Search Results

Search found 1782 results on 72 pages for 'dates'.

Page 9/72 | < Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >

  • How to create database records for a financial year

    - by David A Gibson
    Hello, I need to create entities (specifically contracts) in a database table that are associated with a financial year. These contracts will be applied to projects. Any contract variation will be recorded by creating a new contract record for the same financial year but the original will remain associated with the project as a history. The projects can last several years and so at any one time a project will have a live contract record for each year as well as any number of historic contracts for that year. All of which is incidental but I'm trying to provide some context. If the contracts where for the year - it would be easy and I'd just store the Year either as a date field with the 1st of January or just an Integer. However the contracts run for financial years and I don't know how to approach this. I don't want a separate table containing the financial years as I don't want the users to have to maintain this. I don't want to store the financial year as a string "2009/2010" as this is not ideal for sorting/extracting the data. Any ideas will be helpful, my best so far is to have starting and ending year in 2 columns and just "KNOW" that starting is April of the year etc Thanks

    Read the article

  • Find date difference in php?

    - by Karthik
    Is there anyway to find the date difference in php? I have the input of from date 2003-10-17 and todate 2004-03-24. I need the results how many days is there within these two days. Say if 224 days, i need the output in days only. I find the solution through mysql but i need in php. Anyone help me, Thanks in advance.

    Read the article

  • Algorithm: how to check intersections of recurring events definitions?

    - by glaz666
    The question comes from MS Outlook calendar behavior. Imagine I have two recurring events (starting from today): "each second Monday" and "every odd date". Is there any way to check intersections and/or find the first intersecting date algorithmically without brute-forcing over each date? Definitions can be made in CRON's notations or ICal notation. I think it doesn't matter. Are there any solutions for this in Gregorian calendar?

    Read the article

  • How to group items by date range in XSLT?

    - by glenatron
    I have a bunch of data that looks a little like this: <item> <colour>Red</colour> <date_created>2009-10-10 12:01:55</date_created> <date_sold>2009-10-20 22:32:12</date_sold> </item> <item> <colour>Blue</colour> <date_created>2009-11-01 13:21:00</date_created> <date_sold>2009-11-21 12:32:12</date_sold> </item> <item> <colour>Blue</colour> <date_created>2009-10-29 21:23:02</date_created> <date_sold>2009-10-20 02:02:22</date_sold> </item> <item> <colour>Red</colour> <date_created>2009-11-02 09:11:51</date_created> <date_sold>2009-11-20 09:15:53</date_sold> </item> <item> <colour>Red</colour> <date_created>2009-10-18 11:00:55</date_created> <date_sold>2009-10-20 11:12:22</date_sold> </item> Now what I would like to be able to do is to run that through an XSLT stylesheet such that I get ouput looking like this: Colour | In stock 1 week | In stock 2 weeks | In stock 3 weeks Red | 1 | 3 | 2 Blue | 0 | 2 | 1 Currently I have a stylesheet that uses basic muenchian grouping to show that 30% of stock was Red and 70% blue, but I can't see a way to find the number of nodes withing a given date range. Is there a way to use keys to select a range? Do I need to create some kind of intermediate data node? Is there a different route that shows I'm barking up the wrong tree with both those suggestions? Is this even possible with XSLT or do I need to find a way to change the data source?

    Read the article

  • How to sanity check a date in java

    - by Bloodboiler
    I find it curious that the most obvious way to create Date objects in Java has been deprecated and appears to have been "substituted" with not so obvious to use lenient calendar. So... How do you check that a date given as a combination of day, month and year is a valid date? For instance a date 2008-02-31 (as in yyyy-mm-dd) would be invalid date.

    Read the article

  • Get the number of calendar weeks between 2 dates in C#

    - by Phil Scholtes
    For the purposes of this question, let's assume the user will be from the US and will use the standard Gregorian calendar. So, a calendar week starts on Sunday and ends on Saturday. What I'm trying to do is determine the number of calendar weeks that exist between two dates. A perfect example of my problem exists in October 2010. Between 10/16 and 10/31 there are 4 calendar weeks. View a picture of October 2010 October 10 - October 16 October 17 - October 23 October 24 - October 30 October 31 - November 6 I'd prefer to stay away from any hardcoded logic like: if (Day == DayOfWeek.Saturday && LastDayOfMonth == 31) { ... } Can anyone think of a logical way to do this?

    Read the article

  • Formatting Timestamps in Java

    - by Craig H
    Is there a way to format a UTC time into any arbitrary string format I want in java? Basically I was thinking of having some class take the timestamp and I pass it is string telling it how I want it formated, and it returns the formatted string for me. Is there a way to do this?

    Read the article

  • calculating offer period for subscription

    - by TheVillageIdiot
    I'm maintaining a web application which deals with some kind of subscriptions. Users can to renew their subscriptions from 2 months before expiry (not earlier than that). Sometimes user does not renew before expiry and get grace period which is of 3 months. Now he can renew in these 3 months of grace period. Now the problem part. In the previous transactions of renew requests I have to show what was the offer period for that particular request (subscription start and subscription end period if renew was granted). Things are pretty simple if user renews before expiry, but I'm not able to get things straight if there is grace period specially when the subscriptions is expiring in last months of the year. Also there sometimes calculations go haywire when subscription is ending in jan or feb. All this is happening because offer period is not saved with the application anywhere (I don't know why). so if subscription is ending in 20 October 2008 and renew application is submitted in 16 January 2009 (because of grace period) the offer period should be 21 October 2008 to 20 October 2009.

    Read the article

  • Search for a date between given ranges - Lotus

    - by Kris.Mitchell
    I have been trying to work out what is the best way to search for gather all of the documents in a database that have a certain date. Originally I was trying to use FTsearch or search to move through a document collection, but I changed over to processing a view and associated documents. My first question is what is the easiest way to spin through a set of documents and find if a date stored in the documents is greater than or less than a specified date? So, to continue working I implemented the following code. If (doc.creationDate(0) > cdat(parm1)) And (doc.creationDate(0) < CDat(parm2)) then ... end if but the results are off Included! Date:3/12/10 11:07:08 P1:3/1/10 P2: 3/5/10 Included! Date:3/13/10 9:15:09 P1:3/1/10 P2: 3/5/10 Included! Date:3/17/10 16:22:07P1:3/1/10 P2: 3/5/10 You can see that the date stored in the doc is not between P1 and P2. BUT! it does limit the documents with a date less than P1 correctly. So I won't get a result for a document with a date less than 3/1/10 If there isn't a better way than the if statement, can someone help me understand why the two examples from above are included?

    Read the article

  • Problem with date_select when using :discard option. (Rails)

    - by MikeH
    I'm using a date_select with the option :discard_year => true If a user selects a date in the date select, and then he comes back and returns the select to the prompt values of Month and Day, Rails automatically sets the select values to January 1. I know this is the intended functionality if a month is selected and a day is left blank, but that's not the case here. In my example, the user sets both the month and day back to the prompt. By Rails forcing January 1, I'm getting bad results. I've tried every parameter available in the api. :default = nil, :include_blank = true. None of those change the behavior I'm describing. I've isolated the root of the problem, which is this: Because I'm discarding the :year parameter, when the user tries to return the month and day to the prompt values, Rails doesn't see an empty prompt select. It perhaps sees a year selected with empty month and day, which it then sets to January 1. This is the case because the :discard_year parameter does in fact set a date in the database, it just removes it from the view. How can I code around this problem?

    Read the article

  • SQL Server 2005 Fail: Return Dates As Strings

    - by Abs
    Hello all, I am using the SQL Server PHP Driver, I think this question can be answered without knowing what this is. I have come across this many times, what does it mean by NAMES? Column names?: SET NAMES utf8 Is there a query similar to the above that will get my dates to be returned as a string? For some reason on my SQL Sever 2008 on Vista, this works: $connectionInfo = array('Database' => $dbname, 'ReturnDatesAsStrings' => true) But the above 'ReturnDatesAsStrings' does not work on my SQL Server 2005 on a windows server machine? I can't execute any queries after setting the above! Does SQL Server 2005 support ReturnDatesAsStrings? Is there some other parameter I can pass to do the same? Thanks all for any help EDIT I should of mentioned this but if there is a solution I am hoping for one that is in the form of a setting that can be set before any queries can be executed as I do not have control on what queries will be executed.

    Read the article

  • Given a date range how to calculate the number of weekends partially or wholly within that range?

    - by andybak
    Given a date range how to calculate the number of weekends partially or wholly within that range? (A few definitions as requested: take 'weekend' to mean Saturday and Sunday. The date range is inclusive i.e. the end date is part of the range 'wholly or partially' means that any part of the weekend falling within the date range means the whole weekend is counted.) To simplify I imagine you only actually need to know the duration and what day of the week the initial day is... I darn well now it's going to involve doing integer division by 7 and some logic to add 1 depending on the remainder but I can't quite work out what... extra points for answers in Python ;-) Edit Here's my final code. Weekends are Friday and Saturday (as we are counting nights stayed) and days are 0-indexed starting from Monday. I used onebyone's algorithm and Tom's code layout. Thanks a lot folks. def calc_weekends(start_day, duration): days_until_weekend = [5, 4, 3, 2, 1, 1, 6] adjusted_duration = duration - days_until_weekend[start_day] if adjusted_duration < 0: weekends = 0 else: weekends = (adjusted_duration/7)+1 if start_day == 5 and duration % 7 == 0: #Saturday to Saturday is an exception weekends += 1 return weekends if __name__ == "__main__": days = ['Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'] for start_day in range(0,7): for duration in range(1,16): print "%s to %s (%s days): %s weekends" % (days[start_day], days[(start_day+duration) % 7], duration, calc_weekends(start_day, duration)) print

    Read the article

  • my NSDateFormatter works only in the iPhone simulator

    - by Manuel Spuhler
    I use a NSDateFormatter which works fine in the simulator, but I get a nil when I run it in the iPhone. I hardcoded the date to be sure of the format, but it fails anyway. NSString *strPubDate = @"Fri, 8 May 2009 08:08:35 GMT"; NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; [dateFormatter setFormatterBehavior:NSDateFormatterBehavior10_4]; [dateFormatter setDateFormat:@"EEE, d MMM yyyy HH:mm:ss Z"]; NSDate *myDate = [dateFormatter dateFromString:strPubDate]; I tried with different region settings, languages etc. on the iPhone. Any idea what is going wrong?

    Read the article

  • Speeding up PostgreSQL query where data is between two dates

    - by Roger
    I have a large table ( 50m rows) which has some data with an ID and timestamp. I need to query the table to select all rows with a certain ID where the timestamp is between two dates, but it currently takes over 2 minutes on a high end machine. I'd really like to speed it up. I have found this tip which recommends using a spatial index, but the example it gives is for IP addresses. However, the speed increase (436s to 3s) is impressive. How can I use this with timestamps?

    Read the article

  • NSPredicateEditorRowTemplate for date comparison

    - by Dave DeLong
    I'm building an NSPredicateEditor, and I want the ability to do advanced date comparison. I realize that I can build an NSPredicateEditorRowTemplate with a rightExpressionType of NSDateAttributeType, but the predicates I want to build need to be much more advanced than that. For example, I need to basic comparison like: dateKeypath < aDate dateKeypath <= aDate dateKeypath = aDate dateKeypath != aDate dateKeypath > aDate dateKeypath >= aDate These basic comparisons are quite easy to achieve, and I have these working. However, I also need to do comparisons like: dateKeypath isInTheLast n days (or weeks, months, years) dateKeypath isNotInTheLast n days (or weeks, months, years) dateKeypath between aDate and anotherDate How can I achieve these sorts of comparisons? I understand that I'll need to create a custom NSPredicateEditorRowTemplate, but I haven't found any clear documentation on how to achieve something like this. EDIT Bonus points are available for also knowing how to make these comparisons a full date-time (year-month-day-hour-minute-second) comparison (as NSDateAttributeType only has year-month-day granularity).

    Read the article

  • data type mismatch when comparing dates in MS-Access

    - by jonos
    I have dates stored in an MS-Access table in the 'General Date' format. I'm trying to create a query that returns records between a specific date range (all records from March 2010) however I encounter a 'data type mismatch in critera expression' message. Here is my statement; SELECT Loan.loan_datetimeLeant, product_name, [product_artist/director], product_category, loanItem_cost FROM Loan INNER JOIN ((Product INNER JOIN Item ON Product.[product_id] = Item.[product_id]) INNER JOIN Loan_Items ON Item.[item_id] = Loan_Items.[item_id]) ON (Loan.[cust_id] = Loan_Items.[cust_id]) AND (Loan.[loan_datetimeLeant] = Loan_Items.[loan_datetimeLeant]) WHERE Loan.loan_datetimeLeant = '01/03/2010' AND Loan.loan_datetimeLeant <= '31/03/2010' ORDER BY Loan.loan_datetimeLeant ; I have tried variations on the date format (mm/dd/yyyy, dd/mm/yyyy 00:00:00)

    Read the article

  • Calculate the year for ending month/day?

    - by Dave Jarvis
    Given: Start Year Start Month & Start Day End Month & End Day What SQL statement results in TRUE if a date lands between the Start and End days? 1st example: Start Date = 11-22 End Date = 01-17 Start Year = 2009 Specific Date = 2010-01-14 TRUE 2nd example: Start Date = 11-22 End Date = 11-16 Start Year = 2009 Specific Date = 2010-11-20 FALSE 3rd example: Start Date = 02-25 End Date = 03-19 Start Year = 2004 Specific Date = 2004-02-29 TRUE I was thinking of using the MySQL functions datediff and sign plus a CASE condition to determine whether the year wraps, but it seems rather expensive. Am looking for a simple, efficient calculation. Update 1 The problem is the end date cannot simply use the year. The year must be increased if the end month/day combination happens before the start date. The start date is easy: Start Date = date( concat_ws( '-', year, Start Month, Start Day ) ) The end date is not so simple. Update 2 Here is what I was thinking about for obtaining the end year: end_year = case sign( diff( date( concat_ws( year, start_month, start_day ) ), date( concat_ws( year, end_month, end_day ) ) ) ) when -1 then Start_Year + 1 else Start_Year end case Then wrap that expression (once syntactically correct) inside of another date, followed by BETWEEN statement. Update 3 To clear up some confusion: there is no end year. The end year must be calculated. Thank you!

    Read the article

  • Bash Nested Loops, mixture of dates and numbers

    - by Saleh
    Hi, I am trying to output a range of commands with different dates and numbers associated. for each hour eg. Output im trying to do in a loop is: shell.sh filename<number e.g. between 1-24> <date e.g. 20100928> <number e.g. between 1-24> <id> So basically the the above will generate an output done 24 times for each particular day with a unique 4 digit id. I was thinking of having a nested loop, as the batch number needs to be unique. can anyone help?

    Read the article

  • Relative Dates with Datejs

    - by Prasanna
    I have a requirement where in, I have to parse the dates relative to a date object returned from the server side. But the datejs library always considers only the browsers date object. The situation is something like this: The server gives back the date in PST and the browser is in IST. And all the inputs are getting parsed with respect to the current date in IST instead of current date in PST. Is there any way I could resolve this. Or could you suggest any workarounds. Thanks in advance.

    Read the article

  • number of months between two dates - using boost's date

    - by MartinP
    I've used boost::gregorian::date a bit now. I can see that there are the related months & years & weeks duration types. I can see how to use known durations to advance a given date. Qu: But how can I get the difference between two dates in months (or years or weeks) ? I was hoping to find a function like: template<typename DURATION> DURATION date_diff<DURATION>(const date& d1,const date& d2); There would need to be some handling of rounding too.

    Read the article

< Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >