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  • form submitting with mechanize and Python

    - by MATELIN Alexis
    I'm trying to scrap a website that requires to submit two forms : a first one to loggin and a second one to specify my research. I'm using Python and the mechanize package. No problem with the first one, but i just can't figure out how to pass through the second one. Here is the part of my code related to the firm above-mentionned agemin=18 agemax=25 by='region' country='France' region=2 newcustomers=1 browser.select_form(nr=0) browser['age[min]']=agemin browser['age[max]']=agemax browser['country']=country browser['region']=region browser['by']=by browser['new-customers']=newcustomers response=browser.submit() content=response.read() but when I submit the variable 'age[min]' by example, I get the following error message : TypeError: object of type 'int' has no len() to give you some more informations, here is what I get with 'print br.form' <POST http://www.adopteunmec.com/qsearch/ajax_quick application/x-www-form-urlencoded <SelectControl(age[min]=[, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, *30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])> <SelectControl(age[max]=[, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, *45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99])> <SelectControl(by=[*region, distance])> <SelectControl(country=[*fr, be, ch, ca])> <SelectControl(region=[*1, 2, 3, 4, 5, 6, 7, 8, 22, 23, 9, 10, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 11])> <SelectControl(distance[min]=[*, 0, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250, 260, 270, 280, 290, 300, 310, 320, 330, 340, 350, 360, 370, 380, 390, 400, 410, 420, 430, 440, 450, 460, 470, 480, 490, 500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600, 610, 620, 630, 640, 650, 660, 670, 680, 690, 700, 710, 720, 730, 740, 750, 760, 770, 780, 790, 800, 810, 820, 830, 840, 850, 860, 870, 880, 890, 900, 910, 920, 930, 940, 950, 960, 970, 980, 990, 1000])> <SelectControl(distance[max]=[, 0, 10, 20, 30, 40, 50, 60, 70, *80, 90, 100, 110, 120, 130, 140, 150, 160, 170, 180, 190, 200, 210, 220, 230, 240, 250, 260, 270, 280, 290, 300, 310, 320, 330, 340, 350, 360, 370, 380, 390, 400, 410, 420, 430, 440, 450, 460, 470, 480, 490, 500, 510, 520, 530, 540, 550, 560, 570, 580, 590, 600, 610, 620, 630, 640, 650, 660, 670, 680, 690, 700, 710, 720, 730, 740, 750, 760, 770, 780, 790, 800, 810, 820, 830, 840, 850, 860, 870, 880, 890, 900, 910, 920, 930, 940, 950, 960, 970, 980, 990, 1000])> <CheckboxControl(new=[*1])>> My guess is that the form needs an object (like a list) containing all the variables to accept it ; that's why it refuses the variables submited one by one. Thank you in advance for any help ! Alexis

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  • Application shows low memory warning and crashes while loading images?

    - by Bhoomi
    I am using following code for loading images from server using following code.When i scroll UITableView application crashes. AsynchrohousImageView class .m file - (void)dealloc { [connection cancel]; //in case the URL is still downloading [connection release]; [data release]; [_imageView release]; [_activityIndicator release]; [super dealloc]; } - (void)loadImageFromURL:(NSURL*)url defaultImageName:(NSString *)defaultImageName showDefaultImage:(BOOL)defaultImageIsShown showActivityIndicator:(BOOL)activityIndicatorIsShown activityIndicatorRect:(CGRect)activityIndicatorRect activityIndicatorStyle:(UIActivityIndicatorViewStyle)activityIndicatorStyle { if (connection!=nil) { [connection release]; } if (data!=nil) { [data release]; } if ([[self subviews] count]>0) { [[[self subviews] objectAtIndex:0] removeFromSuperview]; // } if (defaultImageIsShown) { self.imageView = [[[UIImageView alloc] initWithImage:[UIImage imageNamed:defaultImageName]] autorelease]; } else { self.imageView = [[[UIImageView alloc] init] autorelease]; } [self addSubview:_imageView]; _imageView.frame = self.bounds; [_imageView setNeedsLayout]; [self setNeedsLayout]; if (activityIndicatorIsShown) { self.activityIndicator = [[[UIActivityIndicatorView alloc] initWithActivityIndicatorStyle:activityIndicatorStyle] autorelease]; [self addSubview:_activityIndicator]; _activityIndicator.frame = activityIndicatorRect; _activityIndicator.center = CGPointMake(_imageView.frame.size.width/2, _imageView.frame.size.height/2); [_activityIndicator setHidesWhenStopped:YES]; [_activityIndicator startAnimating]; } NSURLRequest* request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; } - (void)connection:(NSURLConnection *)theConnection didReceiveData:(NSData *)incrementalData { if (data==nil) { data = [[NSMutableData alloc] initWithCapacity:2048]; } [data appendData:incrementalData]; } - (void)connectionDidFinishLoading:(NSURLConnection*)theConnection { [connection release]; connection=nil; _imageView.image = [UIImage imageWithData:data]; if (_activityIndicator) { [_activityIndicator stopAnimating]; } [data release]; data=nil; } - (UIImage*) image { UIImageView* iv = [[self subviews] objectAtIndex:0]; return [iv image]; } In ViewController Class Which loads image - (UITableViewCell *)tableView:(UITableView *)tV cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *reuseIdentifier =@"CellIdentifier"; ListCell *cell = (ListCell *)[tableView dequeueReusableCellWithIdentifier:reuseIdentifier]; if (cell==nil) { cell = [[ListCell alloc]initWithStyle:UITableViewCellStyleDefault reuseIdentifier:reuseIdentifier]; NSMutableDictionary *dicResult = [arrResults objectAtIndex:indexPath.row]; NSURL *url=[NSURL URLWithString:[dicResult objectForKey:@"Image"]]; AsynchronousImageView *asyncImageView = [[AsynchronousImageView alloc] initWithFrame:CGRectMake(5, 10,80,80)]; [asyncImageView loadImageFromURL:url defaultImageName:@"DefaultImage.png" showDefaultImage:NO showActivityIndicator:YES activityIndicatorRect:CGRectMake(5, 10,30,30) activityIndicatorStyle:UIActivityIndicatorViewStyleGray]; // load our image with URL asynchronously [cell.contentView addSubview:asyncImageView]; // cell.imgLocationView.image = [UIImage imageNamed:[dicResult valueForKey:@"Image"]]; [asyncImageView release]; } if([arrResults count]==1) { UITableViewCell *cell1=[tableView dequeueReusableCellWithIdentifier:reuseIdentifier]; if(cell1==nil) cell1=[[[UITableViewCell alloc]initWithStyle:UITableViewCellStyleDefault reuseIdentifier:reuseIdentifier] autorelease]; NSMutableDictionary *dicResult = [arrResults objectAtIndex:0]; cell1.textLabel.text=[dicResult valueForKey:@"NoResults"]; return cell1; } else { NSMutableDictionary *dicResult = [arrResults objectAtIndex:indexPath.row]; NSString *title = [NSString stringWithFormat:@"%@ Bedrooms-%@", [dicResult valueForKey:KEY_NUMBER_OF_BEDROOMS],[dicResult valueForKey:KEY_PROPERTY_TYPE]]; NSString *strAddress = [dicResult valueForKey:KEY_DISPLAY_NAME]; NSString *address = [strAddress stringByReplacingOccurrencesOfString:@", " withString:@"\n"]; NSString *price = [dicResult valueForKey:KEY_PRICE]; NSString *distance = [dicResult valueForKey:KEY_DISTANCE]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; cell.lblTitle.text = title; cell.lblAddress.text = address; if ([price length]>0) { cell.lblPrice.text = [NSString stringWithFormat:@"£%@",price]; }else{ cell.lblPrice.text = @""; } if ([distance length]>0) { cell.lblmiles.text = [NSString stringWithFormat:@"%.2f miles",[distance floatValue]]; }else{ cell.lblmiles.text = @""; } } return cell; } How can i resolve this? I have attached heapshot analysis screen shot of it.Here non Object consumes so much of memory what is that?

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  • Java code optimization leads to numerical inaccuracies and errors

    - by rano
    I'm trying to implement a version of the Fuzzy C-Means algorithm in Java and I'm trying to do some optimization by computing just once everything that can be computed just once. This is an iterative algorithm and regarding the updating of a matrix, the clusters x pixels membership matrix U, this is the update rule I want to optimize: where the x are the element of a matrix X (pixels x features) and v belongs to the matrix V (clusters x features). And m is a parameter that ranges from 1.1 to infinity. The distance used is the euclidean norm. If I had to implement this formula in a banal way I'd do: for(int i = 0; i < X.length; i++) { int count = 0; for(int j = 0; j < V.length; j++) { double num = D[i][j]; double sumTerms = 0; for(int k = 0; k < V.length; k++) { double thisDistance = D[i][k]; sumTerms += Math.pow(num / thisDistance, (1.0 / (m - 1.0))); } U[i][j] = (float) (1f / sumTerms); } } In this way some optimization is already done, I precomputed all the possible squared distances between X and V and stored them in a matrix D but that is not enough, since I'm cycling througn the elements of V two times resulting in two nested loops. Looking at the formula the numerator of the fraction is independent of the sum so I can compute numerator and denominator independently and the denominator can be computed just once for each pixel. So I came to a solution like this: int nClusters = V.length; double exp = (1.0 / (m - 1.0)); for(int i = 0; i < X.length; i++) { int count = 0; for(int j = 0; j < nClusters; j++) { double distance = D[i][j]; double denominator = D[i][nClusters]; double numerator = Math.pow(distance, exp); U[i][j] = (float) (1f / (numerator * denominator)); } } Where I precomputed the denominator into an additional column of the matrix D while I was computing the distances: for (int i = 0; i < X.length; i++) { for (int j = 0; j < V.length; j++) { double sum = 0; for (int k = 0; k < nDims; k++) { final double d = X[i][k] - V[j][k]; sum += d * d; } D[i][j] = sum; D[i][B.length] += Math.pow(1 / D[i][j], exp); } } By doing so I encounter numerical differences between the 'banal' computation and the second one that leads to different numerical value in U (not in the first iterates but soon enough). I guess that the problem is that exponentiate very small numbers to high values (the elements of U can range from 0.0 to 1.0 and exp , for m = 1.1, is 10) leads to ver y small values, whereas by dividing the numerator and the denominator and THEN exponentiating the result seems to be better numerically. The problem is it involves much more operations. Am I doing something wrong? Is there a possible solution to get both the code optimized and numerically stable? Any suggestion or criticism will be appreciated.

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  • Changes to data inside class not being shown when accessed from outside class.

    - by Hypatia
    I have two classes, Car and Person. Car has as one of its members an instance of Person, driver. I want to move a car, while keeping track of its location, and also move the driver inside the car and get its location. However, while this works from inside the class (I have printed out the values as they are calculated), when I try to access the data from main, there's nothing there. I.e. the array position[] ends up empty. I am wondering if there is something wrong with the way I have set up the classes -- could it be a problem of the scope of the object? I have tried simplifying the code so that I only give what is necessary. Hopefully that covers everything that you would need to see. The constructer Car() fills the offset array of driver with nonzero values. class Car{ public: Container(float=0,float=0,float=0); ~Container(); void move(float); void getPosition(float[]); void getDriverPosition(float[]); private: float position[3]; Person driver; float heading; float velocity; }; class Person{ public: Person(float=0,float=0,float=0); ~Person(); void setOffset(float=0,float=0,float=0); void setPosition(float=0,float=0,float=0); void getOffset(float[]); void getPosition(float[]); private: float position[3]; float offset[3]; }; Some of the functions: void Car::move(float time){ float distance = velocity*time; location[0] += distance*cos(PI/2 - heading); location[1] += distance*sin(PI/2 - heading); float driverLocation [3]; float offset[3]; driver->getOffset(offset); for (int i = 0; i < 3; i++){ driverLocation[i] = offset[i] + location[i]; } } void Car::getDriverPosition(float p[]){ driver.getPosition(p); } void Person::getPosition(float p[]){ for (int i = 0; i < 3; i++){ p[i] = position[i]; } } void Person::getOffset(float o[]){ for (int i = 0; i < 3; i++){ o[i] = offset[i]; } } In Main: Car * car = new Car(); car->move(); float p[3]; car->getDriverPosition(p); When I print driverLocation[] inside the move() function, I have actual nonzero values. When I print p[] inside main, all I get are zeros.

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  • SHould i buy Thermal binder or spiral binder [closed]

    - by Mirage
    i need to print a lot of dcuments and the problem i come up with is the stapling all the pages. I thought i should buy a binder which can releive me a lot. I am confused whether i should buy thermal binder or spiral binder. Money is not any problem but i want the long term use. How reliable is the thermal binder? I think spiral binder can last very long as its pure mechanical ANy suggesstions

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  • Overcoming maximum file path length restrictions in Windows

    - by Christopher Edwards
    One of our customers habitually use very long path names (several nested folders, with long names) and we routinely encounter "user education issues" in order to shorten the path to less than 260 characters. Is there a technical solution available, can we flick some sort of switch in Windows 7 and Windows 2008 R2 to say "yeah just ignore these historical problems, and make +260 character path name work". P.S. I have read and been totally unedified by Naming Files, Paths, and Namespaces

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  • Open a terminal window & run command, then close the terminal window if command completed successfully?

    - by Caspar
    I'm trying to write a script to do the following: Open a terminal window which runs a long running command (Ideally) move the terminal window to the top left corner of the screen using xdotool Close the terminal window only if the long running command exited with a zero return code To put it in Windows terms, I'd like to have the Linux equivalent of start cmd /c long_running_cmd if long_running_cmd succeeds, and do the equivalent of start cmd /k long_running_cmd if it fails. What I have so far is a script which starts xterm with a given command, and then moves the window as desired: #!/bin/bash # open a new terminal window in the background with the long running command xterm -e ~/bin/launcher.sh ./long_running_cmd & # move the terminal window (requires window process to be in background) sleep 1 xdotool search --name launcher.sh windowmove 0 0 And ~/bin/launcher.sh is intended to run whatever is passed as a command line argument to it: #!/bin/bash # execute command line arguments $@ But, I haven't been able to get the xterm window to close after long_running_cmd is done. I think something like xterm -e ~/bin/launcher.sh "./long_running_cmd && kill $PPID" & might be what I'm after, so that xterm is launched in the background and it runs ./long_running_cmd && kill $PPID. So the shell in the xterm window then runs the long running command and if it completes successfully, the parent process of the shell (i.e. the process owning the xterm window) is killed, thereby closing the xterm window. But, that doesn't work: nothing happens, so I suspect my quoting or escaping is incorrect, and I haven't been able to fix it. An alternate approach would be to get the PID of long_running_cmd, use wait to wait for it to finish, then kill the xterm window using kill $! (since $! refers to last task started in the background, which will be the xterm window). But I can't figure out a nice way to get the PID & exit value of long_running_cmd out of the shell running in the xterm window and into the shell which launched the xterm window (short of writing them to a file somewhere, which seems like it should be unnecessary?). What am I doing wrong, or is there an easier way to accomplish this?

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  • OpenOffice.org 3 waits 25 seconds before opening

    - by Joey Adams
    I'm on Fedora 14, and OpenOffice 3.3.0 takes a long time to open (about 30 seconds, sometimes less). It isn't a CPU or disk performance issue, it's just simply a very long delay before the program opens. It appears to be a frivolous network connection timing out. According to Wireshark, it tries to look up: dulcimer.(none) which fails, after which it tries to look up: dulcimer.(none).mylitestream.com (dulcimer is my hostname, and LiteStream is my ISP) Is there a way to work around this bug in OpenOffice?

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  • Turn icon previews off globally in Mac OS X Snow Leopard

    - by Frederik
    When connecting to network drives (e.g. using ExpanDrive) every operation takes a long time. I've discovered this is due to the Finder trying to render an icon preview of every music file and PDF it encounters. Over the network, this can take a long time. I know I can turn off icon previews on a per-folder basis using the "View Options" dialog. Is it possible to change these settings globally?

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  • how to see activity logs on a linux pc?

    - by iamrohitbanga
    I want to find out everything possible about the how the pc was used in the past few days. Like who logged in, for how long was the PC was locked and any other information about user activity that is logged on my PC. I know that last command can be used to find out who was logged in and for how long. Any other information that can be found out.

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  • OpenOffice 3 takes forever to open

    - by Joey Adams
    I'm on Fedora 14, and OpenOffice 3.3.0 takes a long time to open (about 30 seconds, sometimes less). It isn't a CPU or disk performance issue, it's just simply a very long delay before the program opens. It appears to be a frivolous network connection timing out. According to Wireshark, it tries to look up: dulcimer.(none) which fails, after which it tries to look up: dulcimer.(none).mylitestream.com (dulcimer is my hostname, and LiteStream is my ISP) Is there a way to work around this bug in OpenOffice?

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  • How to set the time HylaFax waits for the remote device to pick up

    - by Flo
    I'm using HylaFax on one of my server to send facsimile to different devices which works pretty well except for one device. I'm not sure, but the problem might be, that the remote device takes to long to pick up and response to the call. I tested it by calling the fax number with my phone and it took 30 seconds till the remote side picked up. So is there a way to tell HylaFax how long it should wait for the remote device to answer?

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  • Time until Members added to Group Policy is Replicated

    - by Kyle Brandt
    If I have a group policy, and add a group/user/machine etc to that group policy, how long is it until all domain controllers have that change in effect? This is a Windows 2003 Domain set up with controllers at different geographic locations (Each with a different L3 network). I realize it probably depends, but how do I figure out how long it generally takes for my given setup? Also, is there an event I can check to see if it has a reached a particular domain controller?

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  • Why do scrollbars stop working when the mouse is too far away?

    - by compie
    Dragging a (Windows) scrollbar only works as long as the cursor is not too far away from the scrollbar itself. How can I 'fix' this bevaviour? Is there some kind of threshold in the registry? Tip: to see this behavior: click on a scrollbar (dont' release the mouse button) and move up/down. This works, as long as you don't move too much to the left.

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  • "Test to measure your ability to follow directions and solve complex problems in a neat and orderly manner." [closed]

    - by Matt
    Use the table of symbol substitutions when answering the problem below: Circle = 0 Dot = 1 Line = 2 Triangle = 3 Square = 4 Pentagon = 5 Hexagon = 6 Cross = 7 Heart = 8 Smiley Face = 9 Use the following special rule when answering the problem below: If ever a square is next to a cross during long multiplication, the square shall be treated as a triangle. Problem: Show your work in doing long multiplication of Pentagon Pentagon Nonagon by Line Square Octagon. Show your work using symbols not numbers.

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  • Upstart restart process time

    - by user567938
    A question about upstart. I understand the restart command does a stop and restart of the process. What happens if the process will not stop and check for the signals for a long time (20min or 2h)? Will it still restart after such a long time ? Example my-process: until stop_signal_received work for 2h end So the script will check for stop signals every 2 hours. $sudo restart my-process Will the process restart after 2 hours or not?

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  • Best password practices?

    - by sansenya
    for sensitive data, would it be better to have a somewhat long, but memorable password (and hence not totally random) or use a program like keepass to make a super long, random password with the highest possible entropy, and then just write down the password on a piece of paper kept in ones pocket. If that bang on the door comes, then swallow the paper. Which is a better security practice? I'm not in any way a criminal, i just am curious about topics concerning security. Thanks.

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  • How can I truncate an NSString to a set length?

    - by nevan
    I searched, but surprisingly couldn't find an answer. I have a long NSString that I want to shorten. I want the maximum length to be around 20 characters. I read somewhere that the best solution is to use substringWithRange. Is this the best way to truncate a string? NSRange stringRange = {0,20}; NSString *myString = @"This is a string, it's a very long string, it's a very long string indeed"; NSString *shortString = [myString substringWithRange:stringRange]; It seems a little delicate (crashes if the string is shorter than the maximum length). I'm also not sure if it's Unicode-safe. Is there a better way to do it? Does anyone have a nice category for this?

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  • Android text layout question: two textviews, side-by-side, with different layout alignments and weights

    - by thx1200
    I'm still a bit of an Android noob, forgive me if this is simple and I'm just not seeing it. There are two portions of text in a view that spans the entire width horizontally, but is only as high as one line of text. The left side must always be displayed in full, but should take no more horizontal space than it needs. The right side should be pushed over by the left side and fill up the remainder of the screen width. If the right side text is smaller than this width, the text should be right-aligned horizontally. If the text is greater than the width, it should scroll horizontally. The text on the right side will be updated frequently and should slide up with new text when the app tells it (explaining the TextSwitcher in the layout). I have tried two different layout styles. In both situations, I can get the left side to "push" the layout, the right side to scroll, but I can't figure out how to get the right side to right align. It is always left aligned. Here is a picture showing what is happening... http://img10.imageshack.us/img10/5599/androidlayout.png In addition (but less important), in my layout code I have android:fadingEdge="none" on the TextViews, but it still has a faded edge on the left and right side when it scrolls. Why is that? Here are the two layouts I created, which yield the results shown, but not the results I want. Using a horizontal LinearLayout... <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_gravity="right" android:layout_marginLeft="3px" android:layout_marginRight="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="match_parent" android:layout_height="match_parent" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </LinearLayout> And the RelativeLayout style... <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/LinearLayoutStatusBar" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_margin="2px" android:background="#555555" > <TextView android:id="@+id/TextViewTimer" android:textSize="18px" android:textColor="#FFFFFF" android:layout_gravity="left" android:layout_weight="0" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="0px" android:layout_marginRight="3px" android:layout_alignParentLeft="true" android:text="Left Side" > </TextView> <TextSwitcher android:id="@+id/TextSwitcherDetails" android:inAnimation="@anim/push_up_in" android:outAnimation="@anim/push_up_out" android:layout_weight="1" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_marginLeft="3px" android:layout_marginRight="0px" android:layout_toRightOf="@+id/TextViewTimer" android:layout_alignParentRight="true" android:fadingEdge="none" android:fadingEdgeLength="0px" > <TextView android:id="@+id/TextViewDetails1" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 1" > </TextView> <TextView android:id="@+id/TextViewDetails2" android:textSize="18px" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_gravity="right" android:singleLine="true" android:ellipsize="marquee" android:marqueeRepeatLimit="marquee_forever" android:scrollHorizontally="true" android:focusable="true" android:focusableInTouchMode="true" android:fadingEdge="none" android:fadingEdgeLength="0px" android:text="Right Side 2 - This is a really long text this is long and fun and fun and long" > </TextView> </TextSwitcher> </RelativeLayout> So how do I get that text on the right side to right-align. Thanks!

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  • Java Simple WGS84 Lat Lon to Pixel X, Y

    - by Cnich
    I've read a multitude of information regarding map projection today. The amount of information available is overwhelming. I am attempting to simply convert lat, long values into a screen X, Y coordinate not using any map. I do not need the values projected onto any map, just on the window. The window itself is representing approx. a 1500x1500 meter location. Lat, Long accuracy needed is to a 1/10th of a second. What may be some simpler ways in converting lat/long representation to the screen? I've read several articles and post regarding translation onto images, but nothing related to the natural java coordinate system. Thanks for any insight.

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  • Location.getTime() returning a future time.

    - by fiXedd
    The following code: // get the last known location Criteria c = new Criteria(); c.setAccuracy(Criteria.ACCURACY_FINE); Location lastKnown = mLocationManager.getLastKnownLocation(mLocationManager.getBestProvider(c, true)); // compare times long currentTime = System.currentTimeMillis(); long gpsTime = lastKnown.getTime(); long age = (currentTime - gpsTime) / 1000; Gives me: currentTime = 1270062152738 gpsTime = 1270085378000 age = -23225 If you'll notice, it's returning the last location fix's time as a time in the future. Why is this happening? EDIT: From Location.getTime() : Returns the UTC time of this fix, in milliseconds since January 1, 1970. From System.currentTimeMillis() : Returns the current system time in milliseconds since January 1, 1970 00:00:00 UTC. This method shouldn't be used for measuring timeouts or other elapsed time measurements, as changing the system time can affect the results.

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