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  • SharpArch.Core.PreconditionException: For better clarity and reliability, Entities with an assigned

    - by Quintin Par
    When I do a save of an entity with assigned id I get a SharpArch.Core.PreconditionException: For better clarity and reliability, Entities with an assigned Id must call Save or Update My class is public class CompanyUserRepository : RepositoryWithTypedId<CompanyUser, string>, ICompanyUserRepository { public override CompanyUser SaveOrUpdate(CompanyUser entity) { var user = base.SaveOrUpdate(entity); //Do some stuff return user; } } How do I go about saving this entity? RepositoryWithTypedId does not expose a Save method Related question. This tells you the reason, but I haven't found out the Sharp Architecture way to do a Save.

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  • Finding tags in query string with regular expression

    - by fatmatto
    Hi everybody! I have to set some routing rules in my php application, and they should be in the form /%var/something/else/%another_var In other words i beed a regex that returns me every URI piece marked by the % character, String marked by % represent var names so they can be almost every string. another example: from /%lang/module/controller/action/%var_1 i want the regex to extract lang and var_1 i tried something like /.*%(.*)[\/$]/ but it doesn't work.....

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  • How can we order a column as int using hibernate criteria API?

    - by Satya
    Hi I want to fetch the data form data base using hibernate Criteria API. That data should be ordered by some column as number. This column is defined as varchar in DB. But I have to fetch as numberic. I am facing problem using criteria API as it is ordering like string onyly. Ex: I am getting data like 9, 8, 7, 6, 5, 4, 3, 2, 1,10 but i want data as 10,9,8,7,6,5,4,3,2,1 Is there any Hibernate methods to covert varchar to number like convert("some column",int ) or cast("some column",int) ?

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  • Accessing the Identity object in a MVC repository

    - by Rod
    Hi, I have a pretty generic repository that does basic CRUD for many of my business entities. The entities enherit form a generic object that has a few fields I maintain for all objects. eg. ModifiedBy, CreatedBy, CreatedDate, ModifiedDate. These fields ModifiedBy and CreatedBy will always be set before any update/save. My questions is: Is there any way to gain access to the Identity object from my MVC web application in my repositories? I was hoping to set the modifiedby to the identity user for any update in one shot?? Best Regard, Rod

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  • which regular expression will capture this sequence?

    - by John Smith
    The text follows this pattern <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) so basically the above line might repeat itself multiple times, and the idea is to retrieve the first 3 characters immediately after ABC. I have tried regular expressions along the lines of \<tr class="text" [.]+ABC(?<capture>[.]{3}) but they all fail. Can someone give me a hint?

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  • Help me to split string with Regular Expression

    - by Lu Lu
    Hello, I have a string: CriteriaCondition={FieldName={*EPS}*$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)} Help me to get the first word which ends with the first word "={" & get the next following word which ends with "}". The result must be: Word1 = "CriteriaCondition" Word2 = "FieldName={EPS}$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)" And with the string "FieldName=(EPS)$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)", help me to split to pairs: FieldName EPS MinValue -201 MaxValue 304 TradingPeriod -1 Thanks.

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  • Regular expression

    - by atno
    Hi I have an array that its first element might contains something like [some text, here. That's some text] I'm trying to figure out a pattern to check if such string exists and if not create it but having problem with making the pattern. Here's what I've done so far $pattern = '/^\[*\]$/'; if(preg_match($pattern,$exploded[0])){ $name = array_shift($exploded); }else{ $name = "[Unnamed import] - " .gmdate("His"); } But I always get [Unnamed import] - 032758 even when I'm sure that pattern match

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  • How to map a Dictionary<string, string> spanning several tables

    - by Kim Johansson
    I have four tables: CREATE TABLE [Languages] ( [Id] INTEGER IDENTITY(1,1) NOT NULL, [Code] NVARCHAR(10) NOT NULL, PRIMARY KEY ([Id]), UNIQUE INDEX ([Code]) ); CREATE TABLE [Words] ( [Id] INTEGER IDENTITY(1,1) NOT NULL, PRIMARY KEY ([Id]) ); CREATE TABLE [WordTranslations] ( [Id] INTEGER IDENTITY(1,1) NOT NULL, [Value] NVARCHAR(100) NOT NULL, [Word] INTEGER NOT NULL, [Language] INTEGER NOT NULL, PRIMARY KEY ([Id]), FOREIGN KEY ([Word]) REFERENCES [Words] ([Id]), FOREIGN KEY ([Language]) REFERENCES [Languages] ([Id]) ); CREATE TABLE [Categories] ( [Id] INTEGER IDENTITY(1,1) NOT NULL, [Word] INTEGER NOT NULL, PRIMARY KEY ([Id]), FOREIGN KEY ([Word]) REFERENCES [Words] ([Id]) ); So you get the name of a Category via the Word - WordTranslation - Language relations. Like this: SELECT TOP 1 wt.Value FROM [Categories] AS c LEFT JOIN [WordTranslations] AS wt ON c.Word = wt.Word WHERE wt.Language = ( SELECT TOP 1 l.Id FROM [Languages] WHERE l.[Code] = N'en-US' ) AND c.Id = 1; That would return the en-US translation of the Category with Id = 1. My question is how to map this using the following class: public class Category { public virtual int Id { get; set; } public virtual IDictionary<string, string> Translations { get; set; } } Getting the same as the SQL query above would be: Category category = session.Get<Category>(1); string name = category.Translations["en-US"]; And "name" would now contain the Category's name in en-US. Category is mapped against the Categories table. How would you do this and is it even possible?

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  • Pass a captured named regular expression to URL dictionary in generic view

    - by Trent Jurewicz
    I am working with a generic view in Django. I want to capture a named group parameter in the URL and pass the value to the URL pattern dictionary. For example, in the URLConf below, I want to capture the parent_slug value in the URL and pass it to the queryset dictionary value like so: urlpatterns = patterns('django.views.generic.list_detail', (r'^(?P<parent_slugs>[-\w])$', 'object_list', {'queryset':Promotion.objects.filter(category=parent_slug)}, 'promo_promotion_list'), ) Is this possible to do in one URLConf entry, or would it be wiser if I create a custom view to capture the value and pass the queryset directly to the generic view from my overridden view?

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  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

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  • Find last match with python regular expression

    - by SDD
    I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

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  • Java Mvc And Hibernate

    - by GigaPr
    Hi i am trying to learn Java, Hibernate and the MVC pattern. Following various tutorial online i managed to map my database, i have created few Main methods to test it and it works. Furthermore i have created few pages using the MVC patter and i am able to display some mock data as well in a view. the problem is i can not connect the two. this is what i have My view Looks like this <%@ include file="/WEB-INF/jsp/include.jsp" %> <html> <head> <title>Users</title> <%@ include file="/WEB-INF/jsp/head.jsp" %> </head> <body> <%@ include file="/WEB-INF/jsp/header.jsp" %> <img src="images/rss.png" alt="Rss Feed"/> <%@ include file="/WEB-INF/jsp/menu.jsp" %> <div class="ContainerIntroText"> <img src="images/usersList.png" class="marginL150px" alt="Add New User"/> <br/> <br/> <div class="usersList"> <div class="listHeaders"> <div class="headerBox"> <strong>FirstName</strong> </div> <div class="headerBox"> <strong>LastName</strong> </div> <div class="headerBox"> <strong>Username</strong> </div> <div class="headerAction"> <strong>Edit</strong> </div> <div class="headerAction"> <strong>Delete</strong> </div> </div> <br><br> <c:forEach items="${users}" var="user"> <div class="listElement"> <c:out value="${user.firstName}"/> </div> <div class="listElement"> <c:out value="${user.lastName}"/> </div> <div class="listElement"> <c:out value="${user.username}"/> </div> <div class="listElementAction"> <input type="button" name="Edit" title="Edit" value="Edit"/> </div> <div class="listElementAction"> <input type="image" src="images/delete.png" name="image" alt="Delete" > </div> <br /> </c:forEach> </div> </div> <a id="addUser" href="addUser.htm" title="Click to add a new user">&nbsp;</a> </body> </html> My controller public class UsersController implements Controller { private UserServiceImplementation userServiceImplementation; public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ModelAndView modelAndView = new ModelAndView("users"); List<User> users = this.userServiceImplementation.get(); modelAndView.addObject("users", users); return modelAndView; } public UserServiceImplementation getUserServiceImplementation() { return userServiceImplementation; } public void setUserServiceImplementation(UserServiceImplementation userServiceImplementation) { this.userServiceImplementation = userServiceImplementation; } } My servelet definitions <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- the application context definition for the springapp DispatcherServlet --> <bean name="/home.htm" class="com.rssFeed.mvc.HomeController"/> <bean name="/rssFeeds.htm" class="com.rssFeed.mvc.RssFeedsController"/> <bean name="/addUser.htm" class="com.rssFeed.mvc.AddUserController"/> <bean name="/users.htm" class="com.rssFeed.mvc.UsersController"> <property name="userServiceImplementation" ref="userServiceImplementation"/> </bean> <bean id="userServiceImplementation" class="com.rssFeed.ServiceImplementation.UserServiceImplementation"> <property name="users"> <list> <ref bean="user1"/> <ref bean="user2"/> </list> </property> </bean> <bean id="user1" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName1"/> <property name="lastName" value="lastName1"/> <property name="username" value="username1"/> <property name="password" value="password1"/> </bean> <bean id="user2" class="com.rssFeed.domain.User"> <property name="firstName" value="firstName2"/> <property name="lastName" value="lastName2"/> <property name="username" value="username2"/> <property name="password" value="password2"/> </bean> <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"></property> <property name="prefix" value="/WEB-INF/jsp/"></property> <property name="suffix" value=".jsp"></property> </bean> </beans> and finally this class to access the database public class HibernateUserDao extends HibernateDaoSupport implements UserDao { public void addUser(User user) { getHibernateTemplate().saveOrUpdate(user); } public List<User> get() { User user1 = new User(); user1.setFirstName("FirstName"); user1.setLastName("LastName"); user1.setUsername("Username"); user1.setPassword("Password"); List<User> users = new LinkedList<User>(); users.add(user1); return users; } public User get(int id) { throw new UnsupportedOperationException("Not supported yet."); } public User get(String username) { return null; } } the database connection occurs in this file <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver"/> <property name="url" value="jdbc:hsqldb:hsql://localhost/rss"/> <property name="username" value="sa"/> <property name="password" value=""/> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean" > <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/rssFeed/domain/User.hbm.xml</value> </list> </property> <property name="hibernateProperties" > <props> <prop key="hibernate.dialect">org.hibernate.dialect.HSQLDialect</prop> </props> </property> </bean> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory"/> </bean> <bean id="userDao" class="com.rssFeed.dao.hibernate.HibernateUserDao"> <property name="sessionFactory" ref="sessionFactory"/> </bean> </beans> Could you help me to solve this problem i spent the last 4 days and nights on this issue without any success Thanks

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  • Regular Expression - Match only 7 chars?

    - by Simon
    I'm trying to match a SEDOL (exactly 7 chars: 6 alpha-numeric chars followed by 1 numeric char) My regex ([A-Z 0-9]{6})[0-9]{1} matches correctly but strings greater than 7 chars that begin with a valid match also match (if you see what I mean :)). For example: B3KMJP4 matches correctly but so does: B3KMJP4x which shouldn't match. Can anyone show me how to avoid this?

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  • Scala: Matching optional Regular Expression groups

    - by Brian Heylin
    I'm trying to match on an option group in Scala 2.8 (beta 1) with the following code: import scala.xml._ val StatementPattern = """([\w\.]+)\s*:\s*([+-])?(\d+)""".r def buildProperty(input: String): Node = input match { case StatementPattern(name, value) => <propertyWithoutSign /> case StatementPattern(name, sign, value) => <propertyWithSign /> } val withSign = "property.name: +10" val withoutSign = "property.name: 10" buildProperty(withSign) // <propertyWithSign></propertyWithSign> buildProperty(withoutSign) // <propertyWithSign></propertyWithSign> But this is not working. What is the correct way to match optional regex groups?

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  • regular expression for letters, numbers and - _ .

    - by Jorre
    I'm having trouble checking in PHP if a value is is any of the following combinations letters (upper or lowercase) numbers (0-9) underscore (_) dash (-) point (.) no spaces! or other characters a few examples: OK: "screen123.css" OK: "screen-new-file.css" OK: "screen_new.js" NOT OK: "screen new file.css" I guess I need a regex for this, since I need to throw an error when a give string has other characters in it than the ones mentioned above.

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  • how to fix my error saying expected expression before 'else'

    - by user292489
    this program intended to read a .txt, a set of numbers, file and wwrite to another two .txt files called even amd odd as follows: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int i=0,even,odd; int number[i]; // check to make sure that all the file names are entered if (argc != 3) { printf("Usage: executable in_file output_file\n"); exit(0); } FILE *dog = fopen(argv[1], "r"); FILE *feven= fopen(argv[2], "w"); FILE *fodd= fopen (argv[3], "w"); // check whether the file has been opened successfully if (dog == NULL) { printf("File %s cannot open!\n", argv[1]); exit(0); } //odd = fopen(argv[2], "w"); { if (i%2!=1) i++;} fprintf(feven, "%d", even); fscanf(dog, "%d", &number[i]); else { i%2==1; i++;} fprintf(fodd, "%d", odd); fscanf(dog, "%d", &number[i]); fclose(feven); fclose(fodd);

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  • Buggy Perl regular expression

    - by Tichomir Mitkov
    Hi, there I'm writing a program that has to get values from a file. In the file each line indicates an entity. Each entity has three values. For example: Value1 Value2 value3 I have a regular expresion to match them m/(.*?) (.*?) (.*?)/m; But it seems that the third value in never matched! The only way to match the third value is to add another value in the file and another "matching brackets" in the expresion. But this does not satisfy me. Thanks in Advance!

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