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  • C++ for games

    - by Bi
    Hi I am a relatively newbie in C++ and worked in the game industry for a few months. I am looking to get back to the industry and understand that one needs to be a very good C++ programmer (mainly bcos of how competitive it is to get into making games). I was wondering if there are really good websites online that would help with that. Basically I am looking for something that would help me MASTER C++ concepts as well as help me be a good coder through programming examples that I can code. Thanks Bi

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  • Insertion sort invariant assertion fails

    - by user1661211
    In the following code at the end of the for loop I use the assert function in order to test that a[i+1] is greater than or equal to a[i] but I get the following error (after the code below). Also in c++ the assert with the following seems to work just fine but in python (the following code) it does not seem to work...anyone know why? import random class Sorting: #Precondition: An array a with values. #Postcondition: Array a[1...n] is sorted. def insertion_sort(self,a): #First loop invariant: Array a[1...i] is sorted. for j in range(1,len(a)): key = a[j] i = j-1 #Second loop invariant: a[i] is the greatest value from a[i...j-1] while i >= 0 and a[i] > key: a[i+1] = a[i] i = i-1 a[i+1] = key assert a[i+1] >= a[i] return a def random_array(self,size): b = [] for i in range(0,size): b.append(random.randint(0,1000)) return b sort = Sorting() print sort.insertion_sort(sort.random_array(10)) The Error: Traceback (most recent call last): File "C:\Users\Albaraa\Desktop\CS253\Programming 1\Insertion_Sort.py", line 27, in <module> print sort.insertion_sort(sort.random_array(10)) File "C:\Users\Albaraa\Desktop\CS253\Programming 1\Insertion_Sort.py", line 16, in insertion_sort assert a[i+1] >= a[i] AssertionError

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  • cannot see values from list in c#

    - by PriceCheaperton
    I have the following code: But i cannot response write the values in the list for debugging purposes... public void LottoWinners(object sender, EventArgs e) { Dictionary<int, int> number = new Dictionary<int, int>(); Random generator = new Random(); while (number.Count < 6) { number[generator.Next(1, 49)] = 1; } int[] lotto = number.Keys.OrderBy(n => n).ToArray(); List<int> lst = lotto.OfType<int>().ToList(); StringBuilder builder = new StringBuilder(); for (int i = 0; i < lst.Count; i++) // Loop through List with for { builder.Append(lst).Append("|"); // Append string to StringBuilder } string result = builder.ToString(); // Get string from StringBuilder Response.Write(result); } But all i see is as my result. I should be seeing the values of my list! System.Collections.Generic.List`1

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  • Criteria for triggering garbage collection in .Net

    - by Kennet Belenky
    I've come across some curious behavior with regard to garbage collection in .Net. The following program will throw an OutOfMemoryException very quickly (after less than a second on a 32-bit, 2GB machine). The Foo finalizer is never called. class Foo { static Dictionary<Guid, WeakReference> allFoos = new Dictionary<Guid, WeakReference>(); Guid guid = Guid.NewGuid(); byte[] buffer = new byte[1000000]; static Random rand = new Random(); public Foo() { // Uncomment the following line and the program will run forever. // rand.NextBytes(buffer); allFoos[guid] = new WeakReference(this); } ~Foo() { allFoos.Remove(guid); } static public void Main(string args[]) { for (; ; ) { new Foo(); } } } If the rand.nextBytes line is uncommented, it will run ad infinitum, and the Foo finalizer is regularly invoked. Why is that? My best guess is that in the former case, either the CLR or the Windows VMM is lazy about allocating physical memory. The buffer never gets written to, so the physical memory is never used. When the address space runs out, the system crashes. In the latter case, the system runs out of physical memory before it runs out of address space, the GC is triggered and the objects are collected. However, here's the part I don't get. Assuming my theory is correct, why doesn't the GC trigger when the address space runs low? If my theory is incorrect, then what's the real explanation?

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  • Session scoped bean as class attribute of Spring MVC Controller

    - by Sotirios Delimanolis
    I have a User class: @Component @Scope("session") public class User { private String username; } And a Controller class: @Controller public class UserManager { @Autowired private User user; @ModelAttribute("user") private User createUser() { return user; } @RequestMapping(value = "/user") public String getUser(HttpServletRequest request) { Random r = new Random(); user.setUsername(new Double(r.nextDouble()).toString()); request.getSession().invalidate(); request.getSession(true); return "user"; } } I invalidate the session so that the next time i got to /users, I get another user. I'm expecting a different user because of user's session scope, but I get the same user. I checked in debug mode and it is the same object id in memory. My bean is declared as so: <bean id="user" class="org.synchronica.domain.User"> <aop:scoped-proxy/> </bean> I'm new to spring, so I'm obviously doing something wrong. I want one instance of User for each session. How?

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  • question about permutation problem

    - by davit-datuashvili
    i have posted similar problem here http://stackoverflow.com/questions/2920315/permutation-of-array but i want following we know that with length n there is n! possible permutation from which one such that all element are in order they are in sorted variant so i want break permutation when array is in order and print result but something is wrong i think that problem is repeated of permutation here is my code import java.util.*; public class permut{ public static Random r=new Random(); public static void display(int a[],int n){ for (int i=0;i<n;i++){ System.out.println(a[i]); } } public static void Permut(int a[],int n){ int j=0; int k=0; while (j<fact(n)){ int s=r.nextInt(n); for (int i=0;i<n;i++){ k=a[i]; a[i]=a[s]; a[s]=k; } j++; if (sorted(a,n)) display(a,n); break; } } public static void main(String[]args){ int a[]=new int[]{3,4,1,2}; int n=a.length; Permut(a,n); } public static int fact(int n){ if (n==0 || (n==1) ) return 1; return n*fact(n-1); } public static boolean sorted(int a[],int n ){ boolean flag=false; for (int i=0;i<n-1;i++){ if (a[i]<a[i+1]){ flag=true; } else{ flag=false; } } return flag; } } can anybody help me? result is nothing

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  • Matlab Coin Toss Simulation

    - by user1772959
    I have to write some code in Matlab that simulates tossing a coin 150 times. I have to count how many times the coin lands on heads and create a vector that gives a running percentage of the heads. Then I have to make a table of the number of trials, random 'flips", and the running percentages of heads. I assume random "flips" means heads or tails for that trial. I also have to create a line graph with trials on the x-axis and probabilities (percentages) on the y-axis. I'm assuming the percentages are just the percentage of getting heads. Sorry if this post was long. I figure giving the details now will make it easier to see what I was trying to do with the code. I didn't create the table or plot yet because I'm not even sure how to code for the actual problem. NUM_TRIALS = 150; trials = 1:NUM_TRIALS; heads = 0; t = rand(NUM_TRIALS,1); for i = trials if (t < 0.5) heads = heads + 1; end z = zeros(NUM_TRIALS,1); percent_h = heads/trials; end

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  • Dealbreakers for new programming jobs?

    - by Echostorm
    What might be said or implied at an interview or job posting that should set off alarm bells for a coder? I'm still only a few years in the industry but I already know to look out for excessive red tape and bureaucracy. Cubes and a noisy office also tell me that I'll be both miserable and unproductive and that management does not appreciate what coders need to work well. Edit: The way things are going I'm taking extra time to look at the company's stability. If they depend on a single vendor for their livelihood and could be out of business if the vendor decides they don't really need the service or can do it in-house. What are your dealbreakers?

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  • Listing C/C++ functions (Code analysis in Unix)

    - by Jond
    Whether we're maintaining unfamiliar code or checking out the implementation details of an Apache module it can help if we can quickly traverse the code and build up an overview of what we're looking at. Grep serves most of my daily needs but there are some cases where it just wont do. Here's a common example of how it can help. To find the definition of a PHP function I'm interested in I can type this at the command line: grep -r "function myfunc" . This could be adapted very quickly to C or C++ if we know the return type, but things become more complicated if, say, I want to list every method that my class provides: grep "function " ./src/mine.class.php Since there's no single keyword that denotes a function or method in C++ and because it's generally more complex syntax, I think I'd need some kind of static code analysis tool, smart use of the C Preprocessor or blind faith the coder followed strict code guidelines (# of whitespace, position of curlies etc) to get these sorts of results. What would you recommend? p.s. be nice, this is my first post ;-) :p

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  • Why can't we just use a hash of passphrase as the encryption key (and IV) with symmetric encryption algorithms?

    - by TX_
    Inspired by my previous question, now I have a very interesting idea: Do you really ever need to use Rfc2898DeriveBytes or similar classes to "securely derive" the encryption key and initialization vector from the passphrase string, or will just a simple hash of that string work equally well as a key/IV, when encrypting the data with symmetric algorithm (e.g. AES, DES, etc.)? I see tons of AES encryption code snippets, where Rfc2898DeriveBytes class is used to derive the encryption key and initialization vector (IV) from the password string. It is assumed that one should use a random salt and a shitload of iterations to derive secure enough key/IV for the encryption. While deriving bytes from password string using this method is quite useful in some scenarios, I think that's not applicable when encrypting data with symmetric algorithms! Here is why: using salt makes sense when there is a possibility to build precalculated rainbow tables, and when attacker gets his hands on hash he looks up the original password as a result. But... with symmetric data encryption, I think this is not required, as the hash of password string, or the encryption key, is never stored anywhere. So, if we just get the SHA1 hash of password, and use it as the encryption key/IV, isn't that going to be equally secure? What is the purpose of using Rfc2898DeriveBytes class to generate key/IV from password string (which is a very very performance-intensive operation), when we could just use a SHA1 (or any other) hash of that password? Hash would result in random bit distribution in a key (as opposed to using string bytes directly). And attacker would have to brute-force the whole range of key (e.g. if key length is 256bit he would have to try 2^256 combinations) anyway. So either I'm wrong in a dangerous way, or all those samples of AES encryption (including many upvoted answers here at SO), etc. that use Rfc2898DeriveBytes method to generate encryption key and IV are just wrong.

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  • how i can send date from site to other sites

    - by moustafa
    Hi, Im not much of a php coder, mainly use VB. But i had a problem with one of my apps. To make it more secure i would need each php parameter to go through one site. Here is an example of what i mean: Application loads sends ip and location to 2 servers (a.php & b.php) the problem so far is that the pc is making direct connections to these pages. What i was trying to do is make it so that it only sends one command to z.php and the page z.php would send the data to a.php and b.php. My question is how would i set up z.php? I hope i make sense, i have looked everywhere and couldnt find an answer.

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  • WordPress [img] tags

    - by Lokheed
    Hey guys, I'm trying to allow that standard BB [img] [/img] tags on my WordPress blog. I got this snippet from the net, but it only works on lower case [img] tags. I'd like it to apply to both [img] and [IMG]. As you can tell, I'm totally not a coder. function embed_images($content) { $content = preg_replace('/\[img=?\]*(.*?)(\[\/img)?\]/e', '"<img src=\"$1\" alt=\"" . basename("$1") . "\" />"', $content); return $content; } add_filter('comment_text', 'embed_images'); I know '||' is 'or' but don't know enough coding to make the changes. Any help is greatly appreciated. Thanks.

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  • Replace carriage returns and line feeds in out.println?

    - by Mike
    I am a novice coder and I am using the following code to outprint a set of Image keywords and input a "|" between them. <% Set allKeywords = new HashSet(); for (AlbumObject ao : currentObjects) { XmpManager mgr = ao.getXmpManager(); if (mgr != null) { allKeywords.addAll(mgr.getKeywordSet()); } } //get the Iterator Iterator itr = allKeywords.iterator(); while(itr.hasNext()){ String str = itr.next(); out.println(str +"|"); } %> I want the output to be like this: red|blue|green|yellow but it prints out: red| blue| green| yellow which breaks my code. I've tried this: str.replaceAll("\n", ""); str.replaceAll("\r", ""); and str.replaceAll("(?:\\n|\\r)", ""); No luck. I'd really appreciate some help!

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  • VB looping complication

    - by user1819469
    I have to come up with a program that shifts names in a text box a random amount of times. I have gotten everything up to the point where the names shifts a random amount of times. It only shifts its once, but my messagebox appears through the code as many times as the names should be shifting once i click ok. Does anyone know why the loop is not working for the name shifts. I was thinking maybe the messagebox needs to control the loop, but I have searched endlessly and cannot find how that would be done. Any suggestions or referrals to other sites would be nice thanks. My code is below. Public Class Form1 Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim RandomNumber As Integer Dim min, max As Integer Dim temp, temp2, temp3, temp4, temp5, temp6 As String Dim i As Integer min = 3 max = 11 Randomize() RandomNumber = Int((max - min + 1) * Rnd() + min) temp = n1.Text temp2 = n2.Text temp3 = n3.Text temp4 = n4.Text temp5 = n5.Text temp6 = n6.Text For i = 0 To RandomNumber - 1 n1.Text = temp6 n2.Text = temp n3.Text = temp2 n4.Text = temp3 n5.Text = temp4 n6.Text = temp5 MessageBox.Show("Shift " & i & " of " & RandomNumber & " complete") Next End Sub End Class

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  • Site won't open in Facebook App for ios, nor redirect to Safari

    - by user1431811
    I'm not a heavy coder here, so i'll ask my best. We made a brochure about our home town. However users spreading it trough facebook cant open the links when in their facebook app. The app does not send it to safari either. If opened directly from safari it is no problem. The link is http://visit.lodingen360.com Is there anything i can do to the site/index.html/whatever that will make it open in safari when the link is clicked in the facebook app for ios? (that won't affect visiting the site from pc's and so on) Is there anything uiwebview won't read that can force it to safari, so that we can redirect from the thing opened in safari to the site?

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  • Do running times match with O(nlogn)?

    - by user472221
    Hi I have written a class(greedy strategy) that at first i used sort method which has O(nlogn) Collections.sort(array, new SortingObjectsWithProbabilityField()); and then i used the insert method of binary search tree which takes O(h) and h here is the tree height. for different n ,the running time will be : n,running time 17,515428 33,783340 65,540572 129,1285080 257,2052216 513,4299709 which I think is not correct because for increasing n , the running time should almost increase. This method will take the running time: Exponent = -1; for(int n = 2;n<1000;n+=Math.pow(2,exponent){ for (int j = 1; j <= 3; j++) { Random rand = new Random(); for (int i = 0; i < n; i++) { Element e = new Element(rand.nextInt(100) + 1, rand.nextInt(100) + 1, 0); for (int k = 0; k < i; k++) { if (e.getDigit() == randList.get(k).getDigit()) { e.setDigit(e.getDigit() + 1); } } randList.add(e); } double sum = 0.0; for (int i = 0; i < randList.size(); i++) { sum += randList.get(i).getProbability(); } for (Element i : randList) { i.setProbability(i.getProbability() / sum); } //Get time. long t2 = System.nanoTime(); GreedyVersion greedy = new GreedyVersion((ArrayList<Element>) randList); long t3 = System.nanoTime(); timeForGreedy = timeForGreedy + t3 - t2; } System.out.println(n + "," + "," + timeForGreedy/3 ); exponent++; } thanks

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  • How can I learn Android?

    - by Daisama
    I am a freshman in college which has been Java programming for over a year. I haven taken a couple of programming courses, both of which were with Java. And I have done web development for several years. So overall, I would't say that I am a complete beginner in programming. Recently, I have developed a strong interest in developing for Android. I read that Android development was with Java and I thought it would making development easier for me. But I was very wrong. Based on reviews from Amazon, I have begun reading "Professional Android Application Development by Meier but everything is going over my head. The Busy Coder's Guide to Android Development seems a bit more for my level but I still want everybody else's opinion. The Google stuff isn't very helpful to me at my level and neither are the tutorials on anddev and such. Any advice for a complete beginner on how to get started? Thanks.

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  • Scientific Data processing (Graph comparison and interpretation)

    - by pinkynobrain
    Hi stackoverflow friends, I'm trying to write a program to automate one of my more boring and repetitive work tasks. I have some programming experience but none with processing or interpreting large volumes of data so I am seeking your advice (both suggestions of techniques to try and also things to read to learn more about doing this stuff). I have a piece of equipment that monitors an experiment by taking repeated samples and displays the readings on its screen as a graph. The input of experiment can be altered and one of these changes should produce a change in a section of the graph which I currently identify by eye and is what I'm looking for in the experiment. I want to automate it so that a computer looks at a set of results and spots the experiment input that causes the change. I can already extract the results from the machine. Currently they results for a run are in the form of an integer array with the index being the sample number and the corresponding value being the measurement. The overall shape of the graph will be similar for each experiment run. The change I'm looking for will be roughly the same and will occur in approximately the same place every time for the correct experiment input. Unfortunately there are a few gotchas that make this problem more difficult. There is some noise in the measuring process which mean there is some random variation in the measured values between different runs. Although the overall shape of the graph remains the same. The time the experiment takes varies slightly each run causing two effects. First, the a whole graph may be shifted slightly on the x axis relative to another run's graph. Second, individual features may appear slightly wider or narrower in different runs. In both these cases the variation isn't particularly large and you can assume that the only non random variation is caused by the correct input being found. Thank you for your time, Pinky

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  • Stop functions in 5 minutes if they dont end running

    - by george mano
    I want to add a feature in my project. I have 2 functions running in a for-loop because I want to find the solution of the functions in random arrays. I also have an function that makes random arrays. In each loop the array that is made by the random_array fun are the input of the 2 functions. The 2 functions print solutions in the screen , they dont return an argument. int main(){ for (i=0;i<50 i++) { arr1=ramdom_array(); func1(arr1) func2(arr1) } } I need to stop the functions running if they have not ended in 5 minutes. I have thought that I have to put in the functions something like this : void func1(array<array<int,4>,4> initial) { while (5minutes_not_passed) { //do staff if(solution==true) break; } } But I dont know what to put in the 5minutes_not_passed. the declaration of the functions are like this: void func1(array<array<int,4>,4> initial) void func2(array<array<int,4>,4> initial) I have found that I can use the thread library but I dont think meshing up with threads in a good idea. I believe something like a timer is needed. Note that the functions sometimes might end before 5 minutes.

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  • Starting out with Objective C; need some guidance

    - by alimaxwell
    Hi Everyone, I have started learning Objective C with no prior programming experience from the 'Become an X-Coder' eBook (http://download.cocoalab.com.s3.amazonaws.com/BecomeAnXcoder.pdf). My question is, if I want to be doing iPhone development, am I going in the right direction? Am I learning the wrong language, or should I be learning Cocoa Touch? As I said, I have no prior experience, and just need someone to point me in the right direction. Apoligies if I have put this in the wrong place. Thanks very much for your time.

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  • Is there a tool that automatically saves incremental changes to files while coding?

    - by Bob.
    One of my favorite features of Google docs is the fact that it's constantly automatically saving versions of my document as I work. This means that even if I forget to save at a certain point before making a critical change there's a good chance that a save point has been created automatically. At the very least, I can return the document to a state prior to the mistaken change and continue working from that point. Is there a tool with an equivalent feature for a Ruby coder running on Mac OS (or UNIX)? For example, a tool that will do an automatic Git check-in every couple of minutes to my local repository for the files I'm working on. Maybe I'm paranoid, but this small bit of insurance could put my mind at ease during my day-to-day work.

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  • select k th mimimum from array a[0..n-1]

    - by davit-datuashvili
    i have done folloing code from progrmming pearls here is code import java.util.*; public class select { public static int select1(int x[],int l,int u,int k){ //pre l<=k<=u //post x[l..k-1]<=x[k]<=x[k+1..u] Random r=new Random(); int t=r.nextInt(u-1-l)+l; if (l>=u) return -1 ; swap(l,t); int s=x[l]; int i=l; int j=u+1; while (true){ do { i++; }while (i<=u && x[i]<t); do { j--; }while (x[j]>t); if (i>j) break; int temp=x[i]; x[i]=x[j];x[j]=t; swap(l,j); if (j<k){ return select1(x,j+1,u,k); } } return select1(x,l,j-1,k); } public static void main(String[] args) { int x[]=new int[]{4,7,9,3,2,12,13,10,20}; select1(x,0,x.length-1,5); } public static void swap(int i,int j){ int c=i; i=j; j=c; } } but here is mistake Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: -1 at select.select1(select.java:21) at select.main(select.java:36) Java Result: 1 please help

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  • How to ensure I get the picture is complete? (in java)

    - by Zenofo
    i using below code to get a picture from URL: URL url=new URL("http://www.google.com/images/logos/ps_logo2.png"); InputStream in=url.openStream(); ByteArrayOutputStream tmpOut = new ByteArrayOutputStream(); byte[] buf = new byte[512]; int len; while (true) { len = in.read(buf); if (len == -1) { break; } tmpOut.write(buf, 0, len); } tmpOut.close(); byte[] picture=tmpOut.toByteArray(); System.out.println(picture.length); this code is okay,but my internet connect is very very bad, so ,I maybe get a broken picture like this: How can I ensure the picture file is complete ? I think you can add this code to try and test this: if (len == -1) { change to if (len == -1 || (int)(Math.random()*100)==1 ) { full test code: URL url=new URL("http://www.google.com/images/logos/ps_logo2.png"); InputStream in=url.openStream(); ByteArrayOutputStream tmpOut = new ByteArrayOutputStream(); byte[] buf = new byte[512]; int len; while (true) { len = in.read(buf); if (len == -1 || (int)(Math.random()*100)==1 ) { break; } tmpOut.write(buf, 0, len); } tmpOut.close(); byte[] picture =tmpOut.toByteArray(); System.out.println(picture.length); thanks for help :)

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  • Curious about IObservable? Here’s a quick example to get you started!

    - by Roman Schindlauer
    Have you heard about IObservable/IObserver support in Microsoft StreamInsight 1.1? Then you probably want to try it out. If this is your first incursion into the IObservable/IObserver pattern, this blog post is for you! StreamInsight 1.1 introduced the ability to use IEnumerable and IObservable objects as event sources and sinks. The IEnumerable case is pretty straightforward, since many data collections are already surfacing as this type. This was already covered by Colin in his blog. Creating your own IObservable event source is a little more involved but no less exciting – here is a primer: First, let’s look at a very simple Observable data source. All it does is publish an integer in regular time periods to its registered observers. (For more information on IObservable, see http://msdn.microsoft.com/en-us/library/dd990377.aspx ). sealed class RandomSubject : IObservable<int>, IDisposable {     private bool _done;     private readonly List<IObserver<int>> _observers;     private readonly Random _random;     private readonly object _sync;     private readonly Timer _timer;     private readonly int _timerPeriod;       /// <summary>     /// Random observable subject. It produces an integer in regular time periods.     /// </summary>     /// <param name="timerPeriod">Timer period (in milliseconds)</param>     public RandomSubject(int timerPeriod)     {         _done = false;         _observers = new List<IObserver<int>>();         _random = new Random();         _sync = new object();         _timer = new Timer(EmitRandomValue);         _timerPeriod = timerPeriod;         Schedule();     }       public IDisposable Subscribe(IObserver<int> observer)     {         lock (_sync)         {             _observers.Add(observer);         }         return new Subscription(this, observer);     }       public void OnNext(int value)     {         lock (_sync)         {             if (!_done)             {                 foreach (var observer in _observers)                 {                     observer.OnNext(value);                 }             }         }     }       public void OnError(Exception e)     {         lock (_sync)         {             foreach (var observer in _observers)             {                 observer.OnError(e);             }             _done = true;         }     }       public void OnCompleted()     {         lock (_sync)         {             foreach (var observer in _observers)             {                 observer.OnCompleted();             }             _done = true;         }     }       void IDisposable.Dispose()     {         _timer.Dispose();     }       private void Schedule()     {         lock (_sync)         {             if (!_done)             {                 _timer.Change(_timerPeriod, Timeout.Infinite);             }         }     }       private void EmitRandomValue(object _)     {         var value = (int)(_random.NextDouble() * 100);         Console.WriteLine("[Observable]\t" + value);         OnNext(value);         Schedule();     }       private sealed class Subscription : IDisposable     {         private readonly RandomSubject _subject;         private IObserver<int> _observer;           public Subscription(RandomSubject subject, IObserver<int> observer)         {             _subject = subject;             _observer = observer;         }           public void Dispose()         {             IObserver<int> observer = _observer;             if (null != observer)             {                 lock (_subject._sync)                 {                     _subject._observers.Remove(observer);                 }                 _observer = null;             }         }     } }   So far, so good. Now let’s write a program that consumes data emitted by the observable as a stream of point events in a Streaminsight query. First, let’s define our payload type: class Payload {     public int Value { get; set; }       public override string ToString()     {         return "[StreamInsight]\tValue: " + Value.ToString();     } }   Now, let’s write the program. First, we will instantiate the observable subject. Then we’ll use the ToPointStream() method to consume it as a stream. We can now write any query over the source - here, a simple pass-through query. class Program {     static void Main(string[] args)     {         Console.WriteLine("Starting observable source...");         using (var source = new RandomSubject(500))         {             Console.WriteLine("Started observable source.");             using (var server = Server.Create("Default"))             {                 var application = server.CreateApplication("My Application");                   var stream = source.ToPointStream(application,                     e => PointEvent.CreateInsert(DateTime.Now, new Payload { Value = e }),                     AdvanceTimeSettings.StrictlyIncreasingStartTime,                     "Observable Stream");                   var query = from e in stream                             select e;                   [...]   We’re done with consuming input and querying it! But you probably want to see the output of the query. Did you know you can turn a query into an observable subject as well? Let’s do precisely that, and exploit the Reactive Extensions for .NET (http://msdn.microsoft.com/en-us/devlabs/ee794896.aspx) to quickly visualize the output. Notice we’re subscribing “Console.WriteLine()” to the query, a pattern you may find useful for quick debugging of your queries. Reminder: you’ll need to install the Reactive Extensions for .NET (Rx for .NET Framework 4.0), and reference System.CoreEx and System.Reactive in your project.                 [...]                   Console.ReadLine();                 Console.WriteLine("Starting query...");                 using (query.ToObservable().Subscribe(Console.WriteLine))                 {                     Console.WriteLine("Started query.");                     Console.ReadLine();                     Console.WriteLine("Stopping query...");                 }                 Console.WriteLine("Stopped query.");             }             Console.ReadLine();             Console.WriteLine("Stopping observable source...");             source.OnCompleted();         }         Console.WriteLine("Stopped observable source.");     } }   We hope this blog post gets you started. And for bonus points, you can go ahead and rewrite the observable source (the RandomSubject class) using the Reactive Extensions for .NET! The entire sample project is attached to this article. Happy querying! Regards, The StreamInsight Team

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  • Simplex Noise Help

    - by Alex Larsen
    Im Making A Minecraft Like Gae In XNA C# And I Need To Generate Land With Caves This Is The Code For Simplex I Have /// <summary> /// 1D simplex noise /// </summary> /// <param name="x"></param> /// <returns></returns> public static float Generate(float x) { int i0 = FastFloor(x); int i1 = i0 + 1; float x0 = x - i0; float x1 = x0 - 1.0f; float n0, n1; float t0 = 1.0f - x0 * x0; t0 *= t0; n0 = t0 * t0 * grad(perm[i0 & 0xff], x0); float t1 = 1.0f - x1 * x1; t1 *= t1; n1 = t1 * t1 * grad(perm[i1 & 0xff], x1); // The maximum value of this noise is 8*(3/4)^4 = 2.53125 // A factor of 0.395 scales to fit exactly within [-1,1] return 0.395f * (n0 + n1); } /// <summary> /// 2D simplex noise /// </summary> /// <param name="x"></param> /// <param name="y"></param> /// <returns></returns> public static float Generate(float x, float y) { const float F2 = 0.366025403f; // F2 = 0.5*(sqrt(3.0)-1.0) const float G2 = 0.211324865f; // G2 = (3.0-Math.sqrt(3.0))/6.0 float n0, n1, n2; // Noise contributions from the three corners // Skew the input space to determine which simplex cell we're in float s = (x + y) * F2; // Hairy factor for 2D float xs = x + s; float ys = y + s; int i = FastFloor(xs); int j = FastFloor(ys); float t = (float)(i + j) * G2; float X0 = i - t; // Unskew the cell origin back to (x,y) space float Y0 = j - t; float x0 = x - X0; // The x,y distances from the cell origin float y0 = y - Y0; // For the 2D case, the simplex shape is an equilateral triangle. // Determine which simplex we are in. int i1, j1; // Offsets for second (middle) corner of simplex in (i,j) coords if (x0 > y0) { i1 = 1; j1 = 0; } // lower triangle, XY order: (0,0)->(1,0)->(1,1) else { i1 = 0; j1 = 1; } // upper triangle, YX order: (0,0)->(0,1)->(1,1) // A step of (1,0) in (i,j) means a step of (1-c,-c) in (x,y), and // a step of (0,1) in (i,j) means a step of (-c,1-c) in (x,y), where // c = (3-sqrt(3))/6 float x1 = x0 - i1 + G2; // Offsets for middle corner in (x,y) unskewed coords float y1 = y0 - j1 + G2; float x2 = x0 - 1.0f + 2.0f * G2; // Offsets for last corner in (x,y) unskewed coords float y2 = y0 - 1.0f + 2.0f * G2; // Wrap the integer indices at 256, to avoid indexing perm[] out of bounds int ii = i % 256; int jj = j % 256; // Calculate the contribution from the three corners float t0 = 0.5f - x0 * x0 - y0 * y0; if (t0 < 0.0f) n0 = 0.0f; else { t0 *= t0; n0 = t0 * t0 * grad(perm[ii + perm[jj]], x0, y0); } float t1 = 0.5f - x1 * x1 - y1 * y1; if (t1 < 0.0f) n1 = 0.0f; else { t1 *= t1; n1 = t1 * t1 * grad(perm[ii + i1 + perm[jj + j1]], x1, y1); } float t2 = 0.5f - x2 * x2 - y2 * y2; if (t2 < 0.0f) n2 = 0.0f; else { t2 *= t2; n2 = t2 * t2 * grad(perm[ii + 1 + perm[jj + 1]], x2, y2); } // Add contributions from each corner to get the final noise value. // The result is scaled to return values in the interval [-1,1]. return 40.0f * (n0 + n1 + n2); // TODO: The scale factor is preliminary! } public static float Generate(float x, float y, float z) { // Simple skewing factors for the 3D case const float F3 = 0.333333333f; const float G3 = 0.166666667f; float n0, n1, n2, n3; // Noise contributions from the four corners // Skew the input space to determine which simplex cell we're in float s = (x + y + z) * F3; // Very nice and simple skew factor for 3D float xs = x + s; float ys = y + s; float zs = z + s; int i = FastFloor(xs); int j = FastFloor(ys); int k = FastFloor(zs); float t = (float)(i + j + k) * G3; float X0 = i - t; // Unskew the cell origin back to (x,y,z) space float Y0 = j - t; float Z0 = k - t; float x0 = x - X0; // The x,y,z distances from the cell origin float y0 = y - Y0; float z0 = z - Z0; // For the 3D case, the simplex shape is a slightly irregular tetrahedron. // Determine which simplex we are in. int i1, j1, k1; // Offsets for second corner of simplex in (i,j,k) coords int i2, j2, k2; // Offsets for third corner of simplex in (i,j,k) coords /* This code would benefit from a backport from the GLSL version! */ if (x0 >= y0) { if (y0 >= z0) { i1 = 1; j1 = 0; k1 = 0; i2 = 1; j2 = 1; k2 = 0; } // X Y Z order else if (x0 >= z0) { i1 = 1; j1 = 0; k1 = 0; i2 = 1; j2 = 0; k2 = 1; } // X Z Y order else { i1 = 0; j1 = 0; k1 = 1; i2 = 1; j2 = 0; k2 = 1; } // Z X Y order } else { // x0<y0 if (y0 < z0) { i1 = 0; j1 = 0; k1 = 1; i2 = 0; j2 = 1; k2 = 1; } // Z Y X order else if (x0 < z0) { i1 = 0; j1 = 1; k1 = 0; i2 = 0; j2 = 1; k2 = 1; } // Y Z X order else { i1 = 0; j1 = 1; k1 = 0; i2 = 1; j2 = 1; k2 = 0; } // Y X Z order } // A step of (1,0,0) in (i,j,k) means a step of (1-c,-c,-c) in (x,y,z), // a step of (0,1,0) in (i,j,k) means a step of (-c,1-c,-c) in (x,y,z), and // a step of (0,0,1) in (i,j,k) means a step of (-c,-c,1-c) in (x,y,z), where // c = 1/6. float x1 = x0 - i1 + G3; // Offsets for second corner in (x,y,z) coords float y1 = y0 - j1 + G3; float z1 = z0 - k1 + G3; float x2 = x0 - i2 + 2.0f * G3; // Offsets for third corner in (x,y,z) coords float y2 = y0 - j2 + 2.0f * G3; float z2 = z0 - k2 + 2.0f * G3; float x3 = x0 - 1.0f + 3.0f * G3; // Offsets for last corner in (x,y,z) coords float y3 = y0 - 1.0f + 3.0f * G3; float z3 = z0 - 1.0f + 3.0f * G3; // Wrap the integer indices at 256, to avoid indexing perm[] out of bounds int ii = i % 256; int jj = j % 256; int kk = k % 256; // Calculate the contribution from the four corners float t0 = 0.6f - x0 * x0 - y0 * y0 - z0 * z0; if (t0 < 0.0f) n0 = 0.0f; else { t0 *= t0; n0 = t0 * t0 * grad(perm[ii + perm[jj + perm[kk]]], x0, y0, z0); } float t1 = 0.6f - x1 * x1 - y1 * y1 - z1 * z1; if (t1 < 0.0f) n1 = 0.0f; else { t1 *= t1; n1 = t1 * t1 * grad(perm[ii + i1 + perm[jj + j1 + perm[kk + k1]]], x1, y1, z1); } float t2 = 0.6f - x2 * x2 - y2 * y2 - z2 * z2; if (t2 < 0.0f) n2 = 0.0f; else { t2 *= t2; n2 = t2 * t2 * grad(perm[ii + i2 + perm[jj + j2 + perm[kk + k2]]], x2, y2, z2); } float t3 = 0.6f - x3 * x3 - y3 * y3 - z3 * z3; if (t3 < 0.0f) n3 = 0.0f; else { t3 *= t3; n3 = t3 * t3 * grad(perm[ii + 1 + perm[jj + 1 + perm[kk + 1]]], x3, y3, z3); } // Add contributions from each corner to get the final noise value. // The result is scaled to stay just inside [-1,1] return 32.0f * (n0 + n1 + n2 + n3); // TODO: The scale factor is preliminary! } private static byte[] perm = new byte[512] { 151,160,137,91,90,15, 131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23, 190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33, 88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166, 77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244, 102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196, 135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123, 5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42, 223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9, 129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228, 251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107, 49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254, 138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180, 151,160,137,91,90,15, 131,13,201,95,96,53,194,233,7,225,140,36,103,30,69,142,8,99,37,240,21,10,23, 190, 6,148,247,120,234,75,0,26,197,62,94,252,219,203,117,35,11,32,57,177,33, 88,237,149,56,87,174,20,125,136,171,168, 68,175,74,165,71,134,139,48,27,166, 77,146,158,231,83,111,229,122,60,211,133,230,220,105,92,41,55,46,245,40,244, 102,143,54, 65,25,63,161, 1,216,80,73,209,76,132,187,208, 89,18,169,200,196, 135,130,116,188,159,86,164,100,109,198,173,186, 3,64,52,217,226,250,124,123, 5,202,38,147,118,126,255,82,85,212,207,206,59,227,47,16,58,17,182,189,28,42, 223,183,170,213,119,248,152, 2,44,154,163, 70,221,153,101,155,167, 43,172,9, 129,22,39,253, 19,98,108,110,79,113,224,232,178,185, 112,104,218,246,97,228, 251,34,242,193,238,210,144,12,191,179,162,241, 81,51,145,235,249,14,239,107, 49,192,214, 31,181,199,106,157,184, 84,204,176,115,121,50,45,127, 4,150,254, 138,236,205,93,222,114,67,29,24,72,243,141,128,195,78,66,215,61,156,180 }; private static int FastFloor(float x) { return (x > 0) ? ((int)x) : (((int)x) - 1); } private static float grad(int hash, float x) { int h = hash & 15; float grad = 1.0f + (h & 7); // Gradient value 1.0, 2.0, ..., 8.0 if ((h & 8) != 0) grad = -grad; // Set a random sign for the gradient return (grad * x); // Multiply the gradient with the distance } private static float grad(int hash, float x, float y) { int h = hash & 7; // Convert low 3 bits of hash code float u = h < 4 ? x : y; // into 8 simple gradient directions, float v = h < 4 ? y : x; // and compute the dot product with (x,y). return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -2.0f * v : 2.0f * v); } private static float grad(int hash, float x, float y, float z) { int h = hash & 15; // Convert low 4 bits of hash code into 12 simple float u = h < 8 ? x : y; // gradient directions, and compute dot product. float v = h < 4 ? y : h == 12 || h == 14 ? x : z; // Fix repeats at h = 12 to 15 return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -v : v); } private static float grad(int hash, float x, float y, float z, float t) { int h = hash & 31; // Convert low 5 bits of hash code into 32 simple float u = h < 24 ? x : y; // gradient directions, and compute dot product. float v = h < 16 ? y : z; float w = h < 8 ? z : t; return ((h & 1) != 0 ? -u : u) + ((h & 2) != 0 ? -v : v) + ((h & 4) != 0 ? -w : w); } This Is My World Generation Code Block[,] BlocksInMap = new Block[1024, 256]; public bool IsWorldGenerated = false; Random r = new Random(); private void RunThread() { for (int BH = 0; BH <= 256; BH++) { for (int BW = 0; BW <= 1024; BW++) { Block b = new Block(); if (BH >= 192) { } BlocksInMap[BW, BH] = b; } } IsWorldGenerated = true; } public void GenWorld() { new Thread(new ThreadStart(RunThread)).Start(); } And This Is A Example Of How I Set Blocks Block b = new Block(); b.BlockType = = Block.BlockTypes.Air; This Is A Example Of How I Set Models foreach (Block b in MyWorld) { switch(b.BlockType) { case Block.BlockTypes.Dirt: b.Model = DirtModel; break; ect. } } How Would I Use These To Generate To World (The Block Array) And If Possible Thread It More? btw It's 1024 Wide And 256 Tall

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