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  • When I zip up my demo FlashDevelop project..why does it break?

    - by Ryan
    I built an AS3 image gallery using FlashDevelop. Before I zip up the application, I can run the image gallery in my browser by simply opening the index.html for the project. Everything works perfectly. I then zip up the project as proj-0.1.2.zip using winrar. I then unzip this newly created zip and try to load the application using the project index.html like above. The gallery doesn't function properly. From seeing what happens, it appears as though the image metadata is not present(but I'm not sure, see below). There are other applications as well that are broken. Videos don't load. If an application doesn't depend on any external assets then everything looks fine. Another thing..If I then build the FlashDevelop project and republish the swf..then it works in the index.html like I want. What is going on here? I want people to be able to fire up my demo apps out of the box by just running the index.html. If that doesn't always work and they have to figure out that they need to rebuild the SWF then that's pretty bad.

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  • excel - merge cells including a zip code

    - by evanmcd
    Hi all, I have the need to merge a bunch of cells that comprise an address (street, city, state, zip) into a single cell. No problem except with the zip code. The zip cell has only 4 digits for any zip that starts with 0. So, I change it's format to be Special - Zip Code. That makes the cell itself show the beginning 0, but the merged cell still does not show the leading 0. Does anyone know how to get the leading 0 in the merged column? Thanks Evan

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  • Need to convert a ZIP file to a random text file.

    - by Arsheep
    As title says need to convert a Zip file to text file , no matter the size and no matter if it will make sense or not.But i need to reconvert it to that zip file again (Lose less). The main problem i am having is how to find a alternative text/number version of a character. The Ascii wont work clearly ,So need help what can be a alternative text for a character specially that garbage looking binary chars in zip , when you see in a editor. I am not a native English speaker , so i hope the above will make a sense to you guys :)

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  • jQuery form zip code to state function

    - by Dakota R.
    I'm trying to convert a preexisting javascript function into a jQuery function. The function comes from http://javascript.internet.com/forms/zip-to-state.html and aims to convert a user-entered zip code into a state. I'm using jQuery 1.3.2, with all the necessary plugins, but I'm not very familiar with jQuery syntax and how to convert this from plain ol' Javascript syntax. The setState function takes two parameters, the zip code element and the state element, so I'm trying to do something like this: $('$zip_code').change( function () { setState($(this), $('#state')); }); Any thoughts on this syntax? Thanks, Dakota function getState(zip) { if ((parseInt(zipString.substr(zip / 4, 1), 16) & Math.pow(2, zip % 4)) && (zip.length == 5)) for (var i = 0; i < stateRange.length; i += 7) if (zip <= 1 * stateRange.substr(i, 5)) return stateRange.substr(i + 5, 2); return null; } function setState(txtZip, optionBox) { if (txtZip.value.length != 5 || isNaN(txtZip.value / 4)) { optionBox.options[0].selected = true; alert("Please enter a 5 digit, numeric zip code."); return; } var state = getState(txtZip.value); for (var i = 0; i < optionBox.options.length; i++) if (optionBox.options[i].value == state) return optionBox.options[i].selected = true; for (var i = 0; i < optionBox.options.length; i++) if (optionBox.options[i].value == "XX") return optionBox.options[i].selected = true; }

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  • Python 2.6 does not like appending to existing archives in zip files

    - by user313661
    Hello, In some Python unit tests of a program I'm working on we use in-memory zipfiles for end to end tests. In SetUp() we create a simple zip file, but in some tests we want to overwrite some archives. For this we do "zip.writestr(archive_name, zip.read(archive_name) + new_content)". Something like import zipfile from StringIO import StringIO def Foo(): zfile = StringIO() zip = zipfile.ZipFile(zfile, 'a') zip.writestr( "foo", "foo content") zip.writestr( "bar", "bar content") zip.writestr( "foo", zip.read("foo") + "some more foo content") print zip.read("bar") Foo() The problem is that this works fine in Python 2.4 and 2.5, but not 2.6. In Python 2.6 this fails on the print line with "BadZipfile: File name in directory "bar" and header "foo" differ." It seems that it is reading the correct file bar, but that it thinks it should be reading foo instead. I'm at a loss. What am I doing wrong? Is this not supported? I tried searching the web but could find no mention of similar problems. I read the zipfile documentation, but could not find anything (that I thought was) relevant, especially since I'm calling read() with the filename string. Any ideas? Thank you in advance!

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  • The 2010 JavaOne Java EE 6 Panel: Where We Are and Where We're Going

    - by janice.heiss(at)oracle.com
    An informative article, based on a 2010 JavaOne (San Francisco, California) panel session, surveys a variety of expert perspectives on Java EE 6.The panel, moderated by Oracle's Alexis Moussine-Pouchkine, consisted of:* Adam Bien, Consultant Author/ Speaker, adam-bien.com* Emmanuel Bernard, Principal Software Engineer, JBoss by Red Hat,* David Blevins, Senior Software Engineer, and co-founder of the OpenEJB project and a     founder of Apache Geronimo* Roberto Chinnici, Technical Staff Consulting Member, Oracle* Jim Knutson, Java EE Architect, IBM* Reza Rahman, Lead Engineer, Caucho Technology, Inc.,* Krasimir Semerdzhiev, Development Architect, SAP Labs BulgariaThe panel addressed such topics as Platform and API Adoption, Contexts and Dependency Injection (CDI), Java EE vs. Spring, the impact of Java EE 6 on tooling and testing, Java EE.next, along with a variety of audience questions. Read the entire article for the whole picture.

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  • unzip file on small drive

    - by David Oneill
    I have a zip file that contains many files. Each file in the zip file is about 100MB, and is compressed about 10% (IE it is about 90MB in the zip file). The whole zip file is 20GB, and I'm trying to unzip it onto a drive that has only 30GB free. On Windows 7, how can I unzip a zip file on my laptop's harddrive that doesn't have enough space for both the zipped and unzipped copies of the file? IE can I tell windows to remove stuff from the zip file as it is uncompressed?

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  • Filename encoding broken after unzip on windows

    - by flammi88
    I zipped a directory on my linux server. Many files in the directory have german umlauts in their filename. The filesystem is ext3 and the system locale is set to de_DE.utf8. I used the following command to create the zip file: zip -r somezip.zip somefolder/ I transfered this file via WinSCP to my windows laptop and unzipped it. The issue: All filenames with german umlauts are broken. On my linux server the filenames are displayed correctly. I assume that I made a mistake when i created the zip file. Has someone any ideas how i can perserve the right filename encoding when I zip the files with the zip command on linux?

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  • Filename encoding broken after unzip on windows

    - by flammi88
    I zipped a directory on my linux server. Many files in the directory have german umlauts in their filename. The filesystem is ext3 and the system locale is set to de_DE.utf8. I used the following command to create the zip file: zip -r somezip.zip somefolder/ I transfered this file via WinSCP to my windows laptop and unzipped it. The issue: All filenames with german umlauts are broken. On my linux server the filenames are displayed correctly. I assume that I made a mistake when i created the zip file. Has someone any ideas how i can perserve the right filename encoding when I zip the files with the zip command on linux?

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  • how to properly Install chromium from zip and make it the default browser

    - by ClarifyLinux
    Since the Chromium PPA is no longer maintained, for those of us preferring to use chromium over chrome, we have two options: Build and Install from Source Download either 'beta' or daily builds (in a zip file) Unfortunately for me, option 1 is overly complicated. I know how to compile most any other applications in Ubuntu but I've never been able to get chromium to build correctly. I am currently using option 2. In Chromium I have the Chromium Updater installed (http://goo.gl/ffAMy). This gives me quick access to the most recent 64bit versions. Once downloaded, I install to /home/myuser/opt/chrome-linux. From this directory I can run the chrome binary. It works perfectly except for the fact that I cannot get it to act as my default browser. I've tried, as root, installing the binary in /opt/chrome-linux/ with a symbolic link to the 'chrome' binary in /usr/bin. Unfortunately, this doesn't work as a non root user. So my question is - How do I properly install a downloaded chromium zip build so tht it's listed as an option for the default browser?

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  • java.util.zip.ZipException: Error opening file When Deploying an Application to Weblogic Server

    - by lmestre
    The latest weeks we had a hard time trying to solve a deployment issue.* WebLogic Server 10.3.6* Target: WLS Cluster<21-10-2013 05:29:40 PM CLST> <Error> <Console> <BEA-240003> <Console encountered the following error weblogic.management.DeploymentException:        at weblogic.servlet.internal.WarDeploymentFactory.findOrCreateComponentMBeans(WarDeploymentFactory.java:69)        at weblogic.application.internal.MBeanFactoryImpl.findOrCreateComponentMBeans(MBeanFactoryImpl.java:48)        at weblogic.application.internal.MBeanFactoryImpl.createComponentMBeans(MBeanFactoryImpl.java:110)        at weblogic.application.internal.MBeanFactoryImpl.initializeMBeans(MBeanFactoryImpl.java:76)        at weblogic.management.deploy.internal.MBeanConverter.createApplicationMBean(MBeanConverter.java:89)        at weblogic.management.deploy.internal.MBeanConverter.createApplicationForAppDeployment(MBeanConverter.java:67)        at weblogic.management.deploy.internal.MBeanConverter.setupNew81MBean(MBeanConverter.java:315)        at weblogic.deploy.internal.targetserver.operations.ActivateOperation.compatibilityProcessor(ActivateOperation.java:81)        at weblogic.deploy.internal.targetserver.operations.AbstractOperation.setupPrepare(AbstractOperation.java:295)        at weblogic.deploy.internal.targetserver.operations.ActivateOperation.doPrepare(ActivateOperation.java:97)        at weblogic.deploy.internal.targetserver.operations.AbstractOperation.prepare(AbstractOperation.java:217)        at weblogic.deploy.internal.targetserver.DeploymentManager.handleDeploymentPrepare(DeploymentManager.java:747)        at weblogic.deploy.internal.targetserver.DeploymentManager.prepareDeploymentList(DeploymentManager.java:1216)        at weblogic.deploy.internal.targetserver.DeploymentManager.handlePrepare(DeploymentManager.java:250)        at weblogic.deploy.internal.targetserver.DeploymentServiceDispatcher.prepare(DeploymentServiceDispatcher.java:159)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer.doPrepareCallback(DeploymentReceiverCallbackDeliverer.java:171)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer.access$000(DeploymentReceiverCallbackDeliverer.java:13)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer$1.run(DeploymentReceiverCallbackDeliverer.java:46)        at weblogic.work.SelfTuningWorkManagerImpl$WorkAdapterImpl.run(SelfTuningWorkManagerImpl.java:545)        at weblogic.work.ExecuteThread.execute(ExecuteThread.java:256)        at weblogic.work.ExecuteThread.run(ExecuteThread.java:221)Caused by: java.util.zip.ZipException: Error opening file - C:\Oracle\Middleware\user_projects\domains\MyDomain\servers\MyServer\stage\myapp\myapp.war Message - error in opening zip file        at weblogic.servlet.utils.WarUtils.existsInWar(WarUtils.java:87)        at weblogic.servlet.utils.WarUtils.isWebServices(WarUtils.java:76)        at weblogic.servlet.internal.WarDeploymentFactory.findOrCreateComponentMBeans(WarDeploymentFactory.java:61) So the first idea you have with that error is that the war file is corrupted or has incorrect privileges.        We tried:1. Unzipping the  war file, the file was perfect.2. Checking the size, same size as in other environments.3. Checking the ownership of the file, same as in other environments.4. Checking the permissions of the file, same as other applications.Then we accepted the file was fine, so we tried enabling some deployment debugs, but no clues.We also tried:1. Delete all contents of <MyDomain/servers/<MyServer>/tmp> a and <MyDomain/servers/<MyServer>/cache> folders, the issue persisted.2. When renaming the application the deployment was sucessful3. When targeting to the Admin Server, deployment was also working.4. Using 'Copy this application onto every target for me' didn't help either.Finally, my friend 'Test Case' solved the issue again.I saw this name in the config.xml<jdbc-system-resource>    <name>myapp</name>    <target></target>    <descriptor-file-name>jdbc/myapp-jdbc.xml</descriptor-file-name>  </jdbc-system-resource> So, it turned out that customer had created a DataSource with the same name as the application 'myapp' in the above example.By deleting the datasource and created another exact DataSource with a different name the issue was solved.At this point, Do you know Why 'java.util.zip.ZipException: Error opening file' was occurring?Because all names is WebLogic Server need to be unique.References: http://docs.oracle.com/cd/E23943_01/web.1111/e13709/setup.htm"Assigning Names to WebLogic Server ResourcesMake sure that each configurable resource in your WebLogic Server environment has a unique name. Each, domain, server, machine, cluster, JDBC data source, virtual host, or other resource must have a unique name." Enjoy!

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  • Inconsistent file downloads of (what should be) the same file

    - by Austin A.
    I'm working on a system that archives large collections of timetstamped images. Part of the system deals with saving an image to a growing .zip file. This morning I noticed that the log system said that an image was successfully downloaded and placed in the zip file, but when I downloaded the .zip (from an apache alias running on our server), the images didn't match the log. For example, although the log said that camera 3484 captured on January 17, 2011, when I download from the apache alias, the downloaded zip file only contains images up to January 14. So, I sshed onto the server, and unzipped the file in its own directory, and that zip file has images from January 14 to today (January 17). What strikes me as odd is that this should be the exact same file as the one I downloaded from the apache alias. Other experiments: I scp-ed the file from the server to my local machine, and the zip file has the newer images. But when I use an SCP client (in this case, Fugu for OSX), I get the zip file for the older images. In short: unzipping a file on the server or after downloading through scp or after downloading through wget gives one zip file, but unzipping a file from Chrome, Firefox, or SCP client gives a different zip file, when they should be exactly the same. Unzipping on the server... [user@server ~]$ cd /export1/amos/images/2011/84/3484/00003484/ [user@server 00003484]$ ls -la total 6180 drwxr-sr-x 2 user groupname 24 Jan 17 11:20 . drwxr-sr-x 4 user groupname 36 Jan 11 19:58 .. -rw-r--r-- 1 user groupname 6309980 Jan 17 12:05 2011.01.zip [user@server 00003484]$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg extracting: 20110114_143554.jpg replace 20110114_143554.jpg? [y]es, [n]o, [A]ll, [N]one, [r]ename: y extracting: 20110114_143554.jpg extracting: 20110114_153458.jpg (...bunch of files...) extracting: 20110117_170459.jpg extracting: 20110117_173458.jpg extracting: 20110117_180501.jpg Using the wget through apache alias. local:~ user$ wget http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip --12:38:13-- http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip => `2011.01.zip' Resolving example.com... ip.ip.ip.ip Connecting to example.com|ip.ip.ip.ip|:80... connected. HTTP request sent, awaiting response... 200 OK Length: 6,327,747 (6.0M) [application/zip] 100% [=====================================================================================================>] 6,327,747 1.03M/s ETA 00:00 12:38:56 (143.23 KB/s) - `2011.01.zip' saved [6327747/6327747] local:~ user$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg (... same as before...) extracting: 20110117_183459.jpg Using scp to grab the zip local:~ user$ scp user@server:/export1/amos/images/2011/84/3484/00003484/2011.01.zip . 2011.01.zip 100% 6179KB 475.3KB/s 00:13 local:~ user$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg (...same as before...) extracting: 20110117_183459.jpg Using Fugu to download 2011.01.zip from /export1/amos/images/2011/84/3484/00003484/ gives images 20110113_090457.jpg through 201100114_010554.jpg Using Firefox to download 2011.01.zip from http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip gives images 20110113_090457.jpg through 201100114_010554.jpg Using Chrome gives same results as Firefox. Relevant section from apache httpd.conf: # ScriptAlias: This controls which directories contain server scripts. # ScriptAliases are essentially the same as Aliases, except that # documents in the realname directory are treated as applications and # run by the server when requested rather than as documents sent to the client. # The same rules about trailing "/" apply to ScriptAlias directives as to # Alias. # ScriptAlias /cgi-bin/ "/var/www/cgi-bin/" Alias /zipfiles/ /export1/amos/images/

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  • CVE-2004-1010 Buffer Overflow vulnerability in Zip utility

    - by chandan
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2004-1010 Buffer Overflow vulnerability 10.0 Zip Solaris 10 SPARC: 147378-01 X86: 147379-01 Solaris 9 Contact Support This notification describes vulnerabilities fixed in third-party components that are included in Sun's product distribution.Information about vulnerabilities affecting Oracle Sun products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • CVE-2008-6536 Unspecified vulnerability in 7-zip

    - by chandan
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2008-6536 Unspecified vulnerability 10.0 7-zip Solaris 10 SPARC: 137321-02 x86: 137322-02 Solaris 9 SPARC: 137477-02 x86: 137478-02 This notification describes vulnerabilities fixed in third-party components that are included in Oracle's product distributions.Information about vulnerabilities affecting Oracle products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • I forgot the password to a cbz/zip file

    - by hurley
    I forgot the password to a cbz file, which when I open it says it only contains empty pages, so i rename it to zip, since I read it will open anyway, and I enter what I supposed to be the password, and it starts extracting some 100 files, but it stops and asks for a password again and none of my known passwords work. Help? it's a backup for over 2 years of work. I'm using Archive Manager at Ubuntu 13.

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  • How to download an MP3 or ZIP file onto mobile devices

    - by Hope4You
    I want to be able to download digital goods to smartphone users (music in format .mp3 or .zip). But iPhone and iPad do not allow direct forced downloads. How can I provide mobile users with digital downloads? I use PHP. The only way I can think of to do this is to use the Dropbox Web API to transfer files to the user's Dropbox account, which then synchronizes with their mobile device. Any other suggestions would be appreciated.

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  • Is there a way to determine the original size or file count of a 7-zip archive?

    - by Zac B
    I know that when I compress an archive with the 7za utility, it gives me stats like the number of files processed and the amount of bytes processed (the original size of the data). Is it possible, using the commandline (on linux) or some programming language, to determine: the original size of an archive, before it was compressed? the number of files/directories contained within an archive? The answer might be "no, just decompress the whole archive and do counting/sizing then", but it would be useful to know if there was a faster/less space-greedy way.

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  • ASP.NET Create zip file for download: the compressed zipped folder is invalid or corrupted

    - by Jason Braswell
    string fileName = "test.zip"; string path = "c:\\temp\\"; string fullPath = path + fileName; FileInfo file = new FileInfo(fullPath); Response.Clear(); Response.ClearContent(); Response.ClearHeaders(); Response.Buffer = true; Response.AppendHeader("content-disposition", "attachment; filename=" + fileName ); Response.AppendHeader("content-length", file.Length.ToString()); Response.ContentType = "application/x-compressed"; Response.TransmitFile(fullPath); Response.Flush(); Response.End(); The actual zip file c:\temp\test.zip is good, valid, whatever you want to call it. When I navigate to the directory c:\temp\ and double-click on the test.zip file; it opens right up. My problem seems only to be with the download. The code above executes without any issue. A file download dialog is presented. I can chose to either save or open. If I try to open the file from the dialog, or save it and then open it. I get the following dialog message: The Compressed (zipped) Folder is invalid or corrupted. For Response.ContentType I've tried: application/x-compressed application/x-zip-compressed application/x-gzip-compresse application/octet-stream application/zip The zip file is being created with some prior code (that I'm sure is working fine due to my ability to open the created file directly) using: Ionic.zip http://www.codeplex.com/DotNetZip

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  • uncompressing .zip file in linux [closed]

    - by Suren
    hi, I have a .zip file (It contains multiple files, ex: file1.txt file2.txt file3.txt.. n so on) in a directory. And my query is: How to extract the files from .zip archive to the very same directory and how to create the list of all the files extracted from .zip archive.** The extracted file name should be printed like this in the file named: file_list: file1.txt file2.txt file3.txt filen.txt I have tried the following command assuming that my .zip file name is "data.zip". unzip -qoj data.zip | unzip -ql data.zip > file_list I have used unzip -qoj data.zip to extract all the files in the same directory(quietly,overwrite,junk_path). When I try to insert -l with the first unzip command then the command doesn't extract the file in the current and only files are listed thats why I have to used unzip again after the first pipe(If I am making a mistake here let me know please). I get the following output Length Date Time Name -------- ---- ---- ---- 0 12-21-09 14:25 data/ 6148 12-21-09 14:25 data/.DS_Store 0 12-21-09 14:25 __MACOSX/ 0 12-21-09 14:25 __MACOSX/data/ 82 12-21-09 14:25 __MACOSX/data/._.DS_Store 82 12-11-09 13:59 data/file1.txt 120 12-11-09 13:59 data/file2.txt 166 12-11-09 13:59 data/file3.txt -------- ------- 6598 8 files How do I extract only file1.txt file2.txt file3.txt from this stdout? Is it possible to do this with linux command or I have to write a perl script for this? Thank you.

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  • How to create a zip file and keep entries for directories?

    - by NathanZ
    I would like to create a zip archive from a folder and keep entries for (non-empty) directories. In the code below, FileInputStream throws a FileNotFoundException when a directory is passed to AddToZip. I have tried to put a condition around the actual writing of bytes but it makes the whole archive invalid. How can I add directory entries to the archive? public static void addToZip(File directoryToZip, File file, ZipOutputStream zos) throws FileNotFoundException, IOException { String zipFilePath = file.getCanonicalPath().substring(directoryToZip.getCanonicalPath().length() + 1,file.getCanonicalPath().length()); System.out.println("Writing '" + zipFilePath + "' to zip file"); ZipEntry zipEntry = new ZipEntry(zipFilePath); zos.putNextEntry(zipEntry); FileInputStream fis = new FileInputStream(file); // Throws a FileNotFoundException when directory byte[] bytes = new byte[1024]; int length; while ((length = fis.read(bytes)) >= 0) { zos.write(bytes, 0, length); } zos.closeEntry(); fis.close(); }

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  • I am trying to zip files individually, but the file type is unknown

    - by Jason Mander
    I am trying to zip some files with an unknown file type individually. I am using the following code in a batch script to do that: @ECHO OFF FOR %%A IN (bestbuy*nat*component.cpi*) DO "C:\Program Files\7-Zip\7z.exe" a -mx9 -m0=lzma2:d256m "%%~nA.7z" "%%A" The code will compress files individually ONLY if the file has an extension. Unfortunately the files that I have don't have any extension. In the code I am trying to zip files by doing a pattern match, the files are getting compressed into ONE file (which I do not want, I want each file compressed individually). Why does this code create separate zip files when the files have an extension (for example if I add .txt to the end of the files) and when there is no extension the code creates one zipped file. Can anyone please help me with the code to compress files with unknown file type so that each file gets compressed individually Your help would be greatly appreciated. Jason

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  • MDW Reports–New Source Code ZIP File Available

    - by billramo
    In my MDW Reports series, I attached V1 of the RDL files in my post - May the source be with you! MDW Report Series Part 6–The Final Edition. Since that post, Rachna Agarwal from MSIT in India updated the RDL files that are ready to go in a single ZIP. The reports assume that they will ne uploaded to the Report Manager’s root folder and use a shared data source named MDW. The reports also integrate with the new Query Hash Statistics reports. You can download them from my SQLBlog.com download site.

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