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  • SharePoint 2010 – SQL Server has an unsupported version 10.0.2531.0

    - by Jeff Widmer
    I am trying to perform a database attach upgrade to SharePoint Foundation 2010. At this point I am trying to attach the content database to a Web application by using Windows Powershell: Mount-SPContentDatabase -Name <DatabaseName> -DatabaseServer <ServerName> -WebApplication <URL> [-Updateuserexperience] I am following the directions from this TechNet article: Attach databases and upgrade to SharePoint Foundation 2010.  When I go to mount the content database I am receiving this error: Mount-SPContentDatabase : Could not connect to [DATABASE_SERVER] using integrated security: SQL server at [DATABASE_SERVER] has an unsupported version 10.0.2531.0. Please refer to “http://go.microsoft.com/fwlink/?LinkId=165761” for information on the minimum required SQL Server versions and how to download them. At first this did not make sense because the default SharePoint Foundation 2010 website was running just fine.  But then I realized that the default SharePoint Foundation site runs off of SQL Server Express and that I had just installed SQL Server Web Edition (since the database is greater than 4GB) and restored the database to this version of SQL Server. Checking the documentation link above I see that SharePoint Server 2010 requires a 64-bit edition of SQL Server with the minimum required SQL Server versions as follows: SQL Server 2008 Express Edition Service Pack 1, version number 10.0.2531 SQL Server 2005 Service Pack 3 cumulative update package 3, version number 9.00.4220.00 SQL Server 2008 Service Pack 1 cumulative update package 2, version number 10.00.2714.00 The version of SQL Server 2008 Web Edition with Service Pack 1 (the version I installed on this machine) is 10.0.2531.0. SELECT @@VERSION: Microsoft SQL Server 2008 (SP1) - 10.0.2531.0 (X64)   Mar 29 2009 10:11:52   Copyright (c) 1988-2008 Microsoft Corporation  Web Edition (64-bit) on Windows NT 6.1 <X64> (Build 7600: ) (VM) But I had to read the article several times since the minimum version number for SQL Server Express is 10.0.2531.0.  At first I thought I was good with the version of SQL Server 2008 Web that I had installed, also 10.0.2531.0.  But then I read further to see that there is a cumulative update (hotfix) for SQL Server 2008 SP1 (NOT the Express edition) that is required for SharePoint 2010 and will bump the version number to 10.0.2714.00. So the solution was to install the Cumulative update package 2 for SQL Server 2008 Service Pack 1 on my SQL Server 2008 Web Edition to allow SharePoint 2010 to work with SQL Server 2008 (other than the SQL Server 2008 Express version). SELECT @@VERSION (After installing Cumulative update package 2): Microsoft SQL Server 2008 (SP1) - 10.0.2714.0 (X64)   May 14 2009 16:08:52   Copyright (c) 1988-2008 Microsoft Corporation  Web Edition (64-bit) on Windows NT 6.1 <X64> (Build 7600: ) (VM)

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  • How to configure a longer version Number in artifactory

    - by claudine
    The version-numbers for our jars have to be longer them x.x.x. We would rather need x.x.x.x to integrate some old-fashioned self-made mechanism. This is, because we tag our software with x.x.x and as soon as we have a delivery to a customer one specific jar has to be build exactly at this point of time to fit to another backend, which communicates with our program. For that reason this one jar has the version 2.3.4.1, when generated and in next delivery of the same Version it is build and named 2.3.4.2. Now artifactory cannot handle this an doesn't save more than x.x.x.2 in some cases. So we thought of maybe edit the regular expression in the maven repository layout (see attached Screenshot) Because testing the path in the field below shows, that it cannot handle the version number. Of course for the rest of our jars still x.x.x has to work.. For Example here is the maven-metadata.xml <?xml version="1.0" encoding="UTF-8"?> <metadata> <groupId>com.firm</groupId> <artifactId>someid</artifactId> <version>1.5.1</version> <versioning> <latest>1.5.1</latest> <release>1.5.1</release> <versions> <version>1.4.62</version> </versions> <lastUpdated>20120926073942</lastUpdated> </versioning> </metadata> The folder structure looks like: someid 1.4.62 1.4.62.1 1.4.62.2 1.4.62.3 If we deploy an new artifact version (1.4.62.1), the maven-metadata.xml contains the 1.4.62.1 version. But the artifactory overrides the version number (1.4.62.x) to (1.4.62) after an unspecified time. It seems that the artifactory only support major, minor and revision numbers, and deletes the buildnumber. Now we looking for a solution do disable this behavior. We use the JFrog Artifactory version 2.5.0 (rev. 13086). Any ideas, maybe? Thanks in andvance

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  • Script to rebuild git history, applying code cleanup to every version

    - by rjmunro
    Has anyone got a script for git that can go through the history, check out each version, apply a cleanup script, then check the cleaned version into another repository? I have some code which I've been developing, but I haven't been consistent with code formatting e.g. tabs vs spaces etc. I'd like to rewrite my entire history to be consistent with the new standards.

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  • Get current Apache version string for display

    - by Stijn Sanders
    I'm writing an Apache module and want to get a string with the Apache name version and other details. Much like what gets added to outgoing headers, e.g.: Server: Apache/2.2.13 (Win32) I've tried code like this: apr_table_get(request_rec->headers_out,"Server") But that doesn't seem to work. Is there an API call I haven't found or am I doomed to get version resource data from httpd.exe?

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  • HSSFS Part 2.1 - Parsing @@VERSION

    - by Most Valuable Yak (Rob Volk)
    For Part 2 of the Handy SQL Server Function Series I decided to tackle parsing useful information from the @@VERSION function, because I am an idiot.  It turns out I was confused about CHARINDEX() vs. PATINDEX() and it pretty much invalidated my original solution.  All is not lost though, this mistake turned out to be informative for me, and hopefully for you. Referring back to the "Version" view in the prelude I started with the following query to extract the version number: SELECT DISTINCT SQLVersion, SUBSTRING(VersionString,PATINDEX('%-%',VersionString)+2, 12) VerNum FROM VERSION I used PATINDEX() to find the first hyphen "-" character in the string, since the version number appears 2 positions after it, and got these results: SQLVersion VerNum ----------- ------------ 2000 8.00.2055 (I 2005 9.00.3080.00 2005 9.00.4053.00 2008 10.50.1600.1 As you can see it was good enough for most of the values, but not for the SQL 2000 @@VERSION.  You'll notice it has only 3 version sections/octets where the others have 4, and the SUBSTRING() grabbed the non-numeric characters after.  To properly parse the version number will require a non-fixed value for the 3rd parameter of SUBSTRING(), which is the number of characters to extract. The best value is the position of the first space to occur after the version number (VN), the trick is to figure out how to find it.  Here's where my confusion about PATINDEX() came about.  The CHARINDEX() function has a handy optional 3rd parameter: CHARINDEX (expression1 ,expression2 [ ,start_location ] ) While PATINDEX(): PATINDEX ('%pattern%',expression ) Does not.  I had expected to use PATINDEX() to start searching for a space AFTER the position of the VN, but it doesn't work that way.  Since there are plenty of spaces before the VN, I thought I'd try PATINDEX() on another character that doesn't appear before, and tried "(": SELECT SQLVersion, SUBSTRING(VersionString,PATINDEX('%-%',VersionString)+2, PATINDEX('%(%',VersionString)) FROM VERSION Unfortunately this messes up the length calculation and yields: SQLVersion VerNum ----------- --------------------------- 2000 8.00.2055 (Intel X86) Dec 16 2008 19:4 2005 9.00.3080.00 (Intel X86) Sep 6 2009 01: 2005 9.00.4053.00 (Intel X86) May 26 2009 14: 2008 10.50.1600.1 (Intel X86) Apr 2008 10.50.1600.1 (X64) Apr 2 20 Yuck.  The problem is that PATINDEX() returns position, and SUBSTRING() needs length, so I have to subtract the VN starting position: SELECT SQLVersion, SUBSTRING(VersionString,PATINDEX('%-%',VersionString)+2, PATINDEX('%(%',VersionString)-PATINDEX('%-%',VersionString)) VerNum FROM VERSION And the results are: SQLVersion VerNum ----------- -------------------------------------------------------- 2000 8.00.2055 (I 2005 9.00.4053.00 (I Msg 537, Level 16, State 2, Line 1 Invalid length parameter passed to the LEFT or SUBSTRING function. Ummmm, whoops.  Turns out SQL Server 2008 R2 includes "(RTM)" before the VN, and that causes the length to turn negative. So now that that blew up, I started to think about matching digit and dot (.) patterns.  Sadly, a quick look at the first set of results will quickly scuttle that idea, since different versions have different digit patterns and lengths. At this point (which took far longer than I wanted) I decided to cut my losses and redo the query using CHARINDEX(), which I'll cover in Part 2.2.  So to do a little post-mortem on this technique: PATINDEX() doesn't have the flexibility to match the digit pattern of the version number; PATINDEX() doesn't have a "start" parameter like CHARINDEX(), that allows us to skip over parts of the string; The SUBSTRING() expression is getting pretty complicated for this relatively simple task! This doesn't mean that PATINDEX() isn't useful, it's just not a good fit for this particular problem.  I'll include a version in the next post that extracts the version number properly. UPDATE: Sorry if you saw the unformatted version of this earlier, I'm on a quest to find blog software that ACTUALLY WORKS.

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  • Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variabl

    - by Thomas
    Hi, I'm working with PHP PDO and I have the following problem: Warning: PDOStatement::execute(): SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens in /var/www/site/classes/enterprise.php on line 63 Here is my code: public function getCompaniesByCity(City $city, $options = null) { $database = Connection::getConnection(); if(empty($options)) { $statement = $database-prepare("SELECT * FROM empresas WHERE empresas.cidades_codigo = ?"); $statement-bindValue(1, $city-getId()); } else { $sql = "SELECT * FROM empresas INNER JOIN prods_empresas ON prods_empresas.empresas_codigo = empresas.codigo WHERE "; foreach($options as $option) { $sql .= 'prods_empresas.produtos_codigo = ? OR '; } $sql = substr($sql, 0, -4); $sql .= ' AND empresas.cidades_codigo = ?'; $statement = $database-prepare($sql); echo $sql; foreach($options as $i = $option) { $statement-bindValue($i + 1, $option-getId()); } $statement-bindValue(count($options), $city-getId()); } $statement-execute(); $objects = $statement-fetchAll(PDO::FETCH_OBJ); $companies = array(); if(!empty($objects)) { foreach($objects as $object) { $data = array( 'id' = $object-codigo, 'name' = $object-nome, 'link' = $object-link, 'email' = $object-email, 'details' = $object-detalhes, 'logo' = $object-logo ); $enterprise = new Enterprise($data); array_push($companies, $enterprise); } return $companies; } } Thank you very much!

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  • How to get element order number

    - by martin-masiar
    Hello everyone, how can i get order number of some element by javascript/jquery? <ul> <li>Anton</li> <li class="abc">Victor</li> <li class="abc">Simon</li> <li>Adam</li> <li>Peter</li> <li class="abc">Tom</li> </ul> There is 3xli with abc class. Now I need to get order(sequence) number of Simon li. Thanks in advance

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  • T-SQL - Left Outer Joins - Filters in the where clause versus the on clause.

    - by Greg Potter
    I am trying to compare two tables to find rows in each table that is not in the other. Table 1 has a groupby column to create 2 sets of data within table one. groupby number ----------- ----------- 1 1 1 2 2 1 2 2 2 4 Table 2 has only one column. number ----------- 1 3 4 So Table 1 has the values 1,2,4 in group 2 and Table 2 has the values 1,3,4. I expect the following result when joining for Group 2: `Table 1 LEFT OUTER Join Table 2` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL `Table 2 LEFT OUTER Join Table 1` T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 The only way I can get this to work is if I put a where clause for the first join: PRINT 'Table 1 LEFT OUTER Join Table 2, with WHERE clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL and a filter in the ON for the second: PRINT 'Table 2 LEFT OUTER Join Table 1, with ON clause' select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Can anyone come up with a way of not using the filter in the on clause but in the where clause? The context of this is I have a staging area in a database and I want to identify new records and records that have been deleted. The groupby field is the equivalent of a batchid for an extract and I am comparing the latest extract in a temp table to a the batch from yesterday stored in a partioneds table, which also has all the previously extracted batches as well. Code to create table 1 and 2: create table table1 (number int, groupby int) create table table2 (number int) insert into table1 (number, groupby) values (1, 1) insert into table1 (number, groupby) values (2, 1) insert into table1 (number, groupby) values (1, 2) insert into table2 (number) values (1) insert into table1 (number, groupby) values (2, 2) insert into table2 (number) values (3) insert into table1 (number, groupby) values (4, 2) insert into table2 (number) values (4) EDIT: A bit more context - depending on where I put the filter I different results. As stated above the where clause gives me the correct result in one state and the ON in the other. I am looking for a consistent way of doing this. Where - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number --****************************** WHERE table1.groupby = 2 AND table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 2 2 NULL On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table1 LEFT OUTER join table2 --****************************** on table1.number = table2.number AND table1.groupby = 2 --****************************** WHERE table2.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- 1 1 NULL 2 2 NULL 1 2 NULL Where (table 2 this time) - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number AND table1.groupby = 2 --****************************** WHERE table1.number IS NULL Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- NULL NULL 3 On - select table1.groupby as [T1_Groupby], table1.number as [T1_Number], table2.number as [T2_Number] from table2 LEFT OUTER join table1 --****************************** on table2.number = table1.number --****************************** WHERE table1.number IS NULL AND table1.groupby = 2 Result: T1_Groupby T1_Number T2_Number ----------- ----------- ----------- (0) rows returned

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  • PHP - Math - Round Number Function

    - by aSeptik
    Hi All guys! this time i have a math question for you! Assuming we have three numbers one is the Number of Votes the second is the Total Values and the last is the Units Ratings. units_ratings can be a number from 1 to 10; if ( total_values / units_ratings != number_of_votes ) { //do something for let the "number_of_votes" fit the division! } I ask this to you, cause i want know the best (fastest) way of achieve this! Thanks!

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  • What's the best version control/QA workflow for a legacy system?

    - by John Cromartie
    I am struggling to find a good balance with our development and testing process. We use Git right now, and I am convinced that ReinH's Git Workflow For Agile Teams is not just great for capital-A Agile, but for pretty much any team on DVCS. That's what I've tried to implement but it's just not catching. We have a large legacy system with a complex environment, hundreds of outstanding and undiscovered defects, and no real good way to set up a test environment with realistic data. It's also hard to release updates without disrupting users. Most of all, it's hard to do thorough QA with this process... and we need thorough testing with this legacy system. I feel like we can't really pull off anything as slick as the Git workflow outlined in the link. What's the way to do it?

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  • Noob Droid Question regarding random number

    - by Pete Herbert Penito
    Brand new to droid programming, but would love to learn as much as possible, so I finally got my emulator working correctly, I even got a hello world button to work, I'm attempting to make this button display a random number, I've googled this and came up with this code: Random generator = new Random(); int n = generator.nextInt(n); I fixed the Random function by including some Random java utility. I'm assuming this code above goes in the .java file of the project, so my button code looks as follows (tested and works): PopUpText.makeText(v.getContext(), "Hello World", PopUpText.LENGTH_LONG).show(); I figured I could replace "Hello World" with n to display the number in the box, however the following error is stopping the compile: The local variable n may not have been initialized Any ideas why this is happening? Any advice would be hugely appreciated.

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  • What libgdx project files can I ignore from version control?

    - by Zhen
    In an automatically created libgdx project, what files can I safely tell Git (or other revision control systems) to ignore? I'm considering these: *-android/.settings/ *-android/bin/ *-desktop/.settings/ *-desktop/bin/ *-html/.settings/ *-html/gwt-unitCache/ *-html/war/WEB-INF/classes/ *-html/war/WEB-INF/deploy/ *-html/war/assets/ *-html/war/ */.settings/ */bin/ Am I missing some? Is there a complete list somewhere?

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  • Is there a version control system that can show changes to a specific method or function?

    - by chesles
    Sometimes it would be nice to be able to say something like: (git|svn|hg|etc) diff Foo.c:main (git|svn|hg|etc) log log Foo.c:main to see the changes made to a specific function within a source file since the last commit, or the complete history of changes. My question is two-fold: Does something exist that does this? Would such a tool be practical? It would have to do some simple parsing of the code at each revision in order to compare different versions of the function; would the overhead be too much for it to be efficient?

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  • How do professional application developers use version control systems, like GIT and Subversion?

    - by Wolfi
    I am a beginner developer and I have been wondering from the start, how do professional use tools like GIT and Subversion (I don't have a very good understanding about these tools), to fulfill their project's needs. If they do use it, how would I set up something like that? My applications are not so large and I am not working in a team yet, would they be of huge help to me? There are questions on this site about how to use the tools, but I need beginner support.

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  • Fastest method to define whether a number is a triangular number

    - by psihodelia
    A triangular number is the sum of the n natural numbers from 1 to n. What is the fastest method to find whether a given positive integer number is a triangular one? I suppose, there must be a hidden pattern in a binary representation of such numbers (like if you need to find whether a number is even/odd you check its least significant bit). Here is a cut of the first 1200th up to 1300th triangular numbers, you can easily see a bit-pattern here (if not, try to zoom out): (720600, '10101111111011011000') (721801, '10110000001110001001') (723003, '10110000100000111011') (724206, '10110000110011101110') (725410, '10110001000110100010') (726615, '10110001011001010111') (727821, '10110001101100001101') (729028, '10110001111111000100') (730236, '10110010010001111100') (731445, '10110010100100110101') (732655, '10110010110111101111') (733866, '10110011001010101010') (735078, '10110011011101100110') (736291, '10110011110000100011') (737505, '10110100000011100001') (738720, '10110100010110100000') (739936, '10110100101001100000') (741153, '10110100111100100001') (742371, '10110101001111100011') (743590, '10110101100010100110') (744810, '10110101110101101010') (746031, '10110110001000101111') (747253, '10110110011011110101') (748476, '10110110101110111100') (749700, '10110111000010000100') (750925, '10110111010101001101') (752151, '10110111101000010111') (753378, '10110111111011100010') (754606, '10111000001110101110') (755835, '10111000100001111011') (757065, '10111000110101001001') (758296, '10111001001000011000') (759528, '10111001011011101000') (760761, '10111001101110111001') (761995, '10111010000010001011') (763230, '10111010010101011110') (764466, '10111010101000110010') (765703, '10111010111100000111') (766941, '10111011001111011101') (768180, '10111011100010110100') (769420, '10111011110110001100') (770661, '10111100001001100101') (771903, '10111100011100111111') (773146, '10111100110000011010') (774390, '10111101000011110110') (775635, '10111101010111010011') (776881, '10111101101010110001') (778128, '10111101111110010000') (779376, '10111110010001110000') (780625, '10111110100101010001') (781875, '10111110111000110011') (783126, '10111111001100010110') (784378, '10111111011111111010') (785631, '10111111110011011111') (786885, '11000000000111000101') (788140, '11000000011010101100') (789396, '11000000101110010100') (790653, '11000001000001111101') (791911, '11000001010101100111') (793170, '11000001101001010010') (794430, '11000001111100111110') (795691, '11000010010000101011') (796953, '11000010100100011001') (798216, '11000010111000001000') (799480, '11000011001011111000') (800745, '11000011011111101001') (802011, '11000011110011011011') (803278, '11000100000111001110') (804546, '11000100011011000010') (805815, '11000100101110110111') (807085, '11000101000010101101') (808356, '11000101010110100100') (809628, '11000101101010011100') (810901, '11000101111110010101') (812175, '11000110010010001111') (813450, '11000110100110001010') (814726, '11000110111010000110') (816003, '11000111001110000011') (817281, '11000111100010000001') (818560, '11000111110110000000') (819840, '11001000001010000000') (821121, '11001000011110000001') (822403, '11001000110010000011') (823686, '11001001000110000110') (824970, '11001001011010001010') (826255, '11001001101110001111') (827541, '11001010000010010101') (828828, '11001010010110011100') (830116, '11001010101010100100') (831405, '11001010111110101101') (832695, '11001011010010110111') (833986, '11001011100111000010') (835278, '11001011111011001110') (836571, '11001100001111011011') (837865, '11001100100011101001') (839160, '11001100110111111000') (840456, '11001101001100001000') (841753, '11001101100000011001') (843051, '11001101110100101011') (844350, '11001110001000111110') For example, can you also see a rotated normal distribution curve, represented by zeros between 807085 and 831405?

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  • Version control a content management system?

    - by Mike
    I have the following directory structure in the CMS application we have written: /application /modules /cms /filemanager /block /pages /sitemap /youtube /rss /skin /backend /default /css /js /images /frontend /default /css /js /images Application contains code specific to the current CMS implementation, i.e code for this specific cms. Modules contain reusable portions of code that we share across projects, such as libraries to work with youtube or rss feeds. We include these as git submodules, so that we can update the module in any website and push the changes back across all other projects. It makes it really easy to apply a change to our code and distribute it. We wanted to turn the CMS into a module so we get the same benefit - we can run the entire project under source control, then update the cms as required through a git-submodule. We have run into a problem however: the cms requires javascript/images/css in order for it to work correctly. Things we have thought about: We could create 2 submodules, one for cms-skin and one for cms, but this means you cannot "git pull" one version without having some idea of which versions of skin work with which versions of cms. i.e version 1.2.2 CMS might have issues with 1.0.3 CMS-Skin We could add the skin to the cms module but this has the following problems: Skin should be available on the document root, module code shouldn't be, and if it is it should probably be secured via .htaccess It doesn't seem to make any sense bundling assets with php code We could create a symlink between /skin/backend/ to go to /modules/cms/skin but does this cause any security problems, and do we want to require something like a symlink for the application to work? We could create a hook for git or a shell script that copies files from modules/cms/skin to skin/backend when an update occurs, but this means we lose the ability to edit CMS core files in a project then push them back How is this typically done in large scale cms's? How is it possible to get the source code for a cms under version control, work on the application for a client, then update the sourcecode as releases and given by the vendor? How do applications like Magento or Drupal do this?

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  • Fastest way to pad a number in Java to a certain number of digits

    - by Martin
    Am trying to create a well-optimised bit of code to create number of X-digits in length (where X is read from a runtime properties file), based on a DB-generated sequence number (Y), which is then used a folder-name when saving a file. I've come up with three ideas so far, the fastest of which is the last one, but I'd appreciate any advice people may have on this... 1) Instantiate a StringBuilder with initial capacity X. Append Y. While length < X, insert a zero at pos zero. 2) Instantiate a StringBuilder with initial capacity X. While length < X, append a zero. Create a DecimalFormat based on StringBuilder value, and then format the number when it's needed. 3) Create a new int of Math.pow( 10, X ) and add Y. Use String.valueOf() on the new number and then substring(1) it. The second one can obviously be split into outside-loop and inside-loop sections. So, any tips? Using a for-loop of 10,000 iterations, I'm getting similar timings from the first two, and the third method is approximately ten-times faster. Does this seem correct? Full test-method code below... // Setup test variables int numDigits = 9; int testNumber = 724; int numIterations = 10000; String folderHolder = null; DecimalFormat outputFormat = new DecimalFormat( "#,##0" ); // StringBuilder test long before = System.nanoTime(); for ( int i = 0; i < numIterations; i++ ) { StringBuilder sb = new StringBuilder( numDigits ); sb.append( testNumber ); while ( sb.length() < numDigits ) { sb.insert( 0, 0 ); } folderHolder = sb.toString(); } long after = System.nanoTime(); System.out.println( "01: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" ); // DecimalFormat test before = System.nanoTime(); StringBuilder sb = new StringBuilder( numDigits ); while ( sb.length() < numDigits ) { sb.append( 0 ); } DecimalFormat formatter = new DecimalFormat( sb.toString() ); for ( int i = 0; i < numIterations; i++ ) { folderHolder = formatter.format( testNumber ); } after = System.nanoTime(); System.out.println( "02: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" ); // Substring test before = System.nanoTime(); int baseNum = (int)Math.pow( 10, numDigits ); for ( int i = 0; i < numIterations; i++ ) { int newNum = baseNum + testNumber; folderHolder = String.valueOf( newNum ).substring( 1 ); } after = System.nanoTime(); System.out.println( "03: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" );

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  • Calculate the number of ways to roll a certain number

    - by helloworld
    I'm a high school Computer Science student, and today I was given a problem to: Program Description: There is a belief among dice players that in throwing three dice a ten is easier to get than a nine. Can you write a program that proves or disproves this belief? Have the computer compute all the possible ways three dice can be thrown: 1 + 1 + 1, 1 + 1 + 2, 1 + 1 + 3, etc. Add up each of these possibilities and see how many give nine as the result and how many give ten. If more give ten, then the belief is proven. I quickly worked out a brute force solution, as such int sum,tens,nines; tens=nines=0; for(int i=1;i<=6;i++){ for(int j=1;j<=6;j++){ for(int k=1;k<=6;k++){ sum=i+j+k; //Ternary operators are fun! tens+=((sum==10)?1:0); nines+=((sum==9)?1:0); } } } System.out.println("There are "+tens+" ways to roll a 10"); System.out.println("There are "+nines+" ways to roll a 9"); Which works just fine, and a brute force solution is what the teacher wanted us to do. However, it doesn't scale, and I am trying to find a way to make an algorithm that can calculate the number of ways to roll n dice to get a specific number. Therefore, I started generating the number of ways to get each sum with n dice. With 1 die, there is obviously 1 solution for each. I then calculated, through brute force, the combinations with 2 and 3 dice. These are for two: There are 1 ways to roll a 2 There are 2 ways to roll a 3 There are 3 ways to roll a 4 There are 4 ways to roll a 5 There are 5 ways to roll a 6 There are 6 ways to roll a 7 There are 5 ways to roll a 8 There are 4 ways to roll a 9 There are 3 ways to roll a 10 There are 2 ways to roll a 11 There are 1 ways to roll a 12 Which looks straightforward enough; it can be calculated with a simple linear absolute value function. But then things start getting trickier. With 3: There are 1 ways to roll a 3 There are 3 ways to roll a 4 There are 6 ways to roll a 5 There are 10 ways to roll a 6 There are 15 ways to roll a 7 There are 21 ways to roll a 8 There are 25 ways to roll a 9 There are 27 ways to roll a 10 There are 27 ways to roll a 11 There are 25 ways to roll a 12 There are 21 ways to roll a 13 There are 15 ways to roll a 14 There are 10 ways to roll a 15 There are 6 ways to roll a 16 There are 3 ways to roll a 17 There are 1 ways to roll a 18 So I look at that, and I think: Cool, Triangular numbers! However, then I notice those pesky 25s and 27s. So it's obviously not triangular numbers, but still some polynomial expansion, since it's symmetric. So I take to Google, and I come across this page that goes into some detail about how to do this with math. It is fairly easy(albeit long) to find this using repeated derivatives or expansion, but it would be much harder to program that for me. I didn't quite understand the second and third answers, since I have never encountered that notation or those concepts in my math studies before. Could someone please explain how I could write a program to do this, or explain the solutions given on that page, for my own understanding of combinatorics? EDIT: I'm looking for a mathematical way to solve this, that gives an exact theoretical number, not by simulating dice

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  • Row Number Transformation

    The Row Number Transformation calculates a row number for each row, and adds this as a new output column to the data flow. The column number is a sequential number, based on a seed value. Each row receives the next number in the sequence, based on the defined increment value. Develop seamlessly between Management Studio and Visual StudioSQL Connect is a Visual Studio add-in that makes it easy to keep your database and Visual Studio project in sync.

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  • how to version minder for web application data

    - by dankyy1
    hi all;I'm devoloping a web application which renders data from DB and also updates datas with editor UI Pages.So i want to implement a versioning mechanism for render pages got data over db again if only data on db updated by editor pages.. I decided to use Session objects for the version information that client had taken latestly.And the Application object that the latest DB version of objects ,i used the data objects guid as key for each data item client version holder class like below ItemRunnigVersionInformation class holds currentitem guid and last loadtime from DB public class ClientVersionManager { public static List<ItemRunnigVersionInformation> SessionItemRunnigVersionInformation { get { if (HttpContext.Current.Session["SessionItemRunnigVersionInformation"] == null) HttpContext.Current.Session["SessionItemRunnigVersionInformation"] = new List<ItemRunnigVersionInformation>(); return (List<ItemRunnigVersionInformation>)HttpContext.Current.Session["SessionItemRunnigVersionInformation"]; } set { HttpContext.Current.Session["SessionItemRunnigVersionInformation"] = value; } } /// <summary> /// this will be updated when editor pages /// </summary> /// <param name="itemRunnigVersionInformation"></param> public static void UpdateItemRunnigSessionVersion(string itemGuid) { ItemRunnigVersionInformation itemRunnigVersionAtAppDomain = PlayListVersionManager.GetItemRunnigVersionInformationByID(itemGuid); ItemRunnigVersionInformation itemRunnigVersionInformationAtSession = SessionItemRunnigVersionInformation.FirstOrDefault(t => t.ItemGuid == itemGuid); if ((itemRunnigVersionInformationAtSession == null) && (itemRunnigVersionAtAppDomain != null)) { ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(SessionItemRunnigVersionInformation, itemRunnigVersionAtAppDomain); } else if (itemRunnigVersionAtAppDomain != null) { ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Remove(SessionItemRunnigVersionInformation, itemRunnigVersionInformationAtSession); ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(SessionItemRunnigVersionInformation, itemRunnigVersionAtAppDomain); } } /// <summary> /// by given parameters check versions over PlayListVersionManager versions and /// adds versions to clientversion manager if any item version on /// playlist not found it will also added to PlaylistManager list /// </summary> /// <param name="playList"></param> /// <param name="userGuid"></param> /// <param name="ownerGuid"></param> public static void UpdateCurrentSessionVersion(PlayList playList, string userGuid, string ownerGuid) { ItemRunnigVersionInformation tmpItemRunnigVersionInformation; List<ItemRunnigVersionInformation> currentItemRunnigVersionInformationList = new List<ItemRunnigVersionInformation>(); if (!string.IsNullOrEmpty(userGuid)) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(userGuid); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(userGuid, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(currentItemRunnigVersionInformationList, tmpItemRunnigVersionInformation); } if (!string.IsNullOrEmpty(ownerGuid)) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(ownerGuid); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(ownerGuid, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(currentItemRunnigVersionInformationList, tmpItemRunnigVersionInformation); } if ((playList != null) && (playList.PlayListItemCollection != null)) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(playList.GUID); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(playList.GUID, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } currentItemRunnigVersionInformationList.Add(tmpItemRunnigVersionInformation); foreach (PlayListItem playListItem in playList.PlayListItemCollection) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(playListItem.GUID); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(playListItem.GUID, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } currentItemRunnigVersionInformationList.Add(tmpItemRunnigVersionInformation); foreach (SoftKey softKey in playListItem.PlayListSoftKeys) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(softKey.GUID); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(softKey.GUID, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(currentItemRunnigVersionInformationList, tmpItemRunnigVersionInformation); } foreach (MenuItem menuItem in playListItem.MenuItems) { tmpItemRunnigVersionInformation = PlayListVersionManager.GetItemRunnigVersionInformationByID(menuItem.Guid); if (tmpItemRunnigVersionInformation == null) { tmpItemRunnigVersionInformation = new ItemRunnigVersionInformation(menuItem.Guid, DateTime.Now.ToUniversalTime()); PlayListVersionManager.UpdateItemRunnigAppDomainVersion(tmpItemRunnigVersionInformation); } ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Add(currentItemRunnigVersionInformationList, tmpItemRunnigVersionInformation); } } } SessionItemRunnigVersionInformation = currentItemRunnigVersionInformationList; } public static ItemRunnigVersionInformation GetItemRunnigVersionInformationById(string itemGuid) { return SessionItemRunnigVersionInformation.FirstOrDefault(t => t.ItemGuid == itemGuid); } public static void DeleteItemRunnigAppDomain(string itemGuid) { ExtensionMethodsForClientVersionManager.ExtensionMethodsForClientVersionManager.Remove(SessionItemRunnigVersionInformation, NG.IPTOffice.Paloma.Helper.ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.GetMatchingItemRunnigVersionInformation(SessionItemRunnigVersionInformation, itemGuid)); } } and that was for server one public class PlayListVersionManager { public static List<ItemRunnigVersionInformation> AppDomainItemRunnigVersionInformation { get { if (HttpContext.Current.Application["AppDomainItemRunnigVersionInformation"] == null) HttpContext.Current.Application["AppDomainItemRunnigVersionInformation"] = new List<ItemRunnigVersionInformation>(); return (List<ItemRunnigVersionInformation>)HttpContext.Current.Application["AppDomainItemRunnigVersionInformation"]; } set { HttpContext.Current.Application["AppDomainItemRunnigVersionInformation"] = value; } } public static ItemRunnigVersionInformation GetItemRunnigVersionInformationByID(string itemGuid) { return ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.GetMatchingItemRunnigVersionInformation(AppDomainItemRunnigVersionInformation, itemGuid); } /// <summary> /// this will be updated when editor pages /// if any record at playlistversion is found it will be addedd /// </summary> /// <param name="itemRunnigVersionInformation"></param> public static void UpdateItemRunnigAppDomainVersion(ItemRunnigVersionInformation itemRunnigVersionInformation) { ItemRunnigVersionInformation itemRunnigVersionInformationAtAppDomain = NG.IPTOffice.Paloma.Helper.ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.GetMatchingItemRunnigVersionInformation(AppDomainItemRunnigVersionInformation, itemRunnigVersionInformation.ItemGuid); if (itemRunnigVersionInformationAtAppDomain == null) { ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.Add(AppDomainItemRunnigVersionInformation, itemRunnigVersionInformation); } else { ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.Remove(AppDomainItemRunnigVersionInformation, itemRunnigVersionInformationAtAppDomain); ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.Add(AppDomainItemRunnigVersionInformation, itemRunnigVersionInformation); } } //this will be checked each time if needed to update item over DB public static bool IsRunnigItemLastVersion(ItemRunnigVersionInformation itemRunnigVersionInformation, bool ignoreNullEntry, out bool itemNotExistsAtAppDomain) { itemNotExistsAtAppDomain = false; if (itemRunnigVersionInformation != null) { ItemRunnigVersionInformation itemRunnigVersionInformationAtAppDomain = AppDomainItemRunnigVersionInformation.FirstOrDefault(t => t.ItemGuid == itemRunnigVersionInformation.ItemGuid); itemNotExistsAtAppDomain = (itemRunnigVersionInformationAtAppDomain == null); if (itemNotExistsAtAppDomain && (ignoreNullEntry)) { ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.Add(AppDomainItemRunnigVersionInformation, itemRunnigVersionInformation); return true; } else if (!itemNotExistsAtAppDomain && (itemRunnigVersionInformationAtAppDomain.LastLoadTime <= itemRunnigVersionInformation.LastLoadTime)) return true; else return false; } else return ignoreNullEntry; } public static void DeleteItemRunnigAppDomain(string itemGuid) { ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.Remove(AppDomainItemRunnigVersionInformation, NG.IPTOffice.Paloma.Helper.ExtensionMethodsFoPlayListVersionManager.ExtensionMethodsFoPlayListVersionManager.GetMatchingItemRunnigVersionInformation(AppDomainItemRunnigVersionInformation, itemGuid)); } } when more than one client requests the page i got "Collection was modified; enumeration operation may not execute." like below.. xception: System.Web.HttpUnhandledException: Exception of type 'System.Web.HttpUnhandledException' was thrown. ---> System.InvalidOperationException: Collection was modified; enumeration operation may not execute. at System.ThrowHelper.ThrowInvalidOperationException(ExceptionResource resource) at System.Collections.Generic.List1.Enumerator.MoveNextRare() at System.Collections.Generic.List1.Enumerator.MoveNext() at System.Linq.Enumerable.FirstOrDefault[TSource](IEnumerable1 source, Func2 predicate) at NG.IPTOffice.Paloma.Helper.PlayListVersionManager.UpdateItemRunnigAppDomainVersion(ItemRunnigVersionInformation itemRunnigVersionInformation) in at System.Web.UI.Control.LoadRecursive() at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) --- End of inner exception stack trace --- at System.Web.UI.Page.HandleError(Exception e) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) at System.Web.UI.Page.ProcessRequest() at System.Web.UI.Page.ProcessRequestWithNoAssert(HttpContext context) at System.Web.UI.Page.ProcessRequest(HttpContext context) at ASP.playlistwebform_aspx.ProcessRequest(HttpContext context) in c:\WINDOWS\Microsoft.NET\Framework\v2.0.50727\Temporary ASP.NET Files\ipservicestest\8921e5c8\5d09c94d\App_Web_n4qdnfcq.2.cs:line 0 at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously)----------- how to implement version management like this scnerio? how can i to avoid this exception? thnx

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