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• error in coding a lexer in c

  - by mekasperasky

  #include<stdio.h> #include<ctype.h> #include<string.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i=0,j,k,count=0; char a,b[100],c[10000],d[100]; memset ( d, 0, 100 ); j=30; FILE *fp1,*fp2; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("lext.txt","w"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; k=0; while(!feof(fp1)) { a=fgetc(fp1); if(a!=' '&&a!='\n') { if (!isalpha(a)) { switch(a) { case '+':{fprintf(fp2,"+ ----> PLUS \n"); i=0;break;} case '-':{fprintf(fp2,"- ---> MINUS \n"); i=0;break;} case '*':{fprintf(fp2, "* --->MULT \n"); i=0;break;} case '/':{fprintf(fp2, "/ --->DIV \n"); i=0;break;} //case '+=':fprintf(fp2, "%.20s\n", "ADD_ASSIGN"); //case '-=':fprintf(fp2, "%.20s\n", "SUB_ASSIGN"); case '=':{fprintf(fp2, "= ---> ASSIGN \n"); i=0;break;} case '%':{fprintf(fp2, "% ---> MOD \n"); i=0;break;} case '<':{fprintf(fp2, "< ---> LESSER_THAN \n"); i=0;break;} case '>':{fprintf(fp2, "> --> GREATER_THAN \n"); i=0;break;} //case '++':fprintf(fp2, "%.20s\n", "INCREMENT"); //case '--':fprintf(fp2, "%.20s\n", "DECREMENT"); //case '==':fprintf(fp2, "%.20s\n", "ASSIGNMENT"); case ';':{fprintf(fp2, "; --->SEMI_COLUMN \n"); i=0;break;} case ':':{fprintf(fp2, ": --->COLUMN \n"); i=0;break;} case '(':{fprintf(fp2, "( --->LPAR \n"); i=0;break;} case ')':{fprintf(fp2, ") --->RPAR \n"); i=0;break;} case '{':{fprintf(fp2, "{ --->LBRACE \n"); i=0;break;} case '}':{fprintf(fp2, "} ---> RBRACE \n"); i=0;break;} } } else { d[i]=a; //printf("%c\n",d[i]); i=i+1; } //} /* we can make the lexer more complex by including even more depths of checks for the symbols*/ } else { d[i+1]='\0'; printf("\n"); if((strcmp(d,"if ")==0)){fprintf(fp2,"if ----> IDENTIFIER \n"); //printf("%s \n",d); memset ( d, 0, 100 ); //printf("%s \n",d); count=count+1;} else if(strcmp(d,"then")==0){fprintf(fp2,"then ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"else")==0){fprintf(fp2,"else ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"switch")==0){fprintf(fp2,"switch ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"printf")==0){fprintf(fp2,"prtintf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"scanf")==0){fprintf(fp2,"scanf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"NULL")==0){fprintf(fp2,"NULL ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"int")==0){fprintf(fp2,"INT ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"char")==0){fprintf(fp2,"char ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"float")==0){fprintf(fp2,"float ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"long")==0){fprintf(fp2,"long ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"double")==0){fprintf(fp2,"double ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"const")==0){fprintf(fp2,"const ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"continue")==0)fprintf(fp2,"continue ----> IDENTIFIER \n"); else if(strcmp(d,"size of")==0){fprintf(fp2,"size of ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"register")==0){fprintf(fp2,"register ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"short")==0){fprintf(fp2,"short ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"auto")==0){fprintf(fp2,"auto ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"while")==0){fprintf(fp2,"while ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"do")==0){fprintf(fp2,"do ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"case")==0){fprintf(fp2,"case ----> IDENTIFIER \n"); count=count+1;} else if (isdigit(d[i])) { fprintf(fp2,"%s ---->NUMBER",d); } else if (isalpha(a)) { fprintf(fp2,"%s ----> Variable",d); //printf("%s",d); // memset ( d, 0, 100 );} //fprintf(fp2, "s\n", b); i=0; k=k+1; continue; } i=i+1; k=k+1; } fclose(fp1); fclose(fp2); printf("%d",count); return 0; } In this code , my source.txt has if (a+b) stored . But only ( , + and ) is getting written into lext.txt and not the identifier if or the variable a and b . Any particular reason why?

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• Handling aces and finding a segfault in a blackjack program

  - by Bill Adams

  Here's what i have so far... I have yet to figure out how i'm going to handle the 11 / 1 situation with an ace, and when the player chooses an option for hit/stand, i get segfault. HELP!!! #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define DECKSIZE 52 #define VALUE 9 #define FACE 4 #define HANDSIZE 26 typedef struct { int value; char* suit; char* name; }Card; typedef struct { int value; char* suit; char* name; }dealerHand; typedef struct { int value; char* suit; char* name; }playerHand; Card cards[DECKSIZE]; dealerHand deal[HANDSIZE]; playerHand dealt[HANDSIZE]; char *faceName[]={"two","three", "four","five","six", "seven","eight","nine", "ten", "jack","queen", "king","ace"}; char *suitName[]={"spades","diamonds","clubs","hearts"}; void printDeck(){ int i; for(i=0;i<DECKSIZE;i++){ printf("%s of %s value = %d\n ",cards[i].name,cards[i].suit,cards[i].value); if((i+1)%13==0 && i!=0) printf("-------------------\n\n"); } } void shuffleDeck(){ srand(time(NULL)); int this; int that; Card temp; int c; for(c=0;c<10000;c++){ //c is the index for number of individual card shuffles should be set to c<10000 or more this=rand()%DECKSIZE; that=rand()%DECKSIZE; temp=cards[this]; cards[this]=cards[that]; cards[that]=temp; } } /*void hitStand(i,y){ // I dumped this because of a segfault i couldn't figure out. int k; printf(" Press 1 to HIT or press 2 to STAND:"); scanf("%d",k); if(k=1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } } */ int main(){ int suitCount=0; int faceCount=0; int i; int x; int y; int d; int p; int k; for(i=0;i<DECKSIZE;i++){ //this for statement builds the deck if(faceCount<9){ cards[i].value=faceCount+2; }else{ //assigns face cards as value 10 cards[i].value=10; } cards[i].suit=suitName[suitCount]; cards[i].name=faceName[faceCount++]; if(faceCount==13){ //this if loop increments suit count once cards[i].value=11; //all faces have been assigned, and also suitCount++; //assigns the ace as 11 faceCount=0; } //end building deck } /*printDeck(); //prints the deck in order shuffleDeck(); //shuffles the deck printDeck(); //prints the deck as shuffled This was used in testing, commented out to keep the deck hidden!*/ shuffleDeck(); x=0; y=0; for(i=0;i<4;i++){ //this for loop deals the first 4 cards, dealt[y].suit=cards[i].suit; //first card to player, second to dealer, dealt[y].name=cards[i].name; //as per standard dealing practice. dealt[y].value=cards[i].value; i++; y++; deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; } printf(" Dealer's hand is: %s of %s and XXXX of XXXX. (Second card is hidden!)\n",deal[0].name,deal[0].suit,deal[1].name,deal[1].suit); printf(" Player's hand is: %s of %s and %s of %s.\n",dealt[0].name,dealt[0].suit,dealt[1].name,dealt[1].suit); printf(" the current value of the index i=%d\n",i); //this line gave me the value of i for testing d=deal[0].value+deal[1].value; p=dealt[0].value+dealt[1].value; if(d==21){ printf(" The Dealer has Blackjack! House win!\n"); }else{ if(d>21){ printf(" The dealer is Bust! You win!\n"); }else{ if(d>17){ printf(" Press 1 to HIT or 2 to STAND"); scanf("%d",k); if(k==1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } }else{ if(d<17){ printf(" Dealer Hits!"); deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; i++; } } } } return 0; }

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• ANSI C blackjack assignment, linux GCC compiler, i'm stuck...

  - by Bill Adams

  Here's what i have so far... I have yet to figure out how i'm going to handle the 11 / 1 situation with an ace, and when the player chooses an option for hit/stand, i get segfault. HELP!!! #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define DECKSIZE 52 #define VALUE 9 #define FACE 4 #define HANDSIZE 26 typedef struct { int value; char* suit; char* name; }Card; typedef struct { int value; char* suit; char* name; }dealerHand; typedef struct { int value; char* suit; char* name; }playerHand; Card cards[DECKSIZE]; dealerHand deal[HANDSIZE]; playerHand dealt[HANDSIZE]; char *faceName[]={"two","three", "four","five","six", "seven","eight","nine", "ten", "jack","queen", "king","ace"}; char *suitName[]={"spades","diamonds","clubs","hearts"}; void printDeck(){ int i; for(i=0;i<DECKSIZE;i++){ printf("%s of %s value = %d\n ",cards[i].name,cards[i].suit,cards[i].value); if((i+1)%13==0 && i!=0) printf("-------------------\n\n"); } } void shuffleDeck(){ srand(time(NULL)); int this; int that; Card temp; int c; for(c=0;c<10000;c++){ //c is the index for number of individual card shuffles should be set to c<10000 or more this=rand()%DECKSIZE; that=rand()%DECKSIZE; temp=cards[this]; cards[this]=cards[that]; cards[that]=temp; } } /*void hitStand(i,y){ // I dumped this because of a segfault i couldn't figure out. int k; printf(" Press 1 to HIT or press 2 to STAND:"); scanf("%d",k); if(k=1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } } */ int main(){ int suitCount=0; int faceCount=0; int i; int x; int y; int d; int p; int k; for(i=0;i<DECKSIZE;i++){ //this for statement builds the deck if(faceCount<9){ cards[i].value=faceCount+2; }else{ //assigns face cards as value 10 cards[i].value=10; } cards[i].suit=suitName[suitCount]; cards[i].name=faceName[faceCount++]; if(faceCount==13){ //this if loop increments suit count once cards[i].value=11; //all faces have been assigned, and also suitCount++; //assigns the ace as 11 faceCount=0; } //end building deck } /*printDeck(); //prints the deck in order shuffleDeck(); //shuffles the deck printDeck(); //prints the deck as shuffled This was used in testing, commented out to keep the deck hidden!*/ shuffleDeck(); x=0; y=0; for(i=0;i<4;i++){ //this for loop deals the first 4 cards, dealt[y].suit=cards[i].suit; //first card to player, second to dealer, dealt[y].name=cards[i].name; //as per standard dealing practice. dealt[y].value=cards[i].value; i++; y++; deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; } printf(" Dealer's hand is: %s of %s and XXXX of XXXX. (Second card is hidden!)\n",deal[0].name,deal[0].suit,deal[1].name,deal[1].suit); printf(" Player's hand is: %s of %s and %s of %s.\n",dealt[0].name,dealt[0].suit,dealt[1].name,dealt[1].suit); printf(" the current value of the index i=%d\n",i); //this line gave me the value of i for testing d=deal[0].value+deal[1].value; p=dealt[0].value+dealt[1].value; if(d==21){ printf(" The Dealer has Blackjack! House win!\n"); }else{ if(d>21){ printf(" The dealer is Bust! You win!\n"); }else{ if(d>17){ printf(" Press 1 to HIT or 2 to STAND"); scanf("%d",k); if(k==1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } }else{ if(d<17){ printf(" Dealer Hits!"); deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; i++; } } } } return 0; }

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• How to use correctly the comments in C/++

  - by Lucio

  I'm learning to program in C and in my stage, the best form to use correctly the comments is writing good comments from the beginning. As the comments are not just for that one understands better the code but others too, I want to know the views of all of you to reach a consensus. So what I want is that the most experienced users edit the following code as you please. (If it's unnecessary, delete it; If it's wrong, correct it; If needed, add more) Thus there'll be multiple answers with different syntax and the responses with the most votes will be taken as referring when commenting. The code to copy, paste and edit to your pleasure is: (And I remark again, just import the comments, not the code) /* This programs find 1 number in 1 file. The file is binary type and has integers in series. The number is integer type and it's entered from the keyboard. When finished the program, a poster will show the results: Saying if the number is in the file or not. */ #include <stdio.h> //FUNCTION 1 //Open file 'path' and closes it. void openf(char path[]) { int num; //Read from Keyboard a Number and it save it into 'num' var printf("Ready for read number.\n\nNumber --> "); fflush(stdin); scanf("%d",&num); //Open file 'path' in READ mode FILE *fvar; fvar=fopen(path,"rb"); //IF error happens when open file, exit of function if (fvar==NULL) { printf("ERROR while open file %s in read mode.",path); exit(1); } /*Verify the result of 'funct' function IF TRUE, 'num' it's in the file*/ if (funct(path,fvar,num)) printf("The number %d it is in the file %s.",num,path); else printf("The number %d it is not in the file %s.",num,path); fclose(fvar); } /*FUNCTION 2 It is a recursive function. Reads number by number until the file is empty or the number is found. Parameters received: 'path' -> Directory file 'fvar' -> Pointer file 'num' -> Number to compare */ int funct(char path[],FILE *fvar,int num) { int compare; //FALSE condition when the pointer reaches the end if (fread(&compare,sizeof(int),1,fvar)>0) /*TRUE condition when the number readed is iqual that 'num' ELSE will go to the function itself*/ if (compare!=num) funct(path,fvar,num); else return 1; else return 0; } int main(int argc, char **argv) { char path[30]="file.bin"; //Direction of the file to process openf(path); //Function with algorithm return 0; }

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• C code won't compile

  - by cc

  Please help me to understand why the following code will not compile: #include <stdio.h> //#include <iostream> //using namespace std; int main(void){ int i,k,x,y,run,e,r,s,m,count=0; char numbers[19][19]; for(i=0;i<19;i++){ for (k=0;k<19;k++){ numbers[i][k]='.'; } } void drawB(){ printf(" 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 \n"); printf ("0 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[0][0],numbers[0][1],numbers[0][2],numbers[0][3],numbers[0][4], numbers[0][5],numbers[0][6],numbers[0][7],numbers[0][8],numbers[0][9], numbers[0][10],numbers[1][11],numbers[1][12],numbers[1][13],numbers[0][14] ,numbers[0][15],numbers[0][16],numbers[0][17],numbers[0][18]); printf ("1 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[1][0],numbers[1][1],numbers[1][2],numbers[1][3],numbers[1][4], numbers[1][5],numbers[1][6],numbers[1][7],numbers[1][8],numbers[1][9], numbers[1][10],numbers[1][11],numbers[1][12],numbers[1][13],numbers[1][14] ,numbers[1][15],numbers[1][16],numbers[1][17],numbers[1][18]); printf ("2 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" numbers[2][0],numbers[2][1],numbers[2][2],numbers[2][3],numbers[2][4], numbers[2][5],numbers[2][6],numbers[2][7],numbers[2][8],numbers[2][9], numbers[2][10],numbers[2][11],numbers[2][12],numbers[2][13],numbers[2][14] ,numbers[2][15],numbers[2][16],numbers[2][17],numbers[2][18]); printf ("3 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[3][0],numbers[3][1],numbers[3][2],numbers[3][3],numbers[3][4], numbers[3][5],numbers[3][6],numbers[3][7],numbers[3][8],numbers[3][9], numbers[3][10],numbers[3][11],numbers[3][12],numbers[3][13],numbers[3][14] ,numbers[3][15],numbers[3][16],numbers[3][17],numbers[3][18]); printf ("4 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[4][0],numbers[4][1],numbers[4][2],numbers[4][3],numbers[4][4], numbers[4][5],numbers[4][6],numbers[4][7],numbers[4][8],numbers[4][9], numbers[4][10],numbers[4][11],numbers[4][12],numbers[4][13],numbers[4][14] ,numbers[4][15],numbers[4][16],numbers[4][17],numbers[4][18]); printf ("5 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[5][0],numbers[5][1],numbers[5][2],numbers[5][3],numbers[5][4], numbers[5][5],numbers[5][6],numbers[5][7],numbers[5][8],numbers[5][9], numbers[5][10],numbers[5][11],numbers[5][12],numbers[5][13],numbers[5][14] ,numbers[5][15],numbers[5][16],numbers[5][17],numbers[5][18]); printf ("6 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[6][0],numbers[6][1],numbers[6][2],numbers[6][3],numbers[6][4], numbers[6][5],numbers[6][6],numbers[6][7],numbers[6][8],numbers[6][9], numbers[6][10],numbers[6][11],numbers[6][12],numbers[6][13],numbers[6][14] ,numbers[6][15],numbers[6][16],numbers[6][17],numbers[6][18]); printf ("7 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[7][0],numbers[7][1],numbers[7][2],numbers[7][3],numbers[7][4], numbers[7][5],numbers[7][6],numbers[7][7],numbers[7][8],numbers[7][9], numbers[7][10],numbers[7][11],numbers[7][12],numbers[7][13],numbers[7][14] ,numbers[7][15],numbers[7][16],numbers[7][17],numbers[7][18]); printf ("8 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[8][0],numbers[8][1],numbers[8][2],numbers[8][3],numbers[8][4], numbers[8][5],numbers[8][6],numbers[8][7],numbers[8][8],numbers[8][9], numbers[8][10],numbers[8][11],numbers[8][12],numbers[8][13],numbers[8][14] ,numbers[8][15],numbers[8][16],numbers[8][17],numbers[8][18]); printf ("9 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[9][0],numbers[9][1],numbers[9][2],numbers[9][3],numbers[9][4], numbers[9][5],numbers[9][6],numbers[9][7],numbers[9][8],numbers[9][9], numbers[9][10],numbers[9][11],numbers[9][12],numbers[9][13],numbers[9][14] ,numbers[9][15],numbers[9][16],numbers[9][17],numbers[9][18]); printf ("0 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[10][0],numbers[10][1],numbers[10][2],numbers[10][3],numbers[10][4], numbers[10][5],numbers[10][6],numbers[10][7],numbers[10][8],numbers[10][9], numbers[10][10],numbers[10][11],numbers[10][12],numbers[10][13],numbers[10][14] ,numbers[10][15],numbers[10][16],numbers[10][17],numbers[10][18]); printf ("1 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[11][0],numbers[11][1],numbers[11][2],numbers[11][3],numbers[11][4], numbers[11][5],numbers[11][6],numbers[11][7],numbers[11][8],numbers[11][9], numbers[11][10],numbers[11][11],numbers[11][12],numbers[11][13],numbers[11][14] ,numbers[11][15],numbers[11][16],numbers[11][17],numbers[11][18]); printf ("2 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[12][0],numbers[12][1],numbers[12][2],numbers[12][3],numbers[12][4], numbers[12][5],numbers[12][6],numbers[12][7],numbers[12][8],numbers[12][9], numbers[12][10],numbers[12][11],numbers[12][12],numbers[12][13],numbers[12][14] ,numbers[12][15],numbers[12][16],numbers[12][17],numbers[12][18]); printf ("3 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[13][0],numbers[13][1],numbers[13][2],numbers[13][3],numbers[13][4], numbers[13][5],numbers[13][6],numbers[13][7],numbers[13][8],numbers[13][9], numbers[13][10],numbers[13][11],numbers[13][12],numbers[13][13],numbers[13][14] ,numbers[13][15],numbers[13][16],numbers[13][17],numbers[13][18]); printf ("4 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[14][0],numbers[14][1],numbers[14][2],numbers[14][3],numbers[14][4], numbers[14][5],numbers[14][6],numbers[14][7],numbers[14][8],numbers[14][9], numbers[14][10],numbers[14][11],numbers[14][12],numbers[14][13],numbers[14][14] ,numbers[14][15],numbers[14][16],numbers[14][17],numbers[14][18]); printf ("5 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[15][0],numbers[15][1],numbers[15][2],numbers[15][3],numbers[15][4], numbers[15][5],numbers[15][6],numbers[15][7],numbers[15][8],numbers[15][9], numbers[15][10],numbers[15][11],numbers[15][12],numbers[15][13],numbers[15][14] ,numbers[15][15],numbers[15][16],numbers[15][17],numbers[15][18]); printf ("6 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[16][0],numbers[16][1],numbers[16][2],numbers[16][3],numbers[16][4], numbers[16][5],numbers[16][6],numbers[16][7],numbers[16][8],numbers[16][9], numbers[16][10],numbers[16][11],numbers[16][12],numbers[16][13],numbers[16][14] ,numbers[16][15],numbers[16][16],numbers[16][17],numbers[16][18]); printf ("7 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[17][0],numbers[17][1],numbers[17][2],numbers[17][3],numbers[17][4], numbers[17][5],numbers[17][6],numbers[17][7],numbers[17][8],numbers[17][9], numbers[17][10],numbers[17][11],numbers[17][12],numbers[17][13],numbers[17][14] ,numbers[17][15],numbers[17][16],numbers[17][17],numbers[17][18]); printf ("8 %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c %c \n\n" ,numbers[18][0],numbers[18][1],numbers[18][2],numbers[18][3],numbers[18][4], numbers[18][5],numbers[18][6],numbers[18][7],numbers[18][8],numbers[18][9], numbers[18][10],numbers[18][11],numbers[18][12],numbers[18][13],numbers[18][14] ,numbers[18][15],numbers[18][16],numbers[18][17],numbers[18][18]); } void checkSurrounded (int x,int y){ //numbers [x-1,y-1 ] , numbers [x-1,y ] , numbers [x-1,y+1 ] //numbers [x,y-1 ] , numbers [x,y ] , numbers [x,y+1 ] //numbers [x+1,y-1, ] , numbers [x+1,y ] , numbers [x+1,y+1 ] if(numbers[x][y]=='A'){ if((numbers[x-1][y-1]=='B') && (numbers[x-1][y]=='B') && (numbers[x-1][y+1]=='B') && (numbers[x][y-1]=='B') && (numbers[x][y+1]=='B') && (numbers[x+1][y-1]=='B') && (numbers[x+1][y]=='B')){ numbers[x][y]='B';} } if(numbers[x][y]=='B'){ if((numbers[x-1][y-1]=='A') && (numbers[x-1][y]=='A') && (numbers[x-1][y+1]=='A') && (numbers[x][y-1]=='A') && (numbers[x][y+1]=='A') && (numbers[x+1][y-1]=='A') && (numbers[x+1][y]=='A')){ numbers[x][y]='A'; } } } /** void checkArea(){ //detect enemy stone //store in array //find adjacent enemy stones // store the enemy stones in the array //keep on doing this until there are no more enemy stones that are adjacent for (s=0;s<19;s++) { for (m=0;m<19;m++) { if (numbers[s][m]=='A'){ count++; } } } }//end fn void checkAdjacent(int x, int y){ if (numbers [x][y]=='A'){ if((numbers[x][y-1]=='B' && numbers [x-1][y]=='B' && numbers[x][y+1]=='B' && numbers[x+1][y]=='B')){ } } } void getUserInput(){ int run=1; while(run){ printf("Enter x coordinate\n"); scanf("%d",&x); printf("Enter y coordinate\n"); scanf("%d",&y); if((x>18 || y>18 || x<0 || y<0) && !( numbers[x][y]=='.' )){ printf("invalid imput\n"); } else{ numbers[x][y]='B'; run=0; drawB(); } } } */ void getCupInput(){ //go through borad //starting from [0][0] //stop at first player stone //save as target x and target y //surround target x and target y //if already surrounded //start looking in borad again from last position //at end of board reset to [0][0] for(s=0;s<19;s++) { for(m=0;m<19;m++) { if (numbers[s][m]==0){ count++; } } } x=x-2; y=y+2; numbers[x][y]='A'; drawB(); } while(1){ //getUserInput(); getCupInput(); } system("pause"); return 0; }

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• Help debugging c fifos code - stack smashing detected - open call not functioning - removing pipes

  - by nunos

  I have three bugs/questions regarding the source code pasted below: stack smashing deteced: In order to compile and not have that error I have addedd the gcc compile flag -fno-stack-protector. However, this should be just a temporary solution, since I would like to find where the cause for this is and correct it. However, I haven't been able to do so. Any clues? For some reason, the last open function call doesn't work and the programs just stops there, without an error, even though the fifo already exists. I want to delete the pipes from the filesystem after before terminating the processes. I have added close and unlink statements at the end, but the fifos are not removed. What am I doing wrong? Thanks very much in advance. P.S.: I am pasting here the whole source file for additional clarity. Just ignore the comments, since they are in my own native language. server.c: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> #include <errno.h> #define MAX_INPUT_LENGTH 100 #define FIFO_NAME_MAX_LEN 20 #define FIFO_DIR "/tmp/" #define FIFO_NAME_CMD_CLI_TO_SRV "lrc_cmd_cli_to_srv" typedef enum { false, true } bool; bool background = false; char* logfile = NULL; void read_from_fifo(int fd, char** var) { int n_bytes; read(fd, &n_bytes, sizeof(int)); *var = (char *) malloc (n_bytes); read(fd, *var, n_bytes); printf("read %d bytes '%s'\n", n_bytes, *var); } void write_to_fifo(int fd, char* data) { int n_bytes = (strlen(data)+1) * sizeof(char); write(fd, &n_bytes, sizeof(int)); //primeiro envia o numero de bytes que a proxima instrucao write ira enviar write(fd, data, n_bytes); printf("writing %d bytes '%s'\n", n_bytes, data); } int main(int argc, char* argv[]) { //CRIA FIFO CMD_CLI_TO_SRV, se ainda nao existir char* fifo_name_cmd_cli_to_srv; fifo_name_cmd_cli_to_srv = (char*) malloc ( (strlen(FIFO_NAME_CMD_CLI_TO_SRV) + strlen(FIFO_DIR) + 1) * sizeof(char) ); strcpy(fifo_name_cmd_cli_to_srv, FIFO_DIR); strcat(fifo_name_cmd_cli_to_srv, FIFO_NAME_CMD_CLI_TO_SRV); int n = mkfifo(fifo_name_cmd_cli_to_srv, 0660); //TODO ver permissoes if (n < 0 && errno != EEXIST) //se houver erro, e nao for por causa de ja haver um com o mesmo nome, termina o programa { fprintf(stderr, "erro ao criar o fifo\n"); fprintf(stderr, "errno: %d\n", errno); exit(4); } //se por acaso já existir, nao cria o fifo e continua o programa normalmente //le informacao enviada pelo cliente, nesta ordem: //1. pid (em formato char*) do processo cliente //2. comando /CONNECT //3. nome de fifo INFO_SRV_TO_CLIXXX //4. nome de fifo MSG_SRV_TO_CLIXXX char* command; char* fifo_name_info_srv_to_cli; char* fifo_name_msg_srv_to_cli; char* client_pid_string; int client_pid; int fd_cmd_cli_to_srv, fd_info_srv_to_cli; fd_cmd_cli_to_srv = open(fifo_name_cmd_cli_to_srv, O_RDONLY); read_from_fifo(fd_cmd_cli_to_srv, &client_pid_string); client_pid = atoi(client_pid_string); read_from_fifo(fd_cmd_cli_to_srv, &command); //recebe commando /CONNECT read_from_fifo(fd_cmd_cli_to_srv, &fifo_name_info_srv_to_cli); //recebe nome de fifo INFO_SRV_TO_CLIXXX read_from_fifo(fd_cmd_cli_to_srv, &fifo_name_msg_srv_to_cli); //recebe nome de fifo MSG_TO_SRV_TO_CLIXXX //CIRA FIFO MSG_CLIXXX_TO_SRV char fifo_name_msg_cli_to_srv[FIFO_NAME_MAX_LEN]; strcpy(fifo_name_msg_cli_to_srv, FIFO_DIR); strcat(fifo_name_msg_cli_to_srv, "lrc_msg_cli"); strcat(fifo_name_msg_cli_to_srv, client_pid_string); strcat(fifo_name_msg_cli_to_srv, "_to_srv"); n = mkfifo(fifo_name_msg_cli_to_srv, 0660); if (n < 0) { fprintf(stderr, "error creating %s\n", fifo_name_msg_cli_to_srv); fprintf(stderr, "errno: %d\n", errno); exit(5); } //envia ao cliente a resposta ao commando /CONNECT fd_info_srv_to_cli = open(fifo_name_info_srv_to_cli, O_WRONLY); write_to_fifo(fd_info_srv_to_cli, fifo_name_msg_cli_to_srv); free(logfile); free(fifo_name_cmd_cli_to_srv); close(fd_cmd_cli_to_srv); unlink(fifo_name_cmd_cli_to_srv); unlink(fifo_name_msg_cli_to_srv); unlink(fifo_name_msg_srv_to_cli); unlink(fifo_name_info_srv_to_cli); printf("fim\n"); return 0; } client.c: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> #include <errno.h> #define MAX_INPUT_LENGTH 100 #define PID_BUFFER_LEN 10 #define FIFO_NAME_CMD_CLI_TO_SRV "lrc_cmd_cli_to_srv" #define FIFO_NAME_INFO_SRV_TO_CLI "lrc_info_srv_to_cli" #define FIFO_NAME_MSG_SRV_TO_CLI "lrc_msg_srv_to_cli" #define COMMAND_MAX_LEN 100 #define FIFO_DIR "/tmp/" typedef enum { false, true } bool; char* nickname; char* name; char* email; void write_to_fifo(int fd, char* data) { int n_bytes = (strlen(data)+1) * sizeof(char); write(fd, &n_bytes, sizeof(int)); //primeiro envia o numero de bytes que a proxima instrucao write ira enviar write(fd, data, n_bytes); printf("writing %d bytes '%s'\n", n_bytes, data); } void read_from_fifo(int fd, char** var) { int n_bytes; read(fd, &n_bytes, sizeof(int)); *var = (char *) malloc (n_bytes); printf("read '%s'\n", *var); read(fd, *var, n_bytes); } int main(int argc, char* argv[]) { pid_t pid = getpid(); //CRIA FIFO INFO_SRV_TO_CLIXXX char pid_string[PID_BUFFER_LEN]; sprintf(pid_string, "%d", pid); char* fifo_name_info_srv_to_cli; fifo_name_info_srv_to_cli = (char *) malloc ( (strlen(FIFO_DIR) + strlen(FIFO_NAME_INFO_SRV_TO_CLI) + strlen(pid_string) + 1 ) * sizeof(char) ); strcpy(fifo_name_info_srv_to_cli, FIFO_DIR); strcat(fifo_name_info_srv_to_cli, FIFO_NAME_INFO_SRV_TO_CLI); strcat(fifo_name_info_srv_to_cli, pid_string); int n = mkfifo(fifo_name_info_srv_to_cli, 0660); if (n < 0) { fprintf(stderr, "error creating %s\n", fifo_name_info_srv_to_cli); fprintf(stderr, "errno: %d\n", errno); exit(6); } int fd_cmd_cli_to_srv, fd_info_srv_to_cli; fd_cmd_cli_to_srv = open("/tmp/lrc_cmd_cli_to_srv", O_WRONLY); char command[COMMAND_MAX_LEN]; printf("> "); scanf("%s", command); while (strcmp(command, "/CONNECT")) { printf("O primeiro comando deverá ser \"/CONNECT\"\n"); printf("> "); scanf("%s", command); } //CRIA FIFO MSG_SRV_TO_CLIXXX char* fifo_name_msg_srv_to_cli; fifo_name_msg_srv_to_cli = (char *) malloc ( (strlen(FIFO_DIR) + strlen(FIFO_NAME_MSG_SRV_TO_CLI) + strlen(pid_string) + 1) * sizeof(char) ); strcpy(fifo_name_msg_srv_to_cli, FIFO_DIR); strcat(fifo_name_msg_srv_to_cli, FIFO_NAME_MSG_SRV_TO_CLI); strcat(fifo_name_msg_srv_to_cli, pid_string); n = mkfifo(fifo_name_msg_srv_to_cli, 0660); if (n < 0) { fprintf(stderr, "error creating %s\n", fifo_name_info_srv_to_cli); fprintf(stderr, "errno: %d\n", errno); exit(7); } // ENVIA COMANDO /CONNECT write_to_fifo(fd_cmd_cli_to_srv, pid_string); //envia pid do processo cliente write_to_fifo(fd_cmd_cli_to_srv, command); //envia commando /CONNECT write_to_fifo(fd_cmd_cli_to_srv, fifo_name_info_srv_to_cli); //envia nome de fifo INFO_SRV_TO_CLIXXX write_to_fifo(fd_cmd_cli_to_srv, fifo_name_msg_srv_to_cli); //envia nome de fifo MSG_TO_SRV_TO_CLIXXX // recebe do servidor a resposta ao comanddo /CONNECT printf("msg1\n"); printf("vamos tentar abrir %s\n", fifo_name_info_srv_to_cli); fd_info_srv_to_cli = open(fifo_name_info_srv_to_cli, O_RDONLY); printf("%s aberto", fifo_name_info_srv_to_cli); if (fd_info_srv_to_cli < 0) { fprintf(stderr, "erro ao criar %s\n", fifo_name_info_srv_to_cli); fprintf(stderr, "errno: %d\n", errno); } printf("msg2\n"); char* fifo_name_msg_cli_to_srv; printf("msg3\n"); read_from_fifo(fd_info_srv_to_cli, &fifo_name_msg_cli_to_srv); printf("msg4\n"); free(nickname); free(name); free(email); free(fifo_name_info_srv_to_cli); free(fifo_name_msg_srv_to_cli); unlink(fifo_name_msg_srv_to_cli); unlink(fifo_name_info_srv_to_cli); printf("fim\n"); return 0; } makefile: CC = gcc CFLAGS = -Wall -lpthread -fno-stack-protector all: client server client: client.c $(CC) $(CFLAGS) client.c -o client server: server.c $(CC) $(CFLAGS) server.c -o server clean: rm -f client server *~

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• Parallel port with C#

  - by Michael S.

  Hello, I am trying to send data to LPT1 port with a C# program, unfortunately with no success.. I am using windows 7 x64. I tried both x86 and x64 (inpoutx64.dll) dll's.. With the x64 dll when I send: Output(888, 255); It just continues the program as everything went ok, but i can't see anything on my multimeter (only the static 0.02V).. I also tried the following with C++: int main () { int val = 0; printf("Enter a value\n"); scanf("%d", &val); _outp(0x378, val); getchar(); _outp(0x378, 0); return 0; } But it throws an exception: Unhandled exception at 0x01281428 in ppac.exe: 0xC0000096: Privileged instruction. I remember once I made something like this work on xp, I hope it's possible on win7 too.. Please help me with this. Thanks.

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• Link List Problem,

  - by david

  OK i have a problem with a Link List program i'm trying to Do, the link List is working fine. Here is my code #include <iostream> using namespace std; struct record { string word; struct record * link; }; typedef struct record node; node * insert_Node( node * head, node * previous, string key ); node * search( node *head, string key, int *found); void displayList(node *head); node * delete_node( node *head, node * previous, string key); int main() { node * previous, * head = NULL; int found = 0; string node1Data,newNodeData, nextData,lastData; //set up first node cout <<"Depature"<<endl; cin >>node1Data; previous = search( head, node1Data, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, node1Data); cout <<"Depature inserted"<<endl; //insert node between first node and head cout <<"Destination"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Destinationinserted"<<endl; //insert node between second node and head cout <<"Cost"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Cost inserted"<<endl; cout <<"Number of Seats Required"<<endl; //place node between new node and first node cin >>nextData; previous = search( head, nextData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, nextData); cout <<"Number of Seats Required inserted"<<endl; //insert node between first node and head cout <<"Name"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Name inserted"<<endl; //insert node between node and head cout <<"Address "<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Address inserted"<<endl; //place node as very last node cin >>lastData; previous = search( head, lastData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, lastData); cout <<"C"<<endl; displayList(head); char Ans = 'y'; //Delete nodes do { cout <<"Enter Keyword to be delete"<<endl; cin >>nextData; previous = search( head, nextData, &found); if (found == 1) head = delete_node( head, previous,nextData); displayList(head); cout <<"Do you want to Delete more y /n "<<endl; cin >> Ans; } while( Ans =='y'); int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); } /******************************************************* search function to return previous position of node ******************************************************/ node * search( node *head, string key, int *found) { node * previous, * current; current = head; previous = current; *found = 0;//not found //if (current->word < key) move through links until the next link //matches or current_word > key while( current !=NULL) { //compare exactly if (key ==current->word ) { *found = 1; break; } //if key is less than word else if ( key < current->word ) break; else { //previous stays one link behind current previous = current; current = previous -> link; } } return previous; } /******************************************************** display function as used with createList ******************************************************/ void displayList(node *head) { node * current; //current now contains the address held of the 1st node similar //to head current = head; cout << "\n\n"; if( current ==NULL) cout << "Empty List\n\n"; else { /*Keep going displaying the contents of the list and set current to the address of the next node. When set to null, there are no more nodes */ while(current !=NULL) { cout << current->word<<endl; current = current ->link; } } } /************************************************************ insert node used to position node (i) empty list head = NULL (ii) to position node before the first node key < head->word (iii) every other position including the end of the list This is done using the following steps (a) Pass in all the details to create the node either details or a whole record (b) Pass the details over to fill the node (C) Use the if statement to add the node to the list **********************************************************/ node * insert_Node( node * head, node * previous, string key ) { node * new_node, * temp; new_node = new node; //create the node new_node ->word = key; new_node -> link = NULL; if (head == NULL || key < head->word ) //empty list { //give address of head to temp temp = head; //head now points to the new_node head = new_node; //new_node now points to what head was pointing at new_node -> link = temp; } else { //pass address held in link to temp temp = previous-> link; //put address of new node to link of previous previous -> link = new_node; //pass address of temp to link of new node new_node -> link = temp; } return head; } node * delete_node( node *head, node * previous, string key) { /* this function will delete a node but will not return its contents */ node * temp; if(key == head->word) //delete node at head of list { temp = head; //point head at the next node head = head -> link; } else { //holds the address of the node after the one // to be deleted temp = previous-> link; /*assign the previous to the address of the present node to be deleted which holds the address of the next node */ previous-> link = previous-> link-> link; } delete temp; return head; }//end delete The problem i have is when i Enter in the Number 2 in the Node(Seats) i like to get a Counter Taken 2 off of 50, some thing like what i have here enter code here int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); How can i get what the User enters into number of Seats into this function

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• How to write a C program using the fork() system call that generates the Fibonacci sequence in the

  - by Ellen

  The problem I am having is that when say for instance the user enters 7, then the display shows: 0 11 2 3 5 8 13 21 child ends. I cannot seem to figure out how to fix the 11 and why is it displaying that many numbers in the sequence! Can anyone help? The number of the sequence will be provided in the command line. For example, if 5 is provided, the first five numbers in the Fibonacci sequence will be output by the child process. Because the parent and child processes have their own copies of the data, it will be necessary for the child to output the sequence. Have the parent invoke the wait() call to wait for the child process to complete before exiting the program. Perform necessary error checking to ensure that a non-negative number is passed on the command line. #include <stdio.h> #include <sys/types.h> #include <unistd.h> int main() { int a=0, b=1, n=a+b,i,ii; pid_t pid; printf("Enter the number of a Fibonacci Sequence:\n"); scanf("%d", &ii); if (ii < 0) printf("Please enter a non-negative integer!\n"); else { pid = fork(); if (pid == 0) { printf("Child is producing the Fibonacci Sequence...\n"); printf("%d %d",a,b); for (i=0;i<ii;i++) { n=a+b; printf("%d ", n); a=b; b=n; } printf("Child ends\n"); } else { printf("Parent is waiting for child to complete...\n"); wait(NULL); printf("Parent ends\n"); } } return 0; }

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• Making a switch statement in C with an array?

  - by Eric

  I am trying to make a switch statement that takes in a word into an array and then throws each letter through a switch statement and allocates a point to each letter depending on which letter it is and giving a final point value for the word, and I can't seem to get the array part right. Any help would be appreciated! int main(){ int letter_points = 0; char word[7]; int word_length = 7; int i; printf("Enter a Word\n"); scanf("%s", word); for(i = 0; i < word_length; i++){ switch(word){ //1 point case 'A': case 'E': case 'I': case 'L': case 'N': case 'O': case 'R': case 'S': case 'T': case 'U': letter_points++; break; //2 points case 'D': case 'G': letter_points += 2; break; //3 points case 'B': case 'C': case 'M': case 'P': letter_points += 3; break; //4 points case 'F': case 'H': case 'V': case 'W': case 'Y': letter_points += 4; break; //5 points case 'K': letter_points += 5; break; //8 points case 'J': case 'X': letter_points += 8; break; //10 points case 'Q': case 'Z': letter_points += 10; break; } } printf("%d\n", letter_points); return; }

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• Code Explanation (MPICH)

  - by user243680

  #include "mpi.h" #include <stdio.h> #include <math.h> double f(double a) { return (4.0 / (1.0 + a*a)); } void main(int argc, char *argv[]) { int done = 0, n, myid, numprocs,i; double PI25DT = 3.141592653589793238462643; double mypi, pi, h, sum, x; double startwtime, endwtime; int namelen; char processor_name[MPI_MAX_PROCESSOR_NAME]; MPI_Init(&argc,&argv); MPI_Comm_size(MPI_COMM_WORLD,&numprocs); MPI_Comm_rank(MPI_COMM_WORLD,&myid); MPI_Get_processor_name(processor_name,&namelen); fprintf(stderr,"Process %d on %s\n", myid, processor_name); fflush(stderr); n = 0; while (!done) { if (myid == 0) { printf("Enter the number of intervals: (0 quits) ");fflush(stdout); scanf("%d",&n); startwtime = MPI_Wtime(); } MPI_Bcast(&n, 1, MPI_INT, 0, MPI_COMM_WORLD); if (n == 0) done = 1; else { h = 1.0 / (double) n; sum = 0.0; for (i = myid + 1; i <= n; i += numprocs) { x = h * ((double)i - 0.5); sum += f(x); } mypi = h * sum; MPI_Reduce(&mypi, &pi, 1, MPI_DOUBLE, MPI_SUM, 0, MPI_COMM_WORLD); if (myid == 0) { printf("pi is approximately %.16f, Error is %.16f\n", pi, fabs(pi - PI25DT)); endwtime = MPI_Wtime(); printf("wall clock time = %f\n", endwtime-startwtime); } } } MPI_Finalize(); } Can anyone explain me the above code what it does??I am in lab and my miss has asked me to explain and i dont know what it is.please help

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• Can you tell me why this generates time limit exceeded in spoj(Prime Number Generator)

  - by magiix

  #include<iostream> #include<string.h> #include<math.h> using namespace std; bool prime[1000000500]; void generate(long long end) { memset(prime,true,sizeof(prime)); prime[0]=false; prime[1]=false; for(long long i=0;i<=sqrt(end);i++) { if(prime[i]==true) { for(long long y=i*i;y<=end;y+=i) { prime[y]=false; } } } } int main() { int n; long long b,e; scanf("%d",&n); while(n--) { cin>>b>>e; generate(e); for(int i=b;i<e;i++) { if(prime[i]) printf("%d\n",i); } } return 0; } That's my code for spoj prime generator. Altought it generates the same output as another accepted code ..

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• Pipe overwrites buffer, don't know how to overcome

  - by Kalec

  I use a simple pipe. I read with a while, 1 char at a time, I think every time I read a char I overwrite something #include <unistd.h> #include <stdio.h> #include <stdlib.h> #include <sys/wait.h> #include <string.h> int main () { int pipefd[2]; int cpid; char buf[31]; if (pipe(pipefd) == -1) { perror("pipe"); exit(EXIT_FAILURE) } cpid = fork(); if (cpid == -1) P perror("cpid"); exit(EXIT_FAILURE); } if (cpid == 0) { // child reads from pipe close (pipefd[1]); // close unused write end while (read (pipefd[0], &buf, 1)>0); printf ("Server receives: %s", buf); close (pipefd[0])l exit (EXIT_SUCCESS); } else { // parent writes to pipe close (pipefd[0]); // closing unused read end; char buf2[30]; printf("Server transmits: "); scanf ("%s", buf2); write (pipefd[1], buf2, strlen(buf2)+1); close(pipefd[1]); wait(NULL); exit(EXIT_SUCCESS); } return 0; } For example, if I input: "Flowers" it prints F and then ~6 unprintable characters

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• What do these C operators mean?

  - by Melkhiah66

  I'm reading the book "Programming Challenges: The Programming Contest Training Manual" and are implementing a problem where I do not understand the use of operators c1 and the comparison if (n&1), someone could help me to know they mean? this is the example code #include <stdio.h> #define MAX_N 300 #define MAX_D 150 long cache[MAX_N/2][2]; void make_cache(int n,int d,int mode) { long tmp[MAX_D]; int i,count; for(i=0;i<MAX_D;i++) tmp[i]=0; tmp[0]=1;count=0; while(count<=n) { count++; for(i=(count&1);i<=d;i+=2) { if(i) tmp[i] = tmp[i-1] + tmp[i+1]; else if(!mode) tmp[0]=tmp[1]; else tmp[0]=0; } if((count&1)==(d&1)) cache[count>>1][mode]=tmp[d]; } } int main() { int n,d,i; long sum; while(1) { scanf("%d %d",&n,&d); if(n&1) sum=0; else if(d==1) sum=1; else if(n<(d<<1)) sum=0; else if(n==(d<<1)) sum=1; else { make_cache(n,d,0); make_cache(n,d,1); sum=0; for(i=0;i<=(n>>1);i++) sum+=cache[i][0]*cache[(n>>1)-i][1]; } printf("%ld\n",sum); } return 0; }

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• calculating min and max of 2-D array in c

  - by m2010

  This program to calculate sum,min and max of array elements Max value is the problem, it is always not true. void main(void) { int degree[3][2]; int min_max[][]; int Max=min_max[0][0]; int Min=min_max[0][0]; int i,j; int sum=0; clrscr(); for(i=0;i<3;i++) { for(j=0;j<2;j++) { printf("\n enter degree of student no. %d in subject %d:",i+1,j+1); scanf("%d",&degree[i][j]); } } for(i=0;i<3;i++) { for(j=0;j<2;j++) { printf("\n Student no. %d degree in subject no. %d is %d",i+1,j+1,degree[i][j]); } } for(i=0;i<3;i++) { sum=0; for(j=0;j<2;j++) { sum+=degree[i][j]; } printf("\n sum of degrees of student no. %d is %d",i+1,sum); min_max[i][j]=sum; if(min_max[i][j] <Min) { Min=min_max[i][j]; } else if(min_max[i][j]>Max) { Max=min_max[i][j]; } } printf("\nThe minimum sum of degrees of student no. %d is %d",i,Min); printf("\nThe maximum sum of degrees of student no. %d is %d",i,Max); getch(); }

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• Problem when reading input in C

  - by gcx

  I've made a Linked List. Its elements keep both previous and next items' address. It gets commands from an input file. It detects the command and uses the following statement as a parameter. (text: add_to_front john - means: add_to_front(john)) Code: http://pastebin.com/KcAm1y3L When I try to give the commands from an input file it gives me same output over and over. However, if I write inputs in main() manually, it works. For ex input file: add_to_front john add_to_back jane add_to_back jane print (unfortunately) the output is: >add_to_front john >add_to_back jane >add_to_back jane >print jane jane jane Although, if I write add_to_front(john); add_to_back(jane); add_to_back(jane); print(); instead of this command check: while (scanf("%s",command)!=EOF) { if (strcmp(command,"add_to_front")==0) { gets(parameter); add_to_front(parameter); } else if (strcmp(command,"add_to_back")==0) { gets(parameter); add_to_back(parameter); } else if (strcmp(command,"remove_from_back")==0) remove_from_back(parameter); ... printf(" HUH?\n"); } } in main() it gives the correct output. I know it's a lot to ask but this thing is bothering me for 2 days. What do you think i'm doing wrong?

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• C dynamic memory allocation for table of structs

  - by JosiP

  Hi here is my code. I want to dynamincly change no of elemnts in table with structs __state: typedef struct __state{ long int timestamp; int val; int prev_value; }*state_p, state_t; int main(int argc, char **argv){ int zm; int previous_state = 0; int state = 0; int i = 0; int j; state_p st; //here i want to have 20 structs st. st = (state_p) malloc(sizeof(state_t) * 20); while(1){ previous_state = state; scanf("%d", &state); printf("%d, %d\n", state, previous_state); if (previous_state != state){ printf("state changed %d %d\n", previous_state, state); // here i got compile error: main.c: In function ‘main’: main.c:30: error: incompatible type for argument 1 of ‘save_state’ main.c:34: error: invalid type argument of ‘->’ main.c:34: error: invalid type argument of ‘->’ save_state(st[i],previous_state, state); } i++; } return 0; } I suppose i have to change that st[i] to smth like st+ptr ? where pointer is incermeting in each loop iteration ? Or am I wrong ? When i change code: initialization into state_p st[20] and in each loop iteration i put st[i] = (state_p)malloc(sizeof(state_t)) everything works fine, but i want to dynammicly change number of elemets in that table. Thx in advance for any help

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• error in finding out the lexems and no of lines of a text file in C

  - by mekasperasky

  #include<stdio.h> #include<ctype.h> #include<string.h> int main() { int i=0,j,k,lines_count[2]={1,1},operand_count[2]={0},operator_count[2]={0},uoperator_count[2]={0},control_count[2]={0,0},cl[13]={0},variable_dec[2]={0,0},l,p[2]={0},ct,variable_used[2]={0,0},constant_count[2],s[2]={0},t[2]={0}; char a,b[100],c[100]; char d[100]={0}; j=30; FILE *fp1[2],*fp2; fp1[0]=fopen("program1.txt","r"); fp1[1]=fopen("program2.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("ccv1ouput.txt","wb"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1[0]==NULL) { perror("failed to open program1.txt"); //return EXIT_FAILURE; } if(fp1[1]==NULL) { perror("failed to open program2.txt"); //return EXIT_FAILURE; } i=0; k=0; ct=0; while(ct!=2) { while(!feof(fp1[ct])) { a=fgetc(fp1[ct]); if(a!=' '&&a!='\n') { if (!isalpha(a) && !isdigit(a)) { switch(a) { case '+':{ i=0; cl[0]=1; operator_count[ct]=operator_count[ct]+1;break;} case '-':{ cl[1]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '*':{ cl[2]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '/':{ cl[3]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '=':{a=fgetc(fp1[ct]); if (a=='='){cl[4]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1;} else { cl[5]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '%':{ cl[6]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '<':{ a=fgetc(fp1[ct]); if (a=='=') {cl[7]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[8]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break; } case '>':{ ; a=fgetc(fp1[ct]); if (a=='='){cl[9]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[10]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '&':{ cl[11]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '|':{ cl[12]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '#':{ while(a!='\n') { a=fgetc(fp1[ct]); } } } } else { d[i]=a; i=i+1; k=k+1; } } else { //printf("%s \n",d); if((strcmp(d,"if")==0)){ memset ( d, 0, 100 ); i=0; control_count[ct]=control_count[ct]+1; } else if(strcmp(d,"then")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"else")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"while")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"int")==0){ while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"char")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"float")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"printf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100); } else if(strcmp(d,"scanf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100);} else if (isdigit(d[i-1])) { memset ( d, 0, 100 ); i=0; constant_count[ct]=constant_count[ct]+1; operand_count[ct]=operand_count[ct]+1; } else if (isalpha(d[i-1]) && strcmp(d,"int")!=0 && strcmp(d,"char")!=0 && strcmp(d,"float")!=0 && (strcmp(d,"if")!=0) && strcmp(d,"then")!=0 && strcmp(d,"else")!=0 && strcmp(d,"while")!=0 && strcmp(d,"printf")!=0 && strcmp(d,"scanf")!=0) { memset ( d, 0, 100 ); i=0; operand_count[ct]=operand_count[ct]+1; } else if(a=='\n') { lines_count[ct]=lines_count[ct]+1; memset ( d, 0, 100 ); } } } fclose(fp1[ct]); operand_count[ct]=operand_count[ct]-5; variable_used[0]=operand_count[0]-constant_count[0]; variable_used[1]=operand_count[1]-constant_count[1]; for(j=0;j<12;j++) uoperator_count[ct]=uoperator_count[ct]+cl[j]; fprintf(fp2,"\n statistics of program %d",ct+1); fprintf(fp2,"\n the no of lines ---> %d",lines_count[ct]); fprintf(fp2,"\n the no of operands --->%d",operand_count[ct]); fprintf(fp2,"\n the no of operator --->%d",operator_count[ct]); fprintf(fp2,"\n the no of control statments --->%d",control_count[ct]); fprintf(fp2,"\n the no of unique operators --->%d",uoperator_count[ct]); fprintf(fp2,"\n the no of variables declared--->%d",variable_dec[ct]); fprintf(fp2,"\n the no of variables used--->%d",variable_used[ct]); fprintf(fp2,"\n ---------------------------------"); fprintf(fp2,"\n \t \t \t"); ct=ct+1; } t[0]=lines_count[0]+control_count[0]+uoperator_count[0]; t[1]=lines_count[1]+control_count[1]+uoperator_count[1]; s[0]=operator_count[0]+operand_count[0]+variable_dec[0]+variable_used[0]; s[1]=operator_count[1]+operand_count[1]+variable_dec[1]+variable_used[1]; fprintf(fp2,"\n the time complexity of program 1 is %d",t[0]); fprintf(fp2,"\n the time complexity of program 2 is %d",t[1]); fprintf(fp2,"\n the space complexity of program 1 is %d",s[0]); fprintf(fp2,"\n the space complexity of program 2 is %d",s[1]); if((t[0]>t[1]) && (s[0] >s[1])) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if(t[0]<t[1] && s[0] < s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2 " ); else if (t[0]+s[0] > t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2"); else if (t[0]+s[0] < t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if (t[0]+s[0] == t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is equal to that of program 2"); fclose(fp2); return 0; } this code basically compares two c codes and finds out the no. of variables declared , used , no. of control statements , no. of lines and no. of unique operators , and operands , so as to find out the time complexity and space complexity of of the two programs given in the text file program1.txt and program2.txt ... Lets say program1.txt is this #include<stdio.h> #include<math.h> int main () { FILE *fp; fp=fopen("output.txt","w"); long double t,y=0,x=0,e=5,f=1,w=1; for (t=0;t<10;t=t+0.01) { //if (isnan(y) || isinf(y)) //break; fprintf(fp,"%ld\t%ld\n",y,x); y = y + ((e*(1 - (x*x))*y) - x + f*cos(w*0.1))*0.1; x = x + y*0.1; } fclose(fp); return (0); } i havent indented it as its just a text file . But my output is totally faulty . Its not able to find the any of the ouput that i need . Where is the bug in this ? I am not able to figure out as the algorithm looks fine .

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• select failing with C program but not shell

  - by Gary

  So I have a parent and child process, and the parent can read output from the child and send to the input of the child. So far, everything has been working fine with shell scripts, testing commands which input and output data. I just tested with a simple C program and couldn't get it to work. Here's the C program: #include <stdio.h> int main( void ) { char stuff[80]; printf("Enter some stuff:\n"); scanf("%s", stuff); return 0; } The problem with with the C program is that my select fails to read from the child fd and hence the program cannot finish. Here's the bit that does the select.. //wait till child is ready fd_set set; struct timeval timeout; FD_ZERO( &set ); // initialize fd set FD_SET( PARENT_READ, &set ); // add child in to set timeout.tv_sec = 3; timeout.tv_usec = 0; int r = select(FD_SETSIZE, &set, NULL, NULL, &timeout); if( r < 1 ) { // we didn't get any input exit(1); } Does anyone have any idea why this would happen with the C program and not a shell one? Thanks!

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• I am trying to find how many vowels and consonants in my string in C

  - by John Walter

  #include <stdio.h> #include <string.h> int main() { int i; int counter=0, counter2=0; char *s; char name[30]; char vowel[6] = "AEIOU"; char consonants[21] = "BCDFGHJKLMNPQRSTVWXYZ"; printf ("input the string: "); scanf ("%s", name); printf ("The string is %s\n", name); for (i=0; name[i]!='\0'; i++) { if (s = strchr(vowel, name[i])) { counter++; } else if (s =strchr(consonants, name[i])) { counter2++; } printf ("First counter is %d\n", counter); printf ("The second counter is %d\n", counter2); return 0; } } And the question is, what is wrong with my code? why counter is not working? Because I tried a lot of ways, and nothing works, maybe someone can explain for me.

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• Segmentation fault in C recursive Combination (nCr)

  - by AruniRC

  PLease help me out here. The program is supposed to recursively find out the combination of two numbers. nCr = n!/ (r!(n-r)! ). I'm getting this error message when i compile it on GCC. Here's what the terminal shows: Enter two numbers: 8 4 Segmentation fault (Program exited with code:139) The code is given here: #include<stdio.h> float nCr(float, float, float); int main() { float a, b, c; printf("Enter two numbers: \n"); scanf("%f%f", &a, &b); c = nCr(a, b, a-b); printf("\n%.3f", c); return 0; } float nCr(float n, float r, float p) { if(n<1) return (1/(p*r))*(nCr(1, r-1, p-1)); if(r<1) return (n/(p*1))*(nCr(n-1, 1, p-1)); if(p<1) return (n/r)*(nCr(n-1, r-1, 1)); return ( n/(p*r) )*nCr(n-1, r-1, p-1); }

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• Structure's with strings and input

  - by Beginnernato

  so i have the following structure and function that add's things to the function - struct scoreentry_node { struct scoreentry_node *next; int score; char* name; } ; typedef struct scoreentry_node *score_entry; score_entry add(int in, char* n, score_entry en) { score_entry r = malloc(sizeof(struct scoreentry_node)); r->score = in; r->name = n; r->next = en; return r; } i have input that take it in the following main file: int score; char name[]; int main(void) { score_entry readin = NULL; while(1) { scanf("%s%d", name, &score); readin = add(score, name, readin); // blah blah I dont know why but when input a name it gets added to readin, but when i input another name all the name's in readin have this new name for example: input: bob 10 readin = 10 bob NULL jill 20 readin = 20 jill 10 jill NULL I dont know why bob disappear's... any reason why it does that ?

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• Basic C programming question

  - by Amit

  Hi all, I've just started to learn C and it's going pretty slow...I wanted to write a program that takes in an integer argument and returns it's doubled value (aka take in integer, multiply by 2, and printf that value). I purposely did not want to use the scanf function. Here's what I have so far and what is not compiling... #include <stdio.h> int main(int index) { if (!(index)) { printf("No index given"); return 1; } a = index*2; printf("Mult by 2 %d",a); return 0; } So basically when the program is executed I want to supply the index integer. So, in cygwin, I would write something like ./a 10 and 10 would be stored into the index variable. Also, I want to program to return "No index given" and exit if no index value was supplied... Anyone care to help what I'm doing wrong? EDIT: This code returns 1 error upon compilation and is based on the help by @James: #include <stdio.h> int main(int 1, char index) { int index, a; if (!(index)) { printf("No index given"); return 1; } a = index*2; printf("Mult by 2 %d",a); return 0; } Thanks! Amit

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• Segmentation fault on certain inputs and not others

  - by Brandon Schwandt

  Heres a function I wrote that has some debugging elements in it already. When i enter either a "y" or a "Y" as the input I get a segmentation fault during runtime. When I enter any other value the code runs. The seg fault kicks out after it scans and gives me the response but before the "scan worked" line is output. DOn't know why it would act like this only on these values. If anyone needs the function call I have that as well. query_user(char *response [10]) { printf("response after query call before clear=%s\n",response); strcpy(response,""); printf("response after clearing before scan=%s\n",response); printf("Enter another person into the line? y or n\n"); scanf("%s", response); printf("response after scan=%s\n",response); printf("scan worked"); } main() { char response [10]; strcpy(response,"y"); printf("response=%s\n",response); printf("When finished with program type \"done\" to exit\n"); while (strcmp(response,"done") != 0) { printf("response after while loop and before query call=%s\n",response); query_user(&response); } } output on error: response after query call before clear=y response after clearing before scan= Enter another person into the line? y or n y response after scan=y Segmentation Fault (core dumped) output on non-error: response after query call before clear=y response after clearing before scan= Enter another person into the line? y or n n response after scan=n scan worked Cycle number 0 (program continues to run outside this function)

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• BASIC Menu-driven program repeates twice after successful completion of first task.

  - by Zazu

  Hello, Im using Plato3 to write C programs. Im creating a menu-driven program but want to test out the basic concept of getting it to work #include<stdio.h> #include<ctype.h> int function1(); main(){ char s; do{ puts("\n choose the following"); puts("(P)rint\n"); puts("(Q)uit\n"); scanf("%c",&s); s=toupper(s); switch (s){ case 'P' : function1(); break; case 'Q' : return -1; break; } }while (function1()==0); } int function1(){ printf("Hello World"); return 0; } The problem is that once function1() returns the value 0, the whole program is echoed ... why ? Example : Running the program gives this : Hello WorldHellow World choose the following (P)rint (Q)uit Hello World choose the following (P)rint (Q)uit -- Any idea why ? Please help, thanks !!!!

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