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  • Can Spring access-denied-handler refer to popup?

    - by Rens Groenveld
    I am working with Spring Security 3.1.x and have implemented method annotation securities. As I want, when I perform a certain action while being logged in as a used that doesn't have the rights, I get a 403 acces is denied in my console! Perfect! Now I would like to catch this 403, and give the user a popup with a custom message. I don't want to redirect users to a page saying that they have no rights. Is there any way the access-denied-handler of Spring can take care of a popup? Or can it only redirect to another page? Maybe there are other options for me? Thanks in advance!

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  • JDO architecture: One to many relationship and cascading deleting

    - by user361897
    I’m new to object oriented database designs and I’m trying to understand how I should be structuring my classes in JDO for google app engine, particularly one to many relationships. Let’s say I’m building a structure for a department store where there are many departments, and each department has many products. So I’d want to have a class called Department, with a variable that is a list of a Product class. @PersistenceCapable public class Department { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private String deptID; @Persistent private String departmentName; @Persistent private List<Product>; } @PersistenceCapable public class Product { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private String productID; @Persistent private String productName; } But one Product can be in more than one Department (like a battery could be in electronics and household supplies). So the next question is, how do I not duplicate data in the OOD world and have only one copy of product data in numerous departments? And the next question is, let’s say I delete out a particular product, how do each of the departments know it was deleted?

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  • Android: Alignment of four squares

    - by metter
    Hello There I am trying to align four equally sized squares on an Android Screen & I have now tried what feels like a million different approaches, yet none of them seem to work :(. What I've got at the moment is the following: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/MasterLayout" android:layout_width="wrap_content" android:layout_height="fill_parent" android:background="#FFFFFF" <TableRow android:layout_weight="1" android:background="#BBBBBB" android:padding="0dip"> <TableRow android:layout_weight="1" android:padding="0dip"> This basically does the job. However, every one of those four Images has a huge padding above and under it. How do I get rid of that? Or do I need to use a different Layout type alltogether? To help illustrate my problem, here's a picture. On the left is what I got, on the right is what I need. Image Thank you very much! Cheers, Markus!

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  • Not able to click on all the links in Selenium Webdriver.Only the first link gets clicked

    - by Kiran
    .i want to go to a frame in which some links are there....Once I come in to a fram.i want to click all the links one by one..using webdriver...below is the code i have written.plz suggest me public static void main(String[] args) { // TODO Auto-generated method stub WebDriver driver=new FirefoxDriver(); driver.get("http://timesofindia.indiatimes.com/home"); WebDriverWait wait= new WebDriverWait(driver,200); wait.until(ExpectedConditions.presenceOfElementLocated(By.id("riShop"))); driver.switchTo().frame("riShop"); List<WebElement> lst=driver.findElements(By.tagName("a")); for(inti=0;i<lst.size();i++){ lst.get(i).click(); driver.navigate().back(); } } } } In the above code....only the first link gets clicked and then i get exception like..unable to locate the next element.....NoSuchException plz suggest me something about it...

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  • How to Prevent an Applet from Unloading across web pages?

    - by Francis Shanahan
    I have a large applet that takes some 40 seconds to initialize (cabs are cached so ignore download time for this question). The issue is, if the user goes to Page A which launches the applet (single window) and then navigates to page B, the applet is unloaded. If the user goes back to Page A, they incur the 40 seconds init time once again. I'd like to be able to launch the applet, incurring the 40 seconds init time once and only once. The applet needs to reside inside a single browser window (the same window as my web application). In other words, I cannot launch the applet in a popup. Does anyone have any creative ideas around how to prevent the applet unloading?

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  • Complete list of Fonts which support

    - by Yan Cheng CHEOK
    Currently, if I change the locale setting of my application by Locale.setDefault(Locale.ENGLISH); Locale.setDefault(Locale.SIMPLIFIED_CHINESE); What I understand from this JFreeChart forum is that, I am not using correct font. Once you get the reference of the LegentTitle, you can set it to any font. Apparently, JFreeChart's default is "Tahoma" and it doesn't support Chinese characters. May I know, how I can programmatic determine, as list of available Fonts in my system, which support Chinese? I can hard code it to Serif (It fully support Chinese, doesn't it?), its look n feel doesn't looks good to me. I would like to have more choices.

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  • Storing Result set into an array

    - by OVERTONE
    i know this should be simpel and im probably staring straight at the problem but once again im stuck and need the help of the code gurus. im trying too take one row from a column in jdbc, and put them in an array. i do this as follows: public void fillContactList() { createConnection(); try { Statement stmt = conn.createStatement(); ResultSet namesList = stmt.executeQuery("SELECT name FROM Users"); try { while (namesList.next()) { contactListNames[1] = namesList.getString(1); System.out.println("" + contactListNames[1]); } } catch(SQLException q) { } conn.commit(); stmt.close(); conn.close(); } catch(SQLException e) { } creatConnection is an already defined method that does what it obviously does. i creat my result set while theres another one, i store the string of that column into an array. then print it out for good measure. too make sure its there. the problem is that its storing the entire column into contactListNames[1] i wanted to make it store column1 row 1 into [1] then column 1 row 2 into [2] i know i could do this with a loop. but i dont know too take only one row at a time from a single column. any ideas? p.s ive read the api, i jsut cant see anything that fits.

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  • Android: Prompt user to save changes when Back button is pressed

    - by chriskopec
    I have an activity that contains several user editable items (an EditText field, RatingBar, etc). I'd like to prompt the user if the back/home button is pressed and changes have been made that have not yet been saved. After reading through the android documentation, it seems like this piece of code should go in the onPause method. I've tried putting an AlertDialog in the onPause however the dialog gets shown and then immediately tears down because nothing is there to block the pause from completing. This is what I've come up with so far: @Override protected void onPause() { super.onPause(); AlertDialog ad = new AlertDialog.Builder(this).setMessage( R.string.rating_exit_message).setTitle( R.string.rating_exit_title).setCancelable(false) .setPositiveButton(android.R.string.ok, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { // User selects OK, save changes to db } }).setNeutralButton(android.R.string.cancel, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { // User selects Cancel, discard all changes } }).show(); } Am I on the right track or is there another way to accomplish what I'm trying to do here? Any help would be great!

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  • JSP Component Creation

    - by jboyd
    When creating JSP pages one thing that I'd often like is the ability to do something like this: <jsp:include page="fancystoryrenderer.jsp" value="${aStoryObjectInMyModel}/> ... fancystoryrenderer.jsp <div id="fancymainbody"> ... ${theStory.title} ... </div> The main important characteristics of this is that I can reuse the same component on the same JSP page in different places without having to copy paste the component and give the story variables different names, notice that the story is called "theStory" in the JSP and not "aStoryObjectInMyModel", the linkage between our model has been broken by the view, which is a good thing in this case How do you do this?

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  • Get first character of each word and its position in a sentence/paragraph

    - by Radhika
    I am trying to create a map by taking the first character of each word and it's position in a sentence/paragraph. I am using regex pattern to achieve this. Regex is a costly operation. Are there are any ways to achieve this? Regex way: public static void getFirstChar(String paragraph) { Pattern pattern = Pattern.compile("(?<=\\b)[a-zA-Z]"); Map newMap = new HashMap(); Matcher fit = pattern.matcher(paragraph); while (fit.find()) { newMap.put((fit.group().toString().charAt(0)), fit.start()); } }

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  • Regular expression to truncate a String

    - by user470184
    To truncate a String here is what I'm using : String test1 = "this is test truncation 1.pdf"; String p1 = test1.substring(0, 10) + "..."; System.out.println(p1); The output is 'this is te...' How can I access the file name extension so that output becomes : 'this is te... pdf' I could use substring method to access the last three characters but other file extensions could be 4 chars in length such as .aspx Is there a regular expression I can use so that "this is test truncation 1.pdf" becomes "this is te... pdf"

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  • Using the JPA Criteria API, can you do a fetch join that results in only one join?

    - by Shaun
    Using JPA 2.0. It seems that by default (no explicit fetch), @OneToOne(fetch = FetchType.EAGER) fields are fetched in 1 + N queries, where N is the number of results containing an Entity that defines the relationship to a distinct related entity. Using the Criteria API, I might try to avoid that as follows: CriteriaBuilder builder = entityManager.getCriteriaBuilder(); CriteriaQuery<MyEntity> query = builder.createQuery(MyEntity.class); Root<MyEntity> root = query.from(MyEntity.class); Join<MyEntity, RelatedEntity> join = root.join("relatedEntity"); root.fetch("relatedEntity"); query.select(root).where(builder.equals(join.get("id"), 3)); The above should ideally be equivalent to the following: SELECT m FROM MyEntity m JOIN FETCH myEntity.relatedEntity r WHERE r.id = 3 However, the criteria query results in the root table needlessly being joined to the related entity table twice; once for the fetch, and once for the where predicate. The resulting SQL looks something like this: SELECT myentity.id, myentity.attribute, relatedentity2.id, relatedentity2.attribute FROM my_entity myentity INNER JOIN related_entity relatedentity1 ON myentity.related_id = relatedentity1.id INNER JOIN related_entity relatedentity2 ON myentity.related_id = relatedentity2.id WHERE relatedentity1.id = 3 Alas, if I only do the fetch, then I don't have an expression to use in the where clause. Am I missing something, or is this a limitation of the Criteria API? If it's the latter, is this being remedied in JPA 2.1 or are there any vendor-specific enhancements? Otherwise, it seems better to just give up compile-time type checking (I realize my example doesn't use the metamodel) and use dynamic JPQL TypedQueries.

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  • making a jar file for console

    - by user472221
    Hi I have a program without a GUI and I use console! So first I read a line from a user from console BufferedReader userReader = new BufferedReader(new InputStreamReader(System.in)); and then I will write an answer for the user in the console! System.out.println("Server:"+output); I want to create a jar file for it ! but how can i show my console in jar file with out using GUI? please help me thanks.

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  • Space as grouping separator in printf

    - by blekione
    I know how to use comma in printf as grouping separator to print value in format like 1,000,000.00 to print it that way I'm using command System.out.printf ("%,.2f", value); but how to use space as grouping separator to format value like 1 000 000.00 I tried to find solution but solutions with using DecimalFormat look at now to complicate for me (beginner level). Is there as easy way as in example with comma to do it?

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  • graphing amplitude

    - by John
    I was wondering if someone could point me to a good tutorial or show me how to graph the amplitude from a bytearray. The audio format I am using is: ULAW 8000.0 Hz, 8 bit, mono, 1 bytes/frame.

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  • Barcode reading method?

    - by Atlas
    I recently acquired a Metrologic Barcode scanner (USB port), as everyone already knows it works as a keyboard emulator out of the box. Now my question, how do I configure the scanner and my application, so that my app can process the barcode data directly. That is, I don't want the user to focus on a "Text field" and then process the data when the KeyPress event fires.

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  • ListView created programmatically - emptyView doesn't show

    - by Yorick
    I've created custom ListView programmatically, and set view to show when ListAdapter is empty but nothing shows on the screen in that case, what can be wrong? public PlayerList(Context context, Activity activity) { super(context); mParent = activity; setOnItemClickListener( new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { ... } }; List<PlayerInfo> players; players = getPlayerList(); // here size of players == 0 setAdapter(new PlayersAdapter(this.getContext(), R.id.player_name, players)); LayoutInflater vi = (LayoutInflater)mParent.getSystemService(Context.LAYOUT_INFLATER_SERVICE); emptyView = vi.inflate(R.layout.empty_view, null); // emptyView is View, and member of PlayerList this.setEmptyView(emptyView); }

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  • Multiple returns: Which one sets the final return value?

    - by DR
    Given this code: String test() { try { return "1"; } finally { return "2"; } } Do the language specifications define the return value of a call to test()? In other words: Is it always the same in every JVM? In the Sun JVM the return value is 2, but I want to be sure, that this is not VM-dependant.

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  • StreamTokenizer Iterator Adapter help

    - by alpdog14
    I have this StreamTokenizer Iterator Adapter that is suppose to create a Tokenizer Iterator Index Builder then build the index from a STIA wrapped around a StreamTokenizer. I am having trouble implementing the hasNext and Next for my STIA, can anyone help me, here is my class: public class StreamTokenizerIteratorAdapter implements Iterator<Token> { DefaultIndexImpl index; StreamTokenizer source; public StreamTokenizerIteratorAdapter(final StreamTokenizer source) { if (source == null) throw new IllegalArgumentException("source == null"); } @Override public boolean hasNext() { return !index.isEmpty(); } public Token next() { if(!index.isEmpty()) return next(); else return null; } @Override public void remove() { throw new UnsupportedOperationException(); } } Should I be using the source element in the hasNext() and next()?

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  • arrayListOutOfBoundsException... Please Help?

    - by Jacob
    This is my class Debugger. Can anyone try and run it and see whens wrong? Ive spent hours on it already. :( public class Debugger { private String codeToDebug = ""; public Debugger(String code) { codeToDebug = code; } /** * This method itterates over a css file and adds all the properties to an arraylist */ public void searchDuplicates() { boolean isInside = false; ArrayList<String> methodStorage = new ArrayList(); int stored = 0; String[] codeArray = codeToDebug.split(""); try { int i = 0; while(i<codeArray.length) { if(codeArray[i].equals("}")) { isInside = false; } if(isInside && !codeArray[i].equals(" ")) { boolean methodFound = false; String method = ""; int c = i; while(!methodFound) { method += codeArray[c]; if(codeArray[c+1].equals(":")) { methodFound = true; } else { c++; } } methodStorage.add(stored, method); System.out.println(methodStorage.get(stored)); stored++; boolean stillInside = true; int skip = i; while(stillInside) { if(codeArray[skip].equals(";")) { stillInside = false; } else { skip++; } } i = skip; } if(codeArray[i].equals("{")) { isInside = true; } i++; } } catch(ArrayIndexOutOfBoundsException ar) { System.out.println("------- array out of bounds exception -------"); } } /** * Takes in String and outputs the number of characters it contains * @param input * @return Number of characters */ public static int countString(String input) { String[] words = input.split(""); int counter = -1; for(int i = 0; i<words.length; i++){ counter++; } return counter; } public static void main(String[] args) { Debugger h = new Debugger("body {margin:;\n}"); h.searchDuplicates(); } }

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