Search Results

Search found 11188 results on 448 pages for 'variable'.

Page 9/448 | < Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >

  • Have loaded a php variable into flash but cant apply it in a function...

    - by Paul Elliot
    hi I have created an actionscript function which stops an animation on a specific frame which works fine. I have then loaded in a php file with a variable which will contain the number for the frame i want the animation to stop on. This has loaded in fine and i have loaded it in a function. what i cant seem to do is to get the variable into the function which tells the animation to stop playing. here is my code: //load variables varReceiver = new LoadVars(); // create an object to store the variables varReceiver.load("http://playground.nsdesign6.net/percentage/external.php"); //load variables //function1 varReceiver.onLoad = function() { //value is the var that is created. var paul = this.percentage; } //function1 //function2 this.onEnterFrame = function() { if(this._currentframe==(percentage)) { this.stop(); this.onEnterFrame = undefined; } } play(); //function2 cheers paul

    Read the article

  • In C++, what is the "order of precedence" for shadowed variable names?

    - by Emile Cormier
    In C++, what is the "order of precedence" for shadowed variable names? I can't seem to find a concise answer online. For example: #include <iostream> int shadowed = 1; struct Foo { Foo() : shadowed(2) {} void bar(int shadowed = 3) { std::cout << shadowed << std::endl; // What does this output? } int shadowed; }; int main() { Foo().bar(); } I can't think of any other scopes where a variable might conflict. Please let me know if I missed one.

    Read the article

  • Is it a good idea to define a variable in a local block for a case of a switch statement?

    - by Paperflyer
    I have a rather long switch-case statement. Some of the cases are really short and trivial. A few are longer and need some variables that are never used anywhere else, like this: switch (action) { case kSimpleAction: // Do something simple break; case kComplexAction: { int specialVariable = 5; // Do something complex with specialVariable } break; } The alternative would be to declare that variable before going into the switch like this: int specialVariable = 5; switch (action) { case kSimpleAction: // Do something simple break; case kComplexAction: // Do something complex with specialVariable break; } This can get rather confusing since it is not clear to which case the variable belongs and it uses some unnecessary memory. However, I have never seen this usage anywhere else. Do you think it is a good idea to declare variables locally in a block for a single case?

    Read the article

  • Is it bad practice to initialize a variable to a dummy value?

    - by froadie
    This question is a result of the answers to this question that I just asked. It was claimed that this code is "ugly" because it initializes a variable to a value that will never be read: String tempName = null; try{ tempName = buildFileName(); } catch(Exception e){ ... System.exit(1); } FILE_NAME = tempName; Is this indeed bad practice? Should one avoid initializing variables to dummy values that will never actually be used? (EDIT - And what about initializing a String variable to "" before a loop that will concatenate values to the String...? Or is this in a separate category? e.g. String whatever = ""; for(String str : someCollection){ whatever += str; } )

    Read the article

  • Who knows the value of global variables in the qt qtscript script to access the global variable to change the global variable value; [closed]

    - by dawntrees
    Who knows the value of global variables in the qt qtscript script to access the global variable to change the global variable value; forexample int gVar=0; int main(int argc, char *argv[]) { QScriptEngine engine; QScriptValue varValue = m_engine-newVariant(gVar); engine.globalObject().setProperty("gVar", varValue); QScriptValue result = m_engine->evaluate("gVar=100;"); qDebug()<<"gVar================"<<gVar; return 0; } Why gVar = 0 and not equal to 100; how can we make gVar equal to 100(gVar=100) Who can help group I appreciate it, thanks!

    Read the article

  • Inherit one instance variable from the global scope

    - by Julian
    I'm using Curses to create a command line GUI with Ruby. Everything's going well, but I have hit a slight snag. I don't think Curses knowledge (esoteric to be fair) is required to answer this question, just Ruby concepts such as objects and inheritance. I'm going to explain my problem now, but if I'm banging on, just look at the example below. Basically, every Window instance needs to have .close called on it in order to close it. Some Window instances have other Windows associated with it. When closing a Window instance, I want to be able to close all of the other Window instances associated with it at the same time. Because associated Windows are generated in a logical fashion, (I append the name with a number: instance_variable_set(self + integer, Window.new(10,10,10,10)) ), it's easy to target generated windows, because methods can anticipate what assosiated windows will be called, (I can recreate the instance variable name from scratch, and almost query it: instance_variable_get(self + integer). I have a delete method that handles this. If the delete method is just a normal, global method (called like this: delete_window(@win543) then everything works perfectly. However, if the delete method is an instance method, which it needs to be in-order to use the self keyword, it doesn't work for a very clear reason; it can 'query' the correct instance variable perfectly well (instance_variable_get(self + integer)), however, because it's an instance method, the global instances aren't scoped to it! Now, one way around this would obviously be to simply make a global method like this: delete_window(@win543). But I have attributes associated with my window instances, and it all works very elegantly. This is very simplified, but it literally translates the problem exactly: class Dog def speak woof end end def woof if @dog_generic == nil puts "@dog_generic isn't scoped when .woof is called from a class method!\n" else puts "@dog_generic is scoped when .woof is called from the global scope. See:\n" + @dog_generic end end @dog_generic = "Woof!" lassie = Dog.new lassie.speak #=> @dog_generic isn't scoped when .woof is called from an instance method!\n woof #=> @dog_generic is scoped when .woof is called from the global scope. See:\nWoof! TL/DR: I need lassie.speak to return this string: "@dog_generic is scoped when .woof is called from the global scope. See:\nWoof!" @dog_generic must remain as an insance variable. The use of Globals or Constants is not acceptable. Could woof inherit from the Global scope? Maybe some sort of keyword: def woof < global # This 'code' is just to conceptualise what I want to do, don't take offence! end Is there some way the .woof method could 'pull in' @dog_generic from the global scope? Will @dog_generic have to be passed in as a parameter?

    Read the article

  • Compare a variable that can have numeric or string as value

    - by Tarun
    I have a variable named Seconds_Behind_Master from one of my scripts. The problem is that this variable can either have a numeric value or can also take a string NULL as its value. Now, when I try to execute this script in shell it gets executed but gives a warning like this: [: Illegal number: NULL I believe it is due to the fact that in this case the value is NULL but when it compares it with numeral value 60 it gives this warning. How can I rectify it? Here is the piece of code: Seconds_Behind_Master=$Show_Slave_Status | grep "Seconds_Behind_Master" | awk -F": " {' print $2 '} if [ "$Seconds_Behind_Master" -ge "60" ]; then echo "replication delayed greater than or equal to 60." else if [ "$Seconds_Behind_Master" = "NULL" ]; then echo "Delay is Null." fi fi

    Read the article

  • Creating a new variable versus assigning an existing one

    - by rwallace
    Which is more common, creating a new variable versus assigning an existing variable (field, array element etc - anything that syntactically uses the assignment operator)? The reason I ask is that I'm designing a new language, and wondering which of these two operations should get the shorter syntax. It's not intended to be a pure functional language, or the question wouldn't arise, so I'd ideally like to count usage across large existing code bases in procedural and object-oriented languages like C, C++ and Java, though as far as I can see there isn't an easy way to do this automatically, and going by memory and eyeball, neither is obviously more common than the other.

    Read the article

  • how to read the password from variable?

    - by Viswa
    I am trying to move my file to another system which is located in some other place, with this command: rsync -avrz src destination It works fine. But what I need is to put this command in shell script and run it like: #! /bin/sh rsync -avrz srcfilelocation destination When it runs, it asks for the destination system password. I know that password and give it manually. Now I have decided to assign the password to an environment variable, like pswd="destination system password". I need my shell script to read the password from this variable. How can I write a script to do this?

    Read the article

  • Global variable in a Linux shared library

    - by user3730495
    Suppose we have the following setup under Linux, .so library named "libcnt.so" and 3 user space apps: "app1", "app2", "app3". This library does 1 simple thing, it says to the app (app dynamically links the library at runtime) by how many apps it is already linked. Apps should have access to link counter. My knowledge in C and Linux is somewhat limited in this aspect, but as I understand this information should be stored in a global variable inside the shared object. Something like: in libcnt.h extern int cnt_loads; in libcnt.c int cnt_loads = 0; // where each linking increments this counter or something... So, my question is how it should be declared and/or defined inside .so library to guaranty that multiple apps from user space get the same instance of that variable counter?

    Read the article

  • In C++, what is the scope resolution ("order of precedence") for shadowed variable names?

    - by Emile Cormier
    In C++, what is the scope resolution ("order of precedence") for shadowed variable names? I can't seem to find a concise answer online. For example: #include <iostream> int shadowed = 1; struct Foo { Foo() : shadowed(2) {} void bar(int shadowed = 3) { std::cout << shadowed << std::endl; // What does this output? { int shadowed = 4; std::cout << shadowed << std::endl; // What does this output? } } int shadowed; }; int main() { Foo().bar(); } I can't think of any other scopes where a variable might conflict. Please let me know if I missed one. What is the order of priority for all four shadow variables when inside the bar member function?

    Read the article

  • PHP - How do you secure a unique variable name?

    - by 102319141763223461745
    This function cropit, which I shamelessly stole off the internet, crops a 90x60 area from an existing image. In this code, when I use the function for more than one item (image) the one will display on top of the other (they come to occupy the same output space). I think this is because the function has the same (static) name ($dest) for the destination of the image when it's created (imagecopy). I tried, as you can see to include a second argument to the cropit function which would serve as the "name" of the $dest variable, but it didn't work. In the interest of full disclosure I have 22 hours of PHP experience (incidentally the same number of hours since the last I slept) and I am not that smart to begin with. Even if there's something else at work here entirely, seems to me that generally it must be useful to have a way to secure that a variable is always given a unique name. function cropit($srcimg, $dest) { $im = imagecreatefromjpeg($srcimg); $img_width = imagesx($im); $img_height = imagesy($im); $width = 90; $height = 60; $tlx = floor($img_width / 2) - floor ($width / 2); $tly = floor($img_height / 2) - floor ($height / 2); if ($tlx < 0) { $tlx = 0; } if ($tly < 0) { $tly = 0; } if (($img_width - $tlx) < $width) { $width = $img_width - $tlx; } if (($img_height - $tly) < $height) { $height = $img_height - $tly; } $dest = imagecreatetruecolor ($width, $height); imagecopy($dest, $im, 0, 0, $tlx, $tly, $width, $height); imagejpeg($dest); imagedestroy($dest); } $img = "imagefolder\imageone.jpg"; $img2 = "imagefolder\imagetwo.jpg"; cropit($img, $i1); cropit($img2, $i2); ?

    Read the article

  • Assigning a 2D array (of pointers) to a variable in an object for access in C++?

    - by MrMormon
    I'm sorry if I didn't pick a descriptive or concise name. A lot of questions sound similar, but I haven't been able to find what I'm looking for. What I want to do is store a 2D array of pointers somewhere and assign a variable in some object to that array to be able to access it. Here's some example code that has the same compile error I'm getting with a bigger project. #include <iostream> using namespace std; struct X{ float * b[8][8]; X(){ *(b[1][5]) = 1; cout << *(b[1][5]) << endl; } void Set(float * c[8][8]){ b = c; cout << *(b[1][5]) << endl; } }; main(){ float * a[8][8]; *(a[1][5]) = 2; X obj; obj.Set(a); } What I want to happen in this code is that an X object starts with its own 2D array, whose value pointed to by b[1][5] should be printed as "1". Then the main method's 2D array, a, is passed to the object's Set() method and assigned to its array variable. The value pointed to by b[1][5] should then be printed as "2". However, I can't figure out what type the Set() parameter, c, should be. I get error: incompatible types in assignment of ‘float* (*)[8]’ to ‘float* [8][8]’ when I try to compile. As for why I want to do this, I'm trying to use an array of pointers to objects, not floats, but it's the same error.

    Read the article

  • Why doesn't my environment variable get set?

    - by reprogrammer
    I have to set an environment variable called GDK_NATIVE_WINDOWS to fix the problem with Eclipse buttons in Ubuntu. To set the environment variable, I added the following line to ~/.pam_environment. GDK_NATIVE_WINDOWS DEFAULT=true Surprisingly, the environment variable doesn't get set when I echo $GDK_NATIVE_WINDOWS in a terminal. However, all other environment variables that I've listed in ~/.pam_environment are set properly. Besides, when I switch to a tty, e.g. Alt+Ctrl+F1, the environment variable gets set correctly. Can anyone tell what's wrong with setting this environment variable in ~/.pam_environment?

    Read the article

  • Caching of path environment variable on windows?

    - by jwir3
    I'm assisting one of our testers in troubleshooting a configuration problem on a Windows XP SP3 system. Our application uses an environment variable, called APP_HOME, to refer to the directory where our application is installed. When the application is installed, we utilize the following environment variables: APP_HOME = C:\application\ PATH = %PATH%;%APP_HOME%bin Now, the problem comes in that she's working with multiple versions of the same application. So, in order to switch between version 7.0 and 8.1, for example, she might use: APP_HOME = C:\application_7.0\ (for 7.0) and then change it to: APP_HOME = C:\application_8.1\ (for 8.1) The problem is that once this change is made, the PATH environment variable apparently still is looking at the old expansion of the APP_HOME variable. So, for example, after she has changed APP_HOME, PATH still refers to the 7.0 bin directory. Any thoughts on why this might be happening? It looks to me like the PATH variable is caching the expansion of the APP_HOME environment variable. Is there any way to turn this behavior off?

    Read the article

  • Why doesn't my environment variable get set?

    - by reprogrammer
    I have to set an environment variable called GDK_NATIVE_WINDOWS to fix the problem with Eclipse buttons in Ubuntu. To set the environment variable, I added the following line to ~/.pam_environment. GDK_NATIVE_WINDOWS DEFAULT=true Surprisingly, the environment variable doesn't get set when I echo $GDK_NATIVE_WINDOWS in a terminal. However, all other environment variables that I've listed in ~/.pam_environment are set properly. Besides, when I switch to a tty, e.g. Alt+Ctrl+F1, the environment variable gets set correctly. Can anyone tell what's wrong with setting this environment variable in ~/.pam_environment?

    Read the article

  • flex debugger (how to retrieve a session variable set by a browser)

    - by Rees
    hello, i'm creating a flex application and trying to debug using the "Network Monitor" view. The script i'm debugging fetches a PHP session variable (the PHP outputs xml) and the actionscript retrieves the value from the HTTPService event. if I am using say a chrome browser, i can correctly retrieve the session variable ANY TIME. if I switch to say a firefox browser, then clearly the chrome session variable is unavailable to firefox. My issue is that I create the session variable with say chrome, and then try to retrieve my session variable from my FLEX application debugger (which always returns null) -when I really want it to return my session variable. is there a way for my flex debugger to retrieve this session variable set by chrome (or any browser)? (I'm even using chrome as my debugging browser for flex)

    Read the article

  • What's the scope of a Python variable declared in an if statement?

    - by froadie
    I'm new to Python, so this is probably a simple scoping question. The following code in a Python file (module) is confusing me slightly: if __name__ == '__main__': x = 1 print x In other languages I've worked in, this code would throw an exception, as the x variable is local to the if statement and should not exist outside of it. But this code executes, and prints 1. Can anyone explain this behavior? Are all variables declared in a module global/available to the entire module?

    Read the article

  • What exactly is a variable in C++?

    - by FredOverflow
    The standard says A variable is introduced by the declaration of an object. The variable's name denotes the object. But what does this definition actually mean? Does a variable give a name to an object, i.e. are variables just a naming mechanism for otherwise anonymous objects? Or is a variable the name itself? Or is a variable a named object in the sense that every variable is also an object? Or is a variable just a "proxy" with a name that "delegates" all operations to the real object? To confuse things further, many C++ books seem to treat variables and objects as synonyms. What is your take on this?

    Read the article

< Previous Page | 5 6 7 8 9 10 11 12 13 14 15 16  | Next Page >