root.dataType; var dataPage = _root.dataPage; var dataVar = _root.dataVar; _root.mc.onRelease = function() { getURL("index.php?page="+dataPage+"&num="+dataNum+"&"+dataType+"="+dataVar, "_self"); }; And my external AS file is as follows. import mx.transitions.Tween; /** * * StandardKey is attached to a movieclip in the library. * It handles the basic button behavior of the keyboard keys. * When each button is placed on the stage, it's instance name * will be the unique ID of the key. * */ class StandardKey extends MovieClip { /////////////////////////////////////// //Stage Elements var highlight:MovieClip; //End Stage Elements var highlightTween:Tween; function StandardKey(Void) { //Repaint the key with 0 alpha highlight._alpha = 0; } function onPress(Void):Void { //Do the highlight animation highlightTween.stop(); highlightTween = new Tween(highlight, "_alpha", mx.transitions.easing.Regular.easeInOut, 100, 0, 10, false); } } Here is my attempt at moving timeline and external AS2 to AS3 Timeline i now have : var dataField = this.dataField; var dataType = this.dataType; var dataPage = this.dataPage; var dataVar = this.dataVar; var dataNum = this.dataNum; _root.mc.onRelease = function() { navigateToURL(new URLRequest("index.php?page="+dataPage+"&num="+dataNum+"&"+dataType+"="+dataVar, "_self")); }; External AS3 i have package { import fl.transitions.Tween; import fl.transitions.easing.*; import flash.display.MovieClip; /** * * StandardKey is attached to a movieclip in the library. * It handles the basic button behavior of the keyboard keys. * When each button is placed on the stage, it's instance name * will be the unique ID of the key. * */ public class StandardKey extends MovieClip { /////////////////////////////////////// //Stage Elements var highlight:MovieClip; //End Stage Elements var highlightTween:Tween; public function StandardKey(Void) { //Repaint the key with 0 alpha highlight._alpha = 0; } public function onPress(Void):void { //Do the highlight animation highlightTween.stop(); highlightTween = new Tween(highlight, "_alpha", fl.transitions.easing.Regular.easeInOut, 100, 0, 10, false); } } } The errors i am currently getting are : Scene 1, Layer 'Label', Frame 1, Line 6 1120: Access of undefined property _root. Scene 1, Layer 'Label', Frame 1, Line 7 1137: Incorrect number of arguments. Expected no more than 1. If any one could help me work this out i would appreciate it very much. Kind regards Mat.

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  • How do I solve "Two different CRTLDLLs are loaded" when using packages in C++ Builder 2010?

    - by David M
    Hi, We are trying to split up our monolithic EXE into a combination of an EXE and several packages. So far, we have one package that we're trying to use, and when running the EXE Codeguard shows the following error on startup: CG Error Two different CRTLDLLs are loaded. CG might report false errors (C:\Windows\system32\CC32100MT.DLL) (D:\Projects\Foo\Bar.bpl) OK I read this as two different runtime libraries being loaded - one, the correct one (CC32100MT.dll), one incorrect, which is the package we're trying to use. Continuing to run the program shows odd errors, especially casting between classes or passing a pointer to a class as a parameter in a method that crosses the EXE/DLL boundary. Codeguard itself doesn't show any other errors at all though. How do we solve this? Some more details We've looked at as many things as we (the developer working on this and I) can collectively think of: Each project is built using runtime packages. The EXE host lists Bar in its package list. Each project is set to compile with dynamic RTL. However, changing this does not solve the problem. The package is linked to the EXE via its BPI file, but linking via a LIB makes no difference either. The EXE and BPL are compiled with the same project settings, where the same options exist for both types of project. We think, anyway :) There is only one copy of the BPL and BPI on the system: it's definitely linking to the right one. Examining the EXE and BPL with Depends and TDump show they are both using C:\Windows\system32\CC32100MT.DLL. They should both be using the one RTL. Creating a new project (a plain VCL forms application) and linking to the BPL (via its BPI) works fine. Something in the process of adding all the files and LIBs that make our EXE contain the code it needs to changes this, but we haven't been able to figure out what. The LIBs all either correspond to DLLs we use (flat C interface, usually look as though they were built with MSVC) or are simple projects with lots of related files, compiled to a lib for the purpose of linking into the EXE - these correspond roughly to the areas of the program we want to split to BPLs, by the way. There don't seem to be project options for the LIB projects that would affect RTL linking, unless we've missed them. I have exhaustively hunted through Depends and looked at all RTL and CC32*.dll files the EXE and every single DLL references. All are identical: rtl140.bpl and CC32100MT.DLL. Fully qualified paths show they are the same files, too. Everything should be using the one same run-time library. We're stumped. Absolutely stumped. We've had other problems using BPLs (they seem to be surprisingly tricky things, especially using C++) but have managed to solve them all. This one we've had no luck at all and we'd really appreciate any insights :) We're using C++Builder 2010 (as part of RAD Studio actually, but with little Delphi code apart from components.)

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  • Isn't it better to use a single try catch instead of tons of TryParsing and other error handling sometimes?

    - by Ryan Peschel
    I know people say it's bad to use exceptions for flow control and to only use exceptions for exceptional situations, but sometimes isn't it just cleaner and more elegant to wrap the entire block in a try-catch? For example, let's say I have a dialog window with a TextBox where the user can type input in to be parsed in a key-value sort of manner. This situation is not as contrived as you might think because I've inherited code that has to handle this exact situation (albeit not with farm animals). Consider this wall of code: class Animals { public int catA, catB; public float dogA, dogB; public int mouseA, mouseB, mouseC; public double cow; } class Program { static void Main(string[] args) { string input = "Sets all the farm animals CAT 3 5 DOG 21.3 5.23 MOUSE 1 0 1 COW 12.25"; string[] splitInput = input.Split(' '); string[] animals = { "CAT", "DOG", "MOUSE", "COW", "CHICKEN", "GOOSE", "HEN", "BUNNY" }; Animals animal = new Animals(); for (int i = 0; i < splitInput.Length; i++) { string token = splitInput[i]; if (animals.Contains(token)) { switch (token) { case "CAT": animal.catA = int.Parse(splitInput[i + 1]); animal.catB = int.Parse(splitInput[i + 2]); break; case "DOG": animal.dogA = float.Parse(splitInput[i + 1]); animal.dogB = float.Parse(splitInput[i + 2]); break; case "MOUSE": animal.mouseA = int.Parse(splitInput[i + 1]); animal.mouseB = int.Parse(splitInput[i + 2]); animal.mouseC = int.Parse(splitInput[i + 3]); break; case "COW": animal.cow = double.Parse(splitInput[i + 1]); break; } } } } } In actuality there are a lot more farm animals and more handling than that. A lot of things can go wrong though. The user could enter in the wrong number of parameters. The user can enter the input in an incorrect format. The user could specify numbers too large or too small for the data type to handle. All these different errors could be handled without exceptions through the use of TryParse, checking how many parameters the user tried to use for a specific animal, checking if the parameter is too large or too small for the data type (because TryParse just returns 0), but every one should result in the same thing: A MessageBox appearing telling the user that the inputted data is invalid and to fix it. My boss doesn't want different message boxes for different errors. So instead of doing all that, why not just wrap the block in a try-catch and in the catch statement just display that error message box and let the user try again? Maybe this isn't the best example but think of any other scenario where there would otherwise be tons of error handling that could be substituted for a single try-catch. Is that not the better solution?

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  • Why are transactions not rolling back when using SpringJUnit4ClassRunner/MySQL/Spring/Hibernate

    - by Trevor
    I am doing unit testing and I expect that all data committed to the MySQL database will be rolled back... but this isn't the case. The data is being committed, even though my log was showing that the rollback was happening. I've been wrestling with this for a couple days so my setup has changed quite a bit, here's my current setup. LoginDAOTest.java: @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations={"file:web/WEB-INF/applicationContext-test.xml", "file:web/WEB-INF/dispatcher-servlet-test.xml"}) @TransactionConfiguration(transactionManager = "transactionManager", defaultRollback = true) public class UserServiceTest { private UserService userService; @Test public void should_return_true_when_user_is_logged_in () throws Exception { String[] usernames = {"a","b","c","d"}; for (String username : usernames) { userService.logUserIn(username); assertThat(userService.isUserLoggedIn(username), is(equalTo(true))); } } ApplicationContext-Text.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver"/> <property name="url" value="jdbc:mysql://localhost:3306/test"/> <property name="username" value="root"/> <property name="password" value="Ecosim07"/> </bean> <tx:annotation-driven transaction-manager="transactionManager"/> <bean id="userService" class="Service.UserService"> <property name="userDAO" ref="userDAO"/> </bean> <bean id="userDAO" class="DAO.UserDAO"> <property name="hibernateTemplate" ref="hibernateTemplate"/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource"/> <property name="mappingResources"> <list> <value>/himapping/User.hbm.xml</value> <value>/himapping/setup.hbm.xml</value> <value>/himapping/UserHistory.hbm.xml</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager" p:sessionFactory-ref="sessionFactory"/> <bean id="hibernateTemplate" class="org.springframework.orm.hibernate3.HibernateTemplate"> <property name="sessionFactory"> <ref bean="sessionFactory"/> </property> </bean> </beans> I have been reading about the issue, and I've already checked to ensure that the MySQL database tables are setup to use InnoDB. Also I have been able to successfully implement rolling back of transactions outside of my testing suite. So this must be some sort of incorrect setup on my part. Any help would be greatly appreciated :)

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  • TypeError: Error #2007: Parameter child must be non-null.

    - by Bobby Francis Joseph
    I am running the following piece of code: package { import fl.controls.Button; import fl.controls.Label; import fl.controls.RadioButton; import fl.controls.RadioButtonGroup; import flash.display.Sprite; import flash.events.MouseEvent; import flash.text.TextFieldAutoSize; public class RadioButtonExample extends Sprite { private var j:uint; private var padding:uint = 10; private var currHeight:uint = 0; private var verticalSpacing:uint = 30; private var rbg:RadioButtonGroup; private var questionLabel:Label; private var answerLabel:Label; private var question:String = "What day is known internationally as Speak Like A Pirate Day?"; private var answers:Array = [ "August 12", "March 4", "September 19", "June 22" ]; public function RadioButtonExample() { setupQuiz(); } private function setupQuiz():void { setupQuestionLabel(); setupRadioButtons(); setupButton(); setupAnswerLabel(); } private function setupQuestionLabel():void { questionLabel = new Label(); questionLabel.text = question; questionLabel.autoSize = TextFieldAutoSize.LEFT; questionLabel.move(padding, padding + currHeight); currHeight += verticalSpacing; addChild(questionLabel); } private function setupAnswerLabel():void { answerLabel = new Label(); answerLabel.text = ""; answerLabel.autoSize = TextFieldAutoSize.LEFT; answerLabel.move(padding + 120, padding + currHeight); addChild(answerLabel); } private function setupRadioButtons():void { rbg = new RadioButtonGroup("question1"); createRadioButton(answers[0], rbg); createRadioButton(answers[1], rbg); createRadioButton(answers[2], rbg); createRadioButton(answers[3], rbg); } private function setupButton():void { var b:Button = new Button(); b.move(padding, padding + currHeight); b.label = "Check Answer"; b.addEventListener(MouseEvent.CLICK, checkAnswer); addChild(b); } private function createRadioButton(rbLabel:String, rbg:RadioButtonGroup):void { var rb:RadioButton = new RadioButton(); rb.group = rbg; rb.label = rbLabel; rb.move(padding, padding + currHeight); addChild(rb); currHeight += verticalSpacing; } private function checkAnswer(e:MouseEvent):void { if (rbg.selection == null) { return; } var resultStr:String = (rbg.selection.label == answers[2]) ? "Correct" : "Incorrect"; answerLabel.text = resultStr; } } } This is from Adobe Livedocs. http://www.adobe.com/livedocs/flash/9.0/ActionScriptLangRefV3/ I have added a Radiobutton to stage and then deleted it so that its there in the library. However I am getting the following error TypeError: Error #2007: Parameter child must be non-null. at flash.display::DisplayObjectContainer/addChildAt() at fl.controls::BaseButton/fl.controls:BaseButton::drawBackground() at fl.controls::LabelButton/fl.controls:LabelButton::draw() at fl.controls::Button/fl.controls:Button::draw() at fl.core::UIComponent/::callLaterDispatcher() Can anyone tell me what is going on and how to remove this error.

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  • Why does this Quicksort work?

    - by IVlad
    I find this Quicksort partitioning approach confusing and wrong, yet it seems to work. I am referring to this pseudocode. Note: they also have a C implementation at the end of the article, but it's very different from their pseudocode, so I don't care about that. I have also written it in C like this, trying to stay true to the pseudocode as much as possible, even if that means doing some weird C stuff: #include <stdio.h> int partition(int a[], int p, int r) { int x = a[p]; int i = p - 1; int j = r + 1; while (1) { do j = j - 1; while (!(a[j] <= x)); do i = i + 1; while (!(a[i] >= x)); if (i < j) { int t = a[i]; a[i] = a[j]; a[j] = t; } else { for (i = 1; i <= a[0]; ++i) printf("%d ", a[i]); printf("- %d\n", j); return j; } } } int main() { int a[100] = //{8, 6,10,13,15,8,3,2,12}; {7, 7, 6, 2, 3, 8, 4, 1}; partition(a, 1, a[0]); return 0; } If you run this, you'll get the following output: 1 6 2 3 4 8 7 - 5 However, this is wrong, isn't it? Clearly a[5] does not have all the values before it lower than it, since a[2] = 6 > a[5] = 4. Not to mention that 7 is supposed to be the pivot (the initial a[p]) and yet its position is both incorrect and lost. The following partition algorithm is taken from wikipedia: int partition2(int a[], int p, int r) { int x = a[r]; int store = p; for (int i = p; i < r; ++i) { if (a[i] <= x) { int t = a[i]; a[i] = a[store]; a[store] = t; ++store; } } int t = a[r]; a[r] = a[store]; a[store] = t; for (int i = 1; i <= a[0]; ++i) printf("%d ", a[i]); printf("- %d\n", store); return store; } And produces this output: 1 6 2 3 8 4 7 - 1 Which is a correct result in my opinion: the pivot (a[r] = a[7]) has reached its final position. However, if I use the initial partitioning function in the following algorithm: void Quicksort(int a[], int p, int r) { if (p < r) { int q = partition(a, p, r); // initial partitioning function Quicksort(a, p, q); Quicksort(a, q + 1, r); // I'm pretty sure q + r was a typo, it doesn't work with q + r. } } ... it seems to be a correct sorting algorithm. I tested it out on a lot of random inputs, including all 0-1 arrays of length 20. I have also tried using this partition function for a selection algorithm, in which it failed to produce correct results. It seems to work and it's even very fast as part of the quicksort algorithm however. So my questions are: Can anyone post an example on which the algorithm DOESN'T work? If not, why does it work, since the partitioning part seems to be wrong? Is this another partitioning approach that I don't know about?

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  • Recommended integration mechanism for bi-directional, authenticated, encrypted connection in C clien

    - by rcampbell
    Let me first give an example. Imagine you have a single server running a JVM application. This server keeps a collection of N equations, once for each client: Client #1: 2x Client #2: 1 + y Client #3: z/4 This server includes an HTTP interface so that random visitors can type https://www.acme.com/client/3 int their browsers and see the latest evaluated result of z/4. The tricky part is that either the client or the server may change the variable value at any time, informing the other party immediately. More specifically, Client #3 - a C app - can initially tell the server that z = 20. An hour later that same client informs the server that z = 23. Likewise the server can later inform the client that z = 28. As caf pointed out in the comments, there can be a race condition when values are changed by the client and server simultaneously. The solution would be for both client and server to send the operation performed in their message, which would need to be executed by the other party. To keep things simple, let's limit the operations to (commutative) addition, allowing us to disregard message ordering. For example, the client seeds the server with z = 20: server:z=20, client:z=20 server sends {+3} message (so z=23 locally) & client sends {-2} message (so z=18 locally) at the exact same time server receives {-2} message at some point, adds to his local copy so z=21 client receives {+3} message at some point, adds to his local copy so z=21 As long as all messages are eventually evaluated by both parties, the correct answer will eventually be given to the users of the client and server since we limited ourselves to commutative operations (addition of 3 and -2). This does mean that both client and server can be returning incorrect answers in the time it takes for messages to be exchanged and processed. While undesirable, I believe this is unavoidable. Some possible implementations of this idea include: Open an encrypted, always on TCP socket connection for communication Pros: no additional infrastructure needed, client and server know immediately if there is a problem (disconnect) with the other party, fairly straightforward (except the the encryption), native support from both JVM and C platforms Cons: pretty low-level so you end up writing a lot yourself (protocol, delivery verification, retry-on-failure logic), probably have a lot of firewall headaches during client app installation Asynchronous messaging (ex: ActiveMQ) Pros: transactional, both C & Java integration, free up the client and server apps from needing retry logic or delivery verification, pretty straightforward encryption, easy extensibility via message filters/routers/etc Cons: need additional infrastructure (message server) which must never fail, Database or file system as asynchronous integration point Same pros/cons as above but messier RESTful Web Service Pros: simple, possible reuse of the server's existing REST API, SSL figures out the encryption problem for you (maybe use RSA key a la GitHub for authentication?) Cons: Client now needs to run a C HTTP REST server w/SSL, client and server need retry logic. Axis2 has both a Java and C version, but you may be limited to SOAP. What other techniques should I be evaluating? What real world experiences have you had with these mechanisms? Which do you recommend for this problem and why?

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  • Where should I create my DbCommand instances?

    - by Domenic
    I seemingly have two choices: Make my class implement IDisposable. Create my DbCommand instances as private readonly fields, and in the constructor, add the parameters that they use. Whenever I want to write to the database, bind to these parameters (reusing the same command instances), set the Connection and Transaction properties, then call ExecuteNonQuery. In the Dispose method, call Dispose on each of these fields. Each time I want to write to the database, write using(var cmd = new DbCommand("...", connection, transaction)) around the usage of the command, and add parameters and bind to them every time as well, before calling ExecuteNonQuery. I assume I don't need a new command for each query, just a new command for each time I open the database (right?). Both of these seem somewhat inelegant and possibly incorrect. For #1, it is annoying for my users that I this class is now IDisposable just because I have used a few DbCommands (which should be an implementation detail that they don't care about). I also am somewhat suspicious that keeping a DbCommand instance around might inadvertently lock the database or something? For #2, it feels like I'm doing a lot of work (in terms of .NET objects) each time I want to write to the database, especially with the parameter-adding. It seems like I create the same object every time, which just feels like bad practice. For reference, here is my current code, using #1: using System; using System.Net; using System.Data.SQLite; public class Class1 : IDisposable { private readonly SQLiteCommand updateCookie = new SQLiteCommand("UPDATE moz_cookies SET value = @value, expiry = @expiry, isSecure = @isSecure, isHttpOnly = @isHttpOnly WHERE name = @name AND host = @host AND path = @path"); public Class1() { this.updateCookie.Parameters.AddRange(new[] { new SQLiteParameter("@name"), new SQLiteParameter("@value"), new SQLiteParameter("@host"), new SQLiteParameter("@path"), new SQLiteParameter("@expiry"), new SQLiteParameter("@isSecure"), new SQLiteParameter("@isHttpOnly") }); } private static void BindDbCommandToMozillaCookie(DbCommand command, Cookie cookie) { long expiresSeconds = (long)cookie.Expires.TotalSeconds; command.Parameters["@name"].Value = cookie.Name; command.Parameters["@value"].Value = cookie.Value; command.Parameters["@host"].Value = cookie.Domain; command.Parameters["@path"].Value = cookie.Path; command.Parameters["@expiry"].Value = expiresSeconds; command.Parameters["@isSecure"].Value = cookie.Secure; command.Parameters["@isHttpOnly"].Value = cookie.HttpOnly; } public void WriteCurrentCookiesToMozillaBasedBrowserSqlite(string databaseFilename) { using (SQLiteConnection connection = new SQLiteConnection("Data Source=" + databaseFilename)) { connection.Open(); using (SQLiteTransaction transaction = connection.BeginTransaction()) { this.updateCookie.Connection = connection; this.updateCookie.Transaction = transaction; foreach (Cookie cookie in SomeOtherClass.GetCookieArray()) { Class1.BindDbCommandToMozillaCookie(this.updateCookie, cookie); this.updateCookie.ExecuteNonQuery(); } transaction.Commit(); } } } #region IDisposable implementation protected virtual void Dispose(bool disposing) { if (!this.disposed && disposing) { this.updateCookie.Dispose(); } this.disposed = true; } public void Dispose() { this.Dispose(true); GC.SuppressFinalize(this); } ~Class1() { this.Dispose(false); } private bool disposed; #endregion }

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  • Submitting a URL into a Form without "http://", with "www.", or with neither

    - by John
    (EDITED) Hello, In the form below, the filed for <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> fine when a URL is submitted that has a "http://" at the beginning of it. However, it doesn't work if a URL is submitted with only a "www." in front of it, or with neither a "http://" nor a "www." How can I make it work in all if the submitted URL has any or none of the following at the beginning of it: http:// www. http://www. Thanks in advance, John Form: echo '<div class="submittitle">Submit an item.</div>'; echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; submit2.php: <?php if($_SERVER['REQUEST_METHOD'] == "POST"){header('Location: http://www...com/.../submit2.php');} require_once "header.php"; if (isLoggedIn() == true) { $remove_array = array('http://www.', 'http://', 'https://', 'https://www.', 'www.'); $cleanurl = str_replace($remove_array, "", $_POST['url']); $cleanurl = strtolower($cleanurl); $cleanurl = preg_replace('/\/$/','',$cleanurl); $cleanurl = stripslashes($cleanurl); $title = $_POST['title']; $uid = $_POST['uid']; $title = mysql_real_escape_string($title); $title = stripslashes($title); $cleanurl = mysql_real_escape_string($cleanurl); $site1 = 'http://' . $cleanurl; $displayurl = parse_url($site1, PHP_URL_HOST); function isURL($url1 = NULL) { if($url1==NULL) return false; $protocol = '(http://|https://)'; $allowed = '[-a-z0-9]{1,63}'; $regex = "^". $protocol . // must include the protocol '(' . $allowed . '\.)'. // 1 or several sub domains with a max of 63 chars '[a-z]' . '{2,6}'; // followed by a TLD if(eregi($regex, $url1)==true) return true; else return false; } if(isURL($site1)==true) mysql_query("INSERT INTO submission VALUES (NULL, '$uid', '$title', '$cleanurl', '$displayurl', NULL)"); else echo "<p class=\"topicu\">Not a valid URL.</p>\n"; } else { show_loginform(); } if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } require_once "footer.php"; ?>

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  • Supporting Piping (A Useful Hello World)

    - by blastthisinferno
    I am trying to write a collection of simple C++ programs that follow the basic Unix philosophy by: Make each program do one thing well. Expect the output of every program to become the input to another, as yet unknown, program. I'm having an issue trying to get the output of one to be the input of the other, and getting the output of one be the input of a separate instance of itself. Very briefly, I have a program add which takes arguments and spits out the summation. I want to be able to pipe the output to another add instance. ./add 1 2 | ./add 3 4 That should yield 6 but currently yields 10. I've encountered two problems: The cin waits for user input from the console. I don't want this, and haven't been able to find a simple example showing a the use of standard input stream without querying the user in the console. If someone knows of an example please let me know. I can't figure out how to use standard input while supporting piping. Currently, it appears it does not work. If I issue the command ./add 1 2 | ./add 3 4 it results in 7. The relevant code is below: add.cpp snippet // ... COMMAND LINE PROCESSING ... std::vector<double> numbers = multi.getValue(); // using TCLAP for command line parsing if (numbers.size() > 0) { double sum = numbers[0]; double arg; for (int i=1; i < numbers.size(); i++) { arg = numbers[i]; sum += arg; } std::cout << sum << std::endl; } else { double input; // right now this is test code while I try and get standard input streaming working as expected while (std::cin) { std::cin >> input; std::cout << input << std::endl; } } // ... MORE IRRELEVANT CODE ... So, I guess my question(s) is does anyone see what is incorrect with this code in order to support piping standard input? Are there some well known (or hidden) resources that explain clearly how to implement an example application supporting the basic Unix philosophy? @Chris Lutz I've changed the code to what's below. The problem where cin still waits for user input on the console, and doesn't just take from the standard input passed from the pipe. Am I missing something trivial for handling this? I haven't tried Greg Hewgill's answer yet, but don't see how that would help since the issue is still with cin. // ... COMMAND LINE PROCESSING ... std::vector<double> numbers = multi.getValue(); // using TCLAP for command line parsing double sum = numbers[0]; double arg; for (int i=1; i < numbers.size(); i++) { arg = numbers[i]; sum += arg; } // right now this is test code while I try and get standard input streaming working as expected while (std::cin) { std::cin >> arg; std::cout << arg << std::endl; } std::cout << sum << std::endl; // ... MORE IRRELEVANT CODE ...

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  • Defend PHP; convince me it isn't horrible

    - by Jason L
    I made a tongue-in-cheek comment in another question thread calling PHP a terrible language and it got down-voted like crazy. Apparently there are lots of people here who love PHP. So I'm genuinely curious. What am I missing? What makes PHP a good language? Here are my reasons for disliking it: PHP has inconsistent naming of built-in and library functions. Predictable naming patterns are important in any design. PHP has inconsistent parameter ordering of built-in functions, eg array_map vs. array_filter which is annoying in the simple cases and raises all sorts of unexpected behaviour or worse. The PHP developers constantly deprecate built-in functions and lower-level functionality. A good example is when they deprecated pass-by-reference for functions. This created a nightmare for anyone doing, say, function callbacks. A lack of consideration in redesign. The above deprecation eliminated the ability to, in many cases, provide default keyword values for functions. They fixed this in PHP 5, but they deprecated the pass-by-reference in PHP 4! Poor execution of name spaces (formerly no name spaces at all). Now that name spaces exist, what do we use as the dereference character? Backslash! The character used universally for escaping, even in PHP! Overly-broad implicit type conversion leads to bugs. I have no problem with implicit conversions of, say, float to integer or back again. But PHP (last I checked) will happily attempt to magically convert an array to an integer. Poor recursion performance. Recursion is a fundamentally important tool for writing in any language; it can make complex algorithms far simpler. Poor support is inexcusable. Functions are case insensitive. I have no idea what they were thinking on this one. A programming language is a way to specify behavior to both a computer and a reader of the code without ambiguity. Case insensitivity introduces much ambiguity. PHP encourages (practically requires) a coupling of processing with presentation. Yes, you can write PHP that doesn't do so, but it's actually easier to write code in the incorrect (from a sound design perspective) manner. PHP performance is abysmal without caching. Does anyone sell a commercial caching product for PHP? Oh, look, the designers of PHP do. Worst of all, PHP convinces people that designing web applications is easy. And it does indeed make much of the effort involved much easier. But the fact is, designing a web application that is both secure and efficient is a very difficult task. By convincing so many to take up programming, PHP has taught an entire subgroup of programmers bad habits and bad design. It's given them access to capabilities that they lack the understanding to use safely. This has led to PHP's reputation as being insecure. (However, I will readily admit that PHP is no more or less secure than any other web programming language.) What is it that I'm missing about PHP? I'm seeing an organically-grown, poorly-managed mess of a language that's spawning poor programmers. So convince me otherwise!

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  • header() function in php : No any redirection!

    - by jasmine
    I have written a very very very simple!! script in php. header redirection not working. 1- encoding : UTF-8 without BOM 2- with adding ob_start() the problem is countiueing. What is wrong in my code; login.php: <?php session_start(); require_once("funcs.php"); db_connection(); $username = $_POST['username']; $password = $_POST['pwd']; $submit = $_POST['login']; if($submit){ if (!filled_out($_POST)) { echo "please fill all fields"; } else{ $query = "SELECT * FROM users WHERE username ='{$username}' AND password ='{$password}'"; $result = mysql_query($query); if(mysql_num_rows($result) == 1){ $found_user = mysql_fetch_array($result); $_SESSION['id'] = $found_user['id']; $_SESSION['username'] = $found_user['username']; $_SESSION['password'] = $found_user['password']; setcookie(session_name(), '', time()+86400, '/'); header("Location: tst.php"); } else{ echo "incorrect username or password"; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org /TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form id="form1" name="form1" method="post" action=""> <p> <label for="username">Username:</label> <input type="text" name="username" id="username" /> </p> <p> <label for="textfield">Password</label> <input type="password" name="pwd" id="pwd" /> </p> <p> <input name="login" type="submit" id="login" value="Log in" /> </p> </form> </body> </html> <?php db_disconnect();?> and tst.php: <?php session_start(); require_once("funcs.php"); if (!isset($_SESSION['id'])){ header("Location : login.php"); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <table id="structure"> <tr> <td id="navigation">&nbsp; </td> <td id="page"> <?php echo "welcome"."". $_SESSION['username']; ?> </td> </tr> </table> </body> </html> <?php db_disconnect();?> wthit oppening tst.php directly, header() doesnot redirect to login.php

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  • Printing out variables in c changes values of variables

    - by George Wilson
    I have an odd problem with some c-programme here. I was getting some wrong values in a matrix I was finding the determinant of and so I started printing variables - yet found that by printing values out the actual values in the code changed. I eventually narrowed it down to one specific printf statement - highlighted in the code below. If I comment out this line then I start getting incorrect values in my determinent calculations, yet by printing it out I get the value out I expect Code below: #include <math.h> #include <stdio.h> #include <stdlib.h> #define NUMBER 15 double determinant_calculation(int size, double array[NUMBER][NUMBER]); int main() { double array[NUMBER][NUMBER], determinant_value; int size; array[0][0]=1; array[0][1]=2; array[0][2]=3; array[1][0]=4; array[1][1]=5; array[1][2]=6; array[2][0]=7; array[2][1]=8; array[2][2]=10; size=3; determinant_value=determinant_calculation(size, array); printf("\n\n\n\n\n\nDeterminant value is %lf \n\n\n\n\n\n", determinant_value); return 0; } double determinant_calculation(int size, double array[NUMBER][NUMBER]) { double determinant_matrix[NUMBER][NUMBER], determinant_value; int x, y, count=0, sign=1, i, j; /*initialises the array*/ for (i=0; i<(NUMBER); i++) { for(j=0; j<(NUMBER); j++) { determinant_matrix[i][j]=0; } } /*does the re-cursion method*/ for (count=0; count<size; count++) { x=0; y=0; for (i=0; i<size; i++) { for(j=0; j<size; j++) { if (i!=0&&j!=count) { determinant_matrix[x][y]=array[i][j]; if (y<(size-2)) { y++; } else { y=0; x++; } } } } //commenting this for loop out changes the values of the code determinent prints -7 when commented out and -3 (expected) when included! for (i=0; i<size; i++) { for(j=0; j<size; j++){ printf("%lf ", determinant_matrix[i][j]); } printf("\n"); } if(size>2) { determinant_value+=sign*(array[0][count]*determinant_calculation(size-1 ,determinant_matrix)); } else { determinant_value+=sign*(array[0][count]*determinant_matrix[0][0]); } sign=-1*sign; } return (determinant_value); } I know its not the prettiest (or best way) of doing what I'm doing with this code but it's what I've been given - so can't make huge changes. I don't suppose anyone could explain why printing out the variables can actually change the values? or how to fix it because ideally i don't want to!!

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  • What is the best free or low-cost Java reporting library (e.g. BIRT, JasperReports, etc.) for making

    - by Max3000
    I want to print, email and write to PDF very simple reports. The reports are basically a list of items, divided in various sections/columns. The sections are not necessarily identical. Think newspaper. I just wasted a solid 2 days of work trying to make this kind of reports using JasperReports. I find that Jasper is great for outputing "normalized" data. The kind that would come out of a database for instance, each row neatly describing an item and each item printed on a line. I'm simplifying a bit but that's the idea. However, given what I want to do I always ended up completely lost. Data not being displayed for no apparent reason, columns of texts never the correct size, column positioning always ending up incorrect, pagination not sanely possible (I was never able to figure it out; the FAQ gives an obscure workaround), etc. I came to the conclusion that Jasper is really not built to make the kind of reports I want. Am I missing something? I'm ready to pay for a tool, as long as the price is reasonable. By reasonable I mean a few $100s. Thanks. EDIT: To answer cetus, here is more information about the report I made in Jasper. What I want is something like this: text text text text ------------------- text | text text |---------- text | text text | text --------| text text |---------- text | text What I made in jasper is this: (detail band) subreport | subreport ------------------------------------ subreport | subreport ------------------------------------ subreport | subreport The subreports are all the same actual report. This report has one field (called "field") and basically just prints this field in a detail band. Hence, running a single subreport simply lists all items from the datasource. The datasource itself is a simple custom JRDatasource containing a collection of strings in the field "field". The datasource iterates over the collection until there are no more strings. Each subreport has its own datasource. I tried many different variations of the above, with all sorts of different properties for the report, subreports, etc. IMO, this is fairly simple stuff. However, the problems I encounter are as follows: Subreports starting from the 3rd don't show up when their position type is 'float'. They do show up when they have 'fix relative to top'. However, I don't want to do this because the first two subreports can be of any length. I can't make each subreport to stretch according to its own length. Instead, they either don't stretch at all (which is not desirable because they have different lenghts) or they stretch according to the longest subreport. This makes a weird layout for sure. Pagination doesn't happen. If some subreports fall outside the page, they simple don't show. One alternative is to increase the 'page height' considerably and the 'detail band height' accordingly. However, in this case it is not really possibly to know the total height in advance. So I'm stuck with calculating/guessing it myself, before the report is even generated. More importantly, long reports end up on one page and this is not acceptable (the printout text is too small, it's ugly/non-professional to have different reports with different PDF page lengths, etc.). BTW, I used iReport so it's possibly limitations of iReport I'm listing here and not of Jasper itself. That's one of the things I'm trying to find out asking this question here. One alternative would be to generate the jrxml myself with just static text but I'm afraid I'll encounter the very same limitations. Anyway, I just generally wasted so much time getting anything done with Jasper that I can't help thinking its not the right tool for the job. (Not to say that Jasper doesn't excel in what it's good at).

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  • [Qt/C++] Need help in optimizing a drawing code ...

    - by Ahmad
    Hello all ... I needed some help in trying to optimize this code portion ... Basically here's the thing .. I'm making this 'calligraphy pen' which gives the calligraphy effect by simply drawing a lot of adjacent slanted lines ... The problem is this: When I update the draw region using update() after every single draw of a slanted line, the output is correct, in the sense that updates are done in a timely manner, so that everything 'drawn' using the pen is immediately 'seen' the drawing.. however, because a lot (100s of them) of updates are done, the program slows down a little when run on the N900 ... When I try to do a little optimization by running update after drawing all the slanted lines (so that all lines are updated onto the drawing board through a single update() ), the output is ... odd .... That is, immediately after drawing the lines, they lines seem broken (they have vacant patches where the drawing should have happened as well) ... however, if I trigger a redrawing of the form window (say, by changing the size of the form), the broken patches are immediately fixed !! When I run this program on my N900, it gets the initial broken output and stays like that, since I don't know how to enforce a redraw in this case ... Here is the first 'optimized' code and output (partially correct/incorrect) void Canvas::drawLineTo(const QPoint &endPoint) { QPainter painter(&image); painter.setPen(QPen(Qt::black,1,Qt::SolidLine,Qt::RoundCap,Qt::RoundJoin)); int fx=0,fy=0,k=0; qPoints.clear(); connectingPointsCalculator2(qPoints,lastPoint.x(),lastPoint.y(),endPoint.x(),endPoint.y()); int i=0; int x,y; for(i=0;i<qPoints.size();i++) { x=qPoints.at(i).x(); y=qPoints.at(i).y(); painter.setPen(Qt::black); painter.drawLine(x-5,y-5,x+5,y+5); **// Drawing slanted lines** } **//Updating only once after many draws:** update (QRect(QPoint(lastPoint.x()-5,lastPoint.y()-5), QPoint(endPoint.x()+5,endPoint.y()+5)).normalized()); modified = true; lastPoint = endPoint; } Image right after scribbling on screen: http://img823.imageshack.us/img823/8755/59943912.png After re-adjusting the window size, all the broken links above are fixed like they should be .. Here is the second un-optimized code (its output is correct right after drawing, just like in the second picture above): void Canvas::drawLineTo(const QPoint &endPoint) { QPainter painter(&image); painter.setPen(QPen(Qt::black,1,Qt::SolidLine,Qt::RoundCap,Qt::RoundJoin)); int fx=0,fy=0,k=0; qPoints.clear(); connectingPointsCalculator2(qPoints,lastPoint.x(),lastPoint.y(),endPoint.x(),endPoint.y()); int i=0; int x,y; for(i=0;i<qPoints.size();i++) { x=qPoints.at(i).x(); y=qPoints.at(i).y(); painter.setPen(Qt::black); painter.drawLine(x-5,y-5,x+5,y+5); **// Drawing slanted lines** **//Updating repeatedly during the for loop:** update(QRect(QPoint(x-5,y-5), QPoint(x+5,y+5)).normalized());//.adjusted(-rad,-rad,rad,rad)); } modified = true; int rad = (myPenWidth / 2) + 2; lastPoint = endPoint; } Can anyone see what the issue might be ?

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  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

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  • Basic C question, concerning memory allocation and value assignment

    - by VHristov
    Hi there, I have recently started working on my master thesis in C that I haven't used in quite a long time. Being used to Java, I'm now facing all kinds of problems all the time. I hope someone can help me with the following one, since I've been struggling with it for the past two days. So I have a really basic model of a database: tables, tuples, attributes and I'm trying to load some data into this structure. Following are the definitions: typedef struct attribute { int type; char * name; void * value; } attribute; typedef struct tuple { int tuple_id; int attribute_count; attribute * attributes; } tuple; typedef struct table { char * name; int row_count; tuple * tuples; } table; Data is coming from a file with inserts (generated for the Wisconsin benchmark), which I'm parsing. I have only integer or string values. A sample row would look like: insert into table values (9205, 541, 1, 1, 5, 5, 5, 5, 0, 1, 9205, 10, 11, 'HHHHHHH', 'HHHHHHH', 'HHHHHHH'); I've "managed" to load and parse the data and also to assign it. However, the assignment bit is buggy, since all values point to the same memory location, i.e. all rows look identical after I've loaded the data. Here is what I do: char value[10]; // assuming no value is longer than 10 chars int i, j, k; table * data = (table*) malloc(sizeof(data)); data->name = "table"; data->row_count = number_of_lines; data->tuples = (tuple*) malloc(number_of_lines*sizeof(tuple)); tuple* current_tuple; for(i=0; i<number_of_lines; i++) { current_tuple = &data->tuples[i]; current_tuple->tuple_id = i; current_tuple->attribute_count = 16; // static in our system current_tuple->attributes = (attribute*) malloc(16*sizeof(attribute)); for(k = 0; k < 16; k++) { current_tuple->attributes[k].name = attribute_names[k]; // for int values: current_tuple->attributes[k].type = DB_ATT_TYPE_INT; // write data into value-field int v = atoi(value); current_tuple->attributes[k].value = &v; // for string values: current_tuple->attributes[k].type = DB_ATT_TYPE_STRING; current_tuple->attributes[k].value = value; } // ... } While I am perfectly aware, why this is not working, I can't figure out how to get it working. I've tried following things, none of which worked: memcpy(current_tuple->attributes[k].value, &v, sizeof(int)); This results in a bad access error. Same for the following code (since I'm not quite sure which one would be the correct usage): memcpy(current_tuple->attributes[k].value, &v, 1); Not even sure if memcpy is what I need here... Also I've tried allocating memory, by doing something like: current_tuple->attributes[k].value = (int *) malloc(sizeof(int)); only to get "malloc: * error for object 0x100108e98: incorrect checksum for freed object - object was probably modified after being freed." As far as I understand this error, memory has already been allocated for this object, but I don't see where this happened. Doesn't the malloc(sizeof(attribute)) only allocate the memory needed to store an integer and two pointers (i.e. not the memory those pointers point to)? Any help would be greatly appreciated! Regards, Vassil

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  • Please clarify how create/update happens against child entities of an aggregate root

    - by christian
    After much reading and thinking as I begin to get my head wrapped around DDD, I am a bit confused about the best practices for dealing with complex hierarchies under an aggregate root. I think this is a FAQ but after reading countless examples and discussions, no one is quite talking about the issue I'm seeing. If I am aligned with the DDD thinking, entities below the aggregate root should be immutable. This is the crux of my trouble, so if that isn't correct, that is why I'm lost. Here is a fabricated example...hope it holds enough water to discuss. Consider an automobile insurance policy (I'm not in insurance, but this matches the language I hear when on the phone w/ my insurance company). Policy is clearly an entity. Within the policy, let's say we have Auto. Auto, for the sake of this example, only exists within a policy (maybe you could transfer an Auto to another policy, so this is potential for an aggregate as well, which changes Policy...but assume it simpler than that for now). Since an Auto cannot exist without a Policy, I think it should be an Entity but not a root. So Policy in this case is an aggregate root. Now, to create a Policy, let's assume it has to have at least one auto. This is where I get frustrated. Assume Auto is fairly complex, including many fields and maybe a child for where it is garaged (a Location). If I understand correctly, a "create Policy" constructor/factory would have to take as input an Auto or be restricted via a builder to not be created without this Auto. And the Auto's creation, since it is an entity, can't be done beforehand (because it is immutable? maybe this is just an incorrect interpretation). So you don't get to say new Auto and then setX, setY, add(Z). If Auto is more than somewhat trivial, you end up having to build a huge hierarchy of builders and such to try to manage creating an Auto within the context of the Policy. One more twist to this is later, after the Policy is created and one wishes to add another Auto...or update an existing Auto. Clearly, the Policy controls this...fine...but Policy.addAuto() won't quite fly because one can't just pass in a new Auto (right!?). Examples say things like Policy.addAuto(VIN, make, model, etc.) but are all so simple that that looks reasonable. But if this factory method approach falls apart with too many parameters (the entire Auto interface, conceivably) I need a solution. From that point in my thinking, I'm realizing that having a transient reference to an entity is OK. So, maybe it is fine to have a entity created outside of its parent within the aggregate in a transient environment, so maybe it is OK to say something like: auto = AutoFactory.createAuto(); auto.setX auto.setY or if sticking to immutability, AutoBuilder.new().setX().setY().build() and then have it get sorted out when you say Policy.addAuto(auto) This insurance example gets more interesting if you add Events, such as an Accident with its PolicyReports or RepairEstimates...some value objects but most entities that are all really meaningless outside the policy...at least for my simple example. The lifecycle of Policy with its growing hierarchy over time seems the fundamental picture I must draw before really starting to dig in...and it is more the factory concept or how the child entities get built/attached to an aggregate root that I haven't seen a solid example of. I think I'm close. Hope this is clear and not just a repeat FAQ that has answers all over the place.

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • Using LINQ Distinct: With an Example on ASP.NET MVC SelectListItem

    - by Joe Mayo
    One of the things that might be surprising in the LINQ Distinct standard query operator is that it doesn’t automatically work properly on custom classes. There are reasons for this, which I’ll explain shortly. The example I’ll use in this post focuses on pulling a unique list of names to load into a drop-down list. I’ll explain the sample application, show you typical first shot at Distinct, explain why it won’t work as you expect, and then demonstrate a solution to make Distinct work with any custom class. The technologies I’m using are  LINQ to Twitter, LINQ to Objects, Telerik Extensions for ASP.NET MVC, ASP.NET MVC 2, and Visual Studio 2010. The function of the example program is to show a list of people that I follow.  In Twitter API vernacular, these people are called “Friends”; though I’ve never met most of them in real life. This is part of the ubiquitous language of social networking, and Twitter in particular, so you’ll see my objects named accordingly. Where Distinct comes into play is because I want to have a drop-down list with the names of the friends appearing in the list. Some friends are quite verbose, which means I can’t just extract names from each tweet and populate the drop-down; otherwise, I would end up with many duplicate names. Therefore, Distinct is the appropriate operator to eliminate the extra entries from my friends who tend to be enthusiastic tweeters. The sample doesn’t do anything with the drop-down list and I leave that up to imagination for what it’s practical purpose could be; perhaps a filter for the list if I only want to see a certain person’s tweets or maybe a quick list that I plan to combine with a TextBox and Button to reply to a friend. When the program runs, you’ll need to authenticate with Twitter, because I’m using OAuth (DotNetOpenAuth), for authentication, and then you’ll see the drop-down list of names above the grid with the most recent tweets from friends. Here’s what the application looks like when it runs: As you can see, there is a drop-down list above the grid. The drop-down list is where most of the focus of this article will be. There is some description of the code before we talk about the Distinct operator, but we’ll get there soon. This is an ASP.NET MVC2 application, written with VS 2010. Here’s the View that produces this screen: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<TwitterFriendsViewModel>" %> <%@ Import Namespace="DistinctSelectList.Models" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">     Home Page </asp:Content><asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">     <fieldset>         <legend>Twitter Friends</legend>         <div>             <%= Html.DropDownListFor(                     twendVM => twendVM.FriendNames,                     Model.FriendNames,                     "<All Friends>") %>         </div>         <div>             <% Html.Telerik().Grid<TweetViewModel>(Model.Tweets)                    .Name("TwitterFriendsGrid")                    .Columns(cols =>                     {                         cols.Template(col =>                             { %>                                 <img src="<%= col.ImageUrl %>"                                      alt="<%= col.ScreenName %>" />                         <% });                         cols.Bound(col => col.ScreenName);                         cols.Bound(col => col.Tweet);                     })                    .Render(); %>         </div>     </fieldset> </asp:Content> As shown above, the Grid is from Telerik’s Extensions for ASP.NET MVC. The first column is a template that renders the user’s Avatar from a URL provided by the Twitter query. Both the Grid and DropDownListFor display properties that are collections from a TwitterFriendsViewModel class, shown below: using System.Collections.Generic; using System.Web.Mvc; namespace DistinctSelectList.Models { /// /// For finding friend info on screen /// public class TwitterFriendsViewModel { /// /// Display names of friends in drop-down list /// public List FriendNames { get; set; } /// /// Display tweets in grid /// public List Tweets { get; set; } } } I created the TwitterFreindsViewModel. The two Lists are what the View consumes to populate the DropDownListFor and Grid. Notice that FriendNames is a List of SelectListItem, which is an MVC class. Another custom class I created is the TweetViewModel (the type of the Tweets List), shown below: namespace DistinctSelectList.Models { /// /// Info on friend tweets /// public class TweetViewModel { /// /// User's avatar /// public string ImageUrl { get; set; } /// /// User's Twitter name /// public string ScreenName { get; set; } /// /// Text containing user's tweet /// public string Tweet { get; set; } } } The initial Twitter query returns much more information than we need for our purposes and this a special class for displaying info in the View.  Now you know about the View and how it’s constructed. Let’s look at the controller next. The controller for this demo performs authentication, data retrieval, data manipulation, and view selection. I’ll skip the description of the authentication because it’s a normal part of using OAuth with LINQ to Twitter. Instead, we’ll drill down and focus on the Distinct operator. However, I’ll show you the entire controller, below,  so that you can see how it all fits together: using System.Linq; using System.Web.Mvc; using DistinctSelectList.Models; using LinqToTwitter; namespace DistinctSelectList.Controllers { [HandleError] public class HomeController : Controller { private MvcOAuthAuthorization auth; private TwitterContext twitterCtx; /// /// Display a list of friends current tweets /// /// public ActionResult Index() { auth = new MvcOAuthAuthorization(InMemoryTokenManager.Instance, InMemoryTokenManager.AccessToken); string accessToken = auth.CompleteAuthorize(); if (accessToken != null) { InMemoryTokenManager.AccessToken = accessToken; } if (auth.CachedCredentialsAvailable) { auth.SignOn(); } else { return auth.BeginAuthorize(); } twitterCtx = new TwitterContext(auth); var friendTweets = (from tweet in twitterCtx.Status where tweet.Type == StatusType.Friends select new TweetViewModel { ImageUrl = tweet.User.ProfileImageUrl, ScreenName = tweet.User.Identifier.ScreenName, Tweet = tweet.Text }) .ToList(); var friendNames = (from tweet in friendTweets select new SelectListItem { Text = tweet.ScreenName, Value = tweet.ScreenName }) .Distinct() .ToList(); var twendsVM = new TwitterFriendsViewModel { Tweets = friendTweets, FriendNames = friendNames }; return View(twendsVM); } public ActionResult About() { return View(); } } } The important part of the listing above are the LINQ to Twitter queries for friendTweets and friendNames. Both of these results are used in the subsequent population of the twendsVM instance that is passed to the view. Let’s dissect these two statements for clarification and focus on what is happening with Distinct. The query for friendTweets gets a list of the 20 most recent tweets (as specified by the Twitter API for friend queries) and performs a projection into the custom TweetViewModel class, repeated below for your convenience: var friendTweets = (from tweet in twitterCtx.Status where tweet.Type == StatusType.Friends select new TweetViewModel { ImageUrl = tweet.User.ProfileImageUrl, ScreenName = tweet.User.Identifier.ScreenName, Tweet = tweet.Text }) .ToList(); The LINQ to Twitter query above simplifies what we need to work with in the View and the reduces the amount of information we have to look at in subsequent queries. Given the friendTweets above, the next query performs another projection into an MVC SelectListItem, which is required for binding to the DropDownList.  This brings us to the focus of this blog post, writing a correct query that uses the Distinct operator. The query below uses LINQ to Objects, querying the friendTweets collection to get friendNames: var friendNames = (from tweet in friendTweets select new SelectListItem { Text = tweet.ScreenName, Value = tweet.ScreenName }) .Distinct() .ToList(); The above implementation of Distinct seems normal, but it is deceptively incorrect. After running the query above, by executing the application, you’ll notice that the drop-down list contains many duplicates.  This will send you back to the code scratching your head, but there’s a reason why this happens. To understand the problem, we must examine how Distinct works in LINQ to Objects. Distinct has two overloads: one without parameters, as shown above, and another that takes a parameter of type IEqualityComparer<T>.  In the case above, no parameters, Distinct will call EqualityComparer<T>.Default behind the scenes to make comparisons as it iterates through the list. You don’t have problems with the built-in types, such as string, int, DateTime, etc, because they all implement IEquatable<T>. However, many .NET Framework classes, such as SelectListItem, don’t implement IEquatable<T>. So, what happens is that EqualityComparer<T>.Default results in a call to Object.Equals, which performs reference equality on reference type objects.  You don’t have this problem with value types because the default implementation of Object.Equals is bitwise equality. However, most of your projections that use Distinct are on classes, just like the SelectListItem used in this demo application. So, the reason why Distinct didn’t produce the results we wanted was because we used a type that doesn’t define its own equality and Distinct used the default reference equality. This resulted in all objects being included in the results because they are all separate instances in memory with unique references. As you might have guessed, the solution to the problem is to use the second overload of Distinct that accepts an IEqualityComparer<T> instance. If you were projecting into your own custom type, you could make that type implement IEqualityComparer<T>, but SelectListItem belongs to the .NET Framework Class Library.  Therefore, the solution is to create a custom type to implement IEqualityComparer<T>, as in the SelectListItemComparer class, shown below: using System.Collections.Generic; using System.Web.Mvc; namespace DistinctSelectList.Models { public class SelectListItemComparer : EqualityComparer { public override bool Equals(SelectListItem x, SelectListItem y) { return x.Value.Equals(y.Value); } public override int GetHashCode(SelectListItem obj) { return obj.Value.GetHashCode(); } } } The SelectListItemComparer class above doesn’t implement IEqualityComparer<SelectListItem>, but rather derives from EqualityComparer<SelectListItem>. Microsoft recommends this approach for consistency with the behavior of generic collection classes. However, if your custom type already derives from a base class, go ahead and implement IEqualityComparer<T>, which will still work. EqualityComparer is an abstract class, that implements IEqualityComparer<T> with Equals and GetHashCode abstract methods. For the purposes of this application, the SelectListItem.Value property is sufficient to determine if two items are equal.   Since SelectListItem.Value is type string, the code delegates equality to the string class. The code also delegates the GetHashCode operation to the string class.You might have other criteria in your own object and would need to define what it means for your object to be equal. Now that we have an IEqualityComparer<SelectListItem>, let’s fix the problem. The code below modifies the query where we want distinct values: var friendNames = (from tweet in friendTweets select new SelectListItem { Text = tweet.ScreenName, Value = tweet.ScreenName }) .Distinct(new SelectListItemComparer()) .ToList(); Notice how the code above passes a new instance of SelectListItemComparer as the parameter to the Distinct operator. Now, when you run the application, the drop-down list will behave as you expect, showing only a unique set of names. In addition to Distinct, other LINQ Standard Query Operators have overloads that accept IEqualityComparer<T>’s, You can use the same techniques as shown here, with SelectListItemComparer, with those other operators as well. Now you know how to resolve problems with getting Distinct to work properly and also have a way to fix problems with other operators that require equality comparisons. @JoeMayo

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