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  • Red Hat 6.5- sysctl -w net.ipv6.conf.default.accept_redirects=0

    - by kjbradley
    I am in the process of writing a Red Hat 6.5 Kickstart disc with hardened security. I have run a program to determine where the weaknesses are in my system, and apparently there is a medium severity problem by accepting IPV6 redirects. When I implement the following line in my post script in my kickstart, I can't access any websites externally with wget, or ssh/scp in from my computer. sysctl -w net.ipv6.conf.default.accept_redirects=0 Is there a workaround to this so that the system will still be hardened but I will be able to access systems that are external?

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  • What does the red x icon mean next to a user in folder permissions (Windows 7)

    - by Scott Szretter
    In trying to debug various strange issues on a machine, I found something strange - when I go to C:\Users\administrator and get properties, security tab, it lists the users (the local admin account, system, and 'administrator' which is the domain administrator account). It all looks fine in terms of permissions (full control, etc.) compared to other machines. The one difference is there is a small red circle with an X to the left of the user icon/name. Additionally, there are various folders where it says access denied under there - for example, my documents! Even logged in as the local machine administrator account (which is not named administrator), I am unable to change the permissions - it says access denied. Any ideas what this means and how to fix it? I even tried re-joining the machine to the domain.

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  • Setting up Red Hat Enterprise Linux Server as a mail exchange server

    - by Syedur
    I am a Unix/Linux/Windows Server noob. So, keep that in mind before you throw your stones at my glass house. :P I have a Windows Server 2008 R2 machine that's acting as domain controller, Server A. It's also running a DNS server. I have a Red Hat Enterprise Linux Server 5.3, Server B that is intended for mail server. In order for the mail delivery to happen, I understand that I have to set an MX record on Server A and point it to Server B. Well, I did. I manually added a host name on Server A and pointed to Server B's IP address. Then I added an MX record and pointed it to the host name. That didn't do the trick. After taking the above steps, I used the "dig" command on Server B to lookup the MX record coming back from Server A and it wasn't what I was expecting. What am I doing wrong here? I have noticed that... my Windows machines that are joined to the domain (Server A) are listed under the host names. The machines that are not joined to the domain are not list. This is fine, I am not worried about this. What does concern me, do I have to join the Server B to domain in order for Server A to recognize as a valid host and forward the MX properly? If so, some simple steps on how to join Server B to the domain would also help.

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  • What does it mean for the file name to be shown with red background

    - by user56614
    I'm trying to install Cisco VPN client on Linux Ubuntu 10.04. The installer creates the directory, places all the necessary files in it, and then fails to launch the binary. I tried to launch it myself, the system rebukes me too. Closer inspection yields the following: eugene@eugene-desktop:/opt/cisco/vpn/bin$ sudo chmod u+x vpnagentd eugene@eugene-desktop:/opt/cisco/vpn/bin$ ls -la total 5124 drwxr-xr-x 2 root root 4096 2010-10-23 11:51 . drwxr-xr-x 6 root root 4096 2010-10-23 11:51 .. -rwxr-xr-x 1 root root 1607236 2010-10-23 11:51 vpn -rwsr-xr-x 1 root root 1204692 2010-10-23 11:51 vpnagentd -r--r--r-- 1 root root 697380 2010-10-23 11:51 vpndownloader.sh -rwxr-xr-x 1 root root 1712708 2010-10-23 11:51 vpnui -rwxr-xr-x 1 root root 3654 2010-10-23 11:51 vpn_uninstall.sh eugene@eugene-desktop:/opt/cisco/vpn/bin$ ./vpnagentd bash: ./vpnagentd: No such file or directory eugene@eugene-desktop:/opt/cisco/vpn/bin$ sudo ./vpnagentd sudo: unable to execute ./vpnagentd: No such file or directory The file name "vpnagentd" is shown in white letters with red background. The other three executables are in green letters with black background, as expected. Any ideas?

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  • Red Hat - Accept Self-Signed Certificates

    - by user552788
    Hi: Is there a way I can get a Red Hat Linux box to trust a self-signed certificate? e.g. wget https://example.com - gives an error that certificate is untrusted as 'https://example.com' has a self-signed certificate; with wget '--no-check-certificate' can over-ride checking of the certificate. But I would like to get the Red Hat to implicitly trust the self-signed certificate - is there a way to do this? Thanks.

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  • How to get a profile picture from fb:friends selector

    - by malshan
    Im a Newbie to PHP and FBML(Facebook Markup Language).....so now im coding a Facebook app so I need to get profile picture and friend name when I select a name from FB:Friend Selector Select a Friend <fb:friend-selector uid="exclude_ids" name="pal" idname="friend_sel" /> I use exclude_ids to see all friends in my selector so how to get profile picture? I can get name from this but how to get the profile pic large?

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  • Linux per-process resource limits - a deep Red Hat Mystery

    - by BobBanana
    I have my own multithreaded C program which scales in speed smoothly with the number of CPU cores.. I can run it with 1, 2, 3, etc threads and get linear speedup.. up to about 5.5x speed on a 6-core CPU on a Ubuntu Linux box. I had an opportunity to run the program on a very high end Sunfire x4450 with 4 quad-core Xeon processors, running Red Hat Enterprise Linux. I was eagerly anticipating seeing how fast the 16 cores could run my program with 16 threads.. But it runs at the same speed as just TWO threads! Much hair-pulling and debugging later, I see that my program really is creating all the threads, they really are running simultaneously, but the threads themselves are slower than they should be. 2 threads runs about 1.7x faster than 1, but 3, 4, 8, 10, 16 threads all run at just net 1.9x! I can see all the threads are running (not stalled or sleeping), they're just slow. To check that the HARDWARE wasn't at fault, I ran SIXTEEN copies of my program independently, simultaneously. They all ran at full speed. There really are 16 cores and they really do run at full speed and there really is enough RAM (in fact this machine has 64GB, and I only use 1GB per process). So, my question is if there's some OPERATING SYSTEM explanation, perhaps some per-process resource limit which automatically scales back thread scheduling to keep one process from hogging the machine. Clues are: My program does not access the disk or network. It's CPU limited. Its speed scales linearly on a single CPU box in Ubuntu Linux with a hexacore i7 for 1-6 threads. 6 threads is effectively 6x speedup. My program never runs faster than 2x speedup on this 16 core Sunfire Xeon box, for any number of threads from 2-16. Running 16 copies of my program single threaded runs perfectly, all 16 running at once at full speed. top shows 1600% of CPUs allocated. /proc/cpuinfo shows all 16 cores running at full 2.9GHz speed (not low frequency idle speed of 1.6GHz) There's 48GB of RAM free, it is not swapping. What's happening? Is there some process CPU limit policy? How could I measure it if so? What else could explain this behavior? Thanks for your ideas to solve this, the Great Xeon Slowdown Mystery of 2010!

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  • WPF validation red border doesn't show If UserControl collapsed first

    - by Creepy Gnome
    There seems to be a bug with WPF in 3.5, and I was hoping someone may have found a workaround. Basically if you have a custom UserControl that contains a TextBox and it is in a Window but initialized to be Collapsed by default in the xaml or code behind if it fails validation when you make the control visible it will not show the red border until it fails while visible. However, this works correctly when visibility is set to Hidden, just no when Collapsed. I am already overriding the ErrorTemplate with a style to workaround the Adornment issue with the red border staying visibile when you collapse the control. Below is my full style for the TextBox. If there is any additional changes or additions to make it work correctly with collapsed controls that would be great. <Style TargetType="TextBox"> <Setter Property="Margin" Value="3" /> <Setter Property="Validation.ErrorTemplate"> <Setter.Value> <ControlTemplate> <ControlTemplate.Resources> <BooleanToVisibilityConverter x:Key="converter" /> </ControlTemplate.Resources> <DockPanel LastChildFill="True"> <Border BorderThickness="2" BorderBrush="Red" Visibility="{ Binding ElementName=placeholder, Mode=OneWay, Path=AdornedElement.IsVisible, Converter={StaticResource converter}}" > <AdornedElementPlaceholder x:Name="placeholder" /> </Border> </DockPanel> </ControlTemplate> </Setter.Value> </Setter> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true" > <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}" /> </Trigger> </Style.Triggers> </Style>

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  • Free API for Friends Invite from Gmail,Yahoo,AOL,Hotmail PHP Ajax

    - by Gobi
    Hi, i need any opensource api for implementing address book import for friends invite from Gmail,yahoo,hotmail,aol etc ... its may be ajax or php or javascript . openinvite.com is there but i cant download it for loacl testing since it asking valid website domain . conatact grabber is also but got some problem in using it finally i got a class for google contacts import its jus workin smart simple jus providing USERNAME and PASS. like this im expecting for others. im working this in Drupal.

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  • Facebook friends.getLists failing

    - by Shaun Budhram
    Hi all, I'm trying a simple request on Facebook to return all my friend lists. I'm trying this in Facebook's test console, as well as through an iPhone app i'm working on. friends.getLists (also alternatively through FQL) SELECT flid, name FROM friendlist WHERE owner=4810796 I am currently logged in, so using that number should be valid. Both are returning an empty list (not erroring out), but I am certain that I have a few friend lists set up. I've also tried using this with a test account I set up, but got the same results. I could have sworn this command was working earlier. Can anyone please either verify or reject that this is happening for them? Thanks.

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  • How do people charge friends for development projects?

    - by Crashalot
    A friend has begged our consulting firm several times to build an iPhone app. We are reluctant to jeopardize the friendship and charge market rates. At the same time, we're so busy it would be imprudent not to charge fairly. We tried referring her to other shops, but she doesn't feel comfortable with anyone but us. How do people charge friends? Since I'm asking about fees, I'm also curious to know if people charge on a fixed-price basis or hourly basis? Thanks!

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  • How do I find/make programming friends?

    - by Anton
    I recently got my first programming internship and was extremely excited to finally be able to talk with and interact with fellow programmers. I had this assumption that I would find a bunch of like minded individuals who enjoyed programming and other aspects of geek culture. Unfortunately, I find myself working with normal people who program for a living and never discuss or show interest in programming outside of their work. It is incredibly disappointing, because I do think one of the best ways to progress in life and as a programmer is to talk about what you enjoy with others and to build bonds with people who enjoy similar things. So how do I go about finding/making programmer friends?

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  • Graph call "/me/friends" doesn't contain names if called from a testuser

    - by Marc
    When I log into Facebook with my account and call the Graph API with /me/friends it returns an array like this: [ {id: "6868...", name: "John Smith"}, {id: "7531...", name: "Diane Smith"}, ... ] But if I'm logged in with a Facebook testuser and do the same call I get an array like this: [ {id: "100002927..."}, {id: "100003151..."}, ... ] So I'm missing the name property. Bug? Or did I some mistake? I'm using the JS SDK, but I think that doesn't matter.

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  • Some facebook friends' birthdays returning as null but I have the correct API permissions

    - by Andrei Radulescu
    I'm tring to get my friends' birthdays in my app and some of them are null. I thought that those people don't have a birthday set, but they actually do. My fql query is: SELECT uid,name,birthday_date FROM user WHERE uid IN (SELECT uid2 from friend where uid1=me()) My app has the "friends_birthday" permission set. I also tried with "birthday" instead of "birthday_date". Same result. I imagine that this happens because they opted out somehow, but I don't know how. Is there an alternate solution to actually get their birthdays from facebook? Thanks!

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  • Facebook,Android- How to get friends birthday from facebook

    - by Eriz
    I tried to goto lots of questions on this forum but could not find one useful so i decided to ask one myself. I want to pull the birthday's of all the friends in the users friend list. After going through a lot of stuff i found there are 2 ways to do that 1. Graph API 2. FQL Query So, my first question is , which one of them is better/easy to integrate in the app. Q2. http://developers.facebook.com/docs/tutorials/androidsdk/3.0/scrumptious/ is this tutorial useful for what i want to do. Q3. If i use Graph API/FQL Query , could you please give me a link which is helpful or a Code snippet Thanks In Advance, Eriz

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  • list all likes to a certain post coming from my friends

    - by Max Favilli
    I know I can get posts (paginated, 25 at times) of a certain user with this: https://graph.facebook.com/575128756/posts And the likes of a certain post (paginated, 25 at times) with this GRAPH api call (I omit the first part of the url): /575128756_176517292390301/likes But if I want to get the likes from friends of the post user only? FQL could be an alternative (from table like and subqueries for friend and stream), but FQL seems so buggy in my tests I don't feel comfortable using it in a productive system. Is there anyway to achieve my target using the GRAPH api?

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  • Class architecture, no friends allowed

    - by Captain Comic
    The question of why there are no friends in C# has been extensively discussed. I have the following design problems. I have a class that has only one public function AddOrder(Order ord). Clients are allowed to call only this function. All other logic must be hidden. Order class is listening to market events and must call other other function of TradingSystem ExecuteOrder, so I have to make it public as well. Doing that I will allow clients of Trading system to call this function and I don't want that. class TradingSystem { // Trading system stores list of orders List<Order> _orders; // this function is made public so that Order can call ir public ExecuteOrder(Order ord) { } // this function is made public for external clients public AddOrder(OrderRequest ordreq) { // create order and pass it this order.OnOrderAdded(this); } } class Order { TradingSystem _ts; public void OnOrderAdded(TradingSystem ts) { _ts = ts; } void OnMarketEvent() { _ts.ExecuteOrder() } }

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  • Merge Twitter Outh and Facebook Connect Friends

    - by G Ullman
    Basically what I want to do is download all a users facebook and twitter friends and somehow find a way to figure out which entries represent the same person. I know it's possible because a lot of social search sites like spokeo achieve what I want and more, so does anyone know how they go about doing it or the best way to go about it? I have a basic idea of the facebook and twitter api calls I need to be making however feel free to add any advice or warnings there as well. I know facebook hashes the emails which seems like it could pose a problem. Any help is greatly appreciated.

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  • An Open Letter from Lyle Ekdahl, Group Vice President and General Manager, Oracle's JD Edwards

    - by Brian Dayton
    From Lyle Ekdahl, Group Vice President and General Manager, Oracle's JD Edwards As you may have heard, we recently announced some changes to the way Oracle will offer licensing of technology products with JD Edwards EnterpriseOne. Specifically, we have withdrawn from new sales the product known as JD Edwards EnterpriseOne Technology Foundation ("Blue Stack"). Our motivation for this change is simply to streamline licensing for our customers. Going forward, customers will license Oracle products from Oracle and IBM products from IBM. Customers who are currently licensed for Technology Foundation will continue to receive support--unchanged--through September 30, 2016. This announcement affects how customers license these IBM products; it does not affect Oracle's certification roadmap for IBM products with JD Edwards EnterpriseOne. Customers who are currently running their JD Edwards EnterpriseOne infrastructure using IBM platform components can continue to do so regardless of whether they license these components via Technology Foundation or directly from IBM. New customers choosing to run JD Edwards EnterpriseOne on IBM technology should license JD Edwards EnterpriseOne Core Tools from Oracle while licensing Infrastructure and any licenses of IBM products from IBM. For more information about this announcement, customers should refer to My Oracle Support article 1232453.1 Questions included in the "Frequently Asked Questions" document on My Oracle Support: Is Oracle dropping support for IBM DB2 and IBM WebSphere with JD Edwards EnterpriseOne? No. This announcement affects how customers license these IBM products; it does not affect Oracle's certification roadmap for these products. The JD Edwards EnterpriseOne matrix of supported databases, web servers, and portals remains unchanged, including planned support for IBM DB2, IBM WebSphere Application Server, and IBM WebSphere Portal. Customers who are currently running their JD Edwards EnterpriseOne infrastructure using IBM platform components can continue to do so regardless of whether they license these components via Technology Foundation or directly from IBM. As always, the timing and versions of such third-party certifications remain at Oracle's discretion. Does this announcement mean that Oracle is withdrawing support for JD Edwards EnterpriseOne on the IBM i platform? Absolutely not. JD Edwards EnterpriseOne support on the IBM i platform remains unchanged. This announcement simply states that customers will acquire Oracle products from Oracle and IBM products from IBM. In fact, as evidenced by the recent "IBM i Solution Edition for JD Edwards" offering, IBM and the JD Edwards product teams continue to innovate and offer attractive, cost-competitive solutions to the ERP marketplace. For more information about this offering see: http://www-03.ibm.com/systems/i/advantages/oracle/. I hope this clarifies any concerns. Let me know if you have any additional questions or concerns. -Lyle

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