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  • Remote Management/VNC Mac OSX Server 10.6 from Windows Server 2008

    - by Jonar
    What is the most compatible/reliable software to remote manage an osx server using windows server? I tried to activate the remote management from osx server then use remote desktop login from windows(failed) Tried to activate built in vnc server from osx server then use vnc client from windows(failed) tried to install osxvnc server(vine server) on osx then use either tightvnc or ultravnc on windows (connects but after sometime disconnect) PS. I would prefer a free software for both servers.

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  • Multiple PXE boots on the same subnet for RIS and WDS

    - by Tim
    We are looking to migrate off our existing server 2003 sp2 machine, running RIS (which I know is WDS as of Server 2003 Sp2, but to be clear..) with a bunch of legacy RiSETUP images to a Server 2008 r2 box. Because the change in architecture (x86 to x64), and a limitation of the Server 2008 upgrade path that won't allow mixed-mode WDS services to be upgraded, I am forced to look at running Server 2003 for RIS and Server 2008 R2 for WDS for Windows 7 on the same network. The problem I'm facing is how to deal with both PXE services at the same time? I'd still like the existing RIS server to be available for production use, but start working on WDS for deploying Windows 7. Is there a way to have a sort of PXE "chooser" ? Or some other mechanism to be able to select which server the client should download the boot image from? Thanks!

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  • cloning a kvm guest os to a vmdk file

    - by Bond
    I have a production environment where I am having 4 Guest OS running on a Ubuntu server which uses kvm. These OS are in an LVM based setup.I want these Virtual Machines to be in a vmdk format also.Where people would do experiments with these Virtual Machines so this in a vmware environment (or it can be Xen too) would be different from the kvm server.I would not have any control on that other environment so I want to give people vmdk images of these virtual machines. The production Virtual Machines will still keep running on kvm server but the VMs on which experiments would be done would be of type vmdk.(vmdk is a constraint) Here is output of lvscan ACTIVE '/dev/abcd/lvm1' [100.00 GiB] inherit ACTIVE '/dev/abcd/lvm2' [150.00 GiB] inherit ACTIVE '/dev/abcd/lvm3' [50.00 GiB] inherit ACTIVE '/dev/abcd/lvm4' [100.00 GiB] inherit I was reading man page of qemu-img and what I understand is I need to first create a qcow image file which I need to populate and then convert that to a vmdk file. Is that understanding correct? Now suppose /dev/abcd/lvm4 is the virtual machine with which I am going to start this experiment.I can shutdown the production VMs for some time to do this. So is the following way correct to go on server 1 (where kvm is running) qemu-img convert -c -f raw -O vmdk /dev/abcd/lvm4 /backup/lvm4.img or it will affect the lvm4 on kvm server 1. I do not want the VM running on original server to at all loose its any of the content but also have a vmdk file for each of the Guest OS on kvm. Before I proceed with any of the above things on the production machine I just want to make sure that I am doing the correct thing so I asking here.

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  • DNS and RPC Unavailable

    - by Berek Bryan
    I have a server that is host a MSSQL database and some other server related tasks. The server communicaties with a large number of devices. The devices send data to the server. The communication links are down between the devices on the intranet and to the outside world. However it seems I can ping and can be pinged from machines on the same switch. This includes the DNS Servers. When I run, C:\ipconfig /registerdns I get RPC Server is Unavailable. So, it seems that the server can not verify the DNS server. Both DNS server are up and running. No other machines are affected on the network.

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  • Setting up a VPN server that uses a proxy server

    - by Mehdi
    My PC(Windows 7) is connected to internet through a proxy server configured in internet options. I have set up a VPN server in my PC. But the clients that connect to my VPN server don't have access to internet. I know that if I set the proxy setting in client they can connect to internet. But is there a way that my VPN server pass traffic through the proxy server? What about using another vpn server instead of proxy server?

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  • IIS6 Permissions

    - by Gordon Carpenter-Thompson
    We have a set of IIS6 Jakarta/ASP.NET applications (implemented as virtual directories) on a machine without a domain. The directories all exist under the default website. We need to setup the permissions so that certain users can access only specific applications yet others users can access several of the applications. The way it's been setup previously has been to explicitly deny access to the users for every application except the ones that they are allowed to see. The problem is that the list of applications changes fairly often (for demos etc) and it's been known for the developers to forget to deny the old users access to the new applications which leads to security problems. This is all quite unmaintainable. Does anybody have any advice on this? Surely I can't be the only person to find this all a bit of a mess? Thanks

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  • Accessing SQL Server in Windows XP Mode Virtual Pc

    - by DavidStein
    I have a laptop running 64bit Windows 7 Ultimate. I created a Virtual PC using Microsoft XP Mode. I've installed SQL Server 2000 on the Virtual Machine. I have SQL Server 2008 R2 installed on the Windows 7 machine (laptop). I can browse to the SQL 2000 instance (it sees it), but I cannot successfully connect using either Windows or SQL Server Authentication. I don't get an error, the attempt just times out. I have the Windows XP Mode Firewall turned off, and there doesn't appear to be anything in the Event logs either. Any ideas how I can query the XP Mode SQL Server from the Windows 7 machine?

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  • How to stream sound from an esx virtual machine ?

    - by Adrien
    Hi, I try to play sound from my monitoring application, which is an xp virtual machine on VMware ESX 3, on a physical machine with a real sound card, but I can not add from the ESX console sound card. Currently, I transmit sound with opening an RDP session and play it in this session. I would like to play sound without openning RDP session, do you have a solution to add a virtual sound card and then stream it with vlc?

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  • SQL 2008 R2 Named Instance Client Connectivity Issues?

    - by Jerry Dodge
    We're upgrading our software from using SQL 2000 to 2008 R2. Our customers will be installing an update which uninstalls 2000 and installs 2008 R2 under the same instance. So if no instance existed, then no instance name will be set (default). However, the problem starts with the customers which have a named SQL instance. Starting in 2008 R2 (not sure of ones before), for some reason, a client connecting to the server by its instance name is unsuccessful. I'm testing from the Management Studio - if I can't connect this, then nothing can connect. I browse network servers, and find the specific server\instance in the list. But, upon trying to connect to an instance name like MyServer\INST, I get: A network-related or instance-specific error occurred while establishing a connection to SQL Server. The server was not found or was not accessible. Verify that the instance name is correct and that SQL Server is configured to allow remote connections. (provider: SQL Network Interfaces, error: 26 - Error Locating Server/Instance Specified) (Microsoft SQL Server, Error: -1) I do in fact have TCP/IP and Named Pipes protocols enabled, this is the first thing I did. When I connect to the server using a comma (,) and port number like MyServer, 49195, it works just fine. So it appears that client computers are just unable to identify the instance names. This has happened on all our installations of SQL 2008 R2 and from all client computers, including Win 7, XP, Vista, Server 2008, and Server 2003. We never experienced such issues on earlier versions of SQL. The problem even persists if the firewalls and antiviruses are all disabled. Now, this is a large update which we will be distributing soon to all our customers, and we want to minimize the interaction they need with us to get this installed. We absolutely hate the idea of using a port number, because it will always be different, and we would have to modify each client to point to this server/port. Some of our customers may have hundreds of client computers. How do I make client connections to a named SQL instance work again? After all, this is the whole purpose of named instances, and if a client can't connect to this instance by its name, then what is it even named for? EDIT It was mentioned to make sure SQL Browser is running, so I checked, and it is running. The server is also able to connect to its self (locally) - just external connections are refused. UPDATE After more careful checking, I learned the firewall wasn't completely disabled when testing, and upon disabling it completely, this works. So it appears that SQL Browser is being blocked by the firewall from external clients from accessing.

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  • IP Forwarding and Routing in Windows 2008

    - by Danialzo
    I have Hyper-V running on a windows 2008. I got a new ip stack from the data center to be set on my virtual machines. But I have difficulties to set these IPs on my VMs because they are on different network. my current server ip is xxx.xxx.18.6 with MASK : 255.255.255.224 and the GW is xxx.xxx.18.1 my new ip stack is xxx.xxx.168.176/29 I can use RRAS to achieve this. Do I need to create another NIC? How do I make these VMs reachable from outside?

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  • Windows 8 with LiveID login authenticates as Guest to remote SQl Server

    - by Tim Long
    I have a network where several users are using Office Accounting 2009 in multi-user client/server mode. OA is built on SQL Server. One PC acts as the 'server' and has the SQl Server instance, the others have only the application installed and no SQL instance, all of the apps connect remotely to the SQL instance on the 'server'. I'm using the term 'server' loosely here, it is just a normal workstation that happens to be designated as the server and runs the SQL instance. There is no NT domain, all user accounts are local accounts. The way that OA works in multi-user mode is that each user is required to have a local account with the same username and password on both the client and 'server' PCs. This has been working well, no along comes Windows 8. I use my 'Microsoft Account' aka LiveID to log into Windows 8. Office Accounting runs fine and attempts to connect to the database, but fails, 'you do not have permission to perform this operation'. In the SQL logs, I get this error: 2012-10-28 17:54:01.32 Logon Error: 18456, Severity: 14, State: 11. 2012-10-28 17:54:01.32 Logon Login failed for user 'SERVER\Guest'. Reason: Token-based server access validation failed with an infrastructure SERVER is the hostname of the server. So it seems to be authenticating as 'Guest'?? To verify this, I enabled the Guest account on the 'server' PC and then added Guest as an allowed user within Office Accounting (this simply creates the user in SQL and gives it an appropriate database role). Sure enough, My Windows 8 PC was then able to connect to the database when using Office Accounting. Clearly, having users authenticate as 'Guest' stinks from a security and auditing standpoint. So what I need are some ideas for how to work around this. I've tried switching the Windows 8 PC to a 'local account' and that works too, but requires giving up significant functionality on the Windows 8 PC. What I really need is a way to force the Windows 8 PC to use a specific set of credentials when connecting to the remote SQL instance. Office Accounting takes the logged in username, which is my LiveID and doesn't correspond to any Windows user name. Anyone solved this issue?

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  • Archive Manager, SQL 2005 and MaxTokenSize high CPU

    - by Tim Alexander
    So, I posted this question a few days ago: Impact of increasing the MaxTokenSize for Kerberos Tickets Since then the thought was to test our settings on two member servers, one with IIS and one without. I setup two GPOs to configure the MaxTokenSize reg setting to 48000 and MaxFieldLength/MaxRequestBytes to 64200 (based on MS KB2020943, these are set at 4/3 * T + 200). The member server seemed to work ok (a devalued tape backup server). The IIS server however has had some strange repercussions. The IIS Sserver host Quest Software Archive Manager (AM) 4.5 that communicates with SQL Server 2005 Enterprise on Server 2003 R2. After the changes all looked good until the SQL Server hit 100% CPU. I have removed the GPOS, removed the reg values and even replaced them with defaults (12000 for token size and can't remember the other one but was in a blog post about the issue in my other post). No change. Bouncing the IIS Server stops the high CPU and a colleague has looked at the SQL server and it is definitely the AM connection taking up the time/work on the SQL server. I haven't changed the reg values on the SQL server or the DCs but am reluctant to do so without understanding why this has happened. I am guessing its to do with the overriding auth and group issue we have but I am not seeing Kerberos errors in either event log. Has anyone seen something similar or does anyone have some tips? Was definitely blindsided by the Kerberos issue and am swimming against the tide to keep things functioning.

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  • Is it possible to ensure that multiple applications run in the same terminal server session using RemoteApp?

    - by mbrownnyc
    We are interested in implementing RemoteApp on Windows 2008 R2 to serve out a few programs. Since the developers use shared memory to pass messages between processes, it is necessary that we provide them with a solution that will allow this. They have researched and discovered that if the applications exist in the same terminal server session that they will be able to access shared memory. Is there a way to absolutely ensure that multiple RemoteApps are running within the same session (with the same user) so that they can access the same shared memory?

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  • Top - what does Virtual memory size mean? ...linux/ubuntu

    - by user42159
    I am running Top to monitor my server performance and 2 of my java processes show virtual memory of upto 800MB-1GB. Is that a bad thing? What does virtual memory mean? And oh btw, I have swap of 1GB and it shoes 0% used. So I am confused. Java process = 1 Tomcat server + my own java deamon Server = Ubuntu 9.10 (karmic)

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  • Recommendations for remote server management software, similar to Puppet or Canonical Landscape?

    - by rmh
    We currently have five Ubuntu 10.04 LTS servers, and keeping them all up-to-date is starting to be a pain. I've been looking into solutions like Puppet and Canonical Landscape. Out of the two I prefer Puppet -- it would be useful to be able to ensure the permissions of various directories on the machines, and define groups and users on the server which are then propagated to clients. Is there any other software in this vein that I should be taking a look at?

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  • Virtualnetwork with virtualbox

    - by vpereira
    I would like to test a firewall solution. For that i would like to create a virtual network, without contact with my network and configure two virtual ethernet cards in my firewall. is that possible? say that my virtual machine has two ethernets? If with virtualbox is not possible, is it possible with any VM solution? To create virtual network and virtual devices in my virtual operational system

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  • Problems Allocating Objects of Derived Class Where Base Class has Abstract Virtual Functions

    - by user1743901
    I am trying to get this Zombie/Human agent based simulation running, but I am having problems with these derived classes (Human and Zombie) who have parent class "Creature". I have 3 virtual functions declared in "Creature" and all three of these are re-declared AND DEFINED in both "Human" and "Zombie". But for some reason when I have my program call "new" to allocate memory for objects of type Human or Zombie, it complains about the virtual functions being abstract. Here's the code: definitions.h #ifndef definitions_h #define definitions_h class Creature; class Item; class Coords; class Grid { public: Creature*** cboard; Item*** iboard; int WIDTH; int HEIGHT; Grid(int WIDTHVALUE, int HEIGHTVALUE); void FillGrid(); //initializes grid object with humans and zombies void Refresh(); //calls Creature::Die(),Move(),Attack(),Breed() on every square void UpdateBuffer(char** buffer); bool isEmpty(int startx, int starty, int dir); char CreatureType(int xcoord, int ycoord); char CreatureType(int startx, int starty, int dir); }; class Random { public: int* rptr; void Print(); Random(int MIN, int MAX, int LEN); ~Random(); private: bool alreadyused(int checkthis, int len, int* rptr); bool isClean(); int len; }; class Coords { public: int x; int y; int MaxX; int MaxY; Coords() {x=0; y=0; MaxX=0; MaxY=0;} Coords(int X, int Y, int WIDTH, int HEIGHT) {x=X; y=Y; MaxX=WIDTH; MaxY=HEIGHT; } void MoveRight(); void MoveLeft(); void MoveUp(); void MoveDown(); void MoveUpRight(); void MoveUpLeft(); void MoveDownRight(); void MoveDownLeft(); void MoveDir(int dir); void setx(int X) {x=X;} void sety(int Y) {y=Y;} }; class Creature { public: bool alive; Coords Location; char displayletter; Creature() {Location.x=0; Location.y=0;} Creature(int i, int j) {Location.setx(i); Location.sety(j);} virtual void Attack() =0; virtual void AttackCreature(Grid G, int attackdirection) =0; virtual void Breed() =0; void Die(); void Move(Grid G); int DecideSquare(Grid G); void MoveTo(Grid G, int dir); }; class Human : public Creature { public: bool armed; //if armed, chances of winning fight increased for next fight bool vaccinated; //if vaccinated, no chance of getting infected int bitecount; //if a human is bitten, bite count is set to a random number int breedcount; //if a human goes x steps without combat, will breed if next to a human int starvecount; //if a human does not eat in x steps, will die Human() {displayletter='H';} Human(int i, int j) {displayletter='H';} void Attack(Grid G); void AttackCreature(Grid G, int attackdirection); void Breed(Grid G); //will breed after x steps and next to human int DecideAttack(Grid G); }; class Zombie : public Creature { public: Zombie() {displayletter='Z';} Zombie(int i, int j) {displayletter='Z';} void Attack(Grid G); void AttackCreature(Grid G, int attackdirection); void Breed() {} //does nothing int DecideAttack(Grid G); void AttackCreature(Grid G, int attackdirection); }; class Item { }; #endif definitions.cpp #include <cstdlib> #include "definitions.h" Random::Random(int MIN, int MAX, int LEN) //constructor { len=LEN; rptr=new int[LEN]; //allocate array of given length for (int i=0; i<LEN; i++) { int random; do { random = rand() % (MAX-MIN+1) + MIN; } while (alreadyused(random,LEN,rptr)); rptr[i]=random; } } bool Random::alreadyused(int checkthis, int len, int* rptr) { for (int i=0; i<len; i++) { if (rptr[i]==checkthis) return 1; } return 0; } Random::~Random() { delete rptr; } Grid::Grid(int WIDTHVALUE, int HEIGHTVALUE) { WIDTH = WIDTHVALUE; HEIGHT = HEIGHTVALUE; //builds 2d array of creature pointers cboard = new Creature**[WIDTH]; for(int i=0; i<WIDTH; i++) { cboard[i] = new Creature*[HEIGHT]; } //builds 2d array of item pointers iboard = new Item**[WIDTH]; for (int i=0; i<WIDTH; i++) { iboard[i] = new Item*[HEIGHT]; } } void Grid::FillGrid() { /* For each creature pointer in grid, randomly selects whether to initalize as zombie, human, or empty square. This methodology can be changed to initialize different creature types with different probabilities */ int random; for (int i=0; i<WIDTH; i++) { for (int j=0; j<HEIGHT; j++) { Random X(1,100,1); //create a single random integer from [1,100] at X.rptr random=*(X.rptr); if (random < 20) cboard[i][j] = new Human(i,j); else if (random < 40) cboard[i][j] = new Zombie(i,j); else cboard[i][j] = NULL; } } //at this point every creature pointer should be pointing to either //a zombie, human, or NULL with varying probabilities } void Grid::UpdateBuffer(char** buffer) { for (int i=0; i<WIDTH; i++) { for (int j=0; j<HEIGHT; j++) { if (cboard[i][j]) buffer[i][j]=cboard[i][j]->displayletter; else buffer[i][j]=' '; } } } bool Grid::isEmpty(int startx, int starty, int dir) { Coords StartLocation(startx,starty,WIDTH,HEIGHT); switch(dir) { case 1: StartLocation.MoveUp(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 2: StartLocation.MoveUpRight(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 3: StartLocation.MoveRight(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 4: StartLocation.MoveDownRight(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 5: StartLocation.MoveDown(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 6: StartLocation.MoveDownLeft(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 7: StartLocation.MoveLeft(); if (cboard[StartLocation.x][StartLocation.y]) return 0; case 8: StartLocation.MoveUpLeft(); if (cboard[StartLocation.x][StartLocation.y]) return 0; } return 1; } char Grid::CreatureType(int xcoord, int ycoord) { if (cboard[xcoord][ycoord]) //if there is a creature at location xcoord,ycoord return (cboard[xcoord][ycoord]->displayletter); else //if pointer at location xcoord,ycoord is null, return null char return '\0'; } char Grid::CreatureType(int startx, int starty, int dir) { Coords StartLocation(startx,starty,WIDTH,HEIGHT); switch(dir) { case 1: StartLocation.MoveUp(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 2: StartLocation.MoveUpRight(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 3: StartLocation.MoveRight(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 4: StartLocation.MoveDownRight(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 5: StartLocation.MoveDown(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 6: StartLocation.MoveDownLeft(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 7: StartLocation.MoveLeft(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); case 8: StartLocation.MoveUpLeft(); if (cboard[StartLocation.x][StartLocation.y]) return (cboard[StartLocation.x][StartLocation.y]->displayletter); } //if function hasn't returned by now, square being looked at is pointer to null return '\0'; //return null char } void Coords::MoveRight() {(x==MaxX)? (x=0):(x++);} void Coords::MoveLeft() {(x==0)? (x=MaxX):(x--);} void Coords::MoveUp() {(y==0)? (y=MaxY):(y--);} void Coords::MoveDown() {(y==MaxY)? (y=0):(y++);} void Coords::MoveUpRight() {MoveUp(); MoveRight();} void Coords::MoveUpLeft() {MoveUp(); MoveLeft();} void Coords::MoveDownRight() {MoveDown(); MoveRight();} void Coords::MoveDownLeft() {MoveDown(); MoveLeft();} void Coords::MoveDir(int dir) { switch(dir) { case 1: MoveUp(); break; case 2: MoveUpRight(); break; case 3: MoveRight(); break; case 4: MoveDownRight(); break; case 5: MoveDown(); break; case 6: MoveDownLeft(); break; case 7: MoveLeft(); break; case 8: MoveUpLeft(); break; case 0: break; } } void Creature::Move(Grid G) { int movedir=DecideSquare(G); MoveTo(G,movedir); } int Creature::DecideSquare(Grid G) { Random X(1,8,8); //X.rptr now points to 8 unique random integers from [1,8] for (int i=0; i<8; i++) { int dir=X.rptr[i]; if (G.isEmpty(Location.x,Location.y,dir)) return dir; } return 0; } void Creature::MoveTo(Grid G, int dir) { Coords OldLocation=Location; Location.MoveDir(dir); G.cboard[Location.x][Location.y]=this; //point new location to this creature G.cboard[OldLocation.x][OldLocation.y]=NULL; //point old location to NULL } void Creature::Die() { if (!alive) { delete this; this=NULL; } } void Human::Breed(Grid G) { if (!breedcount) { Coords BreedLocation=Location; Random X(1,8,8); for (int i=0; i<8; i++) { BreedLocation.MoveDir(X.rptr[i]); if (!G.cboard[BreedLocation.x][BreedLocation.y]) { G.cboard[BreedLocation.x][BreedLocation.y])=new Human(BreedLocation.x,BreedLocation.y); return; } } } } int Human::DecideAttack(Grid G) { Coords AttackLocation=Location; Random X(1,8,8); int attackdir; for (int i=0; i<8; i++) { attackdir=X.rptr[i]; switch(G.CreatureType(Location.x,Location.y,attackdir)) { case 'H': break; case 'Z': return attackdir; case '\0': break; default: break; } } return 0; //no zombies! } int AttackRoll(int para1, int para2) { //outcome 1: Zombie wins, human dies //outcome 2: Human wins, zombie dies //outcome 3: Human wins, zombie dies, but human is bitten Random X(1,100,1); int roll= *(X.rptr); if (roll < para1) return 1; else if (roll < para2) return 2; else return 3; } void Human::AttackCreature(Grid G, int attackdirection) { Coords AttackLocation=Location; AttackLocation.MoveDir(attackdirection); int para1=33; int para2=33; if (vaccinated) para2=101; //makes attackroll > para 2 impossible, never gets infected if (armed) para1-=16; //reduces chance of zombie winning fight int roll=AttackRoll(para1,para2); //outcome 1: Zombie wins, human dies //outcome 2: Human wins, zombie dies //outcome 3: Human wins, zombie dies, but human is bitten switch(roll) { case 1: alive=0; //human (this) dies return; case 2: G.cboard[AttackLocation.x][AttackLocation.y]->alive=0; return; //zombie dies case 3: G.cboard[AttackLocation.x][AttackLocation.y]->alive=0; //zombie dies Random X(3,7,1); //human is bitten bitecount=*(X.rptr); return; } } int Zombie::DecideAttack(Grid G) { Coords AttackLocation=Location; Random X(1,8,8); int attackdir; for (int i=0; i<8; i++) { attackdir=X.rptr[i]; switch(G.CreatureType(Location.x,Location.y,attackdir)) { case 'H': return attackdir; case 'Z': break; case '\0': break; default: break; } } return 0; //no zombies! } void Zombie::AttackCreature(Grid G, int attackdirection) { int reversedirection; if (attackdirection < 9 && attackdirection>0) { (attackdirection<5)? (reversedirection=attackdirection+4):(reversedirection=attackdirection-4); } else reversedirection=0; //this should never happen //when a zombie attacks a human, the Human::AttackZombie() function is called //in the "reverse" direction, utilizing that function that has already been written Coords ZombieLocation=Location; Coords HumanLocation=Location; HumanLocation.MoveDir(attackdirection); if (G.cboard[HumanLocation.x][HumanLocation.y]) //if there is a human there, which there should be G.cboard[HumanLocation.x][HumanLocation.y]->AttackCreature(G,reversedirection); } void Zombie::Attack(Grid G) { int attackdirection=DecideAttack(G); AttackCreature(G,attackdirection); } main.cpp #include <cstdlib> #include <iostream> #include "definitions.h" using namespace std; int main(int argc, char *argv[]) { Grid G(500,500); system("PAUSE"); return EXIT_SUCCESS; }

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  • BizTalk Server 2009 R2 = BizTalk Server 2010

    - by Rajesh Charagandla
    Microsoft has renamed BizTalk Server 2009 R2 as BizTalk Server 2010, and is now telling customers that the evolution of the product recommends it as a major version versus a minor update. BizTalk Server 2009 R2 was designed mainly to bring to the table support for the company’s latest technologies, including Windows Server 2008 R2, SQL Server 2008 R2 and Visual Studio 2010. Following is list of key capabilities added to the release 1.       Enhanced trading partner management that will enable our customers to manage complex B2B relationships with ease 2.       Increase productivity through enhanced BizTalk Mapper. These enhancements are critical in increasing productivity in both EAI and B2B solutions; and a favorite feature of our customers. 3.       Enable secure data transfer across business partners with FTPS adapter 4.       Updated adapters for SAP 7, Oracle eBusiness Suite 12.1, SharePoint 2010 and SQL Server 2008 R2 5.       Improved and simplified management with updated System Center management pack 6.       Simplified management through single dashboard which enables IT Pros to backup and restore BizTalk configuration 7.       Enhanced performance tuning capabilities at Host and Host Instance level 8.       Continued innovation in RFID Space with out of box event filtering and delivery of RFID events

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  • Configuring Team Foundation Server Basic on Home Server.

    - by Enrique Lima
    For the installation I selected only the Team Foundation Server role. Then, I opened the Team Foundation Server Administration Console (which I think is a great addition and improvement over the way TFS was configured in the past) to proceed with the configuration of the pieces. Once I selected the Configure Installed Features, the Configuration Center opened up. Now, the choices … In my implementation here I just want to take advantage of Source Control primarily.  I want to be able to store my code and projects.  So, Basic it is! So, the Basic Configuration Wizard opens up.  Now the options to configure are very limited, but we have to provide details for the SQL Server Instance. And now, to select Install SQL Server express.  If you want to take advantage of another system in your environment to host your database, well you could Use an existing SQL Server Instance. Once it has the details it needs, you get a Summary view to confirm your choices. Once, you click next or verify, it runs readiness checks on your system to make sure the installation will have a successful pass.  And we love GREEN! Now, since got the green flag, our next stop is to let the wizard do its magic, click on Configure.  And once again, we love GREEN! We click Next, and … We like a big Green Success sign … We close the Configuration Center … First results … Web Access …  Nothing to show … but we are there! And all this running from a Microsoft Home Server installation.

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