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• Swing: set JFrame content area size

  - by igul222

  I'm trying to make a JFrame with a usable content area of exactly 500x500. If I do this... public MyFrame() { super("Hello, world!"); setSize(500,500); } ... I get a window whose full size is 500x500, including the title bar, etc., where I really need a window whose size is something like 504x520 to account for the window border and titlebar. How can I achieve this?

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• KXML library Problem

  - by Hesham

  i'm working j2me with netbeans platform and i had a problem while i was trying to read a XML file and i added the library kxml.zip to my project's libraries and i used some of it's functions, there r no errors or red lines in the code, but the problem is that i cant run the project cos it come up with errors while compiling and all these errors are on the kxml functions, so any on can help me through this cos i really dont know what to do to make it run properly

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• Does thread pool size keep growing for scheduledthreadpoolexecutor?

  - by Sourajit Basak

  Imagine a situation where tasks are being added to scheduledthreadpoolexecutor. Each of these tasks will keep on running at different periodic intervals. Although all such tasks will not be running at the same time because each is set at different intervals, there may be a situation where a high number of threads are competing for execution. Is there any restriction on total number of threads ? It seems there is a restriction on the total number of idle threads. And does this concept of idle thread imply that long running tasks (thread) may be destroyed and recreated when needed ?

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• Complete list of Fonts which support

  - by Yan Cheng CHEOK

  Currently, if I change the locale setting of my application by Locale.setDefault(Locale.ENGLISH); Locale.setDefault(Locale.SIMPLIFIED_CHINESE); What I understand from this JFreeChart forum is that, I am not using correct font. Once you get the reference of the LegentTitle, you can set it to any font. Apparently, JFreeChart's default is "Tahoma" and it doesn't support Chinese characters. May I know, how I can programmatic determine, as list of available Fonts in my system, which support Chinese? I can hard code it to Serif (It fully support Chinese, doesn't it?), its look n feel doesn't looks good to me. I would like to have more choices.

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• Why would you have two constructors with the same signature?

  - by kunjaan

  What are the use cases of having two constructors with the same signature?

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• Hibernate Persistence problems with Bean Mapping (Dozer)

  - by BuffaloBuffalo

  I am using Hibernate 3, and having a particular issue when persisting a new Entity which has an association with an existing detached entity. Easiest way to explain this is via code samples. I have two entities, FooEntity and BarEntity, of which a BarEntity can be associated with many FooEntity: @Entity public class FooEntity implements Foo{ @Id private Long id; @ManyToOne(targetEntity = BarEntity.class) @JoinColumn(name = "bar_id", referencedColumnName = "id") @Cascade(value={CascadeType.ALL}) private Bar bar; } @Entity public class BarEntity implements Bar{ @Id private Long id; @OneToMany(mappedBy = "bar", targetEntity = FooEntity.class) private Set<Foo> foos; } Foo and Bar are interfaces that loosely define getters for the various fields. There are corresponding FooImpl and BarImpl classes that are essentially just the entity objects without the annotations. What I am trying to do is construct a new instance of FooImpl, and persist it after setting a number of fields. The new Foo instance will have its 'bar' member set to an existing Bar (runtime being a BarEntity) from the database (retrieved via session.get(..)). After the FooImpl has all of its properties set, Apache Dozer is used to map between the 'domain' object FooImpl and the Entity FooEntity. What Dozer is doing in the background is instantiating a new FooEntity and setting all of the matching fields. BarEntity is cloned as well via instantiation and set the FooEntity's 'bar' member. After this occurs, passing the new FooEntity object to persist. This throws the exception: org.hibernate.PersistentObjectException: detached entity passed to persist: com.company.entity.BarEntity Below is in code the steps that are occurring FooImpl foo = new FooImpl(); //returns at runtime a persistent BarEntity through session.get() Bar bar = BarService.getBar(1L); foo.setBar(bar); ... //This constructs a new instance of FooEntity, with a member 'bar' which itself is a new instance that is detached) FooEntity entityToPersist = dozerMapper.map(foo, FooEntity.class); ... session.persist(entityToPersist); I have been able to resolve this issue by either removing or changing the @Cascade annotation, but that limits future use for say adding a new Foo with a new Bar attached to it already. Is there some solution here I am missing? I would be surprised if this issue hasn't been solved somewhere before, either by altering how Dozer Maps the children of Foo or how Hibernate reacts to a detached Child Entity.

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• Reading http file on url

  - by Nkunzis

  I am trying to read an xml file on an http url. "Unexpected end of file from server" keeps on coming . the page is password protected, I would like to know if I am properly giving in my url authentication details. I tried with non protected pages and I can read them properly. Here is my code: URL url = new URL("http://username:[email protected]:0000/test.xml"); URLConnection yc = url.openConnection(); BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream())); String inputLine; while ((inputLine = in.readLine()) != null) System.out.println(inputLine); in.close();

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• GET is not working for firstResource Rest example

  - by Anandan

  Hi, I am newbie to rest. I am using the following code example to understand the RESTlet. http://www.restlet.org/documentation/1.1/firstResource I am using RESTClient addon to firefox for testing. When i do GET on http://localhost/rest, i get a response "ok". But when i do GET on http://localhost/items, I get an error "404 Not found" Here's the sample code: public synchronized Restlet createRoot() { Router router = new Router(getContext()); router.attach("/items", ItemsResource.class); router.attach("/items/{itemName}", ItemResource.class); Restlet restlet = new Restlet() { @Override public void handle(Request request, Response response) { StringBuilder stringBuilder = new StringBuilder(); stringBuilder.append("ok"); response.setEntity(new StringRepresentation(stringBuilder .toString(), MediaType.TEXT_HTML)); } }; router.attach("/rest", restlet); return router; } ItemResource is same as provided in the link. and I use tomcat to run the servlet. Why am I getting the "Not found" error? Am i missing something here? Thanks & Regards, Anandan

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• How to select item in jComboBox

  - by jtnire

  Hi folks, I have a jComboBox that I am populating with some objects. The objects are of a type which I have made myself, and include a String and an int. The object's toString method returns the String, which is displayed in the Combo Box. Now, I wish to select an item in the Combo Box with code. How do I do this? There are multiple items starting with the same letter Thanks

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• Wait between tasks with SingleThreadExecutor

  - by Lord.Quackstar

  I am trying to (simply) make a blocking thread queue, where when a task is submitted the method waits until its finished executing. The hard part though is the wait. Here's my 12:30 AM code that I think is overkill: public void sendMsg(final BotMessage msg) { try { Future task; synchronized(msgQueue) { task = msgQueue.submit(new Runnable() { public void run() { sendRawLine("PRIVMSG " + msg.channel + " :" + msg.message); } }); //Add a seperate wait so next runnable doesn't get executed yet but //above one unblocks msgQueue.submit(new Runnable() { public void run() { try { Thread.sleep(Controller.msgWait); } catch (InterruptedException e) { log.error("Wait to send message interupted", e); } } }); } //Block until done task.get(); } catch (ExecutionException e) { log.error("Couldn't schedule send message to be executed", e); } catch (InterruptedException e) { log.error("Wait to send message interupted", e); } } As you can see, there's alot of extra code there just to make it wait 1.7 seconds between tasks. Is there an easier and cleaner solution out there or is this it?

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• how do i set up an SMS server?

  - by I__

  just like google as the number GOOGL (46645) i would like to also set up a server like this that will have the ability to receive text messages. how do i do this??

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• Extract elements from list based on object property type

  - by Dustin Digmann

  Often, I have a list of objects. Each object has properties. I want to extract a subset of the list where a specific property has a predefined value. Example: I have a list of User objects. A User has a homeTown. I want to extract all users from my list with "Springfield" as their homeTown. I normally see this accomplished as follows: List users = getTheUsers(); List returnList = new ArrayList(); for (User user: users) { if ("springfield".equalsIgnoreCase(user.getHomeTown()) returnList.add(user); } I am not particularly satisfied with this solution. Yes, it works, but it seems so slow. There must be a non-linear solution. Suggestions?

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• Jaxb to generate the XML directly to the OutputStream

  - by sonu

  Hi, I have a 500Mb csv file. I need to convert it into XML file. I am using the Jaxb to created the xml file. It is working fine for small amout of data. but for large amout of data like 300 mb it is throwing out of memory exception. Can anyone tell me that How can I create each element and write it into a file without creating the whole tree using the jaxb?" Thanks Sonu

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• How can i find roughly time of song from its size

  - by angelina

  Dear all, I have a song say about 5.1 mb ,i want to calculate total duration of song before being played on media player the file format is wave file.

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• What features EJB3 bring and also how does EJB3 stack up with Spring Framework ?

  - by Rachel

  I have never worked on ejb, when I started programming Spring was already arrived and all my projects have been with Spring only, recently I had one interview and they wanted knowledge of EJB3.0 and so I want to know how does EJB3.0 stack up with Spring Framework and why many projects now a day are with Spring Framework and not with EJB3.0, do not quote me here as I can be wrong I would really appreciate if difference and benefits of using one over another could be explained from practical perspective.

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• Can php listen for a mysql database change or update? ...thinking real-time, live search here

  - by Derrick

  Im trying to think of the best way to handle real time search for a website. The only solution I can come up with is to keep checking the server every few seconds for something new in the database, but that does not seem very practical to me.

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• Best Design Pattern to Implement while Mapping Actions in MVC

  - by FidEliO

  What could be the best practices of writing the following case: We have a controller which based on what paths users take, take different actions. For example: if user chooses the path /path1/hello it will say hello. If a user chooses /path1/bye?name="Philipp" it will invoke sayGoodBye() and etc. I have written a switch statement inside the controller which is simple, however IMO not efficient. What are the best way to implement this, considering that paths are generally String. private void takeAction() { switch (path[1]) { case "hello": //sayHello(); break; case "bye": //sayBye(); break; case "case3": //Blah(); break; ... } }

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• Tomcat does not persist UserPrinciple during restart

  - by mabuzer

  How to force Tomcat to serialize UserPrinciple so that the user is kept logged in when Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.26

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• unit testing with junit4

  - by Codenotguru

  how do i create a test suite in junit4 ??

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• Full and Partial Matching of Sets

  - by jeffrey

  I have several sets of the same type [Y, M, D] and am trying to write a function to search these sets and return an array of the available sets that fit my parameters. ReturnedSets = return_matches(Y,M,D); I want the three parameters of the function return_matches to be optional. Which means any combination of values can be used to return the sets. For example, one could write - return_matches(13,null,2); - and the function would look for all sets that contain [13, anyValue, 2]; I'm writing this in PHP, to allow users to manage dated files on my website, but I'd like to be able to use this function again for other uses. Thanks! edit: (This, or variations of this, is all I can come up with so far... There is something extra that I don't understand, because this function ends up / would not work to return sets that contain y and d, but leaving m arbitrary. if(y == s[0]){ if(m == s[1]){ if(d == s[2]){ print "day match"; } } else {print "month match";} } else {print "year match";} } else {print "no match";}

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• Given an array of integers [x0 x1 x2], how do you calculate all possible permutations from [0 0 0] t

  - by user319951

  I am writing a program that takes in an ArrayList and I need to calculate all possible permutations starting with a list of zeroes, up to the value in the corresponding input list. Does anyone know how to iteratively calculate these values? For example, given [ 1 2 ] as input, it should find and store the following lists: [0 0], [1 0], [1 1], [1 2], [0 1], [0 2] Thanks!

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• How to merge arraylist element ?

  - by tiendv

  I have a string example = " Can somebody provide an algorithm sample code in your reply ", after token and do some i want on string example i have arraylist like : ArrayList <token > arl = " "Can somebody provide ", "code in your ", "somebody provide an algorith", " in your reply" ) "Can somebody provide ", i know position start and end in string test : star = 1 end = 3 " code in your ", i know position stat = 7 end = 10, "somebody provide an algorith", i know position stat = 7 end = 10, "in your reply" i know position stat = 11 end = 14, we can see,some element in arl overlaping :"Can somebody provide "," code in your ","somebody provide an algorith". The problem here is how can i merge overlaping element to recived arraylist like ArrayList result ="" Can somebody provide an algorithm sample code","" in your reply""; Here my code : but it only merge fist elecment if check is overloaping public ArrayList<TextChunks> finalTextChunks(ArrayList<TextChunks> textchunkswithkeyword) { ArrayList<TextChunks > result = (ArrayList<TextChunks>) textchunkswithkeyword.clone(); //System.out.print(result.size()); int j; for(int i=0;i< result.size() ;i++) { int index = i; if(i+1>=result.size()){ break; } j=i+1; if(result.get(i).checkOverlapingTwoTextchunks(result.get(j))== true) { TextChunks temp = new TextChunks(); temp = handleOverlaping(textchunkswithkeyword.get(i),textchunkswithkeyword.get(j),resultSearchEngine); result.set(i, temp); result.remove(j); i = index; continue; } } return result; } Thanks in avadce

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• Counting the number of occurrences of characters in an array

  - by Anthony Pittelli

  This is what I have but it is not working, this is confusing for me. If you scroll down I commented on someones post the exact problem I am having and what I am trying to do. I was thinking maybe the problem is my code to generate the random characters: public void add (char fromChar, char toChar){ Random r = new Random(); //creates a random object int randInt; for (int i=0; i<charArray.length; i++){ randInt = r.nextInt((toChar-fromChar) +1); charArray[i] = (char) randInt; //casts these integers as characters } }//end add public int[] countLetters() { int[] count = new int[26]; char current; for (int b = 0; b <= 26; b++) { for (int i = 97; i <= 123; i++) { char a = (char) i; for (int ch = 0; ch < charArray.length; ch++) { current = charArray[ch]; if (current == a) { count[b]++; } } } } return count; }

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• Printing a list using reflection

  - by TFool

  public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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• multiple screen support

  - by pedr0

  Hi at all, I have some problem with multiple screen support, I work with dp(dpi) for specify the layout_heigth and layout_width and I hope that is the better way to support multiple screen, but when I tried with two smartphone I meet two different result. I give an example, this is a layout I use: <?xml version="1.0" encoding="UTF-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/cities_main_layout" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <ListView android:id="@+id/citieslist" android:layout_width="wrap_content" android:layout_height="320dip" android:layout_gravity="center_vertical" android:layout_below="@id/cities_main_layout" /> <LinearLayout android:id="@+id/cities_button_layout" android:orientation="horizontal" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@id/citieslist" android:layout_gravity="center_vertical"> <Button android:id="@+id/bycountry" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_bycountry" /> <Button android:id="@+id/top10" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_top10" /> <Button android:id="@+id/recommended" android:layout_height="50dip" android:layout_width="105dip" android:background="@drawable/buttonmarket" android:text="@string/button_recommended" /> </LinearLayout> </RelativeLayout> The button are at the bottom of the layout, and I see two different result: In the last smartphone I can see the buttons, instead in the first I cannot...what's wrong? I have to write a layout for any set of screen??!!!

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