Search Results

Search found 16022 results on 641 pages for 'model export'.

Page 9/641 | < Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >

  • ASP.Net MVC 2 is it possible to get the same instance of model(with slight changes) in HttpPost meth

    - by jjjjj
    Hi I have a complex entity User: public class User : BaseEntity { public virtual Taxi Taxi { get; set; } --> That is why i call it "complex" public virtual string Login { get; set; } public virtual string Password { get; set; } } where Taxi is a parent of User (Taxi has-many Users): public class Taxi : BaseEntity { public virtual string Name { get; set; } public virtual string ClientIp { get; set; } } BaseEntity consists of public virtual int Id { get; private set; } The problem occurs while trying to edit User [Authorize] public ActionResult ChangeAccountInfo() { var user = UserRepository.GetUser(User.Identity.Name); return View(user); } My ChangeAccountInfo.aspx <fieldset> <legend>Fields</legend> <% %> <div class="editor-label"> <%: Html.LabelFor(model => model.Login) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Login) %> <%: Html.ValidationMessageFor(model => model.Login) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Password) %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.HiddenFor(model => model.Taxi.Name)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> Post changes: [Authorize] [HttpPost] public ActionResult ChangeAccountInfo(User model) { if (ModelState.IsValid) { UserRepository.UpdateUser(model); return RedirectToAction("ChangeAccountInfoSuccess", "Account"); } return View(model); } But, the (User model) parameter has User.Id == 0 -- User entity had 5 before edit User.Login == "my new login" User.Password == "my new password" User.Taxi.Id == 0 -- User.Taxi entity had 3 before edit User.Taxi.Name == "old hidden name" User.Taxi.ClientIp == null -- User entity had 192.168.0.1 before edit Q: Is it possible not to mark all the fields of an entity (that should be in my UpdateUser) with tag "hidden" but still have them unchanged in my HttpPost method? e.g. not User.Taxi.ClientIp = null, but User.Taxi.ClientIp = 192.168.0.1 I'm using nhibernate, if it matters.

    Read the article

  • ForEach with EditorFor

    - by hermiod
    I have got an Entity model which contains a collection of Message objects which are of the type Message which has several properties, including content, MessageID, from, and to. I have created an EditorTemplate for type Message, however, I cannot get it to display the contents of the Messages collection. There are no errors, but nothing is output. Please note that the view code is from an EditorTemplate for the parent Talkback class. Can you have an EditorTemplate calling another EditorTemplate for a child collection? Both the Talkback and Message class are generated by Entity framework from an existing database. View code: <% foreach (TalkbackEntityTest.Message msg in Model.Messages) { Html.EditorFor(x=> msg, "Message"); } %> This is my template code. It is the standard auto-generated view code with some minor changes. <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<TalkbackEntityTest.Message>" %> <%: Html.ValidationSummary(true) %> <fieldset> <legend>Fields</legend> <div class="editor-label"> <%: Html.LabelFor(model => model.MessageID) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.MessageID) %> <%: Html.ValidationMessageFor(model => model.MessageID) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.acad_period) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.acad_period) %> <%: Html.ValidationMessageFor(model => model.acad_period) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.talkback_id) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.talkback_id) %> <%: Html.ValidationMessageFor(model => model.talkback_id) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.From) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.From) %> <%: Html.ValidationMessageFor(model => model.From) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.To) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.To) %> <%: Html.ValidationMessageFor(model => model.To) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.SentDatetime) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.SentDatetime, String.Format("{0:g}", Model.SentDatetime)) %> <%: Html.ValidationMessageFor(model => model.SentDatetime) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.content) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.content) %> <%: Html.ValidationMessageFor(model => model.content) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.MessageTypeID) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.MessageTypeID) %> <%: Html.ValidationMessageFor(model => model.MessageTypeID) %> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> There is definitely content in the Message collection as, if I remove EditorFor and put in response.write on the content property of the Message class, I get the content field for 3 Message objects on the page, which is exactly as expected.

    Read the article

  • In MVC , DAO should be called from Controller or Model

    - by tito
    I have seen various arguments against the DAO being called from the Controller class directly and also the DAO from the Model class.Infact I personally feel that if we are following the MVC pattern , the controller should not coupled with the DAO , but the Model class should invoke the DAO from within and controller should invoke the model class.Why because , we can decouple the model class apart from a webapplication and expose the functionalities for various ways like for a REST service to use our model class. If we write the DAO invocation in the controller , it would not be possible for a REST service to reuse the functionality right ? I have summarized both the approaches below. Approach #1 public class CustomerController extends HttpServlet { proctected void doPost(....) { Customer customer = new Customer("xxxxx","23",1); new CustomerDAO().save(customer); } } Approach #2 public class CustomerController extends HttpServlet { proctected void doPost(....) { Customer customer = new Customer("xxxxx","23",1); customer.save(customer); } } public class Customer { ........... private void save(Customer customer){ new CustomerDAO().save(customer); } } Note- Here is what a definition of Model is : Model: The model manages the behavior and data of the application domain, responds to requests for information about its state (usually from the view), and responds to instructions to change state (usually from the controller). In event-driven systems, the model notifies observers (usually views) when the information changes so that they can react. I would need an expert opinion on this because I find many using #1 or #2 , So which one is it ?

    Read the article

  • export command within shell script

    - by shantanuo
    When I use export command at command prompt, it works as expected. But it does not work from shell script. [root@server shantanu]# export myip=10 [root@server shantanu]# echo $myip 10 [root@server shantanu]# vi myip.sh #!/bin/sh export myipadd=10 [root@server shantanu]# sh -xv myip.sh #!/bin/sh export myipadd=10 + export myipadd=10 + myipadd=10 [root@server shantanu]# echo $myipadd I want to make the variable available to the same script next time when it runs. In other words I am looking for some way to memorize the variable value.

    Read the article

  • How can I export a folder with many subfolders w/ all msgs in eml format from Thunderbird

    - by Erik Vold
    I'm trying to export a very large folder that has emails and many subfolders into a folder on the file system with the same structure and where all the emails are in .eml format. Or I'd like to export the messages in a way that they are easy to import in to Thunderbird. I can't seem to find a way except slowly drag and drop the email messages, while manually creating each folder, and that could take days to do, so I need a better method.

    Read the article

  • Export to Excel from ASP.NET produces files unreadable with Excel Viewer

    - by MainMa
    Hi, I want to output some dynamic data from an ASP.NET website to Excel. I found that the easiest way which does not require to use Excel XML or to install Excel on server machine is to output data as a table and specify application/vnd.ms-excel type. The problem is when I do so and try to open the file in Excel Viewer, I receive the following error message: Microsoft Excel Viewer cannot open files of this type. Then nothing is opened. Even an easiest code such as: protected void Page_Load(object sender, EventArgs e) { Response.Clear(); Response.Buffer = true; HttpContext.Current.Response.AddHeader("content-disposition", "attachment; filename=Example.xls"); Response.ContentType = "application/vnd.ms-excel"; StringWriter stringWriter = new System.IO.StringWriter(); HtmlTextWriter htmlTextWriter = new System.Web.UI.HtmlTextWriter(stringWriter); dataGrid.RenderControl(htmlTextWriter); Response.Write("<html><body><table><tr><td>A</td><td>B</td></tr><tr><td>C</td><td>D</td></tr></table></body></html>"); Response.End(); } produces the same error. What can cause such behavior? Is it because the Viewer cannot read such files, but full Excel version can?

    Read the article

  • Custom model binder for model inner property

    - by Andrej Kaurin
    My model is like this public class MyModel { string ID {get;set;} string Title {get;set;} MyOtherModel Meta {get;set;} } How to define custom model binder for type (MyOtherModel) so when default binder binds MyModel it calls custom model binder for 'Meta' property. I registered it in App start like: ModelBinders.Binders[typeof(MyOtherModel)] = new MyCustomBinder(); but this doesn't work. Any idea or any good article with more infor regarding to model binders?

    Read the article

  • Actor model to replace the threading model?

    - by prosseek
    I read a chapter in a book (Seven languages in Seven Weeks by Bruce A. Tate) about Matz (Inventor of Ruby) saying that 'I would remove the thread and add actors, or some other more advanced concurrency features'. Why and how an actor model can be an advanced concurrency model that replaces the threading? What other models are the 'advanced concurrency model'?

    Read the article

  • How do I reference Django Model from another model

    - by user313943
    Im looking to create a view in the admin panel for a test program which logs Books, publishers and authors (as on djangoproject.com) I have the following two models defined. class Author(models.Model): first_name = models.CharField(max_length=30) last_name = models.CharField(max_length=30) email = models.EmailField() def __unicode__(self): return u'%s %s' % (self.first_name, self.last_name) class Book(models.Model): title = models.CharField(max_length=100) authors = models.ManyToManyField(Author) publisher = models.ForeignKey(Publisher) publication_date = models.DateField() def __unicode__(self): return self.title What I want to do, is change the Book model to reference the first_name of any authors and show this using admin.AdminModels. #Here is the admin model I've created. class BookAdmin(admin.ModelAdmin): list_display = ('title', 'publisher', 'publication_date') # Author would in here list_filter = ('publication_date',) date_hierarchy = 'publication_date' ordering = ('-publication_date',) fields = ('title', 'authors', 'publisher', 'publication_date') filter_horizontal = ('authors',) raw_id_fields = ('publisher',) As I understand it, you cannot have two ForeignKeys in the same model. Can anyone give me an example of how to do this? I've tried loads of different things and its been driving me mad all day. Im pretty new to Python/Django. Just to be clear - I'd simply like the Author(s) First/Last name to appear alongside the book title and publisher name. Thanks

    Read the article

  • Export from HTML to PDF (C#)

    - by Sem Dendoncker
    Hi, In our applications we make html documents as reports and exports. But now our customer wants a button that saves that document on their pc. The problem is that the document includes images. You can create a word document with the following code: private void WriteWordDoc(string docName) { Response.Buffer = true; Response.ContentType = "application/msword"; Response.AddHeader("content-disposition", String.Format("attachment;filename={0}.doc", docName.Replace(" ", "_"))); Response.Charset = "utf-8"; } But the problem is that the images are just links an thus not embedded in the word document. Therefore I'm looking for an alternative PDF seems to be a good alternative, does anyone know a good pdf writer for C#? One that has some good references and has been tested properly? Best regards, Sem

    Read the article

  • Export list as .txt (Python)

    - by Nimbuz
    My Python module has a list that contains all the data I want to save as a .txt file somewhere. The list contains several tuples like so: list = [ ('one', 'two', 'three'), ('four', 'five', 'six')] How do I print the list so each tuple item is separated by a tab and each tuple is separated by a newline? Thanks

    Read the article

  • How to define one-to-many connection between a same model through another model

    - by Mekajiki
    I want to define one-to-many relationship as follows; User has one introducer User has many newcomers(who is introduced by the user) Use "Introduction" model instead of adding a column to users table. My table and model definition is as follows; DB Scheme: create_table "introductions", force: true do |t| t.integer "introducer_id" t.integer "newcomer_id" t.datetime "created_at" t.datetime "updated_at" User model: class User < ActiveRecord::Base has_many :introductions, foreign_key: :introducer_id has_many :newcomers, through: :introductions, source: :newcomer belongs_to :introduction, foreign_key: :newcomer_id belongs_to :introducer end Introduction model: class Introduction < ActiveRecord::Base belongs_to :introducer, class_name: 'User' belongs_to :newcomer, class_name: 'User' end This works fine: user1.newcomers.push user2 but, user2.introducer # => nil How can I define belongs_to relationship correctly?

    Read the article

  • MVC Rendered Partial, how to get partial/view model in main model post to controller

    - by user1475788
    I have a text file and when users upload the file, the controller action method parses that file using state machine and uses a generic list to store some values. I pass this back to the view in the form of an IEnumerable. Within my main view, based on this ienumerable list I render a partail view to iterate items and display labels and a textarea. Users could add their input in the text area. When the users hit the save button this ienumrable list from the partial view rendered is null. so please advice any solutions. here is my main view @model RunLog.Domain.Entities.RunLogEntry @{ ViewBag.Title = "Create"; Layout = "~/Views/Shared/_Layout.cshtml"; } @using (Html.BeginForm("Create", "RunLogEntry", FormMethod.Post, new { enctype = "multipart/form-data" })) { <div id="inputTestExceptions" style="display: none;"> <table class="grid" style="width: 450px; margin: 3px 3px 3px 3px;"> <thead> <tr> <th> Exception String </th> <th> Comment </th> </tr> </thead> <tbody> @if (Model.TestExceptions != null) { foreach (var p in Model.TestExceptions) { Html.RenderPartial("RunLogTestExceptionSummary", p); } } </tbody> </table> </div> } partial view as follows: @model RunLog.Domain.Entities.RunLogEntryTestExceptionDisplay <tr> <td> @Model.TestException@ </td> <td>@Html.TextAreaFor(Model.Comment, new { style = "width: 200px; height: 80px;" }) </td> </tr> Controller action [HttpPost] public ActionResult Create(RunLogEntry runLogEntry, String ServiceRequest, string Hour, string Minute, string AMPM, string submit, IEnumerable<HttpPostedFileBase> file, String AssayPerformanceIssues1, IEnumerable<RunLogEntryTestExceptionDisplay> models) { } The problem is test exceptions which contains exception string and comment is comming back null.

    Read the article

  • Import CSV from url address and export as XML -- Rails

    - by Jeffrey
    Two questions: How can I import a file from a web address, without a form? Example: Organisation.import(:from = 'http://wufoo.com/report.csv') How can I use xml builder without pulling from the db? More Info My company uses wufoo for web forms. The data from wufoo is exported as csv files. To get the data into my company's cms, it needs to be formatted as xml. I don't need to store any of the data, aside from the url to the csv file. I thought this might work well as a simple rails app.

    Read the article

  • MySQL Export with Column Heading

    - by st4nt0n
    Hello - I am very, very, new to mySQL. I've got experience in general technical terms, but not with the syntax or concepts of mySQL. I have been tasked with exporting a table from MySQL into a pipe delimited .txt or .xls that I can use to add 7500 more records to manually, then import back into the table. I tried to use INTO OUTFILE, but I don't get column headings, which I need for reference to merge the new records. Is there a good resource that can explain this to a complete novice? I would usually go down to my bookstore and start learning, but I'm on a bit of a time crunch. Thanks all!

    Read the article

  • SecurityException when trying to export a java resource

    - by thecoop
    I'm trying to get the source of a java resource stored in an oracle database using this code (connecting as SYSTEM for testing): DECLARE javalob CLOB; BEGIN DBMS_LOB.CREATETEMPORARY(javalob, false); DBMS_JAVA.EXPORT_RESOURCE('RESOURCENAME', 'SCHEMA', javalob); DBMS_OUTPUT.PUT_LINE(javalob); END; But when I try to run it I get this: Java call terminated by uncaught Java exception: java.lang.SecurityException: cannot read <Resource Handle: RESOURCENAME|SCHEMA|301> because SYSTEM does not have execute privilege on it This thing is, I'm not sure how to grant permissions on <Resource Handle: RESOURCENAME|SCHEMA|301>, as this isn't a SQL or PL/SQL object. And why doesn't SYSTEM have access to it anyway?

    Read the article

  • Drupal Views Bonus Pack export issue

    - by evanmcd
    Hi, In trying to solve the problem of getting data from Drupal into XML, I found the Views Bonus Pack module, which with a little figuring out works great. Except... When setting the Style property in the Basic settings of Feed view to XML file no items show up unless I am authenticated. If I log in, I see all the entries. If I log out, I see only <xml> <node/> </xml> The Access setting is set to unrestricted in both the Defaults and the Feed view. Anybody have any ideas as to how to fix this? Thanks a lot.

    Read the article

  • Using a join model to relate a model to itself

    - by Gabe Hollombe
    I have two models: User MentoringRelationship MentoringRelationship is a join model that has a mentor_id column and a mentee_id column (both of these reference user_ids from the users table). How can I specify a relation called 'mentees' on the User class that will return all of the users mentored by this user, using the MentoringRelationships join table? What relations do we need to declare in the User model and in the MentoringRelationship model?

    Read the article

  • MVVM- View Model-View Model Communications

    - by user275561
    How do I go about having two view models communicate with one another using MVVM Light. I know how to use the messenger class and register etc.. Here is my Scenario A Settings View ---> a Settings View Model . . . A MainPage View ---> A MainPage ViewModel If something changes in the Settings View it will Message back to the Settings View Model. So then I want the Settings View Model to communicate to the MainPage View Model about what changed. THe MainPage ViewModel will then tell the View.

    Read the article

  • How to import and export only data of whole database in access 2007

    - by DiegoMaK
    Hi, I have two identical databases with same structure, database a in computer a and database b in computer b. The data of database a*(a.accdb)* and database b*(b.accdb)* are different. then in database a i have for example ID:1, 2, 3 and in database B i Have ID:4,5,6 Then i need merge these databases data in only one database(a or b, doesn't matter) so the final database looks like. ID:1,2,3,4,5,6 I search an easy way to do this. because i have many tables. and do this by union query is so tedious. I search for example for a backup option for only data without scheme as in postgreSQl or many others RDBMS, but i don't see this options in access 2007. pd:only just table could be duplicate values(i guess that pk doesn't allow copy a duplicate value and all others values will be copied well). if i wrong please correct me. thanks for your help.

    Read the article

  • export a JOGL applet and embedd into a html page

    - by nkint
    hi guys it is some time that i'm testing opengl with java and JOGL. now i have good result and i wanto to pubblish it on web. but i have some problem. i'm in eclipse, and i'm testing an Applet with JOGL. first of all i have this run time error (but the program works correctly): java.lang.IllegalArgumentException: adding a window to a container at java.awt.Container.checkNotAWindow(Container.java:431) at java.awt.Container.addImpl(Container.java:1039) at java.awt.Container.add(Container.java:365) at AppletHelloWorld.init(AppletHelloWorld.java:30) at sun.applet.AppletPanel.run(AppletPanel.java:424) at java.lang.Thread.run(Thread.java:619) then i found this incredibly clear page and i do what is said, i open html with the browser, the libs are downloaded but it stops at "Starting applet AppletHelloWorld" that is the name i gave to my applet. mayebe i miss something like main function or exporting well the jar? this is my main code: public class AppletHelloWorld extends Applet { public static void main(String[] args) { JFrame fr=new JFrame(); fr.setBounds(0,0,1015,600); fr.add(new AppletHelloWorld()); fr.setVisible(true); } public void init() { setLayout(null); MyJOGLProject canvas = new MyJOGLProject(); //MyJOGLProject extends JFrame canvas.run(); Container c = new Container(); c.add(canvas); add(c); } //....

    Read the article

< Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >