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  • Create custom component based on LinearLayout, declaring layout in XML

    - by pheelicks
    I've been trying to create a Compound Control in Android 1.5 (as described here) but havn't been able to find any good examples on how to do this using an XML file to specify a layout. I'm fine with creating an Activity and then loading an xml file using the following in the constructor: setContentView(R.layout.main); However, I want to do this in subclass of LinearLayout - so I can use this compound component in other XML layouts. Something along the lines of: public class CustomView extends LinearLayout { public CustomView(Context context) { super(context); setupView(); } public CustomView(Context context, AttributeSet attrs) { super(context, attrs); setupView(); } public void setupView() { setContentView(R.layout.custom); // Not possible } } What is the correct way of going about doing this?

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  • if-else structure

    - by Halo
    I have these long statements that I will refer to as x,y etc. here. My conditional statements' structure goes like this: if(x || y || z || q){ if(x) do someth else if (y) do something if(z) do something else if(q) do something } else do smthing Is there a better, shorter way to write this thing? Thanks

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  • Problem with extending JPanel

    - by Halo
    I have an abstract entity: public abstract class Entity extends JPanel implements FocusListener And I have a TextEntity: public class TextEntity extends Entity Inside TextEntity's constructor I want to put a JTextArea that will cover the panel: textArea = new JTextArea(); textArea.setSize(getWidth(),getHeight()); add(textArea); But getWidth() and getHeight() returns 0. Is it a problem with the inheritance or the constructor?

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  • Caching instances in a jee web app

    - by SibzTer
    Hi, Consider the scenario of a typical webapp with JSFs on the front and ejb3, with Hibernate as JPA provider, talking to backend database such as mysql, etc. The main user actions are login and mostly CRUD operations (minus any D(elete) operations). And the App Server is GlassFish of course. Given this scenario, how and where all would one go about providing caching to improve performance? From what I have googled, I have seen that hibernate provides some sort of caching through different cache providers. Is there any sort of caching that can be provided for the jsf pages? How about session beans or entity beans on the ejb side of things? Also, I just read about memcached and was wondering if this was something to consider?

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  • Displaying NON-ASCII Characters using HttpClient

    - by Abdullah Gheith
    So, i am using this code to get the whole HTML of a website. But i dont seem to get non-ascii characters with me. all i get is diamonds with question mark. characters like this: å, appears like this: ? I doubt its because of the charset, what could it then be? Log.e("HTML", "henter htmlen.."); String url = "http://beep.tv2.dk"; HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); client.getParams().setParameter(CoreProtocolPNames.HTTP_ELEMENT_CHARSET, "UTF-8"); HttpGet request = new HttpGet(url); HttpResponse response = client.execute(request); Header h = HeaderValueFormatter response.addHeader(header) String html = ""; InputStream in = response.getEntity().getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder str = new StringBuilder(); String line = null; while((line = reader.readLine()) != null) { str.append(line); } in.close(); //b = false; html = str.toString();

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  • Dynamically refresh JTextArea as processing occurs?

    - by digiarnie
    I am trying to create a very simple Swing UI that logs information onto the screen via a JTextArea as processing occurs in the background. When the user clicks a button, I want each call to: textArea.append(someString + "\n"); to immediately show up in the UI. At the moment, the JTextArea does not show all log information until the processing has completed after clicking the button. How can I get it to refresh dynamically?

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  • How can you tell if an activities state is stored?

    - by Joren
    I have an activity which pulls some JSON from my server, and then uses it to draw a list. That list launches further activities. My problem is that I can't figure out a way to tell if the activity is still alive when you go back to it, so I end up re-querying my JSON from the server and redrawing the list every time the user goes back to the activity. How can I tell if my activity is still alive so I can skip the redraw?

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  • Does anyone know why my maps only show grid

    - by NickTFried
    I've doubled checked my API key is right and that is right I doubled checked that it was correct. Here is my source and XML could anyone check to see what is wrong. Also I make sure I have internet. <?xml version="1.0" encoding="utf-8"?> <uses-permission android:name="android.permissions.INTERNET"/> <uses-permission android:name="android.permissions.ACCESS_FINE_LOCATION"/> <application android:icon="@drawable/icon" android:label="@string/app_name"> <uses-library android:name="com.google.android.maps" /> <activity android:name=".CadetCommand" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name="RedLight"></activity> <activity android:name="PTCalculator"></activity> <activity android:name="LandNav"></activity> </application> <uses-sdk android:minSdkVersion="4"/> package edu.elon.cs.mobile; import com.google.android.maps.MapActivity; import com.google.android.maps.MapView; import android.os.Bundle; public class LandNav extends MapActivity{ public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.landnav); } @Override protected boolean isRouteDisplayed() { return false; } }

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  • Locking a file to verify a single execution of a service. How reliable?

    - by Camilo Díaz
    Hello, I am deploying a little service to an UNIX(AIX) system. I want to check if there is no active instance of that service running when starting it. How reliable is to implement that check like this? Try to acquire a lock on a file (w/ FileChannel) If succeeds, keep lock and continue execution If fails, exit and refuse to run the main body I am aware of software like the Tanuki wrapper, however, I'm longing for a simpler(maybe not portable) solution. Regarding PIDFILE(s): I want to avoid using them if possible, as I don't have administrative rights on the machine, neither knowledge in AIX's shell programming.

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  • Delete element from array

    - by Julio Diaz
    Is there a way I can get rid of some elements in an array. for instance, if i have this array int testArray[] = {0,2,0,3,0,4,5,6} Is there a "fast" way to get rid of the elements that equal 0 int resultArray[] = {2,3,4,5,6} I tried this function but I got lost using Lists public int[] getRidOfZero(int []s){ List<> result=new ArrayList<>(); for(int i=0; i<s.length; i++){ if(s[i]<0){ int temp = s[i]; result.add(temp); } } return result.toArray(new int[]); }

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  • Help naming a class that has a single public method called Execute()

    - by devoured elysium
    I have designed the following class that should work kind of like a method (usually the user will just run Execute()): public abstract class ??? { protected bool hasFailed = false; protected bool hasRun = false; public bool HasFailed { get { return hasFailed; } } public bool HasRun { get { return hasRun; } } private void Restart() { hasFailed = false; hasRun = false; } public bool Execute() { ExecuteImplementation(); bool returnValue = hasFailed; Restart(); return returnValue; } protected abstract void ExecuteImplementation(); } My question is: how should I name this class? Runnable? Method(sounds awkward)?

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  • Sending JSON(jQuery) to PHP and decoding it

    - by dscher
    I can't for the life of me figure out what I'm doing wrong. It seems like it should be simple because I can't find anyone else with this issue but I can't figure out to send basic data via javascript(jQuery) to PHP and decode it. For the sake of simplicity, this is what I have: JAVASCRIPT var json_data = { "name" : "john doe" }; $.ajax({ type: "POST", url: "../bin/process.php", dataType: "json", data: json_data }); and my PHP FILE $arr = json_decode("json_data", true); $fp = fopen('data.txt', "w"); fwrite($fp, $arr['name']); fclose($fp); The file I'm writing ends up with nothing in it. If I do an: fwrite($fp, 'test'); I get a file with the word test in it but no matter what I do I don't get the json data I sent. Can someone please share a thorough example of A to Z. Thanks for any help.

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  • What are the advantages of using J2EE over ASP.net?

    - by m_oLogin
    We are currently planning to launch a couple of internal web projects in the future. Our company's dev teams are mostly experienced in J2EE and have worked with it for years. Today, we have the choice of launching a couple of our projects on .net. I have checked out a couple of sources on the net, and it seems like the "J2EE vs ASP.net" combat brings out as much discord as the overseen "Apple vs Microsoft" or "Free Eclipse vs Visual Studio"... Nevertheless, I have been somewhat quite impressed with ASP.net's abilities to create great things with huge simplicity (for ex. asp.net ajax's demos). No more tons of xmls to play with, no more tons of frameworks to configure (we usually use the famous combo struts/spring/hibernate)... It just seemed to me that ASP.net had some good advantages over J2EE, but then again, I may speak by ignorance. What I want to know is this : What are the real advantages of using J2EE over ASP.net? Is there anything that cannot be done in ASP.net that can be done in J2EE? Once the frameworks are all in place and configured, is it faster to develop apps in J2EE than it is in .net? Are the applications generally easier to maintain in J2EE than in ASP.net? Is it worth it for some developpers to leave their J2EE knowledge on the side and move on to ASP.net if it does exactly the same thing?

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  • Import? Initialize? what do to?

    - by Jeremy B
    I'm working on homework and I'm close but I am having an issue. I just learned how to work with packages in eclipse so I have a class that is importing another class from a package (I think I said that right) The main prompts the user to enter an integer between -100 and 100 and I am having an issue with validating it. I know the issue is where I'm importing I'm just unsure the direction I need to go to fix it. This is a section of my main code. (my issue starts with the last couple lines if you want to skip ahead) import myUtils.util.Console; public class ConsoleTestApp { public static void main(String args[]) { // create the Console object Console c = new Console(); // display a welcome message c.println("Welcome to the Console Tester application"); c.println(); // int c.println("Int Test"); int i = c.getIntWithinRange("Enter an integer between -100 and 100: ", -101, 101); c.println(); I have a class called Console that is located in another package that I believe I have properly imported. here is the code I am stuck on in my console class. public int getIntWithinRange(String prompt, int min, int max) { int i = 0; boolean isValid = false; while (isValid == false) { System.out.println(prompt); if (sc.hasNextInt()) { //if user chooses menu option less than 1 the program will print an error message i = sc.nextInt(); if (i < min) { System.out.println("Error! Please enter an int greater than -100"); } else if (i > max) { System.out.println("Error! Please enter an int less than 100"); } else isValid = true; } else System.out.println("Error! Invalid number value"); sc.nextLine(); } // return the int return i; } when I run this I keep getting my last print which is an invalid number value. am I not importing the code from the main method in the other console properly?

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  • Avoiding duplication in JavaDoc comments

    - by TERACytE
    I am writing a class where the same xml is used between some methods. e.g. /** * Sample Response: * <xmp> * <myXML> * <stuff> data </stuff> * </myXML> * </xmp> */ CommonXML Method1(); /** * Sample Submission: * <xmp> * <myXML> * <stuff> data </stuff> * </myXML> * </xmp> */ void Method2(CommonXML xml); I would like to write my documentation so that if the xml changes I have one resource to modify, rather than updating all of the JavaDoc for the affected methods. Does anyone know how to accomplish this?

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  • Migrate existing Maven Project into an OSGI Bundle

    - by user1706291
    i am new to the whole OSGi stuff and my task is to create an OSGi Bundle out from an exisitng maven project. To get started i decided to pick the smallest part and starting with it: Here is the pom.xml project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd"> <modelVersion>4.0.0</modelVersion> <parent> <artifactId>cross</artifactId> <groupId>net.sf.maltcms</groupId> <version>1.2.12-SNAPSHOT</version> </parent> <artifactId>cross-main</artifactId> <packaging>jar</packaging> <name>cross-main</name> <dependencies> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-annotations</artifactId> <version>${project.version}</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-event</artifactId> <version>${project.version}</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-tools</artifactId> <version>${project.version}</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-exception</artifactId> <version>${project.version}</version> </dependency> <dependency> <groupId>commons-codec</groupId> <artifactId>commons-codec</artifactId> <version>1.4</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-main-api</artifactId> <version>${project.version}</version> <exclusions> <exclusion> <artifactId>commons-logging</artifactId> <groupId>commons-logging</groupId> </exclusion> </exclusions> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-aop</artifactId> <version>3.0.6.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-asm</artifactId> <version>3.0.6.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-beans</artifactId> <version>3.0.6.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-context</artifactId> <version>3.0.6.RELEASE</version> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-core</artifactId> <version>3.0.6.RELEASE</version> <exclusions> <exclusion> <artifactId>commons-logging</artifactId> <groupId>commons-logging</groupId> </exclusion> </exclusions> </dependency> <dependency> <groupId>org.springframework</groupId> <artifactId>spring-expression</artifactId> <version>3.0.6.RELEASE</version> </dependency> <dependency> <groupId>commons-io</groupId> <artifactId>commons-io</artifactId> <version>2.1</version> </dependency> <dependency> <groupId>net.sf.ehcache</groupId> <artifactId>ehcache-core</artifactId> <version>2.4.6</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>cross-math</artifactId> <version>${project.version}</version> </dependency> <dependency> <groupId>com.db4o</groupId> <artifactId>db4o-all</artifactId> <version>8.0.249</version> </dependency> <dependency> <groupId>net.sf.mpaxs</groupId> <artifactId>mpaxs-spi</artifactId> <version>1.6.10</version> </dependency> <dependency> <groupId>net.sf.mpaxs</groupId> <artifactId>mpaxs-server</artifactId> <version>1.6.10</version> </dependency> </dependencies> I did some research and found the Apache Bundle Plugin for maven and changed the pom to this <packaging>bundle</packaging> and added <build> <plugins> <plugin> <groupId>org.apache.felix</groupId> <artifactId>maven-bundle-plugin</artifactId> <extensions>true</extensions> <configuration> <instructions> <Bundle-SymbolicName>${pom.artifactId}</Bundle-SymbolicName> </instructions> </configuration> </plugin> </plugins> </build> mvn clean install went fine and i got a jar file containing the manifest, but of course the bundle could not be resolved BundleException: The bundle "cross-main_1.2.12.SNAPSHOT [30]" could not be resolved. Reason: Missing Constraint: Import-Package: com.db4o; version="[8.0.0,9.0.0) To make a long story short: What are the possibiliteis to migrate a maven application into an OSGi Bundle? Espacially how to manage the dependencys

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  • [hibernate - jpa] @OneToOne annotoation problem (i think...)

    - by blow
    Hi all, im new in hibernate and JPA and i have some problems with annotations. My target is to create this table in db (PERSON_TABLE with personal-details) ID ADDRESS NAME SURNAME MUNICIPALITY_ID First of all, i have a MUNICIPALITY table in db containing all municipality of my country. I mapped this table in this ENTITY: @Entity public class Municipality implements Serializable { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String country; private String province; private String name; @Column(name="cod_catasto") private String codCatastale; private String cap; public Municipality() { } ... Then i make an EMBEDDABLE class Address containing fields that realize a simple address... @Embeddable public class Address implements Serializable { @OneToOne(cascade=CascadeType.ALL) @JoinColumn(name="id_municipality") private Municipality municipality; @Column(length=45) private String address; public Address() { } ... Finally i embedded this class into Person ENTITY @Entity public class Person implements Serializable { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String name; private String surname; @Embedded private Address address; public Person() { } ... All works good when i have to save a new Person record, in fact hibernate creates a PERSON_TABLE as i want, but if i try to retrieve a Person record i have an exception. HQL is simply "from Person" The excpetion is (Entities is the package containing all classes above-mentioned): org.hibernate.AnnotationException: @OneToOne or @ManyToOne on Entities.Person.address.municipality references an unknown entity: Entities.Municipality Is the @OneToOne annotation the problem? Thanks.

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  • Does this Maven plugin really have an invalid descriptor?

    - by ovr
    COMMAND: mvn org.apache.maven.plugins:maven-archetype-plugin:2.0-alpha-4:generate -DarchetypeGroupId=org.beardedgeeks -DarchetypeArtifactId =gae-eclipse-maven-archetype -DarchetypeVersion=1.1.2 -DarchetypeRepository=http://beardedgeeks.googlecode.com/svn/repository/release s OUTPUT: [INFO] Scanning for projects... [INFO] ------------------------------------------------------------------------ [ERROR] BUILD ERROR [INFO] ------------------------------------------------------------------------ [INFO] Internal error in the plugin manager getting plugin 'org.apache.maven.plugins:maven-archetype-plugin': Plugin 'org.apache.maven .plugins:maven-archetype-plugin:2.0-alpha-4' has an invalid descriptor: 1) Plugin's descriptor contains the wrong group ID: net.kindleit 2) Plugin's descriptor contains the wrong artifact ID: maven-gae-plugin 3) Plugin's descriptor contains the wrong version: 0.5.9 [INFO] ------------------------------------------------------------------------ [INFO] For more information, run Maven with the -e switch [INFO] ------------------------------------------------------------------------ [INFO] Total time: < 1 second [INFO] Finished at: Wed Jun 09 20:48:35 CEST 2010 [INFO] Final Memory: 3M/15M [INFO] ------------------------------------------------------------------------ I have a hard time believing this Maven plugin has an invalid descriptor since other people seem to be using it with no problem. Am I doing something wrong?

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  • In this example, would Customer or AccountInfo properly be the entity group parent?

    - by Badhu Seral
    In this example, the Google App Engine documentation makes the Customer the entity group parent of the AccountInfo entity. Wouldn't AccountInfo encapsulate Customer rather than the other way around? Normally I would think of an AccountInfo class as including all of the information about the Customer. import javax.jdo.annotations.IdGeneratorStrategy; import javax.jdo.annotations.PersistenceCapable; import javax.jdo.annotations.Persistent; import javax.jdo.annotations.PrimaryKey; import com.google.appengine.api.datastore.Key; import com.google.appengine.api.datastore.KeyFactory; @PersistenceCapable public class AccountInfo { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Key key; public void setKey(Key key) { this.key = key; } } // ... KeyFactory.Builder keyBuilder = new KeyFactory.Builder(Customer.class.getSimpleName(), "custid985135"); keyBuilder.addChild(AccountInfo.class.getSimpleName(), "acctidX142516"); Key key = keyBuilder.getKey(); AccountInfo acct = new AccountInfo(); acct.setKey(key); pm.makePersistent(acct);

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  • How to get dynamically session object in struts2

    - by Sujeet Singh
    I am trying to get dynamically session object in struts2 application. <s:if test="%{#session['resToken'].bookingType == 1}"> resToken can be get by <s:property value="%{resToken}">.. But I can't write <s:property> within <s:if test=""> its giving me error of double quotes.. org.apache.jasper.JasperException: /WEB-INF/jsp/booking/banquet/guest-Info-View.jsp(150,40) Unterminated &lt;s:if tag

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  • Make XStream ignore one specific private variable

    - by Tigraine
    Hi guys, I have a little problem with a class I am currently writing a save function for. I'm using XStream (com.thoughtworks.xstream) to serialize a class to XML using the DOMDriver. The class looks like this: public class World { private Configuration config; public World(Configuration config) { this.config = config; } } So, the issue here is that I do not want to serialize Configuration when serializing world, rather I'd like to give XStream a preconstructed Configuration instance when calling fromXml(). Problem here is mainly class design, Configuration holds a private reference to the GUI classes and therefore serializing Configuration means serializing the whole application completely with GUI etc.. And that's kind of bad. Is there a way to instruct XStream to not serialize the private field config, and upon load supply XStream with a configuration instance to use? greetings Daniel

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  • Eclipse gives me a weird error when compiling...

    - by Legend
    I have this function which returns a datatype InetAddress[] public InetAddress [] lookupAllHostAddr(String host) throws UnknownHostException { Name name = null; try { name = new Name(host); } catch (TextParseException e) { throw new UnknownHostException(host); } Record [] records = null; if (preferV6) records = new Lookup(name, Type.AAAA).run(); if (records == null) records = new Lookup(name, Type.A).run(); if (records == null && !preferV6) records = new Lookup(name, Type.AAAA).run(); if (records == null) throw new UnknownHostException(host); InetAddress[] array = new InetAddress[records.length]; for (int i = 0; i < records.length; i++) { Record record = records[i]; if (records[i] instanceof ARecord) { ARecord a = (ARecord) records[i]; array[i] = a.getAddress(); } else { AAAARecord aaaa = (AAAARecord) records[i]; array[i] = aaaa.getAddress(); } } return array; } Eclipse complains that the return type should be byte[][] but when I change the return type to byte[][], it complains that the function is returning the wrong data type. I'm stuck in a loop. Does anyone know what is happening here?

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  • How to find which file is open in eclipse editor without using IEditorPart?

    - by Destructor
    I want to know which file (or even project is enough) is opened in eclipse editor? I know we can do this once we get IEditorPart from doSetInput method, IFile file = ((IFileEditorInput) iEditorPart).getFile(); But I want the name of file without using IEditorPart, how can I do the same? Checking which is the selected file in project explorer is not of much help because, user can select multiple files at once and open all simultaneously and I did not way to distinguish which file opened at what time. Adding more info: I have an editor specified for a particular type of file, now every time it opens, during intializing editor I have some operation to do based on project properties. While initializing editor, I need the file handle (of the one which user opened/double clicked) or the corresponding project handle. I have my editor something this way: public class MyEditor extends TextEditor{ @Override protected void initializeEditor() { setSourceViewerConfiguration(new MySourceViewerConfiguration( CDTUITools.getColorManager(), store, "MyPartitions", this)); } //other required methods @Override protected void doSetInput(IEditorInput input) throws CoreException { if(input instanceof IFileEditorInput) { IFile file = ((IFileEditorInput) input).getFile(); } } } as I have done in the doSetInput() method , I want the file handle(even project handle is sufficient). But the problem is in initializeEditor() function there is no reference to editorInput, hence I am unable to get the file handle. In the source viewer configuration file, I set the code scanners and this needs some project specific information that will set the corresponding rules.

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