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  • need to align part of list item to right of li - using CSS3 Jquery column-layout

    - by Brad
    Using this jquery script to acheive CSS3 3-columns, to display a list of members alphabetically. I need it to display this way, which is does: A D B E C F Here is what I am using http://www.csscripting.com/css-multi-column/example6.php? (using this js file http://www.csscripting.com/js/v1.0beta/css3-multi-column.js) To the right of each member, it has their phone extension, which I want to float to the right, so it easy to read. I tried putting the phone extension within a div and span and when I do that, it tends to screw up at the last item in each column, by placing the person's name correctly, but their extension is the very first item in the next column. Screenshot: http://cl.ly/fq4 of what it is doing HTML Code: <div class="Article3Col"> <ul> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> <li>Doe, John <div style="float:right;"> 8317 </div> </li> <li>Doe, Sally <div style="float:right;"> 8729 </div> </li> </ul> </div> CSS: .Article3Col { column-count:3; } Any help is appreciated.

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  • Can I have a shell alias evaluate a history substitution command?

    - by Brandon
    I'm trying to write an alias for cd !!:1, which takes the 2nd word of the previous command, and changes to the directory of that name. For instance, if I type rails new_project cd !!:1 the second line will cd into the "new_project" directory. Since !!:1 is awkward to type (even though it's short, it requires three SHIFTed keys, on opposite sides of of the keyboard, and then an unSHIFTed version of the key that was typed twice SHIFTed), I want to just type something like cd- but since the !!:1 is evaluated on the command line, I (OBVIOUSLY) can't just do alias cd-=!!:1 or I'd be saving an alias that contained "new_project" hard-coded into it. So I tried alias cd-='!!:1' The problem with this is that the !!:1 is NEVER evaluated, and I get a message that no directory named !!:1 exists. How can I make an alias where the history substitution is evaluated AT THE TIME I ISSUE THE ALIAS COMMAND, not when I define the alias, and not never? (I've tried this in both bash and zsh, and get the same results in both.)

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  • Delphi 7: how to execute shell command and check the result?

    - by mawg
    I'm using Delphi 7 and can't predict the target version of Windows. I need to create a database (probably MySql, but might be something else) and define some table structures. I do not need to populate any data. Unfortunately, all of the ADO components seem to expect that a database already exists and they will then allow you to manipulate it. So, since it's only a few simple commands, I thought that I might as well use ShellExectute(). Agree? Disagree? Can anyone give me a sample code which will attempt to run "MySql --version" and let me check the result? After that I should be able to figure it out for myself. Thanks.

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  • Could not find rake-10.1.0 in any of the sources

    - by spuder
    I've got a ruby on rails application (gitlab) which is installed via puppet. Everything on the test system runs fine, but production generates an error about rake Running /home/git/gitlab-shell/bin/check Could not find rake-10.1.0 in any of the sources Run bundle install to install missing gems. Here is the full rake check: root@gitlab:/home/git# sudo -u git -H bundle exec rake gitlab:check RAILS_ENV=production Checking Environment ... Git configured for git user? ... yes Has python2? ... yes python2 is supported version? ... yes Checking Environment ... Finished Checking GitLab Shell ... GitLab Shell version >= 1.7.1 ? ... OK (1.7.1) Repo base directory exists? ... yes Repo base directory is a symlink? ... no Repo base owned by git:git? ... yes Repo base access is drwxrws---? ... yes update hook up-to-date? ... yes update hooks in repos are links: ... Could not find rake-10.1.0 in any of the sources Run `bundle install` to install missing gems. gitlab-shell self-check failed Try fixing it: Make sure GitLab is running; Check the gitlab-shell configuration file: sudo -u git -H editor /home/git/gitlab-shell/config.yml Please fix the error above and rerun the checks. Checking GitLab Shell ... Finished Checking Sidekiq ... Running? ... yes Number of Sidekiq processes ... 1 Checking Sidekiq ... Finished Checking GitLab ... Database config exists? ... yes Database is SQLite ... no All migrations up? ... yes GitLab config exists? ... yes GitLab config outdated? ... no Log directory writable? ... yes Tmp directory writable? ... yes Init script exists? ... yes Init script up-to-date? ... yes projects have namespace: ... Spencer Owen / bar ... yes Projects have satellites? ... Spencer Owen / bar ... can't create, repository is empty Redis version >= 2.0.0? ... yes Your git bin path is "/usr/bin/git" Git version >= 1.7.10 ? ... yes (1.8.4) Checking GitLab ... Finished The step 'gitlab-shell check' effectively runs the following command. If I run that command manually, everything passes. root@gitlab:/home/git/gitlab# sudo -u git -H /home/git/gitlab-shell/bin/check Check GitLab API access: OK Check directories and files: /home/git/repositories: OK /home/git/.ssh/authorized_keys: OK I have verified that rake is in fact installed root@gitlab:/home/git/gitlab# gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# bundle install root@gitlab:/home/git/gitlab# sudo -u git -H gem install rake -v 10.1.0 root@gitlab:/home/git/gitlab# sudo -u git -H bundle install Ruby is installed with update alternatives root@gitlab:/home/git/gitlab# sudo -u git -H ruby --version ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-linux] root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which ruby` lrwxrwxrwx 1 root root 22 Oct 8 20:26 /usr/bin/ruby -> /etc/alternatives/ruby root@gitlab:/home/git/gitlab# sudo -u git -H gem --version 2.1.10 root@gitlab:/home/git/gitlab# sudo -u git -H ls -l `which gem` lrwxrwxrwx 1 root root 21 Oct 10 20:50 /usr/bin/gem -> /etc/alternatives/gem I've tried the solution mentioned below, to allow shared gems http://stackoverflow.com/questions/19284914/bundle-exec-fails-with-could-not-find-rake-10-1-0-in-any-of-the-sources http://stackoverflow.com/questions/18978002/could-not-find-rake-with-bundle-exec root@gitlab:/home/git/gitlab# cat /home/git/gitlab/.bundle/config --- BUNDLE_FROZEN: '1' BUNDLE_PATH: vendor/bundle BUNDLE_WITHOUT: development:test:postgres BUNDLE_DISABLE_SHARED_GEMS: '1' I've exhausted google, so I'm hoping for someone more familiar with ruby to offer any ideas how to resolve the error. Could not find rake-10.1.0 in any of the sources

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  • How do I create a Launcher in Ubuntu 9.1 that runs a shell script?

    - by mkelley33
    Here's my situation: New to Ubuntu (just nstalled 9.10 Karmic Koala 64 bit) Purpose: to easily run PyCharm without too much typing (ie. cd... ./pycharm.sh) Want to create desktop Launcher instead of terminal & typing (without resorting to the "Run in Terminal" option) Tried to create Launcher to executes .sh script in Document directory Right-clicked Desktop Create Launcher a. Type == Application; Browse [insert absolute path to .sh script]; no luck b. Type == Application in Terminal; Browse ...ditto I'm open to any other alternatives that involve as little typing as possible. I would like to just start Ubuntu, click Launcher icons, and have terminals spring to life, running the intended scripts. Crazy? No. Lazy? Probably. Productive? Hopefully :)

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  • shell command to find a process id and attach to it?

    - by lallous
    Hello I want to attach to a running process using 'ddd', what I manually do is: # ps -ax | grep PROCESS_NAME Then I get a list and the pid, then I type: # ddd PROCESS_NAME THE_PID Is there is a way to type just one command directly? Remark: When I type ps -ax | grep PROCESS_NAME <- grep will match both the process and grep command line itself.

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  • How to give focus to default program of shell-opened file, from Java ?

    - by Rabarberski
    From within Java, I am opening an Excel file with the default file handler (MS Excel, in this case :-) ) using the method described in this stackoverflow question: Desktop dt = Desktop.getDesktop(); dt.open(new File(filename)); However, the Excel program doesn't get the focus. Is there any easy way to do so? Edit: There is a related stackoverflow question for C#, but I didn't find any similar Java method.

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  • How to run a GUI app from ssh shell?

    - by karramba
    I can access my linux box by ssh and by vnc. I want to run a GUI application, but directly from ssh, I don't want to access through VNC and click around. So, after logging in using ssh, I want to issue a magic command, so that when I log in through VNC I will see my GUI app running. How can I do this?

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  • Can I use a local::lib if local::lib isn't installed globally and without eval-ing it in shell?

    - by xenoterracide
    I have a problem, I want to use local::lib; in a script. But because I need to use this script many places, I don't want to try adding the eval to bashrc, every time I install this script to a server. and I can't get local::lib installed globally (in the default @INC) on the servers. Is there any way I can use local::lib from within the script so that it knows where the module local::lib is without the eval that local::lib recommends and without installing it into a directory in the default @INC on the server?

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  • How would I write this shell script as a Windows batch script?

    - by Jeremy Banks
    I haven't had a chance to test this script, I'm just using it as a suitable pseudocode. It's just supposed to copy all files in the current directory into a timestamped subdirectory. ID="$(date +%Y%b%d%H%M%S)" COMMITABLE="$(ls | egrep --invert-match ^(STATES|PARENT)\$)" STATE_PATH="$(pwd)/STATES/$ID" mkdir --parents "$STATE_PATH" cp $COMMITABLE "$STATE_PATH" ln -s "$STATE_PATH" PARENT

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  • 2 or more FOR loops in command shell merging fileA line1 with fileB line1, &c.

    - by rfransix
    Hi, i'm trying to build an ldif import file. I have 2 files, one with the DN and another with the employeeNumber, they match up line for line. Here's the code that does not work: @echo on ::Set BATCH Input Directory set batchdir=e:\Meta ::Set the input file containing the server list set infile=%batchdir%\DDNs3 set infile2=%batchdir%\DDNs4 ::If exists, we remove output file Rm DDNs3.ldif ::For loop below process each line in the input list. FOR /F "tokens=* delims=" %%i IN (%infile%) do ( FOR /F "tokens=* delims=" %%k IN (%infile2%) do ( Echo dn: %%i Echo changetype: modify Echo replace: employeeNumber Echo employeeNumber: %%k ) ) DDNs3.ldif I've tried several variations, including: ::For loop below process each line in the input list. FOR /F "tokens=* delims=" %%i IN (%infile%) do ( Echo dn: %%i Echo changetype: modify Echo replace: employeeNumber FOR /F "tokens=* delims=" %%k IN (%infile2%) do ( Echo employeeNumber: %%k echo. ) ) DDNs3.ldif

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  • How to make two different files (with their contents) equal using command in linux shell?

    - by user2617138
    How to make two different files (their contents) equal using terminal in Linux? Suppose i have a file A in which the content is Hello world and i have a file B in which the content is Hello worlds. Now we find the difference between the 2 files using the diff or sdiff utility. Now i want to append the contents of the 2 different files into a single file or make the two different files (their contents) equal using terminal or any other utility.

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  • how to fix "BusyBox v1.17.1 (Ubuntu 1:1.17.1-10ubuntu1) built-in shell (ash) Enter 'help' for a list of built-in commands?"

    - by Joseph
    So I was using Ubuntu when suddenly the whole thing froze up and I had to reboot. And from that moment on, the system when it is starting up, prompts this little selection menu: GNU GRUB version 1.99~rc1-13ubuntu3 Ubuntu, with Linux 2.6.38-10-generic ubuntu, with Linux 2.6.38-10-generic (recovery mode) Previous Linux versions Memory test (memtest86+) Memory test (memtest86+, serial console 115200) I have chosen all of the available choices but all I get is another command line system that reads: BusyBox v1.17.1 (Ubuntu 1:1.17.1-10ubuntu1) built-in shell (ash) Enter 'help' for a list of built-in commands. (initramfs): And honestly I can't do anything with it. Does anyone have any idea of what is going on and how I can get Ubuntu to work again?

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  • ErrorListProvider in VS2010 throws InvalidOperationException about IVsTaskList

    - by Ben Hall
    I'm trying to hook into the ErrorListProvider in VS2010 to provide some more feedback from my VS2010 extension addin. The code is as follows: try { ErrorListProvider errorProvider = new ErrorListProvider(ServiceProvider); ErrorTask error = new ErrorTask(); error.Category = TaskCategory.BuildCompile; error.Text = "ERROR!"; errorProvider.Tasks.Add(error); } catch (InvalidOperationException) { } However the following exception is thrown: System.InvalidOperationException was caught Message=The service 'Microsoft.VisualStudio.Shell.Interop.IVsTaskList' must be installed for this feature to work. Ensure that this service is available. Source=Microsoft.VisualStudio.Shell.10.0 StackTrace: at Microsoft.VisualStudio.Shell.TaskProvider.get_VsTaskList() at Microsoft.VisualStudio.Shell.TaskProvider.Refresh() at Microsoft.VisualStudio.Shell.TaskProvider.TaskCollection.Add(Task task) Does anyone have any ideas why?

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  • How LINQ to Object statements work

    - by rajbk
    This post goes into detail as to now LINQ statements work when querying a collection of objects. This topic assumes you have an understanding of how generics, delegates, implicitly typed variables, lambda expressions, object/collection initializers, extension methods and the yield statement work. I would also recommend you read my previous two posts: Using Delegates in C# Part 1 Using Delegates in C# Part 2 We will start by writing some methods to filter a collection of data. Assume we have an Employee class like so: 1: public class Employee { 2: public int ID { get; set;} 3: public string FirstName { get; set;} 4: public string LastName {get; set;} 5: public string Country { get; set; } 6: } and a collection of employees like so: 1: var employees = new List<Employee> { 2: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 3: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 4: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 5: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 6: }; Filtering We wish to  find all employees that have an even ID. We could start off by writing a method that takes in a list of employees and returns a filtered list of employees with an even ID. 1: static List<Employee> GetEmployeesWithEvenID(List<Employee> employees) { 2: var filteredEmployees = new List<Employee>(); 3: foreach (Employee emp in employees) { 4: if (emp.ID % 2 == 0) { 5: filteredEmployees.Add(emp); 6: } 7: } 8: return filteredEmployees; 9: } The method can be rewritten to return an IEnumerable<Employee> using the yield return keyword. 1: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 2: foreach (Employee emp in employees) { 3: if (emp.ID % 2 == 0) { 4: yield return emp; 5: } 6: } 7: } We put these together in a console application. 1: using System; 2: using System.Collections.Generic; 3: //No System.Linq 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 15: }; 16: var filteredEmployees = GetEmployeesWithEvenID(employees); 17:  18: foreach (Employee emp in filteredEmployees) { 19: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 20: emp.ID, emp.FirstName, emp.LastName, emp.Country); 21: } 22:  23: Console.ReadLine(); 24: } 25: 26: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 27: foreach (Employee emp in employees) { 28: if (emp.ID % 2 == 0) { 29: yield return emp; 30: } 31: } 32: } 33: } 34:  35: public class Employee { 36: public int ID { get; set;} 37: public string FirstName { get; set;} 38: public string LastName {get; set;} 39: public string Country { get; set; } 40: } Output: ID 2 First_Name Jim Last_Name Ashlock Country UK ID 4 First_Name Jill Last_Name Anderson Country AUS Our filtering method is too specific. Let us change it so that it is capable of doing different types of filtering and lets give our method the name Where ;-) We will add another parameter to our Where method. This additional parameter will be a delegate with the following declaration. public delegate bool Filter(Employee emp); The idea is that the delegate parameter in our Where method will point to a method that contains the logic to do our filtering thereby freeing our Where method from any dependency. The method is shown below: 1: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 2: foreach (Employee emp in employees) { 3: if (filter(emp)) { 4: yield return emp; 5: } 6: } 7: } Making the change to our app, we create a new instance of the Filter delegate on line 14 with a target set to the method EmployeeHasEvenId. Running the code will produce the same output. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, filterDelegate); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  37: public class Employee { 38: public int ID { get; set;} 39: public string FirstName { get; set;} 40: public string LastName {get; set;} 41: public string Country { get; set; } 42: } Lets use lambda expressions to inline the contents of the EmployeeHasEvenId method in place of the method. The next code snippet shows this change (see line 15).  For brevity, the Employee class declaration has been skipped. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  The output displays the same two employees.  Our Where method is too restricted since it works with a collection of Employees only. Lets change it so that it works with any IEnumerable<T>. In addition, you may recall from my previous post,  that .NET 3.5 comes with a lot of predefined delegates including public delegate TResult Func<T, TResult>(T arg); We will get rid of our Filter delegate and use the one above instead. We apply these two changes to our code. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14:  15: foreach (Employee emp in filteredEmployees) { 16: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 17: emp.ID, emp.FirstName, emp.LastName, emp.Country); 18: } 19: Console.ReadLine(); 20: } 21: 22: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 23: foreach (var x in source) { 24: if (filter(x)) { 25: yield return x; 26: } 27: } 28: } 29: } We have successfully implemented a way to filter any IEnumerable<T> based on a  filter criteria. Projection Now lets enumerate on the items in the IEnumerable<Employee> we got from the Where method and copy them into a new IEnumerable<EmployeeFormatted>. The EmployeeFormatted class will only have a FullName and ID property. 1: public class EmployeeFormatted { 2: public int ID { get; set; } 3: public string FullName {get; set;} 4: } We could “project” our existing IEnumerable<Employee> into a new collection of IEnumerable<EmployeeFormatted> with the help of a new method. We will call this method Select ;-) 1: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 2: foreach (var emp in employees) { 3: yield return new EmployeeFormatted { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; 7: } 8: } The changes are applied to our app. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14: var formattedEmployees = Select(filteredEmployees); 15:  16: foreach (EmployeeFormatted emp in formattedEmployees) { 17: Console.WriteLine("ID {0} Full_Name {1}", 18: emp.ID, emp.FullName); 19: } 20: Console.ReadLine(); 21: } 22:  23: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 24: foreach (var x in source) { 25: if (filter(x)) { 26: yield return x; 27: } 28: } 29: } 30: 31: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 32: foreach (var emp in employees) { 33: yield return new EmployeeFormatted { 34: ID = emp.ID, 35: FullName = emp.LastName + ", " + emp.FirstName 36: }; 37: } 38: } 39: } 40:  41: public class Employee { 42: public int ID { get; set;} 43: public string FirstName { get; set;} 44: public string LastName {get; set;} 45: public string Country { get; set; } 46: } 47:  48: public class EmployeeFormatted { 49: public int ID { get; set; } 50: public string FullName {get; set;} 51: } Output: ID 2 Full_Name Ashlock, Jim ID 4 Full_Name Anderson, Jill We have successfully selected employees who have an even ID and then shaped our data with the help of the Select method so that the final result is an IEnumerable<EmployeeFormatted>.  Lets make our Select method more generic so that the user is given the freedom to shape what the output would look like. We can do this, like before, with lambda expressions. Our Select method is changed to accept a delegate as shown below. TSource will be the type of data that comes in and TResult will be the type the user chooses (shape of data) as returned from the selector delegate. 1:  2: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 3: foreach (var x in source) { 4: yield return selector(x); 5: } 6: } We see the new changes to our app. On line 15, we use lambda expression to specify the shape of the data. In this case the shape will be of type EmployeeFormatted. 1:  2: public class Program 3: { 4: [STAThread] 5: static void Main(string[] args) 6: { 7: var employees = new List<Employee> { 8: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 9: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 10: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 11: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 12: }; 13:  14: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 15: var formattedEmployees = Select(filteredEmployees, (emp) => 16: new EmployeeFormatted { 17: ID = emp.ID, 18: FullName = emp.LastName + ", " + emp.FirstName 19: }); 20:  21: foreach (EmployeeFormatted emp in formattedEmployees) { 22: Console.WriteLine("ID {0} Full_Name {1}", 23: emp.ID, emp.FullName); 24: } 25: Console.ReadLine(); 26: } 27: 28: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 29: foreach (var x in source) { 30: if (filter(x)) { 31: yield return x; 32: } 33: } 34: } 35: 36: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 37: foreach (var x in source) { 38: yield return selector(x); 39: } 40: } 41: } The code outputs the same result as before. On line 14 we filter our data and on line 15 we project our data. What if we wanted to be more expressive and concise? We could combine both line 14 and 15 into one line as shown below. Assuming you had to perform several operations like this on our collection, you would end up with some very unreadable code! 1: var formattedEmployees = Select(Where(employees, emp => emp.ID % 2 == 0), (emp) => 2: new EmployeeFormatted { 3: ID = emp.ID, 4: FullName = emp.LastName + ", " + emp.FirstName 5: }); A cleaner way to write this would be to give the appearance that the Select and Where methods were part of the IEnumerable<T>. This is exactly what extension methods give us. Extension methods have to be defined in a static class. Let us make the Select and Where extension methods on IEnumerable<T> 1: public static class MyExtensionMethods { 2: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 3: foreach (var x in source) { 4: if (filter(x)) { 5: yield return x; 6: } 7: } 8: } 9: 10: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 11: foreach (var x in source) { 12: yield return selector(x); 13: } 14: } 15: } The creation of the extension method makes the syntax much cleaner as shown below. We can write as many extension methods as we want and keep on chaining them using this technique. 1: var formattedEmployees = employees 2: .Where(emp => emp.ID % 2 == 0) 3: .Select (emp => new EmployeeFormatted { ID = emp.ID, FullName = emp.LastName + ", " + emp.FirstName }); Making these changes and running our code produces the same result. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new EmployeeFormatted { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (EmployeeFormatted emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } 55:  56: public class EmployeeFormatted { 57: public int ID { get; set; } 58: public string FullName {get; set;} 59: } Let’s change our code to return a collection of anonymous types and get rid of the EmployeeFormatted type. We see that the code produces the same output. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (var emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: public static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: public static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } To be more expressive, C# allows us to write our extension method calls as a query expression. Line 16 can be rewritten a query expression like so: 1: var formattedEmployees = from emp in employees 2: where emp.ID % 2 == 0 3: select new { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; When the compiler encounters an expression like the above, it simply rewrites it as calls to our extension methods.  So far we have been using our extension methods. The System.Linq namespace contains several extension methods for objects that implement the IEnumerable<T>. You can see a listing of these methods in the Enumerable class in the System.Linq namespace. Let’s get rid of our extension methods (which I purposefully wrote to be of the same signature as the ones in the Enumerable class) and use the ones provided in the Enumerable class. Our final code is shown below: 1: using System; 2: using System.Collections.Generic; 3: using System.Linq; //Added 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 15: }; 16:  17: var formattedEmployees = from emp in employees 18: where emp.ID % 2 == 0 19: select new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: }; 23:  24: foreach (var emp in formattedEmployees) { 25: Console.WriteLine("ID {0} Full_Name {1}", 26: emp.ID, emp.FullName); 27: } 28: Console.ReadLine(); 29: } 30: } 31:  32: public class Employee { 33: public int ID { get; set;} 34: public string FirstName { get; set;} 35: public string LastName {get; set;} 36: public string Country { get; set; } 37: } 38:  39: public class EmployeeFormatted { 40: public int ID { get; set; } 41: public string FullName {get; set;} 42: } This post has shown you a basic overview of LINQ to Objects work by showning you how an expression is converted to a sequence of calls to extension methods when working directly with objects. It gets more interesting when working with LINQ to SQL where an expression tree is constructed – an in memory data representation of the expression. The C# compiler compiles these expressions into code that builds an expression tree at runtime. The provider can then traverse the expression tree and generate the appropriate SQL query. You can read more about expression trees in this MSDN article.

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  • How to scrape a _private_ google group?

    - by John
    Hi there, I'd like to scrape the discussion list of a private google group. It's a multi-page list and I might have to this later again so scripting sounds like the way to go. Since this is a private group, I need to login in my google account first. Unfortunately I can't manage to login using wget or ruby Net::HTTP. Surprisingly google groups is not accessible with the Client Login interface, so all the code samples are useless. My ruby script is embedded at the end of the post. The response to the authentication query is a 200-OK but no cookies in the response headers and the body contains the message "Your browser's cookie functionality is turned off. Please turn it on." I got the same output with wget. See the bash script at the end of this message. I don't know how to workaround this. am I missing something? Any idea? Thanks in advance. John Here is the ruby script: # a ruby script require 'net/https' http = Net::HTTP.new('www.google.com', 443) http.use_ssl = true path = '/accounts/ServiceLoginAuth' email='[email protected]' password='topsecret' # form inputs from the login page data = "Email=#{email}&Passwd=#{password}&dsh=7379491738180116079&GALX=irvvmW0Z-zI" headers = { 'Content-Type' => 'application/x-www-form-urlencoded', 'user-agent' => "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US) AppleWebKit/533.2 (KHTML, like Gecko) Chrome/6.0"} # Post the request and print out the response to retrieve our authentication token resp, data = http.post(path, data, headers) puts resp resp.each {|h, v| puts h+'='+v} #warning: peer certificate won't be verified in this SSL session Here is the bash script: # A bash script for wget CMD="" CMD="$CMD --keep-session-cookies --save-cookies cookies.tmp" CMD="$CMD --no-check-certificate" CMD="$CMD --post-data='[email protected]&Passwd=topsecret&dsh=-8408553335275857936&GALX=irvvmW0Z-zI'" CMD="$CMD --user-agent='Mozilla'" CMD="$CMD https://www.google.com/accounts/ServiceLoginAuth" echo $CMD wget $CMD wget --load-cookies="cookies.tmp" http://groups.google.com/group/mygroup/topics?tsc=2

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  • C++ help with getline function with ifstream

    - by John
    So I am writing a program that deals with reading in and writing out to a file. I use the getline() function because some of the lines in the text file may contain multiple elements. I've never had a problem with getline until now. Here's what I got. The text file looks like this: John Smith // Client name 1234 Hollow Lane, Chicago, IL // Address 123-45-6789 // SSN Walmart // Employer 58000 // Income 2 // Number of accounts the client has 1111 // Account Number 2222 // Account Number ifstream inFile("ClientInfo.txt"); if(inFile.fail()) { cout << "Problem opening file."; } else { string name, address, ssn, employer; double income; int numOfAccount; getline(inFile, name); getline(inFile, address); // I'll stop here because I know this is where it fails. When I debugged this code, I found that name == "John", instead of name == "John Smith", and Address == "Smith" and so on. Am I doing something wrong. Any help would be much appreciated.

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  • In CAB is a service it's own module?

    - by David Anderson
    I'm learning Composite Application Block and I've hit a rock about services. I have my shell application in its own solution, and of course a test module in its own solution (developed and testing completely independent and external of the shell solution). If I created a service named "Sql Service", would I need to put this in it's own library, so that both the shell, and the module know the types? If that's the case, then for good practice, should I put the service project in the shell solution, or external just like a module (in it's own solution), even though it's not loaded as a module? Then, what about references? Should the shell reference this directly, add then add the service? Or load it as a module and add the service? I have a lot of confusion on where I should create my services, and if I should reference or load as modules..

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