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  • Only change img inside children li

    - by steve
    Say my code is as follows: <ul> <li><img /></li> <li> <ul> <li><img /></li> </ul> </li> </ul> I'm trying to set a default size for the first img tag, but not affect the second one. everything I do affects the other one as well. Currently I have tried: $('ul#gallery > li').find('img').css('width','650px'); $('ul#gallery > li img').css('width','650px'); among others, but nothing works.

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  • Walking to the North Pole to raise money to protect children from cruelty.

    - by jessica.ebbelaar
    Hi, my name is Luca. I joined Oracle in 2005 and I am currently working as a Dell EMEA Channel Manager UK, Ireland and Iberia and I am responsible for the Oracle Dell relationship for the above 3 countries. On the 31st of March 2011 I will set out to complete the ultimate challenge. I will walk and ski across the frozen Arctic to the Top of The World: the GEOGRAPHIC North Pole. While dragging all my supplies over 60 Nautical miles of moving sea ice, in temperatures as low as minus 30 degrees Celsius. I will spend 8 to 10 days preparing, working, living and travelling to the North Pole to 90 degree north. In November I spent a full week of training for this trip.( watch my video). This gave me the opportunity to meet the rest of the team, testing all the gear and carrying an 18inch tyre around the country side for 8 hours per day. I am honored to embark this challenging journey to support the National Society for the Prevention of Cruelty to Children (NSPCC). The NSPCC helped more than 750,000 young people to speak out for the first time about abuse they had suffered. I am a firm believer that in order to build a stronger, healthier and wiser society we need to support and help future generations from the beginning of their life journey. This is why cruelty to children must stop. FULL STOP.   Through Virgin Money Giving, you can sponsor me and donations will be quickly processed and passed to NSPCC. Virgin Money Giving is a non-profit organization and will claim gift aid on a charity's behalf where the donor is eligible for this. If you are a UK tax payer please don't forget to select Gift Aid. Gift Aid is great because it means charities get extra money added to their donations at no extra cost to the donor. For every £1 donated, the charity currently receives £1.28 when you add Gift Aid. Anyone who would like to find out more can visit my Facebook page ‘Luca North Pole charity fundraising trip’ I really appreciate all your support and thank you for supporting the NSPCC. Tags van Technorati: Channel Manager,challenge,Arctic,North Pole,NSPCC,cruelty to children,Luca North Pole charity fundraising trip. If fou have any questions related to this article contact [email protected].

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  • What happens to a SIGINT (^C) when sent to a perl script containing children?

    - by CmdrGuard
    I have a Perl script that forks. Each fork runs an external program, parses the output, and converts the output to a Storable file. The Storable files are then read in by the parent and the total data from each of the children are analyzed before proceeding onto a repeat of the previous fork or else the parent stops. What exactly happens when I issue a ^C while some of the children are still running the external program? The parent perl script was called in the foreground and, I presume, remained in the foreground despite the forking. Is the SIGINT passed to all children, that is, the parent, the parent's children, and the external program called by the children??

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  • How to create a dynamic number of possibly children objects using partial views?

    - by NullReference
    I have a parent object that contains a property that is a list of children objects. I'd like to have it so that when the form loads to create the parent object a partial view is used to create the list of child objects. The problem is I have to idea how to have the list of children object populated. I can do one object ok, but a dynamic list of possible children is difficult. Any ideas? @Html.RenderPartial("_CreateChild", Model.Children); public class Parent { private List<Child> _list; public Guid Id { get; set; } public List<Child> Children { get { return _list; } set { _list = value; } } public Parent() { _list = new List<Child>(); } }

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  • How to replace slide effect to fade out/fade in effect on this slideshow?

    - by LDam
    Hi guys! I need replace slide effect to fade-out/fade-in effect on the prev and next slide functions: function animate(dir,clicked){ u = true; switch(dir){ case 'next': t = t+1; m = (-(t*w-w)); current(t); if(o.autoHeight){autoHeight(t);} if(s<3){ if (t===3){$(o.slides,obj).children(':eq(0)').css({left:(s*w)});} if (t===2){$(o.slides,obj).children(':eq('+(s-1)+')').css({position:'absolute',left:(w)});} } $(o.slides,obj).animate({left: m}, o.slidespeed,function(){ if (t===s+1) { t = 1; $(o.slides,obj).css({left:0},function(){$(o.slides,obj).animate({left:m})}); $(o.slides,obj).children(':eq(0)').css({left: 0}); $(o.slides,obj).children(':eq('+(s-1)+')').css({ position:'absolute',left:-w}); } if (t===s) $(o.slides,obj).children(':eq(0)').css({left:(s*w)}); if (t===s-1) $(o.slides,obj).children(':eq('+(s-1)+')').css({left:s*w-w}); u = false; }); break; case 'prev': t = t-1; m = (-(t*w-w)); current(t); if(o.autoHeight){autoHeight(t);} if (s<3){ if(t===0){$(o.slides,obj).children(':eq('+(s-1)+')').css({position:'absolute',left:(-w)});} if(t===1){$(o.slides,obj).children(':eq(0)').css({position:'absolute',left:0});} } $(o.slides,obj).animate({left: m}, o.slidespeed,function(){ if (t===0) { t = s; $(o.slides,obj).children(':eq('+(s-1)+')').css({position:'absolute',left:(s*w-w)}); $(o.slides,obj).css({left: -(s*w-w)}); $(o.slides,obj).children(':eq(0)').css({left:(s*w)}); } if (t===2 ) $(o.slides,obj).children(':eq(0)').css({position:'absolute',left:0}); if (t===1) $(o.slides,obj).children(':eq('+ (s-1) +')').css({position:'absolute',left:-w}); u = false; }); break; case 'fade': t = [t]*1; m = (-(t*w-w)); current(t); if(o.autoHeight){autoHeight(t);} $(o.slides,obj).children().fadeOut(o.fadespeed, function(){ $(o.slides,obj).css({left: m}); $(o.slides,obj).children(':eq('+(s-1)+')').css({left:s*w-w}); $(o.slides,obj).children(':eq(0)').css({left:0}); if(t===s){$(o.slides,obj).children(':eq(0)').css({left:(s*w)});} if(t===1){$(o.slides,obj).children(':eq('+(s-1)+')').css({ position:'absolute',left:-w});} $(o.slides,obj).children().fadeIn(o.fadespeed); u = false; }); break; default: break; } }; I had tried, but the auto restart didn't work! You can view the documentation and download the complete code with the examples in this link: http://github.com/nathansearles/loopedSlider/tree/master Please help me! (Sorry for my bad english!)

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  • Add 'expand' button to JTree node that has no children?

    - by thedude19
    I'd like to add the 'expand' button to my JTree's nodes to indicate that they are expandable. The catch is that they have no children until the user clicks on them (due to processing that happens in the background). Is there any way I can set a node as a parent or having children without it actually having children? Thanks

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  • How to iterate a list inside a list in java?

    - by user2142786
    Hi i have two value object classes . package org.array; import java.util.List; public class Father { private String name; private int age ; private List<Children> Childrens; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } public List<Children> getChildrens() { return Childrens; } public void setChildrens(List<Children> childrens) { Childrens = childrens; } } second is for children package org.array; public class Children { private String name; private int age ; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } } and i want to print there value i nested a list inside a list here i am putting only a single value inside the objects while in real i have many values . so i am nesting list of children inside father list. how can i print or get the value of child and father both. here is my logic. package org.array; import java.util.ArrayList; import java.util.Iterator; import java.util.List; public class ArrayDemo { public static void main(String[] args) { List <Father> fatherList = new ArrayList<Father>(); Father father = new Father(); father.setName("john"); father.setAge(25); fatherList.add(father); List <Children> childrens = new ArrayList<Children>(); Children children = new Children(); children.setName("david"); children.setAge(2); childrens.add(children); father.setChildrens(childrens); fatherList.add(father); Iterator<Father> iterator = fatherList.iterator(); while (iterator.hasNext()) { System.out.println(iterator.toString()); } } }

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  • It's 2011-Do You Know Where Your Children Are?

    - by andyleonard
    Introduction This is not a post about children. I was feeling plucky when I wrote this post at the end of last year. Sometimes when I feel plucky I'm inspired to create awesome blog post titles and ideas. Other times, this happens. 2011 Is Here! I was born in 1963. As I child I watched Neil Armstrong and Buzz Aldrin walk on the moon while Walter Cronkite narrated. At 11, I was fortunate enough to live next door to an engineer who taught me Motorola 6800 machine code and then BASIC . I have a long...(read more)

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  • How many hours do you spend programming outside of work if you are married (with children) [closed]

    - by eterps
    I recently attended a conference and met some insanely talented developers with mile-long lists of accomplishments. One puzzling thing I noticed about many of these wildly successful people is that a lot of their output (books, blogs, games, mobile apps) are done as hobby projects outside of their normal jobs. Not only this, but most of them were married, and some even with children. I'm absolutely baffled by this. My question is targeted to folks that are married, working full time, and also spend time outside of work on hobby projects or extra programming. The question is: How many hours do you put in programming outside of your normal job, and how do you balance it with your family life?

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  • If not now, then when?

    - by Chris Gardner
    Originally posted on: http://geekswithblogs.net/freestylecoding/archive/2013/10/25/if-not-now-then-when.aspx The time has been flying by this year. It seems like only yesterday that I mentioned the gorillagator, a simple construct of confusion to try to draw attention to my message. In reality, that message was sent over a month ago. During that time, the hours slipped to days and days to weeks. Many exciting things have happened to myself; I'm sure many exciting things have happened to you. I'm also sure that many terrifying things have happened to children and their families. 62 children enter treatment at a Children's Miracle Network Hospital every minute. That's nearly 60,000 children since I sent the last email. To put that number in perspective, that is more than the population of Greenland. If we expand that to the past year, they have been nearly 550,000 children treated. That is almost the population of Huntsville, Decatur, and all their suburbs combined. Over the past 4 years, I have raised a little more than $3,000 for Children's Hospital of Alabama. As a result, I received a call from the organizers of Extra Life thanking me for my dedicated work and informing me that I was the top supporters for Children's Hospital of Alabama ... with my measly three grand. We can do much better than that. It may sound like I'm trying to have fun by playing games for 24 hours. It is more than that. It is me using my time and body as a catalyst. It is me putting my passion to work for a cause. It is me turning my love into something tangible. I have been campaigning and fighting to give these children a chance for years. I have been asking you to help me support these children and families. I've been putting in countless hours of talking to people, impassioned emails, and carefully constructed tweets. I have been fighting with cutting edge, and sometimes expensive, technology to try to provide live streams of my marathons. I yearly put my body through 24 (and, this year, 25) hours of no sleep. I do this to represent the countless hours these families sit awake at their children's side. All I ask is a few minutes on a website and a few dollars. These few minutes and few dollars go a long way help people that are experiencing circumstances that only occur in our nightmares. I also ask that you take one extra step. Forward this plea to those that you know. I can only reach a small fraction of a percentage of the people that may be able to help. Together, we can reach the world. I raise money for Children's Hospital of Alabama. As this message branches out, people may wish to support a hospital closer to their area. I have included a link to the list of people that have dedicated their time and have received no donations. Find someone on the list supporting your local hospital and give them a donation. Let them know that their time and effort are appreciated. Together, we can do something great. Together, we can make a difference. Together, we all stand tall. Thank you. You can get more information at http://www.extra-life.org and http://childrensmiraclenetworkhospitals.org/" My donation page is http://www.extra-life.org/participant/cgardner The list of participants without donations is http://www.extra-life.org/index.cfm?fuseaction=donorDrive.eventParticipantList&page=629&eventID=512

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  • C++ Segmentation Fault when Iterating through a Vector

    - by user1790374
    I have a program that maintains an integer vector. I have three functions that add an integer, remove an integer and check whether an integer is already in the vector. The problem is with the last one. vector<int> children; void CtpTestingApplication::addChild(int child) { for (int i=0; i<children.size(); i++) { //already a child if (children[i]==child) return; } //child not yet recorded children.push_back(child); received.push_back(false); cout<<"added child "<<child; } void CtpTestingApplication::removeChild(int child) { Enter_Method("removeChild"); for (int i=0; i<children.size(); i++) { //already a child, remove it if (children[i]==child) { children.erase(children.begin()+i); received.erase(received.begin()+i); cout<<"removed child "<<child; } } //not recorded, no need to remove } bool CtpTestingApplication::isChild(int child) { Enter_Method("isChild"); vector<int>::iterator ic; bool result = false; for (ic= children.begin(); ic < children.end(); ic++) { cout<<*ic<<" vs "<<child; // if (child==*ic) result = true; } return result; } I always get segmentation fault when I uncomment "if (child==*ic)", even though printouts show that the vector is not empty and contains the expected integers. For example, with the if statements commented, I can see 1 vs 4, 2 vs 4, 4 vs 4, 12 vs 4 I also attempted looping using children[i] and so on, but to no avail. Any help would be appreciated. Thank you.

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  • Hibernate - EhCache - Which region to Cache associations/sets/collections ??

    - by lifeisnotfair
    Hi all, I am a newcomer to hibernate. It would be great if someone could comment over the following query that i have: Say i have a parent class and each parent has multiple children. So the mapping file of parent class would be something like: parent.hbm.xml <hibernate-mapping > <class name="org.demo.parent" table="parent" lazy="true"> <cache usage="read-write" region="org.demo.parent"/> <id name="id" column="id" type="integer" length="10"> <generator class="native"> </generator> </id> <property name="name" column="name" type="string" length="50"/> <set name="children" lazy="true"> <cache usage="read-write" region="org.demo.parent.children" /> <key column="parent_id"/> <one-to-many class="org.demo.children"/> </set> </class> </hibernate-mapping> children.hbm.xml <hibernate-mapping > <class name="org.demo.children" table="children" lazy="true"> <cache usage="read-write" region="org.demo.children"/> <id name="id" column="id" type="integer" length="10"> <generator class="native"> </generator> </id> <property name="name" column="name" type="string" length="50"/> <many-to-one name="parent_id" column="parent_id" type="integer" length="10" not-null="true"/> </class> </hibernate-mapping> So for the set children, should we specify the region org.demo.parent.children where it should cache the association or should we use the cache region of org.demo.children where the children would be getting cached. I am using EHCache as the 2nd level cache provider. I tried to search for the answer to this question but couldnt find any answer in this direction. It makes more sense to use org.demo.children but I dont know in which scenarios one should use a separate cache region for associations/sets/collections as in the above case. Kindly provide your inputs also let me know if I am not clear in my question. Thanks all.

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  • Inexpensive generation of hierarchical unique IDs

    - by romaninsh
    My application is building a hierarchical structure like this: root = { 'id': 'root', 'children': [ { 'name': 'root_foo', 'children': [] }, { 'id': 'root_foo2', 'children': [ { 'id': 'root_foo2_bar', 'children': [] } ] } ] } in other words, it's a tree of nodes, where each node might have child elements and unique identifier I call "id". When a new child is added, I need to generate a unique identifier for it, however I have two problems: identifiers are getting too long adding many children takes slower, as I need to find first available id My requirement is: naming of a child X must be determined only from the state in their ancestors When I re-generate tree with same contents, the IDs must be same or in other words, when we have nodes A and B, creating child in A, must not affect the name given to children of B. I know that one way to optimize would be to introduce counter in each node and append it to the names which will solve my performance issue, but will not address the issue with the "long identifiers". Could you suggest me the algorithm for quickly coming up with new IDs?

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  • Retrieve entities with children per one sql call. ADO.NET Entity framework

    - by Andrew Florko
    Hello everybody, I have two tables: A & B B { B1: Field1, B2: Field2, ... } A { Children: List of B, A1: Field1, A2: Field2, } I want to retrieve "A" entities with related "B" entities like this: DataContext.A.Select( a = new MySubset( A1 = a.A1, Children = a.Children.Select(b = b.B1).ToList()); But EF can't translate ToList into SQL, so i have to call ToList() per each instance in query producing additional network call. How can I avoid this? Thank you in advance.

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  • php, js - echoing a number based on how many children there are?

    - by benbyford
    Creating a site in with FrogCMS and using alot of jquery to create an all in one screen site. having trouble in php echoing a number for the number of children for a subject in the database which i can then use as a var in js. some things ive tried, but im not really a developer so having issues here is some code frog supplies to show to utilise articles for example, and articles then has childen in the database. find('/articles/'); ? children(array('limit' = 1, 'order' = 'page.created_on DESC')); ? but im not sure how to create a discrete number to use with the jquery concerning the number of children?? thanks

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  • Intro Bar like stack overflow

    - by Dasa
    I have a simple top bar using jquery like the one on stackoverflow, but i want it to only appear on the first time a person visits the website. below is the HTML followed by the "bxSlider.js" file <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript" src="bxSlider.js"></script> <title>topbar</title> <style type="text/css" media="screen"> #message { font-family:Arial,Helvetica,sans-serif; position:fixed; top:0px; left:0px; width:100%; z-index:105; text-align:center; color:white; padding:2px 0px 2px 0px; background-color:#8E1609; } #example1 { text-align: center; width: 80%; } .close-notify { white-space: nowrap; float:right; margin-right:10px; color:#fff; text-decoration:none; padding-left:3px; padding-right:3px } .close-notify a { color: #fff; } h4, p { margin:0px; padding:0px; } </style> </head> <body> <DIV ID='message' style="display: none;"> <DIV ID="example1"> <DIV CLASS="item"> <h4>Head 1</h4> <p>Text 1</p> </div><!-- end item --> <DIV CLASS="item"> <h4>Head 2</h4> <p>Text 2</p> </div><!-- end item --> </div><!-- end example1 --> <a href="#" CLASS="close-notify" onclick="closeNotice()">X</a> </div> <script type="text/javascript"> $(document).ready(function() { $("#message").fadeIn("slow"); $('#example1').bxSlider({ mode: 'slide', speed: 250, wrapper_CLASS: 'example1_container' }); }); function closeNotice() { $("#message").fadeOut("slow"); } </script> </body> </html> /** * * * bxSlider: Content slider / fade / ticker using the jQuery javascript library. * * Author: Steven Wanderski * Email: [email protected] * URL: http://bxslider.com * * **/ jQuery.fn.bxSlider = function(options){ ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Declare variables and functions ///////////////////////////////////////////////////////////////////////////////////////////////////////////// var defaults = { mode: 'slide', speed: 500, auto: false, auto_direction: 'left', pause: 2500, controls: true, prev_text: 'prev', next_text: 'next', width: $(this).children().width(), prev_img: '', next_img: '', ticker_direction: 'left', wrapper_class: 'container' }; options = $.extend(defaults, options); if(options.mode == 'ticker'){ options.auto = true; } var $this = $(this); var $parent_width = options.width; var current = 0; var is_working = false; var child_count = $this.children().size(); var i = 0; var j = 0; var k = 0; function animate_next(){ is_working = true; $this.animate({'left':'-' + $parent_width * 2 + 'px'}, options.speed, function(){ $this.css({'left':'-' + $parent_width + 'px'}).children(':first').appendTo($this); is_working = false; }); } function animate_prev(){ is_working = true; $this.animate({'left': 0}, options.speed, function(){ $this.css({'left':'-' + $parent_width + 'px'}).children(':last').insertBefore($this.children(':first')); is_working = false; }); } function fade(direction){ if(direction == 'next'){ var last_before_switch = child_count - 1; var start_over = 0; var incr = k + 1; }else if(direction == 'prev'){ var last_before_switch = 0; var start_over = child_count -1; var incr = k - 1; } is_working = true; if(k == last_before_switch){ $this.children().eq(k).fadeTo(options.speed, 0); $this.children().eq(start_over).fadeTo(options.speed, 1, function(){ is_working = false; k = start_over; }); }else{ $this.children().eq(k).fadeTo(options.speed, 0); $this.children().eq(incr).fadeTo(options.speed, 1, function(){ is_working = false; k = incr; }); } } function add_controls(){ ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Check if user selected images to use for next / prev ///////////////////////////////////////////////////////////////////////////////////////////////////////////// if(options.prev_img != '' || options.next_img != ''){ $this.parent().append('<a class="slider_prev" href=""><img src="' + options.prev_img + '" alt=""/></a><a class="slider_next" href=""><img src="' + options.next_img + '" alt="" /></a>'); }else{ $this.parent().append('<a class="slider_prev" href="">' + options.prev_text + '</a><a class="slider_next" href="">' + options.next_text + '</a>'); } $this.parent().find('.slider_prev').css({'float':'left', 'outline':'0', 'color':'yellow'}); $this.parent().find('.slider_next').css({'float':'right', 'outline':'0', 'color':'yellow'}); ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Accomodate padding-top for controls when elements are absolutely positioned (only in fade mode) ///////////////////////////////////////////////////////////////////////////////////////////////////////////// if(options.mode == 'fade'){ $this.parent().find('.slider_prev').css({'paddingTop' : $this.children().height()}) $this.parent().find('.slider_next').css({'paddingTop' : $this.children().height()}) } ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Actions when user clicks next / prev buttons ///////////////////////////////////////////////////////////////////////////////////////////////////////////// $this.parent().find('.slider_next').click(function(){ if(!is_working){ if(options.mode == 'slide'){ animate_next(); if(options.auto){ clearInterval($.t); $.t = setInterval(function(){animate_next();}, options.pause); } }else if(options.mode == 'fade'){ fade('next'); if(options.auto){ clearInterval($.t); $.t = setInterval(function(){fade('next');}, options.pause); } } } return false; }); $this.parent().find('.slider_prev').click(function(){ if(!is_working){ if(options.mode == 'slide'){ animate_prev(); if(options.auto){ clearInterval($.t); $.t = setInterval(function(){animate_prev();}, options.pause); } }else if(options.mode == 'fade'){ fade('prev'); if(options.auto){ clearInterval($.t); $.t = setInterval(function(){fade('prev');}, options.pause); } } } return false; }); } function ticker() { if(options.ticker_direction == 'left'){ $this.animate({'left':'-' + $parent_width * 2 + 'px'}, options.speed, 'linear', function(){ $this.css({'left':'-' + $parent_width + 'px'}).children(':first').appendTo($this); ticker(); }); }else if(options.ticker_direction == 'right'){ $this.animate({'left': 0}, options.speed, 'linear', function(){ $this.css({'left':'-' + $parent_width + 'px'}).children(':last').insertBefore($this.children(':first')); ticker(); }); } } ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Create content wrapper and set CSS ///////////////////////////////////////////////////////////////////////////////////////////////////////////// $this.wrap('<div class="' + options.wrapper_class + '"></div>'); //console.log($this.parent().css('paddingTop')); if(options.mode == 'slide' || options.mode == 'ticker'){ $this.parent().css({ 'overflow' : 'hidden', 'position' : 'relative', 'margin' : '0 auto', 'width' : options.width + 'px' }); $this.css({ 'width' : '999999px', 'position' : 'relative', 'left' : '-' + $parent_width + 'px' }); $this.children().css({ 'float' : 'left', 'width' : $parent_width }); $this.children(':last').insertBefore($this.children(':first')); }else if(options.mode == 'fade'){ $this.parent().css({ 'overflow' : 'hidden', 'position' : 'relative', 'width' : options.width + 'px' //'height' : $this.children().height() }); if(!options.controls){ $this.parent().css({'height' : $this.children().height()}); } $this.children().css({ 'position' : 'absolute', 'width' : $parent_width, 'listStyle' : 'none', 'opacity' : 0 }); $this.children(':first').css({ 'opacity' : 1 }); } ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Check if user selected "auto" ///////////////////////////////////////////////////////////////////////////////////////////////////////////// if(!options.auto){ add_controls(); }else{ if(options.mode == 'ticker'){ ticker(); }else{ ///////////////////////////////////////////////////////////////////////////////////////////////////////////// // Set a timed interval ///////////////////////////////////////////////////////////////////////////////////////////////////////////// if(options.mode == 'slide'){ if(options.auto_direction == 'left'){ $.t = setInterval(function(){animate_next();}, options.pause); }else if(options.auto_direction == 'right'){ $.t = setInterval(function(){animate_prev();}, options.pause); } }else if(options.mode == 'fade'){ if(options.auto_direction == 'left'){ $.t = setInterval(function(){fade('next');}, options.pause); }else if(options.auto_direction == 'right'){ $.t = setInterval(function(){fade('prev');}, options.pause); } } if(options.controls){ add_controls(); } } } }

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  • Drupal 6: Printing Unadulterated Primary Links and all children...

    - by dcolumbus
    How in the WORLD is possible? I swear, I've read the equivalent of 3 encyclopedias to no avail. I've tried solutions within regions, page.tpl.php and blocks. None of them give me what I need... and I know there are so many other people that need this too! I've come to the conclusion that I want to print out the menu within my page.tpl.php ... so no block solutions, please. I want to be able to loop through the primary menu links (AND children) and rewrite the output so that there's no default Drupal class tagging. The closest I've found is this example: <?php if (is_array($primary_links)) : ?> <ul id="sliding-navigation"> <?php foreach ($primary_links as $link): ?> <li class="sliding-element"><?php $href = $link['href'] == "<front>" ? base_path() : base_path() . drupal_get_path_alias($link['href']); print "<a href='" . $href . "'>" . $link['title'] . "</a>"; ?></li> <?php endforeach; ?> </ul> <?php endif; ?> As you can see, links are being reprinted with a custom UL and LI class ... that's GREAT! However, no children are being printed. How would I extend this code so that all children are a part of the list? NOTE: I don't want the children to only appear on their parent page, they must be present all the time. Otherwise, the drop-down menu I have planned is useless. I sincerely thank you in advance to lessening my gargantuan headache!

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  • How to get all objects with their children using django orm?

    - by kender
    Hi, I got very simple hierarchical structure: every object can have 0 or 1 parent. There's no limit on how many children each object can have. So in my application I got such a model: class O(Model): name = CharField(max_length = 20) parent = ForeignKey('O', related_name = 'children') Now I would like to be able to fetch all objects who have a particular one Object1 in their parent-tree (as in their parent or parent of their parents, etc). Should I use mptt or is there a simpler approach?

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  • Using KnockoutJS 2.2.0 & jQuery 1.8.2 remove all bindings from all children of #someDiv

    - by Nukeface
    I'm wanting to delete All bindings (ko.cleanNode) from all child elements of a certain div. Must be a noobie question but I can't figure out how to use jQuery to loop through all childre, grand-children, great-grand-children, etc. whilst having KnockoutJS remove the bindings of all the DOM elements. I do NOT want to remove the elements from the DOM. This is a single page application, therefore the elements are pre-loaded as embedded resources and don't get resend to a client if they were to visit the page again. If a client revisits that part of the application I'll have a function rebind the necessary elements, which currently works fine. Current setup: <html> <head> //loading all resources </head> <body> //load first element using some obscure setup <div id="firsPage" data-role="page"> <div data-role="header">@Global.header</div> <div data-role="fieldcontain"> <label for="firstInput" /> <input id="firstInput some other stuff /> </div> <div data-role="datebox <!-- some settings --> > //creates table using jQuery mobile (lots of (great-)(grand-)children) </div> <div data-role="fieldcontain"> <div id="secondInput"> <div class="checklist"> <ul> <li /> <li /> </ul> </div> </div> </div> </div> //Here the whole thing starts again <div id="secondPage" data-role="page"> <!-- repeat above innerHTML in your mind ;) --> </div> //And here again! and again... </body> The problem I'm having is that bindings of the children don't seem to get "cleaned up" when i use ko.cleanNode($('#firstPage')[0]); Or when I get the Element into a variable and then format it to ko.cleanNode($element). Is there a way to do this? Been staring at it for a good few hours now, so probably overlooking a way too obvious way of doing it... Thanks!

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  • Patterns for a tree of persistent data with multiple storage options?

    - by Robin Winslow
    I have a real-world problem which I'll try to abstract into an illustrative example. So imagine I have data objects in a tree, where parent objects can access children, and children can access parents: // Interfaces interface IParent<TChild> { List<TChild> Children; } interface IChild<TParent> { TParent Parent; } // Classes class Top : IParent<Middle> {} class Middle : IParent<Bottom>, IChild<Top> {} class Bottom : IChild<Middle> {} // Usage var top = new Top(); var middles = top.Children; // List<Middle> foreach (var middle in middles) { var bottoms = middle.Children; // List<Bottom> foreach (var bottom in bottoms) { var middle = bottom.Parent; // Access the parent var top = middle.Parent; // Access the grandparent } } All three data objects have properties that are persisted in two data stores (e.g. a database and a web service), and they need to reflect and synchronise with the stores. Some objects only request from the web service, some only write to it. Data Mapper My favourite pattern for data access is Data Mapper, because it completely separates the data objects themselves from the communication with the data store: class TopMapper { public Top FetchById(int id) { var top = new Top(DataStore.TopDataById(id)); top.Children = MiddleMapper.FetchForTop(Top); return Top; } } class MiddleMapper { public Middle FetchById(int id) { var middle = new Middle(DataStore.MiddleDataById(id)); middle.Parent = TopMapper.FetchForMiddle(middle); middle.Children = BottomMapper.FetchForMiddle(bottom); return middle; } } This way I can have one mapper per data store, and build the object from the mapper I want, and then save it back using the mapper I want. There is a circular reference here, but I guess that's not a problem because most languages can just store memory references to the objects, so there won't actually be infinite data. The problem with this is that every time I want to construct a new Top, Middle or Bottom, it needs to build the entire object tree within that object's Parent or Children property, with all the data store requests and memory usage that that entails. And in real life my tree is much bigger than the one represented here, so that's a problem. Requests in the object In this the objects request their Parents and Children themselves: class Middle { private List<Bottom> _children = null; // cache public List<Bottom> Children { get { _children = _children ?? BottomMapper.FetchForMiddle(this); return _children; } set { BottomMapper.UpdateForMiddle(this, value); _children = value; } } } I think this is an example of the repository pattern. Is that correct? This solution seems neat - the data only gets requested from the data store when you need it, and thereafter it's stored in the object if you want to request it again, avoiding a further request. However, I have two different data sources. There's a database, but there's also a web service, and I need to be able to create an object from the web service and save it back to the database and then request it again from the database and update the web service. This also makes me uneasy because the data objects themselves are no longer ignorant of the data source. We've introduced a new dependency, not to mention a circular dependency, making it harder to test. And the objects now mask their communication with the database. Other solutions Are there any other solutions which could take care of the multiple stores problem but also mean that I don't need to build / request all the data every time?

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  • Converting a flat array to a nested array

    - by matte
    Hi, I am trying to convert a flat array to a nested array depending on the 'level' data of each array item. 'level' data shows us if current array item is a child, a parent or a sibling. Here is the flat array: $sequentialArray = array( array('title'=>'Page 1', 'level'=>0), array('title'=>'Page 2', 'level'=>0), array('title'=>'Page 3', 'level'=>1), array('title'=>'Page 4', 'level'=>1), array('title'=>'Page 5', 'level'=>2), array('title'=>'Page 6', 'level'=>0), array('title'=>'Page 7', 'level'=>1), array('title'=>'Page 8', 'level'=>0) ); And here is the expected result: $nestedArray = array( array('title'=>'Page 1', 'children'=>array()), array('title'=>'Page 2', 'children'=>array( array('title'=>'Page 3', 'children'=>array()), array('title'=>'Page 4', 'children'=>array( array('title'=>'Page 5', 'children'=>array()) )), )), array('title'=>'Page 6', 'children'=>array( array('title'=>'Page 7', 'children'=>array()) )), array('title'=>'Page 8', 'children'=>array()), ); I tried using references with array indexes but that didn't work. Any ideas?

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  • outer join for parent child chain

    - by dotnetcoder
    Considering below tables and relationships: parent --1:Many-- children --1:Many-- shubchildren Parent may or many not have children records. children always have subchildren records. I wan to write a qiery to select parent names where any if matched parent.name,children.name or subchildren.name Here i understand I have to do a left outer join between parent and children. But what kind of join should I put between children and subchildren ?

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  • How to initialize list with parent child relation

    - by user2917702
    Let's say I have the following classes. public class Parent { public string name; IList<Children> children; } public class Child { public string parentName; public int age; } As it is understandable, each parent can have multiple children, and we can have multiple parents. What is the best way to initialize these classes? Is it better to get all of the parents, and all of the children from database then use LINQ? IList<Parent> parents = GetParents()//assume this gets parents from db IList<Child> children = GetChildren() //assume this gets children from db foreach(Parent parent in parents) { parent.children = children.Where(x=>x.parentName==parent.name).ToList(); } or get all of the parents and iterate through each parent to query database by parentName to get children information? Due to requirement that I have, I cannot use datatable or dataset; I can only use datareader. IList<Parent> parents = GetParents()//assume this gets parents from db foreach(Parent parent in parents) { parent.children = GetChildrenByParentName();//assume this gets parents from db by parentName } Thank you

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