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  • Filtering on a left join in SQLalchemy

    - by Adam Ernst
    Using SQLalchemy I want to perform a left outer join and filter out rows that DO have a match in the joined table. I'm sending push notifications, so I have a Notification table. This means I also have a ExpiredDeviceId table to store device_ids that are no longer valid. (I don't want to just delete the affected notifications as the user might later re-install the app, at which point the notifications should resume according to Apple's docs.) CREATE TABLE Notification (device_id TEXT, time DATETIME); CREATE TABLE ExpiredDeviceId (device_id TEXT PRIMARY KEY, expiration_time DATETIME); Note: there may be multiple Notifications per device_id. There is no "Device" table for each device. So when doing SELECT FROM Notification I should filter accordingly. I can do it in SQL: SELECT * FROM Notification LEFT OUTER JOIN ExpiredDeviceId ON Notification.device_id = ExpiredDeviceId.device_id WHERE expiration_time == NULL But how can I do it in SQLalchemy? sess.query( Notification, ExpiredDeviceId ).outerjoin( (ExpiredDeviceId, Notification.device_id == ExpiredDeviceId.device_id) ).filter( ??? ) Alternately I could do this with a device_id NOT IN (SELECT device_id FROM ExpiredDeviceId) clause, but that seems way less efficient.

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  • JOIN (SELECT DISTINCT [..] substitute

    - by FRKT
    Hello, I'd like to find a substitute for using SELECT DISTINCT in a derived table. Let's say I have three tables: CREATE TABLE `trades` ( `tradeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `employeeID` int(11) unsigned NOT NULL, `corporationID` int(11) unsigned NOT NULL, `profit` int(11) NOT NULL, KEY `tradeID` (`tradeID`), KEY `employeeID` (`employeeID`), KEY `corporationID` (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `corporations` ( `corporationID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`corporationID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 CREATE TABLE `employees` ( `employeeID` int(11) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, PRIMARY KEY (`employeeID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 Let's say I'd like to find out how much profit a specific employee has generated. Simple: SELECT SUM(profit) FROM trades JOIN employees ON trades.employeeID = employees.employeeID AND employees.employeeID = 1; It gets trickier if I'd like to query how much revenue a specific corporation has, however. I cannot simply replicate the aforementioned query, because two or more employees from the same company might be involved in the same trade. This query should do the trick: SELECT SUM(profit) FROM trades JOIN (SELECT DISTINCT tradeID FROM trades WHERE trades.corporationID = 1) ... unfortunately, DISTINCT JOINs seem crazy ineffective. Is there any alternative I can use to determine how much revenue a corporation has, taking into account that a corporation might be listed several times with the same tradeID?

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  • Hibernate HQL m:n join problem

    - by smallufo
    I am very unfamiliar with SQL/HQL , and am currently stuck with this 'maybe' simple problem : I have two many-to-many Entities , with a relation table : Car , CarProblem , and Problem . One Car may have many Problems , One Problem may appear in many Cars, CarProblem is the association table with other properties . Now , I want to find Car(s) with specified Problem , how do I write such HQL ? All ids are Long type . I've tried a lot of join / inner-join combinations , but all in vain.. -- updated : Sorry , forget to mention : Car has many CarProblem Problem has many CarProblem Car and Problem are not directly connected in Java Object. -- update , java code below -- @Entity public class Car extends Model{ @OneToMany(mappedBy="car" , cascade=CascadeType.ALL) public Set<CarProblem> carProblems; } @Entity public class CarProblem extends Model{ @ManyToOne public Car car; @ManyToOne public Problem problem; ... other properties } @Entity public class Problem extends Model { other properties ... // not link to CarProblem , It seems not related to this problem // **This is a very stupid query , I want to get rid of it ...** public List<Car> findCars() { List<CarProblem> list = CarProblem.find("from CarProblem as cp where cp.problem.id = ? ", id).fetch(); Set<Car> result = new HashSet<Car>(); for(CarProblem cp : list) result.add(cp.car); return new ArrayList<Car>(result); } } The Model is from Play! framework , so these properties are all public .

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  • SQL Standard Regarding Left Outer Join and Where Conditions

    - by Ryan
    I am getting different results based on a filter condition in a query based on where I place the filter condition. My questions are: Is there a technical difference between these queries? Is there anything in the SQL standard that explains the different resultsets in the queries? Given the simplified scenario: --Table: Parent Columns: ID, Name, Description --Table: Child Columns: ID, ParentID, Name, Description --Query 1 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID) WHERE c.ID IS NULL OR c.Description = 'FilterCondition' --Query 2 SELECT p.ID, p.Name, p.Description, c.ID, c.Name, c.Description FROM Parent p LEFT OUTER JOIN Child c ON (p.ID = c.ParentID AND c.Description = 'FilterCondition') I assumed the queries would return the same resultsets and I was surprised when they didn't. I am using MS SQL2005 and in the actual queries, query 1 returned ~700 rows and query 2 returned ~1100 rows and I couldn't detect a pattern on which rows were returned and which rows were excluded. There were still many rows in query 1 with child rows with data and NULL data. I prefer the style of query 2 (and I think it is more optimal), but I thought the queries would return the same results.

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  • Left Join only returning one row

    - by Adam
    I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

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  • Oracle - Update statement with inner join

    - by user169743
    I have a query which works fine in MySQL, I'm trying to get it working on oracle but get the following error SQL Error: ORA-00933: SQL command not properly ended 00933. 00000 - "SQL command not properly ended" The query is: UPDATE table1 INNER JOIN table2 ON table1.value = table2.DESC SET table1.value = table2.CODE WHERE table1.UPDATETYPE='blah'; I'd be extremely grateful for any help.

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  • SQL is this equvelent to a LEFT JoIn?

    - by Jim
    Is this equvelent to a LEFT JOIN? select distinct a.name, b.name from tableA a, (select name from tableB) as b It seems as though there is no link between the two tables. Is there an easier / more efficient way to write this?

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  • How to do a join that removes values?

    - by Georg
    Customers Holidays id | name customer_id | start | end ---+------ ------------+--------+------ 1 | Peter 1 | 5 | 10 2 | Simon 1 | 15 | 20 3 | Mary 2 | 5 | 20 How should my SQL query look that out of start=11,end=14 I get these customers: Peter Mary Is this even manageable with a simple SQL join, or do I need to use sub-queries?

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  • Self join to a table

    - by Mohit
    I have a table like Employee ================== name salary ================== a 10000 b 20000 c 5000 d 40000 i want to get all the employee whose salary is greater than A's salary. I don't want to use any nested or sub query. It has been asked in an interview and hint was to use self join. I really can't figure out how to achieve the same.

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  • Mysql Left Join Null Result

    - by Ozzy
    I have this query SELECT articles.*, users.username AS `user` FROM `articles` LEFT JOIN `users` ON articles.user_id = users.id ORDER BY articles.timestamp Basically it returns the list of articles and the username that the article is associated to. Now if there is no entry in the users table for a particular user id, the users var is NULL. Is there anyway to make it that if its null it returns something like "User Not Found"? or would i have to do this using php?

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  • PHP MySQL join table

    - by Jordan Pagaduan
    $sql = "SELECT logs.full_name, logout.status FROM logs, logout WHERE logs.employee_id = logout.employee_id"; tables -- logs logout I'm having error on this. I search join tables in google. And that's what I got. What is wrong with this code?

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  • Sql query to get the GrandFather name by doing a self join

    - by mahesh
    Hello all , Can any one please give me the query to get the child name and his grand fathers name For eg - if i have a table Relationships in the i have childid and fatherid columns so how will i get the grandfather, i can easily get the father name by using a join but for grandfather i need to do joins 2 times so can any one help me with this D.Mahesh

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  • how to create a linq query using join and max

    - by geoff swartz
    I have 2 tables in my linq dbml. One is people with a uniqueid called peopleid and the other is a vertical with a foreign key for peopleid and a uniqueid called id. I need to create a type of linq query that does a left outer join on people and gets the latest record in the vertical table based off the max(id) column. Can anyone suggest what this should look like? Thanks.

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  • INNER JOIN Returns Too Many Results

    - by Alon
    I have the following SQL: SELECT * FROM [Database].dbo.[TagsPerItem] INNER JOIN [Database].dbo.[Tag] ON [Tag].Id = [TagsPerItem].TagId WHERE [Tag].Name IN ('home', 'car') and it returns: Id TagId ItemId ItemTable Id Name SiteId 1 1 1 Content 1 home 1 2 1 2 Content 1 home 1 3 1 3 Content 1 home 1 4 2 4 Content 2 car 1 5 2 5 Content 2 car 1 6 2 12 Content 2 car 1 instead of just two records, which these names are "home" and "car". How can I fix it? Thanks.

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  • Column-oriented DBMS and JOIN operations

    - by André
    From some of the research I've done on NoSQL, column-oriented databases (like HBase or Cassandra) seem to solve the problem of costly JOIN operations, but I don't get how this approach solves this problem. Can anyone explain it to me and/or link me to interesting documentation regarding this area? Thanks

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  • can we use join inside join in mysql?

    - by I Like PHP
    i have 3 tables structure is below tbl_login login_id | login_name 1 | keshav tbl_role role_id | login_id( refer to tbl_login.login_id) 1 | 1 tbl_stuff stuff_id | role_id( refer to tbl_role.role_id) 1 | 1 i need data in follow format stuff_id | login_name 1 | keshav how to use JOIN to retrive the above data in mysql?

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  • How to output JOINed tables?

    - by ilhan
    $id=(int)$_GET["id"]; $result = mysql_query("SELECT questionstable.*, categorytable.name FROM questionstable INNER JOIN categorytable ON categorytable.id = questionstable.category WHERE id=$id"); $row = mysql_fetch_assoc($result); Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\Program Files\EasyPHP-5.3.4.0\www\scsoru.php on line 33

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  • MySQL SELECT Statment issue

    - by mouthpiec
    Hi, I have the following query which returns 2 tuples SELECT bar_id, bar_name, town_name, bar_telephone, subscription_type_id, type FROM towns, subscriptiontype, regions, bar LEFT JOIN barpictures bp ON bar.bar_id = bp.bar_id_fk WHERE town_id = town_id_fk AND bar.test_field = 0 AND subscription_type_id = subscription_type_id_fk AND region_id = region_id_fk AND (type like 'logo%' OR type IS NULL) The main difference between the tuples is that one has 'type' = logo and the other tuple has 'type' = logo_large. I need that instead of having two tuples, I need that I have 2 type attributes, one holding the "logo" and the other the "logo_large" eg bar_id, bar_name, town_name, bar_telephone, subscription_type_id, type1, type2 is this possible

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  • Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID

    - by Jian Lin
    Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID); ? The ( ) usually is for specifying grouping of something. But in this case, are we supposed to be able to use 2 or more field names... in the example above, it can be all clear that it is 1 field, is it just that the parser is not made to bypass the ( ) when it is all clear? (such as in the language Ruby).

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  • Mysql join two tables and add column values

    - by Mike
    My knowledge of mysql is not very in depth. If I have two tables that for example look like this: Table1 Date v1 v2 v3 05/01/2010 26 abc 45 05/02/2010 31 def 25 05/03/2010 50 ghi 46 Table2 Date v1 v2 v3 05/01/2010 42 jkl 15 05/02/2010 28 mno 14 05/03/2010 12 pqr 64 How can I join them in a query by their date and have the sum of table1.v1 and table2.v1 and also have the sum of table1.v3 and table2.v3. V2 should be ignored.

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  • SQL: GROUP BY after JOIN without overriding rows?

    - by krismeld
    I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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  • help with t-sql self join

    - by stackoverflowuser
    Based on the following table ID Date State ----------------------------- 1 06/10/2010 Complete 1 06/04/2010 Pending 2 06/06/2010 Active 2 06/05/2010 Pending I want the following ouptut ID Date State --------------------------- 1 06/04/2010 Complete 2 06/05/2010 Active So date is the earliest one and State is the latest one. I am failing to apply self join on the table to get the output. Thanks

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  • Mysql SQL join question

    - by David
    I am trying to find all deals information along with how many comments they have received. My query select deals.*, count(comments.comments_id) as counts from deals left join comments on comments.deal_id=deals.deal_id where cancelled='N' But now it only shows the deals that have at least one comment. What is the problem?

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