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  • red black tree balancing?

    - by Anirudh Kaki
    i am working to generate tango tree, where i need to check whether every sub tree in tango is balanced or not. if its not balanced i need to make it balance? I trying so hard to make entire RB-tree balance but i not getting any proper logic so can any one help me out?? here i am adding code to check how to find my tree is balanced are not but when its not balanced how can i make it balance. static boolean verifyProperty5(rbnode n) { int left = 0, right = 0; if (n != null) { bh++; left = blackHeight(n.left, 0); right = blackHeight(n.right, 0); } if (left == right) { System.out.println("black height is :: " + bh); return true; } else { System.out.println("in balance"); return false; } } public static int blackHeight(rbnode root, int len) { bh = 0; blackHeight(root, path1, len); return bh; } private static void blackHeight(rbnode root, int path1[], int len) { if (root == null) return; if (root.color == "black"){ root.black_count = root.parent.black_count+1; } else{ root.black_count = root.parent.black_count; } if ((root.left == null) && (root.right == null)) { bh = root.black_count; } blackHeight(root.left, path1, len); blackHeight(root.right, path1, len); }

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  • How to prevent external translation of a movieclip object on stage in AS3?

    - by Aaron H.
    I have a MovieClip object, which is exported for actionscript (AS3) in an .swc file. When I place an instance of the clip on the stage without any modifications, it appears in the upper left corner, about half off stage (i.e. only the lower right quadrant of the object is visible). I understand that this is because the clip has a registration point which is not the upper left corner. If you call getBounds() on the movieclip you can get the bounds of the clip (presumably from the "point" that it's aligned on) which looks something like (left: -303, top: -100, right: 303, bottom: 100), you can subtract the left and top values from the clip x and y: clip.x -= bounds.left; clip.y -= bounds.top; This seems to properly align the clip fully on stage with the top left of the clip squarely in the corner of the stage. But! Following that logic doesn't seem to work when aligning it on the center of the stage! clip.x = (stage.stageWidth / 2); etc... This creates the crazy parallel universe where the clip is now down in the lower right corner of the stage. The only clue I have is that looking at: clip.transform.matrix and clip.transform.concatenatedMatrix matrix has a tx value of 748 (half of stage height) ty value of 426 (Half of stage height) concatenatedMatrix has a tx value of 1699.5 and ty value of 967.75 That's also obviously where the movieclip is getting positioned, but why? Where is this additional translation coming from?

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  • How do I animate text links in jquery?

    - by Peter
    I am somewhat new to jquery and I have a problem with something I am trying to implement using jquery. I have a vertical navigation menu where each link animates on hover by changing color, increasing letter spacing, and adding a border on the left. Everything is working the way I want it to except for when I click on the link. After I click on the link, the text changes to a different color and remains that same color even when I hover over the link. I am wanting to make it to where the color change on hover remains intact even after I click the link. I'm sure I am missing something simple, but I have tried everything I know to do with no luck. Any suggestions would be helpful! Here is what I have for the animation... <script type="text/javascript"> $(document).ready(function(){ $("ul.navlist li a").hover(function(){ $(this).stop() .animate({paddingLeft: '10px',letterSpacing: '2px',borderWidth:'20px'},{queue:false,easing:'easeInQuad'},50) }, function(){ $(this).stop() .animate({paddingLeft: '0px', letterSpacing: '0px',borderWidth:'0px'},{queue:false,easing:'easeOutQuad'},50) }); }); </script> My css for the navigation list is here... .navlist { list-style: none; } .navlist a { border-left-color: #555555; border-left-style: solid; border-left-width: 0px; color: #c4c4c4; } .navlist a:hover { border-left-color: #555555; border-left-style: solid; color: #555555; }

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  • rookie MySql question about paging; Is one query enough?

    - by Camran
    I have managed to get paging to work, almost. I want to display to the user, total nr of records found, and the currently displayed records. Ex: 4000 found, displaying 0-100. I am testing this with the nr 2 (because I don't have that many records, have like 20). So I am using LIMIT $start, $nr_results; Do I have to make two queries in order to display the results the way I want, one query fetching all records and then make a mysql_num_rows to get all records, then the one with the LIMIT ? I have this: mysql_num_rows($qry_result); $total_pages = ceil($num_total / $res_per_page); //$res_per_page==2 and $num_total = 2 if ($p - 10 < 1) { $pagemin=1; } else { $pagemin = $p - 10; } if ($p + 10 $total_pages) { $pagemax = $total_pages; } else { $pagemax = $p + 10; } Here is the query: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id ORDER BY modify_date DESC LIMIT 0, 2 Thanks, if you need more input let me know. Basically Q is, do I have to make two queries?

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  • How to change quicksort to output elements in descending order?

    - by masato-san
    Hi, I wrote a quicksort algorithm however, I would like to make a change somewhere so that this quicksort would output elements in descending order. I searched and found that I can change the comparison operator (<) in partition() to other way around (like below). //This is snippet from partition() function while($array[$l] < $pivot) { $l++; } while($array[$r] > $pivot) { $r--; } But it is not working.. If I quicksort the array below, $array = (3,9,5,7); should be: $array = (9,7,5,3) But actual output is: $array = (3,5,7,9) Below is my quicksort which trying to output elements in descending order. How should I make change to sort in descending order? If you need any clarification please let me know. Thanks! $array = (3,9,5,7); $app = new QuicksortDescending(); $app->quicksort($array, 0, count($array)); print_r($array); class QuicksortDescending { public function partitionDesc(&$array, $left, $right) { $l = $left; $r = $right; $pivot = $array[($right+$left)/2]; while($l <= $r) { while($array[$l] > $pivot) { $l++; } while($array[$r] < $pivot) { $r--; } if($l <= $r) {// if L and R haven't cross $this->swap($array, $l, $r); $l ++; $j --; } } return $l; } public function quicksortDesc(&$array, $left, $right) { $index = $this->partition($array, $left, $right); if($left < $index-1) { //if there is more than 1 element to sort on right subarray $this->quicksortDesc($array, $left, $index-1); } if($index < $right) { //if there is more than 1 element to sort on right subarray $this->quicksortDesc($array, $index, $right); } } }

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  • [BST] Deletion procedure

    - by Metz
    Hi all. Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. Thank you. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

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  • How to Make a Game like Space Invaders - Ray Wenderlich (why do my space invaders scroll off screen)

    - by Erv Noel
    I'm following this tutorial(http://www.raywenderlich.com/51068/how-to-make-a-game-like-space-invaders-with-sprite-kit-tutorial-part-1) and I've run into a problem right after the part where I add [self determineInvaderMovementDirection]; to my GameScene.m file (specifically to my moveInvadersForUpdate method) The tutorial states that the space invaders should be moving accordingly after adding this piece of code but when I run they move to the left and they do not come back. I'm not sure what I am doing wrong as I have followed this tutorial very carefully. Any help or clarification would be greatly appreciated. Thanks in advance ! Here is the full GameScene.m #import "GameScene.h" #import <CoreMotion/CoreMotion.h> #pragma mark - Custom Type Definitions /* The type definition and constant definitions 1,2,3 take care of the following tasks: 1.Define the possible types of invader enemies. This can be used in switch statements later when things like displaying different sprites images for each enemy type. The typedef makes InvaderType a formal Obj-C type that is type checked for method arguments and variables.This is so that the wrong method argument is not used or assigned to the wrong variable. 2. Define the size of the invaders and that they'll be laid out in a grid of rows and columns on the screen. 3. Define a name that will be used to identify invaders when searching for them. */ //1 typedef enum InvaderType { InvaderTypeA, InvaderTypeB, InvaderTypeC } InvaderType; /* Invaders move in a fixed pattern: right, right, down, left, down, right right. InvaderMovementDirection tracks the invaders' progress through this pattern */ typedef enum InvaderMovementDirection { InvaderMovementDirectionRight, InvaderMovementDirectionLeft, InvaderMovementDirectionDownThenRight, InvaderMovementDirectionDownThenLeft, InvaderMovementDirectionNone } InvaderMovementDirection; //2 #define kInvaderSize CGSizeMake(24,16) #define kInvaderGridSpacing CGSizeMake(12,12) #define kInvaderRowCount 6 #define kInvaderColCount 6 //3 #define kInvaderName @"invader" #define kShipSize CGSizeMake(30, 16) //stores the size of the ship #define kShipName @"ship" // stores the name of the ship stored on the sprite node #define kScoreHudName @"scoreHud" #define kHealthHudName @"healthHud" /* this class extension allows you to add “private” properties to GameScene class, without revealing the properties to other classes or code. You still get the benefit of using Objective-C properties, but your GameScene state is stored internally and can’t be modified by other external classes. As well, it doesn’t clutter the namespace of datatypes that your other classes see. This class extension is used in the method didMoveToView */ #pragma mark - Private GameScene Properties @interface GameScene () @property BOOL contentCreated; @property InvaderMovementDirection invaderMovementDirection; @property NSTimeInterval timeOfLastMove; @property NSTimeInterval timePerMove; @end @implementation GameScene #pragma mark Object Lifecycle Management #pragma mark - Scene Setup and Content Creation /*This method simply invokes createContent using the BOOL property contentCreated to make sure you don’t create your scene’s content more than once. This property is defined in an Objective-C Class Extension found near the top of the file()*/ - (void)didMoveToView:(SKView *)view { if (!self.contentCreated) { [self createContent]; self.contentCreated = YES; } } - (void)createContent { //1 - Invaders begin by moving to the right self.invaderMovementDirection = InvaderMovementDirectionRight; //2 - Invaders take 1 sec for each move. Each step left, right or down // takes 1 second. self.timePerMove = 1.0; //3 - Invaders haven't moved yet, so set the time to zero self.timeOfLastMove = 0.0; [self setupInvaders]; [self setupShip]; [self setupHud]; } /* Creates an invade sprite of a given type 1. Use the invadeType parameterr to determine color of the invader 2. Call spriteNodeWithColor:size: of SKSpriteNode to alloc and init a sprite that renders as a rect of the given color invaderColor with size kInvaderSize */ -(SKNode*)makeInvaderOfType:(InvaderType)invaderType { //1 SKColor* invaderColor; switch (invaderType) { case InvaderTypeA: invaderColor = [SKColor redColor]; break; case InvaderTypeB: invaderColor = [SKColor greenColor]; break; case InvaderTypeC: invaderColor = [SKColor blueColor]; break; } //2 SKSpriteNode* invader = [SKSpriteNode spriteNodeWithColor:invaderColor size:kInvaderSize]; invader.name = kInvaderName; return invader; } -(void)setupInvaders { //1 - loop over the rows CGPoint baseOrigin = CGPointMake(kInvaderSize.width / 2, 180); for (NSUInteger row = 0; row < kInvaderRowCount; ++row) { //2 - Choose a single InvaderType for all invaders // in this row based on the row number InvaderType invaderType; if (row % 3 == 0) invaderType = InvaderTypeA; else if (row % 3 == 1) invaderType = InvaderTypeB; else invaderType = InvaderTypeC; //3 - Does some math to figure out where the first invader // in the row should be positioned CGPoint invaderPosition = CGPointMake(baseOrigin.x, row * (kInvaderGridSpacing.height + kInvaderSize.height) + baseOrigin.y); //4 - Loop over the columns for (NSUInteger col = 0; col < kInvaderColCount; ++col) { //5 - Create an invader for the current row and column and add it // to the scene SKNode* invader = [self makeInvaderOfType:invaderType]; invader.position = invaderPosition; [self addChild:invader]; //6 - update the invaderPosition so that it's correct for the //next invader invaderPosition.x += kInvaderSize.width + kInvaderGridSpacing.width; } } } -(void)setupShip { //1 - creates ship using makeShip. makeShip can easily be used later // to create another ship (ex. to set up more lives) SKNode* ship = [self makeShip]; //2 - Places the ship on the screen. In SpriteKit the origin is at the lower //left corner of the screen. The anchorPoint is based on a unit square with (0, 0) at the lower left of the sprite's area and (1, 1) at its top right. Since SKSpriteNode has a default anchorPoint of (0.5, 0.5), i.e., its center, the ship's position is the position of its center. Positioning the ship at kShipSize.height/2.0f means that half of the ship's height will protrude below its position and half above. If you check the math, you'll see that the ship's bottom aligns exactly with the bottom of the scene. ship.position = CGPointMake(self.size.width / 2.0f, kShipSize.height/2.0f); [self addChild:ship]; } -(SKNode*)makeShip { SKNode* ship = [SKSpriteNode spriteNodeWithColor:[SKColor greenColor] size:kShipSize]; ship.name = kShipName; return ship; } -(void)setupHud { //Sets the score label font to Courier SKLabelNode* scoreLabel = [SKLabelNode labelNodeWithFontNamed:@"Courier"]; //1 - Give the score label a name so it becomes easy to find later when // the score needs to be updated. scoreLabel.name = kScoreHudName; scoreLabel.fontSize = 15; //2 - Color the score label green scoreLabel.fontColor = [SKColor greenColor]; scoreLabel.text = [NSString stringWithFormat:@"Score: %04u", 0]; //3 - Positions the score label near the top left corner of the screen scoreLabel.position = CGPointMake(20 + scoreLabel.frame.size.width/2, self.size.height - (20 + scoreLabel.frame.size.height/2)); [self addChild:scoreLabel]; //Applies the font of the health label SKLabelNode* healthLabel = [SKLabelNode labelNodeWithFontNamed:@"Courier"]; //4 - Give the health label a name so it can be referenced later when it needs // to be updated to display the health healthLabel.name = kHealthHudName; healthLabel.fontSize = 15; //5 - Colors the health label red healthLabel.fontColor = [SKColor redColor]; healthLabel.text = [NSString stringWithFormat:@"Health: %.1f%%", 100.0f]; //6 - Positions the health Label on the upper right hand side of the screen healthLabel.position = CGPointMake(self.size.width - healthLabel.frame.size.width/2 - 20, self.size.height - (20 + healthLabel.frame.size.height/2)); [self addChild:healthLabel]; } #pragma mark - Scene Update - (void)update:(NSTimeInterval)currentTime { //Makes the invaders move [self moveInvadersForUpdate:currentTime]; } #pragma mark - Scene Update Helpers //This method will get invoked by update -(void)moveInvadersForUpdate:(NSTimeInterval)currentTime { //1 - if it's not yet time to move, exit the method. moveInvadersForUpdate: // is invoked 60 times per second, but you don't want the invaders to move // that often since the movement would be too fast to see if (currentTime - self.timeOfLastMove < self.timePerMove) return; //2 - Recall that the scene holds all the invaders as child nodes; which were // added to the scene using addChild: in setupInvaders identifying each invader // by its name property. Invoking enumerateChildNodesWithName:usingBlock only loops over the invaders because they're named kInvaderType; which makes the loop skip the ship and the HUD. The guts og the block moves the invaders 10 pixels either right, left or down depending on the value of invaderMovementDirection [self enumerateChildNodesWithName:kInvaderName usingBlock:^(SKNode *node, BOOL *stop) { switch (self.invaderMovementDirection) { case InvaderMovementDirectionRight: node.position = CGPointMake(node.position.x - 10, node.position.y); break; case InvaderMovementDirectionLeft: node.position = CGPointMake(node.position.x - 10, node.position.y); break; case InvaderMovementDirectionDownThenLeft: case InvaderMovementDirectionDownThenRight: node.position = CGPointMake(node.position.x, node.position.y - 10); break; InvaderMovementDirectionNone: default: break; } }]; //3 - Record that you just moved the invaders, so that the next time this method is invoked (1/60th of a second from when it starts), the invaders won't move again until the set time period of one second has elapsed. self.timeOfLastMove = currentTime; //Makes it so that the invader movement direction changes only when the invaders are actually moving. Invaders only move when the check on self.timeOfLastMove passes (when conditional expression is true) [self determineInvaderMovementDirection]; } #pragma mark - Invader Movement Helpers -(void)determineInvaderMovementDirection { //1 - Since local vars accessed by block are default const(means they cannot be changed), this snippet of code qualifies proposedMovementDirection with __block so that you can modify it in //2 __block InvaderMovementDirection proposedMovementDirection = self.invaderMovementDirection; //2 - Loops over the invaders in the scene and refers to the block with the invader as an argument [self enumerateChildNodesWithName:kInvaderName usingBlock:^(SKNode *node, BOOL *stop) { switch (self.invaderMovementDirection) { case InvaderMovementDirectionRight: //3 - If the invader's right edge is within 1pt of the right edge of the scene, it's about to move offscreen. Sets proposedMovementDirection so that the invaders move down then left. You compare the invader's frame(the frame that contains its content in the scene's coordinate system) with the scene width. Since the scene has an anchorPoint of (0,0) by default and is scaled to fill it's parent view, this comparison ensures you're testing against the view's edges. if (CGRectGetMaxX(node.frame) >= node.scene.size.width - 1.0f) { proposedMovementDirection = InvaderMovementDirectionDownThenLeft; *stop = YES; } break; case InvaderMovementDirectionLeft: //4 - If the invader's left edge is within 1 pt of the left edge of the scene, it's about to move offscreen. Sets the proposedMovementDirection so invaders move down then right if (CGRectGetMinX(node.frame) <= 1.0f) { proposedMovementDirection = InvaderMovementDirectionDownThenRight; *stop = YES; } break; case InvaderMovementDirectionDownThenLeft: //5 - If invaders are moving down then left, they already moved down at this point, so they should now move left. proposedMovementDirection = InvaderMovementDirectionLeft; *stop = YES; break; case InvaderMovementDirectionDownThenRight: //6 - if the invaders are moving down then right, they already moved down so they should now move right. proposedMovementDirection = InvaderMovementDirectionRight; *stop = YES; break; default: break; } }]; //7 - if the proposed invader movement direction is different than the current invader movement direction, update the current direction to the proposed direction if (proposedMovementDirection != self.invaderMovementDirection) { self.invaderMovementDirection = proposedMovementDirection; } } #pragma mark - Bullet Helpers #pragma mark - User Tap Helpers #pragma mark - HUD Helpers #pragma mark - Physics Contact Helpers #pragma mark - Game End Helpers @end

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  • How to make a div extend when floating it?

    - by cjmcjm
    I'm trying to create a bar with a dynamic horizontal width. The backgrounds are transparent pngs so they can't overlap. I have one for the left side, one to repeat-x across the dynamic width middle and then another bg for the right. Here is kinda what I have so far... .bar{ width: 100%; } .left{ width: 50px; height: 50px; float: left; } .mid{ height: 50px; float: left; } .right{ width: 50px; height: 50px; float: right; } <div class="bar"> <div class="left"></div> <div class="mid"></div> <div class="right"></div> </div> So the main problem is extending the .mid all the way across to meet the right, width: 100% doesn't work. The other problems is what can I do if I have content that needs to overlap the .left and .mid divs? Set up another div and use z-index? Thanks so much!

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  • Define Javascript slider hit/rollover area

    - by Rob
    Hey, Im having an issue defining the hit area for a javascript sliding element. See example: http://www.warface.co.uk/clients/warface.co.uk/ Please slide over the grey box on the right side to reveal the button, although this works I would only like for the slider to only be triggered by rolling over the red block. CSS .slidingtwitter { /* -- This is the hit area -- */ background: #ccc; width:255px; height:55px; overflow: hidden; top:50%; right: 0px; /* -- This is the sliding start point -- */ position: fixed; font-family: Gotham, Sans-Serif; z-index: 50; } .slidingtwitter.right { right:0px; } .slidingtwitter .caption { /* -- This is the sliding area -- */ background: #fff; position: absolute; width:260px; height:55px; right: -205px; /* -- This is the sliding start point -- */ } .slidingtwitter a { color: #484848; font-size: 20px; text-transform: uppercase; } .slidingtwitter a:hover { color: black; } .slidingtwitter .smaller { font-size: 12px; font-family: Gotham Medium; } .twitterblock { background: #f35555 url("styles/images/button_twitter.png") no-repeat 14px 15px ; width:35px; height:35px; padding:10px; float:left; display:block; } .slidingtwitter .followme { background: url("styles/images/button_arrowheadthin.jpg")no-repeat right 0; height:35px; display:block; float:left; line-height:14px; width:140px; margin:10px 0px 0px 14px; padding-top:6px; padding-right: 40px; } JS $('.slidingtwitter').hover(function(){ $(".slide", this).stop().animate({right:'0px'},{queue:false,duration:400}); //Position on rollover },function() { $(".slide", this).stop().animate({right:'-205px'},{queue:false,duration:400}); //Position on rollout }); Any suggestions would be much appreciated.

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  • Alternative to position: relative; for overflow: auto; bug in IE7.

    - by Myles
    I have content arranged thusly: <div id="thumbnails" style="width: 40px; overflow: auto;"> <div style="float:left; width: 20px;">content</div> <div style="float:left; width: 20px;">content</div> <div style="float:left; width: 20px;">content</div> <div style="float:left; width: 20px;">content</div> <div style="float:left; width: 20px;">content</div> <div style="float:left; width: 20px;">content</div> In IE7 this shows up with the content running out of the scrollable box. The answer everywhere is to make #thumbnails position:relative. My problem is that the items in #thumbnails are scriptaculous draggables that drag outside of thumbnails with a ghost of the element that is positioned absolutely. This does not go over well if the parent is positioned:relatively because now the absolute positions are relative to #thumbnails and not the <body>. Does anyone know an alternative solution to the IE7 bug?

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  • WP7 - group of textboxes into some sort of template?

    - by Jeff V
    I'm still pretty new at Silverlight so there might be a way to do this, but I'm just unfamiliar with the terminology... I basically have this grouping of textboxes and textblocks and I would like to repeat this same grouping whenever the addNew button is clicked. Is there a way to do this by creating some sort of template? Or do I have to add each item individually. <Grid> <toolkit:ListPicker Height="70" HorizontalAlignment="Right" Name="listPicker1" VerticalAlignment="Top" Width="56" ItemTemplate="{StaticResource PickerItemTemplate}" FullModeItemTemplate="{StaticResource PickerFullModeItemTemplate}" Margin="0,97,167,0"></toolkit:ListPicker> <TextBlock Height="33" HorizontalAlignment="Left" Margin="10,7,0,0" Name="tbDate" Text="Date:" VerticalAlignment="Top" Width="266" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="9,55,0,0" Name="tbItem" Text="Item:" VerticalAlignment="Top" Width="90" /> <TextBox Height="75" HorizontalAlignment="Left" Margin="92,33,0,0" Name="tbItemName" Text="" VerticalAlignment="Top" Width="341" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="5,118,0,0" Name="tbServing" Text="Serving:" VerticalAlignment="Top" Width="99" /> <TextBox Height="70" HorizontalAlignment="Left" Margin="90,96,0,0" Name="tbServingValue" Text="" VerticalAlignment="Top" Width="75" /> <TextBlock Height="42" HorizontalAlignment="Left" Margin="156,120,0,0" Name="tbUOM" Text="UOM:" VerticalAlignment="Top" Width="60" /> <Button Content="" HorizontalAlignment="Right" Height="63" Margin="0,100,13,0" VerticalAlignment="Top" Width="132" RenderTransformOrigin="0.455,0.286" Style="{StaticResource wp7_buttonAddNew}" x:Name="btnAddNewItem" Click="btnAddNewItem_Click"/> </Grid> Thanks!

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  • Does this query fetch unnecessary information? Should I change the query?

    - by Camran
    I have this classifieds website, and I have about 7 tables in MySql where all data is stored. I have one main table, called "classifieds". In the classifieds table, there is a column called classified_id. This is not the PK, or a key whatsoever. It is just a number which is used for me to JOIN table records together. Ex: classifieds table: fordon table: id => 33 id => 12 classified_id => 10 classified_id => 10 ad_id => 'bmw_m3_92923' This above is linked together by the classified_id column. Now to the Q, I use this method to fetch all records WHERE the column ad_id matches any of the values inside an array, called in this case $ad_arr: SELECT mt.*, fordon.*, boende.*, elektronik.*, business.*, hem_inredning.*, hobby.* FROM classified mt LEFT JOIN fordon ON fordon.classified_id = mt.classified_id LEFT JOIN boende ON boende.classified_id = mt.classified_id LEFT JOIN elektronik ON elektronik.classified_id = mt.classified_id LEFT JOIN business ON business.classified_id = mt.classified_id LEFT JOIN hem_inredning ON hem_inredning.classified_id = mt.classified_id LEFT JOIN hobby ON hobby.classified_id = mt.classified_id WHERE mt.ad_id IN ('$ad_arr')"; Is this good or would this actually fetch unnecessary information? Check out this Q I posted couple of days ago. In the comments HLGEM is commenting that it is wrong etc etc. What do you think? http://stackoverflow.com/questions/2782275/another-rookie-question-how-to-implement-count-here Thanks

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  • "Invalid Object Format Name" in Crystal Reports

    - by cmays90
    When working with Crystal Report Field Objects and attempting to set "EnableSuppress" to False or alter the position or width of a field object is generating an "Invalid Object Format Name" error. The debugger shows all my code running without error until attempting to actually load the report. At that point, it will run the first couple without problem, then it fails when messing with a field object, and none of the rest will run. The code is shown below. Everything that generates an error is a FieldObject, but not all fieldObjects generate errors. In the code below, everything in Section2 is a TextObject and everything in Section3 is a FieldObject. If condition = True Then 'Lines marked as runs ok, only run when a line that generates an error is not present before it. Report.Section2.ReportObjects("Text7").Left = 7830 'Runs ok Report.Section3.ReportObjects("Field4").Left = 8085 'Runs ok Report.Section2.ReportObjects("Text13").ObjectFormat.EnableSuppress = False 'Runs ok Report.Section3.ReportObjects("Field28").ObjectFormat.EnableSuppress = False 'error Report.Section2.ReportObjects("Text9").Left = 10830 'Runs ok Report.Section3.ReportObjects("Field23").Left = 10830 'error Report.Section3.ReportObjects("Field23").Width = 615 'error Report.Section2.ReportObjects("Text10").Left = 11445 'Runs ok Report.Section3.ReportObjects("Field25").Left = 11445 'Runs ok End If

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  • Python: Behavior of object in set operations

    - by Josh Arenberg
    I'm trying to create a custom object that behaves properly in set operations. I've generally got it working, but I want to make sure I fully understand the implications. In particular, I'm interested in the behavior when there is additional data in the object that is not included in the equal / hash methods. It seems that in the 'intersection' operation, it returns the set of objects that are being compared to, where the 'union' operations returns the set of objects that are being compared. To illustrate: class MyObject: def __init__(self,value,meta): self.value = value self.meta = meta def __eq__(self,other): if self.value == other.value: return True else: return False def __hash__(self): return hash(self.value) a = MyObject('1','left') b = MyObject('1','right') c = MyObject('2','left') d = MyObject('2','right') e = MyObject('3','left') print a == b # True print a == c # False for i in set([a,c,e]).intersection(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 right #2 right for i in set([a,c,e]).union(set([b,d])): print "%s %s" % (i.value,i.meta) #returns: #1 left #3 left #2 left Is this behavior documented somewhere and deterministic? If so, what is the governing principle?

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  • how to get the child node in div using javascript

    - by Khushi
    Below is the structure of my div: <div id="ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a" onmouseup="checkMultipleSelection(this,event);"> <table cellpadding="0" cellspacing="0" border="0" width="100%"> <tr> <td style="width:50px; text-align:left;">09:15 AM</td> <td style="width:50px; text-align:left;">Item001</td> <td style="width:50px; text-align:left;">10</td> <td style="width:50px; text-align:left;">Address1</td> <td style="width:50px; text-align:left;">46545465</td> <td style="width:50px; text-align:left;">ref1</td> </tr> </table> </div> Now, if i have the id of the div, how can i get the time and address for this div using JavaScript? Thanks & Regards, Khushi

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  • HTML columns or rows for form layout?

    - by Valera
    I'm building a bunch of forms that have labels and corresponding fields (input element or more complex elements). Labels go on the left, fields go on the right. Labels in a given form should all be a specific width so that the fields all line up vertically. There are two ways (maybe more?) of achieving this: Rows: Float each label and each field left. Put each label and field in a field-row div/container. Set label width to some specific number. With this approach labels on different forms will have different widths, because they'll depend on the width of the text in the longest label. Columns: Put all labels in one div/container that's floated left, put all fields in another floated left container with padding-left set. This way the labels and even the label container don't need to have their widths set, because the column layout and the padding-left will uniformly take care of vertically lining up all the fields. So approach #2 seems to be easier to implement (because the widths don't need to be set all the time), but I think it's also less object oriented, because a label and a field that goes with that label are not grouped together, as they are in approach #1. Also, if building forms dynamically, approach #2 doesn't work as well with functions like addRow(label, field), since it would have to know about the label and the field containers, instead of just creating/adding one field-row element. Which approach do you think is better? Is there another, better approach than these two?

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  • Correct Display configuration. Errors while trying to arrange displays

    - by David Russell Parrish Bojrquez
    I am trying to set up my tv with my laptop trough a VGA cable. The display application in Ubuntu throws a lot of errors to me and I have given up in trying to do it myself. I try to apply the 1920 1080 display. The selected configuration for displays could not be applied Requested size (3200, 1080) exceeds 3D hardware limit (2048, 2048). You must either rearrange the displays so that they fit within a (2048, 2048) square or select the Ubuntu 2D session at login. And Also this: Failed to apply configuration: %s GDBus.Error:org.gtk.GDBus.UnmappedGError.Quark._gnome_2drr_2derror_2dquark.Code3: Requested size (3200, 1080) exceeds 3D hardware limit (2048, 2048). You must either rearrange the displays so that they fit within a (2048, 2048) square or select the Ubuntu 2D session at login. Please Help. @Leozitop No I don't see anything when connected to 1920 1080 because the setup fails before actually applying. Yes there are other resolutions which do work. I believe the problem has something to do with the rotation it is set up. My Ubuntu Display application has only clockwise and counterclockwise options for the TV display. I really don't know why this is happening. Basic procedure: Plug in cable, did not get the resolution I wanted. Changed settings, applied them. Re-peat until desired display is shown. I'm not a computer illiterate, really it baffles me that this is happening. Output of xrandr: david@LapUbuntu:~$ xrandr Screen 0: minimum 320 x 200, current 1880 x 800, maximum 4096 x 4096 LVDS1 connected 1280x800+0+0 (normal left inverted right x axis y axis) 331mm x 207mm 1280x800 60.0*+ 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 connected 600x800+1280+0 left (normal left inverted right x axis y axis) 1600mm x 900mm 1920x1080 60.0 + 1280x1024 60.0 1360x768 60.0 1280x720 60.0 1024x768 60.0 800x600 60.3* 640x480 60.0 TV1 unknown connection (normal left inverted right x axis y axis) 848x480 59.9 + 640x480 59.9 + 1024x768 59.9 800x600 59.9 Note that VGA says left and indeed it is, but no other option was available in the display. Also, note the TV1 unknown connection which I have no idea what it is. Note, also, that this has nothing to do with the display since W7 on the computer works fine and since while boot up, and also, before starting session in ubuntu the rotation is normal. I'll also mention that I HAVE re-installed Ubuntu since I had posted this question from a Live CD of 12.04 LTS. And that before the posting of the question also using 12.04 before another backup that I had to do, the VGA setup was fine without any problems.

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  • Vote of Disconfidence to Entity Framework

    - by Ricardo Peres
    A friend of mine has found the following problem with Entity Framework 4: Two simple classes and one association between them (one to many): One condition to filter out soft-deleted entities (WHERE Deleted = 0): 100 records in the database; A simple query: 1: var l = ctx.Person.Include("Address").Where(x => (x.Address.Name == "317 Oak Blvd." && x.Address.Number == 926) || (x.Address.Name == "891 White Milton Drive" && x.Address.Number == 497)); Will produce the following SQL: 1: SELECT 2: [Extent1].[Id] AS [Id], 3: [Extent1].[FullName] AS [FullName], 4: [Extent1].[AddressId] AS [AddressId], 5: [Extent202].[Id] AS [Id1], 6: [Extent202].[Name] AS [Name], 7: [Extent202].[Number] AS [Number] 8: FROM [dbo].[Person] AS [Extent1] 9: LEFT OUTER JOIN [dbo].[Address] AS [Extent2] ON ([Extent2].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent2].[Id]) 10: LEFT OUTER JOIN [dbo].[Address] AS [Extent3] ON ([Extent3].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent3].[Id]) 11: LEFT OUTER JOIN [dbo].[Address] AS [Extent4] ON ([Extent4].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent4].[Id]) 12: LEFT OUTER JOIN [dbo].[Address] AS [Extent5] ON ([Extent5].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent5].[Id]) 13: LEFT OUTER JOIN [dbo].[Address] AS [Extent6] ON ([Extent6].[Deleted] = 0) AND ([Extent1].[AddressId] = [Extent6].[Id]) 14: ... 15: WHERE ((N'317 Oak Blvd.' = [Extent2].[Name]) AND (926 = [Extent3].[Number])) 16: ... And will result in 680 MB of memory being taken! Now, Entity Framework has been historically known for producing less than optimal SQL, but 680 MB for 100 entities?! According to Microsoft, the problem will be addressed in the following version, there is a Connect issue open. There is even a whitepaper, Performance Considerations for Entity Framework 5, which talks about some of the changes and optimizations coming on version 5, but by reading it, I got even more concerned: “Once the cache contains a set number of entries (800), we start a timer that periodically (once-per-minute) sweeps the cache.” Say what?! The next version of Entity Framework will spawn timer threads?! When Code First came along, I thought it was a step in the right direction. Sure, it didn’t include some things that NHibernate did for quite some time – for example, different strategies for Id generation that do not rely on IDENTITY columns, which makes INSERT batching impossible, or support for enumerated types – but I thought these would come with the time. Now, enumerated types have, but so did… timer threads! I’m afraid Entity Framework is becoming a monster.

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  • What is this JavaScript gibberish?

    - by W3Geek
    I am studying how to make a 2D game with JavaScript by reading open source JavaScript games and I came across this gibberish... aSpriteData = [ "}\"¹-º\"À+º\"À+º\"À+º\"¿¤À ~C_ +º\"À+º\"À+º\"À*P7²OK%¾+½u_\"À<¡a¡a¡bM@±@ª", // 0 ground "a ' ![± 7°³b£[mt<Nµ7z]~¨OR»[f_7l},tl},+}%XN²Sb[bl£[±%Y_¹ !@ $", // 1 qbox "!A % @,[] ±}°@;µn¦&X£ <$ §¤ 8}}@Prc'U#Z'H'@· ¶\"is ¤&08@£(", // 2 mario " ´!A.@H#q8¸»e-½n®@±oW:&X¢a<&bbX~# }LWP41}k¬#3¨q#1f RQ@@:4@$", // 3 mario jump " 40 q$!hWa-½n¦#_Y}a©,0#aaPw@=cmY<mq©GBagaq&@q#0§0t0¤ $", // 4 mario run "+hP_@", // 5 pipe left "¢,6< R¤", // 6 pipe right "@ & ,'+hP?>³®'©}[!»¹.¢_^¥y/pX¸#µ°=a¾½hP?>³®'©}[!»¹.¢_^ Ba a", // 7 pipe top left "@ , !] \"º £] , 8O #7a&+¢ §²!cº 9] P &O ,4 e", // 8 pipe top right " £ #! ,! P!!vawd/XO¤8¼'¤P½»¹²'9¨ \"P²Pa²(!¢5!N*(4´b!Gk(a", // 9 goomba " Xu X5 =ou!¯­¬a[Z¼q.°u#|xv ¸··@=~^H'WOJ!¯­¬a=Nu ²J <J a", // 10 coin // yui "@ & !MX ~L \"y %P *¢ 5a K w !L \"y %P *­a%¬¢ 4 a", // 11 ebox // yui "¢ ,\"²+aN!@ &7 }\"²+aN!XH # }\"²+aN!X% 8}\"²+aN!X%£@ (", // 12 bricks "} %¿¢!N° I¨²*<P%.8\"h,!Cg r¥ H³a4X¢*<P%.H#I¬ :a!u !q", // 13 block makeSpace(20) + "4a }@ }0 N( w$ }\" N! +aa", // 14 bush left " r \"²y!L%aN zPN NyN#²L}[/cy¾ N" + makeSpace(18) + "@", // 15 bush mid makeSpace(18) + "++ !R·a!x6 &+6 87L ¢6 P+ 8+ (", // 16 bush right " %©¦ +pq 7> \"³ s" + makeSpace(25) + "@", // 17 cloud bottom left "a/a_#².Q¥'¥b}8.£¨7!X\"K+5cqs%(" + makeSpace(18) + "0", // 18 cloud bottom mid "bP ¢L P+ 8%a,*a%§@ J" + makeSpace(22) + "(", // 19 cloud bottom right "", // 20 mushroom "", // koopa 16x24 "", // 22 star "", // 23 flagpole "", // 24 flag "", // 25 flagpole top " 6 ~ }a }@ }0 }( }$ }\" }! } a} @} 0} (} $} \"² $", // 26 hill slope "a } \"m %8 *P!MF 5la\"y %P" + makeSpace(18) + "(", // 27 hill mid makeSpace(30) + "%\" t!DK \"q", // 28 hill top "", // 29 castle bricks "", // 30 castle doorway bottom "", // 31 castle doorway top "", // 32 castle top "", // 33 castle top 2 "", // 34 castle window right "", // 35 castle window left "", // 36 castle flag makeSpace(19) + "8@# (9F*RSf.8 A¢$!¢040HD", // 37 goomba flat " *(!¬#q³¡[_´Yp~¡=<¥g=&'PaS²¿ Sbq*<I#*£Ld%Ryd%¼½e8H8bf#0a", // 38 mario dead " = ³ #b 'N¶ Z½Z Z½Z Z½Z Z½Z Z½Z Z½Z =[q ²@ ³ ¶ 0", // 39 coin step 1 " ?@ /q /e '¤ #³ !ºa }@ N0 ?( /e '¤ #³ ¿ _a \"", // 40 coin step 2 " / > ] º !² #¢ %a + > ] º !² #¢ 'a \"", // 41 coin step 3 " 7¢ +² *] %> \"p !Ga t¢ I² 4º *] %> \"p ¡ Oa \"" // 42 coin step 4 ], What does it do? If you want to look at the source file here it is: http://www.nihilogic.dk/labs/mario/mario.js Beware, there is more gibberish inside. I can't seem to make sense of any of it. Thank you.

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  • 2D collision resolving

    - by Philippe Paré
    I've just worked out an AABB collision algorithm for my 2D game and I was very satisfied until I found out it only works properly with movements of 1 in X and 1 in Y... here it is: public bool Intersects(Rectanglef rectangle) { return this.Left < rectangle.Right && this.Right > rectangle.Left && this.Top < rectangle.Bottom && this.Bottom > rectangle.Top; } public bool IntersectsAny(params Rectanglef[] rectangles) { for (int i = 0; i < rectangles.Length; i++) { if (this.Left < rectangles[i].Right && this.Right > rectangles[i].Left && this.Top < rectangles[i].Bottom && this.Bottom > rectangles[i].Top) return true; } return false; } and here is how I use it in the update function of my player : public void Update(GameTime gameTime) { Rectanglef nextPosX = new Rectanglef(AABB.X, AABB.Y, AABB.Width, AABB.Height); Rectanglef nextPosY; if (Input.Key(Key.Left)) nextPosX.X--; if (Input.Key(Key.Right)) nextPosX.X++; bool xFree = !nextPosX.IntersectsAny(Boxes.ToArray()); if (xFree) nextPosY = new Rectanglef(nextPosX.X, nextPosX.Y, nextPosX.Width, nextPosX.Height); else nextPosY = new Rectanglef(AABB.X, AABB.Y, AABB.Width, AABB.Height); if (Input.Key(Key.Up)) nextPosY.Y--; if (Input.Key(Key.Down)) nextPosY.Y++; bool yFree = !nextPosY.IntersectsAny(Boxes.ToArray()); if (yFree) AABB = nextPosY; else if (xFree) AABB = nextPosX; } What I'm having trouble with, is a system where I can give float values to my movement and make it so there's a smooth acceleration. Do I have to retrieve the collision rectangle (the rectangle created by the other two colliding)? or should I do some sort of vector and go along this axis until I reach the collision? Thanks a lot!

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  • Search option: jqGrid + PHP

    - by Felix Guerrero
    Hi, I'm trying to get work this code: $("#list").jqGrid({ url: 'docente.php', datatype: 'json', mtype: 'POST', postData: {c : "", n: "", a: "", d: "", t: "", e: "", f: "", g: $('#selectD').value(), p: "", call: "report"}, colNames: ['C&eacute;dula','Nombres', 'Apellidos', 'Direcci&oacute;n', 'E-mail','Tel&eacute;fono', 'Profesi&oacute;n'], colModel: [ { name:'rows.cedula', index: 'cedula', search:true, jsonmap: 'cedula', width: 150, align: 'left', sortable:true}, { name:'rows.nombre', index: 'nombre', jsonmap: 'nombre', width: 150, align: 'left'}, { name:'rows.apellido', index: 'apellido', jsonmap: 'apellido', width: 240, align: 'left'}, { name:'rows.direccion', index: 'direccion', jsonmap: 'direccion', width: 330, align: 'left'}, { name:'rows.email', index: 'email', jsonmap: 'email',width: 200, align: 'left'}, { name:'rows.telefono', index: 'telefono', jsonmap: 'telefono', width: 170, align: 'left'}, { name:'rows.descripcion_profesion', index: 'descripcion_profesion', jsonmap: 'descripcion_profesion',width: 120, align: 'left'}], pager: '#pager', rowNum: 8, autowidth: true, rowList: [10, 20], sortname: 'cedula', sortorder: 'asc', viewrecords: true, caption: 'Docentes', jsonReader : { root: "rows", repeatitems: false }, height: 350, width: 900 }); $("#list").jqGrid('navGrid','#pager',{search:true, searchtext: "buscar",edit:false,add:false,del:false}); The HMTL I'm using: <div id="reporte"> <table id="list"></table> <div id="pager"> </div> <div> And the PHP code: $total_pages = 0; $limit=10; $count = Profesor::CountAll(); if($count> 0) $total_pages= ceil($count/$limit); else $total_pages=0; $cnx = new PDO("mysql:host=localhost;dbname=appsms","root",""); $rows = array(); $strQuery="select cedula, nombre, apellido, direccion, telefono, email, descripcion_profesion from Profesor join Profesion on " . " (profesor.profesion_id = profesion.id) and (profesor.grado_id_grado = '" .$this->grado . "') order by cedula;"; $stmt = $cnx->prepare($strQuery); $stmt->execute(array("reporte")); $rows = $stmt->fetchAll(PDO::FETCH_ASSOC); $response->page = 1; $response->total= $total_pages; $response->records = sizeof($rows); $i=0; foreach($rows as $result){ $response->rows[$i] = $result; $i++; } echo json_encode($response); The JSON I get: {"page":1,"total":1,"records":2, "rows":[{"cedula":"v-108984103","nombre":"Soneia","apellido":"Rond\u00f3n Contreras","direccion":"El Rosal, calle 2-44","telefono":"04544247008457","email":"[email protected]","descripcion_profesion":"Docente"}, {"cedula":"v-135254741","nombre":"Judith","apellido":"Rangel M\u00e1rquez","direccion":"Sabaneta","telefono":"04247644152499","email":"","descripcion_profesion":"Docente"}]} It loads the query from PHP but the search option doesn't work neither the sorting function on "cedula"'s column. What I need to do?. Thanks in advance.

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  • Jquery flowplayer - tabs - content inside div tags not displaying

    - by Gublooo
    Hey guys, I'm looking for a simple example of JQuery tabs in which I am planning to show two different forms. I came across this example http://flowplayer.org/tools/demos/tabs/index.htm which is perfect for my needs. So I implemented the simple example. The code in question is: <div class="panes" <divFirst tab content. Tab contents are called "panes"</div <divSecond tab content</div <divThird tab content</div </div Now my content for the first tab is a form which has several of its own div tags - when I put that form with div tags as the content for the first tab - nothing appears. So I made a simple change and added another div tag to the content of the first tab as shown below and still nothing appears: <div class="panes" <div<divFirst tab content. Tab contents are called "panes"</div</div <divSecond tab content</div <divThird tab content</div </div Is there a simple way to fix this. This is the content that I want to display in my first tab - Thanks for your help <div id="formbox" class="formbox" <form id="shopping_form" method="post" <div id="3" style="width:520px;" <textarea id="message" name="message" rows="3" cols="50"</textarea </div <div id="store_row" style="width:220px;float:left;padding-bottom:10px;"<bStore</b <input type="text" id="store" name="store" class="required" size="20" / <input type="hidden" id="store_id"/ </div <div id="city_column" style="width:200px;float:left;padding-bottom:10px;"<bCity</b <input type="text" id="city" name="city" size="15"/ </div <div id="findbutton_column" style="vertical-align:top;width:80px;float:left;" <input class="find_address" id="findaddress" type="button" value="Find Store"/ </div <div id="googlerow" style="width:120px;float:left;padding-bottom:10px;" <bSelect Store</b<select id="google_stores" name="google_stores"</select <input type="hidden" id="google_address"/ </div <div id="google_message" style="float:left;padding-bottom:10px;display:none;"</div <div id="locationrow" style="float:left;padding-bottom:10px;display:none;" <bAddress/Country</b <input type="text" id="address" name="address" size="20" / <input type="text" id="country" name="country" size="20"/ </div <div style="width:520px;float:left;padding-bottom:10px;" <bPrice    <input type="text" id="price" name="price" size="20" / </div <div id="buttonrow" style="width:200px;float:right;display:none;" <input id="it" type="image" src="http://images.pe.com.s3.amazonaws.com/it.png" height="35px"/ </div </form </div

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  • Binary Search Tree in C

    - by heapzero
    Hi, I'm a Python guy. Learning C language and I've been trying to implement Binary Search Tree in C. I wrote down the code, and I've been trying from few hours but, not able to get the output as expected. Please help! Please correct me. #include<stdlib.h> #include<stdio.h> typedef int ElementType; typedef struct TreeNode { ElementType element; struct TreeNode *left, *right; } TreeNode; TreeNode *createTree(){ //Create the root of tree TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = 0; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *createNode(ElementType X){ //Create a new leaf node and return the pointer TreeNode *tempNode; tempNode = malloc(sizeof(TreeNode)); tempNode->element = X; tempNode->left = NULL; tempNode->right = NULL; return tempNode; } TreeNode *insertElement(TreeNode *node, ElementType X){ //insert element to Tree if(node==NULL){ return createNode(X); } else{ if(X < node->element){ node->left = insertElement(node->left, X); } else if(X > node->element){ node->right = insertElement(node->right, X); } else if(X == node->element){ printf("Oops! the element is already present in the tree."); } } } TreeNode *displayTree(TreeNode *node){ //display the full tree if(node==NULL){ return; } displayTree(node->left); printf("| %d ", node->element); displayTree(node->right); } main(){ //pointer to root of tree #2 TreeNode *TreePtr; TreeNode *TreeRoot; TreeNode *TreeChild; //Create the root of tree TreePtr = createTree(); TreeRoot = TreePtr; TreeRoot->element = 32; printf("%d\n",TreeRoot->element); insertElement(TreeRoot, 8); TreeChild = TreeRoot->left; printf("%d\n",TreeChild->element); insertElement(TreeRoot, 2); insertElement(TreeRoot, 7); insertElement(TreeRoot, 42); insertElement(TreeRoot, 28); insertElement(TreeRoot, 1); insertElement(TreeRoot, 4); insertElement(TreeRoot, 5); // the output is not as expected :( displayTree(TreeRoot); }

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  • How to create sliding drawer in both sides opposite to one another?

    - by janmejoy
    I have added the code that working for right to left sliding perfectly but i want sliding from left to right also so check the layout and help me out.Here i have mentioned the layout properly for right to left ,Is it possible to get the Slider window in both sides i mean left and right horizontally... <?xml version="1.0" encoding="utf-8"?> <FrameLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent" android:layout_height="match_parent" android:background="@drawable/bg" android:orientation="vertical" > <Button android:id="@+id/ship" android:layout_width="186dp" android:layout_height="23dp" android:layout_marginTop="49dp" android:background="@drawable/signup" android:text="Shipping Calculator" android:textColor="#ffffffff" android:layout_gravity="center" android:textStyle="bold" /> </LinearLayout> <SlidingDrawer android:id="@+id/drawer" android:layout_width="match_parent" android:layout_height="match_parent" android:orientation="horizontal" android:handle="@+id/handle" android:content="@+id/content"> <ImageView android:id="@+id/handle" android:layout_width="wrap_content" android:layout_height="fill_parent" android:src="@drawable/tag"/> <LinearLayout android:id="@+id/content" android:layout_width="wrap_content" android:layout_height="fill_parent" android:background="@drawable/slidimage" android:orientation="vertical" android:padding="10dp" > <TextView android:id="@+id/text1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="center" android:layout_marginTop="15dp" android:layout_marginLeft="51dp" android:text="SIGN-UP" android:textColor="#000000" android:textSize="28dp" android:textStyle="bold" /> </LinearLayout> </SlidingDrawer> <SlidingDrawer android:id="@+id/drawers" android:layout_width="match_parent" android:layout_height="match_parent" android:handle="@+id/handles" android:layout_gravity="left" android:scrollX="100dp" android:orientation="horizontal" android:content="@+id/contents"> <ImageView android:id="@+id/handles" android:layout_width="wrap_content" android:layout_height="fill_parent" android:layout_gravity="left" android:src="@drawable/tag"/> <LinearLayout android:id="@+id/contents" android:layout_width="wrap_content" android:layout_height="fill_parent" android:layout_gravity="left" android:background="@drawable/slidimage" android:orientation="vertical" android:padding="10dp" > <TextView android:id="@+id/text1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="center" android:layout_marginTop="15dp" android:layout_marginLeft="51dp" android:text="SIGN-UP" android:textColor="#000000" android:textSize="28dp" android:textStyle="bold" /> </LinearLayout> </SlidingDrawer> </FrameLayout>

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  • z-index of DIV positioned on top of another div

    - by Elie
    I have two div containers which are structured as follows: <div class="outer-div"> <img src="images/point.png" class="img-a1"> <img src="images/point.png" class="img-a2"> Lots of text goes here. </div> <div class="outer-div"> <img src="images/point.png" class="img-a1"> <img src="images/point.png" class="img-b2"> Some more text goes here </div> The styles associated with this are as follows: .outer-div { position: absolute; top: 0px; left: 0px; width: 500px; } .img-a1 { float:left; z-index:-1; position:relative; margin-left: 250px; margin-bottom: 100px; } .img-b1 { float:right; z-index:-1; position:relative; margin-left: 250px; margin-bottom: 100px; } img-a2 { float:left; z-index:-1; position:relative; margin-left: 400px; margin-bottom: 200px; } img-b2 { float:right; z-index:-1; position:relative; margin-left: 400px; margin-bottom: 200px; } The result of this is to produce something like the following, where ... is the text from div-a and ||| is the text from div-b: .....||||| .....||||| .. || .. || However, since the second div is placed immediately above the first div, none of the text in the second div can be selected, although it can be seen since there is just empty space, and a 1x1 px image above it. Is there a way to get the text from the lower div to be selectable, without making the upper div unselectable?

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